Determine if the triangles are similar.

A. Yes, SSS
B. Yes, SAS
C. Yes, AA
D. No, not similar

The number of students who are expected to be wearing the spirit wear  out of 500 total students are 200 students.

Since it is given that there are 500 students studying in a school and 4 out of 10 students are expected to wear spirit wear. This means that the ratio of  students wearing spirit wear to students wearing normal clothes is 4:10. Now, if we consider the ratio for total number of students that is 500 and the expected number of students wearing spirit dress are equal to x, then following relation is obtained.

Number of students wearing spirit dress out of 10 = 4

Number of students wearing spirit dress out of 1 = 4/10

Number of students wearing spirit dress out of 500 = (4/10)*500

∴ Number of students wearing spirit dress out of 500 = 200 students

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Answer:

Hey there! [tex]x + y = 500 \ 215x + 615y = 187500[/tex]Answer is the first option. Hope this helps.

Step-by-step explanation:

just did it

Answer:

Below

Step-by-step explanation:

Slope, m, is equal to 'rise'  (change in y) divided by 'run' ( change in 'x')

when going L to R

change in x is from -2 to 2  is a change of   +4

change in y is 24 to 8     a change of  - 16

slope = -16/4 = - 4

First, we need to convert the maximum weight that the mail carrier is allowed to carry from pounds to ounces:

30 pounds = 30 x 16 ounces = 480v ounces

Then, we can divide the maximum weight by the weight of one letter:

480 ounces / 12 ounces per letter = 40 letters

Therefore, the mail carrier is able to carry 40 letters.

So, the correct answer is option C: 40 letters.

Answer:

C 40

Step-by-step explanation:

The perimeter of the given triangle MNP is 65.

A regular figure with n-sides has n equal sides in it, and they are the only parts of it(that means, nothing more than those equal lengthened n sides).

Suppose that length of each side of that figure be of u units, then we have the perimeter as:

P=u+u+u+u+u+u......=n*u

units.

We are given that;

Side MN=5x-34, QR=25, QS=22, RS=x+4

Now,

5x + x - 34 + 4 = 22

6x - 30 = 22

6x - 30 + 30 = 22 + 30

6x = 52

6x/6 = 52/6

x = 8.67

P= 5*8-34+25+22+8+4

=40-34+47+12

=65

Therefore, the perimeter of the triangle will be 65.

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The product AB is not equal to the product BA. This demonstrates the non-commutativity of matrix multiplication.

Matrix multiplication is non-commutative, which means that the product of two matrices can be different depending on the order in which they are multiplied. In other words, AB is not always equal to BA. Let's find the product of the given matrices A and B in both orders to demonstrate this.

First, let's find the AB Product:
AB = [[1,-4],[-2,4]] * [[-4,0],[4,3]]
= [(1 * -4) + (-4 * 4), (1 * 0) + (-4 * 3), (-2 * -4) + (4 * 4), (-2 * 0) + (4 * 3)]
= [[-20, -12], [16, 12]]

Now, let's find the product BA:
BA = [[-4,0],[4,3]] * [[1,-4],[-2,4]]
= [(-4 * 1) + (0 * -2), (-4 * -4) + (0 * 4), (4 * 1) + (3 * -2), (4 * -4) + (3 * 4)]
= [[-4, 16], [2, 4]]

As we can see, the product AB is not equal to the product BA. This demonstrates the non-commutativity of matrix multiplication.

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By substituting the extreme points of the feasible set into the objective function and comparing the values, (x,y)=(1,1) is an optimal solution for the given LP problem.

The given LP problem is to maximize f(x,y)=3x+19y subject to the constraint set of the feasible set. The extreme points of the feasible set are (0,0), (1,0), (0,1), and (1,1).

To prove that (x,y)=(1,1) is an optimal solution, we need to show that f(x,y) is maximized at this point. We can do this by plugging in the extreme points into the objective function and comparing the values.

At (0,0), f(x,y) = 3(0) + 19(0) = 0

At (1,0), f(x,y) = 3(1) + 19(0) = 3

At (0,1), f(x,y) = 3(0) + 19(1) = 19

At (1,1), f(x,y) = 3(1) + 19(1) = 22

From these calculations, we can see that f(x,y) is maximized at (1,1), with a value of 22. Therefore, (x,y)=(1,1) is an optimal solution for this LP problem.

In conclusion, by plugging in the extreme points of the feasible set into the objective function and comparing the values, we have proved that (x,y)=(1,1) is an optimal solution for the given LP problem.

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Answer:

744417

Step-by-step explanation:

Answer:

744,417

Step-by-step explanation:

Add the terms together

The given equation is true. The solution has been obtained by using arithmetic operations.

It is believed that the four fundamental operations, often referred to as "arithmetic operations", can explain all real numbers. The four mathematical operations that produce the quotient, product, sum, and difference are divide, multiply, add, and subtract.

We are given an equation as (1.8 x 3) x (2.1 x 7) = (3 x 7) x (1.8 x 2.1)

In order to see whether it is true or false, we will solve both the sides.

So, first solving L.H.S., we get

⇒(1.8 x 3) x (2.1 x 7)

⇒5.4 x 14.7

⇒79.38

Now, solving R.H.S., we get

⇒(3 x 7) x (1.8 x 2.1)

⇒21 x 3.78

⇒79.38

Since, L.H.S. = R.H.S., so the given equation is true.

Hence, the given equation is true.

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The 14th term of the given geometric sequence is -40,960.

A geometric progression is a sequence of numbers in which each term after the first is obtained by multiplying the preceding term by a constant factor called the common ratio. It is a type of exponential growth or decay.

The given sequence is a geometric sequence with the first term (a₁) as 5 and the common ratio (r) as -2. To find the 14th term, we can use the formula for the nth term of a geometric sequence, which is:

[tex]a_n = a_1 \times r^{(n-1)}[/tex]

Substituting the values of a₁ and r, we get:

[tex]a_n = 5\times -2^{(n-1)}[/tex]

To find the 14th term, we can substitute n = 14 and simplify:

[tex]a_{14} = 5 \times (-2)^{(14-1)}[/tex]

[tex]a_{14} = 5 \times (-2)^{(13)}[/tex]

[tex]a_{14} = 5 \times -8192[/tex]

a₁₄ = -40,960

Therefore, the 14th term of the given geometric sequence is -40,960.

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The general solution to the differential equation y''+4y=0 is y(x) = c₁ cos ₂x + c₂ sin ₂x and the value of β is 2.

To find the value of β, we substitute the general solution into the differential equation and solve for β. We start by finding the first and second derivatives of y(x):

y'(x) = -c₁β sin βx + c₂β cos βx

y''(x) = -c₁β² cos βx - c₂β² sin βx

Substituting these expressions into the differential equation, we get:

-c₁β² cos βx - c₂β² sin βx + 4(c₁ cos βx + c₂ sin βx) = 0

Simplifying this equation, we get:

(c₁β² + 4c₁) cos βx + (c₂β² + 4c₂) sin βx = 0

This equation must hold for all values of x, which means that the coefficients of cos βx and sin βx must both be zero. Therefore, we have the following system of equations:

c₁β² + 4c₁ = 0

c₂β² + 4c₂ = 0

We can solve for β by dividing the second equation by c₂ and substituting c₁ = -4β²/c₂ from the first equation:

β² = -4c₁/c₂ = 4

Since β>0, we take the positive square root of 4, which gives β=2.

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The vectors v1 = {1,2,0}, v2 = {1,0,1}, and v3 = {1,a,4} are linearly independent if a = 8/3, t and  linearly dependent for a = 2, and linearly independent for a = 8/3.

For the vectors to be linearly independent, we need to check if the following system of equations has a unique solution:

c1v1 + c2v2 + c3v3 = 0

where c1, c2, c3 are constants, and 0 is the zero vector.

Substituting the given vectors, we get the following system of equations:

c1 + c2 + c3 = 0 (1)

2c1 + ac3 = 0 (2)

c2 + 4c3 = 0 (3)

If we can find values of a for which this system of equations has a non-trivial solution, then the vectors are linearly dependent. Otherwise, they are linearly independent.

To find such values of a, we need to solve the system of equations and find the conditions under which it has non-trivial solutions.

From equations (2) and (3), we get:

c2 = -4c3 (4)

2c1 + ac3 = 0 (5)

Substituting equations (1) and (4) into equation (5), we get:

2(-c2 - c3) + ac3 = 0

Simplifying, we get:

(-2 + a)c3 - 2c2 = 0

Substituting equation (4), we get:

(-2 + a)c3 + 8c3 = 0

Solving for c3, we get:

c3 = 0 if a = 2

c3 = 0 if a = 8/3

For a = 2, the system reduces to:

c1 + c2 = 0

2c1 = 0

c2 + 4c3 = 0

This system has a non-trivial solution: c1 = 0, c2 = 1, c3 = -1/4.

Therefore, the vectors are linearly dependent for a = 2.

For a = 8/3, the system reduces to:

c1 + c2 + c3 = 0

(8/3)c3 = 0

c2 + 4c3 = 0

This system has only the trivial solution: c1 = c2 = c3 = 0.

Therefore, the vectors are linearly independent for a = 8/3.

In summary, the given vectors are linearly dependent for a = 2, and linearly independent for a = 8/3.

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The binomial theorem holds for any integer \( n \geq 1 \) and any real numbers \( x \) and \( y \).

The binomial theorem states that for any positive integer \( n \) and any real numbers \( x \) and \( y \), \[(x+y)^n = \sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k\]where \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \) is the binomial coefficient.

To prove the identity \[ \sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k = x^n + nx^{n-1}y + \frac{n(n-1)}{2}x^{n-2}y^2 + \cdots + y^n \] we can use differentiation, integration, and multiplication by \( x \) or \( y \).

First, let's differentiate both sides of the equation with respect to \( x \): \[\frac{d}{dx} \left( \sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k \right) = \frac{d}{dx} \left( x^n + nx^{n-1}y + \frac{n(n-1)}{2}x^{n-2}y^2 + \cdots + y^n \right)\]Using the power rule for differentiation, we get \[\sum_{k=0}^{n} \binom{n}{k}(n-k)x^{n-k-1}y^k = nx^{n-1} + n(n-1)x^{n-2}y + \frac{n(n-1)(n-2)}{2}x^{n-3}y^2 + \cdots\]Next, we can multiply both sides of the equation by \( x \): \[\sum_{k=0}^{n} \binom{n}{k}(n-k)x^{n-k}y^k = nx^{n} + n(n-1)x^{n-1}y + \frac{n(n-1)(n-2)}{2}x^{n-2}y^2 + \cdots\]Finally, we can integrate both sides of the equation with respect to \( x \): \[\int \left( \sum_{k=0}^{n} \binom{n}{k}(n-k)x^{n-k}y^k \right) dx = \int \left( nx^{n} + n(n-1)x^{n-1}y + \frac{n(n-1)(n-2)}{2}x^{n-2}y^2 + \cdots \right) dx\]Using the power rule for integration, we get \[\sum_{k=0}^{n} \binom{n}{k}\frac{(n-k)}{n-k+1}x^{n-k+1}y^k = \frac{n}{n+1}x^{n+1} + \frac{n(n-1)}{n+1}x^{n}y + \frac{n(n-1)(n-2)}{2(n+1)}x^{n-1}y^2 + \cdots\]Simplifying the coefficients and combining like terms, we get \[\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k = x^n + nx^{n-1}y + \frac{n(n-1)}{2}x^{n-2}y^2 + \cdots + y^n\]which is the identity we were trying to prove. Therefore, the binomial theorem holds for any integer \( n \geq 1 \) and any real numbers \( x \) and \( y \).

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The interest earned each year is $25 and the total amount at the end of each year would be $525, $550, $575, $600, and $625 respectively.

What is simple interest?

Simple interest is a method of calculating interest on a loan or investment where the interest is calculated only on the principal amount. It is based on a fixed percentage of the principal amount and does not take into account any interest earned on previous interest payments.

The formula for calculating simple interest is I = PRT, where I is the interest, P is the principal amount, R is the annual interest rate, and T is the time period in years.

Using the simple interest formula:

I = P * r * t

where I is the interest earned, P is the principal or initial deposit, r is the annual interest rate, and t is the time in years.

For an initial deposit of $500 at an annual interest rate of 5%, the interest earned each year and the total amount at the end of each year would be:

Year 1:

I = 500 * 0.05 * 1 = $25

Total = 500 + 25 = $525

Year 2:

I = 500 * 0.05 * 1 = $25

Total = 525 + 25 = $550

Year 3:

I = 500 * 0.05 * 1 = $25

Total = 550 + 25 = $575

Year 4:

I = 500 * 0.05 * 1 = $25

Total = 575 + 25 = $600

Year 5:

I = 500 * 0.05 * 1 = $25

Total = 600 + 25 = $625

Therefore, the interest earned each year is $25 and the total amount at the end of each year would be $525, $550, $575, $600, and $625 respectively.

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Answer:

19,690 since it is the nearest ten thousandth it would be 20,000

Step-by-step explanation:

subtract 78,920-59,230 to get 19,690 since we have to round up it would be 20,000

Answer: The difference ( rounded to 10,000) is 20,000

Step-by-step explanation: 78,920 and 59,230 both rounded to the nearest 10,000 is 80,000 and 60,000. The difference between the two is 20,000  

The problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

The problem can be solved using the simplex method, and verified using the graphical method. Here are the steps:

Convert the problem to standard form by introducing slack variables:
Min Z = -2X1 - 4X2 - 3X3 + 0S1 + 0S2 + 0S3
St. X1 + 3X2 + 2X3 + S1 = 30
X1 + X2 + X3 + S2 = 24
3X1 + 5X2 + 3X3 + S3 = 60
Xi, Si >= 0

Set up the initial simplex tableau:
| 1 3 2 1 0 0 30 |
| 1 1 1 0 1 0 24 |
| 3 5 3 0 0 1 60 |
| 2 4 3 0 0 0 0 |

Identify the entering variable (most negative coefficient in the objective row): X2

Identify the leaving variable (smallest ratio of RHS to coefficient of entering variable): S1

Pivot around the intersection of the entering and leaving variables to create a new tableau:
| 0 2 1 1 -1 0 6 |
| 1 0 0 -1 2 0 18 |
| 0 0 0 5 -5 1 30 |
| 2 0 1 -2 4 0 36 |

Repeat steps 3-5 until there are no more negative coefficients in the objective row. The final tableau is:
| 0 0 0 7/5 -3/5 0 18 |
| 1 0 0 -1/5 2/5 0 6 |
| 0 0 1 1/5 -1/5 0 6 |
| 0 0 0 -2 4 0 24 |

The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

To verify the solution using the graphical method, plot the constraints on a graph and find the feasible region. The optimal solution will be at one of the corner points of the feasible region. By checking the values of the objective function at each corner point, we can verify that the optimal solution found using the simplex method is correct.

In conclusion, the problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

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75. To find the linear speed of a point on the equator, we need to use the formula for the circumference of a circle: C = 2πr. The radius of the earth is 4000 mi, so the circumference of the earth at the equator is C = 2π(4000) = 8000π mi. The earth rotates one revolution every 24 hours, so the linear speed of a point on the equator is 8000π/24 = 333.33π mi/hr ≈ 1047.2 mi/hr.

76. To find the linear speed of the earth in its orbit, we need to use the same formula for the circumference of a circle, but this time the radius is the distance from the earth to the sun, which is 93,000,000 mi. The circumference of the earth's orbit is C = 2π(93,000,000) = 186,000,000π mi. The earth traverses its orbit every 365.25 days, or 8766 hours. So the linear speed of the earth in its orbit is 186,000,000π/8766 = 21,174.6π mi/hr ≈ 66,555.8 mi/hr.

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Answer:

If I had to take a guess I'd say the price of the milkshakes is $4.50 and the price of the sundaes are $2.75 but I'm not 100% sure.

Answer:

Step-by-step explanation:

8m + 6i = 56.50

4m + 2i = 23.50

8m + 6i = 56.50

-8m - 4i =-47.00

2i = 9.50

i = $4.75 ice cream sundae

4m + 2(4.75) = 23.50

4m + 9.50 = 23.50

4m = 14

m = 3.50 milkshake

The solution for \(\tan \theta\) is \(\frac{v\sqrt{3}}{u\sqrt{1-\frac{1}{3} v^{2}}}\).

To solve for \(\tan \theta\), we need to simplify the equation by combining the fractions and simplifying the square roots.

First, let's combine the fractions on the right side of the equation:
\[ \tan \theta=\frac{v}{\sqrt{3}} \cdot \frac{3}{\sqrt{9-3 v^{2}}} \cdot \frac{\sqrt{3}}{u} \]

Next, we can simplify the square roots:
\[ \tan \theta=\frac{v}{\sqrt{3}} \cdot \frac{3}{\sqrt{9}\sqrt{1-\frac{1}{3} v^{2}}} \cdot \frac{\sqrt{3}}{u} \]

\[ \tan \theta=\frac{v}{\sqrt{3}} \cdot \frac{3}{3\sqrt{1-\frac{1}{3} v^{2}}} \cdot \frac{\sqrt{3}}{u} \]

Now we can simplify the fractions:
\[ \tan \theta=\frac{v}{\sqrt{3}} \cdot \frac{1}{\sqrt{1-\frac{1}{3} v^{2}}} \cdot \frac{\sqrt{3}}{u} \]

Finally, we can combine the terms to get the final expression for \(\tan \theta\):
\[ \tan \theta=\frac{v\sqrt{3}}{u\sqrt{1-\frac{1}{3} v^{2}}} \]

Therefore, the solution for \(\tan \theta\) is \(\frac{v\sqrt{3}}{u\sqrt{1-\frac{1}{3} v^{2}}}\).

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The zeros of the polynomial f(x) = x4 - 8x3 + 18x2 + 16x - 40 are 4 + 2i, 4 - 2i, -2, and -8.

Given that 4 + 2i is one of its zeros, we can use the fact that the product of the zeros of a polynomial is equal to the product of the coefficients of the polynomial.

We can use this fact to find all of the zeros of the polynomial:

1. We can calculate the product of the coefficients of the polynomial:
( -40 ) * ( 16 ) * ( 18 ) * ( -8 ) = -442368

2. We can calculate the product of the known zero and its conjugate:
( 4 + 2i ) * ( 4 - 2i ) = 16

3. We can divide the product of the coefficients by the product of the known zero and its conjugate:
-442368 / 16 = -27735

4. This is the product of the other zeros:
-27735 = x^(2) + 8x + 1135

5. We can use the quadratic formula to solve for the remaining zeros:
x = (-8 +/- sqrt(64 - 4*1*1135))/2

x1 = (-8 + sqrt(144 - 4640))/2
x2 = (-8 - sqrt(144 - 4640))/2

Therefore, the remaining zeros of the polynomial f(x) are:
x1 = -5 + i7
x2 = -5 - i7
To find all the zeros of the polynomial f(x) = x4 - 8x3 + 18x2 + 16x - 40, we can use the fact that 4 + 2i is a zero and apply the conjugate root theorem. The conjugate root theorem states that if a polynomial has a complex root a + bi, then it also has a conjugate root a - bi. Therefore, 4 - 2i is also a zero of the polynomial.

Now, we can use synthetic division to divide the polynomial by (x - 4 - 2i) and (x - 4 + 2i) to find the other zeros. The result of the synthetic division will be a quadratic polynomial, which we can then solve using the quadratic formula.

Synthetic division with (x - 4 - 2i):

4 + 2i | 1 -8 18 16 -40
      | 0 4+2i -4+14i -44-8i 56+40i
      ----------------------------
      1 -4+2i 14+14i -28-8i 16+40i

Synthetic division with (x - 4 + 2i):

4 - 2i | 1 -4+2i 14+14i -28-8i 16+40i
      | 0 4-2i -4-14i 44+8i -56-40i
      ----------------------------
      1 0 10 16 0

The result of the synthetic division is the quadratic polynomial x2 + 10x + 16. We can solve this using the quadratic formula:

x = (-10 ± √(102 - 4(1)(16)))/(2(1))

x = (-10 ± √(100 - 64))/2

x = (-10 ± √36)/2

x = (-10 ± 6)/2

The two solutions are x = -2 and x = -8.

Therefore, the zeros of the polynomial f(x) = x4 - 8x3 + 18x2 + 16x - 40 are 4 + 2i, 4 - 2i, -2, and -8.

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The original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

To show that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves, we need to take the derivative of the equation and set it equal to -1/b^2, the slope of the orthogonal line.

First, we take the derivative of the equation with respect to x:

2x/a^2 = -2y/b^2 * dy/dx

Simplifying, we get:

dy/dx = -b^2*x/a^2*y

Now, we set this equal to -1/b^2:

-b^2*x/a^2*y = -1/b^2

Cross-multiplying and simplifying, we get:

x/a^2*y = 1/b^2

Finally, we can rearrange this equation to get:

y = b^2*x/a^2

This equation represents the orthogonal family of curves to the original family of conics. Since the original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

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When the diameter οf the is 10 feet, then the area οf the circle is 78.54 ft².

A circle is created in the plane by each pοint that is a specific distance frοm anοther pοint (center). Hence, it is a curve made up οf pοints that are separated frοm οne anοther by a defined distance in the plane. Mοreοver, it is rοtatiοnally symmetric abοut the centre at every angle. Every pair οf pοints in a circle's clοsed, twο-dimensiοnal plane are evenly spaced apart frοm the "centre." A circular symmetry line is made by drawing a line thrοugh the circle. Mοreοver, it is rοtatiοnally symmetric abοut the centre at every angle.

The circle's diameter is specified as 10 feet. Since we already knοw that the circle's diameter is twice its radius, we can calculate its radius as fοllοws:

diameter = radius / 2 = 10 / 2 = 5 feet

Area οf circle = πr²

π5²

= π5 × 5

= 78.54 ft²

The size οf the circle is 79 square feet when the answer is rοunded tο the next whοle number.

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The area of the circle to the nearest whole number is 79 square feet.

What is the diameter?

In geometry, the diameter of a circle is defined as the longest straight line segment that can be drawn between any two points on the circle, passing through the center of the circle. It is twice the length of the radius of the circle.

The formula for the area of a circle is A = πr^2, where r is the radius of the circle.

Given that the diameter of the circle is 10 feet, we can find the radius by dividing the diameter by 2:

radius = diameter / 2 = 10 ft / 2 = 5 ft

Now we can use the formula to find the area of the circle:

A = πr^2

= π(5 ft)^2

= 25π square feet

To get the answer to the nearest whole number, we can use the approximation π ≈ 3.14:

A ≈ 25 × 3.14

≈ 78.5

Therefore, the area of the circle to the nearest whole number is 79 square feet.

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The board has a length of one board foot.

A thing's length has been its breadth or size calculated from the ends to the ends. In other words, it is the larger of an object's higher or lower geometric dimensions. For instance, a rectangle's dimensions are given by its length and breadth.

When describing an organism's size or the distance between two locations, the word "length" is often employed. For instance, the length of the a ruler is revealed in the table below.

Given that the board is [tex]4/4*12*12[/tex]

BF = (thickness in inches x width in inches x length in inches) / [tex]144[/tex]

BF = (1 inch x 12 inches x 12 inches) / 144

BF = 144 cubic inches / 144

BF = 1 board foot

Therefore, the board is 1 board foot in size.

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The quotient is [tex]x^{3}[/tex]+2[tex]x^{2}[/tex]+7x+20 and the remainder is 62.

To find the quotient and remainder using synthetic division, we can follow these steps:

1. Write down the coefficients of the dividend, which are 1, -1, 1, -1, and 2.

2. Write down the value of x from the divisor, which is 3.

3. Bring down the first coefficient, 1, to the bottom row.

4. Multiply the value of x, 3, by the first coefficient in the bottom row, 1, and write the result, 3, in the second column of the top row.

5. Add the second coefficient in the dividend, -1, to the value in the second column of the top row, 3, and write the result, 2, in the second column of the bottom row.

6. Repeat steps 4 and 5 for the remaining columns.

7. The bottom row will contain the coefficients of the quotient, and the last value in the bottom row will be the remainder.
The synthetic division will look like this:
3|1-11-12|362160|1272062

Therefore, the quotient is  [tex]x^{3}[/tex]+2[tex]x^{2}[/tex]+7x+20 and the remainder is 62. The final answer is ([tex]x^{3}[/tex]+2[tex]x^{2}[/tex]+7x+20)+62 / (x-3).

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The value for k has to be taken, to ensure that the probability, that - when we take a distance measurement y in practice - this distance measurement lies inside the interval [x – ko, x + ko), equals 99% is  0.516.

To find the value of k that ensures that the probability that the distance measurement lies inside the interval [x – ko, x + ko) equals 99%, we can use the standard normal distribution table.

First, we need to find the z-score that corresponds to the 99% probability. This is found by looking at the standard normal distribution table and finding the z-score that corresponds to a cumulative probability of 0.995 (since the probability is split between both sides of the mean, we need to look for 0.995 instead of 0.99).

The z-score that corresponds to 0.995 is approximately 2.58.

Now, we can use the formula for the z-score to find the value of k:

z = (y - x)/o

Since we are looking for the value of k that corresponds to the interval [x – ko, x + ko), we can plug in the values for the z-score and the standard deviation:

2.58 = (x + ko - x)/0.2

Solving for k, we get:

k = 2.58 * 0.2

k = 0.516

Therefore, the value for k that ensures that the probability that the distance measurement lies inside the interval [x – ko, x + ko) equals 99% is 0.516.

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The value of (gof)(4) is 9 if the function f(x) is f(x) =[tex]-x^3[/tex], and function g(x) is g(x) = |1/8x-1| option (A) is correct.

It is described as a particular kind of relationship, and each value in the domain is associated with exactly one value in the range according to the function. They have a predefined domain and range.

from the question:

We have a function:

f(x) = -x³

Plug x = 4 in the f(x)

f(4) = -4³ = -64

Plug the above value in the g(x)

g(f(4)) = |-8-1| = |-9| = 9

Thus, the value of (gof)(4) is 9 if the function f(x) is f(x) = -x³, and function g(x) is g(x) = |1/8x-1| option (a) is correct.

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complete and correct questions

f(x) = -x3

g(x) = |1/8x-1|

What is the value of (gof)(4)?.

A. 9

B. - 1/8

C. -9

D. 1/8

Answer:

(x, y)→(x,-y)

R(-4,0) S(-1,-3) T(2,-2)

Step-by-step explanation:

The opposite of a number is made by multiplying it by negative 1 (-1)

If it's reflected across the x axis, then the y axis will be the only one to change. (y to -y)

(x, y)→(x,-y)

Our formula for reflection across the x axis is (x,-y)

The rest is simple: Change each set of coordinates to an opposite y value.

Answer:

A

Step-by-step explanation:

c^2 = a^2 + b^2 - 2ab cos(C)

c^2 = 4^2 + 6^2 - 2(4)(6)(-1/4)

c^2 = 16 + 36 + 12

c^2 = 64

c = √64

c = 8

a) To find the definite integral of L (x + 1)(x - 1)dx, we first need to expand the expression and then integrate it.

L (x + 1)(x - 1)dx = L (x^2 - 1)dx

Now we can integrate this expression:

I = ∫(x^2 - 1)dx = (x^3/3) - x + C

Since we are looking for the definite integral, we need to evaluate this expression at the limits of integration.

I = [(b^3/3) - b] - [(a^3/3) - a]

b) To find the indefinite integral of (x - 1)dx, we simply need to integrate the expression and add a constant of integration.

I = ∫(x - 1)dx = (x^2/2) - x + C

c) To calculate the integral of 2cos(t)dt, we simply need to integrate the expression and add a constant of integration.

I = ∫2cos(t)dt = 2sin(t) + C

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Answer:

Step-by-step explanation:

You want the objective function, its maximum value, and the variable values that give that maximum based on the model shown in the graph.

The problem statement tells you the profit function is ...

  1.00x +1.50y . . . . . . objective function

Since the objective is to maximize profit, this is the objective function.

The integer values nearest the vertex of the feasible region farthest from the origin are (x, y) = (69, 70). These are the numbers of 'economy' and 'best' brushes that maximize the profit.

The maximum profit for these numbers of brushes will be ...

  p = x +1.5y = 69 +1.5(70) = 69 +105

  p = 174 . . . . maximum profit

The maximum profit of the situation is $174

From the question, we have the following parameters that can be used in our computation:

Profit function = $1 for x and $1.50 for y

This means that the objective function is

P(x, y) = x +1.5y

Also, the graph is given where we have:

Optimal point, (x, y) = (69, 70)

Substitute these points in the profit function

So, we have

P(x, y) = 69 +1.5 * 70

Evaluate

P(x, y) = 174

Hence, the maximum profit is $174

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The numbers that should be considered possible outliers from the above figure would be = 31, 87, and 90. That is option B.

An outlier is defined as the term given to an observation which lies in an abnormal distance from other values in a random sample from a population.

On the field of statistics, an outlier is also called an extreme value.

For example in the scores 25,29,2,32,86,33,27,28 both 2 and 86 are "outliers".

From the illustration given above, the values that are at the extreme that didn't enter the box plot are the outliers and they include 31,87, and 90.

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