Answer:
mosses
Step-by-step explanation:
use socratic
Mosses are also known as the amphibian of the plant kingdom. The mosses were the first plant that can even survive on the land.
Bryophytes:It is the group of small plants that complete its life cycle in both land and water. They were the first plants to adapt to live on the land.For example- mosses.Conifers, pines, and flowering plants developed much later after the evolution of bryophytes.
Therefore, the mosses were the first plant that can even survive on the land.
Learn more about Bryophytes:
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Samuel filled the glasses shown below completely with water. The total amount of water that Samuel poured into the glasses is 60 cubic centimeters. What is the height of glass 1? Round your answer to the nearest tenth. (Use π = 3.14.) Note that all measurements are in centimeters and images are not drawn to scale. A cylinder with width 4 and height unknown is labeled glass 1, and a cone with height 6 and width 5 is labeled glass 2. 0.2 centimeter 1.7 centimeters 3.9 centimeters 5.6 centimeters
Answer:
1.7
Step-by-step explanation:
1. Find the volume of Glass 2 (volume of a cone = 1/3πr² ·h)
1/3 · 3.14 · 2.5² · 6 = 39.25 cm³
2. Subtract the volume of Glass 2 from the amount of water poured
60 - 39.25 = 20.75 cm³
3. Set up the equation for Glass A using x for the height being solved for (volume of a cylinder = πr² · h)
3.14 · 2² · x = 20.75
12.56x = 20.75
4. Solve for x by dividing both sides by 12.56 (round to the nearest tenth)
x = 1.7
The answer should be 1.7
Determine which of the following statements is true. A: If V is a 6-dimensional vector space, then any set of exactly 6 elements in V is automatically a basis for V. B: If there exists a set that spans V, then dim V = 3. C: If H is a subspace of a finite-dimensional vector space V, then dim H ≤ dim V
Answer:
A. This statement A is false.
B. This statement A is false.
C. This statement is true .
Step-by-step explanation:
Determine which of the following statements is true.
From the statements we are being given , we are to determine if the statements are valid to be true or invalid to be false.
SO;
A: If V is a 6-dimensional vector space, then any set of exactly 6 elements in V is automatically a basis for V
This statement A is false.
This is because any set of exactly 6 elements in V is linearly independent vectors of V . Hence, it can't be automatically a basis for V
B. If there exists a set that spans V, then dim V = 3
The statement B is false.
If there exists a set , let say [tex]v_1 ...v_3[/tex], then any set of n vector (i.e number of elements forms the basis of V) spans V. ∴ dim V < 3
C. If H is a subspace of a finite-dimensional vector space V then dim H ≤ dim V is a correct option.
This statement is true .
We all know that in a given vector space there is always a basis, it is equally important to understand that there is a cardinality for every basis that exist ,hence the dimension of a vector space is uniquely defined.
SO,
If H is a subspace of a finite-dimensional vector space V then dim H ≤ dim V is a correct option.
Perform the indicated operation. 15b/4 * 8/9a^2b^2
Answer:
The simplified expression is [tex]\frac{10}{3 a^2 b}[/tex]
Step-by-step explanation:
The given expression is:
[tex]\frac{15b}{4} * \frac{8}{9a^2 b^2}[/tex]
Multiply the items in the numerator together ( 15b * 8 = 120 b). Also multiply the items in the denominator together ( 4 * 9a²b² = 36a²b²). The expression thus becomes:
[tex]= \frac{120b}{36 a^2 b^2} \\\\[/tex]
Divide both the numerator and the denominator by 12b:
[tex]= \frac{120b /12b}{36 a^2 b^2/12b}[/tex]
The expression finally becomes:
[tex]= \frac{10}{3 a^2 b}[/tex]
Answer:
Step-by-step explanation:
here u go
Transformations of exponential functions
Answer:
Since the transformation is made by shifting the function right, it is a horizontal transformation.
Faizan buys a car for £2000.Its value depreciates by 2% each year. How much is it worth after 1 year?
Answer:
£1960
Step-by-step explanation:
Step 1.
2% = 100% ÷ 50
Step 2.
£2000 ÷ 50 = £40
Step 3.
£2000 - £40 = £1960
what is the point slope equation of a line with a slope 4 of a that contains the point (6, -2)?
Answer:
y+2 = 4(x-6)
Step-by-step explanation:
The point slope equation of a line is
y-y1 = m(x-x1) where m is the slope and ( x1,y1) is a point on the line
y - -2 = 4( x-6)
y+2 = 4(x-6)
Two similar data sets are being compared. The standard deviation of Set A is 4.8. The standard deviation of Set B is 6.5.
Answer:
The spread of the data in Set B is greater than the spread of the data in Set A.
Step-by-step explanation:
Just took the test :3
Tyler needs to get the windows in his new home cleaned. The cleaning company needs to know the total number of window panes before it can
tell him how much the job will cost. There are 12 windows, each with four window panes across and four window panes down. Tyler can find the
total number of window panes by multiplying the number of windows by the number of panes in each window. The total number of window
panes is an expression with a whole number exponent.
Answer:
There are 192 window panes in total.
Step-by-step explanation:
Since each window has four window panes across and four window panes down,the number of panes per window is:
[tex]w=4*4=4^2[/tex]
The total number of window panes in 'n' windows is:
[tex]P=n*4^2[/tex]
With n = 12 windows, the expression that describes the total number of window panes is:
[tex]P=12*4^2\\P=192\ panes[/tex]
There are 192 window panes in total.
Answer:
One window has 4 × 4, or 42, window panes, so 12 windows have 12 × 4^2 window panes.
Step-by-step explanation:
One window has 4 × 4, or 42, window panes, so 12 windows have 12 × 4^2 window panes.
A sample of size 60 from one population of weights had a sample average of 10.4 lb. and a sample standard deviation of 2.7 lb. An independent sample of size 100 from another population of weights had a sample average of 9.7 lb. with a sample standard deviation of 1.9 lb. Find a 95% confidence interval for the difference between the population means.
Answer:
z= 0.278
Step-by-step explanation:
Given data
n1= 60 ; n2 = 100
mean 1= x1`= 10.4; mean 2= x2`= 9.7
standard deviation 1= s1= 2.7 pounds ; standard deviation 2= s2 = 1.9 lb
We formulate our null and alternate hypothesis as
H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)
We set level of significance α= 0.05
the test statistic to be used under H0 is
z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂
the critical region is z > ± 1.96
Computations
z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100
z= 10.4- 9.7/ √ 7.29/60 + 3.61/100
z= 0.7/√ 0.1215+ 0.0361
z=0.7 /√0.1576
z= 0.7 (0.396988)
z= 0.2778= 0.278
Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0 at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.
Calculate the pay for the following day of a
weekly time card given a wage of $14/hr.
Morning:
In 08:00
Out 12:00
Afternoon:
In 12:45
Out 17:30
pay = $[?]
Answer: $122.50
Step-by-step explanation:
In Out
8:00 12:00 = 4 hours
12:45 17:30 = 4.75 hours
Total 8.75 hours
8.75 hours x $14/hr = $122.50
Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:
17:30 → 16:90
- 12:45 - 12:45
4: 45
4 hours 45 minutes = [tex]4\frac{3}{4}[/tex] = 4.75 hours
A weather balloon holds 2,000 cubic meters of helium. The density of helium is 0.1765 kilograms per cubic meter. How many kilograms of helium does the balloon contain? Only enter a numerical value in the answer blank.
Answer:
353 kg
Step-by-step explanation:
So you want to find the number of kg by finding the answer through the density formula. To do this you take the formula of Density, which is [tex]D=\frac{m}{v}[/tex]. Now you substitute D for the density of 0.1765, and v for the volume, which is 2000, to then get [tex]0.1765=\frac{m}{2000}[/tex]. Now you solve for m. To do this you multiply each side by 2000. This brings you with [tex]353=m[/tex] after multiplying 0.1765 and 2000. Hope this helps!
The mass of the helium that the balloon contain will be 353 kilograms.
What is density?Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
The mass and density relation is given as
Mass = density × volume
A weather balloon holds 2,000 cubic meters of helium.
The density of helium is 0.1765 kilograms per cubic meter.
The mass of the helium that the balloon contain will be
Mass = 0.1765 × 2000
Mass = 353 kilograms
To learn more about the density refers to the link;
brainly.com/question/952755
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solve the inequality -2/11 j _< 8
Answer:
j ≥ -44
Step-by-step explanation:
-2/11 j ≤ 8
Multiply each side by -11/2 to isolate j. Flip the inequality since we are multiplying by a negative
-11/2 * -11/2 j ≥ 8 * -11/2
j ≥ -44
Answer:
[tex]j\geq -44[/tex]
Step-by-step explanation:
The inequality given is:
[tex]\frac{-2}{11}j\leq 8[/tex]
To solve the inequality, we must get the variable j by itself.
j is being multiplied by -2/11. To reverse this, we must multiply by the reciprocal of the fraction.
Flip the numerator (top number) and denominator (bottom number) to find the reciprocal.
[tex]\frac{-2}{11} --> \frac{-11}{2}[/tex]
Multiply both sides of the equation by -11/2.
[tex]\frac{-11}{2} *\frac{-2}{11} j \leq 8*\frac{-11}{2}[/tex]
[tex]j\leq 8*\frac{-11}{2}[/tex]
Since we multiplied by a negative number, we must flip the inequality sign.
[tex]j\geq 8*\frac{-11}{2}[/tex]
Multiply 8 and -11/2
[tex]j\geq 8*-5.5[/tex]
[tex]j\geq -44[/tex]
The solution to the inequality is: [tex]j\geq -44[/tex]
Solve tan theta +1=-2tan theta
Answer:
[tex]\boxed{135\°,315\°}[/tex]
Step-by-step explanation:
Solve the trigonometric equation by isolating the function and then taking the inverse. Use the period to find the full set of all solutions.
[tex]\theta = 135+180n[/tex]
[tex]n[/tex] is any integer value.
The value of [tex]n[/tex] cannot exceed 1 or be less than 0, because the value of [tex]\theta[/tex] must be between 0 and 360 degrees.
[tex]\theta = 135+180(0)[/tex]
[tex]\theta = 135[/tex]
[tex]\theta = 135+180(1)[/tex]
[tex]\theta = 315[/tex]
among the following, an incorrect statement is a) the volume of the hollow sphere =4/3π (r^3—r^3), where r is the radius of the outer sphere and r is the radius of the inner sphere. b) the volume of the hemisphere of radius(r) is 2πr^3 c) the surface area sphere = 4πr^2 d) the surface area of a spherical shell = 4π (r^2—r^2), where r = external radius and r= internal radius
please can someone say which one is incorrect
Answer:
fncjcnj jcj jcj jcj jd. d. c. dn. d. c. c. x. c. c. c.
What the answer fast
Answer:
when we add all the angles.
=58+94+15=167
so it's a 180..
180_167
=13
round to nearest tenth.
=10..
C(t) = 2t^4 – 8t^3 +6t^2 Find the t-intercept?
Answer:
0
Step-by-step explanation:
The t-intercept here is what's khown as the x-intercept wich is given by C(t)=0
● C(t) = 2t^4-8t^3+6t^2
● 0 = 2t^4-8t^3+6t^2
Factor using t
● t(2t^3-8t^2+6t^1) = 0
Wich means that t=0
−30=5(x+1) solve for x pls help
Answer:
[tex] \boxed{\sf x = -7} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: x: \\ \sf \implies - 30 = 5(x + 1) \\ \\ \sf - 30 =5(x+ 1) \: is \: equivalent \: to \: 5 (x + 1) = - 30: \\ \sf \implies 5(x + 1) = - 30 \\ \\ \sf Divide \: both \: sides \: of \: 5(x+ 1) = - 30 \: by \: 5: \\ \sf \implies \frac{5(x + 1)}{5} = - \frac{30}{5} \\ \\ \sf \frac{5}{5} = 1 : \\ \sf \implies x + 1 = - \frac{30}{5} \\ \\ \sf - \frac{30}{5} = - \frac{6 \times \cancel{5}}{ \cancel{5}} = - 6 : \\ \sf \implies x + 1 = - 6 \\ \\ \sf Subtract \: 1 \: from \: both \: sides: \\ \sf \implies x + (1 - 1) = - 6 - 1 \\ \\ \sf 1 - 1 = 0 : \\ \sf \implies x = - 6 - 1 \\ \\ \sf - 6 - 1 = - 7 : \\ \sf \implies x = - 7[/tex]
Answer:
[tex] \boxed{x = - 7}[/tex]
Step-by-step explanation:
[tex] \mathrm{ - 30 = 5(x + 1)}[/tex]
Distribute 5 through the parentheses
[tex] \mathrm{ - 30 = 5x + 5} [/tex]
Move constant to L.H.S and change its sign
[tex] \mathrm{ - 30 - 5 = 5x}[/tex]
Calculate
[tex] \mathrm{ - 35 = 5x}[/tex]
Swipe the sides of the equation
[tex] \mathrm{5x = - 35}[/tex]
Divide both sides of the equation by 5
[tex] \mathrm{ \frac{5x}{5} = \frac{ - 35}{5} }[/tex]
Calculate
[tex] \mathrm{x = - 7}[/tex]
Hope I helped!
Best regards!!
core: 0 of 1 pt
9 of 9 (0 complete)
HW Score: 0%, 0 of 9 p
.7.29
Skill Builder
Question Help
The supply function and demand function for the sale of a certain type of DVD player are given by S(p) = 140e 0.005p and D(p) = 448e -0.003p, where S(p) is the number
of DVD players that the company is willing to sell at price p and D(p) is the quantity that the public is willing to buy at price p. Find p such that D(p) = S(p). This is called
the equilibrium price.
The equilibrium price is about $
(Do not round until the final answer. Then round to two decimal places as needed.)
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Enter your answer in the answer box and then click Check Answer.
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Final Check
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Answer:
145.39
Step-by-step explanation:
The ratio of supply to demand will be 1 at the equilibrium price:
S(p)/D(p) = 1 = 140e^(0.005p)/(448e^(-0.003p))
448/140 = e^(0.005p -(-0.003p)) = e^(0.008p)
ln(448/140) = 0.008p . . . . . . . . . taking the natural log
p = ln(448/140)/0.008 ≈ 145.39
The equilibrium price is about $145.39.
What additional information do you need to prove △ABC ≅ △DEF by the SSS Postulate? A. BC = EF B. AB = DE C. AC = DF
Answer:
AC = DF
Step-by-step explanation:
The SSS Postulate occurs when all three corresponding pairs of sides are congruent, therefore, the only missing pair is AC = DF.
A scrub nurse recorded the temperature in the operating theatre every two hours over a 12 hour period from noon to midnight. The results are shown in the following line graph
NoAnswer:
Step-by-step explanation:
Cause I’m good
A rectangular piece of sheet metal has an area of 1200 in2. It is going to be bent into a cylinder with volume 600 in3. What are the dimensions of rectangular piece of sheet metal
Answer:
x=6.28 inches
y=191.08 inches
Step-by-step explanation:
Let the dimensions of the rectangle be x and y
Area of the rectangular sheet
x*y=1200 in^2}
x = circumference of the cylinder
This means x=2πr
Volume of a cylinder=πr^2h
h=y
Volume of the cylind=πr^2(y)=600 in^3
From x=2πr
r=x/2π
Substitute r=x/2π into Volume=πr^2(y)=600 in^3
We have,
Volume of the cylinder=πr^2(y)=600 in^3
π*(x/2π)^2(y)=600
(x^2/4π)y=600
Recall, x*y=1200
y=1200/x
Substitute y=1200/x into (x^2/4π)y=600
(x^2/4π)y=600
(x^2/4π)(1200/x)=600
1200x/4π=600
Multiply both sides by 4π
(x^2/4π)(1200/x)(4π)=600*4π
1200x=2400π
Divide both sides by 1200
1200x/1200 = 2400π/1200
x=2π
Substitute x=2π into y=1200/x
We have,
y=1200/2π
y=600/π
The dimensions are x=2π and y=600/π
Let π=3.14
x=2π
=2(3.14)
=6.28 inches
y=600/π
=600/3.14
=191.08 inches
The function s(V) = Negative RootIndex 3 StartRoot uppercase V EndRoot describes the side length, in units, of a cube with a volume of V cubic units. Jason wants to build a cube with a minimum of 64 cubic centimeters.
What is a reasonable range for s, the side length, in centimeters, of Jason’s cube?
This question is incomplete
Complete Question
The function s(V) = ∛V describes the side length, in units, of a cube with a volume of V cubic units.
Jason wants to build a cube with a minimum of 64 cubic centimeters.
What is a reasonable range for s, the side length, in centimeters, of Jason’s cube?
a) s > 0
b) s ≥ 4
c) s ≥ 8
d) s ≥ 16
Answer:
b) s ≥ 4
Step-by-step explanation:
From the above question, we are given Volume of the cube = 64cm³
We are given the function
s(V) = ∛V
Hence,
The range for the side length s =
s(V) ≥ ∛V
s(V) ≥ ∛64 cm³
s(v) ≥ 4 cm
Therefore, the reasonable range for s, the side length, in centimeters, of Jason’s cube
Option b) s ≥ 4
Answer:
s≥ 4
Step-by-step explanation:
A researcher wishes to estimate the number of households with two cars. A previous study indicates that the proportion of households with two cars is 25%. How large a sample is needed in order to be 99% confident that the sample proportion will not differ from the true proportion by more than 3%?
A) 4.
B) 1132.
C) 1842.
D) 1382.
At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. The lower 5% of the class will not get a passing grade. Find the score that separates the lower 5% of the class from the rest of the class
Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
The graph represents function 1 and the equation represents function 2:
Function 2 y = 4x + 1
How much more is the rate of change of function 2 than the rate of change of function 1?
Greetings from Brasil...
In a linear function, the rate of change is given by M (see below).
F(X) = Mx + NM = rate of change
N = linear coefficient
The Function 2 has M = 4, cause
F(X) = 4X + 1
(M = 4 and N = 1)
For Function 1 we have a rate of change equal to zero, becaus it is a constant function... let's see:
M = ΔY/ΔX
M = (3 - 3)/(4 - 0)
M = 0/4 = 0
So, the Function 2 has 4 times more rate of change than the first
Your answer is two!!
Find (f•g)(x) for the given functions: f(x) = 5/x and g(x) = 3 + x/5.
PLEASE HELP
Speed of pulley A = 400 r.p.m.
Speed of pulley B =
A:100
B:200
C:1600
Speed of pulley C =
A:100
B:1600
C:200
Speed of pulley D =
A:100
B:40
C:160
see attachment a=400 rpm b and c = 200 rpm d = 40 rpm
Answer:
pulley B 200, pulley C 200, pulley D 160
A father's age is 4 times as that of his son's age. in 5 years time, the father will be 3 times as old as his son. what are their present ages?
Answer:
present age of son = 10 present age of father = 40Step-by-step explanation:
Let, present age of son be 'x'
present age of father be 'y'
y = 4x→ equation ( i )
After five years,
Son's age = x + 5
father's age = y + 5
According to Question,
[tex]y + 5 = 3(x + 5)[/tex]
Put the value of y from equation ( i )
[tex]4x + 5 = 3(x + 5)[/tex]
Distribute 3 through the parentheses
[tex]4x + 5 = 3x + 15[/tex]
Move variable to L.H.S and change it's sign
Similarly, Move constant to R.H.S. and change its sign
[tex]4x - 3x = 15 - 5[/tex]
Collect like terms
[tex]x = 15 - 5[/tex]
Calculate the difference
[tex]x = 10[/tex]
Now, put the value of X in equation ( i ) in order to find the present age of father
[tex]y = 4x[/tex]
plug the value of X
[tex] = 4 \times 10[/tex]
Calculate the product
[tex] = 40[/tex]
Therefore,
Present age of son = 10
present age of father = 40
Hope this helps..
Best regards!!
2x + 3 + 7x = – 24, what is the value of x?
14x + 3 = - 24
theeeeen I get stuck, HELP!
Answer:
-3
Step-by-step explanation:
2x + 3 +7x = -24
Add the X together
9x +3 = -24
Bring over the +3. [when you bring over change the sign]
9x = -24 -3
9x = -27
-27 divide by 9 to find X
therefore answer is
x= -3.
Hope this helps
Answer:
x = -3
Step-by-step explanation:
question is
2x + 3 + 7x = -24
First you combine the like terms
2x and 7x you can add them so it will be 9x
so it will then it will be like this:
9x + 3 = -24
now you take the 3 and send it to the other side, and right now the 3 is positive so when it goes to the other side it will turn into -3
so
9x = -24 -3
again now you combine the like terms
-24 -3 = - 27
now you have
9x = -27
now just divide each side by 9
x = -27/9
x = -3
Sorry if this doesnt help
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. VIEW FILE ATTACHED
Answer: see below
Step-by-step explanation:
[tex]P(x)=\dfrac{2}{3x-1}\qquad \qquad Q(x)=\dfrac{6}{-3x+2}\\[/tex]
P(x) ÷ Q(x)
[tex]\dfrac{2}{3x-1}\div \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\times \dfrac{-3x+2}{6}\\\\\\=\large\boxed{\dfrac{-3x+2}{3(3x-1)}}[/tex]
P(x) + Q(x)
[tex]\dfrac{2}{3x-1}+ \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)+ \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)+6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4+18x-6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{12x-2}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{2(6x-1)}{(3x-1)(-3x+2)}}[/tex]
P(x) - Q(x)
[tex]\dfrac{2}{3x-1}- \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)- \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)-6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4-18x+6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-24x+10}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{-2(12x-5)}{(3x-1)(-3x+2)}}[/tex]
P(x) · Q(x)
[tex]\dfrac{2}{3x-1}\times \dfrac{6}{-3x+2}\\\\\\=\large\boxed{\dfrac{12}{(3x-1)(-3x+2)}}[/tex]