Answer:
the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion
Step-by-step explanation:
From the given information:
Let consider y to represent the number of years after 1999
Then the population in time (y) can be expressed as:
P(y) = 9400y + 924900
The average annual income can be written as:
A(y) = 1400y + 30388
The total personal income = P(y) × A(y)
The rate at which the total personal income is rising is T'(y) :
T'(y) = P'(y) × A(y) + P(y) × A'(y)
T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'
T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400
Since in 1999 y =0
Then:
T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400
T'(0) = 9400(30388) + (924900)1400
T'(0) = $1,580,507,200 billion
Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion
A rectangular waterbed is 8 ft long, 5 fr, wide and 1 ft tall.
How many gallons of water are needed to fill the waterbed?
Assume 1 gallon is 0.13 ft.³ round to the nearest whole gallon
Answer: 308 gallons of water.
Step-by-step explanation:
First find the volume of the water been.
The volume of a rectangular prism uses the formula
V= L * W *H
V = 8 * 5 * 1
V = 40 ft^3
Now we will convert 40ft into gallons using what they gave us that 1 gallon is 0.13 ft^3
[tex]\frac{1}{x} = \frac{0.13}{40}[/tex] which means if 1 gallon is 0.13 cubic feet how much will 40 cubic feet be when converted to gallons.
Solve by cross product.
0.13x = 40 divide both sides by 0.13
x= 308
The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm.
(a) Use differentials to estimate the maximum error in the calculated surface area. (Round your answer to the nearest integer.)
cm2
What is the relative error? (Round your answer to three decimal places.)
(b) Use differentials to estimate the maximum error in the calculated volume. (Round your answer to the nearest integer.)
cm^3
What is the relative error? (Round your answer to three decimal places.)
Answer:
Error in the sphere's surface: 29 [tex]cm^2[/tex] and relative error in surface measure: 0.011
Error in the sphere's volume: 205 [tex]cm^3[/tex] and relative error in the volume measure: 0.017
Step-by-step explanation:
(a)
The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:
[tex]l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm[/tex]
and with regards to the error:
[tex]dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm[/tex]
then when we use the formula for the sphere's surface, we get:
[tex]S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2[/tex]
Then the relative error in the surface is:
[tex]\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011[/tex]
(b)
Use the formula for the volume of the sphere:
[tex]V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3[/tex]
Then the relative error in the volume is:
[tex]\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017[/tex]
If 100 envelope cost 70 cents how much would 250 cost
Answer:
178.5 actually
Step-by-step explanation:
convert 1000m to kilometres
Answer:
1km
Step-by-step explanation:
1000m=1km
Ez Money
Answer:
1000m= 1km
if you convert 1m to km is 0.001km times it by 1000, you get 1km.
The height of the right circular cylinder is 10 cm and the radius of the base is 7 cm. Then, the difference between the total surface area and the curved surface area is a) 300 cm^2 b) 308 cm^3 c) 308 cm^2 d) 308 cm
plz answer it fast I will mark them as the brainlist
Answer:
The answer is option C
308cm²Step-by-step explanation:
Total surface area of a cylinder is
2πr( r + h)
The curved surface area of a cylinder is
2πrh
where r and h are the radius and height respectively
h = 10cm
r = 7cm
Total surface area is
2π×7( 7 + 10)
14π ( 7 + 10)
98π + 140π
238π
Which is
748 cm²
The curved surface area is
2π (7)(10)
140π
Which is
440cm²
The difference between the total surface area and the curved surface area of the cylinder is
748 cm² - 440cm²
= 308cm²Hope this helps you
An open box with no lid has a square base and four sides of equal height. The height is 4 inches
greater than the length and width (which are the same). What are the dimensions of the box if the
volume is 63 cubic inches and the surface area is 93 square inches?
PLEASE SHOW YOUR WORK:) THANK YOU SO MUCH
Answer:
width = length = 3 inches
height = 7 inches
Step-by-step explanation:
If x is the width and length of the base, and y is the height, then:
y = x + 4
The volume of the box is:
63 = x²y
The surface area of the box is:
93 = x² + 4xy
Substitute the first equation into the third.
93 = x² + 4x (x + 4)
93 = x² + 4x² + 16x
0 = 5x² + 16x − 93
0 = (x − 3) (5x + 31)
x = 3
y = 7
Use the second equation to check your answer.
63 = (3)²(7)
63 = 63
Answer:
Length=Width=3
Height=7.
Step-by-step explanation:
First, let's write some equations. So, we have an open box (with no lid) that has a square base. It has a height 4 units more of its width/length.
First, let's write the equation for the volume. The volume of a rectangular prism is:
[tex]V=lwh[/tex]
Recall that we have a square base. In other words, the length and width are exactly the same. Therefore, we can do the following substitution:
[tex]V=(w)wh=w^2(h)[/tex]
Now, recall that the height is four units more than the width/length. Therefore, we can make the following substitution:
[tex]V=w^2(w+4)\\63=w^2(w+4)[/tex]
We can't really do anything with this. Let's next find the equation for the surface area.
So, we have 5 sides (not 6 because we have no lid). The bottom side is a square, so it's area is w^2. Since we have a square base, the remaining four sides will have an area w(w+4). In other words:
[tex]93=w^2+4(w(w+4))[/tex]
The left term represents the area of the square base. The right term represents the area of one of the rectangular sides, times sides meaning four sides. Simplify:
[tex]93=w^2+4w^2+16w\\5w^2+16w-93=0[/tex]
This seems solvable. Let's try it. Trying factoring by guessing and checking.
We can see that it is indeed factor-able. -15 and 31 are the numbers:
[tex]5w^2-15w+31w-93=0\\5w(w-3)+31(w-3)=0\\(5w+3)(w-3)=0\\w=3\\h=w+4=7[/tex]
We ignore the other one because width cannot be negative.
So, the width/length is 3 and the height is 7. We can check this by plugging this into the volume formula:
[tex]63\stackrel{?}{=}(3)^2(7)\\63\stackrel{\checkmark}{=}63[/tex]
For each function, determine if it intersects or is parallel to the line y=−1.5x. If it intersects the line, find the intersection point. y=0.5x−6
Answer: the intersection point is (2.4, -4.8)
Step-by-step explanation:
A) we have the function:
y = 0.5*x - 6.
First we want to know if this function intersects the line y´ = -1.5*x
Now, first we can recall that two lines are parallel only if the slope is the same for both lines, here we can see that the slopes are different, so the lines are not parallel, which means that the lines must intersect at some point.
Now, to find the intersection point we asumme y = y´ and want to find the value of x.
0.5*x - 6 = -1.5*x
(0.5 + 1.5)*x - 6 = 0
2.5*x = 6
x = 6/2.5 = 2.4
Now, we evaluate one of the functions in this value of x.
y = 0.5*2.4 - 6 = -4.8
So the intersection point is (2.4, -4.8)
If a pair of dice are rolled,
what is the probability that at least
one die shows a 5?
Answer:
11/36
Step-by-step explanation:
Find the probability that neither dice shows a 5 (also means the dice can show any number except 5- where there are 5 possible choices out of 6):
= 5/6 x 5/6
=25/36
If we subtract the probability that neither dice shows a 5, we can obtain the probability that at least 1 dice shows a 5- (either one of them is 5, or both of them is 5)
1- 25/36
=11/36
Evaluate the following integrals
Answer:
a. (24 ln 2 − 7) / 9
b. x tan x + ln|cos x| + C
Step-by-step explanation:
a. ∫₁² x² ln x dx
Integrate by parts.
If u = ln x, then du = 1/x dx.
If dv = x² dx, then v = ⅓ x³.
∫ u dv = uv − ∫ v du
= (ln x) (⅓ x³) − ∫ (⅓ x³) (1/x dx)
= ⅓ x³ ln x − ∫ ⅓ x² dx
= ⅓ x³ ln x − ¹/₉ x³ + C
= ¹/₉ x³ (3 ln x − 1) + C
Evaluate between x=1 and x=2.
[¹/₉ 2³ (3 ln 2 − 1) + C] − [¹/₉ 1³ (3 ln 1 − 1) + C]
⁸/₉ (3 ln 2 − 1) + C + ¹/₉ − C
⁸/₉ (3 ln 2 − 1) + ¹/₉
⁸/₃ ln 2 − ⁸/₉ + ¹/₉
⁸/₃ ln 2 − ⁷/₉
(24 ln 2 − 7) / 9
b. ∫ x sec² x dx
Integrate by parts.
If u = x, then du = dx.
If dv = sec² x dx, then v = tan x.
∫ u dv = uv − ∫ v du
= x tan x − ∫ tan x dx
= x tan x + ∫ -sin x / cos x dx
= x tan x + ln|cos x| + C
Simplify the expression by using the properties of rational exponents. Write the final answer using positive exponents only. (x4y8)2/3
Answer:
[tex]x^\frac{8}{3} y^\frac{16}{3}[/tex]
Step-by-step explanation:
Given the expression [tex](x^4y^8)^\frac{2}{3}[/tex], to simplify the expression using the rational exponents;
Applying one of the law of indices to simplify the expression;
[tex](a^m)^n = a^{mn}[/tex]
[tex](x^4y^8)^\frac{2}{3}\\\\= (x^4)^\frac{2}{3} * (y^8)^\frac{2}{3}\\\\= x^{4*\frac{2}{3} } * y^{8*\frac{2}{3} }\\\\= x^\frac{8}{3} * y^\frac{16}{3}\\ \\The \ final \ expression \ will \ be \ x^\frac{8}{3} y^\frac{16}{3}[/tex]
High temperatures in a certain city for the month of August follow a uniform distribution over the interval LaTeX: 61^{\circ}F61 ∘ Fto LaTeX: 91^{\circ}F91 ∘ F. Find the high temperature which 90% of the August days exceed.
Answer:
The required probability for the high temperature which 90% of the August days exceed. is 0.0333
Step-by-step explanation:
High temperatures in a certain city for the month of August follow a uniform distribution over the interval 61° F to 91° F . Find the high temperature which 90° F of the August days exceed.
Let assume that X is the random variable
The probability mass function is:
[tex]f(x) = \dfrac{1}{b-a}[/tex]
[tex]f(x) = \dfrac{1}{91-61}[/tex]
[tex]f(x) = \dfrac{1}{30}[/tex]
Thus; The probability density function of X can be illustrated as :
[tex]f(x) = \left \{ {{ \ \ \dfrac{1}{30}} \atop { \limits }}_ \right. _0[/tex] 61 < x < 91 or otherwise
The required probability for the high temperature at 90° F can be calculated as follows:
[tex]P(X> 90) = \int\limits^{91}_{90} {f(x)} \, dx[/tex]
[tex]P(X> 90) = \int\limits^{91}_{90} \ {\dfrac{1}{30} \, dx[/tex]
[tex]P(X> 90) = {\dfrac{1}{30} \int\limits^{91}_{90} \ \, dx[/tex]
[tex]P(X> 90) = {\dfrac{1}{30} [x]^{91}_{90}[/tex]
[tex]P(X> 90) = {\dfrac{1}{30} (91-90)[/tex]
[tex]P(X> 90) = {\dfrac{1}{30} \times 1[/tex]
[tex]P(X> 90) = 0.0333[/tex]
The required probability for the high temperature which 90% of the August days exceed. is 0.0333
Does it take more large paper clips or small paper cps lined up end to end to measure the
width of a piece of printer paper? Explain.
Answer:
Step-by-step explanation:
You haven't answered any questions, yet…
1. Find the sum of the first five (5) terms of the arithmetic progression
60 + 91 +122 ---.
Step-by-step explanation:
to find the sum of nth term
equation is
n/2 ( 2a + (n-1)d) where a is the 1st term and d is the common difference
5/2 ( 120 +( 4 × 31))
5/2 ( 120 + 124)
5/2 × 244
5 × 122 dividing 244 by 2
610
Answer: 610
Step-by-step explanation:
This sequence starts at 60 and increases by increments of 31. Thus, to get the last two numbers, do 122+31=153, and 153+31=184. Then add 60+91+122+153+184 to get 610.
Hope it helps <3
The graph of f*x)=2^(x+3) shifts 10 units to the right when it is replaced with the graph of f(x)=2^(x-k). What is the value of k?
Answer:
7
Step-by-step explanation:
f(x) = 2^(x + 3)
Shifted 10 units to the right:
f(x) = 2^(x + 3 − 10)
f(x) = 2^(x − 7)
Therefore, k = 7.
Which of the binomials below is a factor of this trinomial?
x2 - 5x+ 4
O A. X-1
O B. x2 + 4
C. X+4
D. X + 1
Answer:
A
Step-by-step explanation:
To factor x² - 5x + 4, we need to find 2 numbers that have a sum of -5 and product of 4; these 2 numbers are -1 and -4 so the factored version is (x - 1)(x - 4). Since x - 4 is not an answer choice but x - 1 is, the answer is A.
AACB ~AEFD
x = [?]
Enter your answer in decimal form.
Answer:
11.4Solution,
∆ ACB = ∆ EFD
finding the value of X,
[tex] \frac{x}{3.8} = \frac{15}{5} [/tex]
Apply cross product property
[tex]x \times 5 = 15 \times 3.8[/tex]
Calculate the product
[tex]5x = 57[/tex]
Divide both sides by 5
[tex] \frac{5x}{5} = \frac{57}{5} [/tex]
Calculate
[tex]x = 11.4[/tex]
Hope this helps...
Good luck on your assignment...
Write the equations after translating the graph of y = |x|: one unit up,
Answer:
[tex]g(x) = |x| + 1[/tex]
Step-by-step explanation:
Given
[tex]y = |x|[/tex]
Required
Translate 1 unit up
Start by replacing y with f(x)
[tex]f(x) = |x|[/tex]
To translate an the graph of an absolute function upward, you make use of the formula;
[tex]g(x) = f(x) + k[/tex]
Where k is the number of units
In this case; [tex]k = 1[/tex]
Hence;
[tex]g(x) = f(x) + k[/tex]
Substitute [tex]k = 1[/tex]
[tex]g(x) = f(x) + 1[/tex]
Substitute [tex]f(x) = |x|[/tex]
[tex]g(x) = |x| + 1[/tex]
Hence, the resulting equation is [tex]g(x) = |x| + 1[/tex]
Data was collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram below. 2 4 6 8 10 amount of sugar (mg) 180 182 184 186 188 190 192 194 Frequency What is the sample size for this data set?
Answer:
The sample size is 30.
Step-by-step explanation:
The sample size of a histogram can be calculated by summing up all the frequencies of all the occurrences in the data set
From the question the frequency is given as
Frequency = 2 4 6 8 10
The sample size n =
2 + 4 + 6 + 8 + 10
= 30
Therefore the sample size n of the data set = 30
The instructor wants to give an A to the students whose scores were in the top of the class. What is the minimum score needed to get an A
Answer:
The minimum svore required to get an A is 85.3.
Step-by-step explanation:
Complete Question
Exam grades: Scores on a statistics final in a large class were normally distributed with a mean of 75 and a standard deviation of 8.
The instructor wants to give an A to the students whose scores were in the top 10% of the class. What is the minimum score needed to get an A?
Solution
Scores in the top 10% of the class will have a minimum greater than the remaining bottom 90% of the class.
If the minimum score for the top 10% of the class is x'
P(X ≤ x') = 90% = 0.90
If the z-score of this minimum score of the top 10%, x', is z'.
P(X ≤ x') = P(z ≤ z') = 0.90
using the z-distribution tables
z' = 1.282
But the z-score of any value is given as the value minus the mean divided by the standard deviation.
z = (x - μ)/σ
So,
z' = (x' - μ)/σ
Mean = 75
Standard deviation = 8
z' = 1.282
1.282 = (x' - 75)/8
x' = (1.282 × 8) + 75 = 85.256
= 85.3 to 3 s.f.
Hope this Helps!!!
In a random sample of 500 handwritten zip code digits, 464 were read correctly by an optical character recognition (OCR) system operated by the U.S. Postal Service (USPS). USPS would like to know whether the rate is at least 90% correct.
Required:
Do the data provide evidence that the rate is at least 90% at a 0.05?
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
What equation results from completing the square and then factoring? x^2+22x=31 A.(x+22)^2=53 B.(x+22)^2=152 C.(x+11)^2=152 D.(x+11)^2=53
Answer:
[tex]\boxed{\mathrm{Option \ C}}[/tex]
Step-by-step explanation:
=> [tex]x^2+22x = 31[/tex]
=> [tex](x)^2+2(x)(11) = 31[/tex]
Since b = 11 , So [tex](11)^2[/tex] needs to be added to both sides
Adding [tex](11)^2[/tex] to both sides
=> [tex](x)^2+2(x)(11)+(11)^2 = 31+(11)^2[/tex]
Completing the square
=> [tex](x+11)^2 = 31+121[/tex]
=> [tex](x+11)^2 = 152[/tex]
Please help. I’ll mark you as brainliest if correct!
Answer:
(x, 2 -2x)
Step-by-step explanation:
Written in standard form, both equations are ...
2x +y = 2
Since they are both the same, there are an infinite number of solutions. We can write those solutions in terms of x as ...
y = 2 -2x
The solutions are ...
(x, 2 -2x)
Find the volume of a cylinder with a radius of 2 and a length of 9
Answer:
V = pi 36 units^3
V =113.04 units^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h
V = pi ( 2) ^2 *9
V = pi 36
Letting pi = 3.14
V =113.04
if a 10 pound turkey cost 20.42 how much does 21 pound turkey cost
Answer:
$42.88
Step-by-step explanation:
We can set up a cross product fraction ratio to find how much 21 pounds of turkey costs.
[tex]\frac{10}{20.42} = \frac{21}{x}[/tex]
Let's apply the cross multiplication property.
[tex]20.42\cdot21=428.82[/tex]
Now we divide this by 10.
[tex]428.82\div10=42.882[/tex]
This simplifies down to [tex]42.88[/tex].
Hope this helped!
Which parent function is represented by the graph?
A. The quadratic parent function
B. The absolute value parent function
C. An exponential parent function
D. The linear parent function
Answer:
D. The linear parent function
Step-by-step explanation:
Linear functions are always characterized by a straight line graph with or without an intercept on the vertical or horizontal axis. A linear function usually has an independent variable and a dependent variable. The independent variable is commonly depicted as x while the dependent variable is y.
Thus a linear equation is an equation of the type y=ax where a is a constant term. The equation of a straight line graph his y=mx +c, where;
m= gradient of the straight line graph
x= the independent variable
y= the dependent variable
c= the vertical intercept
Answer:
The linear parent function :)
Step-by-step explanation:
Determine the margin of error in estimating the population mean, μ . A sample of 74 college students yields a mean annual income of Assuming that , find the margin of error in estimating μ at the 99% level of confidence.
Answer:
$253
Step-by-step explanation:
Margin of error is the critical value times the standard error.
MoE = z × σ/√n
At 99% confidence, z = 2.576.
MoE = 2.576 × 844/√74
MoE = 253
Please help, I don’t need an explanation, just the answer.
Answer:
x=2 y=4
Step-by-step explanation:
Ricardo has a square hot tub. He wants to build a square pool next to it that is a dilation of the hot tub using a scale factor of 5. Point Q is the center of dilation. Square A B C D is dilated to created square A prime B prime C prime D prime. The length of B prime C prime is 24 feet. If the pool is to be 24 ft on each side, what is the length of one side of the hot tub? 4 ft 4.8 ft 6 ft 7.2 ft
Answer:
[tex]\boxed{Side \ Length \ of \ hot \ tub = 4.8\ ft.}[/tex]
Step-by-step explanation:
Scale Factor = 5
Also,
B'C' = 24 feet
Since both are squares so both have all sides equal.
Sqaure A'B'C'D' is dilated by a scale factor of 5
So,
AB = BC = CD = DA = 24/5 = 4.8 ft.
The length of one side of the hot tub is 4.8 feet and this can be determined by using the concept of dilation.
Given :
Ricardo has a square hot tub. He wants to build a square pool next to it that is a dilation of the hot tub using a scale factor of 5.Square A B C D is dilated to create square A prime B prime C prime D prime. The length of B prime C prime is 24 feet.The following steps can be used in order to determine the length of one side of the hot tub:
Step 1 - According to the given data, the dilation factor is 5.
Step 2 - So, after the dilation by a factor of 'a' the length of the side be 'b' becomes 'ab'.
Step 3 - So, according to the given data, the length of B prime C prime is 24 feet. Therefore, after the dilation by a factor of 5, the length of the segment BC becomes:
[tex]\rm =\dfrac{24}{5}=4.8\;feet[/tex]
So, the length of one side of the hot tub is 4.8 feet. Therefore, the correct option is b).
For more information, refer to the link given below:
https://brainly.com/question/2856466
State the slope of the line.
1
0
Undefined
-4
Answer:
Hey there!
The slope of a vertical line is undefined! The run is zero, and as we know, dividing by zero is undefined!
Hope this helps :)
Answer:
Undefined
Step-by-step explanation:
A vertical line has an undefined slope or there is no slope of the line.
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 11 ft high
Answer:
0.0526ft/minStep-by-step explanation:
Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.
Volume of a cone V = πr²h/3
If the diameter and the height are equal, then r = h
V = πh²h/3
V = πh³/3
If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min
Using chain rule to get the expression for dV/dt;
dV/dt = dV/dh * dh/dt
From the formula above, dV/dh = 3πh²/3
dV/dh = πh²
dV/dt = πh²dh/dt
20 = πh²dh/dt
To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.
20 = π(11)²dh/dt
20 = 121πdh/dt
dh/dt = 20/121π
dh/dt = 20/380.133
dh/dt = 0.0526ft/min
This means that the height of the pile is increasing at 0.0526ft/min