A catering company is catering a large wedding reception. The host of the reception has
asked the company to spend a total of $454 on two types of meat: chicken and beef. The
chicken costs $5 per pound, and the beef costs $ 7 per pound. If the catering company
buys 25 pounds of chicken, how many pounds of beef can they buy?

Answers

Answer 1

The answer is 47 pounds

Explanation:

1. First, let's calculate the amount of money that was spent on chicken

$5 per pound of chicken x 25 pounds = $125

2. Calculate the amount of money left to buy beef by subtracting the total spend on chicken to the total of the budget.

$454 (total) - $125 (chicken)  =  $329

3. Calculate how many pounds of beef you can buy with the money left by dividing the money into the price for one pound.

$329 / $7 = 47 pounds


Related Questions

Determine the domain of the function. f as a function of x is equal to the square root of two minus x.
x ≤ 2
All real numbers
x > 2
All real numbers except 2

Answers

Answer:

A. x <= 2

Step-by-step explanation:

The domain of a real function should be all real numbers. In

f(x) = sqrt(2-x)

we need 2-x to be non-negative, therefore

2-x >= 0

which implies

x <= 2

Answer:

[tex]\Huge \boxed{{x\leq 2}}[/tex]

Step-by-step explanation:

The function is given,

[tex]f(x)=\sqrt{2-x}[/tex]

The domain of a function are all possible values of x.

There are restrictions for the value of x.

2 - x cannot be equal to a negative number, because the square root of a negative number is undefined. 2 - x has to equal to 0 or be greater than 0.

[tex]2-x\geq 0[/tex]

[tex]-x\geq -2[/tex]

[tex]x\leq 2[/tex]

The domain of the function is x ≤ 2.

According to the histogram below, how many people took the test? 39 9 16 23

Answers

The correct answer is D. 23

Explanation:

Histograms similar to other graphs represent numerical information, usually by using bars, as well as ranges. For example, in the case presented the information presented belongs to the scores obtained in a test, which are shown using ranges. Moreover, it is possible to know the total of people that took the test by adding each of the frequencies, as the frequency in the y-axis shows the number of times the range repeated and it is expected each grade registered belongs to 1 person. This means the total of people is equal to 2 (score from 60-69) + 9 (score from 70-79) + 7 (score from 80-89) + 5 (score from 90-99) = 23 people.

Answer:

the answer is 23

Step-by-step explanation:

hopes this helps:)

The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distance of 10 inches from the object how much pressure is needed for a distance of 3 inches

Answers

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

[tex]p \propto \dfrac{1}{d}[/tex]

Introducing the constant of proportionality

[tex]p = \dfrac{k}{d}[/tex]

If 150 pounds is required for a distance of 10 inches from the object

p=150 poundsd=10 inches

[tex]150 = \dfrac{k}{10}\\\\k=1500[/tex]

Therefore, the relationship between p and d is:

[tex]p = \dfrac{1500}{d}[/tex]

When d=3 Inches

[tex]p = \dfrac{1500}{3}\\\implies p=500$ pounds[/tex]

The pressure applied when the distance is 3 inches is 500 pounds.

What are the dimensions of the rectangle? PLEASE HELP!!

Answers

Answer:

2(x^2 + 8x -55)

Step-by-step explanation:

Well to do the box method we first need to simplify the given equation further to,

[tex]2x^2 + 16x - 110\\[/tex],

For this quadratic the box method doesn't work so we can divide everything by 2 make make it

2(x^2 + 8x -55)

Thus,

[tex]2x^2 + 16x - 110\\[/tex] factored is 2(x^2 + 8x -55).

Hope this helps :)

The value of x that will make L and M

Answers

Greetings from Brasil...

Here we have internal collateral angles. Its sum results in 180, so:

(6X + 8) + (4X + 2) = 180

6X + 4X + 8 + 2 = 180

10X + 10 = 180

10X = 180 - 10

10X = 170

X = 170/10

X = 17

X would equal 17 in this question.

Can someone help me with this one

Answers

Answer:

b^2

------

2a

Step-by-step explanation:

-6ab^3          10b

-------------- * -----------

5a                   -24 ab^2

Rewriting

-6ab^3          10b

-------------- * -----------

 -24 ab^2      5a

Canceling like terms

b                  2b

-------------- * -----------

 4                a

Canceling the 2 and 4

b                  b

-------------- * -----------

 2                a

b^2

------

2a

Answer:

b²/2a

Step-by-step explanation:

[(-6ab³)/5a]*[(10b)/(-24ab²)]

-60ab^4/-120a²b²= ( when divide ,subtract the exponents)

b²/2a

6t+7−2+t combine the like terms to create an equivalent expression

Answers

Answer:

7t+5

Step-by-step explanation:

Answer:

7t +5

Step-by-step explanation:

6t+7−2+t

Combine like terms

6t+t  + 7-2

7t +5

Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the which the card is printed is $0.05 per card, and the cost of printing is $0.15 per card. The company receives $2.15 per card sold. Since the cards have the current year printed on them, unsold cards have no salvage value. Their customers are from the four areas: Los Angeles, Santa Monica, Hollywood, and Pasadena. Based on past data, the number of customers from the each of the four regions is normally distributed with mean 2,000 and standard deviation of 500. (Assume these four are independent.)
What is the optimal production quality for the card? (Use Excel's NORMSINV{} function to find the Z-score. Round intermediate calculations to four decimal places. Submit your answer to the nearest whole number.)

Answers

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

[tex]SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000[/tex]

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

[tex]\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}[/tex]

                               [tex]=\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907[/tex]

Use Excel's NORMSINV{0.907} function to find the Z-score.

z = 1.322

Compute the optimal production quantity for the card as follows:

[tex]\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\[/tex]

                                               [tex]=8000+(1.322\times 1000)\\=8000+1322\\=9322[/tex]

Thus, the optimal production quantity is 9,322 cards.

what is 3141 times X. x=5783978

Answers

Answer:

18167474898

Step-by-step explanation:

I used a calculator.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

∫ ex (sec x + tan²x) dx = ? a) eˣsec²x b) eˣsecx c) eˣtan²x d) eˣtanx

Answers

None of these options seem to be correct. You can check each result by differentiation:

[tex](e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)[/tex]

[tex](e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)[/tex]

[tex](e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)[/tex]

[tex](e^x\tan x)'=e^x(\tan x+\sec^2x)[/tex]

But none of these are equivalent to [tex]e^x(\sec x+\tan^2x)[/tex]...

Which expression is a cube root of -2

Answers

Answer:

∛-2

Step-by-step explanation:

The aritmetic expressión is:

∛-2

A rectangle's length and width are in a ratio of 10:1. The perimeter is 66 feet. What are the length and width?

Answers

hii

Step-by-step explanation:

length-10x

width-x

perimeter-2(l+b)

66=2(10x+x)

66-2=10x+x

64=11x

x=11/64

lenght-11

width-64

Length-11
Width-64
Hope it helps

According to the World Health Organization (WHO) Child Growth Standards, the head circumference for boys at birth is normally distributed with a mean of 34.5cm and a standard deviation of 1.3cm. What is the probability that a boy has a head circumference greater than 36.32cm at birth

Answers

Answer:

0.081

Step-by-step explanation:

To solve this question, we would use the z score formula

z score = (x-μ)/σ, where

x is the raw score = 36.32cm

μ is the population mean = 34.5 cm

σ is the population standard deviation = 1.3cm

z score = (36.32cm - 34.5cm)/1.3cm

z = 1.4

Using the normal distribution to find the z score for 1.4

P(z = 1.4) = 0.91924

Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is

P(x>36.32) = 1 - P(z = 1.4)

= 1 - 0.91924

= 0.080757

Approximately ≈ 0.081

HEREEEEEEEEEEEEEElollll

Answers

Answer:

Hey there!

Your answer would be 4/50. The total times she drawed a purple tile was 4, and she drawed 50 times.

Hope this helps :)

How do you make a table of value for the following equation? 3x=y

Answers

Answer:

Step-by-step explanation:

y= 3x

x            y

0           0

1             3

2            6

3             9

-1            -3

-2             -6

he math team wraps gifts as a way to raise money for traveling to competitions. They offer two choices: a plain wrapping or a decorative wrapping with bows. The table represents the money raised over a busy shopping weekend.

Answers

The team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow.

Answer:

The answer above is correct B

Step-by-step explanation:

Took the Unit Test Review on edg 2020 correct

what is the equation of a vertical ellipse with a major axis= 20 and a minor axis = 14?​

Answers

[tex]\bold{\text{Answer: b.}\quad \dfrac{y^2}{100}+\dfrac{x^2}{49}=1}[/tex]

Step-by-step explanation:

The ellipse is vertical so y has the biggest radius.

Major axis (y) = 20 so the y-radius is 20/2 = 10

Minor axis (x) = 14 so the x-radius is 14/2 = 7

The equation of an ellipse is:   [tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]   where

(h, k) is the center of the ellipsea is the x-radiusb is the y-radius

Given: a = 7, b = 10

Assume: (h, k) = (0, 0)

[tex]\dfrac{(x-0)^2}{7^2}+\dfrac{(y-0)^2}{10^2}=1\\\\\\\dfrac{x^2}{49}+\dfrac{y^2}{100}=1\\\\\\\longrightarrow \dfrac{y^2}{100}+\dfrac{x^2}{49}=1[/tex]

which is greater 7.955 or 7.95

Answers

Answer:

[tex]\boxed{7.955>7.95}[/tex]

Step-by-step explanation:

7.95 can also be written as 7.950 .

So, we'll compare 7.955 and 7.950.

All the digits in ones, tenths, hundredths place are equal so we'll look at the thousandths place.

5 is in the thousandths place of 7.955 and 0 is in the thousandths place of 7.950. Since 5 is greater than 0 so 7.955 is greater than 7.95. It can also be written as:

7.955 > 7.950

From a population that is not normally distributed and whose standard deviation is not known, a sample of 6 items is selected to develop an interval estimate for the mean of the population (μ).
a. The normal distribution can be used.
b. The t distribution with 6 degrees of freedom must be used.
c. The sample size must be increased.
d. The t distribution with 5 degrees of freedom must be used.

Answers

Answer:

d) The t-distribution with 5 degrees of freedom must be used

Step-by-step explanation:

For cases of Normal Distribution where the variance is unknown and the sample size n is smaller than 30, we must use the t-student distribution.

The shape of the curve for t-student is bell-shape (flatter and with wider tails than the bell shape of normal distribution.

Actually, when we deal with t-student distribution we are dealing with a family of curves that will become closer and closer to the bell shape of the normal distribution as the degree of freedom increases. From values of n =30( and bigger),  we can assume that the curve of t-student is the same as for normal distribution

i will give 50 points and brainliest ​

Answers

Answer:

Hey there!

0.5(8.4)(h)=69.3

4.2h=69.3

h=16.5

Hope this helps :)

Answer:

[tex] \boxed{\sf Height \ of \ the \ triangle = 16.5 \ mm} [/tex]

Given:

Area of the triangle = 69.3 mm²

Base of the triangle = 8.4 mm

To Find:

Height of the triangle

Step-by-step explanation:

[tex]\sf \implies Area \ of \ the \ triangle = \frac{1}{2} \times Base \times Height \\ \\ \sf \implies 69.3 = \frac{1}{2} \times 8.4 \times Height \\ \\ \sf \implies 69.3 = \frac{1}{ \cancel{2}} \times \cancel{2} \times 4.2 \times Height \\ \\ \sf \implies 69.3 = 4.2 \times Height \\ \\ \sf \implies 4.2 \times Height = 69.3 \\ \\ \sf \implies Height \times \frac{ \cancel{4.2}}{ \cancel{4.2}} = \frac{69.3}{4.2} \\ \\ \sf \implies Height = \frac{16.5 \times \cancel{4.2}}{ \cancel{4.2}} \\ \\ \sf \implies Height = 16.5 \: mm[/tex]

simple khan academy math help asap

Answers

Answer:

[tex]\boxed{\sf C. \ 6.6 \ units}[/tex]

Step-by-step explanation:

The triangle is a right triangle.

We can use trigonometric functions to solve.

[tex]\sf cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]\sf cos(35)=\frac{MO}{8}[/tex]

[tex]\sf 8 \ cos(35)=MO[/tex]

[tex]\sf 6.55321635...=MO[/tex]

8. Which statement is always true?
A. 9 times a number is always odd.
B. 9 times a number is always even
C. 10 times a number is always odd.
D. 10 times a number is always even.​

Answers

Answer:

D

Step-by-step explanation:

Any number multiplied by an even number will always be even. 10 is an even number.

Answer:

d. 10 times a number is always even

Step-by-step explanation:

multiples of 9 contain 81 and 36 which one is even and the other is odd

multiples of 10 ONLY contain even numbers because   the unit digit for a multiple of 10 is 0.

So whenever you multiply a number by 10 it will be even

Six human skulls from around 4000 b.c. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9
mm. If you want to construct a 95% confidence interval estimate of the mean length of all such skulls, assume that the requirements
are satisfied. Find the critical values that would be used to construct a 95% confidence interval estimate of o

Answers

Answer:

Step-by-step explanation:

Hello!

You have to estimate the mean length of 4000 b.c. human skulls trough a 95% confidence interval.

You know that

n= 6 human skulls

[tex]\frac{}{X}[/tex]= 94.2mm

S= 4.9

Assuming that the variable X: length of a 4000b.c. human skull (mm) has a normal distribution, to construct the interval you have to use the t statistic:

[[tex]\frac{}{X}[/tex] ± [tex]t_{n_1;1-\alpha /2} * \frac{S}{\sqrt{n} }[/tex]]

[tex]t_{n-1;1-\alpha /2}= t_{5; 0.975}= 2.571[/tex]

[94.2 ± 2.571 * [tex]\frac{4.9}{\sqrt{6} }[/tex]]

[89.06; 99.34]mm

With a 95% confidence level you'd expect the interval [89.06; 99.34]mm to contain the value for the average skull length for humans 4000 b.c.

I hope this helps!

please what's the solution for 2a²×4a³​

Answers

Answer:

8a^5

Step-by-step explanation:

Well to start off 2*4=8

So the coefficent will be 8

and when multipling ezponents we add the exponents and 2+3=5 so the exponent will be 5.

So 8a^5 is the answer

Consider the line y=2x-7 What is the slope of a line parallel to this line? What is the slope of a line perpendicular to this line?

Answers

Answer:

The slope of the given line is 2

Answer -1/2 is the line perpendicular

Step-by-step explanation:

This can be rewritten in fraction form as 2/1 since x/1 = x.

Answer: parallel line = 2x, perpendicular line = -1/2x

Explanation:

In order to have a parallel line:

The slope have to be the same as the original which is 2x

In order to have a perpendicular line:

The slope have to be the opposite reciprocal of the original slope

Which is -1/2x

Evaluate the expression.

Answers

Answer:

work is shown and pictured

A set of raw paired sample data is given below. Convert this raw data into paired ranks, and calculate the value of the rs test statistic for this data. a. 0.647 b. 0.652 c. 0.955 d. 0.921

Answers

here is the data set for the complete question

x: 18 21 19 21 20 21

y; 2 14 5 6 18 18

Answer:

B. 0.652

Step-by-step explanation:

x   y   rank of x     rank of y   d         d²

18   2     1                1               0          0

21   14    4                4             0          0

19    5     2               2             0          0

21    6     4               3            1            1

20    18    3             5.5         -2.5      6.25

21     18    4             5.5          -1.5       2.25

∑d² = 8.5

rs = 1 - 6[∑di² + ∑m(m²-1)]/n(n²-1)

= 1 - 6[8.5 +{3(3²-10/12 + 2(2² - 1)/12}]/6(6²-1)

= 1 - 0.348

= 0.652

therefore option b is the right answer.

-6(y+15)=-3y+6
what value of y makes the equation true

Answers

Answer:

y = -32

Step-by-step explanation:

-6(y+15)=-3y+6

Distribute

-6y - 90 = -3y +6

Add 6y to each side

-6y -90+6y = -3y+6y +6

-90 = 3y+6

Subtract 6 from each side

-90 -6 = 3y +6-6

-96 = 3y

Divide by 3

-96/3 = 3y/3

-32 = y

Answer:

-32 !!!!

Step-by-step explanation:

WHY CAN'T ANYONE HELP ME? PLEASE What one is the standard form of the equation y = – 1/4 x – 2? A. x + 4y = 8 B. x + 4y = – 2 C. x + 4y = – 8 or D. –x + 4y = – 8

Answers

Answer:

C. x+4y=-8

Step-by-step explanation:

The standard form of an equation is Ax+Bx=C

y= -[tex]\frac{1}{4}[/tex]x-2

Multiply 4 by both sides

4y= -x-8

1+4y= -8

An hourglass consists of two sets of congruent composite figures on either end. Each composite figure is made up of a cone and a cylinder, as shown below: Hourglass with sand measuring 45 millimeters high © 2011 Jupiterimages Corporation Each cone of the hourglass has a height of 15 millimeters. The total height of the sand within the top portion of the hourglass is 45 millimeters. The radius of both cylinder and cone is 6 millimeters. Sand drips from the top of the hourglass to the bottom at a rate of 10π cubic millimeters per second. How many seconds will it take until all of the sand has dripped to the bottom of the hourglass? (4 points) Select one: a. 126 b. 108 c. 18 d. 29

Answers

Answer:

126

Step-by-step explanation:

Total volume of sand = pi/3*(6^2)*(15) + pi*(6)^2*(30) = 1260*pi mm^3

So it will therefore take 1260*pi/10*pi = 126 seconds for all of the sand from the top hourglass to drip down to the bottom hourglass.

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