Answers
Answer:
P(4, tail) = 1/12
Step-by-step explanation:
The probability of a particular outcome when all possible outcomes are equaly likely, is the number of "desired" oucomes divided by the total number of possible outcomes.
In your case, there are 12 possible outcomes (you can count them, or calculate 6 for the dice times 2 for the coin). Only one of them is "desired", namely the combination of 4 and a tail. Hence 1 divided by 12.
Related Questions
Choose Yes or No to tell if the fraction
4
9
4
9
will make each equation true.
63
×
□
=
28
63
×
□
=
28
18
×
□
=
8
18
×
□
=
8
96
×
□
=
42
96
×
□
=
42
36
×
□
=
16
36
×
□
=
16
Answers
Yes, the fraction 4/9 will make each equation true.
What is the fraction about?Fraction is an element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.
To see why, we can simplify the fraction 4/9 as follows:
4/9 = (4 x 7)/(9 x 7) = 28/63
Now, we can substitute 4/9 with 28/63 in each equation to see that they are all true:
63 x 28/63 = 28
18 x 28/63 = 8
96 x 28/63 = 42
36 x 28/63 = 16
We can also write it as:
63 × (4/9) = 28
18 × (4/9) = 8
96 × (4/9) = 42
36 × (4/9) = 16
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MULTIPLYING FUNCTIONS Perform the indicated operation using the functions
f(x)=3x+0.5
and
g(x)=3x−0.5
. 35.
f(x)⋅g(x)
36.
(f(x)) 2
37.
(g(x)) 2
Answers
The answers are:
35. f(x)⋅g(x) = 9x2 - 0.25
36. (f(x))2 = 9x2 + 3x + 0.25
37. (g(x))2 = 9x2 - 3x + 0.25
To MULTIPLYING FUNCTIONS, we simply multiply the corresponding terms of each function together. Let's use the given functions f(x)=3x+0.5 and g(x)=3x−0.5 and perform the indicated operations.
35. f(x)⋅g(x) = (3x+0.5)(3x−0.5) = 9x2 - 0.25
36. (f(x))2 = (3x+0.5)2 = 9x2 + 3x + 0.25
37. (g(x))2 = (3x-0.5)2 = 9x2 - 3x + 0.25
So, the answers are:
35. f(x)⋅g(x) = 9x2 - 0.25
36. (f(x))2 = 9x2 + 3x + 0.25
37. (g(x))2 = 9x2 - 3x + 0.25
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Solve for c:\(c = 5\frac{5}{6} \times 2 \)
Please hellllppppp
Answers
The solution for c in the equation is 35/3
How to determine the solution for cFrom the question, we have the following parameters that can be used in our computation:
\(c = 5\frac{5}{6} \times 2 \)
Express the equation properly
So, we have the following representation
c = 5 5/6 * 2
Convert the fraction to improper fraction
So, we have the following representation
c = 35/6 * 2
Evaluate the products
c = 35/3
Hence, the solution is 35/3
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Describe the graph of y=1/2x-10 compared to the graph of y=1/x
Answers
Answer:
The graph of y=1/2x-10 is a straight line with a slope of 1/2 and y-intercept of -10. It slopes upward from left to right and intersects the y-axis at -10.
On the other hand, the graph of y=1/x is a hyperbola that passes through the origin and has asymptotes at x=0 and y=0. It consists of two branches that curve towards the asymptotes in opposite directions.
Compared to the graph of y=1/x, the graph of y=1/2x-10 is a simpler and more predictable shape. It does not have asymptotes and has a constant slope. It also does not pass through the origin, unlike the graph of y=1/x.
PLEASE HELP (IMAGE BELOW)
Answers
The expanded and exponential forms of the given algebraic expressions are given below:
1. Expanded form: -3 * y * y * y * y * - 4 * x
Exponential form: 12xy⁴
2. 5x²y⁴ * 5xy⁵
Expanded form: 5 * x * x * y * y * y * y * 5 * x * y * y * y * y * y
Exponential form: 5¹⁺¹ * x² * y⁴⁺⁵ = 5²x²y⁹
3. Expanded form: 2 * t * u * u * u * u * 3 * t * t * t * 4 * t * u * u
Exponential form: 24t³u⁶
What are the expanded and exponential forms of the given algebraic expressions?The expanded and exponential forms of the given algebraic expressions are given below:
1. - 3y⁴ * - 4x
Expanded form: -3 * y * y * y * y * - 4 * x
Exponential form: -3 * y * y * y * y * - 4 * x = 12xy⁴
2. 5x²y⁴ * 5xy⁵
Expanded form: 5 * x * x * y * y * y * y * 5 * x * y * y * y * y * y
Exponential form: 5¹⁺¹ * x² * y⁴⁺⁵ = 5²x²y⁹
3. 2tu⁴ * 3t³ * 4tu²
Expanded form: 2 * t * u * u * u * u * 3 * t * t * t * 4 * t * u * u
Exponential form: 2 * 3 * 4 * t¹⁺¹⁺¹ * u⁴⁺² = 24t³u⁶
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the coefficient β from bivariate OLS has the asymptotic distribution:
√N(β – β) + d(0,σ2),
Where
σ2 Var((Xi - E[X])) / Var(xi)2
Recall that €; = Y;-(a +X;B). This question will teach you about homoskedasticity and heteroskedasticity. By definition, €i is homoskedastic if Var(€ Xi = c) = w2 for all r; that is, the conditional variance of €i given X, doesn't depend on Xi. Otherwise, €i is said to be heteroskedastic.
Show that if €, is homoskedastic, then Var(Y|X, r) doesn't depend on r. (Hint: remember that Varſa +Y] = Var[Y], and when we have conditional expectations/variances we can treat functions of X like constants]
Say Yi is earnings and X, is an indicator for whether someone has gone to college. In light of the fact that we showed in the previous question, what would homoskedasticity imply about the variance of earnings for college and non-college workers? Do you think this is likely to hold in practice?
Show that if €; is homoskedastic and E[ci|Xį] = 0 (as occurs when the CEF is linear), then o? Varex). (Hint: you may use the fact that E[ci] = E(X;ei] = 0, (X (C)
Answers
The variance of the error term is equal to the expected value of the squared error term, which is equal to the variance of Xi.
The asymptotic distribution of the coefficient β from bivariate OLS is given by √N(β – β) + d(0,σ2), where σ2 is the variance of the error term and is given by Var((Xi - E[X])) / Var(xi)2. If the error term is homoskedastic, then the variance of the error term does not depend on the value of Xi and is constant for all values of Xi. This implies that the variance of Y given X and r does not depend on r, as shown below:
Var(Y|X, r) = Var(βX + ε|X, r) = Var(ε|X, r) = σ2
Since the variance of the error term is constant and does not depend on the value of X or r, the variance of Y given X and r is also constant and does not depend on r.
If Yi is earnings and Xi is an indicator for whether someone has gone to college, homoskedasticity would imply that the variance of earnings for college and non-college workers is the same. This is unlikely to hold in practice, as there are likely to be other factors that affect earnings, such as occupation, experience, and location, that may differ between college and non-college workers and lead to different variances in earnings.
If the error term is homoskedastic and E[εi|Xi] = 0, then the variance of the error term is equal to the variance of Xi, as shown below:
Var(εi) = E[εi2] - (E[εi])2 = E[εi2] = E[(Xi - E[Xi])2] = Var(Xi)
This is because the error term is uncorrelated with Xi and has a mean of zero
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One rational root of the given equation is 2 . Use the root and solve the equation. The solution set of x^(3)-5x^(2)-4x+20=0 is
Answers
Answer:
If 2 is a rational root of the equation x^3 - 5x^2 - 4x + 20 = 0, then (x - 2) is a factor of the polynomial. This is because of the rational root theorem, which states that any rational root of a polynomial with integer coefficients must be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient. In this case, the constant term is 20 and the leading coefficient is 1, so the possible rational roots are ±1, ±2, ±4, ±5, ±10, and ±20.
Since 2 is a root, we can use long division or synthetic division to divide x^3 - 5x^2 - 4x + 20 by (x - 2). We get:
code
2 | 1 -5 -4 20 | 2 -6 -20 |------------ | 1 -3 -10 0
Therefore, we have:
x^3 - 5x^2 - 4x + 20 = (x - 2)(x^2 - 3x - 10)
Now, we need to solve the quadratic equation x^2 - 3x - 10 = 0. We can use the quadratic formula:
x = (3 ± sqrt(3^2 - 4(1)(-10))) / 2 x = (3 ± sqrt(49)) / 2 x = (3 ± 7) / 2
So the solutions to the equation x^3 - 5x^2 - 4x + 20 = 0 are:
x = 2, x = (3 + 7)/2 = 5, x = (3 - 7)/2 = -2
Therefore, the solution set is {2, 5, -2}.
Step-by-step explanation:
Step 1: Use the Rational Root Theorem to find possible rational roots The Rational Root Theorem states that any rational root of a polynomial with integer coefficients must be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient. In this case, the constant term is 20 and the leading coefficient is 1, so the possible rational roots are ±1, ±2, ±4, ±5, ±10, and ±20. Since we are given that 2 is a root, we can conclude that (x - 2) is a factor of the polynomial.
Step 2: Use long division or synthetic division to divide the polynomial by (x - 2) We can use long division or synthetic division to divide the polynomial x^3 - 5x^2 - 4x + 20 by (x - 2). Both methods will give the same result, but I'll show the synthetic division method here:
code
2 | 1 -5 -4 20 | 2 -6 -20 |------------ | 1 -3 -10 0
The first row of the division represents the coefficients of the polynomial x^3 - 5x^2 - 4x + 20, starting with the highest degree term. We divide the first coefficient by the divisor, which gives us 1/1 = 1. Then we multiply the divisor (2) by the quotient (1), which gives us 2. We write 2 below the next coefficient (-5), and subtract to get (-5) - 2 = -7. We bring down the next coefficient (-4) to get -7 - (-4) = -3. We repeat the process with -3 as the new dividend, and so on, until we get a remainder of 0 in the last row.
The second row shows the partial quotients (in this case, just one quotient of 1), and the third row shows the coefficients of the quotient polynomial x^2 - 3x - 10. The last row shows the remainder, which is 0 in this case.
Step 3: Factor the quotient polynomial We now have x^3 - 5x^2 - 4x + 20 = (x - 2)(x^2 - 3x - 10), since (x - 2) is a factor of the polynomial. We can factor the quadratic polynomial x^2 - 3x - 10 by finding two numbers that multiply to -10 and add to -3. These numbers are -5 and 2, so we can write:
x^2 - 3x - 10 = (x - 5)(x + 2)
Step 4: Find the solutions to the equation We now have:
x^3 - 5x^2 - 4x + 20 = (x - 2)(x^2 - 3x - 10) = (x - 2)(x - 5)(x + 2)
The solutions to the equation are the values of x that make the polynomial equal to 0. These values are the roots of the equation. We have:
x - 2 = 0, so x = 2 is a root x - 5 = 0, so x = 5 is a root x + 2 = 0, so x = -2 is a root
Therefore, the solution set is {2, 5, -2}.
The solution set of the equation x^(3)-5x^(2)-4x+20=0 is found to be {2, 5, -2}.
One rational root of the given equation is 2. We can use synthetic division to find the other roots.
Set up the synthetic division table by placing the root (2) in the leftmost column and the coefficients of the equation (1, -5, -4, 20) in the top row.
2|1-5-420|2-6-201-3-100
Multiply the root (2) by each of the numbers in the bottom row and place the result in the row below. Then add the numbers in the top and bottom rows to get the numbers in the final row.
The final row represents the coefficients of the reduced equation: x^(2)-3x-10=0. We can use the quadratic formula to find the remaining roots:
x = (-(-3) ± √((-3)^(2) - 4(1)(-10))) / (2(1))
x = (3 ± √(9 + 40)) / 2
x = (3 ± √49) / 2
x = (3 ± 7) / 2
x = 5 or x = -2
So the solution set of the equation is {2, 5, -2}.
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what is 3/8 divided by 1/4
Answers
Answer:
1.5
Step-by-step explanation:
See the screenshots for step by step explanation
Use symoballab it is helpfull
Hellppp meee which one is it????!!!!
Answers
In Booneville, the use of landlines has been declining at a rate of 20% every year. If there are
25,300 landlines this year, how many will there be in 5 years?
If necessary, round your answer to the nearest whole number.
Answers
Answer:
8290
Step-by-step explanation:
Explanation is on the pic
simplify 5x+4y-x-y
I HAVE TO ADD MORE LETTERS SO IM WRITING THIS BIT JUST IGNORE XX
Answers
4
+
3
Hope this helps!!
Answer:
4x+3y
Step-by-step explanation:
Combining like terms, we get:
5x - x + 4y - y = 4x + 3y
Therefore, 5x+4y-x-y simplifies to 4x+3y.
Which amount of money does the digit 5 represent fife tenths of a dollar.
A. 5 dollar bill, a quarter, a dime, 2 nickels, and 4 Penny's.
B. 1 dollar bill, a quarter, a dime, a nickel, and 5 Penny's
C. Two 20 dollar bills, a 10 dollar bill, a quarter, a dime, and 2 Penny's.
D. a 10 dollar bill, a quarter, 5 nickels, and 2 Penny's.
Answers
None of the given options represents an amount of money equivalent to fife tenths of a dollar.
What is Money?
In mathematics, money is a unit of measure used to represent the value of goods or services. It is typically denoted in a currency unit, such as dollars, euros, or yen, and is often used to express prices, wages, or financial transactions. Money is a form of quantitative data and can be manipulated using various mathematical operations, such as addition, subtraction, multiplication, and division.
Fife tenths of a dollar is equivalent to $0.50, since there are 10 tenths in a dollar.
The amount of money that the digit 5 represents $0.50.
Looking at the given options, the only option that contains a total value of $0.50 is option B:
1 dollar bill = $1.00
quarter = $0.25
dime = $0.10
nickel = $0.05
5 Pennies = $0.05
Adding these values together, we get a total of $1.45, which is more than $0.50. Therefore, option B is incorrect.
Option D contains a total value of:
10 dollar bill = $10.00
quarter = $0.25
5 nickels = $0.25
2 Pennies = $0.02
Adding these values together, we get a total of $10.52, which is more than $0.50. Therefore, option D is incorrect.
Option A contains a total value of:
5 dollar bill = $5.00
quarter = $0.25
dime = $0.10
2 nickels = $0.10
4 Pennies = $0.04
Adding these values together, we get a total of $5.49, which is more than $0.50. Therefore, option A is incorrect.
The only remaining option is option C, which contains a total value of:
Two 20 dollar bills = $40.00
10 dollar bill = $10.00
quarter = $0.25
dime = $0.10
2 Pennies = $0.02
Adding these values together, we get a total of $50.37, which is more than $0.50. Therefore, option C is also incorrect.
Thus, none of the given options represents an amount of money equivalent to fife tenths of a dollar.
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You need 2/3 yard of fabric to create. You have 12 feet of blue fabric and 4 feet of yellow. How many headbands can you make
Answers
You can make 16 headbands using the blue fabric and 5 headbands using the yellow fabric, for a total of 21 headbands.
To calculate this, we need to convert 2/3 yard to feet since the fabric is given in feet. 2/3 yard is equal to 2 feet.
Next, we need to determine how much fabric is needed to make one headband, which is 2 feet.
To find out how many headbands we can make using the blue fabric, we divide the total length of blue fabric (12 feet) by the length needed for one headband (2 feet). 12 feet / 2 feet = 6 headbands per yard of blue fabric. Therefore, with 12 feet of blue fabric, we can make 6 x 12 = 72 headbands.
Similarly, to find out how many headbands we can make using the yellow fabric, we divide the total length of yellow fabric (4 feet) by the length needed for one headband (2 feet). 4 feet / 2 feet = 2 headbands per yard of yellow fabric. Therefore, with 4 feet of yellow fabric, we can make 2 x 4 = 8 headbands.
Therefore, we can make a total of 72 + 8 = 80 headbands.
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Complete Question:
You need 2/3 yard of fabric to create a headband: You have 12 feet of blue fabric and 4 feet of yellow fabric; How many headbands can you make with all of the fabric?
I need help please and thank you
Answers
The solution is, distance from the point to the line is 22√10 feet.
What is a straight line?A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.
here, we have,
The distance from point (x, y) to the line ax+by+c=0 is given by ...
d = |ax +by +c|/√(a²+b²)
In general for, the equation of the line is ...
y = x/3 - 4
i.e. x -3y -12 = 0
so the distance formula is ...
d = |x -y -12|/√(1² +(-3)²) = |x -y - 12|/√10
For the given point, the distance is ...
d = |-6 -4 -12|/√10
= 22/√10
d = 22/√10 . . . .
distance from the point to the line = 22/√10
now, distance = 22/√10 * 10
=22√10 feet.
Hence, The solution is, distance from the point to the line is 22√10 feet.
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Use the Simplex algorithm to solve the following problem.Clearly state the solution. min 5x1 + 3x2 + 4x3 S/T 3x1 − 2x2 + x3 ≤ 16 2x1 + x2 + 5x3 ≥ 12 −4x1 + 2x2 + 2x3 = 11 xj ≥ 0
Answers
The Simplex Algorithm to solve the given linear programming problem gives the solution [tex]x_{1}[/tex] = 16, , [tex]x_{2}[/tex] = 0, [tex]x_{3}[/tex] = 11; while the minimum value of objective function is "13.2".
The solution to the given linear programming problem can be obtained using the Simplex algorithm. Using the initial basic feasible solution ([tex]x_{1}[/tex] = 0,[tex]x_{2}[/tex] = 0, [tex]x_{3}[/tex] = 0), the following sequence of steps can be used to solve the problem:
Step 1: Calculate cj - Zj = 5 - 0 = 5 (for [tex]x_{1}[/tex])Step 2: Calculate cj - Zj = 3 - 0 = 3 (for [tex]x_{2}[/tex])Step 3: Calculate cj - Zj = 4 - 0 = 4 (for [tex]x_{3}[/tex])Step 4: Calculate rj - cj = 16 - 3 = 13 (for [tex]x_{1}[/tex])Step 5: Calculate rj - cj = 12 - 3 = 9 (for [tex]x_{2}[/tex])Step 6: Calculate rj - cj = 11 - 4 = 7 (for [tex]x_{3}[/tex])Step 7: Choose x2 as the entering variable, since it has the lowest value of cj - Zj (9). Step 8: Determine the leaving variable. Since [tex]x_{1}[/tex]has the lowest ratio (13/3 = 4.3) it is chosen as the leaving variable.Step 9: Perform the pivot operation, replacing [tex]x_{2}[/tex] in the basis and [tex]x_{1}[/tex]out of the basis.Step 10: Repeat the process until all cj - Zj values are non-positive.The solution of the problem is: [tex]x_{1}[/tex] = 16, [tex]x_{2}[/tex] = 0, [tex]x_{3}[/tex] = 11.
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The sum of the first four terms of an AP is 38 and the sum of the first seven terms is 98. Find the first term and common difference of the AP
Answers
Answer:
The first term is 5The common difference is 3Step-by-step explanation:
Let x be the first term. Let y be the common difference between each number in the sequence. x and the next three terms would be:
x, x+y, x+2y, and x+3y
The sum of the 4 terms is 4x + 6y and is equal to 38
4x + 6y = 38
4x = 38 - 6y
x = (19/2) - (3/2)y [x is isolated here, to the left, for use in a lovely substitution coming up]
or x = 9.5 - 1.5y [simplified]
===
The sum of the first 7 terms would be the first 4 [from above: 4x + 6y] plus the next 3 terms;
4x + 6y
x + 4y
x + 5y
x + 6y
7x + 21y
7x + 21y is equal to 98
7x + 21y = 98
====
We have two equations and two unknowns, so we should be able to find an answer by substitution:
---
From above:
x = (19/2) - (3/2)y
7x + 21y = 98
Now use the first definition of x in the second equation:
7x + 21y = 98
7( (19/2) - (3/2)y) + 21a = 98
66.5 - 10.5y + 21y = 98
10.5y = 31.5
y = 3
Now use this value of y in either equation to find x:
7x + 21*(3) = 98
7x + 63 = 98
7x = 35
x = 5
====
x is the first term: 5y is the common difference: 3Check:
Do the first 4 terms sum to 38?
5 + 8 + 11 + 14 = 38 YES
Do the first 7 terms sum to 98?
38 + 17 + 20 + 23 = YES
Solve for v 4. 4 ( v - 16. 8 ) - -2. 3 = 3. 62
Answers
Simplifying the equation of v 4. 4 ( v - 16. 8 ) - -2. 3 = 3. 62, we find that v = 21.45.
To solve for v, we will use the following steps:
Simplify the left-hand side of the equation by distributing the 4.4:
4.4v - 73.92 + 2.3 = 3.62
Simplify further by combining like terms:
4.4v - 71.62 = 0
Add 71.62 to both sides of the equation:
4.4v = 71.62
Solve for v by dividing both sides by 4.4:
v = 71.62 / 4.4
v = 16.27727...
Round the answer to two decimal places:
v = 21.45
Therefore, the solution to the equation 4.4(v - 16.8) - (-2.3) = 3.62 is v = 21.45.
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In the diagram, NO ∥ MP and NO ≅MP. Which of the following theorems can be used to show that △MNP≅△OPN? Select all that apply.
Answers
Answer is SAS, we can solve this question by SAS theorem of triangle, for that we have to know more about triangle.
What is Triangle?A triangle in geometry is a three-sided polygon or object with three edges and three vertices.
If two triangles satisfy one of the following conditions, they are congruent:
a. Each of the three sets of corresponding sides is equal. (SSS)
b. The comparable angles between two pairs of corresponding sides are equal.(SAS)
c. The corresponding sides between two pairs of corresponding angles are equal. (ASA)
d. One pair of corresponding sides (not between the angles) and two pairs of corresponding angles are equal. (AAS)
e. In two right triangles, the Hypotenuses pair and another pair of comparable sides are equal. (HL)
So, △MNP≅△OPN and NO II MP and NO ≅ MP
then, ∠ ONP = ∠ MPN and Side NP is common.
Therefore we can solve it by SAS Theorem.
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Use the information below to work out the
closest distance that a cinema can put seats
to the screen.
Give your answer to 1 d.p.
Safety rules say that the angle of elevation
from a customer's eyes to the top of the
screen must be no more than 31°.
The top of the cinema screen is 7.6 m above
the floor.
Customers' eyes are 1.2 m above the floor
when they are sat on a seat.
Answers
The closest distance that a cinema can put seats is 10.667 m.
What is Trigonometry?One of the six mathematical functions used to express the side ratios of right triangles, the trigonometric function includes the sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc). The figure shows these six trigonometric functions in respect to a right triangle. Surveying, engineering, and navigation issues where one of a right triangle's acute angles and the length of a side are known but the lengths of the other sides need to be determined can be solved with ease using trigonometry.
As per the given data:
the angle of elevation from a customer's eyes
to the top of the screen ≤ 31°.
Top of the cinema screen = 7.6 m above floor.
Customers' eyes = 1.2 m above floor.
For the closest distance that a cinema can put the seats (B):
the angle of elevation from a customer's eyes
to the top of the screen (maximum) = 31°.
Distance between customer eyes and top of the screen (P) = 7.6 - 1.2 = 6.4 m
∴ With θ = 31° , tanθ = (P/B)
tan31° = (6.4/d)
d = (6.4/tan31°)
d = 10.667 m
Hence, the closest distance that a cinema can put seats is 10.667 m.
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Find the volume of a pyramid with a square base, where the side length of the base is
6.6 in and the height of the pyramid is 7.7 in. Round your answer to the nearest
tenth of a cubic inch.
Answers
We can conclude that the square pyramid has a volume of 111.5 in³.
What is a square pyramid?A square pyramid in geometry is a pyramid with a square base.
It is a right square pyramid with C4v symmetry if the apex is perpendicular to and above the square's center.
It is an equilateral square pyramid, the Johnson solid J1 if all edge lengths are equal.
A polyhedron with seven faces is called a heptahedron.
One "normal" heptahedron exists, and it is formed up of a surface with one side made up of four triangles and three quadrilaterals.
So, 6.6 inches wide is the square pyramid's base.
The square pyramid's height is 7.7 inches or h.
V = a²(h/3) is the formula for the square pyramid's volume.
By changing the values given:
V = 6.6²(7.7/3)
V = 43.56(2.56)
V = 111.51 ≈ 111.5
Therefore, we can say that the square pyramid has a volume of 111.5 in³.
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42. The area of a rectangle is 12x³- 18x² + 6x. The width is equal to the GCF What could the dimensions of the rectangle be? A. 6x(2x² – 3x) B. 3(4x³ - 6x² + 2x) C. x(12x²- 18x + 6) D. 6x(2x² - 3x + 1)
Answers
GCF - Greatest Common Factor
It is simply the largest of the common factors.
We have:
12x³- 18x² + 6x
We find GCF of 12, 18 and 6:
GCF(12, 18, 6) = 6
12 = 2 · 6
18 = 3 · 6
6 = 1 · 6
and GCF of x³, x² and x:
GCF(x³, x², x) = x
x³ = x² · x
x² = x · x
x = 1 · x
Therefore:
12x³- 18x² + 6x = 6x(2x² - 6x + 1)The following frequency table summarizes this year's injuries on the Canadian Rounders cricket team.
Number of injured players Number of matches
0
00
4
44
1
11
5
55
2
22
2
22
3
33
3
33
4
44
2
22
Based on this data, what is a reasonable estimate of the probability that the Canadian Rounders have
0
00 players injured for their next match?
Answers
Answer:
25%
Step-by-step explanation:
Number of favorable outcomes 4
Total number of outcomes=4+5+2+3+2=16
4/16=0.25
0.25x100=25
25%
Can anyone help me solve this question.. Help please !!
Answers
Answer
the answer is b
If f(x)) is an exponential function where f(-1)=18and f(5)=75, then find the value of f(2.5),
Answers
Answer:
We do not have enough information to find the exact value of f(2.5) without additional assumptions about the nature of the exponential function. However, we can make an estimate using the given data and the properties of exponential functions.
First, we can write the general form of an exponential function as:
f(x) = a * b^x
where a is the initial value or y-intercept, and b is the base or growth factor. We can use the two given data points to set up a system of equations and solve for a and b:
f(-1) = a * b^(-1) = 18
f(5) = a * b^5 = 75
Dividing the second equation by the first equation, we get:
f(5) / f(-1) = (a * b^5) / (a * b^(-1)) = b^6 = 75 / 18 = 25 / 6
Taking the sixth root of both sides, we get:
b = (25 / 6)^(1/6) ≈ 1.472
Substituting this value of b into the first equation, we get:
a = f(-1) / b^(-1) = 18 / 1.472 ≈ 12.223
Therefore, we have the exponential function:
f(x) ≈ 12.223 * 1.472^x
Using this function, we can estimate the value of f(2.5) as:
f(2.5) ≈ 12.223 * 1.472^(2.5) ≈ 34.311
Note that this is only an estimate, and the exact value of f(2.5) may be different depending on the specific nature of the exponential function.
Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is p dollars, the revenue R (in dollars) is R(p) = - 4p ^ 2 + 8000p (a) At what prices p is revenue zero? (b) For what range of prices will revenue exceed $1,400,000?
Answers
(a) Revenue will be zero when p = $0 and $2000.
(b) Revenue will exceed $1,400,000 when p > 500 or p > 700
(a) To find the prices at which revenue is zero, we need to set R(p) equal to 0 and solve for p:0 = -4p^2 + 8000p0 = 4p(p - 2000)So either 4p = 0 or p - 2000 = 0.
Solving for p gives us:
p = 0 or p = 2000
Therefore, the prices at which revenue is zero are $0 and $2000.
(b) To find the range of prices for which revenue exceeds $1,400,000, we need to set R(p) greater than 1,400,000 and solve for p:
1,400,000 < -4p^2 + 8000p
Rearranging the equation gives us:
0 < 4p^2 - 8000p + 1,400,000
Factoring the left side of the equation gives us:
0 < (p - 500)(4p - 2800)
So either p - 500 > 0 or 4p - 2800 > 0.
Solving for p gives us:
p > 500 or p > 700
Since we want the range of prices for which revenue exceeds $1,400,000, we need to take the larger value of p.
Therefore, the range of prices for which revenue exceeds $1,400,000 is p > 700, or prices greater than $700.
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A committee of size 10 is to be selected from a group of 10 men and 20 women. If the selection is made randomly,
1. In how many ways can this be done?
2. What is the probability that the committee consists of 5 men and 5 women?
3. What is the probability that there is no woman in the committee?
Answers
If the selection is made randomly, there are 30045015 ways to select a committee of size 10 from a group of 10 men and 20 women. The probability that the committee consists of 5 men and 5 women is 0.129. The probability that there is no woman in the committee is 0.000000033.
1. The total number of ways to select a committee of size 10 from a group of 10 men and 20 women is given by the combination formula:
C(n,k) = n! / (k! * (n-k)!)
Where n is the total number of people (10 men + 20 women = 30) and k is the size of the committee (10).
C(30,10) = 30! / (10! * (30-10)!)
C(30,10) = 30! / (10! * 20!)
C(30,10) = 30045015
Therefore, there are 30045015 ways to select a committee of size 10 from a group of 10 men and 20 women.
2. The probability that the committee consists of 5 men and 5 women is given by:
P(5 men and 5 women) = C(10,5) * C(20,5) / C(30,10)
P(5 men and 5 women) = (10! / (5! * 5!)) * (20! / (5! * 15!)) / (30! / (10! * 20!))
P(5 men and 5 women) = (252 * 15504) / 30045015
P(5 men and 5 women) = 0.129
3. The probability that there is no woman in the committee is given by:
P(no woman) = C(10,10) * C(20,0) / C(30,10)
P(no woman) = (10! / (10! * 0!)) * (20! / (0! * 20!)) / (30! / (10! * 20!))
P(no woman) = (1 * 1) / 30045015
P(no woman) = 0.000000033
Therefore, the probability that there is no woman in the committee is 0.000000033.
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how long in years will it take for the investment y= 5000(1.03)^x , to double in value when starting at 5000? round your answer to the nearest hundredth
Answers
It will take 23.50 years for the investment to double.
How to find the time the investment will double?The investment has the formula y= 5000(1.03)ˣ . Therefore, let's find the time in years the investment will double in value when starting at 5000 units.
The double of 5000 units is 10000 units.
Therefore,
y = 5000(1.03)ˣ
where
x = time in yearsHence,
y = 5000(1.03)ˣ
10000 = 5000(1.03)ˣ
divide both sides by 5000
10000 / 5000 = (1.03)ˣ
2 = (1.03)ˣ
log both sides
x = In 2 / In 1.03
x = 23.4977
Therefore,
x = 23.50 years
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Suppose that tan(theta)=-1/3 and pi/2
Find the exact values of sin (theta/2) and
tan(theta/2)
Answers
To find the exact values of sin(theta/2) and tan(theta/2), we can use the double angle formulas for sine and tangent. The double angle formulas are:
sin(theta/2) = √[(1-cos(theta))/2]
tan(theta/2) = sin(theta)/(1+cos(theta))
We are given that tan(theta) = -1/3. Using the Pythagorean identity, we can find the value of cos(theta):
tan^2(theta) = 1/9
1 + tan^2(theta) = 1 + 1/9 = 10/9
sec^2(theta) = 10/9
sec(theta) = √(10/9) = √10/3
cos(theta) = 1/sec(theta) = 3/√10 = 3√10/10
Now we can plug in the value of cos(theta) into the double angle formulas to find sin(theta/2) and tan(theta/2):
sin(theta/2) = √[(1-(3√10/10))/2] = √[(10-3√10)/20] = √[(10-3√10)]/√20
tan(theta/2) = (-1/3)/(1+(3√10/10)) = (-10/3)/(10+3√10) = (-10)/(10+3√10)
Therefore, the exact values of sin(theta/2) and tan(theta/2) are:
sin(theta/2) = √[(10-3√10)]/√20
tan(theta/2) = (-10)/(10+3√10)
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Which of these statements describe properties of parallelograms? Check all
that apply.
Answers
Answer: The ones you have selected are correct
Step-by-step explanation:
Answer:
the ones you selected are all correct
Step-by-step explanation:
Consider the boundary value problem y′′ −y = 0 y(0) = 0 y(2) =
e2 −e−2 (a) Find the exact solution y(t). (b) Let tn = nh ( n = 0,
1, 2, 3, 4 ) with the step size h = 1/2 . Use the three-poin
Answers
The approximate solution using the three-point formula with step size h = 1/2 is y(t) = 0 for all t.
The boundary value problem given is y′′ − y = 0 with boundary conditions y(0) = 0 and y(2) = e2 − e−2.
(a) To find the exact solution y(t), we can use the characteristic equation r^2 - 1 = 0. This gives us r = 1 and r = -1. The general solution is therefore y(t) = c1e^t + c2e^-t.
Using the boundary conditions, we can find the constants c1 and c2.
For y(0) = 0, we have 0 = c1 + c2, which gives us c2 = -c1.
For y(2) = e2 − e−2, we have e2 − e−2 = c1e^2 + c2e^-2. Substituting c2 = -c1, we get e2 − e−2 = c1e^2 - c1e^-2.
Solving for c1, we get c1 = (e2 − e−2)/(e^2 - e^-2) = 1/2. Therefore, c2 = -1/2.
The exact solution is y(t) = (1/2)e^t - (1/2)e^-t.
(b) To use the three-point formula with step size h = 1/2, we can set up a table with tn and yn values.
tn | yn
---|---
0 | 0
1/2| y1
1 | y2
3/2| y3
2 | e2 - e-2
The three-point formula is yn+1 = yn-1 + 2h(y′n). We can use this formula to find the values of y1, y2, and y3.
For y1, we have y1 = 0 + 2(1/2)(y′0) = y′0. Since y′0 = y′(0) = (1/2)e^0 - (1/2)e^0 = 0, we have y1 = 0.
For y2, we have y2 = y0 + 2(1/2)(y′1) = 0 + 2(1/2)(0) = 0.
For y3, we have y3 = y1 + 2(1/2)(y′2) = 0 + 2(1/2)(0) = 0.
Therefore, the approximate solution using the three-point formula with step size h = 1/2 is y(t) = 0 for all t.
It is important to note that the three-point formula is not accurate for this particular boundary value problem due to the size of the step and the nature of the differential equation. A smaller step size or a different numerical method may yield a more accurate approximation.
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