Answer:
No. A vacuum does not exist at an altitude of 75,000 ft
Explanation:
There is naturally a decrease in air pressure as one goes higher into the atmosphere. However, vacuum conditions are not actually present within the atmosphere as there are still significant amounts of gases even at really high altitudes.
To prove this we know that planes cannot fly in a vacuum, because they need to burn air in order to gain propulsion from their engines.
One military plane - the SR-71 flew at about 90,000 feet.
This is a lot higher than 75,000 feet. For it to be able to at that altitude, it means that there was a significant quantity of air left even at 90,000 feet.
Given the reaction: N2(g) +2O2(g) ⇌ 2NO2(g) The forward reaction is endothermic. Determine which of the following changes would result in more reactant being produced. I. Increase NO2 II. Increase O2 III. Add a catalyst IV. Increase the temperature V. Decrease the pressure A. I and V B. II and IV C. II, III, and V D. All
Answer:
A. I and V
Explanation:
According to Le Chatelier's Principle, increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true. By the same principle, II is false.
For gases, decreasing the pressure will cause the equilibrium to shift towards the side with higher number of moles. So V is true.
The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false. And adding a catalyst has no effect on the equilibrium, so III is false.
The changes would result in more reactants being produced will increase NO₂ and decrease the pressure. Then the correct option is A.
What is a chemical reaction?The chemical reaction is the reaction between two reactants that led to the formation of products.
The products are substances that form after the reaction. The reactants are the substances that are original materials.
Given the reaction: N₂(g) +2O₂(g) ⇌ 2NO₂(g)
The forward reaction is endothermic. Increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.
By the same principle, II is false.
For gases, the decrease in pressure will shift the equilibrium toward the high number of moles side.
So V is true.
The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false. Adding a catalyst has no effect on the equilibrium, so III is false.
The changes would result in more reactants being produced will increase NO₂ and decrease the pressure.
Then the correct option is A.
Learn more about chemical reactions.
https://brainly.com/question/22817140
#SPJ5
A force produces an acceleration of 5 ms
when applied on a body of mass 4 kg. The
magnitude of the force applied is
F = m • a (I. Newton)
F = (4 kg) x (5 m/s^2)
F = 20 Newtons
There are only six player per teams in a hockey game. A group of 14 friends wants to start a game. What is the most sportsman-like way to set up the game ?
Answer:
We have 14 friends, and each team must have 6 players:
Then, in the two teams, we have 2*6 = 12 players.
This will mean that 2 of the friends can not be included in the game.
To solve this:
For example, each of those 2 players go to one of the teams, so we actually have two teams of 7 players.
Only 6 of them will play at the time, and the other player will rotate each fixed amount of time
Then the correct answer would be:
Rotate the players (in the teams) so all of them can play.
A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 142 feet per second from an initial height of 93 feet off the ground, then the height of the projectile, h h, in feet, t t seconds after it's shot is given by the equation:
Explanation:
It is given that,
Initial velocity of the projectile, u = 142 ft/s
Initial height off the ground, [tex]h_o = 93\ feet[/tex]
We need to find the height of the projectile t seconds after its shot. It is a concept of kinematics. The equation of projectile is given by the formula as follows :
[tex]h= -16t^2+ut+h_o[/tex]
t is time in seconds
So, putting all the values we get :
[tex]h= -16t^2+128t+112[/tex]
Hence, this is the required solution.
calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power - 3 column
Answer:
1.1259*10^9 Newton per Columb
Explanation:
the magnitude of the electric field intensity can be calculated using the expresion below;
E=Kq/r^2
Where k= constant
q= electric charge
r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency
:,K=59*10^9 Columb
If we substitute the value into above formula we have
E=(9*10^9)*(5*10^-3)/(20*10^-2)^2
=1.1259*10^9 Newton per Columb
Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb
A ball is launched horizontally at 150 m/s from a cliff. What is its horizontal velocity after 3 seconds? A. 0 m/s B. 30 m/s C. 150 m/s D. 50 m/s
Answer:
50m/s
Explanation:
Formula:
velocity= distance/ time
velocity= 150/ 3
velocity= 50 m/s
I hope this helped you :)
When a ball is launched horizontally at 150 m/s from a cliff then its horizontal velocity after 3 seconds would be 150 m/s, therefore the correct option is C.
What is Velocity?
The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.
The mathematical expression for velocity is given by
velocity= total displacement/Total time
Suppose an object has a total displacement of 100 meters in a total time of 25 seconds its velocity would be 4 meter/seconds
For the given problem situation when a ball is launched horizontally at 150 m/s from a cliff then its horizontal velocity after 3 seconds would be 150 m/s because the horizontal component of the velocity remains constant during a projectile motion, therefore, the correct option is C.
Learn more about Velocity from here
brainly.com/question/18084516
#SPJ5
Consider that each tick mark represents 1 mile on the vector grid, use the Gizmo to simulate the following scenario: Imagine that a hiker walked 6 mi SE and then 4 mi N. Find the sum of the vectors. Which of the following best describes the general direction that the blue line points?
a) south
b) west
c) east
d) cannot be determined from this information
Answer:
The best description of the general direction that the blue line points is East direction
Answer:
c. east
Explanation:
Whats a scientific clame?
Answer:
A claim made by scientists backed up with evidence and research!
Explanation:
Hope this helped! :)
The north pole of a bar magnet is rapidly introduced into a solenoid at one end (say A). Which of the following statements correctly depicts the phenomenon taking place?
(a) No induced emf is developed.
(b) The end A of the solenoid behaves like a south pole.
(c) The end A of the solenoid behaves like north pole.
(d) The end A of the solenoid acquires positive potential.
Answer:
The correct option is;
(b) The end A of the solenoid behaves like a north pole
Explanation:
According to Lenz's law we have that the induced emf direction in the solenoid due to the rapid introduction of the bar magnet will be such that the electric current induced will have a resultant magnet field that will oppose to the movement of the north pole of the bar magnet that resulted in the magnetic field
Therefore, the opposing magnetic pole to the north pole of a magnet is a north pole and the solenoid end A will act like the north pole.
Which of the following are double-displacement reactions? multiple answers
A. 2H2(g) + O2(g) -> 2H2O(g)
B. Zn(s) + 2HCI(aq) -> H2(g) + ZnCI2(s)
C. Ba(OH)2(aq) + 2HCIO4(aq) -> Ba(CIO4)2(aq) + 2H2O(I)
D. HNO3 (aq) + KOH (aq) -> H2O(I) + KNO3 (aq)
Answer:
C and D
Explanation:
A: is a simple composition
B: is a single replacement
C: C is a double displacement
D: is a double replacement
Answer:
The answers are C abd D.
Explanation:
Here,
A no. Is a combination or analysis chemical reaction.
B no.is a single displacement reaction as cl2 goes to zn.
C no. Is double displacement reaction.
D no. Is a double displacement reaction.
Hope it helps.....
(a) Two microwave frequencies are authorized for use in microwave ovens: 900 and 2560 MHz. Calculate the wavelength of each. (b) Which frequency would produce smaller hot spots in foods due to interference effects
Answer:
a) wavelength for the two frequencies are 0.33 m and 0.12 m
(b) 2560 MHz
Explanation:
Given:
microwave frequencies are
900 and 2560 MHz
f1= 900MHz we need to convert it to Go so the unit will be able to be consistent
f1= 900MHz= 900× 10^6Hz
f2= 2560 MHz= 2560×10^6Hz
a)Calculate the wavelength of each
But we can calculate our wavelength λ using the below formula
λ=c/f
c which is the speed of light has a constant value of =3*10^8m/s
Then for the first frequency
λ=c/f =(3×10^8)/900×10^6
=0.33 m
=33 cm.
For the second frequency
λ=c/f = (3×10^8)/2560×10^6
=0.12 m
=12 cm
(b) Which frequency would produce smaller hot spots in foods due to interference effects
(b) 2560 MHz( has the smallest wavelength)
This is because a small wavelength microwave gives a pattern with which is interference with waves and have a closer hotspot
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?
Answer:
0.2 m/s²Explanation:
Given,
Mass ( m ) = 10 kg
Force ( f ) = 2 Newtons
Acceleration ( a ) = ?
Now, let's find the acceleration :
We know that,
[tex]f = ma[/tex]
Plug the values
[tex]2 = 10a[/tex]
Swap the sides of the equation
[tex]10a = 2[/tex]
Divide both sides of the equation by 10
[tex] \frac{10a}{10} = \frac{2}{10} [/tex]
Calculate
[tex]a = 0.2 \: {metre \: per \: second \: }^{2} [/tex]
Hope this helps...
Best regards!!
Supposing we launched a very fast dart from the Space Shuttle, pointed in some direction away from any planet, so that it could travel beyond the solar system. What would it be most likely to hit first after traveling outward for a while
If we launched a very fast dart from the Space Shuttle in a direction away from any planet, Assuming the dart is traveling at an extremely high speed (close to the speed of light), it might eventually encounter a cloud of interstellar gas or dust.
What does the space contain?Space is mostly empty, consisting of a vacuum with very low density. However, space also contains various astronomical objects, such as stars, planets, moons, asteroids, comets, and other celestial bodies.
There is also interstellar gas and dust scattered throughout space, which can sometimes form clouds that give birth to new stars. Additionally, space is permeated by electromagnetic radiation, including cosmic rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Space also contains various forms of energy, including dark energy, which is believed to be responsible for the accelerating expansion of the universe, and dark matter, which is thought to make up the majority of the matter in the universe but cannot be directly observed. Overall, space is a vast and complex environment that continues to fascinate astronomers and scientists.
Here in this question,
Therefore, if launched a very fast dart from the Space Shuttle, is pointed in some direction away from any planet, it could travel beyond the solar system. it would be most likely to hit a cloud of interstellar gas or dust. first after traveling outward for a while.
To know more about the universal gravitation constant click:
brainly.com/question/858421
#SPJ2
Which force is there between an ice skate and the ice
Answer the following three questions in complete sentences. 1. How much does the earth weigh? 2. How far away is the sun? 3. What is a black hole?
Answer: find the answer in the explanation.
Explanation:
1.) The weight of the earth can be calculated and estimated by the physicist by considering the mass of the earth and the knowlegde of gravity.
If the mass of the earth is considered to be 6 × 10^24 kg. Then with Physics formula and some mathematical techniques, we can conclude that the weight of the earth is approximately equal to 6 × 10^25 N.
2.) The distance of the sun to the earth is approximately 1.5 × 10^8 km. This measure is the distance from the surface of the earth to the sun.
3.) The black hole is approximately the size of the earth of very large gravitational field strength. It is a region of space of enormous gravity where no particular object can escape from it. Even electromagnetic radiation or light cannot escape from it.
Answer:
The Earth weighs 5.972 × 10^24 kg
The Sun is 94.022 million miles away.
A black hole is is a region of spacetime where gravity is so strong that nothing, no particles or even electromagnetic radiation such as light can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.
I hope this helps!! :)
It is nighttime, and you dropped your goggles into a swimming pool that is 3.0m deep. If you hold a laser pointer 1.0m directly above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.0m from the edge. How far are the goggles from the edge of the pool
Answer:
The distance of the goggle from the edge of the pool is 4.726 m
Explanation:
The given information are;
The depth of the swimming pool = 3.0 m deep
The height of the laser pointer above the swimming pool edge = 1.0 m
The distance from the pool edge the laser pointer enters the water = 2.0 m
The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°
Therefore, the angle of incidence to the vertical [tex]\theta_i[/tex], = θ - ∅ = 90 - 26.57° = 63.43°
By Snell's law we have;
The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;
[tex]\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}[/tex]
Where:
[tex]n_r[/tex] = Refractive index of the refractive medium which is water = 1.33
[tex]n_i[/tex] = Refractive index of the incidence medium which is air = 1.00
Therefore;
[tex]\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}[/tex]
We have that tan([tex]\theta_r[/tex]) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)
tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)
∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m
The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water
The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m
The distance of the goggle from the edge of the pool = 4.726 m.
Whenever the alternating current frequency in a series RLC circuit is halved,
a. the inductive reactance is doubled and the capacitive reactance is halved.
b. the inductive reactance is doubled and the capacitive reactance is doubled.
c. the inductive reactance is halved and the capacitive reactance is halved.
d. the inductive reactance is halved and the capacitive reactance is doubled.
e. the reactance of the circuit remains the same.
Answer:
The correct option is
a. The inductive reactance is doubled and the capacitive reactance is halved
Explanation:
For a series RLC circuit, is a resonant circuit such that the impedance, Z, is minimum at the resonance frequency
Also we have that the capacitive reactance [tex]X_C[/tex], is given as follows;
[tex]X_c = \dfrac{1}{\omega \cdot C}[/tex]
Where;
ω = Angular frequency = 2πf
Where;
f = The frequency in the circuit
[tex]\therefore X_c = \dfrac{1}{2 \cdot \pi \cdot f \cdot C}[/tex]
The inductive reactance is also given as follows;
[tex]X_L = \omega \cdot L = 2 \cdot \pi \cdot f \cdot L[/tex]
Therefore, when the circuit frequency doubles, the inductive reactance doubles and the capacitive reactance halves
When the alternating current frequency in a series RLC circuit is halved, the inductive reactance is doubled and the capacitive reactance is halved.
What is an alternating current frequency?An Alternating current (ac) frequency is known to be the amount of cycles per second that can be found in an ac sine wave.
The Frequency is known to be the rate through which the current changes direction in terms of per second. It is said to be often measured in hertz (Hz). Note that the alternating current frequency in a series RLC circuit is halved, the inductive reactance increases and the capacitive reactance is reduced.
Learn more about alternating current from
https://brainly.com/question/15595203
2.0 MW is to arrive at a large shopping mall over two 0.100Ω lines. Estimate how much power is saved if the voltage is stepped up from 120 V to 1200 V and then down again, rather than simply transmitting at 120 V. Assume the transformers are each 99% efficient.
Answer:
55 MW.
Explanation:
So, we are given the following data or parameters Below;
=> "2.0 MW is to arrive at a large shopping mall over two 0.100Ω line.
=> " the voltage is stepped up from 120 V to 1200 V and then down again, rather than simply transmitting at 120 V."
=> "Assume the transformers are each 99% efficient."
STEP ONE: determine the current in the transmission line.
Output Current, i = Power/ voltage.
Output Current,i = (2.0 MW × 10^6 W/ 1 MW)/120.
Output Current,i = 1.66 × 10^4 A.
Therefore, current in the transmission line = output voltage × output current/99% × line voltage.
= 120 × 1.66 × 10^4/ 99% × 1200 = 1.68 × 10^3 A.
STEP TWO: determine the power loss in the two lines.
Power loss = i^2 × Resistance
Power loss = (1.66 × 10^4 )^2 × 0.1 × 2 = 5.5 × 10^7 watt.
STEP THREE: determine the power generated.
Power generated = 2 × 10^6 +5.5 × 10^7.
Power generated = 5.57 × 10^7 watt.
STEP FOUR: determine the step down transformer power.
= 2 × 10^6/99% = 2.02 × 10^6.
Thus, 2.02 × 10^6 + 5.57 × 10^5 = 2.58 × 10^6 watt.
STEP FIVE: Determine the total power and the saved power.
Total power = 2.58 × 10^6/ 99%= 2.6 × 10^6.
Saved power = 5.7 × 10^7 - 2.6 × 10^6 .
Conversion to MW gives saved power = 55 MW.
=
You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
define the apparent cubic expansivity of a liquid
Answer:
THE APPARENT CUBIC EXPANSIVITY OF A LIQUID : is defined as the increase in volume per unit volume per unit rise in temperature when the liquid is heated in an expansible vessel.
A 0.10 g honeybee acquires a charge of 23 pC while flying. The electric field near the surface of the earth is typically 100 N/C, directed downward. What is the ratio of the electric force on the bee to the bee's weight
Answer:
Explanation:
force on charge q in electric field E = q E
force on charge of bee in given electric field
= 23 x 10⁻¹² x 100
= 23 x 10⁻¹⁰ N
weight of honey bee = .10 x 10⁻³ x 9.8
= 9.8 x 10⁻⁴ N
Ratio of force / weight of bee
= 23 x 10⁻¹⁰ / 9.8 x 10⁻⁴
= 2.347 x 10⁻⁶ .
Can someone please help me?
An alien spaceship is 650 m above the ground and moving at a constant velocity of 175 m/s upwards.
How high above the ground is the ship after 5 seconds?
Answer:
1525 meters above ground
Explanation:
So to do this you will need to write this in slope intercept form or [tex]y=mx+b[/tex]. So 650 would be the b, 175 would be the m, and the x would be 5 so the equation would be [tex]y=175(5)+650[/tex] so if you solve or simplify the equation you will get 1525 meters above the ground and that would be our final answer.
A board used to pry a boulder loose and roll it over is an example of which of these simple machines?
A.
inclined plane
B.
wheel and axle
C.
lever
D.
pulley
Answer:
C. lever
Explanation:
Any sort of prying tool is an example of a lever.
Answer:
A lever
Explanation:
A man drives his car 5 km east of his starting point then he travels 10 km south and reaches a point. From here he travels 15 km towards west and reaches another point .Finally he travels 20 km towards north. Find the net displacement of the man from where he started. plz nswer it and ell the scale or it!!!!!!!!!!!!!!!!!!!!!
Answer:
According to the question ,
Source point is A and the destination point is D
We have to find the distance of AD
From figure,
AE = AB - EB
EB = DC and ED = BC
Therefore in triangle AED
AD² = AE² + ED²
AD² = 4² + 3²
AD² = 16 + 9
AD² = 25
AD = 5
So , the man is 5km far from the starting point
Hope this helps and pls mark as brainliest :)
Help!
6. Assume a position vs time graph displays a horizontal line, what does this represent?
A. Constant Velocity
B. 0 Acceleration
if it is horizontal line, that means position is same but time is increasing.
velocity=0 . particle is not even moving
an attempt to estimate the height of a tree the Shadow of an upright metre rule was found to be 25 cm and the length of the Shadow of the tree was 7 m what is the height of the tree
Answer:
The actual height of the tree is 28 m
Explanation:
The given information are;
The length of the shadow of an upright meter rule = 25 cm
The actual height of the meter rule = 100 cm
The length of the shadow of the tree = 7 m
The actual height of the tree = h
We have
[tex]\dfrac{The \ length \ of \ the \ shadow \ of \ an \ upright \ metre \ rule}{The \ actual \ height \ of \ the \ metre \ rule} = \dfrac{The \ length \ of \ the \ shadow \ of \ the \ tree}{The \ actual \ height \ of \ the \ tree}[/tex]Which gives;
[tex]\dfrac{25 \ cm}{100 \ cm} = \dfrac{7 \ m}{The \ actual \ height \ of \ the \ tree}[/tex]
Therefore;
[tex]The \ actual \ height \ of \ the \ tree = 7 \ m \times \dfrac{100 \ cm}{25\ cm} = 7 \ m \times 4 = 28 \ m[/tex]
That is the actual height of the tree = 28 m.
CAN YOU HELP ME IN THE FOLLOWING EQUATION THE SPEED IS V = A + BT. DETERMINE THE DIMENSIONS OF A AND B
Answer:
A = [m/s]
B = [m/s²]
Explanation:
Assuming that V has SI units of m/s, then A and BT must also have units of m/s.
A = [m/s]
BT = [m/s]
Since T has SI units of s:
B [s] = [m/s]
B = [m/s²]
Ozone molecules in the stratosphere absorb much of the harmful radiation from the sun. How many ozone molecules are present in 2.00 L of air under the stratospheric ozone conditions of 275 K temperature and 1.89 × 10−3 atm pressure?
Answer:
1.01×10^20 molecules of ozone.
Explanation:
Data obtained from the question include:
Volume (V) = 2 L
Temperature (T) = 275 K
Pressure (P) = 1.89×10¯³ atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) of ozone =.?
Using the ideal gas equation, we can obtain the number of mole of ozone as follow:
PV = nRT
1.89×10¯³ x 2 = n x 0.0821 x 275
Divide both side by 0.0821 x 275
n = (1.89×10¯³ x 2) /(0.0821 x 275)
n = 1.67×10¯⁴ mole.
Therefore the number of mole of ozone in 2 L of air is 1.67×10¯⁴ mole.
Finally, we shall determine the number of molecules present in 1.67×10¯⁴ mole of ozone.
This can be obtained as follow:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ozone contains 6.02×10²³ molecules.
If 1 mole of ozone contains 6.02×10²³ molecules,
therefore, 1.67×10¯⁴ mole of ozone will contain = 1.67×10¯⁴ x 6.02×10²³ = 1.01×10^20 molecules.
Therefore, 1.01×10^20 molecules of ozone are present in 2 L of air.
what is relative velocity?
Answer:
the velocity of a moving body relative to another body is called relative velocity.
A car is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of -0.5 m/s2(metre per sec.Square). Find how far the car will go before it is brought to rest?
The only thing that mkes this question inconvenient is that it uses a mixture of units ... speed in km/hr, and acceleration in m/s². You can't directly mash those together.
What's the speed when we express it in m/s ?
Speed = (90 km/hr) · (1,000 m/km) · (1 hr/3,600 sec)
Speed = (90 · 1,000 · 1 / 3,600) · (km-m-hr / hr-km-sec)
Speed = 25 m/s
OK great !
-- The car is traveling at 25 m/s when the brakes are applied.
-- The brakes slow it down by 0.5 m/s every second.
-- So it takes (25/0.5) = 50 seconds to stop the car.
-- During that time, the car's average speed is (1/2)·(25m/s + 0) = 12.5 m/s .
-- Moving at an average speed of 12.5 m/s for 50 sec, the car travels
(12.5 m/s) · (50 s) = 625 meters