A vertical bar consists of three prismatic segments A1, A2, and A3 with cross-sectional areas of 6000 mm2 , 5000 mm2 , and 4000 mm2 , respectively. The bar is made of steel with E 5 200 GPa. Calculate the displacements at points B, D

Answers

Answer 1

Answer and Explanation:

For computing the displacement at point B and D we need to determine the following calculations

[tex]P_Net = P_C + P_E + P_B[/tex]

= 250 + 350 - 50

= 550 N

Now the deflection for bar AB is

[tex]\delta_{AB} = \frac{PL_{AB}}{AE} \\\\ = \frac{550 \times 500}{6,000 \times 200 \times 10^{3}}[/tex]

[tex]= 2.292 \times 10^{-4} mm[/tex]

Now for bar BC it is

[tex]\delta_{BC} = \frac{PL_{BC}}{AE} \\\\ = \frac{(550 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 1.5 \times 10^{-04} mm[/tex]

And for bar CD it is

[tex]\delta_{CD} = \frac{PL_{CD}}{AE} \\\\ = \frac{(550 -250 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 0.875 \times 10^{-4} mm[/tex]

Now the displacement is as follows

For B

2.292 × 10^{-4} mm

For D, it is

[tex]= 2.292 \times 10^{-4} + 1.5 \times 10^{-4} + 0.875 \times 10^{-4} mm \\\\ = 4.667 \times 10^{-4} mm[/tex]

We simply applied the above formulas for determining the  displacements at points B, D and the same is to be considered  

A Vertical Bar Consists Of Three Prismatic Segments A1, A2, And A3 With Cross-sectional Areas Of 6000

Related Questions

a physical quantity Z is given by z=ad/g .calculte the relatibe error in z​

Answers

Answer:

e_{r} = Δa /a + Δd /Δ d + Δg / g

Explanation:

The error or uncertainty of a quantity is given by several factors, the most direct error is the absolute one that is given by the appreciation of the instruments, when some quantities obtained by a mathematical formula we must know how each error is programmed in the total error, we can see this with the relative error

     

the calculated quantity is Z

its relative error is

            [tex]e_{r}[/tex] = ΔZ/Z = 1/Z  (dZ /da Δa + dZ /dd Δd + dZ /dg Δg)

            e_{r} = 1 / Z (d /g  Δa + a /g  Δd + ad !1/g²! Δg)

            e_{r} = Δa /a + Δd /Δ d + Δg / g

notice that we take the worst case.

The measured quantities have absolute errors Da, Dd, Dg

A 1,383 kg purple car is driving southbound on a road and collides with a 1,827 kg orange car, that was traveling 31.87 m/s eastbound. The two cars collide and stick, sliding 14.54 meters before coming to rest. What was the initial velocity of the two-car system just after the collision? Take the coefficient of friction to be 0.463, and the acceleration due to gravity to be 9.8 m/s2. Answer to two decimal places.

Answers

Answer:

Explanation:

We shall apply work energy theorem to calculate the initial velocity just after the collision .

Their kinetic energy will be equal to work done by friction .

force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity

force = .463 x 3210 x 9.8

= 14565.05 N

work done = force x displacement

= 14565.05 x 14.54 = 211775.88 J

now applying work energy theorem

1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision

.5 x 3210 x v² = 211775.88

v² = 131.94

v  11.48 m /s

Joan makes the device shown in her science class.

An illustration with a battery and ends labeled positive and negative. A wire is connected to the positive end of the battery and curls around an iron nail and connects back with the negative side of the battery.

What would happen to the magnetic field if she connects the battery in the opposite direction?

The field would stop.
The field would get stronger.
The field would reverse its poles.
The field would get weaker.

Answers

Answer:

The field would reverse its poles.

Explanation:

The current flow will reverse directions which will reverse the poles in the magnetic field created around the iron nail.

If she connects the battery in the opposite direction, the magnetic field would reverse its poles.

What is magnetic field?

The magnetic field is the region of space where an object experiences the magnetic force and obtain magnetic properties.

A wire is connected to the positive end of the battery and curls around an iron nail and connects back with the negative side of the battery. This arrangement will let the current flow from the positive end of the battery towards the negative terminal of the battery.

If the battery is connected in the opposite direction, the current will flow from negative to positive terminal.

Therefore, If she connects the battery in the opposite direction, the magnetic field would reverse its poles.

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Find the net force and acceleration. 15 points. Will give brainliest!

Answers

Answer:

[tex]\boxed{F_{net} = 28.7 \ N}[/tex]

[tex]\boxed{a = 2.1 \ m/s^2}[/tex]

Explanation:

Finding the net force:

Firstly , we'll find force of Friction:

[tex]F_{k} = (micro)_{k}mg[/tex]

Where [tex](micro)_{k}[/tex] is the coefficient of friction and m = 13.6 kg

[tex]F_{k} = (0.16)(13.6)(9.8)\\[/tex]

[tex]F_{k} = 21.32 \ N[/tex]

Now, Finding the net force:

[tex]F_{net} = F - F_{k}\\F_{net} = 50 - 21.32\\[/tex]

[tex]F_{net} = 28.7 \ N[/tex]

Finding Acceleration:

[tex]a = \frac{F_{net}}{m}[/tex]

[tex]a = \frac{28.7}{13.6}[/tex]

[tex]a = 2.1 \ m/s^2[/tex]

in a cricket match there are 5000 spectators counted 10 by 10 the number of significant figure in the measurement will be

Answers

Answer:

[tex]\boxed{3 \ Significant \ figures}[/tex]

Explanation:

Total spectators = 5000

Counted by the groups of ten, So at last the result will be:

=> 5000/10 = 500

Significant figures in 500 are 3

SOMEONE HELP ME PLEASE!!!
a. What is the displacement of the car in the graph?
b. What distance has the car travelled? ​

Answers

Answer:

a. 2 m

b. 4 m

Explanation:

a. Assuming d is the position of the car, the displacement is the difference between the final position and the initial position. 3 m - 1 m = 2 m.

b. From t = 0 to t = 2.5, the car moves a distance of 3 m. From t = 2.5 to t = 4, the car moves another 1 m.

So the car moves a total distance of 4 m.

The three-dimensional arrangement of electron groups around the central atom is called ____.

A. Election-pair repulsion
B. Electronegativity
C. Geometric design
D. Electron-group geometry

Answers

Answer:

D. Electron - group geometry

Explanation:

Just did it boom THE BANK BUSTA WINS AGAIN

A car travels 18 km / h to the northwest. What is the speed of this car seen from another car going south at 60 km / h?

Answers

Answer:

73.8 km/h

Explanation:

The velocity of object A relative to object B is:

v = va − vb

Let's say east is +x and north is +y, and angles are measured from +x.

The velocity of the first car in the x direction is:

18 km/h cos 135° = -9√2 km/h

The velocity of the first car in the y direction is:

18 km/h sin 135° = 9√2 km/h

The velocity of the second car in the x direction is:

60 km/h cos 270° = 0 km/h

The velocity of the second car in the y direction is:

60 km/h sin 270° = -60 km/h

The relative velocity in the x direction is:

vₓ = -9√2 km/h − 0 km/h = -9√2 km/h ≈ -12.7 km/h

The relative velocity in the y direction is:

vᵧ = 9√2 km/h − (-60 km/h) = 9√2+60 km/h ≈ 72.7 km/h

The speed, or magnitude of the velocity, is:

v = √(vₓ² + vᵧ²)

v = √((-12.7 km/h)² + (72.7 km/h)²)

v ≈ 73.8 km/h

Which of the following is a device that uses an inclined plane?
Check all that apply.
A. knife
B. wheelchair ramp
C. bicycle
D. half-pipe at a skate park​

Answers

Answer:

A and B

Explanation:

Answer:

B. wheelchair ramp

D. half-pipe at a skate park

Hope that helps!

I REALLY NEED HELP WITH PHYSICS!! HELPPP!! I’m giving 50 points :)))

Answers

Answer:

59%

Explanation:

Data obtained from the question include the following:

Input temperature = 495 K

Output temperature = 293 K

Efficiency =?

The efficiency of the car engine can be obtained by multiplying the ratio of the output temperature to the input temperature by 100 as shown below:

Efficiency = output /input x 100

Efficiency = 293/495 x 100

Efficiency = 59.1 ≈ 59%

Therefore, the efficiency of the car engine is approximately 59%

A man has a mass of 110kg. What is his weight?

Answers

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) =  408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) =  176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) =  1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car B after the collision?

Answers

The velocity of car B after the calculation can be obtained as 5.5 m/s.

What is a collision?

We have to look at the principle of the conservation of the linear momentum and that is what we need so as to be able to deal with the problem that we have in this question as we have it here.

We know that the total momentum of the system would have to be constant and the implication of this is that the momentum before collision must be the same as the momentum after collision if we have been able to designate the system as a closed system.

Using the formula as we have shown it, we know that;

Momentum before Collison must be equal to momentum after collision

As such we have the following as shown below;

(281 * 2.82) + (209 * 1.72) = (281 * 0) + (209 * v)

792.42 + 359.48 = 209 v

v = 5.5 m/s

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Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the velocity of car B?

Answers

Answer:

Ub = 221.99m/s

Explanation:

(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V

(331 x 3.87)+(208 x Ub) = (331 + 208)88

(1257.8) + (208 x Ub) = 47432

(208 x Ub) = 47432 - 1257.8

(208 x Ub) = 46174.2

Ub = 46174.2/208 = 221.99m/s

Ub = 221.99m/s

Answer:

4.75

Explanation:

M1V1 + M2V2 = M1V3 + M2V4

[(331*3.87) , 90°] + 0 = [(331*0.888) , 90°] + M2V4

M2V4 = 987.042 , 90°

divide through by M2

V4 = 4.75 m/s east

if you rub a balloon on your hair, it becomes charged, and as a result It can stick to your head without being held there. why doesn't it fall on the ground?

Answers

The balloon doesn't fall on the ground. Because the electrical field around your head disrupts Earth's gravitational field. Option A is correct.

What is the electrostatic force, and how does it work?

It is a force imposed by one charge on another as a result of the field. The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.

When you brush a balloon against your hair, it charges up and can attach to your head without being kept in place.

Because the electrical field surrounding your head interrupts Earth's gravitational field, it does not fall to the earth.

Hence, option A is correct.

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The solubility of barium nitrate is 9.02 g/100 g H2O at 20°C. A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. Is the solution saturated, unsaturated, or supersaturated?

Answers

Answer:

The solution is unsaturated.

Explanation:

Saturated solutions are those solutions with the maximum amount of solute completely dissolved by the solvent. This indicates that although more solute is added, it does not dissolve. In this case the amount of solute is equal to the solubility coefficient.

The supersaturated solution  is one in which the amount of solute exceeds the solubility of the solvent, that is, it has a greater amount of dissolved solute than that which it admits at that temperature. In this case a solution contains solute above the solubility coefficient.

A solution is considered to be unsaturated if the mass of dissolved solute is less than that corresponding to that of saturation. This indicates that it is possible to add more solute and that it dissolves. In this case the solution contains solute below the solubility coefficient.

The solubility of barium nitrate is 9.02 g/100 g H₂O at 20°C.

A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. This is: 15.2 g /200 g H₂O.  Dividing by two you get: 7.6 g /100 g H₂O

Comparing with the solubility of barium nitrate, you can see that the mass of dissolved solute is less than the corresponding one. This indicates that the solution is unsaturated.

Ionizing radiation is radiation of sufficient energy to produce charged atoms. All of these describe ionizing radiation. is radiation of sufficient energy to produce ions. is radiation of sufficient energy to remove electrons from atoms.

Answers

Answer:

Is radiation of sufficient energy to produce ions.

Is radiation of sufficient energy to remove electrons from atoms.

Explanation:

Ionization radiation is a radiation that travels at a high speed, and possesses sufficient speed to knock electrons off of an atom or a molecule, ionizing the atom. Ionization radiation can be made of travelling subatomic particles, or an electromagnetic wave with high energy, usually the types found at the end of the electromagnetic spectrum. Some subatomic particles that produce ionization are alpha particle, beta particles, and neutron. The electromagnetic waves with ionization abilities includes Gamma rays. -rays, and high energy ultraviolet rays.

A 70.0 kg skier is at rest at the top of a 120m hill. Assuming friction is negligible.
A) What is the speed of the skiers at the bottom of the hill?

Answers

Answer:

49 m/s

Explanation:

Initial potential energy = final kinetic energy

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 120 m)

v = 49 m/s

When you urinate, you increase pressure in your bladder to produce the flow. For an elephant, gravity does the work. An elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. Assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. Assume that urine has the same density as water, and that viscosity can be ignored for this flow.
1) What is the speed of the flow? It is 1.2 m/s
2) If we assume that the liquid is at rest in the bladder (a reasonable assumption) and that the pressure where the urine exits is equal to atmospheric pressure, what does Bernoulli's equation give for the pressure in the bladder? (In fact, the pressure is higher than this; other factors are at work. But you can see that no increase in bladder pressure is needed!)

Answers

Answer:

1)  v = 1.19 m / s , 2)     P₁ = 9.308 10⁴ Pa  

Explanation:

In this exercise we will simulate the emission of urine as a fluid mechanics system

1) they indicate the urine flow rate Q = 0.0060 m³ / s, they also give the diameter of the tube 8.0 cm, they ask us the speed.

   Let's use the continuity equation

            Q = v A

The area of ​​a cycling tube is

            A = π r² = π d² / 4

we substitute

            Q = v π d² / 4

            v = 4Q / π d²

let's calculate

            v = 4 0.006 / (π 0.08²)

            v = 1.19 m / s

2) they ask to find the pressure in the bladder, for this we use the Bernoulli equation, where the index is for the bladder and the index 2 is for the exit point

            P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

in the exercise it indicates that the outlet pressure is equal to the atmospheric pressure P₂ = 1,013 10⁵ Pa, the velocity of the liquid in the bladder is v₁ = 0 and the height difference 1.0 m

           P₁ = P₂ + ½ ρ v₂² + ρ g (y₂-y₁)

let's calculate

          P₁ = 1.013₁ 10⁵⁵ + ½ 1000 1.19 + 1000 9.8 (0-1)

          P₁ = 1.013 105 + 595 - 9800

          P₁ = 9.308 10⁴ Pa

What is the magnetic force on a particle that has 0.000500 C of charge and is moving at
2.50 10m/s to the right through a magnetic field that is 4.20 T and pointing away from
you? Specify both magnitude and direction in your answer.

Answers

Answer:

1.) F = 5.3×10^-3 N

2.) Positive y - direction

Explanation:

The parameters given are:

Charge q = 0.0005C

Velocity V = 2.5010 m/s

Magnetic field B = 4.2 T

Magnetic force F = BVqsinØ

F = BVq

since Ø = 90 degree

Substitute all the parameters into the formula

F = 4.2 × 2.5010 × 0.0005

Therefore, the magnetic force on a particle is F = 5.3 × 10^-3 N

2.) According to Fleming's left hand rule, the direction of the magnetic force will be perpendicular to the magnetic field which moving upward of the screen.

Answer:

it’s f=0.0005 x 2.5 x 10^5 x 4.20

F= 525 N

+ y direction (up)

Explanation:

got it right

Newton's Law of Gravitation can be used to show that if an object weighs w pounds on the surface of the earth, then its weight at a distance x from the center of the earth is W(x)=wR2x2 (for x≥R), where R=3960 miles is the radius of the earth. Estimate the altitude at which a 120- lb pilot would weigh 119.5 lb

Answers

Answer:In other words, with w = 130, W = 129.5, what is x?

You find this by plugging in the values for w, W and R and solving for x.

Note: x is the distance from the center. You were asked for the distance from the surface (the altitude) so there's one more calculation to do when you find x.

Explanation:

Calculating heat gained, need help!!!

Q=(m)(c)(triangle T)

trial 1:

Q=(0.4)(4.186 J/kg)(78)=?

trial 2:

Q=(0.6)(4.186 J/kg)(78)=?

trial 3:

Q=(0.45)(4.186 J/kg)(75)=?

Answers

Explanation:

q = mCΔT

where m is mass,

C is specific heat capacity,

and ΔT is change in temperature.

Make sure all your units match.  Assuming the substance is water, C = 4186 J/kg/°C.

Trial 1:

q = (0.4 kg) (4186 J/kg/°C) (78°C)

q = 130,600 J

Trial 2:

q = (0.6 kg) (4186 J/kg/°C) (78°C)

q = 195,900 J

Trial 3:

q = (0.45 kg) (4186 J/kg/°C) (75°C)

q = 141,300 J

A sports car moving at constant velocity travels 120m in 5.0s. If it then brakes and comes to a stop in 4.0s,what is the magnitude of it's acceleration? ​

Answers

AnswerQUESTION①):

✔ First calculating the speed :

V = d(in m)/t(in s)

V = 120/5 V = 24 m/s

✔ You now know the average car's speed, is time it takes to stop it completely, so you can calculate its acceleration :

a = V/t

a = -24/4 a = 6 m/s² The car has an acceleration of 6 m/s².

a body weights 28N at a height of 3200km from the earth surface.What will be the gravitational force on that body if its lies on the earth surface.

Answers

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

[tex]F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}[/tex]

Now, if the body is on the surface of the Earth, its weight (w) would be:

[tex]F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}[/tex]

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

[tex]\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\[/tex]

Someone help me?

Isaac throws an apple straight up in the positive direction) from 15 m above the ground, reaching a
maximum height of 38 meters. Neglecting air resistance, what is the ball's velocity when it hits the
ground?​

Answers

Answer:

-27.3 m/s

Explanation:

Given:

y₀ = 38 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (-9.8 m/s²) (0 m − 38 m)

v = -27.3 m/s

Or, you can solve with energy.

PE = KE

mgh = ½ mv²

v² = 2gh

v = -27.3 m/s

A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?

Answers

Answer:

Explanation:

Resultant of 12 and 3 ohm in series = 15 ohm

Resultant of 6 and 3 ohm = 9 ohm

Total resultant resistance of circuit = 15 x 9 / (15 + 9)

= 5.625 ohm

current drawn from battery = 4 / 5.625

= .711 A

ii )current through 12 ohm = 4 / (12 + 3 )   , because potential  diff over 12 and 6 ohm will be 4 V .

current through 12 ohm = .267 A

iii )

current through 6 ohm

= .711 - .267

= .444 A

potential difference

= .444 x 6

= 2.664 V .

Culture creates the context for behavior in society. true or false

Answers

Answer:

True every culture is diffrent and culture is the way to grow up, the people or things you live around, or the ways of life you follow or dress.

Explanation: The definition of culture is:  means a particular set of customs, morals, codes and traditions from a specific time and place. All of that develops how a person may behave in society.

Answer:

true

Explanation:

just took the quiz

Average velocity is different than average speed because calculating average velocity involves a)Distance b)Time c)Motion d)Displacemnet

Answers

Answer:

D. Displacement

Explanation:

got it right on edge

Average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.  It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.

The mathematical expression for velocity is given by

velocity= displacement  / time taken

In the displacement time graph the slope of the curve represent the velocity of the object ,the rate of change of velocity is known as the acceleration of the object .

In the velocity time graph the slope of the curve represent the acceleration of the body, The unit of acceleration is metre per second Square

The total distance traveled by an object is different than the total displacement covered by it because the displacement is a vector quantity and it is calculated on the basis of the shortest distance traveled by the body or object.

The main difference between the distance and the displacement is that displacement can be positive or negative or zero but distance can never be negative.

Let’s understand understand with example of average velocity ,suppose an object is moving with 200 m displacement covered in a time of 15 seconds then the average velocity of the object is 13.33 m/s.

Thus, average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.

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a man with mass 81 kg lies on the floor. what is the normal force on the man?

Answers

Answer:

Forces come in pairs, so the force of gravity (9.8 N) with the mans weight (794N) on the earth is counteracted with the normal force ( the force of the earth back on the man) which is the same

Explanation:

Forces are available in pairs, so the force of gravity (nine.8 N) with the man's weight (794N) on the planet is counteracted with the everyday force ( the pressure of the earth again on the man) that's identical.

What is the gravitational force?

Gravitational force is a pressure that draws any items with mass. We name the gravitational force appealing as it constantly attempts to tug loads collectively, it never pushes them apart. In reality, every item, together with you, is pulling on each other objects inside the complete universe.

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250 mL 0.1 M HCl solution is mixed with 250 mL
0.2 M NaOH. The concentration of OH- in the
mixture is

Answers

Answer:

The concentration of OH⁻ in the mixture is 0.05 M

Explanation:

The reaction of neutralization between HCl and NaOH is the following:

H⁺(aq) + OH⁻(aq) ⇄  H₂O(l)

The number of moles of HCl is:

[tex] n_{HCl} = C*V = 0.1 mol/L*0.250L = 0.025 moles [/tex]

Similarly, the number of moles of NaOH is:

[tex] n_{NaOH} = C*V = 0.2 mol/L*0.250L = 0.05 moles [/tex]

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

[tex] n_{NaOH} = 0.05 moles - 0.025 moles = 0.025 moles [/tex]

Finally, the concentration of OH⁻ in the mixture is:

[tex]C =\frac{n_{NaOH}}{V_{T}}=\frac{0.025 moles}{0.250*2 L} = 0.05 moles/L[/tex]

Therefore, the concentration of OH⁻ in the mixture is 0.05 M.

I hope it helps you!

A submarine emerges 1/9 of its volume when it partially floats on the sea surface. For make it completely submerge it is necessary to allow a volume of 50,000 [L] to enter of sea water whose density is 1,026 [g / cm3]. What is the weight of the submarine?

Answers

Answer:

4,524,660 N

Explanation:

Assuming the submarine's density is uniform, 1/9th of the submarine's mass is equal to the mass of the displaced water.

m/9 = (1026 kg/m³) (50 m³)

m = 461,700 kg

mg = 4,524,660 N

Other Questions
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