A sixth-grade class is growing plants for their
science projects. Each student spent $1.00 for a
package of seeds and $2.50 for a container to
plant the seeds in. There are 30 students in the
class. How much money did the sixth-grade class
spend on seeds and containers in all?

Answer:

- 1

Step-by-step explanation:

Given

( [tex]\frac{1+i}{1-i}[/tex] )²

= [tex]\frac{(1+i)^2}{(1-i)^2}[/tex]

= [tex]\frac{(1+i)(1+i)}{(1-i)(1-i)}[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{1+2i+i^2}{1-2i+i^2}[/tex] ← simplify using i² = - 1

= [tex]\frac{1+2i-1}{1-2i-1}[/tex]

= [tex]\frac{2i}{-2i}[/tex]

= - 1

Answer:

please mark my answer brainliest

Step-by-step explanation:

ok

Answer: 40x

First, let's find f(2x)

[tex]f(2x)=4(2x)=8x[/tex]

Using this, let's find g(f(2x)):

[tex]g(f(2x))=g(8x)=5(8x)=40x[/tex]

That's the answer. Let me know if you need any clarifications, thanks!

Answer:

80x²

Step-by-step explanation:

f(x) = 4x², g(x) = 5x

f(2x) = 4(2x)² = 16x²

g(f(2x)) = 5(16x²) = 80x²

Answer:

The cost is $.08 per ounce or 8 cents per ounce

Step-by-step explanation:

1 quart = 32 ounces

2 quarts = 64 pints

2 quarts costs 5.12

Take the cost and divide by the number of ounces

5.12 / 64

.08 per ounce

The cost is $.08 per ounce or 8 cents per ounce

=================================================

Explanation:

1 quart = 32 fluid ounces

2 quarts = 64 fluid ounces (multiply both sides by 2)

He paid 5.12 dollars for 64 fluid ounces, so the unit rate is 5.12/64 = 0.08 dollars per fluid ounce, or 8 cents per fluid ounce.

---------

We can think of it this way in terms of an equation

5.12 dollars = 64 fluid ounces

5.12/64 dollars = 64/64 fluid ounces ... divide both sides by 64

0.08 dollars = 1 fluid ounce

We divided both sides by 64 to turn "64 fluid ounces" into "1 fluid ounce", due to how the term "unit rate" is set up. The term "unit" means "one". Basically we're finding the cost per 1 unit, or per 1 fluid ounce.

Answer:

Step-by-step explanation:

To find the slope first write the equation in the form

y = mx + c

where m is the slope

c is the y intercept

3x - 3y = -45

3y = 3x + 45

Divide both sides by 3

y = 3/3x + 45/3

y = x + 15

From the equation the slope = 1

Parallel lines have equal slope

So

The line parallel to the above line is also

1

Hope this helps you

Answer:

[tex]\boxed{85}[/tex]

Step-by-step explanation:

Sum of 38 and -87:

=> 38 + (-87)

=> 38 - 87

=> -49

Subtraction of -134 from -49:

=> -49 - (-134)

=> -49 + 134

=> 85

Hi,

[tex]y=5x^{2} +12x-2\\y=x(5x+12)-\frac{46}{5} \\y=5(x+\frac{6}{5} )^{2}-\frac{46}{5} \\[/tex]

Have a good day.

Answer:

50

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

(f - g)(x) = ( f(x) ) -  ( g(x) )

(f - g)(x) = (4x^2 - 6) - ( x^2 - 4x - 8)

(f - g)(x) = 4x^2 - 6 - x^2 + 4x + 8

(f - g)(x) = (4x^2-x^2) + 4x + (-6+8)

(f - g)(x) = 3x^2 + 4x + 2

Answer:

BCD

Step-by-step explanation:

Answer: B,C & D

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Put your information in the the point slope formula y-y1=m(x-x1)

This will give you y+5=3(x+3)

simplify

y+5=3x+9

Now subtract 5

y=3x+4

Answer:

[tex]\frac{1}{3x+52}[/tex]

Step-by-step explanation:

Given

[tex]\frac{\frac{1}{x^2+51x+50} }{\frac{2}{x+50}+\frac{1}{x+1} }[/tex]

= [tex]\frac{\frac{1}{(x+50)(x+1)} }{\frac{2(x+1)+x+50}{(x+50)(x+1)} }[/tex]

= [tex]\frac{1}{(x+50)(x+1)}[/tex] × [tex]\frac{(x+50)(x+1)}{2x+2+x+50}[/tex] ← cancel (x + 50)(x + 1) on numerator/denominator

= [tex]\frac{1}{3x+52}[/tex]

Answer:

[tex]\Large\boxed{\sf \bf \ \ \dfrac{1}{3x+52} \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

We need to do something with that, right !?

           [tex]\dfrac{\left(\dfrac{1}{x^2+51x+50\right)}}{\left(\dfrac{2}{x+50}+\dfrac{1}{x+1}\right)}[/tex]

What can we say from [tex]x^2+51x+50[/tex] ?

The sum of the zeroes is -51=(-1)+(-50) and the product is 50 = (-1) x (-50), so we can factorise. Let's do it !

[tex]x^2+51x+50=x^2+50x+x+50=x(x+1)+50(x+1)=(x+1)(x+50)[/tex]

That's a pretty cool first result !

Now, let's play with the denominator.

[tex]\dfrac{2}{x+50}+\dfrac{1}{x+1}\\\\\text{*** We put on the same denominator which is (x+1)(x+50) ***}\\\\=\dfrac{2(x+1)}{(x+50)(x+1)}+\dfrac{x+50}{(x+1)(x+50)}\\\\=\dfrac{2(x+1)+x+50}{(x+50)(x+1)}\\\\=\dfrac{2x+2+x+50}{(x+50)(x+1)}\\\\=\dfrac{3x+52}{(x+50)(x+1)}\\[/tex]

We are almost there.

Let's combine all these results together !

[tex]\dfrac{\left(\dfrac{1}{x^2+51x+50\right)}}{\left(\dfrac{2}{x+50}+\dfrac{1}{x+1}\right)}\\\\\\=\dfrac{\left(\dfrac{1}{(x+1)(x+50)\right)}}{\left(\dfrac{3x+52}{(x+50)(x+1)}\right)}}\\\\\\=\large\boxed{\dfrac{1}{3x+52}}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

[tex]n^6[/tex].

Step-by-step explanation:

[tex]n^4 * \frac{n^7}{n^5}[/tex]

= [tex]n^4 * n^{7 - 5}[/tex]

= [tex]n^4 * n^2[/tex]

= [tex]n^{4 + 2}[/tex]

= [tex]n^6[/tex].

Hope this helps!

Answer:

Length 1 - Width = 19, Area = 19

Length 2 - Width = 18, Area = 36

Length 3 - Width = 17, Area = 51

Length 4 - Width = 16, Area = 64

Length 5 - Width = 15, Area = 75

Step-by-step explanation:

Area Formula: A = lw

Since we only have a combined total of 20 m to use, we have to subtract the number of length in order to find length:

Length 1 = 20 - 1 = Width 19 m

Length 2 = 20 - 2 = Width 18 m

Length 3 = 20 - 3 = Width 17 m

Length 4 = 20 - 4 = Width 16 m

Length 5 = 20 - 5 = Width 15 m

Then we simply plug in our l values and w values into the area formula:

A = 1(19) = 19 m²

A = 2(18) = 36 m²

A = 3(17) = 51 m²

A = 4(16) = 64 m²

A = 5(15) = 75 m²

width from 1-5 =

when lem

length=1, width=19

length=2,width=18

length=3,width=17

length=4,width=16

length=5,width=15

length =1,Area=19

length=2,Area=36

length=3,area=51

length=4,area=64

length=5,area=75.

Step-by-step explanation:

to get our width, we minus each length from the given value which is 20m.

e.g.

when length =1 our width becomes 20-1=19.

and you do same for the rest.

the formula for the area was given to us in the question so we use that to find the area.

A=Length×Width.

e.g when length=1, width =19

so the area becomes 1×19=

[tex] {19m}^{2} [/tex]

please note that your area should be in

[tex] {m}^{2} [/tex]

Answer:

$6.8

Step-by-step explanation:

Let x be the amount of money in Molly's amount

according to question,

4x-25=2.20

4x=2.20+25

4x=27.20

x=27.20/4

x=6.8

So,the amount of money in Molly's amont is $6.8

Answer: $6.80

Step-by-step explanation:

We will represent the amount of money that Molly has with a m. So it tells us the relationship between Kevin's amount and Molly's amount. It is says Kevin has 2.20 less that 4 times Molly's amount so we could represent it by the equation.

25 = 4m -2.20   solve for m.

+2.20     +2.20

27.20 = 4m

m= 6.8

4(6.8) = 27.20 - 25 = 2.20

Answer:

3/4

Step-by-step explanation:

Since, angles θ and α are complementary.

Therefore,

θ + α = 90°

θ = 90° - α

Taking sin both sides.

sin θ = sin (90° - α)

sin θ = cos α (sin (90° - θ) = cos θ)

Since, sin θ = 3/4.....(given)

Hence, cos α = 3/4

Answer:

72 inch²

Step-by-step explanation:

Rectangular classroom

Length=36ft

Width=32ft

scale drawing length = 9 inches

Scale drawing width=x

Ratio of the length to the scale drawing length = 36/9

Ratio of the width to the scale drawing width=32/x

To find x

36/9=32/x

Cross product

36x=32*9

x=288/36

=8

x=8

Area of a rectangle= length × width

Length=9 inches

Width=8 inches

Area of the rectangular classroom= 9 inches × 8 inches

=72 inch²

Answer:

The third one.

Step-by-step explanation:

The last bar graph is skewed to the right, since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs. The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.

Comparatively, bar graphs one and two have approximately symmetrical distributions of numbers on both sides of the central bar. This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.

A bar graph. The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1 is data distribution would most likely have a mean and median that are not close in value.

We have to determine, which data distribution would most likely have a mean and median that are not close in value.

According to the question,

The mean and the median both reflect the skewing, but the mean reflects it more.

The last bar graph is skewed to the right since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs.

The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.

The mean and the median are the same. This example has one mode (unimodal), and the mode is the same as the mean and median.

Bar graphs one and two have approximately symmetrical distributions on both sides of the central bar.

This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.

Hence, The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1.

To know more about Probability click the link given below.

https://brainly.com/question/23044118

Answer:

a) about 0.7 seconds to 5.1 seconds.

b) Listed below.

Step-by-step explanation:

h - 1 = -5x^2 + 29x

h = -5x^2 + 29x + 1

a) We will find the amount of time it takes to get to 18 meters.

18 = -5x^2 + 29x + 1

-5x^2 + 29x + 1 = 18

-5x^2 + 29x - 17 = 0

We will then use the quadratic formula to find the answer.

[please ignore the A-hat; that is a bug]

[tex]\frac{-29±\sqrt{29^2 - 4 * -5 * -17} }{2 * -5}[/tex]

= [tex]\frac{-29±\sqrt{841 - 340} }{-10}[/tex]

= [tex]\frac{-29±\sqrt{501} }{-10}[/tex]

= [tex]\frac{-29 ± 22.38302929}{-10}[/tex]

= [tex]\frac{-6.616970714}{-10}[/tex] and [tex]\frac{-51.38302929}{-10}[/tex]

= 0.6616970714 and 5.138302929

So, the time period for which the baseball is higher than 18 metres ranges from about 0.7 seconds to 5.1 seconds.

b) Restrictions on the domain and range of the function are that the domain and range can never be negative, since time cannot be negative, and height cannot be negative. The height cannot exceed the vertex of the parabola, since that is the highest the ball will ever go. It cannot exceed that height since gravity will cause the ball to fall down.

Hope this helps!

Answer:

Step-by-step explanation:

Initial balance of Marta Fuentes  = $1200.50

Charge made by her bank;

Credit of $505 and Charge on new checks is $12.

Total charge incurred = $505+$12

Total charge incurred = $517

Since there will be no outstanding checks or deposit, her checkbook balance will be the difference between the initial balance and amount charged by the bank.

Checkbook balance = $1200.50 - $517

Checkbook balance = $683.50

Hence her checkbook balance should be $683.50

Answer:

Step-by-step explanation:

f(x) = 2x

When x = 2

Substitute the value of x into f(x)

That's

f(2) = 2(2)

= 4

Hope this helps you

Answer:

f(2)= 4

Step-by-step explanation:

To find f(2) we will use y=2x since f(x)=y

●y=2*2= 4 wich is f(2)

Answer:

Yes, it can.

Step-by-step explanation:

Looking at this table, we can see that each type of hat is ALWAYS next to the same type of flower.

Berets are ALWAYS next to Daffodils.

Panamas are ALWAYS next to Sunflowers.

Cloches are ALWAYS next to Violets.

Bowlers are ALWAYS next to Irises.

Fedoras are ALWAYS next to Narcissuses.

If we assume that every type of FLOWER is a number and every type of HAT is also a number, these will all match up.

So, they are consistent.

This means that the type of flower can be represented as a function of the type of hat.

Hope this helped!

Answer:

No

Step-by-step explanation:

There is not a known causation or correlation between the two variables.

Answer:

Option D. (8, – 4)

Step-by-step explanation:

3x + 4y = 8 ..... (1)

x – y = 12.... (2)

To solve the above equation by elimination method, do the following:

Step 1:

Multiply equation 1 by the coefficient of x in equation 2 i.e 1.

Multiply equation 2 by the coefficient of x in equation 1 i.e 3. This is illustrated below:

1 × Equation 1

1 × (3x + 4y = 8)

3x + 4y = 8 ...... (3)

3 × Equation 2

3 × ( x – y = 12)

3x – 3y = 36......(4)

Step 2:

Subtract equation 3 from equation 4. This is illustrated below:

. 3x – 3y = 36

– (3x + 4y = 8)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

– 7y = 28

Divide both side by the coefficient of y i.e –7

y = 28/–7

y = – 4

Step 3:

Substitute the value of y into any of the equation to obtain the value of x. In this case, we shall substitute the value of y into equation 2 as shown below:

x – y = 12

y = –4

x – (–4) = 12

x + 4 = 12

x = 12 – 4

x = 8

Therefore, the solution to the equation above is (8, – 4)

Answer:

(8, – 4)

Step-by-step explanation:

my math teacher told me

Answer:

Length of first leg = 1.4feet

Hypotenuse = 4.2feet

Explanation:

Since we are dealing with a right angled triangle, we will apply the Pythagoras theorem to solve the question. According to Pythagoras theorem, the square of the hypotenuse is equal to the sum if the square of the other two legs.

Mathematically, a² = b²+c² where a is the hypotenuse and b, c are the other two legs.

From the question, since hypotenuse of a right triangle is three times the length of its first leg, then a = 3b.

Also the other leg is four feet i.e c= 4

Substituting this values into the Pythagoras formula;

a²=b²+c²

(3b)² = b²+4²

9b² = b²+16

9b²-b² = 16

8b² = 16

b² = 16/8

b² = 2

b = √2

b = 1.4

Since a = 3b

a = 3(1.4)

a = 4.2

Hence, the length of the first leg is 1.4feet and that of the hypotenuse is 4.2feet both to the nearest tenth.

Answer:

The equation is true

Step-by-step explanation:

The best way to check if this equate is true is to convert the pi in radians to degree and actually evaluate the trigonometric terms.

Mathematically we know that pi = 180 degrees

So pi/8 = 22.5

and pi/4 = 180/4 = 45

So let’s make our check.

Insert pi = 22.5 and pi = 45

So we have;

tan 22/5 = √(1-cos45)/(1+cos45)

Now let’s evaluate this using a calculator.

tan 22/5 = 0.414213562373

The term in the root; 0.171572875254

The square root of this number is 0.414213562373

This is exactly as what is obtained with the tan 22.5

So we conclude that what we have is true

Answer:

3x + 4y ≥ 82

Step-by-step explanation:

3x + 4y ≥ 82

we can read as: 3 time of right answers of true/false plus 4 times of right answers of multiple choice must be bigger or at least 82

Answer:

The height of the statue is 217 m

Step-by-step explanation:

The hill is 25 ft above the ground,

you are standing 53 ft from the base of the hill,

angle of depression from the top of the angle to where you stand is 12.4°

Let us designate the total height from the base of the hill to the top of the statue as y.

This problem will then form a right angle triangle problem, with the base as the opposite side to the angle, and the total height of the statue and the hill as the adjacent side.

given the opposite as 53 ft,

and the adjacent as y,

and angle ∅ = 12.4°

we use tan ∅ = opp/adj

tan 12.4 = 53/y

0.219 = 53/y

y = 53/0.219 = 242 m

But this height y from base of the hill to the top of the statue is equal to the height of the hill from the base which is 25 ft, and the height of the statue from the top of the hill. This means

y = 242 = 25 + n

where n is the height of the statue.

242 = 25 + n

n = 242 - 25 = 217 m

Answer:

Step-by-step explanation:

Given,

x = 2

y = - 4

Now, let's solve:

[tex] \frac{1}{ {2}^{ - 2} \: {x}^{ - 3} \: {y}^{5} } [/tex]

plug the values

[tex] \frac{1}{ {2}^{ - 2} \: {(2)}^{ - 3} \: {( - 4)}^{5} } [/tex]

A negative base raised to an odd power equals a negative

[tex] \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {( - 4}^{5}) } [/tex]

Determine the sign of the fraction

[tex] - \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {4}^{5} } [/tex]

Write the expression in exponential form with a base of 2

[tex] - \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {2}^{10} } [/tex]

Calculate the product

[tex] - \frac{1}{ {2}^{5} } [/tex]

Evaluate the power

[tex] - \frac{1}{32} [/tex]

Hope this helps...

Best regards!!

Answer:

y = -2/3x - 2

Step-by-step explanation:

Step 1: Find slope m of perpendicular line

Simply take the negative reciprocal of the given line

m = -2/3

y = -2/3x + b

Step 2: Find b

6 = -2/3(-12) + b

6 = 8 + b

b = -2

Step 3: Rewrite perpendicular equation

y = -2/3x - 2