Select all the correct answers. Which of these pairs of functions are inverse functions?

Answer:

to be honest I'm not sure how to do this question plz answer my question plz

Step-by-step explanation:

to be honest I'm not sure how to do this question plz answer my question plz I'm so much home workout

Answer:

[tex]AG=22[/tex]

Step-by-step explanation:

Follow the next steps:

[tex]\frac{A-B}{A-E} =\frac{B-C}{E-F} =\frac{C-D}{F-G} =\frac{A-C}{A-F} =\frac{B-D}{E-G} =\frac{A-D}{A-G}[/tex]

Let:

[tex]\frac{A-B}{A-E} =\frac{B-C}{E-F}\\ \\\frac{4}{A-E} =\frac{5}{10x}\\ \\Solving\hspace{3}for\hspace{3}A-E\\\\A-E=8x[/tex]

Now:

[tex]\frac{C-D}{F-G} =\frac{A-C}{A-F} \\\\\frac{2}{F-G} =\frac{9}{18x} \\\\Solving\hspace{3}for\hspace{3}F-G\\\\F-G=4x[/tex]

Hence:

[tex]A-G=(A-E)+(E-F)+(F-G)=22x[/tex]

Finally:

[tex]\frac{B-D}{E-G} =\frac{A-D}{A-G}\\\\\frac{A-D}{B-D} =\frac{A-G}{E-G}\\[/tex]

[tex]\frac{11}{7} =\frac{22x}{14x} \\\\\frac{11x^{2} }{7} -\frac{11}{7} =0\\\\[/tex]

Hence:

[tex]x=1\\x=-1[/tex]

Since it would be absurd for [tex]x=-1[/tex], the real solution is [tex]x=1[/tex]

Therefore:

[tex]AG=22[/tex]

Answer:

[tex]\huge\boxed{x-intercept=-\dfrac{14}{3}=-4\dfrac{2}{3}}\\\boxed{y-intercept=\dfrac{14}{9}=1\dfrac{5}{9}}[/tex]

Step-by-step explanation:

[tex]-3x+9y=14\\\\x-intercept\ \text{for}\ y=0:\\\\-3x+9(0)=14\\-3x+0=14\\-3x=14\qquad\text{divide both sides by (-3)}\\\boxed{x=-\dfrac{14}{3}=-4\dfrac{2}{3}}}[/tex]

[tex]y-intercept\ \text{for}\ x=0:\\\\-3(0)+9y=14\\0+9y=14\\9y=14\qquad\text{divide both sides by 9}\\\boxed{y=\dfrac{14}{9}=1\dfrac{5}{9}}[/tex]

That's a pretty tall order for Brainly homework.  Let's start with the depressed cubic, which is simpler.

Solve

[tex]y^3 + 3py = 2q[/tex]

We'll put coefficients on the coefficients to avoid fractions down the road.

The key idea is called a split, which let's us turn the cubic equation in to a quadratic.  We split unknown y into two pieces:

[tex]y = s + t[/tex]

Substituting,

[tex](s+t)^3 + 3p(s+t) = 2q[/tex]

Expanding it out,

[tex]s^3+3 s^2 t + 3 s t^2 + t^3 + 3p(s+t) = 2q[/tex]

[tex]s^3+t^3 + 3 s t(s+t) + 3p(s+t) = 2q[/tex]

[tex]s^3+t^3 + 3( s t + p)(s+t) = 2q[/tex]

There a few moves we could make from here. The easiest is probably to try to solve the simultaneous equations:

[tex]s^3+t^3=2q, \qquad st+p=0[/tex]

which would give us a solution to the cubic.

[tex]p=-st[/tex]

[tex]t = -\dfrac p s[/tex]

Substituting,

[tex]s^3 - \dfrac{p^3}{s^3} = 2q[/tex]

[tex](s^3)^2 - 2 q s^3 - p^3 = 0[/tex]

By the quadratic formula (note the shortcut from the even linear term):

[tex]s^3 = q \pm \sqrt{p^3 + q^2}[/tex]

By the symmetry of the problem (we can interchange s and t without changing anything) when s is one solution t is the other:

[tex]s^3 = q + \sqrt{p^3+q^2}[/tex]

[tex]t^3 = q - \sqrt{p^3+q^2}[/tex]

We've arrived at the solution for the depressed cubic:

[tex]y = s+t = \sqrt[3]{q + \sqrt{p^3+q^2}} + \sqrt[3]{ q - \sqrt{p^3+q^2} }[/tex]

This is all three roots of the equation, given by the three cube roots (at least two complex), say for the left radical.  The two cubes aren't really independent, we need their product to be [tex]-p=st[/tex].

That's the three roots of the depressed cubic; let's solve the general cubic by reducing it to the depressed cubic.

[tex]x^3 + ax^2 + bx + c=0[/tex]

We want to eliminate the squared term.  If substitute x = y + k we'll get a 3ky² from the cubic term and ay² from the squared term; we want these to cancel so 3k=-a.

Substitute x = y - a/3

[tex](y - a/3)^3 + a(y - a/3)^2 + b(y - a/3) + c = 0[/tex]

[tex]y^3 - ay^2 + a^2/3 y - a^3/27 + ay^2-2a^2y/3 + a^3/9 + by - ab/3 + c =0[/tex]

[tex]y^3 + (b - a^2/3) y = -(2a^3+9ab) /27 [/tex]

Comparing that to

[tex]y^3 + 3py = 2q[/tex]

we have [tex] p = (3b - a^2) /9, q =-(a^3+9ab)/54 [/tex]

which we can substitute in to the depressed cubic solution and subtract a/3  to get the three roots.  I won't write that out; it's a little ugly.

Answer:

The improper fraction 8/5 can be changed to the mixed number 1 3/5 by dividing the numerator (8) by the denominator (5). This gives a quotient of 1 and a remainder of 3.

Step-by-step explanation:

Answer:

5a

Step-by-step explanation:

Answer:

5a.

Step-by-step explanation:

2a + 3a

= (2 + 3)a

= 5a.

Hope this helps!

Answer:

D.$80

Step-by-step explanation:

$5.26 x 15.5= $81.53

The closest amount to $81.53 is D.$80

Answer:

18. b. 4/14

19. b. 30/40

20. c. 21/48

21. a. 9/20

22. a. 6/24

Step-by-step explanation:

So in these questions all we do is multiply the fractions.

18)

[tex]\frac{4}{7} * \frac{1}{2}[/tex]

4*1 = 4

7*2 = 14

b. 4/14

19)

[tex]\frac{15}{2}*\frac{2}{20}[/tex]

15*2 = 30

2*20 = 40

b. 30/40

20)

[tex]\frac{3}{6}*\frac{7}{8}[/tex]

3*7 = 21

6*8 = 48

c. 21/48

21)

[tex]\frac{9}{10}*\frac{1}{2}[/tex]

9*1 = 9

10*2 = 20

a. 9/20

22)

[tex]\frac{3}{6}*\frac{2}{4}[/tex]

3*2 = 6

6*4=24

a. 6/24

Hope this helps :)

Answer:

14.16 miles further.

Step-by-step explanation:

Campbell to Summerfield

9.52mi + 4.62 mi + 10.08 mi = 24.24 mi

Princeton to summerfield

is 10.08 mi

Therefore difference is 24.24mi - 10.08mi = 14.16 mi

Hope this helps.

Answer:

349

Step-by-step explanation:

We know that a₁ (the first term) is 6 and d (the common difference) is 13 - 6 = 7.

Explicit formula: aₙ = a₁ + (n - 1)d = 13 + (n - 1) * 7 = 7n - 1

Therefore, a₅₀ = 7(50) - 1 = 349

Answer: x(x-4) = 140 This equation can be solve to find the length.

Step-by-step explanation:

If the width of the rectangle will be 4 less than the length and the length is represented by x then we could have the equation   w=x - 4 for the width and the length is just x. And to find the area of a rectangle we multiply the length by the with so multiply x-4 by x  for it to equal 140 because 140 is the area.

x(x-4) = 140   solve for x

[tex]x^{2}[/tex] - 4x = 140   subtract 140 from both sides  

x^2 - 4x - 140 = 0  find a number that the product is 140 and the sum is -4

                                  -14 and 10 works out.

[tex]x^{2}[/tex] - 14x + 10x - 140 = 0  factor by grouping

x(x -14)  10(x-14) = 0     factor out x-14

(x-14) ( x+10) = 0         set them both equal zero.

x-14= 0      or   x+10 = 0

x = 14      or x= -10  

Since -10 can't represent a distance, the answer is 14.

Check.  

In this case the length is 14  and if the width is 4 less than the length then we will subtract 4 from 14.

14- 4 = 10  so the width is 10.

14 * 10 = 140

Answer:

1

 Option B  is the correct answer

2

   [tex]n = 9418[/tex]

Step-by-step explanation:

From the question we are told that

    The  sample size is  [tex]n = 2348[/tex]

    The  sample proportion is  [tex]\r p = 0.54[/tex]

Given that the confidence level is  99%  then the level of significance is evaluated as

      [tex]\alpha = 100 - 99[/tex]

      [tex]\alpha = 1[/tex]%

      [tex]\alpha = 0.01[/tex]

Next we obtain the critical values of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table. The values obtained is  

   [tex]Z_{\frac{\alpha }{2} } = 2.58[/tex]

The reason we are obtaining values for  is because  is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while   is the area under the normal distribution curve for just one tail and we need the  value for one tail in order to calculate the confidence interval .

Next is to calculate the margin of error which is mathematically evaluated as  

        [tex]MOE = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p ( 1 - \r p )}{n } }[/tex]

substituting values

        [tex]MOE = 2.58 * \sqrt{ \frac{0 .54( 1 - 0.54 )}{2348 } }[/tex]

        [tex]MOE = 0.0265[/tex]

Now the interval for the 99% confidence level is evaluated as  

     [tex]\r p - MOE < \r p < \r p + MOE[/tex]

substituting values  

    [tex]0.514 < \r p <0.567[/tex]

Looking at the Confidence interval we see that the proportion of  Americans that watched streamed program up to that point in time is between

     51.4%  and 56.7%

Hence we are 99% confident that this interval contains the true population proportion.

The  sample  size that will be required for the width o 99%  Cl  is mathematically  evaluated as

            [tex]n = \frac{4 *[Z_{\frac{\alpha }{2} }]^2 * \r p (1- \r p )}{MOE^2}[/tex]

substituting values

           [tex]n = \frac{4 *2.58^2 * 0.54 (1- 0.54 )}{0.0265^2}[/tex]

          [tex]n = 9418[/tex]

Answer: Parents and children ( till the age of 5) of Norway

Step-by-step explanation:

Here, A large study of over 2000 parents and children in Norway found that toddlers who regularly slept less than 10 hours per night or woke frequently (three or more times) at night tended to experience more emotional and behavioral problems when they reached age five.

Since the study involved a large random sample of mothers and children and was conducted over several years.

So, the population of interest in this survey is "Parents and children ( till the age of 5) of Norway".

Answer:

Change in the cost of each book printed = $25

Cost to get started = $1150

Step-by-step explanation:

Equation representing the relation between number of copies of the books (x)  and total cost of publishing a book (y) is,

y = 1150 + 25x

This equation is in the form of a linear equation,

y = mx + b

Where m represents the change in cost of printing each book and y-intercept of the line 'b' represents the cost before any book is printed.

By comparing these equations,

m = 25

Therefore, change in the cost of each book printed = $25

b = 1150

Which represents the cost to get started = $1150

Answer:

[tex]\r p = 0.11[/tex]

[tex]\r q = 0.89[/tex]

n = 2000

[tex]E = \pm 5[/tex]

p - population proportion

[tex]\alpha = 5[/tex]%

Step-by-step explanation:

From the question we are told that  

   The  sample size is  [tex]n = 2000[/tex]

   The  proportion of the population for chocolate pie is  [tex]p_c = 0.11[/tex]

   The  margin of error is  [tex]E = \pm 5[/tex]%  

Now in the question we are asked to provide the meaning of  

       [tex]\r p , \r q , n , E , and\ p[/tex]

Now  [tex]\r p[/tex] is the sample proportion of the population that those  chocolate​ pie as  favorite pie of   which is given from the question as 0.11

Now

         [tex]\r q[/tex] is the sample  proportion of the population that choose other pies apart from chocolate pie as their favorite and it is evaluated as

      [tex]\r q = 1 - \r p[/tex]

      [tex]\r q = 1 - 0.11[/tex]

       [tex]\r q = 0.89[/tex]

       n is the sample size which is given as  n =  2000

       E is the margin of  error which given as  [tex]E = \pm 5[/tex]%

       p is the population proportion

Given that the confidence level is  95 %  then the level of significance is  mathematically evaluated as

        [tex]\alpha =(100 - 95)[/tex]%

        [tex]\alpha =[/tex]5%

Answer:

I think it is [tex]\frac{6x-18}{x^{4} }[/tex]

Step-by-step explanation:

Answer:

C. Supplementary

Step-by-step explanation:

Angle a and angle b are on the line CZA.

We can assume that line CZA is a straight line, which is equal to 180 degrees.

Since angle a and b are on the straight line together, they must add to 180 degrees. Therefore, they are supplementary angles.

So, choice C. Supplementary angles is correct.

Answer:

One hour ten minutes

Step-by-step explanation:

departing trains can empty it in 40 minutes.

entering travelers can fill a station in 30 minutes.

Time it will take travellers to fill the train

= Time for departing train + time for filling a station

= 40 minutes+ 30 minutes

= 70 minutes

= One hour ten minutes

−π2≤sin−1x≤π2  

3π2≤5≤2π

−π2≤5−2π≤0≤π2

sin(5–2π)=sin5

Thus, sin−1(sin5)=5−2π

Answer:

The large of a sample size is required is 6,592

Step-by-step explanation:

In order to calculate large of a sample size is required we would have to calculate the following formula:

large of a sample size is required=(Z∝I2/E)∧2* P(1-P)

According to the given data we have the following:

E= margin of error= 1%=0.01

95% confident that your esimate is within 1% of the true population proportion, therefore, level of significance=∝=1-0.95=0.05

Z value for the 95% confident is 1.960, therefore, Z∝I2=1.960

Therefore, large of a sample size is required=(1.960/0.01)∧2* (0.22)(1-0.22)

large of a sample size is required=6,592

The large of a sample size is required is 6,592

Answer:

A  B  C

Step-by-step explanation:

Answer:

abc or 123

Step-by-step explanation:

Answer:

40 cm by 44 cm

Step-by-step explanation:

A square sheet of paper has area 1600 cm^2.

area = s^2

1600 cm^2 = s^2

s = sqrt(1600 cm^2)

s = 40 cm

The side of the square was 40 cm, so the square measured 40 cm by 40 cm.

One side of 4 cm short, so the paper should have been 40 cm by 44 cm.

Answer:

it is a two tailed test

The p - value for z=1.92  is 0.9726

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

Step-by-step explanation:

For p≠0.767

Taking  null hypothesis as p≠0.767 and alternate hypothesis as p =0.767

H0 :p≠0.767  Ha :p≠0.767  it is a two tailed test

The p - value for z=1.92  is 0.9726 from the table.

Using a significance level of α=0.10

z value for 0.10 for two tailed test is ± 1.645

Z >zα

1.92> ± 1.645

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

Answer:

120 + 4w

Step-by-step explanation:

I am indeed doing it aswell

Answer:

The sales account for year 3 is [tex][\frac{32\ \text{mn}-x\ \text{mn}}{x\ \text{mn}}\times 100\%][/tex].

Step-by-step explanation:

As the sales for year 2 is not provided, assume it is x million.

The total sales in year 3 is, 32 million.

Compute the sales account for year 3 as follows:

[tex]\text{Percentage of sales for year 3}=\frac{\text{Total Sales in year 3}-\text{Total Sales in year 2}}{\text{Total Sales in year 2}}\times 100\%[/tex]

                                              [tex]=\frac{32\ \text{mn}-x\ \text{mn}}{x\ \text{mn}}\times 100\%[/tex]

Answer:

See the attachment for sketch

Thr region is unbounded

DNE

Step-by-step explanation:

y≤ -2x + 10

The inequality is a straight line and region marked by the inequality. It has no boundaries. The boundaries extend to infinity. So the region is unbounded. Unbounded region has no corner points.

Answer:

[tex]\huge\boxed{a_3=9,216}[/tex]

Step-by-step explanation:

[tex]a_n=64(12)^{n-1}\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^{3-1}=64(12)^2=64(144)=9,216[/tex]

Step-by-step explanation:

f(x)=2x²+3x+9

g(x) = - 3x + 10

In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9

Expand

(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

= 18x² - 120x + 200 - 9x + 30 + 9

Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

(f⋅g)(x) = 18x² - 129x + 239

To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

That's

(f⋅g)(1) = 18(1)² - 129(1) + 239

= 18 - 129 + 239

We have the final answer as

Hope this helps you

Answer: A) At 90% confidence interval estimate of the population mean

is,( 25.0405 , 25.9595 )

B) YES

Step-by-step explanation:

Given that,

Point estimate = sample mean  Ж = 25.5

Population standard deviation α  = 5.3

Sample size = n =360

At 90% confidence level the z is ,

∝ = 1 - 90% = 1 - 0.90 = 0.1

∝ / 2 = 0.1 / 2 = 0.05  

Z∝/2 = Z0.05 = 1.645 ( WHEN WE USE THE Z TABLE )

Margin of error E = Z∝/2 * ( α/√n)

E = 1.645 * (5.3 / √360 )  = 0.4595

At 90% confidence interval estimate of the population mean

is

Ж - E < ц < Ж + E  

25.5 - 0.4595 <  ц < 25.5 + 0.4595  

25.0405 <  ц < 25.9595  

( 25.0405 , 25.9595 )

At 90% confidence interval estimate of the population mean

is,( 25.0405 , 25.9595 )

B) This confidence interval can be used to estimate the mean weight of all one - year old babies in the US since the mean value of 25.5 falls within the confidence values, we have sufficient evidence to

conclude that the mean weight of all one-year-old boys is 25.5

Answer:

0.76 or 19/25

Step-by-step explanation:

Convert 4/10 so that it has a common denominator with 36/100.

4/10 x 10/10 = 40/100

Now that the denominator is the same, just add the top values.

40/100 + 36/100 = 76/100

We can also simplify the answer to be 19/25 by dividing the top and bottom by 4.

Answer:

Step-by-step explanation:

[tex]\frac{36}{100}+\frac{4}{10}\\Let\: first\: deal\: with\: ;\frac{36}{100}\\\mathrm{Cancel\:the\:common\:factor:}\:4\\=\frac{9}{25}\\\\=\frac{9}{25}+\frac{4}{10}\\Now \:lets \:deal \:with ; \frac{4}{10}\\\mathrm{Cancel\:the\:common\:factor:}\:2\\=\frac{2}{5}\\=\frac{9}{25}+\frac{2}{5}\\\mathrm{Prime\:factorization\:of\:}25:\quad 5\times\:5\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Multiply\:each\:factor\:the\:greatest\:number\:of\:times\:it\:occurs\:in\:either\:}25\mathrm{\:or\:}5\\[/tex]

[tex]\lim_{n \to \infty} a_n =5\cdot \:5\\\\\mathrm{Multiply\:the\:numbers:}\:5\cdot \:5=25\\=25\\\mathrm{Multiply\:each\:numerator\:by\:the\:same\:amount\:needed\:to\:multiply\:its}\\\mathrm{corresponding\:denominator\:to\:turn\:it\:into\:the\:LCM}\:25\\\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}5\\\frac{2}{5}=\frac{2\times \:5}{5\times \:5}=\frac{10}{25}\\=\frac{9}{25}+\frac{10}{25}\\[/tex]

[tex]\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{9+10}{25}\\\\=\frac{19}{25}[/tex]