Answer:
Table C:
Fan Speed Observations of Position vs. Time Graphs
Low:
The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.
Medium:
The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.
High:
The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.
Explanation:
hope it helps
Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.
Materials:
Smooth, inclined plane
Cart or tiny wheeled object
Stopwatches and timers
Measuring tape or meterstick
Procedure:
Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.
Place the cart or small wheeled object at the bottom of the inclined plane.
Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.
Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.
As soon as the cart is freed and begins to move, start the stopwatch or timer.
Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.
Determine the time intervals (Δt) between each position for velocity analysis
Data:
Position (m) Time (s) Time Interval (Δt) (s)
0.0 0.00 -
0.5 0.50 0.50
1.0 0.75 0.25
1.5 1.10 0.35
2.0 1.50 0.40
Analysis:
Calculate the average velocity between each position by dividing the position change by the time interval (x/t).
Create a graph that plots average velocity (V_avg) versus time (t).
Results:
A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.
Conclusion:
The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.
Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
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12. Suppose the polar bears were running on land instead of swimming. if the polar bear runs
at a speed of about 5.5m/s how far will it travel in 55 seconds?
the polar bear will travel 302.5m
A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the instant the ball is thrown. If the boy throws the ball upward at 50.0 ∘ above the horizontal, at 8.00 m/s .
How fast must the dog run to catch the ball just as it reaches the ground?
How far from the tree will the dog catch the ball?
12414253
Explanation:
A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introduction of 430 J of heat caused the system to expand, doing 238 J of work against a constant pressure of 101 kPa. What is the value of for this process
Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
What is an involuntary and a voluntary muscle action?
Answer:
Involuntary muscle action are muscles that move WITHOUT conscious control, and voluntary muscle action are muscles that move WITH conscious control.
Explanation:
A example of a involuntary muscle action would be your heart. Your heart is a muscle beats without you thinking about it and is very vital to your body. A example of a voluntary muscle would be the muscles that are attached to your bones and allow you to move your body, and it's voluntary because your body won't move on it's own.
Hope this helps.
I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What is defined by force per unit area?
1: gravity
2: force
3: temperature
4: pressure
Answer:
4. pressure is defined as force per unit area
Pressure is defined by force per unit area.
WHAT IS PRESSURE:Pressure refers to the force applied to a substance per unit area. Force is measured in Newtons (N) while area is measured in m², hence, the unit of pressure is N/m² also called pascal.Therefore, according to this question, it can be said that pressure is defined by force per unit area
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PLEASE ANSWER ASAP IM GONNA MARK AS BRAINLIEST
What is the value of the force measured by the spring balance?
I WILL MARK BRAINLIEST !! PLEASE HELP!
Answer:
b
Explanation:
Pls help thx need asap!!
Answer:
10N right
Explanation:
First, we need to find the base of the triangle to find the force acting on the right of the object.
We have been given the hypotenuse and we need to find the adjacent, so we are using cosSOH, CAH, TOAcos(θ) = adjacent ÷ hypotenuseNext, sub in the values (we don't know the adjacent so i've called it x):
cos(60) = x ÷ 60To find x, we need to multiply both sides by 60
60 × cos(60) = xx = 30 NNow we know all the forces, we can work out the net force:
Both of the 40N cancel out because they are opposite forcesThe force on the right of the object is 10N stronger than the force on the left (30N - 20N), so the object would move to the rightWhat happens to the size of an Object when it is heated ?
Answer:
the object melts so the size get smaller
HELP! I need some assistance
Answer:
I'm a Filipino hahahah I'm not
10. The SI unit of the solid angle is
a) Degree
b) Steradian
c) Revolution
d) Radian
The S.I unit of solid angle is steradian, or square radian (symbol: sr).
4. A gas's solubility is best in a liquid solvent when the solution is under high or low pressure
Answer:
low pressure
Explanation:
Light of 650 nm wavelength illuminates two slits that are 0.20 mm
apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?
PLEAsE URGENT. thank you
We have that for the Question "Light of 650 nm wavelength illuminates two slits that are 0.20 mm apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?" it can be said that the distance to the screen
d=1.168m
From the question we are told
Light of 650 nm wavelength illuminates two slits that are 0.20 mm
apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?
Generally the equation for the distance is mathematically given as
[tex]d=\frac{0.33*10^{-2}*0.23*10^{-3}}{650*10^{-9}}\\\\d=1.160m[/tex]
d=1.168m
Therefore
The distance to the screen
d=1.168m
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2. A 6.0 kg mass is pulled along a horizontal surface where the coefficient of friction is 0.20.
a) What is the friction force acting on the mass?
b) What force is needed to accelerate it at 0.68 m/s^(2)?
Answer:
Below
Explanation:
a) To find the force of friction acting on the mass we can use this formula :
friction = coefficientoffriction x normal force
First we need to find the normal force of this object :
Fn = mg
= (6.0)(9.8)
= 58.8 N
Now we can find the force of friction acting on the object :
friction = (0.20)(58.8N)
= 11.76 N
= 12 N (we round this to 2 sig figs)
b) To find the force needed to accelerate this object at 0.68 m/s^2 use this :
F = ma
0.68 = x - 11.76 / 6
x = 15.84
x = 16 N
Hope this helps! Best of luck <3
describe in the relationships between all four spheres hydrosphere,atmosphere,biosphere and geosphere support your response with examples
Answer:
The spheres interact with one another, and a change in one might result in a change in another. Humans (biosphere) plough the fields with agricultural machinery made of geosphere materials, while the atmosphere (hydrosphere) provides precipitation to water the plants. The biosphere is home to all living organisms on the earth.
Explanation:
don't ask qestionsmm
the hanging
mass would need to be
Answer:
what do you need help with I can try to help you
make a layout plan of your dream fishpond following parts?
Answer:
Do you have. a picture or full page for you're question its saying following parts
Suppose that scientists observe violent gas eruptions on a planet with an acceleration due to gravity of 3.8 m/s2. The jets throw sand and dust about 75 m above the surface.
What is the speed i of the material just as it leaves the surface?
Scientists estimate that the jets originate as high‑pressure gas speeds through vents just below ground at about 160 km/h. How much energy per kilogram of material does the jet lose to non conservative forces as the high‑speed matter forces its way to the surface and into the air?
Answer:
linarkuoouonpnpjjñihy
Explanation:
HELP
A 3000-kg truck moving with a velocity of 10 m/s hits a 1000-kg parked car. The impact causes the 1000-kg car to be set in motion at 15 m/s . Assuming that momentum is conserved during the collision, determine the velocity of the truck immediately after the collision.
Answer:
Hey I go to GOC send me your number
Explanation:
giúp em toàn bộ nhé ............
Explanation:
nnnnkgcbchg of bbjbjk oh jjzjjzkedkkdkfjjsjdsjfkjfdkkdowkronqfojofj see j FC
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
what is 4 differences between saturated unsaturated and supersaturated solutions
Answer:
Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible.
11. A plow pushes 100 kg of snow with 300 N of force. How much is the pile of snow
accelerated?
Answer:
Explanation:
This is an application of Newton's second Law.
Formula
F = m * a
F = 300 N
m = 100 kg
a = ?
F = m * a
300N = 100 kg * a Divide by 100
300N/100kg = a
a = 3 m/sec^2
A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85×108N/C is directed parallel to the wire, as shown in the figure. (Figure 1)
Part A
Find the tension in the wire.
Express your answer with the appropriate units.
Part B
What would the tension be if both charges were negative?
Express your answer with the appropriate units.
(a) The tension on the wire when the two charges have opposite signs is 383.5 N.
(b) The tension on the wire if both charges were negative is 3.640.25 N.
The given parameters;
first charge, q₁ = 8.75 μC second charge, q₂ = -6.5 μC electric field, E = 1.85 x 10⁸ N/Cdistance between the two charges, r = 2.5 cm(a)
The attractive force between the charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N[/tex]
The force on the negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the two forces and it is calculated as follows;
[tex]T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N[/tex]
(b) when the two charges are negative
The repulsive force between the two charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N[/tex]
The force on the first negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N[/tex]
The force on the second negative charge due to the electric field is calculated as follows;
[tex]F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the three forces and it is calculated as follows;
[tex]T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N[/tex]
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Heat rash is caused by chemical exposure Truth or false
Answer:
This is false.
Explanation:
Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.
Answer:
FALSE
Explanation:
Heat rash develops when blocked pores or sweat ducts trap perspiration under your skin. Symptoms range from superficial blisters to deep, red lumps. Some forms of heat rash feel tingly or intensely itchy.
Which is the largest number? O A. 9.9 x 106 O B. 4.5 x 107 O c. 5.5 x 105 O D. 5.8 x 108
Answer:
107
Explanation:
It's the biggest numberstudent measuring the mass of a rock recorded 6.759 g, 6.786 g, 6.812 g, and 6.779 g. which other measurment of the block mass would be most precise ?
Answer: 6.605
Explanation:
You are having a snowball fight with your best friend on a frosty winter day. You are standing on the roof of your 5 m tall house with a 0.4 kg snowball. You drop the snowball downward from rest toward your friend,
who is making snow angels below you. Ignoring air resistance, solve for the gravitational potential energy of
the snowball before it is released.
a) 12.5 J
b) 19.6J
c) 5J
d) 2J
Answer: B 19.6J
Explanation: The equation for Potential energy is PE=mgh
PE is the potential energy
m=Mass=0.4kg
g=Gravity=9.81m/[tex]s^{2}[/tex]
h=Height=5 metres
(0.4 kg)*(9.81m/[tex]s^{2}[/tex])*(5 metres)=19.62J
Bill is sitting on a tree limb that is 4 meters above the ground with a water balloon. He wants to drop the water balloon so that it falls on his friend Tim who is approaching on a bike at a constant speed of 8 meters per second. How far away should Tim be from a point directly under bill when bill drops the balloon?
Answer:
wow poor bill
Explanation:
a block starts from rest and begins sliding down an incline. The block reaches a speed of 12 meters per second as it slides a distance of 50 meters. calculate the blocks rate of acceleration
Vf² = V₁² + 2ad
(12 m/s) ² = (0 m/s) ² + 2 (a) (50m)
a = 1.44 m/s ²
Answer:
[tex]\boxed {\boxed {\sf 1.44 \ m/s^2}}[/tex]
Explanation:
We are asked to find the block's rate of acceleration.
We are given the final velocity, initial velocity, and distance. Therefore, we will use the following kinematic equation:
[tex]{v_f}^2={v_i}^2+2ad[/tex]
The block starts at rest or 0 meters per second. The block reaches a final velocity of 12 meters per second. The distance traveled is 50 meters.
[tex]v_i[/tex]= 0 m/s [tex]v_f[/tex]= 12 m/s [tex]d[/tex]= 50 mSubstitute the values into the formula.
[tex](12 \ m/s)^2 = (0 m/s)^2 + 2a (50 \ m)[/tex]
Solve the exponents.
(12 m/s)² = 12 m/s * 12 m/s = 144 m²/s²(0 m/s)² = 0 m/s * 0 m/s = 0 m²/s²[tex]144 \ m^2/s^2= 0 m^2/s^2 + 2a (50 \ m)[/tex]
The 0 can be subtracted from both sides, or simply canceled.
[tex]144 \ m^2/s^2 = 2a (50 \ m)[/tex]
Multiply 2 and 50 meters.
[tex]144 \ m^2/s^2 = (2 *50 \ m)* a[/tex]
[tex]144 \ m^2/s^2 = (100 \ m)* a[/tex]
We are solving for a, so we must isolate the variable. It is being multiplied by 100 meters. The inverse of multiplication is division, so we divide both sides by 100 meters.
[tex]\frac {144 \ m^2/s^2}{100 \ m}= \frac{(100 \ m)*a}{100 \ m}[/tex]
[tex]\frac {144 \ m^2/s^2}{100 \ m}=a[/tex]
[tex]1.44 \ m/s^2 =a[/tex]
The block's rate of acceleration is 1.44 meters per second squared.