Use Bayes' theorem to find the indicated probability 5.8% of a population is infected with a certain disease. There is a test for the disease, however the test is not completely accurate. 93.9% of those who have the disease test positive. However 4.1% of those who do not have the disease also test positive (false positives). A person is randomly selected and tested for the disease. What is the probability that the person has the disease given that the test result is positive?
a. 0.905
b. 0.585
c. 0.038
d. 0.475

Answers

Answer 1

Answer:

b. 0.585

Step-by-step explanation:

According to Bayes' theorem:

[tex]P(A|B)=\frac{P(B|A)*P(A)}{P(B)}[/tex]

Let A = Person is infected, and B = Person tested positive. Then:

P(B|A) = 93.9%

P(A) = 5.8%

P(B) = P(infected and positive) + P(not infected and positive)

[tex]P(B) = 0.058*0.939+(1-0.058)*0.041\\P(B)=0.09308[/tex]

Therefore, the probability that a person has the disease given that the test result is positive, P(A|B), is:

[tex]P(A|B)=\frac{0.939*0.058}{0.09308}\\P(A|B)=0.585[/tex]

The probability is 0.585.


Related Questions

Find the area of the trapezoid in the figure below round your final answer to the nearest tenth

Answers

Answer: 60.9 u^2

Step-by-step explanation:

The area of a trapezoid can be calculated as seen in the attachment.

Thus:

[tex]A = \frac{3.7+14.2}{2} * 6.8\\A = \frac{17.9}{2} *6.8\\A = 8.95*6.8\\A = 60.86\\Round\\\left[\begin{array}{c}A=60.9\end{array}\right][/tex]

Hope it helps <3

Answer:

60.9 units^2

Step-by-step explanation:

Well the formula for the area of a trapezoid is,

[tex]\frac{b1+b2}{2} h[/tex]

So b1 and b2 are 142 and 3.7,

14.2 + 3.7 = 17.9

17.9 ÷ 2 = 8.95

8.95 × 6.8 = 60.86

60.9 units^2 rounded to the nearest tenth.

Thus,

the area of the trapezoid is 60.9 units^2.

Hope this helps :)

A scale diagram of a garden shows the length as 14.5cm. If the scale is 1:150, what is the actual length? The garden is _______m in length.

Answers

Answer:

21.75m

Step-by-step explanation:

14.5×150 =2175cm

1m =100cm

to convert into m divide 2175 by 100

=21.75m

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose that for banner-tailed kangaroo rats, X has an exponential distribution with parameter λ = 0.0143. (a) What is the probability that the distance is at most 100 m? What is the probability that the distance is at most 200 m? What is the probability that the distance is between 100 m and 200 m? (b) What is the probability that distance exceeds the mean distance by more than 2 standard deviations? (c) What is the value of the median distance?

Answers

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.[tex]e^{-\lambda.x}[/tex]

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - [tex]e^{-\lambda.x}[/tex]

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - [tex]e^{-0.0143.100}[/tex]

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - [tex]e^{-0.0143.200}[/tex]

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = [tex]\frac{1}{\lambda}[/tex]

E(X) = [tex]\frac{1}{0.0143}[/tex]

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = [tex]\sqrt{\frac{1}{\lambda^{2}} }[/tex]

σ = [tex]\sqrt{\frac{1}{0.0143^{2}} }[/tex]

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - [tex]e^{-0.0143*209.79}[/tex])

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

[tex]\int\limits^m_0 f({x}) \, dx[/tex] = 0.5

[tex]\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx[/tex] = 0.5

[tex]\lambda.\frac{e^{-\lambda.x}}{-\lambda}[/tex] = [tex]-e^{-\lambda.x} + e^{0}[/tex]

[tex]1 - e^{-\lambda.m}[/tex] = 0.5

[tex]-e^{-\lambda.m}[/tex] = - 0.5

ln([tex]e^{-0.0143.m}[/tex]) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

Determine which type of correlation is shown in the graphed relationship

Answers

Answer:

No correlation

Step-by-step explanation:

Hey there! :)

This has no correlation because all the points are spread out throughout the graph making no correlation.

Answer:

D no correlation

Step-by-step explanation:

too many scattered dot all over the place if its some going up down its NO CORRELATION!!!

I really need help on this question

Answers

Answer:

d. 38

Step-by-step explanation:

AB = AD - BD = 54 - 36 = 18

AC = AB + BC = 18 + 20 = 38

Suppose you deposit $600 into an account that pays 5% annual interest, compounded continuously. How much will you have in the account in 4 years? ƒ(t) = aert A) $4,433.43 B)635.62 C)$729.30 D)$732.84

Answers

Answer:

D)$732.84

Step-by-step explanation:

A=p(1+r/n)^nt

P=principal=$600

r=5%=0.05

t=4 years

n=12 months

A=p(1+r/n)^nt

=600(1+0.05/12)^12*4

=600(1+0.0041666666666 )^48

=600(1.0041666666666 )^48

=600( 1.2208953550215 )

=732.53

A=$732.53

Option D)$732.84 is the answer

A car with a standard engine costs $14 000 to purchase and 25€/km to drive. An electric car costs S15 000
to purchase and 20¢/km to operate. How many kilometres would you have to drive for the costs of the
cars to be the same?

Answers

Answer:

200km

Step-by-step explanation:

Car A purchase worth = $14000

Car B purchase worth = $15000

Car A drive worth= 25€ per km

Car B drive worth= 20€ per km

For the worth of the two cars to be equal let's first assume all of the currency to be in dollars$

For A

Worth= 14000+25(x)

For B

Worth= 15000+20(x)

Where x is the distance covered

For the both worth to be equal we equate.

14000+25(x)= 15000+20(x)

25x-20x= 15000-14000

5x= 1000

X= 200

The distance covered by the two cars for the worth to be equal is 200km

Why should you find the least common denominator when adding or subtracting rational expressions?

Answers

Answer:

It is necessary to look for the least common denominator when one is trying to add or subtract rational expressions that do not have the same denominator.

Step-by-step explanation:

for example the denominator of the two addends are not the same. One has (x+2), the other (x-2).

Identify the parameter n in the following binomial distribution scenario. A basketball player has a 0.479 probability of
making a free throw and a 0.521 probability of missing. If the player shoots 17 free throws, we want to know the probability
that he makes more than 9 of them. (Consider made free throws as successes in the binomial distribution.)

Answers

Answer:

n = 17

Step-by-step explanation:

Assuming

- probability of success (making free throw) does not vary

We have

n = 17 (trials)

p = 0.479

x > 9

The answer is "[tex]\bold{p(x>9)=0.2550319}[/tex]"

[tex]\to X:[/tex] Number of creating free throws in a set [tex]\bold{17\ \ x \sim bin(17,0.479)}[/tex]

Know we calculating the P(makes more than 9 of them)

[tex]=\bold{9(X>9)=1-P(Z<=9)}[/tex]

Using the R-code:

[tex]\to \bold{1-p\ binom(9,17,0.479)}\\\\\to \bold{[1]0.2550319}\\\\\bold{\therefore}\\\\ \to \bold{p(x>9)=0.2550319}[/tex]

Learn more:

binomial distribution: brainly.com/question/9065292

An anchor lowered at a constant rate into the ocean takes 5 seconds to move -17.5 meters. What is the rate of the anchor in meters per second?

Answers

Answer:

-3.5 meters per second

Step-by-step explanation:

Take the distance and divide by the time

-17.5 meters/ 5 seconds

-3.5 meters per second

Answer:

-3.5 m/s

Step-by-step explanation:

Rate of the anchor =  [tex]\frac{distance}{time}[/tex]

[tex]\frac{-17.5}{5}[/tex]

-3.5 meters per second.

Determine all numbers at which are function Continuous..
f(x)={
x^2 + 5x - 36/
x^2 + 8x - 9
if x≠-9
if x= -9}
a.
continuous at every real number except x = 1 and x = -9
b. continuous at every real number except x = -9
c.continuous at every real number except x = 1
d. continuous at every real number except x = -9 and x = 4

Answers

Answer:

For this case we have this function:

[tex] f(x) =\frac{x^2 +5x-36}{x^2 +8x-9}, x=9[/tex]

We can factor the denominator and we got:

[tex] f(x) =\frac{x^2 +5x-36}{(x+9)(x-1)}, x=9[/tex]

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

Step-by-step explanation:

For this case we have this function:

[tex] f(x) =\frac{x^2 +5x-36}{x^2 +8x-9}, x=9[/tex]

We can factor the denominator and we got:

[tex] f(x) =\frac{x^2 +5x-36}{(x+9)(x-1)}, x=9[/tex]

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

Answer:

A or continuous at every real number except x=1 and x=-9

Step-by-step explanation:

Just took the test :)

Constructing a cube with double the volume of another cube using only a straightedge and compass was proven possible by advanced algebra.

True or False?

Answers

Answer:

False

Step-by-step explanation:

It was proved with advanced algebra that a doubled cube could never be constructed with a straightedge and compass

the endpoints of GH are g(-7,3) and h(1,-2) what’s the midpoint of GH

Answers

Answer:  [tex]\bigg(-3,\dfrac{1}{2}\bigg)[/tex]

Step-by-step explanation:

G = (-7, 3)    H = (1, -2)

[tex]M_{GH}=\bigg(\dfrac{X_G+X_H}{2},\dfrac{Y_G+Y_H}{2}\bigg)\\\\\\.\qquad = \bigg(\dfrac{-7+1}{2},\dfrac{3+(-2)}{2}\bigg)\\\\\\.\qquad = \bigg(\dfrac{-6}{2},\dfrac{1}{2}\bigg)\\\\\\.\qquad = \large\boxed{\bigg(-3,\dfrac{1}{2}\bigg)}[/tex]

The mid point of the line GH whose end points are (-7,3) and (1,-2) is (-3,1/2).

What is the mid point of a line?

The mid point is a line which divides the line into two equal parts. The formula to calculate the mid point of line whose end points are (x1,y1) and (x2,y2) is {(x1+x2)/2,(y1+y2)/2}.

How to calculate mid point of a line?

To calculate the mid point of the line GH we have to put x1=-7, x2=1,y1=3 and y2=-2 so,

the mid point is {(-7+1)/2,(3-2)/2}

=(-3,1/2)

Hence the mid points of a line GH whose end points are g(-7,3) and h(1,-2) is (-3/1/2).

Learn more about mid point of a line at https://brainly.com/question/18315903

#SPJ2

Please help with this

Answers

Answer: B

Step-by-step explanation:

Because of Supplementary Angles, we know that the two angles in the right side of the equation add up to 90.

Hope it helps <3

6th grade math help me, please :)))

Answers

Answer:

700✖️0.08=56 people is late

700✖️0.12=84 people bought the shirt.

Step-by-step explanation:

8%=0.08

12%=0.12

700✖️0.08=56 people is late

700✖️0.12=84 people bought the shirt.

HOPE THIS HELPS!

Belen wants to create a nut-mix. She can buy peanuts for $1.80 per pound and cashews for $4.50 per pound. If she wants to make a 10 pounds of nut-mix at a cost of $2.61 per pound, how many pounds of peanuts and how many pounds of cashews should she buy?

Answers

Answer:

7 and 3 respectively

Step-by-step explanation:

Peanuts (p/lb) = $1.80

Cashews (p/lb) = $4.50

Total pound = 10 pounds

Aggregate amount (at $2.61 per lb) = $26.1

Pound of peanut to buy = x

Pound of cashew to buy = y

x + y = 10..........(i)

1.8x + 4.5y = 26.1.....(ii)

Multiply equ (i) by 1.8 and equ (ii) by 1

1.8x + 1.8y = 18

1.8x + 4.5y = 26.1

Subtract (i) from (ii)

4.5y - 1.8y = 26.1 - 18

2.7y = 8.1

y = 3

Sub y = 3 into (i)

x + y = 10

x + 3 = 10

x = 10 - 3

= 7

Pounds of peanut to buy = 7 pounds

Pounds of cashew to buy = 3 pounds

Enter the correct answer in the box by replacing the values of a and b. f(x) = a(b)^x

Answers

Answer:

f(x)= 8(0.5)^x

Step-by-step explanation:

As you can see on the graph there are two specific points labeled:

(0,8) and (1,4)

The 8 would be the initial value and starting point of the "design"

A is always the initial value so replace that.

Then proceed to divide 4 by 8 to figure out the percentage change its 0.5

leave x as it is

During the summer months Terry makes and sells necklaces on the beach. Last summer he sold the necklaces for $10 each and his sales averaged 20 per day. When he increased the price by $1, he found that the average decreased by two sales per day. If the material for each necklace costs Terry $6, what should the selling price be to maximize his profit?

Answers

Answer:

The selling price in other to maximize his profit is $13

Step-by-step explanation:

In the above question we are given the following information:

Cost of material per necklace = $6

Firstly, terry sold 20 necklaces per day

= $10 each

Later he increased he increased the prices by 1 dollar and the number of necklaces he sold reduced by 2

Mathematically

18 necklaces = $11 each

Step 1

We find the Cost function C(x)

Let's assume that x = number of necklaces sold

If each material cost $6 , then

C(x) = 6 × x = 6x

Step 2

P(Profit) = R(x) - C(x)

R(x) = Revenue

Where Revenue = x × p(x)

Since p(20) = 10 and p(18) = 11

p(x) = -1/2x + 20

P(Profit) = x ( -1/2x + 20) - C(x)

C(x) = 6x

P = x(-1/2x + 20) - 6x

P = -1/2x² + 20x - 6x

P = -1/2x² + 14x

Step 3

We maximise the profit by differentiating P

P = Profit

P = -1/2x² + 14x

We differentiate P to find x

∆P/∆x = dp/dx = -x + 14

-x + 14 = 0

-x = -14

x = 14

Hence, we substitute 14 for x in the price function

p(x) = - 1/2x + 20

since , x = 14

p(14) = - 1/2 × 14 + 20

= -7 + 20

= $13

Therefore, the selling price function to maximize his profit is $13

Above question the given data:  

Cost of material per necklace = $6 Terry sold 20 necklaces per day = $10 each Price increase by 1 dollar Number of necklaces  sold reduced by 2  

1.Cost function C(x)

Let's assume that x = number of necklaces sold

If each material cost $6 , then

C(x) = 6 × x

C(x) = 6x  

2.P(Profit) = R(x) - C(x)

R(x) = Revenue ,Where Revenue = x × p(x)

Given data:

p(20) = 10

p(18) = 11

p(x) = -1/2x + 20

P(Profit) = R(x) - C(x)

P(Profit) = x ( -1/2x + 20) - C(x)

P = x(-1/2x + 20) - 6x

P = -1/2x² + 20x - 6x

P = -1/2x² + 14x

 

3.Maximise Profit

P = Profit  

P = -1/2x² + 14x

We differentiate P to find x

∆P/∆x = dp/dx = -x + 14

-x + 14 = 0

-x = -14

x = 14

Now, we will substitute 14 for x in the price function

Now ,p(x) = - 1/2x + 20

since , x = 14

p(14) = - 1/2 × 14 + 20  

p(14)= -7 + 20  

p(14)= $13

Thus, the selling price function to maximize his profit is $13.

Learn more :

https://brainly.com/question/24710158?referrer=searchResults

A movie earned $438 million at the box office in
2013. That is 24% more than book of the same
name earned. Estimate how much the book
earned?
Round your answer to the nearest hundredth of
a million dollars.

Answers

Answer:

332.88 million

Step-by-step explanation:

you do the thing

331.36 is the answer.
You can take 76% of 438 to find the answer

x/3 ≥−33 solve for x answer must be simplified

Answers

Answer:

[tex]\boxed{x\geq -99}[/tex]

Step-by-step explanation:

[tex]\frac{x}{3} \geq -33[/tex]

[tex]\sf Multiply \ both \ sides \ by \ 3.[/tex]

[tex]\frac{x}{3} (3) \geq -33(3)[/tex]

[tex]x\geq -99[/tex]

Answer:

[tex]\boxed{\red{x \geqslant - 99}}[/tex]

Step-by-step explanation:

[tex] \frac{x}{3} \geqslant - 33 \\ x \geqslant - 33 \times 3 \\ x \geqslant - 99[/tex]

hope this helps you!

which of the following graph represents the solution set for the inequality 3 - 1/2 x > 10

Answers

Answer:

56

Step-by-step explanation:

PLEASE HELP QUICK!!! A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some children take 5 pieces, and 1 child takes 7 pieces of candy. How many children take 3 pieces of candy?

Answers

Answer: 3 kids take 3 pieces of candy each

Step-by-step explanation:

Let the number of children that took 3 pieces is x ( total take 3*x pieces of candy)

Number of children that took 5 pieces is y ( total take 5*y pieces of candy)

1 child took 1 piece that actually means that x+y=18 and 3*x+5*y=84.

( Because total number of all kids is 19. We just deduct one kid (Let his name is John) who took only 1 candy.  So we have 19-1 =18 kids without John. The similar is with the candies. Total number is 85. We deduct 1 piece which John has taken. )

So we have 2 equations or the system of 2 equations:

1).  x+y=18

2). 3*x +5*y=84

Multuply both sides of equation 1) by 3

We have   3*x+3*y=18*3

Deduct 3*y from both sides of this equation

3*x+3*y-3*y=54-3*y

3*x=54-3*y

Substitute 3*x in equation  2).  by 54-3*y

2) 54-3*y+5*y=84

2*y=30

y=15  ( kids take 5 pieces of candy each)

Using equation 1) find x

x+15=18

x=3 (kids take 3 pieces of candy each)

Tubby Toys estimates that its new line of rubber ducks will generate sales of $7 million, operating costs of $4 million, and a depreciation expense of $1 million. If the tax rate is 25%, what is the firm’s operating cash flow?

Answers

Answer:

2.5m

Step-by-step explanation:

Using the adjusted accounting profits method.

Operating cash flow = After - tax profit + Depreciation. .......... ( 1 )

Given that :

* depreciation expense = $1 million

* Sales generated $7 million

* Tax rate = 25%

Tax rate = 25/100

= 0.25

From equation 1

= ( 7m - 4m - 1m ) ×( 1 - 0.25 ). + 1m

= ( 7m - 5m ) × ( 0.75 ) + 1m

= 2m × 0.75 + 1m

= 1.5m + 1m

= 2.5m

The firm operating cash flow = 2.5m

assume that when adults with smartphones are randomly selected 42 use them in meetings or classes if 15 adult smartphones are randomly selected, find the probability that "fewer" than 4 of them use their smartphones

Answers

Complete Question

Assume that when adults with smartphones are randomly selected 42% use them in meetings or classes if 15 adult smartphones are randomly selected, find the probability that "fewer" than 4 of them use their smartphones

Answer:

The  probability is  [tex]P[X < 4]= 0.00314[/tex]

Step-by-step explanation:

From the question we are told that

      The proportion of those that use smartphone in meeting and classes is  p = 0.42

     The sample size is  [tex]n = 15[/tex]

   The proportion of those that don't use  smartphone in meeting and classes is  

          [tex]q = 1- p[/tex]

=>        [tex]q = 1- 0.42[/tex]

=>         [tex]q = 0.58[/tex]

Now  from the question we can deduce that the usage of the smartphone is having a  binomial  distribution since there is only two outcome  

So  the probability that "fewer" than 4 of them use their smartphones is mathematically evaluated as

       [tex]P[X < 4 ] = P[X = 0] + P[X = 1] +P[X = 2] +P[X = 3][/tex]=

=>     [tex]P[X < 4] = [ \left 15} \atop {0}} \right. ] p^{15-0} * q^0 + [ \left 15} \atop {1}} \right. ] p^{15-1 }* q^1 + [ \left 15} \atop {2}} \right. ] p^{15-2 }* q^2 + [ \left 15} \atop {3}} \right. ] p^{15-3 }* q^3[/tex]

Where  [tex][\left 15} \atop {0}} \right. ][/tex] implies 15  combination 0 which has a value of  1 this is obtained using a scientific calculator

  So for the rest of the equation we will be making use of a scientific calculator to obtain the combinations

      [tex]P[X < 4] = 1 * ^{15} * q^0 + 15 * p^{14 }* q^1 + 105 * p^{13 }* q^2 + 455 * p^{12 }* q^3[/tex]

substituting values

       [tex]= 1 * (0.42)^{15} * (0.58)^0 + 15 * (0.42)^{14 }* (0.58)^1[/tex]

                     [tex]+ 105 * (0.42)^{13 }* (0.58)^2 + 455 * (0.42)^{12 }* (0.58)^3[/tex]

=>       [tex]P[X < 4]= 0.00314[/tex]

Evaluate 7(-4) - |-6| + |4| a 13 b -18 c -30

Answers

Answer:

C. -30

Step-by-step explanation:

We would have to do order of operations or P.E.M.D.A.S. So fist we would do 7 times -4 which is -28 than we would do the absolute value of -6 which is 6 so we would do -28-6 which is -34 and we would do the absolute value of 4 which is 4 and we would add it to -34 which is -30 so our final answer would be C. -30

x(x+3)(x+3)=0 Please I NEED HELP FAST! PLLLLLLLLLLLLLLLLLLLLLLLLLLEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEAAAAAAAAAAAAAAAAAAAAAAAAAAAAASSSSSSSSSSSSSSSSSSSSSSSSSSEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!

Answers

Answer:

[tex]\boxed{x^3+6x^2+9x}[/tex]

Step-by-step explanation:

[tex]x(x+3)(x+3)[/tex]

Resolving the first parenthesis

[tex](x^2+3x) (x+3)[/tex]

Using FOIL

[tex]x^3+3x^2+3x^2+9x[/tex]

Adding like terms

[tex]x^3+6x^2+9x[/tex]

[tex]\text{If } \: a\cdot b \cdot c = 0 \text{ then } a=0 \text{ or } b =0 \text{ or } c=0 \text{ or all of them are equal to zero.}[/tex]

[tex]x(x+3)(x+3) =0[/tex]

[tex]\boxed{x_1 =0}[/tex]

[tex]x_2+3 =0[/tex]

[tex]\boxed{x_2 = -3}[/tex]

[tex]x_3+3 =0[/tex]

[tex]\boxed{x_3 = -3}[/tex]

How much would a computer system cost if you pay $200 down and made 12 monthly payments of only $98.95?

Answers

Answer:

$1387.4

Step-by-step explanation:

Total cost for the computer will be sum of down payments and monthly installments.

____________________________________

Given

down payment = $200

monthly installment value = $98.85

no. of installments = 12

total value of monthly installments = 12*98.95 = $1187.4

Total cost of computer system = $200+  $1187.4 = $1387.4

Find the balance in Asturos savings account if he deposits $2100 at 3.5% simple interest for 2 years

Answers

Answer:

2250

Step-by-step explanation:

Balance : 2100

2 Years

2100 ÷ 100 x 103.5 ÷ 100 x 103.5 = 2249.5725

A square based brass plate in 4mm high and has a mass of 1.05kg. The density of the brass is 4.2g/cm3, calculate the length of the plate in centimeters​

Answers

Answer:

[tex]Length = 25cm[/tex]

Step-by-step explanation:

Given

Brass Shape: Square

[tex]Density = 4.2g/cm^3[/tex]

[tex]Mass = 1.05kg[/tex]

[tex]Height = 4mm[/tex]

Required

Determine the length of the plate

First, we need to calculate the Volume of the Brass using

[tex]Density = \frac{Mass}{Volume}[/tex]

Make Volume the subject of formula

[tex]Volume = \frac{Mass}{Density}[/tex]

Substitute 1.05kg for Mass and 4.2g/cm³ for Density

[tex]Volume = \frac{1,05\ kg}{4.2\ g/cm^3}[/tex]

Convert 1.05 kg to grams

[tex]Volume = \frac{1.05 * 1000\ kg}{4.2\ g/cm^3}[/tex]

[tex]Volume = \frac{1050 \ kg}{4.2\ g/cm^3}[/tex]

[tex]Volume = \frac{1050 \ kg}{4.2\ g/cm^3}[/tex]

[tex]Volume = 250cm^3[/tex]

Next is to determine the Area of the brass;

[tex]Volume = Height * Area[/tex]

Substitute 250cm³ for Volume and 4mm for Height

[tex]250cm^3 = 4mm * Area[/tex]

Convert mm to cm

[tex]250cm^3 = 4 * 0.1cm * Area[/tex]

[tex]250cm^3 = 0.4cm * Area[/tex]

Divide both sides by 0.4cm

[tex]\frac{250cm^3}{0.4cm} = \frac{0.4cm * Area}{0.4cm}[/tex]

[tex]\frac{250cm^3}{0.4cm} =Area[/tex]

[tex]625cm^2 = Area[/tex]

[tex]Area = 625cm^2[/tex]

Lastly, we'll calculate the length of the brass

Since the brass is square based;

[tex]Area = Length^2[/tex]

Substitute 625cm² for Area

[tex]625cm^2 = Length^2[/tex]

Take square root of both sides

[tex]\sqrt{625cm^2} = Length[/tex]

[tex]25cm = Length[/tex]

[tex]Length = 25cm[/tex]

Hence, the length of the square brass is 25cm

What would be the Excel Formula to solve this question?

Deb and Rusty know that buying a house will save them money on taxes because they get to deduct the interest they pay to the bank each year and the property taxes they pay each year. First create a separate worksheet from the amortization schedule. Title this worksheet Analysis. In this worksheet, create a column titled Income starting at $90,000 and increasing at 3% for 20 years. What is their income after 20 years?

Answers

Answer:

Income after 20 years = 162550.01

Step-by-step explanation:

In cell B2, enter 90000

In cell B3, enter +B2*1.03

Copy cell B3 to cells B4:B22

Set number format for column B to 2 decimal places.

Read cell B22 = 162550.01

Income after 20 years = 162550.01

Their income after 20 years would be; 72,550 dollars.

What is income tax?

Income tax is a tax applied on individuals or entities concerning income or profit earned by them.

The income after 20 years can easily be determine by using compounding

Thus the formula;

Future Value = Present Value (1 + I)^ 20

                     = 90,000 (1 + 0.03)^ 20

                     = 162,550 dollars

Income can be determing by subtracting Pv from Fv i.e

Income = 162,550 - 90,000 = 72,550

Calculation on excel sheet;

      A                        B                  C                         D                

1     90,000             1.03            = A1 x1.03        = C1-A1        

2      = D1                  1.03           = A2 x 1.03       = C2-A2

20    = D19               1.03           = A20 x 1.03      = A20 - C20

Thus, In work sheet colunm D will show the income on investment.

Learn more about income;

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