The perimeter of a rectangle is 60 cm. The ratio of length to width is 3:2. Find the length and width of the rectangle.

Answer:

Hey there!

6x+6=7x-6

6=x-6

12=x

x=12

Hope this helps :)

Answer:

The volume is

Step-by-step explanation:

Volume of a sphere is given by

[tex]V = \frac{4}{3} \pi {r}^{ 3} [/tex]

where r is the radius

π = 3.14

From the question we were given the diameter and

radius = diameter/ 2

diameter = 2 feet

radius = 2/2 = 1 feet

So the volume of the sphere is

[tex]V = \frac{4}{3} (3.14)(1) ^{3} [/tex]

[tex] = \frac{4}{3} \times 3.14[/tex]

V = 4.186

We have the final answer as

V = 4 ft³ to the nearest hundredth

Hope this helps you

Answer:

I believe the median is 6.5

Step-by-step explanation:

Answer:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

Step-by-step explanation:

Hope you understand

Answer:

0.60

Step-by-step explanation:

find the probability it is a 2:

0.40 / 1 = 0.4 or 40%

find the probability it isn't a 2:

1 - 0.4 = 0.6

Answer:

A. 0.60

Step-by-step explanation:

I did geometry last year. My teacher assigned it to us.

Hope this helps :)

The average cost of weekly groceries is $124.50."  The statistical measurement are they most likely claiming is Mean

The correct option is (B)

The arithmetic mean of a given data is the sum of all observations divided by the number of observations.

For example, a cricketer's scores in five ODI matches are as follows: 12, 34, 45, 50, 24. To find his average score in a match, we calculate the arithmetic mean of data using the mean formula:

Mean = Sum of all observations/Number of observations

The value of the middlemost observation, obtained after arranging the data in ascending or descending order, is called the median of the data.

For example, consider the data: 4, 4, 6, 3, 2. Let's arrange this data in ascending order: 2, 3, 4, 4, 6. There are 5 observations. Thus, median = middle value i.e. 4.

The value which appears most often in the given data i.e. the observation with the highest frequency is called a mode of data.

As per the situation we have given average cost of groceries.

The mean is also the average sum of data divided by total number of data.

Hence, The statistical measurement is Mean.

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Answer:

[tex]\sqrt[5]{x^7}[/tex]

or (x ^ 1/5) ^7

or ([tex]\sqrt[5]{x}[/tex])^7

Step-by-step explanation:

x ^ 1.4

Rewriting the decimal as an improper fraction

x ^ 14/10

x ^ 7/5

The top is the power and the bottom is the root

[tex]\sqrt[5]{x^7}[/tex]

or (x ^ 1/5) ^7

or ([tex]\sqrt[5]{x}[/tex])^7

======================================================

Work Shown:

f ''' (x) = cos(x) .... third derivative

f '' (x) = sin(x)+C ... integrate both sides to get second derivative. Don't forget the +C at the end

We are given f '' (0) = 9, so we'll make use of this to find C

f '' (x) = sin(x)+C

f '' (0) = sin(0)+C

9 = sin(0) + C

9 = 0 + C

9 = C

C = 9

Therefore, f '' (x) = sin(x)+C turns into f '' (x) = sin(x)+9

------------

Integrate both sides of the second derivative to get the first derivative function

f '' (x) = sin(x)+9

f ' (x) = -cos(x)+9x+D ... D is some constant

Make use of f ' (0) = 4 to find D

f ' (x) = -cos(x)+9x+D

f ' (0) = -cos(0)+9(0)+D

4 = -1 + 0 + D

D = 5

So we have f ' (x) = -cos(x)+9x+D turn into f ' (x) = -cos(x)+9x+5

------------

Lastly, apply another round of integrals and substitutions to find the f(x) function. We'll use f(0) = 8.

f ' (x) = -cos(x)+9x+5

f(x) = -sin(x) + (9/2)x^2 + 5x + E .... E is some constant

f(0) = -sin(0) + (9/2)(0)^2 + 5(0) + E

8 = 0 + 0 + 0 = E

E = 8

------------

We have

f(x) = -sin(x) + (9/2)x^2 + 5x + E

turn into

f(x) = -sin(x) + (9/2)x^2 + 5x + 8

Answer:

C. The interquartile range is 55

Step-by-step explanation:

When you want to find the interquartile range you look at the box plot to see that it is everything from the upper interquartile range to the lower interquartile range is the interquartile range. So from 40 to 65. So there for the answer C. is incorrect.  

Answer:

A.

Step-by-step explanation:

Answer:

[tex]h=30[/tex]

Step-by-step explanation:

Volume of a cone=1540[tex]cm^{3}[/tex], Radius=7cm.

The height of a cone=h

When we need to find the height of a cone, we can use the formula of the volume of a cone, which is [tex]\frac{1}{3} \pi r^{2} h[/tex] to find the height of a cone.

[tex]1540cm^{3} =\frac{1}{3}\pi r^{2} h[/tex]

Put the pi value=22/7 and the value of radius which is 7 cm into the formula.

[tex]1540cm^{3}=\frac{1}{3}*\frac{22}{7} 7^{2}h[/tex]

[tex]1540cm^{3} =\frac{154}{3}h[/tex]

Move [tex]\frac{154}{3}[/tex] to another side. 1540 divided by  [tex]\frac{154}{3}[/tex] to calculate what is the value of h, h is the height of a cone. Like this.

[tex]\frac{1540cm^{3} }{\frac{154}{3} } =h[/tex]

[tex]30=h[/tex]

Rearrange the h.

[tex]h=30[/tex]

I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!

Answer:

The height of the cone is h = 30 cm.

Step-by-step explanation:

The formula for a cone is:

[tex] \\ V = \frac{1}{3}*\pi*r^2*h[/tex]

We have (without using units) and using pi = 22/7:

[tex] \\ 1540 = \frac{1}{3}*\frac{22}{7}*(7)^2*h[/tex]

Which is equals to:

[tex] \\ 1540 = \frac{1}{3}*\frac{22}{7}*(7)*h[/tex]

[tex] \\ 1540 = \frac{1}{3}*22*7*h[/tex]

Well, we have to solve the equation for h:

[tex] \\ \frac{1540*3}{22*7} = h[/tex]

[tex] \\ 30 = h[/tex]

Therefore, the height of the cone is 30 cm.

Answer:

a

Step-by-step explanation:

Since the graph intersects the x-axis at 2 points, it has 2 solutions which means that the discriminant is greater than 0. The only option that satisfies this is 10.

Answer:

10  option a)

Step-by-step explanation:

The discriminant has to be a number greater than zero, since we clearly see two solutions (crossings of the x axis) of the curve. So, the only option larger than zero among the possible answers is 10 (option a)

Answer:

a. 30 meters per second

b. -10 meters per second

Step-by-step explanation:

a. Average rate of change for the height from 0 to 6.6 secs can be calculated using the formula, [tex] m = \frac{H(b) - H(a)}{b - a} [/tex]

Thus,

Where,

[tex] a = 0, H(0) = 0 [/tex]

[tex] b = 6.6, H(6.6) = 198 [/tex]

Plug in the values into the formula:

[tex] m = \frac{198 - 0}{6.6 - 0} [/tex]

[tex] m = \frac{198}{6.6} [/tex]

[tex] m = 30 [/tex]

b. Average rate of change for the height from 8.8 to 13.2 secs = tex] m = \frac{H(b) - H(a)}{b - a} [/tex]

Where,

[tex] a = 8.8, H(8.8) = 44 [/tex]

[tex] b = 13.2, H(13.2) = 0 [/tex]

Plug in the values:

[tex] m = \frac{0 - 44}{13.2 - 8.8} [/tex]

[tex] m = \frac{-44}{4.4} [/tex]

[tex] m = -10 [/tex]

Answer:

[tex]\boxed{\±\sqrt{x+4}}[/tex]

Step-by-step explanation:

The inverse of a function is the reverse of the function.

[tex]f(x)=x^2 -4[/tex]

[tex]y=x^2-4[/tex]

Switch variables.

[tex]x=y^2-4[/tex]

Make y as subject.

Add 4 to both sides.

[tex]x+4=y^2[/tex]

Take the square root on both sides.

[tex]\±\sqrt{x+4} =y[/tex]

Answer:

[tex]f^{-1}[/tex] = ± [tex]\sqrt{x+4}[/tex]

Step-by-step explanation:

[tex]f(x) = x^2-4[/tex]

Replace f(x) by y

[tex]y = x^2-4[/tex]

Exchange x and y

[tex]x = y^2-4[/tex]

Solve for y

[tex]x = y^2-4\\[/tex]

Adding 4 to both sides

[tex]y ^2 = x+4[/tex]

Taking sqrt on both sides

y = ±[tex]\sqrt{x+4}[/tex]

Replacing y by [tex]f^{-1}[/tex]

[tex]f^{-1}[/tex] = ± [tex]\sqrt{x+4}[/tex]

Answer:

(a) The point estimate for the population mean travel tax is $ 83.36.

(b) The lower bound is $73.70 and the upper bound is $93.02 One can be [95]% confident that the mean travel tax for all cities is between these values.

(c) The researcher could decrease the level of confidence.

Step-by-step explanation:

We are given that a normal probability plot suggests the data could come from a population that is normally distributed.

X: 68.87, 78.25, 70.44, 84.67, 79.79, 86.33, 100.24, 98.26.

(a) A point estimate for the population mean travel tax is the sample mean of the data. i.e;

      Point estimate, [tex]\bar X[/tex] =  [tex]\frac{\sum X}{n}[/tex]

                                     =  [tex]\frac{68.87+ 78.25+ 70.44+ 84.67+ 79.79+ 86.33+ 100.24+ 98.26}{8}[/tex]

                                     =  [tex]\frac{666.85}{8}[/tex]  = $83.36

So, the point estimate for the population mean travel tax is $ 83.36.

(b) Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean travel tax = $83.36

             s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]  = $11.55

             n = sample size = 8

             [tex]\mu[/tex] = population mean travel tax

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.365 < N(0,1) < 2.365) = 0.95  {As the critical value of t at 7 degrees of

                                                 freedom are -2.365 & 2.365 with P = 2.5%}  

P(-2.365 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.365) = 0.95

P( [tex]-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.365 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.365 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                        = [ [tex]\$83.36-2.365 \times {\frac{\$11.55}{\sqrt{8} } }[/tex] , [tex]\$83.36+2.365 \times {\frac{\$11.55}{\sqrt{8} } }[/tex] ]

                        = [$73.70, $93.02]

Therefore, a 95% confidence interval for the population average debt load of graduating students with a bachelor's degree is [$73.70, $93.02].

The lower bound is $73.70 and the upper bound is $93.02 One can be [95]% confident that the mean travel tax for all cities is between these values.

(c) The researcher could decrease the level of confidence who wants to increase the precision of the interval but does not have access to additional data.

Answer:

Step-by-step explanation:

[tex]tan^{-1} (\frac{\sqrt{3} }{3} )=x\\tan x=\frac{\sqrt{3} }{3} =tan (\frac{\pi}{6} )\\x=\frac{\pi}{6}[/tex]

Answer:

48 degrees

Step-by-step explanation:

A straight line measures up to 180 degrees so take what we know which is 138 and subtract that from 180 to get your answer 48

Answer:

48

Step-by-step explanation:

Sum of angles On a straight line = 180

Given angle = 132

O, x is the remaining angle that must join 132 to form 180, which is

180-132 = 48 degrees.

Hope this helps

Good luck

Answer:

sqroot 16/49 A

Step-by-step explanation:

The expression  [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] is equivalent to expression [tex]\sqrt{\frac{16}{49}}[/tex] because by property  [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex].

The expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] can be simplified by taking the square root of 16 and the square root of 49 separately.

√16 equals 4 because the square root of 16 is the number that, when multiplied by itself, gives 16.

Similarly, √49 equals 7 because the square root of 49 is the number that, when multiplied by itself, gives 49.

So, the expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] simplifies to 4/7.

and we know that [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex]

[tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to  [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] , which simplifies to 4/7.

Therefore, [tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to  [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] .

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Answer:

D. all of the above

Step-by-step explanation:

All the letters from the options have a line of symmetry.

Answer:

Step-by-step explanation:

18/60-12/60= 4 miles

just my guess

Answer:

1/4

Step-by-step explanation:

-1 1/6 ÷ (-4 2/3)

Change to improper fractions

- ( 6*1 +1)/6 ÷ -(3*4 +2)/3

-7/6÷ -14/3

Copy dot flip

-7/6 * -3/14

Rewriting

-7/14 * -3/6

-1/2 * -1/2

1/4

Answer:

SOLUTION SET ={a/a≥20}

Step-by-step explanation:

[tex]\frac{2a}{5}-2\geq\frac{a}{4}+1[/tex]

[tex]adding 2 on both sides[/tex]

[tex]\frac{2a}{5}-2+2\geq \frac{a}{4}+1+2[/tex]

[tex]now subtracting \frac{a}{4} on both sides[/tex]

[tex]\frac{2a}{5}-\frac{a}{4}\geq 3[/tex]

[tex]takig LCM as 20\\\frac{8a}{20}-\frac{5a}{20}\geq 3[/tex]

[tex]\frac{3a}{20}\geq 3[/tex]

[tex]by cross-multiplication[/tex]

3a≥3×20

3a≥60

dividing 3 on both sides

3a/3≥60/3

a≥20

SOLUTION SET ={a/a≥20} is the answer

i hope this will help you :)

Answer:

A

Step-by-step explanation:

The blue graph, g(x), is shifted down 8 units.

So the answer is f(x)-8 which is A

Answer:  C. g(x) = eˣ⁻¹ - 3

Step-by-step explanation:

g(x) is a vertical shift 8 units down (-8) from f(x)

f(x) = eˣ⁻¹ + 5

g(x) = (eˣ⁻¹ + 5) - 8

      = eˣ⁻¹ - 3

Answer:

52 students

Step-by-step explanation:

From the question above, we have the following information:

a) Vidya ranks 7th from the top.

Mathematically,

Vidya = 7th student

b) Divya 3 ranks behind Vidya.

Divya = Vidya + 3

Hence, Mathematically:

Divya = 7 + 3 = 10

Divya = 10th student

c) Also, Divya is 7 ranks ahead of Medha.

Mathematically,

Medha = 10 + 7= 17

Medha= 17th student

d)Sushma is 32 ranks behind Medha

Mathematically,

Sushma = Medha + 32

= 17 + 32 = 49

Sushma is the 49th student

Therefore, since, Sushma is 4th from the bottom, total number of students is:

49 + 3 = 52 students

Hey there! I'm happy to help!

The surface area is just the area of this net. If you fold up the net it will give you a hollow 3-d shape.

On this net we have three congruent rectangles and two congruent triangles.

We see that each rectangle has a short side of 10 cm and a long side of 15 cm. The area of a rectangle is found by multiplying the long side by the short side.

15×10=150

So, each rectangle has an area of 150 cm².

Now, for the triangles. To find the area of a triangle you multiply the base by the height and then divide by two.

Each triangle has a base of 10 cm and a height 8 2/3 cm.

We multiply them.

10×8 2/3=86 2/3

And we divide by two.

86 2/3 ÷ 2 = 43 1/3

So, each triangle has an area of 43 1/3.  

Now, we add together the areas of our three rectangles and two triangles.

150+150+150+43 1/3+43 1/3=536 2/3

Therefore, the surface area is 536 2/3 cm².

Have a wonderful day!

Answer:

Here,

initial price (p)=$6500

Time from 2007 to 2020 (t)= 13yrs.

rate (r)=14.3%

now,

[tex]present \: price \: (pt) = p(1 - \frac{r}{100} )[/tex]

or, pt = $6500(1-14.3/100)

by simplifying it we get,

The, present price is $5570.5.

now, if you are searching for depreciated amount only then,

depreciated amount =$6500-$5570.5

=$929.5.

Hope it helps...

Assuming both vertical lines are parallel and assuming I'm supposed to find all the unmarked angles...

Angle C:

Supplementary Angles.

x+36=180

180-36=x

x=144

Angle B:

Corresponding Angles.

Angle B ≅ Angle C

144

Angle A:

360 degrees in a quadrilateral

36+144+81+x=360

261+x=360

x = 99

Hope it helps <3

Answer:

Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:

Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.

Step-by-step explanation:

In banking and finance, a credit transaction on a bank account indicates that an additional amount of money has been added to the bank account and the balance has increased. This gives a positive balance in the account

On the other hand, a debit transaction on a bank account indicates that an amount of money has been deducted or withdrawn from the bank account and the balance has therefore reduced. This gives a negative balance in the account.

Based on the above, we have:

a. Ram – Credits AED 500 on 12th May 2020

Since there is no any other credit or debit transaction during the month, this implies that Ram still has Credits AED 500 in his account at the end of the month.

The Credits AED 500 indicates that Ram has a positive balance of AED 500 in his account at the end of the month.

b. Rahul – Debits AED 700 on 12th May 2020 and Credits AED 500 on 15th May 2020.

The balance in the account of Rahul gives Debits of AED 200 as follows:

Debits AED 700 - Credits AED 500 = Debits AED 200

The Debits AED 200 indicates that Rahul has a negative balance of AED 200 in his account at the end of the month.

c. Rohit – Credits AED 700 on 12th May 2002 and Debits AED 500 on 15th May 2020.

The balance in the account of Rohit gives Credits of AED 200 as follows:

Credits AED 700 - Dedits AED 500 = Credits AED 200

The Credits AED 200 indicates that Rohit has a positive balance of AED 200 in his account at the end of the month.

Conclusion

Arrangement of numbers or amounts of money in ascending order implies that they are arranged from the smallest to the largest number or amount.

Since Credits implies positive amount and Debits implies negative amount, Ram therefore has more amount in his account at the end of the month, and the balances in their bank accounts at the end of the month are arranged in ascending order, i.e. from the smallest to the largest, as follows:

Rahul – Debits AED 200; Rohit – Credits AED 200; and Ram – Credits AED 500.

Answer:

For two polygons to be similar, both of the following must be true: Corresponding angles are congruent. Corresponding sides are proportional.

Step-by-step explanation:

HOPE THIS HELPS AND PLSSS MARK AS BRAINLIEST]

THNXX :)

What must be true for two polygons to be similar?

Similar polygons: For two polygons to be similar, both of the following must be true: Corresponding angles are congruent. Corresponding sides are proportional.

Answer:

1.63

HOPE THIS WILL HELP..............!

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▹ Answer

You can use a graphing calculator. Attached is a picture of it graphed.

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

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