The length of ST is 57 unit.
What is Perimeter?A perimeter is a closed path that covers, surrounds, or outlines a two-dimensional shape or length. The circumference of a circle or an ellipse is its perimeter.
As, we know that the four sides of Rhombus are equal.
So, TR = QR
-x+ 68 = 5x + 2
-x - 5x = 2 - 68
-6x = - 66
x= -66/ (-6)
x= 11
So, the length of ST = 5x+ 2 = -x+ 68 = 57 unit
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x:y = 5:3
y:2 = 11:6
The mean of x, y and z is 88 1/3% of 360
Find the range of x, y and z.
If the mean of x, y and z is 88 1/3% of 360. The range of x, y and z is 2,852.
How to find the range of x, y and z?To solve this problem, we need to use the given ratios and proportions to find the values of x, y, and z, and then use the given mean to find their range.
From the first ratio, we have:
x:y = 5:3
This can be written as:
x = (5/3) * y
Substituting this value of x into the second ratio, we get:
y:2 = 11:6
Multiplying both sides by 3, we get:
3y = 22
y = 22/3
Substituting this value of y into the equation for x, we get:
x = (5/3) * (22/3) = 110/9
To find z, we can use the mean of x, y, and z:
(1/3)(x + y + z) = (8/3) * 360
x + y + z = 2880
Substituting the values we found for x and y, we get:
(110/9) + (22/3) + z = 2880
Multiplying both sides by 9, we get:
110 + (66/3) + 9z = 25920
110 + 22 + 9z = 25920
9z = 25788
z = 2864
Therefore, the values of x, y, and z are:
x = 110/9
y = 22/3
z = 2864
To find the range, we need to subtract the smallest value from the largest value:
Range = z - x = 2864 - (110/9) = 2,852
Therefore, the range of x, y, and z is 2,852.
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Please help i don't understand
The slope of the line in simplest form is 1/3.
How to calculate the slope of a line?In Mathematics, the slope of any straight line can be determined by using this mathematical equation;
Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = rise/run
Substituting the given data points into the slope formula, we have the following;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (-2 + 5)/(9 - 0)
Slope, m = 3/9
Slope, m = 1/3
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Mr. Willams’ physical education class lasts 7/8 hour. How many minutes are not spent on instructions? Explain
Answer:
42 minutes are not spent on instructions
Step-by-step explanation:
First, we must find out how many minutes is in [tex]\frac{7}{8}[/tex] hour
[tex]60*\frac{7}{8}=\frac{60*7}{8} =\frac{420}{8} =52.5[/tex]
In [tex]\frac{7}{8}[/tex] hour, there is about 52 [tex]\frac{1}{2}[/tex] minutes
Then we must add up the fractions that are NOT the instructions
[tex]\frac{1}{2} +\frac{3}{10} =\frac{5}{10} +\frac{3}{10} =\frac{8}{10} =\frac{4}{5}[/tex]
[tex]\frac{4}{5}[/tex] of the total time (52 [tex]\frac{1}{2}[/tex] minutes) is not spent on instructions
Then we must multiply the fraction of time spent on other things ([tex]\frac{4}{5}[/tex]) by total time (52 [tex]\frac{1}{2}[/tex] minutes) in order to find out how many minutes weren't spent on instructions.
[tex]\frac{4}{5}*52 \frac{1}{2} =\frac{4}{5}* \frac{105}{2}=\frac{420}{10} =42[/tex]
42 minutes are not spent on instructions
I am a number. If you triple my number, add 5, and then divide me by 2 the result
will be 22. What number am I?
Answer:
5.66666666667
Step-by-step explanation:
5.66666666667 Because you do 22-5 divided by 3 I believe.
30 POINTS + BRAINLIEST
Landon wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), and G (6, 1). He has 16 units of fencing. Where could Landon place point H so that he does not have to buy more fencing?
(0, 1)
(0, −2)
(1, 1)
(1, −2)
Answer:
To determine the location of point H, we need to first find the length of the three sides of the fenced area using the given points E, F, and G.
The length of EF is:
sqrt[(3-1)^2 + (5-5)^2] = 2 units
The length of FG is:
sqrt[(6-3)^2 + (1-5)^2] = sqrt(25) = 5 units
The length of EG is:
sqrt[(6-1)^2 + (1-5)^2] = sqrt(20) = 2sqrt(5) units
The total length of the three sides is:
2 + 5 + 2sqrt(5) = 7 + 2sqrt(5) units
Since Landon has 16 units of fencing, he needs to find a point H such that the length of the fourth side of the fenced area (EH) is:
16 - (7 + 2sqrt(5)) = 9 - 2sqrt(5) units
Let's assume that point H has coordinates (x, y). Then, we can use the distance formula to find the length of EH:
sqrt[(x-1)^2 + (y-5)^2] = 9 - 2sqrt(5)
Squaring both sides and simplifying, we get:
(x-1)^2 + (y-5)^2 = 81 - 36sqrt(5) + 20
(x-1)^2 + (y-5)^2 = 101 - 36sqrt(5)
Now, we can plug in the coordinates of each of the answer choices and see which one satisfies this equation:
For (0, 1):
(0-1)^2 + (1-5)^2 = 16, which is not equal to 101 - 36sqrt(5)
For (0, -2):
(0-1)^2 + (-2-5)^2 = 65, which is not equal to 101 - 36sqrt(5)
For (1, 1):
(1-1)^2 + (1-5)^2 = 16, which is not equal to 101 - 36sqrt(5)
For (1, -2):
(1-1)^2 + (-2-5)^2 = 65, which is equal to 101 - 36sqrt(5)
Therefore, the answer is (1, -2), and Landon can place point H at coordinates (1, -2) to fence in the dog park without having to buy more fencing.
6. What is the length of side AB?
AB =
BC = 2x
T.P. =>
4x² = x² + 6²
3x² = 36
x² = 12
=> x = 2sqrt3
Not so sure on this….
We used two different functions to describe the movement of a falling object. One function measured the distance the object traveled from its starting point, and the other measured its distance from the ground. How are the representations of these functions alike and different?
Answer: The representations of these functions are alike in that they both describe the movement of the falling object. They are different in that one function measures the distance the object has traveled from its starting point, while the other measures its distance from the ground.
Step-by-step explanation:
factored form. (x^(2)-64)/(x^(2)-3x-54)-(x^(2)-81)/(4x^(2)-12x-216) Show your work here
This is the final factored form of the original expression. = (4x^(2)-x-265)/((4(x-9)(x+6)))
To find the factored form of (x^(2)-64)/(x^(2)-3x-54)-(x^(2)-81)/(4x^(2)-12x-216), we will first factor each of the expressions in the numerator and denominator.
The factored form of x^(2)-64 is (x+8)(x-8).
The factored form of x^(2)-3x-54 is (x-9)(x+6).
The factored form of x^(2)-81 is (x+9)(x-9).
The factored form of 4x^(2)-12x-216 is (2x-18)(2x+12).
Now, we can substitute the factored forms back into the original expression:
((x+8)(x-8))/((x-9)(x+6))-((x+9)(x-9))/((2x-18)(2x+12))
Next, we will simplify the expression by canceling out common factors:
((x+8)(x-8))/((x-9)(x+6))-((x+9)(x-9))/(2(x-9)(2x+12))
= ((x+8)(x-8))/((x-9)(x+6))-(1/2)((x+9)/(2x+12))
= ((x+8)(x-8))/((x-9)(x+6))-(1/2)((x+9)/(2(x+6)))
= ((x+8)(x-8))/((x-9)(x+6))-(1/4)((x+9)/(x+6))
Now, we will find a common denominator and combine the two fractions:
= ((4(x+8)(x-8))-(x+9))/((4(x-9)(x+6)))
= ((4x^(2)-256)-(x+9))/((4(x-9)(x+6)))
= (4x^(2)-x-265)/((4(x-9)(x+6)))
This is the final factored form of the original expression.
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Test Prep Dono Dashbour e Unite Unit Activity: The Definite Integral 5 of 8 E Save Task 1 Print or You are learning the landscaping trade as an apprentice for 1plus1 Landscaping. Your supervisor wants you to calculate the area between the curved edge of a garden bed and the side of the house. Using the area, he can calculate the amount of mulch he will need for this job. Your supervisor has not yet provided an equation for the curve. Instead of waiting for the equation, you start a spreadsheet that will aid in the calculation. When you receive the equation, you'll have only a small amount of work to do in order to compute the area that he wants to cover with mulch. Part A Because you don't yet have an equation from your supervisor, choose one to help you set up the spreadsheet. ater, modify the spreadsheet when you receive the actual equation. Use spreadsheet software to: • Estimate the area that lies under the curvey -x + 1 between x = 0 and x = 10 Let the number of sub-intervals ben=5 . First calculate the area using left endpoints and then right endpoints
The area under the curve is 4.55 square units.
Here we have to find the area,
That lies under the curve y -x + 1 between x = 0 and x = 10
Therefore,
To estimate the area that lies under the curve y = -x + 1 between x = 0 and x = 10,
Use the Riemann Sum method,
Divide the interval [0, 10] into n subintervals of equal width,
And let Δx be the width of each subinterval.
Then, we can estimate the area under the curve as the sum of the areas of n rectangles with heights given by the function.
The formula for the Riemann Sum is,
⇒ Δx [f(0) + f(Δx) + f(2Δx) + ... + f((n-1)Δx)]
where Δx = (b-a)/n, a = 0, b = 10, and f(x) = -x + 1.
Let's choose,
n = 100 for a reasonably accurate estimate.
Then, Δx = (10-0)/100 = 0.1
Put it into the formula, we get.
⇒ 0.1[1 + 0.9 + 0.8 + ... + 0.1]
Evaluating the sum using the formula for the sum of an arithmetic series, we get:
⇒ 0.1(0.5)[2 + (99)(-0.9)]
Simplifying, we get,
⇒ 4.55
Therefore, the required area be 4.55 square units.
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Between the hours of 5 p.m. and 10 p.m., the hour hand of a clock moves through an arc of length 17 inches. How many inches long is the hour hand, to the nearest tenth of an inch? ASAPPPPP
Answer:
12:44
12:16
12:08
12:32
12:28
Correct answer:
12:16
Step-by-step explanation:
Explanation:
The path traveled by the tip of the minute hand over the course of one hour is a circle of radius r=6. The circumference of that circle is
C=2πr=2π⋅6=12π.
The tip has traveled 10 inches since noon, so the fraction of the circle traveled is 1012π,
and the number of minutes that have expired since noon is 1012π⋅60≈16.
Therefore, to the nearest minute, the time is 12:16.
oliver earns 361.98 for 5 days of the week
Answer:
Step-by-step explanation:23.80*34=809.20
A farmer purchased 245 acres of land for $4,700/acre. He paid
25% down and obtained a loan for the balance at 6.75% APR over a
20-year period. How much is the annual payment? (Simplify your
answer com
With an APR of 6.75% over a 20-year period, the annual payment for the loan will be $81,371.52.
To find the annual payment for the loan, we need to first find the total cost of the land and the amount of the loan.
Total cost of the land = 245 acres x $4,700/acre = $1,151,500
Down payment = 25% of total cost = 0.25 x $1,151,500 = $287,875
Loan amount = Total cost - Down payment = $1,151,500 - $287,875 = $863,625
Next, we need to use the loan amount, APR, and loan term to find the annual payment. We can use the following formula:
Annual payment = (Loan amount x APR) / (1 - (1 + APR)^(-Loan term))
Plugging in the values we have:
Annual payment = ($863,625 x 0.0675) / (1 - (1 + 0.0675)^(-20))
Annual payment = $58,294.69 / (1 - 0.2837)
Annual payment = $58,294.69 / 0.7163
Annual payment = $81,371.52
Therefore, the annual payment for the loan is $81,371.52.
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Estimate the solution of the linear system graphically and check the solution algebraically: A. A line graph showing 2 intersecting lines, the first line passes through the points (0, 5), (-1, 1), and (-3, -6) and the second line passes through the points (-3, 5), (-2, 3), (-1, 1), (0, -1), (1, -3), and (2, -5). B. A line graph showing 2 intersecting lines, the first line passes through the points (3, 4), (2, 1), (1, -2), and (0, -5) and the second line passes through the points (-5, 4), (-4, 3), (-3, 2), (-2, 1), (-1, 0), (0, -1), (1, -2), (2, -3), and (3, -4). C. A line graph showing 2 intersecting lines, the first line passes through the points (3, 4), (2, 1), (1, -2), (0, -5) and (-1, -8) and the second line passes through the points (5, 4), (4, 3), (3, 2), (2, 1), (1, 0), (0, -1), (-1, -2), (-2, -3), and (-3, -4). D. A line graph showing 2 intersecting lines, the first line passes through the points (2, 5), (1, 2), (0, -1), (-1, -4), and (-2, -7) and the second line passes through the points (-6, 5), (-5, 4), (-4, 3), (-3, 2), (-2, 1), (-1, 0), (0, -1), (1, -2), and (2, -3).
Using graph it is seen that the solution of the linear system is found as (-1, 1).
Explain about graphing linear system?It is as easy to graph two straight lines as it is a set of linear equations. The (x,y) arranged pair where it two lines intersect will be the answer when the lines being graphed (cross).When the crossing point has integer coordinates, the graphing method using graph paper may be helpful. However, it is less useful if the coordinates are still not integers. Use an algebraic optimization technique or get out your graphing calculator if it looks that its intersection point does not sit on the intersections of the grids on the graph paper.The points for the two intersecting lines are-
Red points: (0, 5), (-1, 1), and (-3, -6)
Green points: (-3, 5), (-2, 3), (-1, 1), (0, -1), (1, -3), and (2, -5).
Graph of there points are plotted.
Thus, it is seen that the solution of the linear system graphically is found as (-1, 1).
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The correct question is-
Estimate the solution of the linear system graphically and check the solution algebraically:
A line graph showing 2 intersecting lines, the first line passes through the points (0, 5), (-1, 1), and (-3, -6) and the second line passes through the points (-3, 5), (-2, 3), (-1, 1), (0, -1), (1, -3), and (2, -5).
What is the measurement of the diameter of the circle? (Round to the nearest tenth if needed)
Answer:
The answer is 13.
Step-by-step explanation:
First, we must find the hypotenuse for right angle:
[tex]c^{2} = a^{2} + b^{2}\\ \\\\c^{2} = 12^{2} + 5^{2} \\c^{2} 144 + 25 \\c^{2} = 169 \\c^{2} =\sqrt{169}\\c^{2} = 13[/tex]
What do we call the 3D shape below and what is it's SURFACE AREA? explain how you determined your answer and show your work 10mm 8mm 8mm
Hence, the shape is rectangular prism with the dimensions 10mm, 8mm, and 8mm has a surface area of 448mm2.
How is area of a prism determined?We must first calculate the surface area of each face of a rectangular prism with 10mm, 8mm, and 8mm measurements before adding them all up.
The top and bottom faces, which are both rectangles with measurements of 10 mm by 8 mm, are first measured for area:
Area of the top and bottom faces is equal to 2 (10 x 8 mm) or 160 mm2.
The area of the front and back faces, which are both rectangles measuring 10 mm by 8 mm, is then determined: Area of the front and back faces is equal to 128mm2 (8mm x 8mm).
The area of the two side faces, which are both rectangles with dimensions of 10 mm by 8 mm, is then determined: Area of the side sides is equal to 2 (10mm x 8mm) = 160mm2.
We add up the areas of all the faces to determine the overall surface area:
Whole surface area equals the sum of the areas of the top and bottom faces, the front and back faces, and the side faces.
Surface area total = 160 mm2 + 128 mm2 + 160 mm2
448 mm2 is the total surface area.
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Help I don't understand.
Answer:
Below
Step-by-step explanation:
f(-5) = 85 * .95^(-5) = 109.9 mg remaining after -5 hours this does not fit the context of the problem
( domain ( values of 'x') should be 0 ---> infinity)
f(24) = 85 * .95^24 = 24.8 mg remaining after 24 hours this does fit the context of the problem
The circumference of the base of the cone is 8.5π inches and height is 15. What is the volume of the cone in terms of π? Round to the nearest hundredth.
The volume of the cone in terms of π is [tex]90.312\ inches^{3}[/tex].
What is the volume of a cone?A cone is a three-dimensional body with a flat base that is connected to a pointed top.
The formula for the volume of a cone is :
[tex]Volume,V = \frac{\pi r^{2}H }{3}[/tex]
It is given that height, H = 15 inches.
The formula for the circumference of the base is = [tex]2\pi r[/tex]
So, we can say that :
[tex]2\pi r=8.5\pi[/tex]
[tex]r=\frac{8.5}{2} =2.25[/tex] inches
Therefore, the volume of the cone is, V:
[tex]=\pi \times 4.25^{2} \times 15\\ =90.312\ \text{inches}^{3}[/tex]
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a. 7cm 12cm and 13cm
b. 5cm 12cm and 13 cm
c. 4cm 8cm and 12cm
d. 5cm 10cm and 13cm
Answer: B : 5cm, 12cm and 13cm
Step-by-step explanation:
it says the amount of centimeters on each side on the ruler. its the small numbers
Find a positive value of c so that the following trinomial is factorable. x^(2)-4x+c
Find a positive value of c so that the following trinomial is factorable. [tex]x^2-4x+c[/tex], The value of [tex]c[/tex] will be given by [tex]c=4[/tex].
To find a positive value of c so that the trinomial [tex]x^2-4x+c[/tex] is factorable, we need to use the formula for the sum of two squares. This formula states that [tex](a-b)^2=a^2-2ab+b^2[/tex].
In this case, we can let [tex]a=x[/tex] and [tex]b=2[/tex], so the formula becomes [tex](x-2)^2=x^2-4x+4.[/tex]
Comparing this formula to the given trinomial, we can see that the value of c must be 4 in order for the trinomial to be factorable.
Therefore, the positive value of c that makes the trinomial [tex]x^2-4x+c[/tex] factorable is [tex]c=4[/tex].
In factored form, the trinomial becomes [tex](x-2)^2[/tex].
Answer: [tex]c=4.[/tex]
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Question 3 For each of the following, explain whether it is (always) true or (possibly) false. If true, you must explain why. If false, you must give a concrete counterexample (with numbers).
a) (1.5pts) If b is a linear combination of the columns of the matrix A, then the linear system Ax = b has a unique solution.
b) (1.5pts) If {u, v, w} is linearly independent, then {u+w, v + w} is linearly independent.
c) (1.5pts) If V = span{V1, V2, V3} and dim(V) = 2, then {V2, V3} is a basis of V.
a) (TRUE)
If b is a linear combination of the columns of the matrix A, then the linear system Ax = b has a unique solution.
b) (FALSE)
If {u, v, w} is linearly independent, then {u+w, v + w} is linearly independent.
c) (FALSE)
If V = span{V1, V2, V3} and dim(V) = 2, then {V2, V3} is a basis of V.
About linear combinationa) If b is a linear combination of the columns of matrix A, then the linear system Ax = b has a unique solution. This is (always) true because if b is a linear combination of the columns of matrix A, then it can be written as Ax.
Therefore, if A is invertible, then x = A^(-1)b is a unique solution to Ax = b.
b) If {u, v, w} is linearly independent, then {u+w, v+w} is linearly independent. This is (possibly) false because {u+w, v+w} is linearly dependent if u = -v = w.
Therefore, {u+w, v+w} is not linearly independent.
c) If V = span{V1, V2, V3} and dim(V) = 2, then {V2, V3} is a basis of V.
This is (possibly) false because {V2, V3} is a basis for V if and only if V2 and V3 are linearly independent and span(V).
However, dim(V) = 2 implies that V is a 2-dimensional subspace of R^3, so {V1, V2, V3} cannot be linearly independent.
Therefore, {V2, V3} is not necessarily a basis for V.
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Question 2 Consider the following set of vectors, where c is a scalar. A = {(2,2,0),(1,2,c),(0,0,c),(1,0,0)} a) (1pt) Explain why A is linearly dependent for any value of c. b) (2pts) For c = 0, give a geometric description of Vect (A). c) (2pts) Find all the values of c for which (4,1,3) is in Vect (A).
c = 3.
a) A is linearly dependent for any value of c because the vectors are not linearly independent.
This means that one of the vectors can be written as a linear combination of the others.
For example, the vector (1,2,c) can be written as (2,2,0) + (-1,0,c-0) = (1,2,c).
This means that the set of vectors is linearly dependent.
b) For c = 0, Vector (A) is the set of all linear combinations of the vectors (2,2,0), (1,2,0), (0,0,0), and (1,0,0).
This means that Vect (A) is the set of all points in the xy-plane, or the set of all vectors in R^2.c).
To find all the values of c for which (4,1,3) is in Vect (A),
we need to solve the equation (4,1,3) = a(2,2,0) + b(1,2,c) + d(0,0,c) + e(1,0,0) for the scalars a, b, d, and e.
This gives us the system of equations:4 = 2a + b + e1 = 2a + 2b3 = bc + dc.
Solving this system of equations gives us the values of a, b, d, and e in terms of c.
We can then use these values to find the values of c for which (4,1,3) is in Vect (A).
After solving the system of equations, we find that c = 3 and a = 1, b = -1, d = 0, and e = 2.
Therefore, the value of c for which (4,1,3) is in Vect (A) is c = 3.
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Select the correct slope and y-intercept for the following linear equation:
y=2x+7
The correct slope and y-intercept for the linear equation y=2x+7 are 2 and 7, respectively.
What is y-intercept?The y-intercept of a graph is the point where the graph crosses the y-axis. It is written as (0, b), where b is the y-intercept. The y-intercept is the value of y when x is equal to zero. It can be used to determine the equation of a line when two points on the line are known.
The slope of a linear equation is the coefficient of the x variable, which is 2 in this case. The y-intercept is the constant term, which is 7 in this case.
So, the slope is 2 and the y-intercept is 7.
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These data are a sample of the daily production rate of fiberglass boats from Dhaka Glass – 17 21 18 27 17 21 17 20 32 18 23
The company production manager feels that a standard deviation of more than 3 boats a day indicates unacceptable production-rate variations. Should the production manager be concerned about plant-production rates? Interpret your results.
Yes, the production manager should be concerned about production rate variations. Based on the data provided, the standard deviation of the daily production rate of fiberglass boats from Dhaka Glass is 4.6 boats, which is higher than the threshold of 3 boats a day set by the production manager. This indicates that there are significant variations in the production rate of fiberglass boats, which should be a cause for concern.
To further explain, the standard deviation measures the spread of a set of data. In this case, the data provided shows that the daily production rate of fiberglass boats can vary from 17 to 32 boats a day. The large standard deviation of 4.6 boats suggests that the daily production rate can vary significantly from the average, and this can lead to instability in production.
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0.2=1−(1−T1)30T=135 answer
The solutions to the given equations are T1 = 0.2 and T = 4.5.
To solve the given equations, we will use algebraic methods to isolate the variable on one side of the equation.
First, let's solve the equation 0.2=1−(1−T1).
0.2 = 1 - (1 - T1)
0.2 = 1 - 1 + T1
0.2 = T1
So, T1 = 0.2
Next, let's solve the equation 30T=135.
30T = 135
T = 135/30
T = 4.5
So, T = 4.5
Therefore, the solutions to the given equations are T1 = 0.2 and T = 4.5.
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Find the area of the triangle with the following vertices.
A(5, −1, -2), B(1, 1, 0), and C(3, 2, −1)
4 5
2 5
4 3
2 3
The area of the triangle with the given vertices is 4.47.
To find the area of the triangle with the given vertices, we can use the formula:
Area = (1/2) * |(B-A) x (C-A)|
Where "x" represents the cross product of two vectors.
First, we need to find the vectors B-A and C-A:
B-A = (1-5, 1-(-1), 0-(-2)) = (-4, 2, 2)
C-A = (3-5, 2-(-1), -1-(-2)) = (-2, 3, 1)
Next, we need to find the cross product of these two vectors:
(B-A) x (C-A) = (2*1 - 2*3, 2*(-2) - (-4)*1, (-4)*3 - 2*(-2)) = (-4, 0, -8)
Finally, we can find the area of the triangle by plugging in the values into the formula:
Area = (1/2) * |(-4, 0, -8)|
Area = (1/2) * √((-4)^2 + 0^2 + (-8)^2)
Area = (1/2) * √(80)
Area = (1/2) * 8.94
Area = 4.47
Therefore, the area of the triangle with the given vertices is 4.47.
Learn about Area of the triangle
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Write an expression for "8 minus w."
Answer:
8 - w
Step-by-step explanation:
In my opinion, an expression for eight minus w would be 8 - w. Thanks.
Hope it helps.
Express the following value in scientific notation.
0.0000547
Answer:
To express the value 0.0000547 in scientific notation, we need to move the decimal point to the right until there is only one non-zero digit to the left of the decimal point.
0.0000547 = 5.47 × 10^(-5)
The exponent -5 indicates that we moved the decimal point 5 places to the right.
What is the inequality
1.2 + m≤ 5.5
Answer: The inequality is:
1.2 + m ≤ 5.5
This inequality can be read as "the sum of 1.2 and m is less than or equal to 5.5."
To solve for m, you need to isolate it on one side of the inequality symbol.
1.2 + m ≤ 5.5
Subtract 1.2 from both sides:
m ≤ 5.5 - 1.2
Simplify:
m ≤ 4.3
Therefore, the solution to the inequality is m ≤ 4.3.
Step-by-step explanation:
Can you please give and explain please. I dont get it
Answer: a = 3, b = 2
Step-by-step explanation:
When a system of linear equations has no solution, they are parallel and do not share the same y-intercept.
Parallel lines have the same slope so a must equal 3.
The first equation's y-intercept is -2, so the only other option is b = 2.
Hope this helps!