Answer:
f(x) = 500(2)^x
Step-by-step explanation:
Let's assume the initial x value is 0
500(0)^2 = 0
100(0)^5 = 0
500(2)^0 = 500
500(0)^2 = 0
Answer:
C
Step-by-step explanation:
Edge
You work in a machine design department and need to specify the diameter of a pin that slides back and forth through a hole. The hole diameter is specified as 0.500 inch with a tolerance of 0.010 inch. The maximum pun diameter must be 0.002 inch smaller than the minimum hole diameter. If the pin diameter has a tolerance of 0.010 inch what diameter in inches should you specify for the pin?
Answer:
B. 0.478
Step-by-step explanation:
The diameter of the pin is 0.478 inches as per specification.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
The operator that perform arithmetic operation are called arithmetic operators.
+ Addition operation : Adds values on either side of the operator.
For example 4 + 2 = 6
- Subtraction operation : Subtracts right hand operand from left hand operand.
for example 4 -2 = 2
The hole diameter is specified as 0.500 inches with a tolerance of 0.010 inches.
The maximum pun diameter must be 0.002 inches smaller than the minimum hole diameter.
Diameter: d = 0.500 inch
Tolerance: t = 0.010 inch
Replacing the values:
⇒ dmax = 0.500 - 0.010 - 0.002 - 0.010
Apply the subtraction operation,
⇒ dmax = 0.478 inch
Hence, the diameter of the pin is 0.478 inches as per specification.
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Solve the given integral equation for LaTeX: y(t)y ( t ). LaTeX: y(t)+9\displaystyle{\int_{0}^{t}e^{9(t-v)}y(v)\, dv}=\sin(3t)y ( t ) + 9 ∫ 0 t e 9 ( t − v ) y ( v ) d v = sin ( 3 t ) Group of answer choices LaTeX: y(t)=3\cos(3t)+9\sin(3t)-9 y ( t ) = 3 cos ( 3 t ) + 9 sin ( 3 t ) − 9 LaTeX: y(t)=3\cos(3t)+\sin(3t)-3 y ( t ) = 3 cos ( 3 t ) + sin ( 3 t ) − 3 LaTeX: y(t)=3\cos(3t)+\sin(3t) y ( t ) = 3 cos ( 3 t ) + sin ( 3 t ) LaTeX: y(t)=3\cos(3t)+9\sin(3t) y ( t ) = 3 cos ( 3 t ) + 9 sin ( 3 t ) LaTeX: y(t)=\cos(3t)+3\sin(3t)-3
Looks like the equation is
[tex]y(t)+9\displaystyle\int_0^te^{9(t-v)}y(v)\,\mathrm dv=\sin(3t)[/tex]
Differentiating both sides yields the linear ODE,
[tex]y'(t)+9e^{9(t-t)}y(t)=3\cos(3t)[/tex]
or
[tex]y'(t)+9y(t)=3\cos(3t)[/tex]
Multiply both sides by the integrating factor [tex]e^{9t}[/tex]:
[tex]e^{9t}y'(t)+9e^{9t}y(t)=3e^{9t}\cos(3t)[/tex]
[tex]\left(e^{9t}y(t)\right)'=3e^{9t}\cos(3t)[/tex]
Integrate both sides, then solve for [tex]y(t)[/tex]:
[tex]e^{9t}y(t)=\dfrac1{10}e^{9t}(\sin(3t)+3\cos(3t))+C[/tex]
[tex]y(t)=\dfrac{\sin(3t)+3\cos(3t)}{10}+Ce^{-9t}[/tex]
The given answer choices all seem to be missing C, so I suspect you left out an initial condition. But we can find one; let [tex]t=0[/tex], then the integral vanishes and we're left with [tex]y(0)=0[/tex]. So
[tex]0=\dfrac{0+3}{10}+C\implies C=-\dfrac3{10}[/tex]
So the particular solution is
[tex]y(t)=\dfrac{\sin(3t)+3\cos(3t)-3e^{-9t}}{10}[/tex]
Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted in two stores where the two new systems have been installed result in the following summary of the data: System A System B Size 120 100 mean 4.1 minutes 3.4 minutes Standard Deviation 2.2 minutes 1.5 minutes Test at the 0.05 level of significance to determine whether the population mean checkout times of the two systems differ. Which system is preferred?
Use both the critical and p-value approach.
Hypotheses:
Decision rule:
Calculations:
Conclusions:
Answer:
the answer would be calculations
Step-by-step explanation:
because they have do determine if the check out times differ between the two systems so they need to calculate the difference between the two
x/-8 ≥−5 solve for x
Answer:
x ≤ 40
Step-by-step explanation:
x/-8 ≥−5
Multiply each side by -8, remembering to flip the inequality
x/-8 *-8 ≤−5 *-8
x ≤ 40
Answer:
x ≥ 40
Step-by-step explanation:
[tex]\frac{x}{-8} \geq -5[/tex]
x ≥ -5 * -8
x ≥ 40
Check
40 / -8 ≥ -5
The initial population of a town is , and it grows with a doubling time of 10 years. What will the population be in years?
Answer:
This question is incomplete, i will answer it as:
"The initial population of a town is A, and it grows with a doubling time of 10 years. What will the population be in X years?"
Ok, the growth of a population usually is an exponential growth, so we can write this as:
P(t) = A*exp(r*t)
Where A is the initial population.
r is the rate of growth, and t is our variable, in this case, number of years.
Now we know that when t = 10y, the population doubles, so we should have:
P(10y) = 2*A = A*exp(r*10y)
2 = exp(r*10)
ln(2) = r*10
ln(2)/10 = r = 0.069.
Then our equation is:
P(t) = A*exp(0.069*t)
Now, if we want to know the population in X years, we need to replace the variable t by X
P(t = X) = A*exp(0.069*X)
WHY CAN'T ANYONE HELP ME? Twice last month, Judy Carter rented a car in Fresno, California, and traveled around the Southwest on business. The car rental agency rents its cars for a daily fee, plus an additional charge per mile driven. Judy recalls that her first trip lasted 4 days, she drove 440 miles, and the rental cost her $286. On her second business trip she drove 190 miles in 3 days, and paid $165.50 for the rental. Find the daily fee and the mileage charge.
Answer:
The daily rate is $33 and the per mile rate is $0.35
Step-by-step explanation:
4x + 440y = 286
3x + 190y = 165.5
We can solve this systems of equations by multiplying the second statement by [tex]-\frac{4}{3}[/tex] to try and eliminate the x variable.
4x + 440y = 286
-4x - [tex]\frac{760}{3}[/tex]y = -220[tex]\frac{2}{3}[/tex]
[tex]\frac{560}{3}[/tex] y= [tex]\frac{196}{3}[/tex]
560y = 196
y = 0.35
So, the rate per mile is 0.35. Now, with this info, let's find the daily rate by plugging it into the equation.
[tex]4x + 440\cdot0.35 = 286\\4x + 154 = 286\\4x = 132\\x = 33[/tex]
So, the daily rate is $33 and the mile rate is $0.35.
Hope this helped!
Answer:
the daily fee =33 dollars
and the mileage charge.=0.35
let d: be daily fee and m for mileage
cost of rental =(d*number of days)+ (m*number of mileage)
her first trip: 4d+440m=286
her second trip: 3d+190m=165.5
solve by addition and elimination
4d+440m=286 ⇒ multiply by 3 ⇒12d +1320m=(3)286
3d+190m=165.5⇒ multiply by 4⇒12d+190(4)m=4(165.5)
12d+1320m=858
12d+760m=662
subtract two equation to eliminate d
12d+1320m-12d-760m=858-662
560m=196
m=7/20=0.35 for on mileage
d: 4d+440m=286
4d=286-440(0.35)
d=(286-154)/4 33 dollars
A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain scale before and after hypnosis. Assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. Does hypnotism appear to be effective in reducing pain? In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the difference in the measurements on a pain scale before and after hypnosis. What is the test statistic for this hypothesis test?
Answer:
Step-by-step explanation:
Hello!
This is an example of a pared sample test, the experiment is based on two dependent variables:
X₁: centimeters on a pain scale before hypnosis
X₂: centimeters on a pain scale after hypnosis
Out of these two variables a new variable is determined Xd= X₁-X₂
If the variables have an approximate normal distribution then the variable resulting from their difference will also have an approximate normal distribution.
The claim is that "hypnosis reduced the pain" if so you'd expect the population mean of the difference to be less than zero, symbolically: μd<0
The statistic for this test is a paired sample t test:
[tex]t= \frac{\frac{}{X_d} - Mu_d}{Sd} ~t_{n-1}[/tex]
To calculate the sample mean and variance you have to calculate the difference between the pairs first.
[tex]\frac{}{Xd}[/tex]= ∑Dif/n
[tex]S_d^2= \frac{1}{n-1} [sumDif^2- \frac{(sumDif)^2}{n} ][/tex]
∑Dif= 6.4
∑Dif²= 12.64
[tex]\frac{}{Xd}[/tex]= 6.4/5= 1.28
[tex]S_d^2= \frac{1}{4} [12.64- \frac{(6.4)^2}{5} ]= 1.112[/tex]
Sd= 1.05
[tex]t_{H_0}= \frac{\frac{}{Xd}-Mu_d }{Sd} = \frac{1.28-0}{1.05} = 1.219= 1.22[/tex]
I hope this helps!
A card is drawn from a well shuffled deck of 52 cards. What is the probability of drawing an ace or a 9? Round to nearest thousandth
Answer:
.154
Step-by-step explanation:
There are 52 cards
There are 4 aces and 4 9's for a total of 8 cars
P (ace or 9) = number of aces or 9's / total
= 8/52 = 2 /13 =.153846154
To the nearest thousandth
= .154
Answer:
0.154
Step-by-step explanation:
We want to find the probability of drawing an ace or a 9.
P(ace or 9)= aces and 9s / total cards
There are 4 aces and 4 9s in a standard deck of cards. This means there is a total of 8 aces and 9s.
In a standard deck of cards, there is a total of 52 cards.
P(ace or 9)= aces and 9s / total
aces and 9s= 8
total= 52
P(ace or 9)= 8/52
This fraction can be simplified. Both the numerator and denominator can be evenly divided by 4.
P(ace or 9)= (8/4) / (52/4)
P(ace or 9)= 2/13
P(ace or 9)= 0.153846153846154
Round to the nearest thousandth. The 8 in the ten thousandth place tell sus to round the 3 up to a 4.
P(ace or 9) = 0.154
The probability of drawing an ace or 9 is 0.154
The first three steps in determining the solution set of the system of equations, y = –x2 – 2x + 8 and y = 2x + 11, algebraically are shown in the table
Phuong collects Persian and Oriental rugs in a ratio of 3:4. If Phuong has 84 Oriental rugs, how many rugs are in his collection?
Answer:
The answer is
147Step-by-step explanation:
Let the total number of rugs be x
To find the total number of rugs we must first find the total parts which is
3 + 4 = 7
4/7 of the total rugs are 84 Oriental rugs
Which is written as
[tex] \frac{4}{7} x = 84[/tex]
Multiply through by 7
[tex]7 \times \frac{4}{7} x = 84 \times 7[/tex]
Simplify
[tex]4x = 588[/tex]
Divide both sides by 4
[tex] \frac{4x}{4} = \frac{588}{4} \\ \\ \\ \\ x = 147[/tex]
The total number of rugs is 147Hope this helps you
A bike tire just ran over a nail, and it is losing pressure at a rate of 5% every minute. The tire pressure is currently 1,300 kilopascals. What will it be in 3 minutes? If necessary, round your answer to the nearest tenth.
Answer:
1,114.6 kPa
Step-by-step explanation:
P(t) = 1300 (0.95)^t
P(3) = 1300 (0.95)^3
P(3) = 1114.6
[URGENT] (25 points) Ryan randomly drew a marble out of a bag of marbles, then put it back. He did
this 25 times. Of the 25 times he drew a red marble 6 times. He concluded
that the probability of drawing a red marble was
6/25
Answer:
Unpredictable
Step-by-step explanation:
Cuz if u look at it it is also random and u cant predict a random thing, so its quite simply unpredictable
Graph the linear equation. Find three points that solve the equation. - 3x +2y=2
Answer:
y=3/2x+1 0,1 2,4 4,7
Step-by-step explanation:
-3x+2y=2
+3x
2y=3x+2
/2 /2 /2
y=3/2x+1
Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .
Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k
parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t
Step-by-step explanation: The vector equation is a line of the form:
r = [tex]r_{0}[/tex] + t.v
where
[tex]r_{0}[/tex] is the position vector;
v is the vector;
For point (7,4,5):
[tex]r_{0}[/tex] = 7i + 4j + 5k
Then, the equation is:
r = 7i + 4j + 5k + t(3i + 2j - k)
r = (7 + 3t)i + (4 + 2t)j + (5 - 5t)k
The parametric equations of the line are of the form:
x = [tex]x_{0}[/tex] + at
y = [tex]y_{0}[/tex] + bt
z = [tex]z_{0}[/tex] + ct
So, the parametric equations are:
x = 7 + 3t
y = 4 + 2t
z = 5 - 5t
A random sample of 10 subjects have weights with a standard deviation of 11.6144 kg. What is the variance of their weights? Be sure to include the appropriate units with the result.
Answer:
Variance=134.8943 kg
Step-by-step explanation:
The relationship between standard deviation and variance is that standard deviation is the square root of the variance.
So given the value of standard deviation to be 11.6144kg, the variance will be the square of the number.
Standard deviation= √variance
Standard deviation ²=√variance²
Standard deviation ² = variance
11.6144²= variance
134.8943
Variance=134.8943 kg
Answer:
122.4409 kg
Step-by-step explanation:
(((Please help, asap. Giving brainliest.)))
Explain how you can classify shapes, using the distance and slope formula. <—I got this part I just really need an example. Provide examples to support your response 
Answer:
Step-by-step explanation:
Try to use the distance formula to determine whether the sides are congruent. So take every pair of consecutive vertices and apply the distance formula. So you will have which, in any, sides are congruent.
Use the slope formula to determine which sides are parallel or perpendicular or neither of those. If the slopes are equal the sides are parallel, if the product of the slopes is - 1 the sides are perpendicular. In any other case the sides are neither parallel nor perpendicular.
With that and the definitions of the shapes you will be able to classify shapes.
To write a full example would be very long .
An easy one might be this as an example:
Given the points (0,0), (2,0), (2,2) and (0,2), classify the shape.
When you apply the distance formula: you will find 2 for all the sides, so they are all congruent.
When you apply the slope formula you will find two pair of parallel sides, and the sides that intersects are perpendicular.
Therefore... the classification of the shape is a square.
Find the x-value of the removable discontinuity of the function.
Answer:
x=2
Step-by-step explanation:
[tex]f(x)=\frac{x^2-4}{x^2-12x+20}[/tex]
Factor the numerator and denominator:
[tex]f(x)=\frac{(x-2)(x+2)}{(x-2)(x-10)}[/tex]
We can remove (x-2) from the function:
[tex]f(x)=\frac{x+2}{x-10}[/tex]
(x-2) is a removable discontinuity.
The x-value of x-2 is x=2.
a tax of 0.19 dollars is imposed on each baga of potato chips that is sold. the tax generates revenue of approx 10,000 dollars and ddecreases the equilibrium wuantyiy of potato chips by 156 bags per day/ the tax creates a deadweight lsos of how many dollars
Answer:
The tax creates a deadweight loss of $29.64 dollars per day.
Step-by-step explanation:
a) A bag of potato chips generates $0.19 per bag
If 156 bags are not sold each day because of the imposed tax, the deadweight loss is calculated as follows:
156 x $0.19 = $29.64 per day
b) A deadweight loss is the inefficiency cost imposed by the tax because it causes decreases the equilibrium quantity of bags of potato chips sold each day by 156. By dislocating the equilibrium and the market forces, the tax makes the economy to suffer overall. This may imply that the rate of the tax was not economically reasonable. Unless a tax is imposed to discourage an activity or a consumption, the rate should not be so high as to create inefficiencies in the allocation of economic resources.
How do I tell if scatterplot is linear?
If you are given the graph of g(x)=log2x, how could you graph f(x)=log2x+5
Answer:
The plus 5 is a vertical translation. It would move g(x) up 5 units at all points. So just take g(x) and move the curve up 5 units.
A company pays its employees an average wage of $17.90 an hour with a standard deviation of $1.50. If the wages are approximately normally distributed and paid to the nearest cent, the highest 2.5% of the employees hourly wages is greater than what amount
Answer:
$20.84
Step-by-step explanation:
To solve the above question, we would be using the z score formula
The formula for calculating a z-score :
z = (x - μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation
x = unknown
μ = $17.90
σ = $1.50
We were not given z score in the above question but this can be determined.
We are told in the question to find the amount that the highest 2.5% of the employees hourly wages is greater than.
Hence, our confidence interval = 100 - 2.5 = 97.5%
The z score for 97.5% = 1.96
Below are inequalities equations with more explanation.
P(X ≥ x) = 2.5% = 0.025
P(X ≤ x) = 1 - 0.025 = 0.975
P (X - μ)/σ ≤ (x - μ)/σ) = 0.975
z ≤ (x - μ)/σ = 0.975
z ≤ 1.96 = 0.975
z = (x - μ)/σ,
1.96 = x - 17.90/1.5
Cross Multiply
1.96 × 1.5 = x - 17.90
x = (1.96 × 1.5) + 17.90
x = 2.94 + 17.90
x = 20.84
Therefore, the amount that the highest 2.5% of the employees hourly wages is greater than is $20.84
Marcia is a bag that contains four green marbles, eight yellow marbles, and 20 red marbles. If she chooses one marble from the bag, what is the probability that the marble is not red?
Answer:
3/8
Step-by-step explanation:
The bag contains 4 green marbles, 8 yellow marbles and 20 red marbles.
The total number of marbles is 32.
She chooses one from the bag.
The probability of the marble not being red is:
P(not red) = 1 - P(red)
P(not red) = 1 - (20 / 32) = 1 - 5/8
P(not red) = 3/8
The probability of it not being red is 3/8.
You change oil every 6000 miles and drive 2000 miles a month; how many times a year do you change oil?
Answer:
you would change it 4 times a year
Step-by-step explanation:
if there is 12 months in a year and 3 mounths equal 6000 then divide 12/3=4
please help me please!!!
Answer:
she has covered 6 miles in 1 ½ hours
Step-by-step explanation:
you need to learn how to read a graph.
it quite easy actually.
just look where the line on the graph is on 1.5 hours ( you can count the boxes if you don't know where 1.5 or 1 ½ is)
several different positive integers are written on a blackboard. the product of the smallest two of them is 16. the product of the largest 2 of them is 225. what is the sum of the integers?
Answer:
44
Step-by-step explanation:
The integers 2,8,9 and 25 fit to the terms of the problem.
So the smallest two are 2 and 8 =>2*8=16
and 9*25=225
Note that another pair of integers which product is 16 can be 1 and 16.
However it means that both numbers which product is 225 are bigger than 16 - this is not possible so 16*16=256>225
So only numbers 2,8,9 and 25 fit to the terms of the problem.
Note that there is no any integer number between 8 and 9 . So there are four integers in total and these integers are 2,8,9 and 25.
The sum of these integers is 2+8+9+25=44
17. What is the most likely outcome of decreasing the wavelength of incident light on a diffraction grating? A. lines become narrower B. distance between lines increases C. lines become thicker D. distance between lines decreases
When the wavelength of a diffraction grating is decreased, the distance between lines decreases.
What is a diffraction grating?The diffraction grating is used to carry out interference experiments. It consists of a number of small lines that are constructed to be close to each other and produce an interference pattern.
The outcome of decreasing the wavelength of incident light on a diffraction grating is that the distance between lines decreases.
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If x^2/2 is added to sum of y^2/2
,the number equals to 0 . find the value of x and y
Answer:
0
Step-by-step explanation:
x ^2/2 + y^2/2 = 0
Then x and y can be 0
0^2/2 + 0^2/2
0/2 +0/2 = 0
0 + 0 = 0
0 = 0
Which of the following box plot best represents the set of data below
Answer:
C. Box plot B
Step-by-step explanation:
im not sure what it is asking me to do
Answer:
0.79Step-by-step explanation:
[tex]p(x \leqslant 0) = p( - 5) + p( - 3) + p( - 2) + p(0)[/tex]
[tex] = 0.17 + 0.13 + 0.33 + 0.16 [/tex]
[tex] = 0.79[/tex]
Hope this helps...
Best regards!!
Find the left critical value for 95% confidence interval for σ with n = 41. 26.509 24.433 55.758 59.342
Answer: 59.342
Step-by-step explanation:
The chi-square critical values are used to find the confidence interval for σ.
Left critical value = [tex]\chi^2_{\alpha/2, n-1}[/tex] [i.e. chi-square value from chi-square table corresponding to degree of freedom n-1 and significance level of [tex]\alpha/2[/tex]]
To find : left critical value for 95% confidence interval for σ with n = 41.
Significance level : [tex]\alpha=1-0.95=0.05[/tex]
degree of freedom = 41-1=40
Now, the left critical value for 95% confidence interval for σ with n = 41 is the chi-square value corresponding to degree of freedom n-1 and [tex]\alpha/2=0.025[/tex]
=59.342 [from chi-square table ]