Answer:
8.6 cm
Step-by-step explanation:
V=pi r-squared h
diameter of 10 means radius of 5
675.1=3.14x5x5xh
675.1=78.5h
8.6
Find m to the second power + 1/m to the second power if m+1/m = square root of 71 . WILL MARK BRAINLIEST
=============================================
Explanation:
Note that m + 1/m and m^2 + 1/(m^2) are very similar. If we square (m + 1/m), then we end up with something in the form (a+b)^2 = a^2 + 2ab + b^2, where a = m and b = 1/m. The 2ab portion is equal to 2*m*(1/m) = 2 which allows us to isolate m^2 + 1/(m^2) fully.
The steps below show this
[tex]m + \frac{1}{m} = \sqrt{71}\\\\\left(m + \frac{1}{m}\right)^2 = \left(\sqrt{71}\right)^2\\\\m^2 + 2*m*\frac{1}{m} + \frac{1}{m^2} = 71\\\\m^2 + 2 + \frac{1}{m^2} = 71\\\\m^2 + 2 + \frac{1}{m^2} - 2 = 71-2\\\\m^2 + \frac{1}{m^2} = 69\\\\[/tex]
-------------
Alternatively, you can isolate m in the equation [tex]m + \frac{1}{m} = \sqrt{71}[/tex] to get two irrational solutions. Plug either solution into m^2 + 1/(m^2) and you should get the same result as above.
Aaron covers 300 miles in 6 hours, what's his average speed?
Answer:
50mph
Step-by-step explanation:
Speed=v
time=t
distance=s
v=s/t
v=300m/6h
v=50mph
Let me know if my answer is wrong.
Hope this helps :) ❤❤❤
Answer:
[tex]\boxed{Speed = 50 miles/hr}[/tex]
Step-by-step explanation:
Given:
Distance = S = 300 miles
Time = t = 6 hours
Required:
Average Speed = v = ?
Formula:
Average Speed = Total Distance Covered / Total Time Taken
Solution:
v = S/t
v = 300 miles / 6 hours
v = 50 miles/hr
Can someone help with this please thanks!
Answer:
150 I believe but don't quote me on that
ALGEBRA 1
Find the number of terms in the sequence given below:
1.5, 9, 13, ........, 201
a. 51
b. 42
c. 59
d. 45
Answer:
a. 51
Step-by-step explanation:
[tex]t_{n} =a+(n-1)d[/tex]
201 = 1 + (n - 1)4
200 = (n - 1)4
50 = n - 1
51 = n
Describe the transformation of ƒ(x) = log5 x which is given by g(x) = 3 log5 (x−7). Question 16 options: A) g(x) is shrunk vertically by a factor of 1∕3 and translated to the right 7 units compared to ƒ(x). B) g(x) is stretched vertically by a factor of 2 and translated to the left 7 units compared to ƒ(x). C) g(x) is stretched vertically by a factor of 3 and translated to the right 7 units compared to ƒ(x). D) g(x) is shrunk vertically by a factor of 1∕3 and translated to the left 7 units compared to ƒ(x)
Answer:
C) g(x) is stretched vertically by a factor of 3 and translated to the right 7 units compared to ƒ(x).
Step-by-step explanation:
Notice that by transforming [tex]f(x)=log_5\,(x)[/tex] into [tex]g(x)=3\,log_5\,(x-7)[/tex] we have performed the following transformations:
a) a horizontal shift to the right 7 units by subtracting 7 from the x-variable, and
b) stretching the full function vertically by a factor of 3, by multiplying the full function by 3.
Therefore, our answer matches answer C in the list of possible options
AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.
Answer:
The distance of the midpoint of AB = 4 cm
The distance of the midpoint of CD = 28 cm
Step-by-step explanation:
The given information are;
Segment AD = 36
Point C and point B are points on AD such that AB:BC:CD = 2:3:4
Which gives;
The proportion of AB in AD = 2/(2+3+4) = 2/9
The length of AB = 2/9×36 = 8 cm
The proportion of BC in AD = 3/(2+3+4) = 3/9
The length of AD = 3/9×36 = 12 cm
The proportion of CD in AD = 3/(2+3+4) = 4/9
The length of AD = 4/9×36 = 16 cm
The coordinate of the midpoint of AB = 8/2 = 4 cm from A
The distance of the midpoint of AB = 4 cm
The coordinate of the midpoint of CD = 8 + 12 + 16/2 = 28 cm from A
The distance of the midpoint of CD = 28 cm.
The fourth and fifth graders at Jackson Elementary had a competition to see who could
recycle the most newspaper in a 3-day period. Use the chart to answer the question,
The students at Lee Elementary collected 3 times as much as the students at Jackson. How
many pounds did the students at Lee recycle?
Answer: the elementary 45
Step-by-step explanation: if you need anything else let me know
In the figure below, PR and PQ are tangent to the circle with center O. Given that OQ = 10 and OP = 26, find PR.
Explanation:
OQ = 10 is the radius, and so is segment RO. Both are the same length as they are the radii of the same circle. Triangle ORP has a leg of RO = 10 and a hypotenuse of PO = 26. The unknown side is PR = x.
Use the pythagorean theorem. We can use this theorem because the tangent formed (at point R) creates a 90 degree angle.
a^2 + b^2 = c^2
(PR)^2 + (RO)^2 = (PO)^2
x^2 + 10^2 = 26^2
x^2 + 100 = 676
x^2 = 676 - 100
x^2 = 576
x = sqrt(576) ... apply square root
x = 24
How is everyone doing today? Here is a problem for the day! Problem - 10 + 8 x 119
Answer:
..
-10 + 8× 119
= -10 + 952
= 942. .....
Answer:
236 (i think)
Step-by-step explanation:
cuz 0-10= -10+8= -2 X 119=236 (sorry if you cant read this my keyboard sucks
how is this question solved?
Answer:
[tex]\large \boxed{\sf \ \ 35.805 \ \ }[/tex]
Step-by-step explanation:
Hello,
First of all we need to find the intersection points of y = 12 and
[tex]y=f(x)=e^x+e^{-x}[/tex]
We need to solve the following equation.
[tex]e^x+e^{-x}=12\\\\\text{*** We multiply by }e^x\text{ both side ***}\\\\\left(e^x\right)^2+1=12e^x\\\\\text{*** Let's note } X =e^x\text{, it comes *** }\\\\X^2-12X+1=0[/tex]
[tex]\Delta=b^2-4ac=12^2-4=140=2^2\cdot 35\\\\X_1=\dfrac{12-2\sqrt{35}}{2}=6-\sqrt{35}\\\\X_2=\dfrac{12+2\sqrt{35}}{2}=6+\sqrt{35}\\[/tex]
And, we take the greater solution to solve:
[tex]X=e^x=6+\sqrt{35}<=>\boxed{x=ln(6+\sqrt{5})}[/tex]
Let's note it a.
Let's compute the integral.
We need to compute the following (because 12-f(x) is pair the integral that we are looking for is)
[tex]\displaystyle 2\int\limits^a_{0} {\left(12-(e^x+e^{-x})\right)} \, dx =12*(2a)-2\int\limits^a_{0} {(e^x+e^{-x})} \, dx \\\\=24a-2[e^x-e^{-x}]_{0}^a=24a-2(e^a-e^{-a})[/tex]
We can replace a by the value we already found.
[tex]24\cdot ln(6+\sqrt{35})-2\left( 6+\sqrt{35}-\dfrac{1}{6+\sqrt{35}}\right)\\\\=24\cdot ln(6+\sqrt{35})-2\left(6+\sqrt{35}-\dfrac{\sqrt{35}-6}{(\sqrt{35}-6)(\sqrt{35}+6)}\right)\\\\=24\cdot ln(6+\sqrt{35})-2\left(\dfrac{29*6+29*\sqrt{35}-\sqrt{35}+6}{29}\right)\\\\\\=24\cdot ln(6+\sqrt{35})-2\left(\dfrac{180+28\sqrt{35}}{29}\right)\\\\[/tex]
= 59.46933...-26.66432...=35.8050...
So the answer is [tex]\boxed{\sf \ \ 35.805 \ \ }[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
The linear combination method gives a solution of (–4, 2) for which of these systems of linear equations? 3 x + 13 y = 14. 6 x + 11 y = negative 2. 4 x + 5 y = 12. 8 x + 3 y = negative 4. 5 x + 4 y = 12. 7 x + 8 y = 12. 10 x + 3 y = 8. 17 x + 6 y = 10.
Answer:choice one
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
I did the test
Which equation is correct regarding the measure of ∠MNP?
Answer:
I need the numbers
Step-by-step explanation:
Answer:
m∠MNP = (x – y)
m∠MNP = (x + y)
m∠MNP = (z + y)
m∠MNP = (z – y)
Plot 1 1/3 and 2 7/9
Answer:
I plotted them for you!
The first dot (closest to the left) is 1 1/3 and the one closest to the right is 2 7/9 :)
Step-by-step explanation:
Hope this helped :) good luck!
Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2).
Answer:
(-6,6), (0,12), (4,8)
Step-by-step explanation:
To dilate an object, we need to multiply the x and y values by the given scale factor.
In this case the scale factor is 2 --> 2(x, y)
Before-> After dilation
2(-3,3) = (-6,6)
2(0,6) = (0,12)
2(2,4) = (4,8)
Please leave a 'thanks' if this helps!
Hurry!!
State the domain of the glven relation.
Answer:
x ≤ -1
Step-by-step explanation:
A line passes through the point (6,1)and has a slope of 3/2. write an equation in slope intercept form
Answer:
Step-by-step explanation:
Slope intercept form : y - y1 = m(x -x1)
m = 3/2
(x1, y1) = (6, 1)
[tex]y - 1 = \frac{3}{2}(x - 6)\\\\y -1 = \frac{3}{2}*x -\frac{3}{2}*6\\\\y-1=\frac{3}{2}x-3*3\\\\y-1=\frac{3}{2}x-9\\\\y=\frac{3}{2}x-9+1\\\\y=\frac{3}{2}x -8[/tex]
Answer:
y=3/2 x -8
Step-by-step explanation:
The slope should be in front of the x and the y intercept should be right after the x to create the slope intercept form. I used a graphing calculator which continued the line of 6,1 with a slope of 3/2 and then got
y=3/2x-8
Which equation gives the length of the altitude of ABC?
Answer:
B. AD = sqrt(CD * BD)
Step-by-step explanation:
By the right triangle altitude theorem,
CD/AD = AD/BD
AD^2 = CD * BD
AD = sqrt(CD * BD)
Answer: B. AD = sqrt(CD * BD)
Answer:
B
Step-by-step explanation:
[tex]$\frac{CD}{AD} =\frac{AD}{BD} $[/tex]
[tex]AD^2=CD \cdot BD[/tex]
[tex]AD=\sqrt{CD \cdot BD}[/tex]
In this question, you are clearly supposed to use the geometric mean theorem or known as the right triangle altitude theorem. But note that there are other approaches to find the height of the triangle.
Using Pythagorean theorem:
[tex]AD^2+CD^2=AC^2 \Rightarrow AD=\sqrt{AC^2-CD^2}[/tex]
Also,
[tex]AD=AC\sin(c)[/tex]
I NEED HELP ASAP! What is the interquartile range (IQR) of the data set below? Will give one lucky person the title as the brainliest (if they are correct).
Hey there! I'm happy to help!
First, we arrange the numbers from least to greatest.
26,29,31,31,32,37,43
The median here is 31 because it is the middle number. The three numbers before it is one half of it and the last 3 numbers are their own half, because you cannot split the 31 between the two halves.
Now, we want to find the first quartile. This is basically the media of the first half of numbers. So, our first half consists of 26,29, and 31.
The middle number of this first half is 29.
So, our Q1 (first quartile) is 29.
Now, for the third quartile. We do the exact same thing here but with the second half.
32,37,43
Looking at this, our Q3 is 37
The interquartile range is how far apart Q1 and Q3 are, so to find it, we subtract our Q1 from the Q3.
37-29=48
Therefore, our IQR is 8.
Congratulations! Now you can find the IQR of a data set! Have a wonderful day! :D
Answer:
8
Step-by-step explanation:
You first put the numbers in order. Then you find the median(in this case, 31) and after that you find the Q1 and Q3(think of Q1 as the median of the lower half and Q3 as the mdian of the upper half.) Subtract Q1 from Q3, in this case, 37-29=8. 8 is the IQR or the interquratile range.
One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What weight of candies did they each eat?
Answer:
First person ate 2.1 pounds and second person ate 4.8 pounds
Step-by-step explanation:
First we find the common denominator. So 3/5=12/20. 12/20+3/20+15/20. That means that 5/20=1.5 lb. So 1/20=.3 pounds. So person number one ate .9+1.2=2.1 pounds of candy and person number two ate 4.5+.3=4.8
30 POINTS! Arrange the steps to solve this problem. 9 steps.
Answer:
1. Multiply the first equation by 3
3(x + y ) = 3(-2)
3x + 3y - 6
2. Add 3x + 3y = - 6 ( obtained in step 1) to
2x - 3y = - 9 (given) and solve for x
3. x = - 3
4. Substitute the value of x in the first equation
( x + y = - 2) to get y = - 1
5. The solution for the linear system of equations is ( - 3 , 1)
Hope this helps you
Brett is making chocolate bars. He wants to make 35 bars from Monday to Friday. One cocoa pod makes ⅚ of bar. If he harvests the same number of cocoa pods each day, how many cocoa pods should he harvest each day to reach his goal of making 35 bars total from Monday to Friday?
Answer:
one cocoa pod makes 5/6 bar
to make 35 bars, he needs
35 / (5/6) = 35 * 6/5 = 42 pods
Monday - Friday is 5 days
42/5 = 8.4
(30 POINTS!!!) One press can run the day’s newspapers in 6 hours, while another can do the same job in 8 hours. After running together for 2 hours to complete the job, the faster one breaks. How much longer must the slower press run to finish the newspapers?
Amount of the job done after 2 hours:
2(1/6 + 1/8)
2(4/24 + 3/24)
2(7/24)
7/12 (amount of job finished)
.
amount of job left to do:
1 - 7/12
12/12 - 7/12
5/12 (remaining)
.
Let x = time (hours) slower press takes to finish job
then
x(1/6) = 5/12
multiplying both sides by 6:
x = 5/12 *6
x = 5/2 hours
or
x = 2 hours and 30 minutes
The slower press (8-hour press), will take h 3 hours, 20 minutes to complete the job
The number of members of an online community increases each month. The
function M(t) = N(1 + ) represents the number of members at month t, where
Nis the initial number of members and ris the rate of increase. Select the
correct statement.
O A. Nincreases each month.
B. The initial value is (1 + r).
C. The function is linear.
D. The value of Mis a product of Nand a factor that does not depend
on N.
Can anyone plz help me
Answer:
vertex (-4,-1)
2nd point ( 0,31)
Step-by-step explanation:
f(x) = 2x^2 + 16x + 31
First find the vertex
The x coordinate of the vertex is -b/2a where ax^2 +bx +c
-16/ 2(2) = -16/4 = -4
Substitute into the function
f(-4) = 2 ( -4)^2 +16(-4) +31
= 2 *16-64 + 31
= 31 -64 +31
= -1
The vertex is at ( -4,-1)
Another point can be x=0
f(0) = 0+16(0)+31
= 31
( 0,31)
helpppp me now plz help
Answer:
0.53 is the right answer
Find the variation constant and an equation of variation where y varies directly as x and y=16 when x=2
Answer:
variation constant = k = 8
equation of variation : y = 8x
Step-by-step explanation:
Any relationship of variation can be written as y = kx
where k is the variation constant.
_______________________________________
Let the equationof relation between y and x be y =kx here as well
given
y = 16 when x = 2
substituting this value in the equation y = kx
16 = k*2
=> k = 16/2 = 8
Thus,
variation constant = k = 8
equation of variation : y = 8x
please help attachment
Answer:
v = 7
Step-by-step explanation:
a. v = 5x + 2y
= 5 × 3 + 2 × -4
= 15 + -8
= 7
Sorry I know only the A one anyways , hope this helps :)
Answer:
Step-by-step explanation:
a v = 5x+ 2y = 5*3 + 2*-4 = 7
b 3p(p+5) = 3p^2 =15p
c 4k = 44
k=44/4 =11
i hope the person who had deleted my answer this much explanation is only required if not please say so that I can correct myself by ellaborating ...
Identify an equation in point-slope form for the line perpendicular to
y=-2x+ 8 that passes through (-3,9).
O A. y - 9 = -2(x+3)
O B. y+3 - 3(x-9)
O C. y-9-(x + 2)
O D.y +9 = 2(x – 3)
The correct option is A. The equation in point-slope form for the line perpendicular to y = -2x + 8 and passing through (-3, 9) is: y - 9 = 1/2(x + 3).
To find the equation of a line perpendicular to y = -2x + 8 that passes through the point (-3, 9), we need to determine the slope of the perpendicular line.
The given equation is in slope-intercept form, y = mx + b, where m represents the slope. In this case, the slope of the given line is -2.
Since the perpendicular line has a slope that is the negative reciprocal of -2, we can determine its slope as 1/2.
Now that we have the slope (1/2) and a point (-3, 9) on the line, we can use the point-slope form of a line to write the equation:
y - y₁ = m(x - x₁)
where (x₁, y₁) is the given point and m is the slope.
Plugging in the values, we get:
y - 9 = 1/2(x - (-3))
Simplifying:
y - 9 = 1/2(x + 3)
Rearranging to match the given options:
y - 9 = 1/2(x) + 3/2
The equation in point-slope form for the line perpendicular to y = -2x + 8 and passing through (-3, 9) is:
y - 9 = 1/2(x + 3)
Therefore, the correct option is A.
Learn more about equation here
https://brainly.com/question/17126696
#SPJ2
Complete question is below
Identify an equation in point-slope form for the line perpendicular to
y=-2x+ 8 that passes through (-3,9).
A. y - 9 = 1/2(x+3)
B. y+3 = 3(x-9)
C. y - 9 = (x + 2)
D. y + 9 = 1/2(x – 3)
8. After a certain transformation is applied to point (x,y) is moved to (y,-x).
Name the transformation.
Rotation
Translation
Reflection
Dilation
Answer:
Rotation
Step-by-step explanation:
when you rotate a point it swaps the numarical values x⇄y as well as in some cases it changes its the symbol from negative to positive depending on the quadrant, in this case, it started in quadrant one and ended in quadrant three.
What is the mass in grams of 1.00 gal of water? The density of water is 1.00 g/ml.
The mass of water will be - 3785.41 grams.
We have density of water is 1.00 g/ml.
We have to determine the mass in grams of 1.00 gal of water.
Describe the relation between Mass (m) and Density (ρ).The relation between Mass (m) and Density (ρ) is -
m = ρV
where - V is the volume of object.
According to the question -
Density of water - 1.00 g/ml
Volume of water - 1 gallon = 3785.41 ml
m = ρV
m = 1 x 3785.41 = 3785.41 grams.
Hence, the mass of water will be - 3785.41 grams.
To solve more questions on Mass and Density, visit the link below -
https://brainly.com/question/24641072
#SPJ2