Which confidence level will yield the interval that we are most confident in containing the actual value of the population parameter?
a. 99.2%
b. 99.5%
c. Our confidence in whether an interval actually contains the parameter is not affected by the choice of confidence level.
d. 99.9%

Answer:

Step-by-step explanation:

Given,

a = 4

y = -6

Now,

[tex] - a + 3y[/tex]

Plug the values

[tex] = - 4 + 3 \times ( - 6)[/tex]

Multiply the numbers

[tex] = - 4 + ( - 18)[/tex]

When there is a (+) in front of an expression in parentheses, the expression remains the same.

[tex] = - 4 - 18[/tex]

Calculate

[tex] = - 22[/tex]

Hope this helps..

Best regards!!

Answer:

14

Step-by-step explanation:

-4 + 3(6)

-4+18

14

Answer:

-4

Step-by-step explanation:

The slope would be (5 - (-3)) / (2 - 4) = 8 / -2 = -4.

Answer:

[tex]\huge\boxed{\text{The slope}\ m=-4}[/tex]

Step-by-step explanation:

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

(x₁; y₁), (x₂; y₂) - points on a line

We have the points:

[tex](2;\ 5)\to x_1=2;\ y_1=5\\(4;\ -3)\to x_2=4;\ y_2=-3[/tex]

Substitute:

[tex]m=\dfrac{-3-5}{4-2}=\dfrac{-8}{2}=-4[/tex]

Answer:

C. x = 2

Step-by-step explanation:

[tex] \sqrt{9x + 7} + \sqrt{2x} = 7 [/tex]

Since you have square roots, you need to separate the square roots and square both sides.

[tex] \sqrt{9x + 7} = 7 - \sqrt{2x} [/tex]

Now that one square root is on each side of the equal sign, we square both sides.

[tex] (\sqrt{9x + 7})^2 = (7 - \sqrt{2x})^2 [/tex]

[tex] 9x + 7 = 49 - 14\sqrt{2x} + 2x [/tex]

Now we isolate the square root and square both sides again.

[tex] 7x - 42 = -14\sqrt{2x} [/tex]

Every coefficient is a multiple of 7, so to work with smaller numbers, we divide both sides by 7.

[tex] x - 6 = -2\sqrt{2x} [/tex]

Square both sides.

[tex] (x - 6)^2 = (-2\sqrt{2x})^2 [/tex]

[tex] x^2 - 12x + 36 = 4(2x) [/tex]

[tex] x^2 - 20x + 36 = 0 [/tex]

We need to try to factor the left side.

-2 * (-18) = 36 & -2 + (-18) = -20, so we use -2 and -18.

[tex] (x - 2)(x - 18) = 0 [/tex]

[tex] x = 2 [/tex]   or   [tex] x = 18 [/tex]

Since solving this equation involved the method of squaring both sides, we much check for extraneous solutions by testing our two solutions in the original equation.

Test x = 2:

[tex] \sqrt{9x + 7} + \sqrt{2x} = 7 [/tex]

[tex] \sqrt{9(2) + 7} + \sqrt{2(2)} = 7 [/tex]

[tex] \sqrt{25} + \sqrt{4} = 7 [/tex]

[tex] 5 + 2 = 7 [/tex]

[tex] 5 = 5 [/tex]

We have a true equation, so x = 2 is a true solution of the original equation.

Now we test x = 18.

[tex] \sqrt{9x + 7} + \sqrt{2x} = 7 [/tex]

[tex] \sqrt{9(18) + 7} + \sqrt{2(18)} = 7 [/tex]

[tex] \sqrt{162 + 7} + \sqrt{36} = 7 [/tex]

[tex] \sqrt{169} + 6 = 7 [/tex]

[tex] 13 + 6 = 7 [/tex]

[tex] 19 = 7 [/tex]

Since 19 = 7 is a false equation, x = 18 is not a true solution of the original equation and is discarded as an extraneous solution.

Answer: C. x = 2

________________________Alike______________________

→ Both of the lines are proportional meaning they go through the origin.

→ Both of the lines have a positive slope meaning the slope goes towards the top right corner.

__________________________________________________

_____________________Difference_____________________

→ The 2 lines have different slopes, the first one has a slope of 1/3x whereas the 2nd one has a slope of 3x.

→ The points that create the lines are totally different, no two points are the same.

__________________________________________________

Answer:

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

Step-by-step explanation:

We have the following:

x = the speed of the jet in still air.

y = the speed of the wind

we know that the speed is equal to:

v = d / t

therefore the distance would be:

d = v * t

if we replace with the information of the exercise we have:

3 * (x + y) = 1095

3 * (x - y) = 987

we must solve this system of equations, add both equations and we are left:

3 * x + 3 * y = 1095

3 * x - 3 * y = 987

3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987

6 * x = 2082

x = 2082/6 = 347

now to calculate y, we replace:

3 * (347 + y) = 1095

1041 + 3 * y = 1095

3 * y = 1095 - 1041

y = 54/3 = 18

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

Answer:

Limits for B scores

( 79,2 ; 92 )

Step-by-step explanation:

The interval we are looking for is between 6 % and 59%

p₁  = 6 %     p₁ = 0,06

As this point is at the right tail of the bell we better look for

p = 1- 0,06     p = 0,94

In z-table z score for 0,94062  is:    z₁ = 1,56      ( 0,94062 ≈ 0,94 )

Doing the same to find z₂ score for 59%  or 0,59

In z-table again

p =  0,59      

z₂ = 0,023

Now we know

1,56 * σ  = x₁ - 79

1,56*8,4 + 79 = x₁

x₁  =  92,10        or  x₁ = 92

And

0,023*8,4 + 79  = x₂

x₂ = 79,19         or    x₂ = 79,2

Answer:

sec B = 17 / 15

Step-by-step explanation:

Sec theta = hyp / adj

sec B = 17 / 15

Answer:

17/15

Step-by-step explanation:

The secant of an angle is the ratio of the hypotenuse to the adjacent angle (it is also the reciprocal of cosine).

secθ=hypotenuse/adjacent

sec(∠B)= hypotenuse/adjacent

The hypotenuse in this triangle is 17, because it is opposite the right angle or the little square.

sec(∠B)=17/adjacent

The side adjacent, or next to angle B is 15.

sec(∠B)= 17/15

This fraction cannot be reduced further, therefore the secant of angle B is 17/15.

Answer:

-4x + 4

Step-by-step explanation:

4x - 2( 4x - 2 )

→ Expand out 2 ( 4x - 2 )

2 ( 4x - 2 ) = 8x - 4

→ Substitute the expanded bracket back into the expression

4x - (8x - 4)

→ Collect the 'x' values

-4x + 4

Answer:

  73/55

Step-by-step explanation:

The cosecant (csc) is one of the reciprocal functions:

  csc(θ) = 1/sin(θ)

  sec(θ) = 1/cos(θ)

  cot(θ) = 1/tan(θ)

So, if we can find the sine, we can find the cosecant.

__

The mnemonic SOH CAH TOA reminds you that the sine is ...

  Sin = Opposite/Hypotenuse

The above tells you that ...

  Csc = 1/Sin = Hypotenuse/Opposite

The hypotenuse of your triangle is AC = 73. The side opposite angle θ is BC = 55. So, the ratio you want is ...

  csc(θ) = 73/55

Answer:

[tex]csc (\theta)=\frac{33}{55}[/tex]

Step-by-step explanation:

Hello!

1) The cosecant function is the inverse the sine function. So we can write:

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

2) The sine function is the side opposite angle to [tex]\angle \theta[/tex] over the hypotenuse:

[tex]sin(\theta)=\frac{55}{33}[/tex]

3) So, remembering operations with fractions then the cosecant is:

[tex]csc \theta = \frac{1}{\frac{55}{33} } =1 \times \frac{33}{55}[/tex]

[tex]csc (\theta)=\frac{33}{55}[/tex]

Answer:

think its 3a 3.83838

Step-by-step explanation:

Answer:

-23/11

Step-by-step explanation:

Answer:

D (The last choice)

Step-by-step explanation:

We know that rays are lines with a dot on one side and an arrow on the other. WE also know that lines have two arrows on each end. Keeping this in mind, we can identify which line segments and rays and lines.

Answer:

[tex]5.625\pi[/tex] m³.

Step-by-step explanation:

The volume of a cylinder is found by calculating pi * r^2 * h.

In this case, h = 2.5, and r = 1.5.

pi * 1.5^2 * 2.5

= pi * 2.25 * 2.5

= pi * 5.625

So, the exact volume of the cylinder is [tex]5.625\pi[/tex] m³.

Hope this helps!

Answer: Volume of Cylinder: [tex]\pi r^{2} *h[/tex]

               5.625π  m.

Step-by-step explanation:

[tex]\pi r^{2} *h[/tex]   Cylinder Area Formula

[tex]\pi *1.5^{2} *2.5[/tex]   Substitution

[tex]\pi * 2.25 *2.5[/tex]   Exponent

[tex]\pi *5.625[/tex]   Multiply

[tex]5.625\pi[/tex] Answer

so you have the amount.

amount: 1200

then you have the ratio

ratio: 3:5

you have the count.

count: 2

and then you have the shares

shares: 8

and the amount per share is 150.00

so the total amount of shares is the sum of each person's ratio so,

so 1:5:2:3:9 = 1 + 5 + 2 + 3 +9 = 20 shares.  hope that helps you..

Answer:

Show the table or make ur question a little more clear so I can help

Step-by-step explanation:

Answer:

58 hours

Step-by-step explanation:

First week: 25 5/8 hours = 25 hrs 37 mins and 30 sec

Second weeK: 32 5/6 hrs = 32 hrs and 50 mins

To find the toal time in minutes

(37 + 50) mins = 1 hr 27 mins

Threfore, total number of hours he worked in two weeks:

(25 + 32 + 1) hrs = 58 hours

Answer:

1. [tex] P(x) [/tex] ÷ [tex] Q(x) [/tex]---> [tex] \frac{-3x + 2}{3(3x - 1)} [/tex]

2. [tex] P(x) + Q(x) [/tex]---> [tex]\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}[/tex]

3.  [tex] P(x) - Q(x) [/tex]---> [tex] \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)} [/tex]

4. [tex] P(x)*Q(x) [/tex] --> [tex] \frac{12}{(3x - 1)(-3x + 2)} [/tex]

Step-by-step explanation:

Given that:

1. [tex] P(x) = \frac{2}{3x - 1} [/tex]

[tex] Q(x) = \frac{6}{-3x + 2} [/tex]

Thus,

[tex] P(x) [/tex] ÷ [tex] Q(x) [/tex] = [tex] \frac{2}{3x - 1} [/tex] ÷ [tex] \frac{6}{-3x + 2} [/tex]

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

[tex] \frac{2}{3x - 1}*\frac{-3x + 2}{6} [/tex]

[tex] \frac{2(-3x + 2)}{6(3x - 1)} [/tex]

[tex] = \frac{-3x + 2}{3(3x - 1)} [/tex]

2. [tex] P(x) + Q(x) [/tex] = [tex] \frac{2}{3x - 1} + \frac{6}{-3x + 2} [/tex]

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

[tex] \frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{12x - 2}{(3x - 1)(-3x + 2)} [/tex]

[tex] = \frac{2(6x - 1}{(3x - 1)(-3x + 2)} [/tex]

3. [tex] P(x) - Q(x) [/tex] = [tex] \frac{2}{3x - 1} - \frac{6}{-3x + 2} [/tex]

[tex] \frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)} [/tex]

[tex] \frac{-24x + 10}{(3x - 1)(-3x + 2)} [/tex]

[tex] = \frac{-2(12x - 5}{(3x - 1)(-3x + 2)} [/tex]

4. [tex] P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2} [/tex]

[tex] P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)} [/tex]

[tex] P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)} [/tex]

Composite functions involve combining multiple functions to form a new function

The functions are given as:

[tex]P(x) = \frac{2}{3x - 1}[/tex]

[tex]Q(x) = \frac{6}{-3x + 2}[/tex]

[tex]P(x) \div Q(x)[/tex] is calculated as follows:

[tex]P(x) \div Q(x) = \frac{2}{3x - 1} \div \frac{6}{-3x + 2}[/tex]

Express as a product

[tex]P(x) \div Q(x) = \frac{2}{3x - 1} \times \frac{-3x + 2}{6}[/tex]

Divide 2 by 6

[tex]P(x) \div Q(x) = \frac{1}{3x - 1} \times \frac{-3x + 2}{3}[/tex]

Multiply

[tex]P(x) \div Q(x) = \frac{-3x + 2}{3(3x - 1)}[/tex]

Hence, the value of [tex]P(x) \div Q(x)[/tex] is [tex]\frac{-3x + 2}{3(3x - 1)}[/tex]

P(x) + Q(x) is calculated as follows:

[tex]P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}[/tex]

Take LCM

[tex]P(x) + Q(x) = \frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}[/tex]

Open brackets

[tex]P(x) + Q(x) = \frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}[/tex]

Collect like terms

[tex]P(x) + Q(x) = \frac{18x-6x + 4 - 6}{(3x - 1)(-3x + 2)}[/tex]

[tex]P(x) + Q(x) = \frac{12x - 2}{(3x - 1)(-3x + 2)}[/tex]

Factor out 2

[tex]P(x) + Q(x) = \frac{2(6x -1)}{(3x - 1)(-3x + 2)}[/tex]

Hence, the value of P(x) + Q(x) is [tex]\frac{2(6x -1)}{(3x - 1)(-3x + 2)}[/tex]

P(x) - Q(x) is calculated as follows:

[tex]P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}[/tex]

Take LCM

[tex]P(x) - Q(x) = \frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}[/tex]

Open brackets

[tex]P(x) - Q(x) = \frac{-6x + 4 - 18x +6}{(3x - 1)(-3x + 2)}[/tex]

Collect like terms

[tex]P(x) - Q(x) = \frac{-18x-6x + 4 + 6}{(3x - 1)(-3x + 2)}[/tex]

[tex]P(x) - Q(x) = \frac{-24x +10}{(3x - 1)(-3x + 2)}[/tex]

Factor out -2

[tex]P(x) - Q(x) = \frac{-2(12x -5)}{(3x - 1)(-3x + 2)}[/tex]

Hence, the value of P(x) - Q(x) is [tex]\frac{-2(12x -5)}{(3x - 1)(-3x + 2)}[/tex]

P(x) * Q(x) is calculated as follows:

[tex]P(x) \times Q(x) = \frac{2}{3x - 1} \times \frac{6}{-3x + 2}[/tex]

Multiply

[tex]P(x) \times Q(x) = \frac{12}{(3x - 1)(-3x + 2)}[/tex]

Hence, the value of P(x) * Q(x) is [tex]\frac{12}{(3x - 1)(-3x + 2)}[/tex]

Read more about composite functions at:

https://brainly.com/question/10687170

Answer:

(67/10)x + 9 (answer [2])

Step-by-step explanation:

3(7/5x + 4) - 2(3/2 - 5/4x). after the indicated multiplication has been carried out, is:

(21/5)x + 12 - 3 + (5/2)x

Combining like terms, we get (4.2 + 2.5)x + 9, or

6.7x + 9, or (67/10)x + 9 (answer [2])

Answer:

301.44

Step-by-step explanation:

V=π r² h

V=π (4)² (12)

V= 603.19

divide by 2 to find half full: ≈ 301

301.44

Answer:

Step-by-step explanation:

First, note this parameters from the question.

We let x = number of $5 increases and number of 10 decreases in plates sold.

Our Revenue equation is:

R(x) = (300-10x)(10+5x)

We expand the above equation into a quadratic equation by multiplying each bracket:

R(x) = 3000 + 1500x - 3000x - 1500x^2

R(x) = -1500x^2 - 1500x + 3000 (collect like terms)

Next we simplify, by dividing through by -1500

= 1500x^2/1500 - 1500x/1500 + 3000/1500

= X^2 - x + 2

X^2 - x + 2 = 0

Next, we find the axis of symmetry using the formula x = -b/(2*a) where b = 1, a = 1

X = - (-1)/2*1

X = 1/2

Number of $5 increases = $5x1/2 = $2.5

=$2.5 + $20 = $22.5 ticket price gives max revenue.

Answer:

x4+7x+3

Step-by-step explanation:

Answer:

x=(2+ √-32)/2 or x=(2- √-32)/2

Step-by-step explanation:

x^2 - 2x = -9

x^2 - 2x + 9 =0

x = 2± (√(-2)^2 - 4*1*9)/2*1

Use the quadratic formula in the expression using a=1, b= -2, c=9

x = 2±√4-36 /2

x = 2+√4-36 or x = 2 - √4 - 32 /2

x = (2+√-32) /2 or x=( 2 - √-32 )/2

The solution for the given quadratic equation are (2+i5.7)/2 or (2-i5.7)/2.

The given quadratic equation is x²-2x=-9.

Quadratic formula is the simplest way to find the roots of a quadratic equation.

The roots of a quadratic equation ax² + bx + c = 0 are given by x = [-b ± √(b² - 4ac)]/2a.

By comparing x²-2x+9=0 with ax² + bx + c = 0, we get a=1, b=-2 and c=9

Substitute a=1, b=-2 and c=9 in the quadratic formula, we get

x = [2±√(-2)²-4×1×9)]/2×1

= [2±√4-36]/2

= (2±i5.7)/2

x = (2+i5.7)/2 or (2-i5.7)/2

Therefore, the solution for the given quadratic equation are (2+i5.7)/2 or (2-i5.7)/2.

To learn more about the quadratic formula visit:

https://brainly.com/question/11540485.

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Answer:

Dot paper helps to understand and bring in the big picture in perspective drawing.

Step-by-step explanation:

Dot paper helps to understand patterns and features of the big picture. It helps to understand patterns at various intervals. Drawing with perspective helps to understand the big idea. Perspective reveals your point of view and helps gravitate your idea of the spatial onto paper. You can express linear perspectives.

You can use your principles of perspective drawing to create a perception of your world and your world view through your art.

Answer:

a

  The null hypothesis is  

         [tex]H_o : \mu = 21[/tex]

The Alternative  hypothesis is  

           [tex]H_a : \mu< 21[/tex]

b

     [tex]\sigma_{\= x} = 0.8944[/tex]

c

   [tex]t = -2.236[/tex]

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        [tex]\= x = \frac{20 + 18 + 17 + 22 + 18}{5}[/tex]

       [tex]\= x = 19[/tex]

The standard deviation is evaluated as

        [tex]\sigma = \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }[/tex]

         [tex]\sigma = \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }[/tex]

         [tex]\sigma = 2[/tex]

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         [tex]\alpha = 100 - 90[/tex]

        [tex]\alpha = 10[/tex]%

         [tex]\alpha =0.10[/tex]

Now the null hypothesis is  

         [tex]H_o : \mu = 21[/tex]

the Alternative  hypothesis is  

           [tex]H_a : \mu< 21[/tex]

The  standard error of mean is mathematically evaluated as

         [tex]\sigma_{\= x} = \frac{\sigma}{ \sqrt{n} }[/tex]

substituting values

         [tex]\sigma_{\= x} = \frac{2}{ \sqrt{5 } }[/tex]

        [tex]\sigma_{\= x} = 0.8944[/tex]

The test statistic is  evaluated as  

              [tex]t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }[/tex]

substituting values

              [tex]t = \frac{ 19 - 21 }{ 0.8944 }[/tex]

              [tex]t = -2.236[/tex]

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   [tex]z_{0.10} = 1.28[/tex]

Looking at the obtained value we see that [tex]z_{0.10}[/tex] is greater than the test statistics value so the null hypothesis is rejected

Answer:

25 magazines for $70. (For why, read explanation)

Step-by-step explanation:

We can find the unit price of each of these deals by dividing the cost and the quantity.

[tex]\frac{45}{15}[/tex] = 3, so the first deal is $3 per magazine.

[tex]\frac{70}{25}[/tex] = 2.8, so the second deal is $2.80 per magazine.

Therefore, 25 magazines for $70 is a better deal.

Hope this helped!

Answer:

outside the circle i think

Step-by-step explanation:

Answer:

inside the circle

Step-by-step explanation:

Answer:

c = 11.3 mi/h

Step-by-step explanation:

Since Square has all of the same sides, hence bobs speed will be the same for all of the sides.

All of the sides are equal in a square

=> Let's consider the two sides along with the diagonal a right angled triangle

=> [tex]c^2 = a^2 + b^2[/tex]

Where c is the speed of Rob along the diagonal and b and c is the speed of Bob along the side

=> [tex]c^2 = 8^2+8^2[/tex]

=> [tex]c^2 = 64+64[/tex]

=> [tex]c^2 = 128\\[/tex]

Taking sq root on both sides

=> c = 11.3 mi/h