Answer:
the width of the rectangle is 24 centimeters and the length is 31 centimeters.
Step-by-step explanation:
We first have to write an equation for this, but let's just recall that the area of a rectangle is equal to the length times the width. A=L×W.
A is the area
L is the length
W is the width.
So, for our equation we can start out by putting that 744= ? times ?.
So, we are given that the length is 7 more than the width. We are going to have to translate that to represent the length.
We need a variable. Let's use the letter "W," the width of the rectangle.
W=W.
The length is 7 more than the width, so it is L=W+7.
Length represents the W+7
Width represents W.
Now, we can complete our equation.
744=W(W+7).
Simplify the expression.
744=[tex]W^{2}[/tex]+7W.
Alright, you may be thinking on how we are going to solve this problem. This equation correlates with quadratic functions.
Let's complete the square.
In a quadratic function, the standard from is y=[tex]ax^{2} +bx+c[/tex].
We need to find the c value.
We can do this by applying a formula. The formula states that c= b/2 and the whole thing squared. In other words, [tex](\frac{b}{2} )^{2}[/tex].
In this case, the b value is 7.
square 7, which is 49 and square 2 which is 4.
Now, the c value is 49/4.
We have now just created a perfect square trinomial.
Not only do we add 49/4 to W squared plus 7W, we also add 49/4 to 744.
744 plus 49/4 is 756/25.
Now, we have [tex]W^{2}+7w+\frac{49}{4} = 756.25[/tex]
Change W squared plus 7w plus 49/4 to a binomial squared.
Just take the square root of the a value, W, and 49/4 for c. the square root of W squared is W. the square root of 49/4 is 7/2.
Those values are to the power of 2.
In other words, [tex](W+\frac{7}{2})^{2} =756.25[/tex]
To isolate for W, take the square root of both sides.The square root of W plus 7/2 squared is just W+7/2. The square root of 756.25 is 27.5
There are two solutions for W because square roots be positive or negative, but we are dealing with positive since negative doesn't make sense with the context of the problem.
We have [tex]W+3.5 or \frac{7}{2}=27.5[/tex]
Isolate for W by subtracting both sides by 3.5 You get to W=24.
Therefore, the width of the rectangle is 24 centimeters.
Alright, we found the width. We now need to find the length. The problem stated that the rectangle was 7 more than the width. So, 24+7=31. Therefore, the length of the rectangle is 31 centimeters.
L=31cm
W=24cm.
I hope this was helpful! I wish you have an amazing day!
Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won: 25-34, 35-44, 45-54, 55-64, 65-74, 75-84, 85-94
Frequency: 29, 34, 16, 3, 5, 1, 2
Step-by-step explanation:
kindly find attached detailed information of the remaining information as requested for your reference
1. The lower class limit is the left number in the age column
i.e in the 25-34 the lower class limit is 25
2. The upper class limit is the right number in the age column
i.e in the 25-34 the lower class limit is 34
3. The class width is the difference between the class boundaries of a single class
class width = 34.5-24.5= 10
4. The number of individuals is= 29+34+16+3+5+1+2= 90
What is the size of the matrix resulting from...
Answer:
1 x 3
Step-by-step explanation:
The order of the first matrix is 1 × 3
The order of the second matrix is 3 × 3
that is (1 × 3 ) × (3 × 3 )
The bold values at the ends of the orders give the order of the product, that is
1 × 3
Suppose a college student pays $750 for tuition fees. However, she also has to pay $300 for her textbooks (ouch!). What percent of her total education costs does she pay for her books?
Answer:
Total costs = $700 + $300 = $1000.
$300 / $1000 = 0.3 = 3%
Step-by-step explanation:
Suppose a ball is thrown upward to a height of h 0 meters. After each bounce, the ball rebounds to a fraction r of its previous height. Let h Subscript n be the height after the nth bounce. Consider the following values of h 0 and r. Complete parts (a) and (b) below. h0=30, r=0.25
a- find the first 4 terms of the sequence of heights(hn)
b- find a general expression for the nth term of the sequence (hn)
Answer:
A)1st term:45
2nd term:48.75
3rd term:49.6875
4th term:49.921875
B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)
Step-by-step explanation:
We are given;
h₀ = Initial height of the ball = 30
r = Rebound fraction = 0.25
a) The arithmetic sequence of bouncing balls is given by the following;
Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)
The first term of the sequence is;
S₁ = h₀ + 2h₀r¹
S₁ = 30 + (2 × 30 × 0.25)
S₁ = 45
The second term of the sequence is;
S₂ = h₀ + 2h₀(r¹+r²)
S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75
The third term of the sequence is;
S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875
S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)
S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875
B) The general expression for the nth term of the sequence is;
Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)
McKenzie has a bag contains six red marbles four blue marbles and 14 yellow marbles if she chooses one marble from the bag what is the probability that the marble is not yellow
Answer:
5/12
Step-by-step explanation:
Total number of marbles in the bag
6red+ 4blue + 14 yellow = 24 marbles
Not yellow marbles = 10 marbles
P ( not yellow ) = number of not yellow marbles / total marbles
=10/24
= 5/12
Answer:
5/12
Step-by-step explanation:
6 red marbles
4 blue marbles
14 yellow marbles
total marbles = 6 + 4 + 14 = 24 marbles
24 - 14 = 10 marbles
10 marbles are not yellow.
P(not yellow) = 10/24 = 5/12
5/9 + (1/9 + 4/5)=×
Answer:
22/15I hope it helps :)Step-by-step explanation:
[tex]\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)=x\\x=\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\x=\frac{5}{9}+\frac{1}{9}+\frac{4}{5}\\\mathrm{Compute\:a\:number\:comprised\:of\:factors\\\:that\:appear\:in\:at\:least\:one\:of\:the\:following:}\\9,\:9,\:5\\=3\times \:3\times\:5\\\mathrm{Multiply\:the\:numbers:}\:3\times \:3\times \:5=45\\\frac{5}{9}=\frac{5\times \:5}{9\times \:5}=\frac{25}{45}\\[/tex]
[tex]\frac{1}{9}=\frac{1\times \:5}{9\times \:5}=\frac{5}{45}\\\\\frac{4}{5}=\frac{4\times \:9}{5\times \:9}=\frac{36}{45}\\\\x=\frac{25}{45}+\frac{5}{45}+\frac{36}{45}\\\\\mathrm{Since\:the\:denominators\:are\:equal,\\combine\:the\:fractions}:\\\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\x=\frac{25+5+36}{45}\\\\x=\frac{66}{45}\\\\x=\frac{22}{15}[/tex]
P(x)=2x^5+9x^4+9x^3+3x^2+7x-6;x=i,-2
Answer:
The value of the polynomial function at P(1) and P(-2) is 24 and 0 respectively.
Step-by-step explanation:
We are given with the following polynomial function below;
[tex]\text{P}(x) = 2x^{5} +9x^{4} +9x^{3} +3x^{2}+7x-6[/tex]
Now, we have to calculate the value of P(x) at x = 1 and x = -2.
For this, we will substitute the value of x in the given polynomial and find it's value.
At x = 1;
[tex]\text{P}(1) = 2(1)^{5} +9(1)^{4} +9(1)^{3} +3(1)^{2}+7(1)-6[/tex]
[tex]\text{P}(1) = (2\times 1) +(9\times 1)+(9 \times 1)+(3\times 1)+(7\times 1)-6[/tex]
[tex]\text{P}(1) = 2 +9+9+3+7-6[/tex]
P(1) = 30 - 6
P(1) = 24
At x = -2;
[tex]\text{P}(-2) = 2(-2)^{5} +9(-2)^{4} +9(-2)^{3} +3(-2)^{2}+7(-2)-6[/tex]
[tex]\text{P}(-2) = (2\times -32) +(9\times 16)+(9 \times -8)+(3\times 4)+(7\times -2)-6[/tex]
[tex]\text{P}(-2) = -64 +144-72+12-14-6[/tex]
P(-2) = 156 - 156
P(-2) = 0
Hence, the value of the polynomial function at P(1) and P(-2) is 24 and 0 respectively.
What is the measure of ABC in the figure below?
C
о
A4 20
B
A
А. 420
В. 48°
С. 84°
ОО ОО ОО
D. 30°
E. 21°
O E Cannot be determined
Answer:
i think its 84...
Step-by-step explanation:
not to sure
Each marble bag sold by Carmen's Marble Company contains 3 purple marbles for every 4 blue marbles. If a bag has 28 blue marbles, how many purple marbles does it contain?
Answer:
21 purple marbles
Step-by-step explanation:
my explanation is i looked at it like a ratio so ¾= x/28
then i took 28 ÷ 4 which equals 7, then i took 7 and multiplied it by 3 which gave me 21, so the answer is 21 purple marbles
Lettets a, b, c, and d are angle measures Which should equal 105 to prove false g
Answer:
a equals 105°
Step-by-step explanation:
angles in a straight line add up to 180°
a+75=180
a=180-75
a=105°
42.
You were given the four numbers below and were asked to find the sum
of the first two numbers, the difference between the last two numbers,
the quotient when the sum is divided by the difference and the product
when the quotient is multiplied by 8. What is the final answer?
6458 2994
7013
6945
Answer:
1112
Step-by-step explanation:
6458 + 2994 = 9452
7013 - 6945 = 68
9452/68 = 139
139 * 8 = 1112
how long would it take you to walk from Tucson Arizona to San Clemente California
Answer:
It would take around 152 hours or 468 miles.Step-by-step explanation:
If you walk from Tucson Arizona (Saguaro National Park) to San Clemente California (Dana point), it would take around 152 hours, or 468 miles, if you walking speed is as the average person which is 3 to 4 miles per hour.
Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
Answer:
The answer is 4 + √15 .
Step-by-step explanation:
You have to get rid of surds in the denorminator by multiplying it with the opposite sign :
[tex] \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } [/tex]
[tex] = \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } [/tex]
[tex] = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} } [/tex]
[tex] = \frac{5 + 2 \sqrt{15} + 3 }{5 - 3} [/tex]
[tex] = \frac{8 + 2 \sqrt{15} }{2} [/tex]
[tex] = 4 + \sqrt{15} [/tex]
t-7= -1 what is t in this equation
Answer:
t=6
Step-by-step explanation:
t-7=-1
6-7=-1
t - 7 = -1
t = 7 -1
t = 6
t is equals 6
Rita ha decidido emprender un negocio de ventas de productos de protección personal, para lo cual tiene que inventir 1/3 de su dinero en mascarillas, 4/15 en guantes, 1/10 en protección facial y el resto en alcohol. ¿Que fracciónde dinero se invierte en alcohol?
Answer:
3/10
Step-by-step explanation:
Subtract the sum of 1/3, 4/15 and 1/10 from 1:
10/30 + 8/30 + 3/30 = 21/30, or 7/10
Then: 1 - 7/10 = 3/10
22,403 Check:
- 8,675
how i do this
Answer:
Hello!! :) The answer to your question is 13,728
Steps will be below.
Step-by-step explanation:
So we will subtract 22,403 and 8,675.
When we do that we will get 13,728
To check your answer we have to do the opposite of subtracting which will be adding.
This is how we check our work: the answer we got was 13,728...we have to take that answer and add it to 8,675 which will give us 22,403
(Both of the numbers are from the question)
At the bottom I attached a picture of how I did the subtracting and how I checked my work.
Sorry for my handwriting......if you can’t understand my handwriting, I attached another picture which is more clearer.
ANSWER TO YOUR QUESTION: 13,728
Brainliest would be appreciated! Thank you :3
Hope this helps! :)
Answer:
The answer is 13,728
Step-by-step explanation:
Check your work with addition.
Which statement describes this system of equations? 9x – 6y = 15, 3x – 2y = 5 The equations in the system are equivalent equations. There is no solution to the system of equations. The system of equations has one solution at (3, 2). The system of equations has one solution at (5, 5).
Answer:
There is no solution to the systems of equation.
Step-by-step explanation:
Graph the system by using y=mx+b
Both systems are y=2/5x+5/2.
Answer:
that guy is wrong. its the first option.
Step-by-step explanation:
i just took it
2 + t = -4 what is the t
Answer:
- 6Step-by-step explanation:
[tex]2 + t = - 4[/tex]
Move constant to R.H.S and change its sign
[tex]t = - 4 - 2[/tex]
Calculate
[tex]t = - 6[/tex]
Hope this helps..
Best regards!!
Answer:
t = - 6Step-by-step explanation:
[tex]2 + t = -4 \\Collect -like-terms\\t = -4-2\\t=-6[/tex]
The Ambell Company uses batteries from two different manufacturers. Historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours. Only 75% of the batteries from manufacturer 2 last for over 40 hours. A battery in a critical tool fails at 32 hours. What is the probability it was from manufacturer 2?
Answer:
The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625
Step-by-step explanation:
Given that:
60% of the batteries are from manufacturer 1
90% of these batteries last for over 40 hours
Let the number of the battery duration be n = 0.90
Therefore n' = 1 - 0.90 = 0.10
Let p = manufacturer 1 and q = manufacturer 2
q = 1 - p
q = 1 = 0.6
q = 0.4
Thus ; 40% of the batteries are from manufacturer 2
However;
Only 75% of the batteries from manufacturer 2 last for over 40 hours.
Let number of battery duration be m = 0.75
Therefore ; m' = 1 - 0.75 = 0.25
A battery in a critical tool fails at 32 hours.
Thus; the that the battery in a critical tool fails at 32 hours was from manufacturer 2 is:
[tex]= \dfrac{q \times m' }{ p \times n' + q \times m' }[/tex]
[tex]= \dfrac{0.4 \times0.25 }{ (0.6 \times 0.1) + (0.4 \times 0.25 ) }[/tex]
[tex]=\dfrac{0.1}{0.06+ 0.1}[/tex]
[tex]=\dfrac{0.1}{0.16}[/tex]
= 0.625
The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625
The probability that the battery was from manufacturer 2 is 62.5%.
Since the Ambell Company uses batteries from two different manufacturers, and historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours, while only 75% of the batteries from manufacturer 2 last for over 40 hours, if a battery in a critical tool fails at 32 hours, to determine what is the probability it was from manufacturer 2 the following calculation must be performed:
You must establish the percentage of failure of the total batteries, and determine what percentage of failures corresponds to each manufacturer. Manufacturer 1 = 60 x 0.1 = 6 Manufacturer 2 = 40 x 0.25 = 10 Total = 16 16 = 100 10 = X 100 x 10/16 = X 62.5 = X
Therefore, the probability that the battery was from manufacturer 2 is 62.5%.
Learn more in https://brainly.com/question/14461509
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is found that 4% of the legitimate users originate calls from two or more metropolitan areas in a single day. However, 30% of fraudulent users originate calls from two or more metropolitan areas in a single day. The proportion of fraudulent users is 0.0130%. If the same user originates calls from two or more metropolitan areas in a single day, what is the probability that the user is fraudulent
Answer:
0.0009741
Step-by-step explanation:
The approach to solve this question is by the use of Baye’s theorem in conditional probability
Please check attachment for complete solution and explanation
Answer:
0.000974
Step-by-step explanation:
Let assume that;
P(Q) is the probability that the same user originated calls from two or more metropolitan areas in a single day
Also; Let consider M to be the event that denotes the legitimate users and N to be the event that denote the fraudulent users .
Then;
P(M) = 0.00013
P(N) = 1 - P(M)
P(N) = 1 - 0.00013
P(N) = 0.99987
P(Q|M) = 0.3
P(Q|N) = 0.4
The probability the same users originates calls from two or more metropolitan areas in a single day is calculated as follows:
P(Q) = (P(M) P(Q|M) ) + ( P(N) P(Q|N) )
P(Q) = ( 0.00013 × 0.3 ) + (0.99987 × 0.04 )
P(Q) = 0.000039 + 0.0399948
P(Q) = 0.0400338
However; The probability that the users is fraudulent given that the same users originates calls from two or more metropolitan areas in a single day is,
[tex]P(M|Q) = \dfrac{P(M) P(Q|M)}{(P(M) \ P(Q|M) ) + ((P(N) \ P(Q|N)) } \\ \\ \\ P(M|Q) = \dfrac{0.0001 \times 0.3}{0.0400338} \\ \\ \\ P(M|Q) = \dfrac{0.000039}{0.0400338} \\ \\ \\ \mathbf{P(M|Q) = 0.000974}[/tex]
Consider the recursive function,
f(1) = 2
f(n) = 5•f(n − 1), for n > 2
Answer:
yes?
Step-by-step explanation:
??? can u say exactly what the question is please? thank you
Answer:
the question is:
Which statement is true?
A. The value of F(6) is 2 times the value of f(3).
B. The value of f(6) is 15 times the value of f(3).
C. The value of f(6) is 1/125 times the value of f(3).
D. The value of f(6) is 125 times the value of f(3).
Step-by-step explanation:
comment the answer below for everyone please.
In randomized, double-blind clinical trials of Prevnar, infants were randomly divided into two groups. Subjects in group 1 received Prevnar, while subjects in group 2 received a control vaccine. Aft er the second dose, 137 of 452 subjects in the experimental group (group 1) experienced drowsiness as a side effect. After the second dose, 31 of 99 subjects in the control group (group 2) experienced drowsiness as a side effect. Does the evidence suggest that a lower proportion of subjects in group 1 experienced drowsiness as a side effect than subjects in group 2 at the αα=0.05 level of significance?
Answer:
Step-by-step explanation:
From the summary of the given data;
After the second dose, 137 of 452 subjects in the experimental group (group 1) experienced drowsiness as a side effect.
Let consider [tex]p_1[/tex] to be the probability of those that experience the drowsiness in group 1
[tex]p_1[/tex] = [tex]\dfrac{137}{452}[/tex]
[tex]p_1[/tex] = 0.3031
After the second dose, 31 of 99 subjects in the control group (group 2) experienced drowsiness as a side effect.
Let consider [tex]p_2[/tex] to be the probability of those that experience the drowsiness in group 1
[tex]p_2[/tex] = [tex]\dfrac{31}{99}[/tex]
[tex]p_2[/tex] = 0.3131
The objective is to be able to determine if the evidence suggest that a lower proportion of subjects in group 1 experienced drowsiness as a side effect than subjects in group 2 at the α=0.05 level of significance.
In order to do that; we have to state the null and alternative hypothesis; carry out our test statistics and make conclusion based on it.
So; the null and the alternative hypothesis can be computed as:
[tex]H_o :p_1 =p_2[/tex]
[tex]H_a= p_1<p_2[/tex]
The test statistics is computed as follows:
[tex]Z = \dfrac{p_1-p_2}{\sqrt{p_1 *\dfrac{1-p_1}{n_1} +p_2 *\dfrac{1-p_2}{n_2}} }[/tex]
[tex]Z = \dfrac{0.3031-0.3131}{\sqrt{0.3031 *\dfrac{1-0.3031}{452} +0.3131 *\dfrac{1-0.3131}{99}} }[/tex]
[tex]Z = \dfrac{-0.01}{\sqrt{0.3031 *\dfrac{0.6969}{452} +0.3131 *\dfrac{0.6869}{99}} }[/tex]
[tex]Z = \dfrac{-0.01}{\sqrt{0.3031 *0.0015418 +0.3131 *0.0069384} }[/tex]
[tex]Z = \dfrac{-0.01}{\sqrt{4.6731958*10^{-4}+0.00217241304} }[/tex]
[tex]Z = \dfrac{-0.01}{0.051378 }[/tex]
Z = - 0.1946
At the level of significance ∝ = 0.05
From the standard normal table;
the critical value for Z(0.05) = -1.645
Decision Rule: Reject the null hypothesis if Z-value is lesser than the critical value.
Conclusion: We do not reject the null hypothesis because the Z value is greater than the critical value. Therefore, we cannot conclude that a lower proportion of subjects in group 1 experienced drowsiness as a side effect than subjects in group 2
Select the correct answer.
Answer:
C. 5 × 3
Step-by-step explanation:
The order of a matrix is the number of rows and columns that a matrix has. Rows are listed first and columns are listed second. The matrix has 5 rows going across horizontally and 3 columns going down vertically.
So, the order of the matrix is 5 × 3.
Hope that helps.
A college financial advisor wants to estimate the mean cost of textbooks per quarter for students at the college. For the estimate to be useful, it should have a margin of error of 20 dollars or less. The standard deviation of prices is estimated to be around 100 dollars. How large of a sample size needs to be used to be 95% confident, with the given margin of error?
Answer:
minimum sample size = 97
Step-by-step explanation:
Margin of error = 20
standard deviation = 100
sample size = n
standard error = 100/sqrt(n)
confidence level, alpha = 95%
Using the standard rule for 95% confidence
standard error <= sample mean [tex]\pm[/tex] 1.96 standard error, or
20 <= 1.96*100 / sqrt(n)
n >= (1.96*100/20)^2 = 9.8^2 = 96.04
=>
n >= 97
Which describes the graph in words?
A. All numbers less than -10 and less than or equal to 8.
B. All numbers greater than -10 and less than 8
C. All numbers greater than or equal to -10 and less than or equal to 8
D. All numbers greater than -10 and less than or equal to 8.
D. All numbers greater than -10 and less than or equal to 8
I need the answer quick I have a time limit ( I only get an hour to complete the assignment heh )
Answer:
C (the third table, from the second picture).
Step-by-step explanation:
First, we need to find the slope of the graph.
Two conspicuous points are (0, -3) and (2, 1).
The slope is: (1 - -3) / (2 - 0) = (1 + 3) / 2 = 4 / 2 = 2.
A: In the table, the y-values increase by 2, while the x-values increase by 4. 2 / 4 = 1 / 2 = 0.5. The slope is not the same as the graph.
B: In the table, the y-values decrease by 2, while the x-values increase by 4. -2 / 4 = -1 / 2 = -0.5. The slope is not the same as the graph.
C: In the table, the y-values increase by 4, while the x-values increase by 2. 4 / 2 = 2 / 1 = 2. The slope is the same as the graph, so C is your answer.
D: In the table, the y-values decrease by 4, while the x-values increase by 2. -4 / 2 = -2 / 1 = -2. The slope is not the same as the graph.
Hope this helps!
EXAMPLE 2 (a) Find y' if x3 + y3 = 18xy. (b) Find the tangent to the folium of Descartes x3 + y3 = 18xy at the point (9, 9). (c) At what point in the first quadrant is the tangent line horizontal?
(a) Via implicit differentiation, we get
[tex]x^3+y^3=18xy\implies 3x^2+3y^2y'=18y+18xy'[/tex]
Solve for [tex]y'[/tex]:
[tex]y'=\dfrac{18y-3x^2}{3y^2-18x}=\dfrac{6y-x^2}{y^2-6x}[/tex]
(b) Find the slope of the tangent line at (9, 9) by plugging in x = y = 9 into the equation above:
[tex]y'=\dfrac{6\cdot9-9^2}{9^2-6\cdot9}=-1[/tex]
Use the point-slope formula to find the equation of the line:
[tex]y-9=-1(x-9)\implies y=-x+18[/tex]
(c) The tangent line is horizontal when its slope is 0, so solve [tex]y'=0[/tex]:
[tex]\dfrac{6y-x^2}{y^2-6x}=0\implies6y-x^2=0\implies y=\dfrac{x^2}6[/tex]
Now substitute y in the equation for the folium to solve for x :
[tex]x^3+\left(\dfrac{x^2}6\right)^3=18x\cdot\dfrac{x^2}6[/tex]
[tex]x^3+\dfrac{x^6}{6^3}=3x^3[/tex]
[tex]\dfrac{x^6}{6^3}-2x^3=0[/tex]
[tex]x^3\left(\left(\dfrac x6\right)^3-2\right)=0[/tex]
[tex]\implies x=0\text{ or }x=6\sqrt[3]{2}[/tex]
x = 0 corresponds to y = 0 (plug x = 0 into the folium equation to see why), i.e. the origin. If you don't consider the origin to belong to the first quadrant, then we only keep
[tex]x=6\sqrt[3]{2}\implies y=6\sqrt[3]{4}[/tex]
A bag of marbles contains 4 green marbles, 3 blue marbles, 2 red marbles, and 5 yellow marbles. How many total possible outcomes are there when choosing a marble from the bag?
Answer:
its 14/C
Step-by-step explanation:
i got i right on edg U^U
Answer:
16
Step-by-step explanation:
i did edge test yea dont be imma fake :***
Help ASAP!!!!
Identify the correct trigonometry formula to use to solve for x.
Sin (angle) = opposite leg / hypotenuse
Sin(62) = 18/x
The answer is the third choice.
find the area of the shaded region
Answer:
27 in²
Step-by-step explanation:
area of triangle (whole) = 1/2 x base x height
= 1/2 x 10 x 6
= 30 in²
area of small triangle = 1/2 x base x height
= 1/2 x 3 x 2
= 3 in²
area of shaded region = 30 in² - 3 in²
= 27 in²