AB is indeed the zero matrix, and we have found a 2 x 2 matrix B such that AB is the zero matrix.
When multiplying two matrices, we use the dot product of the rows of the first matrix and the columns of the second matrix to obtain the entries of the resulting matrix. In order for the product of two matrices to be the zero matrix, the dot product of each row of the first matrix with each column of the second matrix must be zero.
Let's construct a 2 x 2 matrix B such that AB is the zero matrix. We can use two different nonzero columns for B to obtain the zero matrix. Let's start with the first column of B:
B = [b1 b3]
[b2 b4]
We need to find values for b1, b2, b3, and b4 such that the dot product of each row of A with each column of B is zero. Let's start with the first row of A and the first column of B:
-12b1 + 4b2 = 0
We can rearrange this equation to solve for b2 in terms of b1:
b2 = 3b1
Now let's look at the second row of A and the first column of B:
15b1 - 5b2 = 0
Substituting the value of b2 from the first equation gives us:
15b1 - 5(3b1) = 0
Simplifying gives us:
0 = 0
This equation is always true, so we can choose any value for b1 and find the corresponding value for b2. Let's choose b1 = 1:
b2 = 3(1) = 3
Now let's look at the first row of A and the second column of B:
-12b3 + 4b4 = 0
We can rearrange this equation to solve for b4 in terms of b3:
b4 = 3b3
Now let's look at the second row of A and the second column of B:
15b3 - 5b4 = 0
Substituting the value of b4 from the first equation gives us:
15b3 - 5(3b3) = 0
Simplifying gives us:
0 = 0
This equation is always true, so we can choose any value for b3 and find the corresponding value for b4. Let's choose b3 = 2:
b4 = 3(2) = 6
Now we have the values for all of the entries of B:
B = [1 2]
[3 6]
Let's check our work by multiplying A and B:
AB = [-12 4] [1 2]
[ 15 -5] [3 6]
= [(-12)(1) + (4)(3) (-12)(2) + (4)(6)]
[(15)(1) + (-5)(3) (15)(2) + (-5)(6)]
= [0 0]
[0 0]
So AB is indeed the zero matrix, and we have found a 2 x 2 matrix B such that AB is the zero matrix.
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The scores of seven people playing a card game are listed below. 57, 97, 121, 81, 133, 66, 146 What is the interquartile range of the scores?
Answer:
To find the interquartile range (IQR) of the given scores, we first need to find the median of the dataset.
Finding the Median:
Arranging the scores in order, we get:
57, 66, 81, 97, 121, 133, 146
The median is the middle score. Since there are seven scores, the middle score is the fourth score, which is 97.
Finding the First Quartile:
The first quartile (Q1) is the median of the lower half of the dataset. In this case, the lower half of the dataset consists of the three scores 57, 66, and 81.
Arranging these scores in order, we get:
57, 66, 81
The median of this lower half is (66 + 81) / 2 = 73.5. This is the value of the first quartile, Q1.
Finding the Third Quartile:
The third quartile (Q3) is the median of the upper half of the dataset. In this case, the upper half of the dataset consists of the three scores 121, 133, and 146.
Arranging these scores in order, we get:
121, 133, 146
The median of this upper half is (133 + 121) / 2 = 127. This is the value of the third quartile, Q3.
Finding the Interquartile Range (IQR):
The interquartile range is the difference between the third quartile and the first quartile, so:
IQR = Q3 - Q1 = 127 - 73.5 = 53.5
Therefore, the interquartile range of the scores is 53.5
Step-by-step explanation:
Find the median of the dataset.
To find the median, we first need to arrange the scores in order from smallest to largest:
57, 66, 81, 97, 121, 133, 146
Since there are seven scores in the dataset, the median is the fourth score, which is 97.
Find the first quartile (Q1).
The first quartile is the median of the lower half of the dataset. To find the lower half of the dataset, we need to look at the scores that are less than or equal to the median. In this case, the lower half of the dataset consists of the scores 57, 66, and 81.
To find the median of the lower half of the dataset, we add the two middle scores together and divide by 2. So:
(66 + 81) / 2 = 73.5
Therefore, Q1 = 73.5.
Find the third quartile (Q3).
The third quartile is the median of the upper half of the dataset. To find the upper half of the dataset, we need to look at the scores that are greater than or equal to the median. In this case, the upper half of the dataset consists of the scores 121, 133, and 146.
To find the median of the upper half of the dataset, we add the two middle scores together and divide by 2. So:
(133 + 121) / 2 = 127
Therefore, Q3 = 127.
Find the interquartile range (IQR).
The interquartile range is the difference between Q3 and Q1. So:
IQR = Q3 - Q1 = 127 - 73.5 = 53.5
Therefore, the interquartile range of the scores is 53.5
The interquartile range (IQR) of the scores is 66.
How to find the interquartile range?To find the interquartile range (IQR), we first need to find the first quartile (Q1) and the third quartile (Q3).
Step 1: Put the scores in order from smallest to largest:
57, 66, 81, 97, 121, 133, 146
Step 2: Find the median (middle value) of the entire dataset:
The median is the middle value, which is 97 in this case.
Step 3: Divide the dataset into two halves:
The lower half of the dataset includes the scores 57, 66, 81, and 97.
The upper half of the dataset includes the scores 121, 133, and 146.
Step 4: Find the median (middle value) of each half:
The median of the lower half is (66+81)/2 = 73.5.
The median of the upper half is (133+146)/2 = 139.5.
Step 5: Find the interquartile range (IQR):
IQR = Q3 - Q1
Q1 = 73.5 and Q3 = 139.5
IQR = 139.5 - 73.5 = 66.
Therefore, the interquartile range (IQR) of the scores is 66.
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What is the absolute deviation for 62 in the data set? {80, 75, 25, 62, 68}
0
5
6
62
The absolute deviation for 612 in the given data set is 14.8.
What is the absolute deviation?The average distance between each data value and the mean is known as the mean absolute deviation (MAD) of a data set.
A measure of variance in a data set is the mean absolute deviation.
We may determine how "spread out" the values in a data collection are by looking at the mean absolute deviation.
So, get the mean as follows:
80+75+25+62+68)/5
310/5
62
Now, get the distance of each number as follows:
-----------------
| 80 | 18 |
| 75 | 13 |
|+ 25 | 37 |
| 62 | 0 |
| 68 | 6 |
-----------------
Now, get the distance:
18+13+37+0+6/5
14.8
Therefore, the absolute deviation for 612 in the given data set is 14.8.
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What is the absolute deviation for 62 in the data set?
{80, 75, 25, 62, 68}
A carpenter builds a rectangular bookcase that is 115 cm long and 76 cm tall. The carpenter uses two braces along the diagonals to support the bookcase.
What is the length of the one of the braces, to the nearest tenth of a centimeter?
Enter your answer as a decimal in the box.
cm
137.84 cm to the nearest tenth would be 137.8 cm
Help find centroid for these
a) The length of DP is,
DP = 11 Units
b) The lengths are,
RY = 12
YN = 24
YT = 10
BT = 30
IY = 10
And, IE = 15
TN = 25
And, IN = 50
What is mean by Triangle?A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.
Given that;
Triangle are shown in figure.
a) We have;
AM = MP
Hence,
12x - 4 = 4x + 12
12x - 4x = 4 + 12
8x = 16
x = 2
Hence, Lenght of DP is,
DP = 7x - 3
DP = 7×2 - 3
DP = 14 - 3
DP = 11
b) We know that;
RY : YN = 1 : 2
Here, RN = 36
Hence, We get;
36 = x + 2x
3x = 36
x = 12
Hence,
RY = x = 12
YN = 2x = 2 x 12 = 24
And, If BY = 20;
YT = 20/2
YT = 10
And, BT = 20 + 10 = 30
If EY = 5;
IY = 2 × 5 = 10
And, IE = 5 + 10 = 15
If IT = 25
Then, TN = 25
And, IN = 25 + 25 = 50
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Use the given function to evaluate \( f(0) \). Enter your answer with no spaces. \[ f(x)=\left\{\begin{array}{llr} 1+x & \text { for } & x
The given function is a piecewise function and we are asked to evaluate f(0). To do this, we need to find the expression that corresponds to x = 0. We can see that x < 2, so the expression we need to use is 1 + x.
Plugging in x = 0 into this expression gives us:
f(0) = 1 + 0 = 1
Therefore, the answer is 1.
In HTML format, the answer would be:
The given function is a piecewise function and we are asked to evaluate f(0). To do this, we need to find the expression that corresponds to x = 0. We can see that x < 2, so the expression we need to use is 1 + x.
Plugging in x = 0 into this expression gives us:
f(0) = 1 + 0 = 1
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Solve for θ if tanθ = 0.94. Round answer to the nearest degree.
Answer: θ=0.75448...πn
The function f(x) will model the roller coaster’s height from the ground in feet over time, measured in seconds since the ride started.
Answer:
1) 12<x<15 is: f(x) = -5(x-12)^2 + 80
2) 15<x<17 is: f(x) = 35
3) 27<x<30 is: f(x) = 2.5x-22.5
Step-by-step explanation:
See the attached image.
1) Plot all the lines as shown
2) Add the inequalities, which will produce the colored regions on DESMOS.
3) Assume that the function having the greatest value in each region is the function that determines the roller coaster's height (My assumption - it is not clear in the problem which function should dominate)
4) for the three regions listed with no corresponding function, identify the line having the greatest value. Thiose are the functions that are noted on the graph and in the answer box above.
5) Take a break
Pls give simple working
Screen shot this and then mark when it should go tyy
Answer:
Step-by-step explanation:
20 points!!!
The priestess at Horus’ temple has to go up a flight of 5 steps each day.The high priest has decreed that she will ascend the steps one or two at a time. She wants to know if she can do this a different way each day for a week.Is it possible? How many ways are there of ascending the steps?
please answer this i will mark you brainliest!
Answer:
We can use a recursive approach to solve this problem. Let's define a function $f(n)$ as the number of ways to ascend a flight of $n$ steps, where the priestess can only take one or two steps at a time.
To ascend a flight of 1 step, there is only one way to do it (take one step). Therefore, $f(1) = 1$.
To ascend a flight of 2 steps, there are two ways to do it (take two steps at once or take one step twice). Therefore, $f(2) = 2$.
For a flight of $n$ steps, the priestess can either take one step and ascend the remaining $n-1$ steps in $f(n-1)$ ways, or take two steps and ascend the remaining $n-2$ steps in $f(n-2)$ ways. Therefore, we have the recursive formula:
$$f(n) = f(n-1) + f(n-2)$$
Using this formula, we can calculate the number of ways to ascend a flight of 5 steps:
$$f(1) = 1$$
$$f(2) = 2$$
$$f(3) = f(2) + f(1) = 3$$
$$f(4) = f(3) + f(2) = 5$$
$$f(5) = f(4) + f(3) = 8$$
Therefore, there are 8 different ways for the priestess to ascend the steps. To find out if she can do this a different way each day for a week, we need to make sure that there are at least 7 different ways. Since there are 8 ways, it is possible for the priestess to ascend the steps in a different way each day for a week.
Determine the area enclosed by
y=(1/2)x+1
y= -(1/4)x+1
y=0
Please show your work, the lecture or the book didn't explain
how to do this. Thank you!
The area enclosed is 3 unit²
the line y=0 simply denotes the x axis. Now, the straight line y= (1/2)x+1 can be written as (x/(-2))+(y/1) = 1. So, this line touches x axis at (-2,0) and y axis at (0,1). the other line y= -(1/4)x+1 can be written as (x/4)+(y/1)=1. So, this line touches y axis at (4,0) and y axis at (0,1). so, it is evident that the triangle that got forms have the vertices of (4,0), (-2,0) and (0,1), the line joining (4,0) and (-2,0) being the base of the triangle.
so, the base of the triangle is 4+2= 6 unit and height of the triangle is 1 unit.
area of the triangle is 1/2* base* height= 1/2*6*1 = 3 unit^2.
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The following TI-
84
Plus display presents some sample statistics.
1-Var-Stats
x
=67
Σ
x=2291
Σx2
=182,361
Sx=8
σx=8.024961059
↓n=29
Part: 0 /
In this case, the mean of the data set is 67, the sum of all the data values is 2291, the sum of all the squared data values is 182,361, the sample standard deviation is 8, the population standard deviation is 8.024961059, and the sample size is 29.
The TI-84 Plus display presents sample statistics for a set of data. The "x" symbol represents the mean, or average, of the data set. The "Σx" symbol represents the sum of all the data values, and the "Σx2" symbol represents the sum of all the squared data values.
These statistics can be used to analyze and interpret the data set. For example, the mean can be used to determine the central tendency of the data, and the standard deviation can be used to measure the spread of the data.
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Solve for v (4)/(5v)=(1)/(10)-(3)/(2v) If there is more than one solt If there is no solution, click o
The solution for v in the equation (4)/(5v)=(1)/(10)-(3)/(2v) is v = 0.
To solve for v in the equation (4)/(5v)=(1)/(10)-(3)/(2v), we need to use the following steps:
Step 1: Multiply both sides of the equation by the common denominator of 10v to get rid of the fractions. This gives us:
(4)(10v)/(5v) = (1)(10v)/(10) - (3)(10v)/(2v)
Step 2: Simplify the equation by canceling out the common terms. This gives us:
8v = v - 15v
Step 3: Combine like terms on the right side of the equation. This gives us:
8v = -14v
Step 4: Add 14v to both sides of the equation to isolate v on one side. This gives us:
22v = 0
Step 5: Divide both sides of the equation by 22 to solve for v. This gives us:
v = 0/22
Step 6: Simplify the fraction to get the final answer. This gives us:
v = 0
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X-15<-6=9 what is the answer pls
The solution set of the inequality x-15≤6/9 is x≤47/3.
What is Inequality?a relationship between two expressions or values that are not equal to each other is called 'inequality.
The given inequality is x-15≤6/9
x minus fifteen lesser than or equal to six by nine.
x is the variable and minus is the operator,
x-15≤6/9
On the right side the numerator and denominator is divided by 3
x-15≤2/3
Add 15 on both sides
x≤2/3+15
x less than or equal to two by three plus fifteen.
x≤2+3(15)/3
When three is multiplied with fifteen we get 45.
x≤45+2/3
So when forty five and two are added we get 47.
x≤47/3
Hence, the solution set of the inequality x-15≤6/9 is x≤47/3.
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Complete quesstion,
Find the solution set of the inequality x-15≤6/9
please help need handwritten work write out the answer step by step explination please help
1- 20x12= 240
2- 12x32= 384
3- 21x21= 441
50/4x-12 + x-4/x^2+x-12=x/2
The value of [tex]x[/tex] that satisfies the equation is [tex]x = 6[/tex].
How can we solve an equation with a fraction and a quadratic expression?
To solve an equation with a fraction and a quadratic expression, we can first try to simplify the fractions by finding a common denominator. Then, we can move all the terms to one side of the equation and simplify it into a quadratic equation. Finally, we can solve the quadratic equation using factoring or the quadratic formula.
Find the value of [tex]x[/tex]:
The given equation is:
[tex]\frac{50}{4x-12}+\frac{x-4}{x^2+x-12}=\frac{x}{2}[/tex]
The first step is to find the LCM of the denominators. Factoring the denominator [tex]x^2+x-12[/tex], we get:
[tex]x^2+x-12=(x+4)(x-3)[/tex]
So the LCM of the denominators is [tex](4x-12)(x+4)(x-3)[/tex]. Multiplying both sides of the equation by this LCM, we get:
[tex]50(x+4)(x-3)+(x-4)(4x-12)=\frac{x}{2}(4x-12)(x+4)(x-3)[/tex]
Expanding and simplifying both sides, we get:
[tex]6x^3-26x^2-13x+56=0[/tex]
Factoring out [tex](x-4)[/tex], we get:
[tex](x-4)(6x^2-10x-14)=0[/tex]
Solving for [tex]x[/tex] using the quadratic formula, we get:
[tex]x=\frac{5\pm\sqrt{29}}{3} \text{ or } x=4[/tex]
However, we need to check if any of these solutions make the denominator zero, which would be undefined. Checking each of the possible solutions, we find that [tex]x=4[/tex] is the only solution that does not make any of the denominators zero.
Therefore, the solution is [tex]x=4[/tex].
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please help me: I have inserted the question below:
The probability that the person chosen at random is a boy is 8/13 and the probability that they are between 120 cm and 130 cm tall is 6/10.
What is a polygon?Polygon is a closed figure that consists of three or more straight lines. It is a two-dimensional shape with straight sides and angles. Polygons are used to construct many shapes in geometry such as triangles, rectangles, squares and many more. Polygons are used in many fields such as computer graphics, navigation, engineering and architecture.
The frequency polygon show that there are more boys than girls in the class. This can be seen from the higher peak on the boys side of the graph. The total number of boys is 8 and the total number of girls is 5. This gives us a probability of 8/13 that the person chosen at random is a boy.
To work out the probability that the person is between 120 cm and 130 cm tall, we must first count the number of individuals in the class in this height range. From the graph, we can see that there are 6 boys and 4 girls in this range. This gives us a probability of 6/10 that the person chosen at random is between 120 cm and 130 cm tall.
In conclusion, the probability that the person chosen at random is a boy is 8/13 and the probability that they are between 120 cm and 130 cm tall is 6/10.
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What am I missing to get full marks
The required cost of the cans of weedkiller needed to cover lawn are £ 47.4.
What is Trapezoid and formula for area?The formula A = 12 (a Plus b) h is used to calculate the area of a trapezoid, where a and b are the bases (parallel sides) and h is the height (the angle between the bases).
According to Question:We have;
Dimensions of Trapezoid; a = 20, b = 12, Height = h
So;
[tex]$Area = \frac{(a+b)h}{2}$[/tex]
For h, Using Pythagoras theorem;
17² = 8² + h²
h = 15 m
Then,
[tex]$Area = \frac{(12+20)15}{2}$[/tex]
Area = 240 Sq meter
Then,
100 Sq meter = £19.75
For 240 Sq meter
= £19.75(2.4)
= £ 47.4
Thus, required cost is £ 47.4.
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Suppose that v1, v2, v3, v4 is a basis for vector space V . Is
it true that v1 + 2v2, v2 + 2v3, v4 is also a basis for V ?
It is true that v1 + 2v2, v2 + 2v3, v4 is also a basis for V.
Suppose that v1, v2, v3, v4 is a basis for vector space V. A basis for a vector space is a set of vectors that are linearly independent and span the entire vector space. In other words, any vector in the vector space can be written as a linear combination of the basis vectors.
In this case, the vectors v1 + 2v2, v2 + 2v3, and v4 are linear combinations of the original basis vectors v1, v2, v3, and v4. Therefore, they are also linearly independent and span the entire vector space V. As a result, the set {v1 + 2v2, v2 + 2v3, v4} is also a basis for V.
In general, any set of vectors that are linearly independent and span the entire vector space can be considered a basis for that vector space. Therefore, it is true that v1 + 2v2, v2 + 2v3, v4 is also a basis for V.
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For which two functions does f(x)→+∞ as x→+∞?
Explain your reasoning.
f(x)=14x+3
g(x)=−35x−8
h(x)=2x−1
HI!!! i really need help with these three problems :)
use the distributary property to remove the parentheses 4(5+x)
Answer:
20+4x
Step-by-step explanation:
4*5=20
4*x=4x
Add the rational expressions. Write your answer in its fully factored form. (c^(2)-9)/(c^(2)+15c+56)+(c^(2)+16c+63)/(8c^(2)+120c+448)
The answer of the expression is (9c^(3)+79c^(2)+82c+369)/(8(c+7)(c+8)).
To add the rational expressions, we need to find a common denominator. The denominators of the two expressions are (c^(2)+15c+56) and (8c^(2)+120c+448), which can be factored into (c+7)(c+8) and 8(c+7)(c+7), respectively. The common denominator is then 8(c+7)(c+8).
Next, we need to multiply each expression by the appropriate factor to get the common denominator. The first expression is multiplied by 8(c+8)/(8(c+8)) and the second expression is multiplied by (c+7)/(c+7). This gives us:
(8(c+8)(c^(2)-9))/(8(c+7)(c+8)) + ((c+7)(c^(2)+16c+63))/(8(c+7)(c+8))
Simplifying the numerators gives us:
(8c^(3)+56c^(2)-72c-72)/(8(c+7)(c+8)) + (c^(3)+23c^(2)+154c+441)/(8(c+7)(c+8))
Combining the numerators and simplifying gives us:
(9c^(3)+79c^(2)+82c+369)/(8(c+7)(c+8))
This is the fully factored form of the sum of the rational expressions.
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a class consist of 12 boys of whom 5 are perfects. how many committee of 8 can be formed if its to have; a) 3 prefects b) at least 3 prefects
Step-by-step explanation:
a) To form a committee of 8 with 3 prefects, we need to choose 3 prefects from the 5 available prefects, and 5 non-prefects from the remaining 7 boys. We can do this by using the combination formula:
Number of ways = (Number of ways to choose 3 prefects) × (Number of ways to choose 5 non-prefects)
Number of ways to choose 3 prefects from 5 = C(5, 3) = 10
Number of ways to choose 5 non-prefects from 7 = C(7, 5) = 21
Therefore, the total number of committees of 8 with 3 prefects that can be formed is:
Number of ways = 10 × 21 = 210
b) To form a committee of 8 with at least 3 prefects, we need to consider two cases: one where we choose exactly 3 prefects, and one where we choose all 5 prefects. We can calculate the number of ways for each case using the combination formula:
Number of ways to choose exactly 3 prefects and 5 non-prefects = C(5, 3) × C(7, 5) = 210
Number of ways to choose all 5 prefects and 3 non-prefects = C(5, 5) × C(7, 3) = 35
Therefore, the total number of committees of 8 with at least 3 prefects that can be formed is:
Number of ways = (Number of ways to choose exactly 3 prefects and 5 non-prefects) + (Number of ways to choose all 5 prefects and 3 non-prefects)
Number of ways = 210 + 35 = 245
A 5-year Treasury bond has a 3.65% yield. A 10-year Treasury
bond yields 6.3%, and a 10-year corporate bond yields 9.75%. The
market expects that inflation will average 3% over the next 10
years (IP10
The real yeild is 0.65%.
The Estimated 10-year Treasury bond yield is 3.65%.
The 10-year Treasury bond yield can be estimated using the 5-year Treasury bond yield and the expected inflation rate of 3%.
This is done by calculating the real yield, which is the difference between the nominal yield and the expected inflation rate.
The 10-year Treasury bond yield can be estimated by adding the real yield of the 5-year Treasury bond to the expected inflation rate of 3%.
Real yield = Nominal yield - Expected inflation rate
Real yield (5-year Treasury bond) = 3.65% - 3% = 0.65%
Estimated 10-year Treasury bond yield = 0.65% + 3% = 3.65%
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The diameter of a circle is 9 in. Find its area to the nearest tenth.
schoology
help
maths i need it done soon
Answer:
[tex] = 3kd + 2d + 5r + 6kr[/tex]
Step-by-step explanation:
[tex]7dk + 6kr + 4d + 8r - 4 kd - 2 d - 3r \\ = 3kd + 2d + 5r + 6kr[/tex]
find the ordered pair that is a member of both -2x-4y=14 and 5y+2x=-4 or indicate if it does not exist or there are infinite possibilities
The ordered pair that is a member of both equations is (-27/7, -11/7).
To find the ordered pair that is a member of both equations, we need to solve the system of equations. We can do this by using the elimination method.
First, we will multiply the first equation by 2 and the second equation by -4 to eliminate the x variable:
-4x - 8y = 28
-20y - 8x = 16
Next, we will add the two equations together:
-28y = 44
Now we can solve for y:
y = -44/28
y = -11/7
Now we can plug this value of y back into one of the original equations to solve for x:
-2x - 4(-11/7) = 14
-2x + 44/7 = 14
-2x = 14 - 44/7
-2x = 54/7
x = -27/7
Therefore, the ordered pair that is a member of both equations is (-27/7, -11/7).
Answer: The ordered pair that is a member of both equations is (-27/7, -11/7).
To know more about ordered pairs, refer here:
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The perimeter of a rectangle is 40cm. If the length is 3times the breadth, calculate the area of the rectangle
Answer:
Step-by-step explanation:
Let [tex]l[/tex] be length, [tex]b[/tex] be breadth.
[tex]l=3b[/tex] [tex](a)[/tex] (the length is 3times the breadth)
[tex]2l+2b=40[/tex] [tex](b)[/tex] (perimeter is 40)
Now we must solve these to find [tex]l[/tex] and [tex]b[/tex]:
Substitute [tex](a)[/tex] into [tex](b)[/tex] :
[tex]2(3b)+2b=40[/tex]
[tex]6b+2b=40[/tex]
[tex]8b=40[/tex]
[tex]b=5cm[/tex]
Substitute [tex]b=5[/tex] into [tex](a)[/tex]:
[tex]l=3\times 5=15cm[/tex]
Find area:
[tex]A=lb=15 \times 3=45cm^2[/tex]
In a statistics class, a teacher had the students complete an activity in which they grabbed as many bite-sized pretzels as they could with their dominant hand, without crushing them. The teacher then measured their handspan in centimeters. A regression analysis was completed and the value for s was found to be 3.05.
Which of the following is the best interpretation of s?
The average residual is about 3.05 pretzels.
The average residual is about 3.05 centimeters.
The average handspan of a student is 3.05 centimeters.
The average number of pretzels a student could grab is 3.05 pretzels.
Solve the equation. Then check your solution. x minus 4 = 2 a. –6 c. 7 b. 6 d. –2 Please select the best answer from the choices provided A B C D
Answer:
b. 6
Step-by-step explanation:
The equation x - 4 = 2 tells us that if we subtract 4 from a number (x), we'll have 2. Let's add 4 to both sides of the equation:
x - 4 = 2
+4 +4
x = 6
X is 6