What’s the perimeter and surface area of this shape?
Please also show working out.
Answers
Answer: Perimeter = 8π ≈ 25.12
Area = 12π ≈ 37.68
Step-by-step explanation:
This is a composite of two figures.
The bigger figure is a quarter-circle with radius (r) = 8 cm
The smaller figure is a quarter-circle with diameter = 8 cm --> r = 4
Perimeter of a quarter-circle = [tex]\dfrac{1}{4}(2\pi r)[/tex] = [tex]\dfrac{\pi r}{2}[/tex]
Perimeter of composite figure = bigger - smaller figure
[tex]P_{bigger}=2\pi(8)\quad = 16\pi\\P_{smaller}=2\pi(4)\quad =8\pi\\P_{composite}=16\pi-8\pi \\.\qquad \qquad = \large\boxed{8\pi}[/tex]
Area of a quarter-circle = [tex]\dfrac{1}{4}\pi r^2[/tex]
[tex]A_{bigger}=\dfrac{1}{4}\pi (8)^2\quad =16\pi\\\\A_{smaller}=\dfrac{1}{4}\pi (4)^2\quad =4\pi\\\\A_{composite}=16\pi-4\pi\\.\qquad \qquad = \large\boxed{12\pi}[/tex]
Related Questions
please help I will give brainiest I need your help!!!!
Answers
Answer:
Step-by-step explanation:
∠OAB is 90 degrees, tangent and a radius met at 90 degree angle
∠OCB=90 degrees, tan and radius meet at 90 degrees angle
OB=12
find angle BOC:
triangle BOA is right angle triangle:
cos(AOB)=adj/hyp=7/12=54.33
angle B= 180-(90+54.33)=35.67
angle COB=54.33 equal to angle AOB
angle AOC=54.33+54.33=108.66
the sum of angles of circle =360
360-108.66= 251.34( exterior angle at the center AOC)
length of the arc= angle (251.34 degrees*7)
convert degrees to radians=4.386 (251.34/π)
length=r*angle in radian=4.386*7=30.71
( i hope this is the answer)
A car travels 120m along a straight road that is inclined at 8° to the horizontal. Calculate the vertical distance through which the car rises. (Sin 8°= 0.1392)
Answers
Answer:
16.704m
Step-by-step explanation:
To solve the above question, we are going to use the Trigonometric function of Sine.
sin θ = Opposite side/Hypotenuse
Where are given θ = 8°
Sin 8° = 0.1392
In the question, we are told that ,
A car travels 120m along a straight road that is inclined at 8° to the horizontal, hence,
Hypotenuse = 120m
We are asked to calculate the vertical distance through which the car rises hence,
Opposite side = vertical distance.
Therefore,
Sin 8° = Opposite/ 120m
Opposite = Sin 8° × 120m
Opposite = 0.1392 × 120m
Opposite = 16.704m
Therefore, the vertical distance through which the car rises is 16.704m
Austin walks 2/3 of the way to school and stopped to rest. Devyn walks 4/6 of the way to school and stops for a rest. Where are they in their route to school? Who has traveled further?
Answers
Answer:
both are at the same distance
Step-by-step explanation:
Answer:
Austin and Devyn both have 1/3 of the way left on their way to school. They both also have walked the same amount.
Step-by-step explanation:
If Austin has to walk to his school, which could be said as 3/3 and Austin has already walked 2/3. Then if we conduct the equation 3/3-2/3=x. x=1/3. Now Devyn has already walked 4/6 of the way to school. If she has to walk a total of 6/6, then we can again make an equation 6/6-4/6=2/6. Now if we take the distance that they both have left to their school, its 1/3 and 2/6. These are both equavalent fractions because if you scale up 1/3, it equals to 2/6. Since they both have an equal amount of distance to travel, that must mean that they both have covered the same amount of distance already. We can double check to be sure. 2/3 *2/2=4/6. The reason we used 2/2 is because4/2=2 and 6/3=2.
(i) The third and the seventh terms of an A.P. are 20 and 36 respectively. Find the first
term and the common difference,
Answers
Answer:
The first term is 12. The common difference is 4.
Step-by-step explanation:
[tex] a_n = a_1 + d(n - 1) [/tex]
The difference between the third and seventh terms is
36 - 20 = 16
The 7th term is the 4th term after the 3rd term, so the common difference is
16/4 = 4
[tex] a_3 = a_1 + 4(3 - 1) [/tex]
[tex] 20 = a_1 + 4(3 - 1) [/tex]
[tex] 20 = a_1 + 8 [/tex]
[tex] a_1 = 12 [/tex]
Answer: The first term is 12. The common difference is 4.
Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form? Y = 3 (x minus seven-halves) squared minus StartFraction 27 Over 4 EndFraction y = 2 (x minus 1) squared minus 11 y = 2 (x minus one-half) squared minus StartFraction 53 Over 4 EndFraction y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction
Answers
Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction
or
[tex]y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]
Step-by-step explanation:
Vertex form of equation : [tex]f (x) = a(x - h)^2 + k,[/tex]where (h, k) is the vertex of the parabola.
[tex]y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]
Hence, the vertex form of the equation is [tex]y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}[/tex]
Answer:
i got y=2(x-1/2)^2- 27/2 so the last one is right
Step-by-step explanation:
:)
What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12? (–∞, –3] [–3, ∞) (–∞, 15] [15, ∞) SORRY THIS IS THE FULL QUESTION
Answers
Answer:
[15, ∞).
Step-by-step explanation:
–3(6 – 2x) ≥ 4x + 12
-18 + 6x ≥ 4x + 12
6x - 4x ≥ 12 + 18
2x ≥ 30
x ≥ 15
This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).
Hope this helps!
01:14:29 The Schwartz family spent a total of $111.75 for Internet service for 3 months. Each month they received $5.50 as a credit on the bill. Which equation and solution shows the cost of their monthly Internet service before the credit? 3 (x + 5.50) = 111.75; the monthly Internet service is $31.75 3 (x minus 5.50) = 111.75; the monthly Internet service is $42.75 One-third (x minus 5.50) = 111.75; the monthly Internet service is $42.75 One-third (x + 5.50) = 111.75; the monthly Internet service is $31.75
Answers
Answer: 3(x minus 5.50) = 111.75; the monthly Internet service is $42.75
Step-by-step explanation:
Given the following :
Total amount spent on internet for 3 months = $111.75
Monthly credit received on bill = $5.50
Monthly Credit of $5.50 means $5.50 is deducted from the amount being paid on thir bill monthly.
Assume their monthly internet service fee = x
The amount paid before the credit deduction each month:
Amount paid - credit
(x - $5.50)
For 3 months :
3 × (x - $5.50) = $117.75
3(x - $5.50) = $117.75
Monthly fee paid before credit deduction:
3(x - $5.50) = $117.75
3x - $16.50 = $117.75
3x = $117.75 + $16.50
3x = $128.25
x = $128.25 / 3
x = $42.75
Answer:
It's b !! :o]
Step-by-step explanation:
Complete the inequality with >, <,>,<,is greater than, comma, is less than, comma or ==equals. 2^52 5 2, start superscript, 5, end superscript 5^25 2 5, squared
Answers
Answer:
[tex]2^5 > 5^2[/tex]
Step-by-step explanation:
Given the expression [tex]2^5 \ 5^2[/tex], we are to complete the inequality by inserting the correct inequality signs in between the values.
Before we do that, we must know the value of each indicinal expressions.
[tex]2^5 = 2*2*2*2*2\\\\2^5 = 4*4*2\\\\2^5 = 16*2\\\\2^5 = 32[/tex]
Also,
[tex]5^{2} = 5*5\\\\5^2 = 25[/tex]
From the values gotten, we can clearly see that 32 is greater than 25. This means that 2⁵ is greater than 5². Hence the inequality sign that will complete the expression is a greater than sign (>).
The inequality will be [tex]2^5 > 5^2[/tex]
Answer:
its this
over here...
Find the intercepts and graph the following linear equations: 2y − 6 = 0
Answers
The y-intercept is [tex](0,\frac{6}{2})=(0,3)[/tex] and there is no x-intercept since the equality can simplified to the point of obtaining a constant function [tex]y=3[/tex] which does not depend on x.
Hope this helps.
Find the value of x in the triangle
shown below.
X
85
67
Answers
Answer:
x = 28 degrees. 180 degrees in a triangle, 180-85-67=28
Answer:
28 degrees
Step-by-step explanation:
The interior angles of a triangle add up to 180 degrees.
The three angles given are: x, 85, and 67.
Therefore, these three angles must add to 180.
x+85+67=180
Combine like terms on the left. Add 85 and 67.
x+ (85+67)=180
x+152=180
We want to find x. We need to get x by itself. 152 is being added to x. The inverse of addition is subtraction. Subtract 152 from both sides.
x+152-152=180-152
x=180-152
x=28
x is 28 degrees.
Are the terms CSC, SEC, and COT equivalent to the terms Sin^-1, Cos^-1, and Tan^-1? Are the three pairs of terms the same thing just written differently, or are they entirely different?
Answers
Answer:
Step-by-step explanation:
It depends on how it is written. By definition
[tex]\csc(x) = (\sin(x))^{-1} = \frac{1}{\sin(x)}[/tex]
[tex]\sec(x) = (\cos(x))^{-1} = \frac{1}{\cos(x)}[/tex]
[tex]\cot(x) = (\tan(x))^{-1} = \frac{1}{\tan(x)}[/tex]
however the functions
[tex]\sin^{-1}(x), \cos^{-1}(x), \tan^{-1}(x)[/tex] are the inverse functions of sine, cosine and tangent respectively. So, they are not equivalent functions
Alonso went to the market with $55 to buy eggs and sugar. He knows he needs a package of 12 eggs that costs $2.75. After getting the eggs, he wants to buy as much sugar as he can with his remaining money. The sugar he likes comes in boxes that each cost $11.50 Write an inequality. Also, after getting the eggs, how many boxes of sugar can Alonso afford? Thanks.
Answers
Answer:
1) The inequality is $55 ≥ $11.50 × S + $2.75
2) Alonso can afford 4 boxes of sugar
Step-by-step explanation:
The given information are;
The total amount with Alonso = $55
The amount of eggs Alonso needs = 12 eggs
The costs of the pack of 12 eggs = $2.75
The number of packs of eggs Alonso buys = 1
The cost of each box of sugar = $11.50
Let the number of boxes of sugar Alonso buys = S
Given that the total amount of money with Alonso is $55, then the inequality will be such that $55 will be equal to or larger than the expression for items bought
Therefore, the inequality is given as follows;
$55 ≥ $11.50 × S + $2.75
2) To find out how many boxes of sugar Alonso can afford, we have;
$55 ≥ $11.50 × S + $2.75
$55 - $2.75≥ $11.50 × S
$52.25 ≥ $11.50 × S
∴ S ≤ $52.25/$11.50 = 4.54
S ≤ 4.54 boxes of sugar
As the sugar comes in whole boxes, Alonso can therefore afford only 4 whole boxes of sugar.
Alonso can afford to buy 4 boxes of sugar.
An inequality to represent how many boxes of sugar can Alonso afford is 55 ≥ 2.75 + 11.50s
Given:
Amount with Alonso = $55
Package of 12 eggs = $2.75
Cost of each box of sugar = $11.50
let
s = number of boxes of sugar Alonso can afford
The inequality:
55 ≥ 2.75 + 11.50s
solve for s
55 - 2.75 ≥ 11.50s
52.25 ≥ 11.50s
divide both sides by 11.50
52.25 / 11.50 ≥ s
4.5434782608695 ≥ s
Alonso can only buy a whole box of sugar
Therefore, the number of boxes of sugar Alonso can afford is 4 boxes
Read more:
https://brainly.com/question/11067755
Simplify this problem. |3r−15| if r<5
Answers
Answer:
We have the problem:
|3r−15| if r<5
First we see the equality, if r = 5 we have:
I3r - 15I = I3*5 - 15I = I0I = 0.
Then the only restriction that we have is:
I3r - 15I > 0.
now, we could simplify it a bit further:
if r < 5, then the thing inside the absolute value will always be negative:
Then we can write:
I3*r - 15I = -(3*r -15) > 0
multiplying by -1 in both sides
(3r - 15) < 0.
if we keep simplifying this, we will get our initial restriction:
3r - 15 < 0
3r < 15
r < 15/3 = 5
r < 5
I would REALLY appreciate if you could help me with this question. I am REALLY stuck...
Answers
Answer: D) Construct the perpendicular bisectors for AB and AC.
The intersection of all three perpendicular bisectors will form the circumcenter, which is the center of the circumcircle. This circle goes through all three corner points of the triangle. At minimum, you only need two perpendicular bisectors to get the job done. Choice B is close, but is missing that second perpendicular bisector.
The angle bisectors intersect to form the incenter, which is the center of the incircle (it's the largest possible circle to fit inside the triangle without spilling over).
Answer:
D. Construct the perpendicular of ab and ac
Step-by-step explanation:
Circumscribe a Circle on a Triangle
Construct the perpendicular bisector of one side of the triangle.
Construct the perpendicular bisector of another side.
Where they cross is the center of the Circumscribed circle.
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle
Mark me as brainliest
Any help with this please???? Running out of time!
Answers
Answer:
Sin A = 21/29Step-by-step explanation:
[tex]Using\: A \: as\: a\: refernce\: angle ;\\Hypotenuse = 29\\Opposite =21\\Adjacent = 20\\\\Using \: SOHCAHTOA\\Sin A = \frac{Opposite}{Hypotenuse} \\\\Sin A = \frac{21}{29}[/tex]
Which choice shows the coordinates of B' if the trapezoid is reflected across the x-axis? On a coordinate plane, trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1). (–7, 2) (2, –7) (7, –2) (–2, 7)
Answers
Answer:
(7, -2)
Step-by-step explanation:
The trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1).
Transformation of a point is the change in location from an original position to a new position. If a shape is transformed, all its points are also transformed. A transformation can either be a rotation, translation, reflection or dilation.
If a point O(x,y) is reflected across the y axis, the new coordinate of the point is at O'(x, -y), i.e. the x coordinate does not change, but the y coordinate is negated.
Since in trapezoid ABCD, the coordinate of point B is (7, 2). The trapezoid is reflected across the x-axis, therefore the new coordinate of B' is at (7, -2)
Answer:c
Step-by-step explanation:
I took the test
Please answer it now in two minutes
Answers
Answer:
∠ I ≈ 60.3°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan I = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{HG}{GI}[/tex] = [tex]\frac{7}{4}[/tex] , thus
∠ I = [tex]tan^{-1}[/tex] ([tex]\frac{7}{4}[/tex] ) ≈ 60.3° ( to the nearest tenth )
the answer is 10 by root 65 so the answer is 10
In a newspaper, it was reported that yearly robberies in Springfield were down 10% to 90 in 2014 from 2013. How many robberies were there in Springfield in 2013?
Answers
Answer:
100.
Step-by-step explanation:
Let the number of robberies be x ( in 2013).
Then x - 0.10x = 90
0.90x = 90
x = 90 / 0.90
= 100.
find tan(a) in the triangle
Answers
Answer:
tan (a) = 24/7Step-by-step explanation:
tan∅ = opposite / adjacent
From the question
AC is the adjacent
BC is the opposite
So we have
tan (a) = BC / AC
tan (a) = 24/7
Hope this helps you
A lake has a small patch of lily pads and every day the patch grows to double its size. It takes 32 days for the patch to cover the lake – how long would it take the patch to cover half the lake?
Answers
Answer:
It took 31 days for the patch to cover half the lake
Step-by-step explanation:
The patch grows to double its size everyday
the patch completely covers the lake in 32 days
Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.
Therefore, the the patch covered half the lake on the 31st day, i.e it took 31 days for the patch to cover half the lake
I'm marking answers as brainliest. The solution to the following system is ________. -9x + 6y = -30, -7x + 12y = -16 * I I (0,2) (4,1) (-4,7) (2,1)
Answers
Answer:
Step-by-step explanation:
-9x + 6y = -30
-7x + 12y = -16
18x - 12y = 60
-7x + 12y = -16
11x = 44
x = 4
-36 + 6y = -30
6y = 6
y = 1
(4,1)
Answer:
(4,1)
Step-by-step explanation:
-9x + 6y = -30.............(1)
-7x + 12y = -16 ............(2)
(2) - 2(1)
-7x+12y - 2(-9x+6y) = -16 - 2(-30)
simplify
11x = 44
or
x = 4 .......................(3a)
substitute (3) in (1)
-9(4) + 6y = -30
6y = -30 + 36
6y = 6
y = 1 ......................(3b)
Using results from (3a) and (3b), we have
solution : (4,1)
A polynomial has a leading coefficient of 1 and the
following factors with multiplicity1:
x-(2 + i)
X - V2
What is the factored form of the polynomial?
Answers
Answer:
(A)[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]
Step-by-step explanation:
A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:
[tex]x-(2+i)\\x-\sqrt{2}[/tex]
We apply the following to find the factored form of the polynomial.
If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.If the polynomial has an irrational root [tex]a+\sqrt{b}[/tex], where a and b are rational and b is not a perfect square, then it has also a conjugate root [tex]a-\sqrt{b}[/tex].[tex]\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}[/tex]
Therefore, the factored form of the polynomial is:
[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]
Answer:
A
Step-by-step explanation:
EDGE 2021
Find the area of the shape shown below.
Answers
Answer:
12 is the total areaStep-by-step explanation:
A of triangle = 1/2 * b * h
b = 6
h = 2
2 * 6 * 0.5
= 12 * 0.5
= 6A of square = l * w
2 * 2
= 4A of Triangle = 1/2 * b * h
2 * 2 * 0.5 =
4 * 0.5
= 22 + 4 + 6
= 6 + 6
= 12Show how you can determine that the inscribed figure inside a quadrilateral is a parallelogram. Support your argument with diagrams.
Answers
Answer:
See diagram
Step-by-step explanation:
A quadrilateral becomes a parallelogram when the diagonals bisects each other at a point E and hence proves the quadrilateral is a parallelogram. It shows both pairs of opposite sides being parallel to each other.
Following the theorem that states that, if two sides of a quadrilateral are opposite and congruent, then it is a parallelogram. Ditto for the theorem that states that, that when diagonals cuts each other at a point in a quadrilateral, then its a parallelogram.
The city park department is planning to enclose a play area with fencing. One side of the area will be against an existing building, so no fence is needed there. Find the dimensions of the maximum rectangular area that can be enclosed with 800 meters of fence. Include the units.
Answers
Answer:
The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.
Step-by-step explanation:
From the given information;
The perimeter of a rectangle = 2 (L+B)
here;
L = the length of the side of the fence
B = the width of the fence
So; The perimeter of a rectangle = 2L+2B
we are also being told that;
One side of the area will be against an existing building
i.e
The perimeter of a rectangle is now = L + 2B = 800 meters
L = 800 - 2B
Similarly; Area of a rectangle = L × B
Area of a rectangle = ( 800 - 2B) × B
Area of a rectangle = 800B - 2B²
assuming A(B) to represent the Area;
Then the maximum area A'(B) = 0 ;
Thus,
A'(B) = 800 - 4B = 0
-4B = - 800
4B = 800
B = 200
Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) = 800 - 400 = 400 meters
PLEASE help me with this question! I really need help...
Answers
Answer:
The third: [tex]\bold{\dfrac{x+5}{x+15}}[/tex]Step-by-step explanation:
[tex]x^2+19x+70\ \implies a=1\,,\ b=19\,,\ c=70\\\\x=\frac{-19\pm\sqrt{19^2-4\cdot1\cdot70}}{2\cdot1}=\frac{-19\pm\sqrt{361-280}}{2}=\frac{-19\pm9}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-5\\\\x^2+19x+70=(x+14)(x+5)\\\\\\x^2-225=x^2-(15)^2=(x-15)(x+15)\\\\\\x^2-5x-150\ \implies a=1\,,\ b=-5\,,\ c=-150\\\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-150)}}{2\cdot1}=\frac{5\pm\sqrt{25+600}}{2}=\frac{5\pm25}{2}\ \Rightarrow\ x_1=-10\,,\ x_2=15\\\\x^2-5x-150=(x+10)(x-15)[/tex]
[tex]x^2+24x+140\ \implies a=1\,,\ b=24\,,\ c=140\\\\x=\frac{-24\pm\sqrt{24^2-4\cdot1\cdot140}}{2\cdot1}=\frac{-24\pm\sqrt{576-560}}{2}=\frac{-24\pm4}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-10\\\\x^2-5x-150=(x+14)(x+10)[/tex]
[tex]\dfrac{x^2+19x+70}{x^2-225}\,\cdot\,\dfrac{x^2-5x-150}{x^2+24x+140}=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{(x+10)(x-15)}{(x+14)(x+10)}=\\\\\\=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{x-15}{x+14}=\dfrac{x+5}{x+15}\cdot\dfrac11=\boxed{\dfrac{x+5}{x+15}}[/tex]
Answer:
The answer is option 3.
Step-by-step explanation:
First, you have to factorize the expressions :
[tex] \frac{ {x}^{2} + 19x + 70 }{ {x}^{2} - 225 } \times \frac{ {x}^{2} - 5x - 150}{ {x}^{2}24x + 140 } [/tex]
[tex] = \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]
Next, you have to cut out the common terms like (x + 14), (x - 15) and (x + 10):
[tex] \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]
[tex] = \frac{x + 5}{x + 15} [/tex]
I need help on this one question ASAP
Answers
Answer:
choose the last option .
you could check my answer using desmos graph (search on Google)
Angle G is a circumscribed angle of circle E. Circle E is shown. Line segments F E and D E are radii. A line is drawn to connect points F and D. Tangents F G and D G intersect at point G outside of the circle. Angles E B D and F D E have measures of x degrees. What is the measure of angle G, in terms of x? x° + x° x° + 90° 180° – x° 180° – 2x°
Answers
Answer:
X+X
Step-by-step explanation:
did it on edg
Answer:
x° + x°
Step-by-step explanation:
Edge 2020
HELP please!!!
Jeanie wants a $100 000 mortgage. She arranged payments for the next 15 years. The bank charges 4.8%/a interest, compounded monthly.
a) how much is each monthly payment
b) how much interest is jeanie paying?
Answers
Answer:
in one month : 13676.57/12=1139.71
the interest on 100000 is: 205148.48-100000=105148.48
Step-by-step explanation:
A=P(1+r)^t (p is the mortgage, t is the time and r is the rate)
p=100000,t=15*12 month,r=4.8%( or 0.048)
A=100000(1+0.048/12)^(12*15)
A=205148.48 (the number rounded to the nearest hundredth)
205128.48 is the amount she has to pay it after 15 years
in one year : 205128.48/15=13676.57 ( rounded to nearest hundredth)
in one month : 13676.57/12=1139.71
the interest on 100000 is: 205148.48-100000=105148.48
what is the domain of the function represented by the graph.?
Answers
Answer:
all real numbers
Step-by-step explanation:
There is nothing on the graph to indicate the function is undefined for any values of x. The domain is all real numbers.
Answer:
Domain is all real numbers.
Step-by-step explanation:
The domain of a quadratic function in standard form is always all real numbers, meaning you can substitute any real number for x.