Step-by-step explanation:
27=9x+2-4x
or, 27-2=9x-4x
or,25=5x
or,25/5=X
so, X=5
Let A={1,2,3,4,5,6,7,8}A={1,2,3,4,5,6,7,8}. Define a relation ∼∼ on AA by a∼ba∼b if and only if 33 divides a−ba−b for all a,b∈Aa,b∈A. 1. Find all the pairs (a,b)∈A×A(a,b)∈A×A such that a∼ba∼b. 2. Show that ∼∼ is an equivalence relation on AA. 3. Find the equivalence classes [2][2] and [3][3].
Define relation.
Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.
What is the range of exponential function g?
The range of the exponential function is: B. [tex]g(x)>-6[/tex]
Recall:
Range of any function includes all possible values of y (output)
Domain of any function includes all possible values of x (input).
Thus:
The values of y in the exponential function greater than -6 on the y-axis as shown in the graph given.
Therefore:
Range of the exponential function given in the graph is: B. [tex]g(x)>-6[/tex].
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Solve M = 5rt^2- 2rv for v.
Can someone please help with this I’ll put it to 100 points
Answer:
(M-5rt^2)/(-2r) =v
Step-by-step explanation:
M = 5rt^2- 2rv
Subtract 5rt^2 from each side
M-5rt^2 = 5rt^2- 2rv -5rt^2
M-5rt^2 = - 2rv
Divide each side by -2r
(M-5rt^2)/(-2r) =- 2rv / (-2r)
(M-5rt^2)/(-2r) =v
Answer:
[tex]v = -\frac{M-5rt^2}{2r}[/tex]
Step-by-step explanation:
[tex]M = 5rt^2 - 2rv[/tex]
Switch sides
[tex]5rt^2-2rv=M[/tex]
Subtract [tex]5rt^2[/tex] from both sides
[tex]5rt^2 - 2rv-5rt^2= M -5rt^2[/tex]
Simplify
[tex]-2rv = M - 5rt^2[/tex]
Divide both sides by [tex]-2r[/tex]
[tex]\frac{-2rv}{-2r} =\frac{M}{-2r} -\frac{5rt^2}{-2r}[/tex]
Simplify
[tex]-\frac{M-5rt^2}{2r}[/tex]
A product is introduced into the market. Suppose a products sales quantity per month q(t) is a function of time t in months is given by q(t) = 5000t-120t^2. And suppose the price in dollars of that product. p(t). is also a function of time t in months and is given by p(t) = 120-t^2.
Required:
a. Find, R'(t). the rate of change of revenue as a function of time t
b. What is the the rate of change of revenue with respect to time 3 months after the introduction?
Answer:
Part A)
[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]
Part B)
After three months, the revenue is increasing at a rate of $391,560 per month.
Step-by-step explanation:
A product is introduced into the market. The quantity per month q sold is given by the function:
[tex]q(t) = 5000t - 120t^2[/tex]
And the price p (in dollars) of the product is given by the function:
[tex]p(t) = 120-t^2[/tex]
Part A)
R(t), or the revenue, will be the product of the quantity sold and its respective price during the month. Hence:
[tex]\displaystyle R(t) = q(t)\cdot p(t)[/tex]
Substitute:
[tex]\displaystyle R(t) = \left(5000t-120t^2\right)\left(120-t^2\right)[/tex]
To find R'(t), take the derivative of both sides with respect to t:
[tex]\displaystyle R'(t) = \frac{d}{dt}\left[ \left(5000t-120t^2\right)\left(120-t^2\right)\right][/tex]
Since the function is a product of two expressions, we can consider using the Product Rule:
[tex]\displaystyle \frac{d}{dx} \left[uv\right] = u'v+uv'[/tex]
Hence:
[tex]\displaystyle R'(t) = \frac{d}{dt}\left[5000t-120t^2\right]\left(120-t^2\right) + \left(5000t-120t^2\right)\frac{d}{dt}\left[120-t^2\right][/tex]
Differentiate. Therefore:
[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]
(We may simplify if we desire, but this is not required by the problem.)
Part B)
To find the rate of change of revenue with respect to time three months after the introduction, we can evaluate R'(t) at t = 3. Hence:
[tex]\displaystyle R'(3) = (5000-240(3))(120-(3)^2)+(5000(3)-120(3)^2)(-2(3))[/tex]
Evaluate:
[tex]R'(3) = 391560\text{ dollars/month}[/tex]
In conclusion, after three months, the revenue is increasing at a rate of $391,560 per month.
(Note: it is increasing because the final value is positive.)
Answers and step by step explanations please?(Just one example)
HELP!! TRUTH TABLE
I would really appreciate it, if someone could walk me through how they did it! Thanks.
p ∧ q (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.
Similarly, (p ∧ q) ∧ r is true only if both p ∧ q and r are true. We know when p ∧ q is true, so (p ∧ q) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.
All other cases are false.
The table should look like this:
[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]
Write the number in expanded form 99,763
Answer:
90,000+9,000+700+60+3
Answer:
90,000 + 9,000 + 700 + 60 + 3 I hope this helped
Please help me with this Geometry problem
Mackenzie purchased a ticket to the local music festival for $25. The ticket
includes entry and access to up to 3 events at the festival. Each additional
event costs $6. The total cost for attending x events is given by the
functions T(x) and E(x).
T(x) = 6(x-3) + 25, where x>3
E(X) = 25, where 0 sxs3
After a small search, I've found that we want to find the inverses of both functions. We will find that E(x) does not have an inverse function, and the inverse function of T(x) is h(x) = x/6 - 1/6
Here we have a piecewise function:
T(x) = 6(x-3) + 25 if x > 3
E(x) = 25 if 0 ≤ x ≤ 3
First, remember that two functions f(x) and g(x) are inverses if:
f(g(x)) = x
g(f(x)) = x
From that definition we can see that E(x) does not have an inverse, because for any function g(x), we will have:
E(g(x)) = 25
So E(x) can't meet the condition.
Now let's analyze the function T(x)
T(x) = 6(x-3) + 25
We can rewrite it as:
T(x) = 6x - 6×3 + 25
T(x) = 6x + 1
Note that T(x) is a linear equation, so the inverse will also be a linear equation. Let's assume that the inverse is h(x) = ax + b
We will have:
T(h(x)) = 6×h(x) + 1 = 6(ax + b) + 1
Now, if these are inverses, we have:
6(ax + b) + 1 = x
6ax + 6b + 1 = x
Then we must have:
6b + 1 = 0
6ax = x
From the first equation, we can get:
6b + 1 = 0
6b = -1
b = -1/6
From the second equation we have:
6ax = x
6a = 1
a = 1/6
Then:
h(x) = x/6 - 1/6
And this is the inverse function of T(x)
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I need help, NO LINKS
how to calculate bearing
Answer:
Step-by-step explanation:
You will have to interpret the question with the aid of a diagram and make out the relevant angles and either make use of cosine rule,sine rule etc....Your knowledge on angles should be sound
The perimeter of the square with side length y
Answer:
4y
Step-by-step explanation:
Answer:
perimeter=4y
Step-by-step explanation:
y+y+y+y=4y
..........
Translate and solve: Three-fourths of p is 18.
hi <3
just form a quick equation:
3/4p = 18
divide both sides by 3/4 to get your answer:
p = 24
hope this helps :)
graph the sequence 2, 4, 6, 8, 10
Answer:
going up in even numbers
Step-by-step explanation:
its like the two times table, and it goes up in even numbers
Answer:
any number you can take
Step-by-step explanation:
like 4'6'8''12
Find the LCM of 315,420,525 using prime factorisation method with slove it
[tex]\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}[/tex]
LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5
LCM = 6300
Hence, the LCM of 315 , 420 , 525 is 6300
Answer:
6300Step-by-step explanation:
Prime factors of given numbers:
315 = 3*3*5*7420 = 2*2*3*5*7525 = 3*5*5*7The LCM is:
LCM(315, 420, 525) = 2*2*3*3*5*5*7 = 6300What is the length of the ladder? It is 6 ft. from the house at the bottom and touches the wall 14 ft. up at the top. Simplify your answer
Answer:
15.2
[tex] {c }^{2} = {a}^{2} + {b}^{2} \: \\ {c}^{2} ={6}^{2} + {14}^{2} \\ {c}^{2} = 36 + 196 \\ {c}^{2} = 232 \\ \sqrt{c } = \sqrt{232} \\ c = 15.23154621[/tex]
help with this problem plz
Answer:
22
Step-by-step explanation:
All thats need to do in this problem is add both line lengths to find the length of FH.
8 + 14 = 22
Best of Luck!
Rewrite as a product of the GCF and another sum 36 + 48
Answer:
72+12
Step-by-step explanation:
Any mathematics genius around. To solve this question.. am giving the brainliest
Snell Co. performs and completes services for a client in May and bills the client $1,000. In June, the client makes a partial payment of $300 cash for the services. In July, the remaining $700 cash is paid. Determine the monthly revenue recorded in May, June, and July for this service
The financial statement performed by Snell Corporation shows how the revenue recognition provides financial statement users(i.e. the client that uses Snell Co. service in May, June, and July) with relevant information regarding the services associated with revenue from customer contracts.
In the given case, the Snell Co. service charge was hiked in May since the entire service income must be accounted for in May. The amount owed from a client is seen as a current asset on the balance sheet, and once the amount is received from a client, it is removed off from the current asset. Thus it is added to the zero dollars ($0) company's cash balance. In this case, the cash collected in June and July is not recorded as revenue.
We can conclude that the monthly revenue recorded from Snell Co. performance and services for the client in May, June, and July for this service is as follows:
Months Revenue
May $1000
June 0
July 0
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Revenue is only earned after the required obligation (goods delivered or service rendered) has been fulfilled. From the question, we noted that Snell Co. performs and completes services for a client in May hence the revenue was earned in May irrespective of when money was received for the service rendered.
As such revenue earned in;
May is $1,000
June is $0
July is $0
for the service rendered
4 2/3 - (1 4/5). PLEASE HELP MEEEEE
Answer: 2 13/ 15
Step-by-step explanation:
what is the distance between the points (7, 8) and (9, 10).
Choose the best description of the commutative property of addition,
O A. When zero is added to a number, the sum is that number.
OB. If two numbers are added in opposite orders, their sum is 0.
O C. The order in which numbers are added does not affect the sum.
D. Numbers should be added in order from smallest to largest.
9514 1404 393
Answer:
C. The order in which numbers are added does not affect the sum.
Step-by-step explanation:
In symbols, the commutative property of addition is ...
a +b = b +a
The order in which numbers are added does not affect the sum.
1) A spinner is divided into equal red, blue, green,
red, black, and yellow sections. What's the
probability of spinning green and then red.
Answer:
1/18
Step-by-step explanation:
Probability of spinning red=2/6=1/3
Probability of spinning green=1/6
probability of spinning green and then red=(1/6)*(1/3)=1/18
2. Which group of numbers is in size order?
A. 3.10 - 3.20 - 3.09 - 3.55
B. 3.09 - 3.10 - 3.2 - 3.5
C. 3.10 - 3.20 - 3.09 - 3.55
D. 3.1 - 3.55 - 3.2 - 3.09
Answer:
B. 3.09-3.10-3.2-3.5 is the answer
Simplify the expression. 8c2 x –3c7
Answer:
the solution is (-2^3 · 3C^9)Step-by-step explanation:
Step 1(8 • (c2)) • (0 - 3c7)Step 223c2 • -3c7Step 3c2 multiplied by c7 = c(2 + 7) = c93 kom 2.7 Eve carves a shape out of wood. What is the volume of the shap 3 cm 1 cm 2 cm 3 cm 4 cm
Answer:
50cm
Step-by-step explanation:
oh apdiya I just wanted to let you
On the first day of December, 34,789 people went to the mall. On the second day 63,587 people went to the mall. How many people went to the mall over the two days
Answer:
98376
Step-by-step explanation:
8 thousands + 4 thousands
What is the answer in standard form?
Answer:
12000
Step-by-step explanation:
8000+4000=12000
2. STEM A circuit board manufacturer rejects a 100-ohm resistor if its measured resistance is 0.15 ohm more than or less than 100 ohms. Resistors A and B are rejected. Resistor A's resistance differs from 100 ohms by 0.15 ohm. Resistor B's resistance differs from 100 ohms by -0.78 ohm. How do the resistances of these two resistors compare? Explain.
The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]
Given that:
[tex]R = 100 \Omega[/tex] ---- the reference resistor
First, we calculate the resistance of both resistors
Resistor A differs by [tex]0.15\Omega[/tex] means that:
[tex]R_A = 100\Omega + 0.15\Omega[/tex]
[tex]R_A = 100.15\Omega[/tex]
Resistor A has a resistance of [tex]100.15\Omega[/tex]
Resistor B differs by [tex]-0.78\Omega[/tex] means that:
[tex]R_B = 100\Omega -0.78\Omega[/tex]
[tex]R_B = 99.22\Omega[/tex]
Resistor B has a resistance of [tex]99.22\Omega[/tex]
By comparing the calculated values, we can conclude that:
Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]
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