Complete the solution of the equation. Find the
value of y when x equals 13.
-3x – 2y = -25
Enter the correct answer.​

Answer:

in one month : 13676.57/12=1139.71

the interest on 100000 is: 205148.48-100000=105148.48

Step-by-step explanation:

A=P(1+r)^t   (p is the mortgage, t is the time and r is the rate)

p=100000,t=15*12 month,r=4.8%( or 0.048)

A=100000(1+0.048/12)^(12*15)

A=205148.48 (the number rounded to the nearest hundredth)

205128.48 is the amount she has to pay it after 15 years

in one year : 205128.48/15=13676.57 ( rounded to nearest hundredth)

in one month : 13676.57/12=1139.71

the interest on 100000 is: 205148.48-100000=105148.48

Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now =  L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle =  800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) =  800 - 400 = 400 meters

Answer:

(x + 3)(x + 8)

Step-by-step explanation:

We're looking for two numbers that have a sum of 11 and product of 24; these numbers are 3 and 8 so the factored form is (x + 3)(x + 8).

Answer:

(x + 8)(x + 3)

Step-by-step explanation:

Hey there!

Well in the polynomial,

x^2+11x+24

we need to find out what*what = 24

8*3 = 24

8x + 3x = 11x

x*x = x^2

Factored (x + 8)(x + 3)

Hope this helps :)

Answer:

both are at the same distance

Step-by-step explanation:

Answer:

Austin and Devyn both have 1/3 of the way left on their way to school. They both also have walked the same amount.

Step-by-step explanation:

If Austin has to walk to his school, which could be said as 3/3 and Austin has already walked 2/3. Then if we conduct the equation 3/3-2/3=x. x=1/3. Now Devyn has already walked 4/6 of the way to school. If she has to walk a total of 6/6, then we can again make an equation 6/6-4/6=2/6. Now if we take the distance that they both have left to their school, its 1/3 and 2/6. These are both equavalent fractions because if you scale up 1/3, it equals to 2/6. Since they both have an equal amount of distance to travel, that must mean that they both have covered the same amount of distance already. We can double check to be sure. 2/3 *2/2=4/6. The reason we used 2/2 is because4/2=2 and 6/3=2.

Answer:

(A)[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the  following factors with multiplicity 1:

[tex]x-(2+i)\\x-\sqrt{2}[/tex]

We apply the following to find the factored form of the polynomial.

[tex]\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}[/tex]

Therefore, the factored form of the polynomial is:

[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]

Answer:

A

Step-by-step explanation:

EDGE 2021

Answer:

choose the last option .

you could check my answer using desmos graph (search on Google)

The y-intercept is [tex](0,\frac{6}{2})=(0,3)[/tex] and there is no x-intercept since the equality can simplified to the point of obtaining a constant function [tex]y=3[/tex] which does not depend on x.

Hope this helps.

Answer:

X+X

Step-by-step explanation:

did it on edg

Answer:

x° + x°

Step-by-step explanation:

Edge 2020

Answer:

16.704m

Step-by-step explanation:

To solve the above question, we are going to use the Trigonometric function of Sine.

sin θ = Opposite side/Hypotenuse

Where are given θ = 8°

Sin 8° = 0.1392

In the question, we are told that ,

A car travels 120m along a straight road that is inclined at 8° to the horizontal, hence,

Hypotenuse = 120m

We are asked to calculate the vertical distance through which the car rises hence,

Opposite side = vertical distance.

Therefore,

Sin 8° = Opposite/ 120m

Opposite = Sin 8° × 120m

Opposite = 0.1392 × 120m

Opposite = 16.704m

Therefore, the vertical distance through which the car rises is 16.704m

Answer: 3(x minus 5.50) = 111.75; the monthly Internet service is $42.75

Step-by-step explanation:

Given the following :

Total amount spent on internet for 3 months = $111.75

Monthly credit received on bill = $5.50

Monthly Credit of $5.50 means $5.50 is deducted from the amount being paid on thir bill monthly.

Assume their monthly internet service fee = x

The amount paid before the credit deduction each month:

Amount paid - credit

(x - $5.50)

For 3 months :

3 × (x - $5.50) = $117.75

3(x - $5.50) = $117.75

Monthly fee paid before credit deduction:

3(x - $5.50) = $117.75

3x - $16.50 = $117.75

3x = $117.75 + $16.50

3x = $128.25

x = $128.25 / 3

x = $42.75

Answer:

It's b !! :o]

Step-by-step explanation:

Answer:

[tex]2^5 > 5^2[/tex]

Step-by-step explanation:

Given the expression [tex]2^5 \ 5^2[/tex], we are to complete the inequality by inserting the correct inequality signs in between the values.

Before we do that, we must know the value of each indicinal expressions.

[tex]2^5 = 2*2*2*2*2\\\\2^5 = 4*4*2\\\\2^5 = 16*2\\\\2^5 = 32[/tex]

Also,

[tex]5^{2} = 5*5\\\\5^2 = 25[/tex]

From the values gotten, we can clearly see that 32 is greater than 25. This means that 2⁵ is greater than 5². Hence the inequality sign that will complete the expression is a greater than sign (>).

The inequality will be [tex]2^5 > 5^2[/tex]

Answer:

its this

over here...

Answer:

x = 28 degrees. 180 degrees in a triangle, 180-85-67=28

Answer:

28 degrees

Step-by-step explanation:

The interior angles of a triangle add up to 180 degrees.

The three angles given are: x, 85, and 67.

Therefore, these three angles must add to 180.

x+85+67=180

Combine like terms on the left. Add 85 and 67.

x+ (85+67)=180

x+152=180

We want to find x. We need to get x by itself. 152 is being added to x. The inverse of addition is subtraction. Subtract 152 from both sides.

x+152-152=180-152

x=180-152

x=28

x is 28 degrees.

Answer:

The first term is 12. The common difference is 4.

Step-by-step explanation:

[tex] a_n = a_1 + d(n - 1) [/tex]

The difference between the third and seventh terms is

36 - 20 = 16

The 7th term is the 4th term after the 3rd term, so the common difference is

16/4 = 4

[tex] a_3 = a_1 + 4(3 - 1) [/tex]

[tex] 20 = a_1 + 4(3 - 1) [/tex]

[tex] 20 = a_1 + 8 [/tex]

[tex] a_1 = 12 [/tex]

Answer: The first term is 12. The common difference is 4.

Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction

or

[tex]y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]

Step-by-step explanation:

Vertex form of equation : [tex]f (x) = a(x - h)^2 + k,[/tex]where (h, k) is the vertex of the parabola.

[tex]y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]

Hence, the vertex form of the equation is [tex]y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]

Answer:

i got y=2(x-1/2)^2- 27/2 so the last one is right

Step-by-step explanation:

:)

Answer:

Step-by-step explanation:

A of triangle = 1/2 * b * h

b = 6

h = 2

2 * 6 * 0.5

= 12 * 0.5

A of square = l * w

2 * 2

A of Triangle = 1/2 * b * h

2 * 2 * 0.5 =

4 * 0.5

2 + 4 + 6

= 6 + 6

Answer:

(7, -2)

Step-by-step explanation:

The trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1).

Transformation of a point is the change in location from an original position to a new position. If a shape is transformed, all its points are also transformed. A transformation can either be a rotation, translation, reflection or dilation.

If a point O(x,y) is reflected across the y axis, the new coordinate of the point is at O'(x, -y), i.e. the x coordinate does not change, but the y coordinate is negated.

Since in trapezoid ABCD, the coordinate of point B is (7, 2). The trapezoid is  reflected across the x-axis, therefore the new coordinate of B' is at (7, -2)

Answer:c

Step-by-step explanation:

I took the test

Answer: D) Construct the perpendicular bisectors for AB and AC.

The intersection of all three perpendicular bisectors will form the circumcenter, which is the center of the circumcircle. This circle goes through all three corner points of the triangle. At minimum, you only need two perpendicular bisectors to get the job done. Choice B is close, but is missing that second perpendicular bisector.

The angle bisectors intersect to form the incenter, which is the center of the incircle (it's the largest possible circle to fit inside the triangle without spilling over).

Answer:

D.  Construct the perpendicular of ab and ac

Step-by-step explanation:

Circumscribe a Circle on a Triangle

Construct the perpendicular bisector of one side of the triangle.

Construct the perpendicular bisector of another side.

Where they cross is the center of the Circumscribed circle.

Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle

Mark me as brainliest

Answer:

  all real numbers

Step-by-step explanation:

There is nothing on the graph to indicate the function is undefined for any values of x. The domain is all real numbers.

Answer:

Domain is all real numbers.

Step-by-step explanation:

The domain of a quadratic function in standard form is always all real numbers, meaning you can substitute any real number for x.

Answer:

1) The inequality is $55 ≥ $11.50 × S + $2.75

2) Alonso can afford 4 boxes of sugar

Step-by-step explanation:

The given information are;

The total amount with Alonso = $55

The amount of eggs Alonso needs = 12 eggs

The costs of the pack of 12 eggs = $2.75

The number of packs of eggs Alonso buys = 1

The cost of each box of sugar =  $11.50

Let the number of boxes of sugar Alonso buys = S

Given that the total amount of money with Alonso is $55, then the inequality will be such that $55 will be equal to or larger than the expression for items bought

Therefore, the inequality is given as follows;

$55 ≥ $11.50 × S + $2.75

2) To find out how many boxes of sugar Alonso can afford, we have;

$55 ≥ $11.50 × S + $2.75

$55 - $2.75≥ $11.50 × S

$52.25 ≥ $11.50 × S

∴ S ≤ $52.25/$11.50 = 4.54

S ≤ 4.54 boxes of sugar

As the sugar comes in whole boxes, Alonso can therefore afford only 4 whole boxes of sugar.

Alonso can afford to buy 4 boxes of sugar.

An inequality to represent how many boxes of sugar can Alonso afford is 55 ≥ 2.75 + 11.50s

Given:

Amount with Alonso = $55

Package of 12 eggs = $2.75

Cost of each box of sugar = $11.50

let

s = number of boxes of sugar Alonso can afford

The inequality:

55 ≥ 2.75 + 11.50s

solve for s

55 - 2.75 ≥ 11.50s

52.25 ≥ 11.50s

divide both sides by 11.50

52.25 / 11.50 ≥ s

4.5434782608695 ≥ s

Alonso can only buy a whole box of sugar

Therefore, the number of boxes of sugar Alonso can afford is 4 boxes

Read more:

https://brainly.com/question/11067755

Answer:

We have the problem:

|3r−15| if r<5

First we see the equality, if r = 5 we have:

I3r - 15I = I3*5 - 15I = I0I = 0.

Then the only restriction that we have is:

I3r - 15I > 0.

now, we could simplify it a bit further:

if r < 5, then the thing inside the absolute value will always be negative:

Then we can write:

I3*r - 15I = -(3*r -15) > 0

multiplying by -1 in both sides

(3r - 15) < 0.

if we keep simplifying this, we will get our initial restriction:

3r - 15 < 0

3r < 15

r < 15/3 = 5

r < 5

Answer:

100.

Step-by-step explanation:

Let the number of robberies be x ( in 2013).

Then x - 0.10x = 90

0.90x = 90

x = 90 / 0.90

= 100.

Answer:

Step-by-step explanation:

[tex]x^2+19x+70\ \implies a=1\,,\ b=19\,,\ c=70\\\\x=\frac{-19\pm\sqrt{19^2-4\cdot1\cdot70}}{2\cdot1}=\frac{-19\pm\sqrt{361-280}}{2}=\frac{-19\pm9}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-5\\\\x^2+19x+70=(x+14)(x+5)\\\\\\x^2-225=x^2-(15)^2=(x-15)(x+15)\\\\\\x^2-5x-150\ \implies a=1\,,\ b=-5\,,\ c=-150\\\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-150)}}{2\cdot1}=\frac{5\pm\sqrt{25+600}}{2}=\frac{5\pm25}{2}\ \Rightarrow\ x_1=-10\,,\ x_2=15\\\\x^2-5x-150=(x+10)(x-15)[/tex]

[tex]x^2+24x+140\ \implies a=1\,,\ b=24\,,\ c=140\\\\x=\frac{-24\pm\sqrt{24^2-4\cdot1\cdot140}}{2\cdot1}=\frac{-24\pm\sqrt{576-560}}{2}=\frac{-24\pm4}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-10\\\\x^2-5x-150=(x+14)(x+10)[/tex]

[tex]\dfrac{x^2+19x+70}{x^2-225}\,\cdot\,\dfrac{x^2-5x-150}{x^2+24x+140}=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{(x+10)(x-15)}{(x+14)(x+10)}=\\\\\\=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{x-15}{x+14}=\dfrac{x+5}{x+15}\cdot\dfrac11=\boxed{\dfrac{x+5}{x+15}}[/tex]

Answer:

The answer is option 3.

Step-by-step explanation:

First, you have to factorize the expressions :

[tex] \frac{ {x}^{2} + 19x + 70 }{ {x}^{2} - 225 } \times \frac{ {x}^{2} - 5x - 150}{ {x}^{2}24x + 140 } [/tex]

[tex] = \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]

Next, you have to cut out the common terms like (x + 14), (x - 15) and (x + 10):

[tex] \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]

[tex] = \frac{x + 5}{x + 15} [/tex]

Answer:

It took 31 days for the patch to cover half the lake

Step-by-step explanation:

The patch grows to double its size everyday

the patch completely covers the lake in 32 days

Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.

Therefore, the the patch covered half the lake on the 31st day, i.e it took 31 days for the patch to cover half the lake

Answer:

Step-by-step explanation:

It depends on how it is written. By definition

[tex]\csc(x) = (\sin(x))^{-1} = \frac{1}{\sin(x)}[/tex]

[tex]\sec(x) = (\cos(x))^{-1} = \frac{1}{\cos(x)}[/tex]

[tex]\cot(x) = (\tan(x))^{-1} = \frac{1}{\tan(x)}[/tex]

however the functions

[tex]\sin^{-1}(x), \cos^{-1}(x), \tan^{-1}(x)[/tex] are the inverse functions of sine, cosine and tangent respectively. So, they are not equivalent functions

Answer:

Step-by-step explanation:

tan∅ = opposite / adjacent

From the question

AC is the adjacent

BC is the opposite

So we have

tan (a) = BC / AC

tan (a) = 24/7

Hope this helps you

Answer:

Step-by-step explanation:

[tex]Using\: A \: as\: a\: refernce\: angle ;\\Hypotenuse = 29\\Opposite =21\\Adjacent = 20\\\\Using \: SOHCAHTOA\\Sin A = \frac{Opposite}{Hypotenuse} \\\\Sin A = \frac{21}{29}[/tex]

Answer:

Step-by-step explanation:

-9x + 6y = -30

-7x + 12y = -16

18x - 12y = 60

 -7x + 12y = -16

11x = 44

x = 4

-36 + 6y = -30

6y = 6

y = 1

(4,1)

Answer:

(4,1)

Step-by-step explanation:

-9x + 6y = -30.............(1)

-7x + 12y = -16 ............(2)

(2) - 2(1)

-7x+12y - 2(-9x+6y) = -16 - 2(-30)

simplify

11x = 44

or

x = 4 .......................(3a)

substitute (3) in (1)

-9(4) + 6y = -30

6y = -30 + 36

6y = 6

y =  1 ......................(3b)

Using results from (3a) and (3b), we have

solution :  (4,1)

Answer:

∠ I ≈ 60.3°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan I = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{HG}{GI}[/tex] = [tex]\frac{7}{4}[/tex] , thus

∠ I = [tex]tan^{-1}[/tex] ([tex]\frac{7}{4}[/tex] ) ≈ 60.3° ( to the nearest tenth )

the answer is 10 by root 65 so the answer is 10

Answer:

[15, ∞).

Step-by-step explanation:

–3(6 – 2x) ≥ 4x + 12

-18 + 6x ≥ 4x + 12

6x - 4x ≥ 12 + 18

2x ≥ 30

x ≥ 15

This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).

Hope this helps!

Answer:

See diagram

Step-by-step explanation:

A quadrilateral becomes a parallelogram when the diagonals bisects each other at a point E and hence proves the quadrilateral is a parallelogram. It shows both pairs of opposite sides being parallel to each other.

Following the theorem that states that, if two sides of a quadrilateral are opposite and congruent, then it is a parallelogram. Ditto for the theorem that states that,  that when diagonals cuts each other at a point in a quadrilateral, then its a parallelogram.