Answer:
0.477 Hz
2.09 s
Explanation:
y = A sin(ωx − φ)
A is the amplitude, ω is the angular frequency, and φ is the phase shift.
ω = 3 rad/s
f = ω / 2π ≈ 0.477 Hz
T = 1/f ≈ 2.09 s
An object weighing 150 N and is suspended from the ceiling by a wire. What is the tension in the cord?
Answer:
150NExplanation:
According to newton's third law of motion, Action and reaction are equal and opposite, hence for an object that weighs 150N suspended by a wire, the tension on the wire is 150N
Ultimately the tension on a string or an object is equal to the mass times gravity(which is same as the weight of the object)
Answer:
its 150
Explanation:
Fill in the blanks in the following statements:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_____light years.
3. The more distant a star, the_____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is_____.
5. The closest stars have parallaxes smaller than______arcsecond.
6. The first successful measurements of stellar parallax were made by______in year______for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is______times______then star Bob.
Answer:
Explanation:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_TWO____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_3.3____light years
3. The more distant a star, the_LESS ____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is__TRUE .___.
5. The closest stars have parallaxes smaller than_.002 _____arcsecond.
6. The first successful measurements of stellar parallax were made by_Friedrich Bessel_____in year_1838_____for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is__4____times_nearer_____than star Bob.
You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a point directly under the goal post is 72° and the blimp will be directly above the 50 yard line. a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line? b. How high above the ground is the blimp? c. In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement? If not, what possible angle of elevation could we use? d. What is the exact angle if the blimp is at 150 feet?
Answer:
a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°
Explanation:
Given the following ;
From the triangle sketch :
Base length = 50 yards
Angle of elevation = 72°
a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?
Using trigonometry :
The height of the blimp will be calculated using :
Tangent :
Tan θ = opposite / Adjacent
B.) How high above the ground is the blimp?
Using :
Tan θ = opposite / Adjacent
Θ = 72° ; adjacent = 52, opposite = height(h)
Tan 72° = h / 50
h = 3.0776835 * 50
h = 153.88 yds
C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?
1 yard = 3 Feets
153.88 yards = 3 * 153.88
= 461.65 feets
No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.
To make viewing possible, the angle of elevation should be:
50 yards is equivalent to (3 * 50) = 150 feets
Max imum Height of blimp = 150 Feets
From pythagoras ;
Tanθ = 150 Feets / 150 Feets
Tanθ = 1
θ = tan^-1(1)
θ = 45°
To make viewing advertisement possible, angle of elevation should not exceed 45°
d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°
Which refers to the rate of change in velocity?
O speed
O acceleration
O direction
O magnitude
Answer:
acceleration is the answer
Answer:
Acceleration
Explanation:
1. The electric field strength between two parallel plates separated by 6.00 cm is 7.50 × 104 V/m . (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?
Answer:
a)4500V
b)750V
Explanation:
Given:
Distance between the plate=
6.00 cm
We need to convert to m
Then the Distance between the plate=
0.06m
electric field strength between two parallel plates =
7.50 × 104 V/m .
Then E= 7.50 × 104 V/m .
(a) What is the potential difference between the plates?
potential difference between the plates can be calculated using the formula below
Δ Vab=ED
Where E is the given electric field strength
D= The Distance between the plate
ΔVab=7.50 × 10⁴V/m ×
0.06m
= 4500V
(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?
the potential 1cm from the zero volt plate
Then the 1cm must be converted to m
= 0.01m
Let us say plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (4500V).
Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also
If the plate with Lowest potential is taken to be zero then
=ΔVab=Vab-Vb=Va-0=Va=ED
Va=7.50 × 10⁴V/m × 0.01=750V
a 6 letter word a way of explaining an object or event using a set of facts
Explanation:
A theory is a way of explaining an object or event using a set of facts.
3.27 moles of an ideal gas has a pressure of 125000 Pa at 15.0 ° C What is the volume of the gas?
Answer:
15.96 m³ (corrected to 2 d.p.)
Explanation:
Using idea gas law:
pV = nRT
pressure p = 125000 Pa
volume V = unknown
no. of moles n= 3.27 moles
ideal gas constant R = 8.3145 J K−1 mol−1
Temperature t (in Kelvins) = 15 + 273.15 = 288.15K
125000 x v = 3.27 x 8.3145 x 288.15
v = 15.96 m³ (corrected to 2 d.p.)
Answer:
0.0626 m^3
Explanation:
First, we know that the equation to calculate the behavior of gases is:
PV=nRT
Looking at the problem, we understand that we are needing to solve for V, which means we need to isolate V to solve for it.
The new equation will look something like this:
V=nRT/P
The last step is to simply plug in the remaining variables:
n=3.27
R=8.31 (that is not given but is a standard number that you will always use for "R"/ the ideal gas constant-it helps to right it down somewhere to reference it if you ever need it!)
P=125000
T=288 (the temp needs to be in degrees K, so take 15.0 degrees c and + 273)
Finally, when you input all of those, you will have something that looks like this:
V=(3.27*8.31*288)/125000
V=0.02608205 m^3
V= 0.0626 m^3 (rounded to 3 sig. figs)
I hope this was helpful and easy to understand!
if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?
Answer:
0.25m/s
Explanation:
m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1
m1*0.50m/s=2m1*v2
V2= m1*0.50m/s÷2m1
V2= 0.25m/s
a) A conductor carrying a current I = 12.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.110 N/m acts on the conductor in the negative y direction. Determine the magnitude of the magnetic field in the region through which the current passes.
Answer:
8.8 mT
Explanation:
Current through the conductor = 12.5 A
Magnetic force per unit length on the wire = 0.110 N/m
Recall that the magnetic force per unit length on a current carrying conductor is in a uniform magnetic field is
[tex]\frac{F}{l}= IBsin\alpha[/tex]
where B is the magnetic field magnitude
[tex]I[/tex] is the current in the conductor
α is the angle the conductor makes with the magnetic field ( since it is perpendicular in this case, α is 90°)
imputing values into the equation, we'll have
0.11 = 12.5 x B x sin 90°
but sin 90° = 1, therefore, we have
0.11 = 12.5B
B = 0.11/12 = 8.8 x 10^-3 T
or rather = 8.8 mT
2. When backing straight or to the right: a. Position your right hand on the back of the passenger seat. b. Grip the steering wheel at the 12 o’clock position with your left hand. c. Move the wheel left or right in the direction in which you want the rear of the vehicle to go. d. All of the above
Answer:
Option d = all of the above.
Explanation:
This question is more of a driving lesson or tutorial Question and not that scientific, it is logical and the "rule" attached to reversing and driving that is operating of vehicles especially cars, trucks and so on.
All the options given in the Question from option 'a' to option 'c' are all correct when driving backwards that is reversing or backing . Driving backward(backing or reversing) is not as easy as during forward (drive mode).
=> " Position your right hand on the back of the passenger seat. Grip the steering wheel at the 12 o’clock position with your left hand"
REASON: FOR BALANCING.
=> " Move the wheel left or right in the direction in which you want the rear of the vehicle to go."
The above, given in the Question are all correct.
When backing straight or to the right, all of the mentioned options are correct and recommended practices are to Position your right hand on the back of the passenger seat. The correct option is option d.
a) Position your right hand on the back of the passenger seat: This is a technique used by some drivers to help them have a better sense of the vehicle's position and reference point while backing up.
b) Grip the steering wheel at the 12 o'clock position with your left hand: This hand position allows for better control and maneuverability of the steering wheel while backing up.
c) Move the wheel left or right in the direction in which you want the rear of the vehicle to go: This is the fundamental principle of steering while backing up. By turning the wheel in the desired direction, you can guide the rear of the vehicle in that direction.
Therefore, These practices can assist in improving control, visibility, and maneuverability while backing up, ensuring a safer and more effective backing maneuver. The correct option is option d.
To know more about the principle of steering:
https://brainly.com/question/29458022
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what is the formula of gravitational force
Answer:
[tex]\displaystyle F_g = \frac{GM_1 m_2}{r^2}[/tex]
[tex]F_g[/tex] is the force.
[tex]G[/tex] is the gravitational constant.
[tex]M_1[/tex] is the mass of one object.
[tex]m_2[/tex] is the mass of the other object.
[tex]r[/tex] is the distance between the two objects.
As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near its center. You have enough wire for 3800 circular turns, and the solenoid must be 1.60 m long and 20.0 cm in diameter. What current will you need to produce the necessary field?
Answer:
Explanation:
Magnetic field = permeability x turn density x current
Magnetic field = 0.22T
turn density = 4150 /1.6 = 2593.75 t/m
permeability : µ = k µ°
µ°= 4 π 10^-7
k = 1
I = 0.22 / 4 π 10^-7 * 2593.75 = 0.22 10^7 /32594 = 67.497 A
can someone proofread my Big freeze theory of the universe? does it make sense?
Answer:
Yes great job it was well written!:)
How will you connect 3 cells each of value 2V to give a total of 3V * Two in parallel with one in series Two in series with one in parallel All in parallel All in series
Answer:
two of them in series with one in parallel
Explanation:
When two or more batteries are connected in
(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is
3V + 2V = 5V
(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.
If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,
(3V + 2V) / 2 =2.5V
Now, from the question.
Since there are three cells each of value 2V.
=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V
=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e
(4V + 2V) / 2 = 6 / 2 = 3V
Therefore, to have a total of 3V from three cells each of 2V, we need to connect two of them in series with one in parallel
What is the wavelength of the following waves?
Answer:
i. the wavelength is 7.2 m
ii. the wavelength is 2.4 m
Explanation:
the wavelength of a wave is from crest to crest or from trough to trough.
A piano has a mass of 99 kg. What is the weight of the piano?
A. 1030 N
B. 842 N
C. 1129 N
D. 970 N
Help!!
Answer:
[tex]D.\ 970\ N[/tex]
Explanation:
Given:
Mass of Piano: 99kg
Required:
Calculate its weight
The weight of an object is calculate as thus;
[tex]Weight = Mass\ (m) * Acceleration\ due\ to\ gravity\ (g)[/tex]
[tex]m = 99kg[/tex] and [tex]g = 9.8m/s^2[/tex]
The formula becomes
[tex]Weight = 99kg * 9.8m/s^2[/tex]
[tex]Weight = 970.2\ kgm/s^2[/tex]
[tex]Weight = 970.2\ N[/tex]
[tex]Weight = 970\ N[/tex] Approximated
Hence, the weight of the piano is 970N
A leopard chasing a deer reaches a constant speed of 75m / s. In How long does 1200m travel?
Answer:
16 seconds
Explanation:
To do this you would set up the equation 75x=1200. Then you would divide 75 from both sides so you get x=16 or it takes 12 seconds for it to travel 1200 meters
Answer:
Time = 16 s
Explanation:
Distance =Speed x Time
1200 = 75 x time
Time = 1200/75 = 16 sec
Signal propagation in the nervous system can be modeled as
a) A resistor network.
b) A wave of electricity that travels down conducting tissue.
c) A series of RC circuits.
Answer:
c) A series of RC circuits.
find the molecular formula of the following
Answer: hello i am a hacker
Explanation:
magnesium sulphate=(24*1)+(32*1)+(16*4)=120 water=H2O=(1*2)+(1*16)=18 carbon dioxide=CO2=(12*1)+(16*2)=44 ammonia=NH3=(14*1)+(1*3)=17 alminiumsulphate=AL2(SO4)3=(26*2)+(32*3)+(12*16)=340 hydrogen peroxide=H2O2=(1*2)+(16*2)=34 zinc sulphate=ZNSO4=(65*1)+(32*1)+(16*4)=161
8. You have two iron rods which are identical in appearance, but one is a permanent magnet and the other is unmagnetized. What series of simple experiments can you perform, using only the two rods, which will allow you to determine which of the rods is the permanent magnet
Answer:
Explanation: Let assume that bars are labeled A and B
Method 1
Using just the identical appearing bar magnet and unmagnetized iron bar.
Place the end of bar A in the middle of bar B.
If bar A sticks to bar B, then bar A is the magnet and bar B the umagnetized iron bar.
If bar A jumps to one of the ends of bar B, then bar B is the magnet.
Reason been that the magnetic field on a bar magnet is greatest at the two poles where the field comes out of the magnet. The center, between the poles, will be the weakest part of the field.
Method 2
Another solution would be to separate the two by quite some distance, float them on a piece of cork/wood in a plastic bucket or suspend them from long strings, then see which one consistently (eventually) lines up tending towards the Earth’s magnetic field.
1. Chanice drives her scooter 7 kilometres north. She stops for lunch and then drives 5 kilometres east. What distance did she cover? What was her displacement?
Answer:
i. Distance covered is 12 kilometres.
ii. Her displacement is 8.6 kilometres.
Explanation:
Distance is a span of length between two points, while displacement is the distance moved in a specified direction. Distance is a scalar quantity, while displacement is a vector.
She drives 7 kilometres north, then 5 kilometres east later.
i. Distance covered = 5 + 7
= 12
Her distance covered is 12 kilometres.
ii. To determine her displacement, apply the Pythagoras rule to the sketch of her journey.
[tex]x^{2}[/tex] = [tex]5^{2}[/tex] + [tex]7^{2}[/tex]
= 25 + 49
= 74
x = [tex]\sqrt{74}[/tex]
= 8.6023
Thus, her displacement is 8.6 kilometres.
In a given chemical reaction the time energy of the products is less than the energy of the reactants which statements is true for this chemical reaction
Answer:
Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.
Explanation:
The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat
Hope this helps...
Have a nice day!!!!
calculate the energy dissipated by an electric iron which draws a current of 5A from a240v power supply for 25minutes
Explanation:
Given,
I = 5 A
V = 240 V
T = 25 mins = 1500 sec
Now,
Energy dissipated = IVT= 5×240×1500 = 1800000 J
can someone plz go help me answer my question? I have to ask twice bc no one answered it the first time. a figure skater can increase her spin rotation rate from an initial rate of 1.0 rev every 1.5s to a final rate of 2.5rev/s. If her initial moment of inertia was 4.6kgxm^2, what is her final moment of inertia?
Answer:
1.2 kg m²
Explanation:
Angular momentum is conserved:
L = L
Iω = Iω
(4.6 kg m²) (1.0 rev / 1.5 s) = I (2.5 rev/s)
I = 1.2 kg m²
A classroom measures 3 m X 4m x 6 m.
Calculate the volume of air in the room. Give your answer in
a
cubic metres (mº).
Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground. Use the formula h(t)=−16t2+v0t+h0, where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?
Answer:
The time it will take for the object to hit the ground will be 4.
Explanation:
You have:
h(t)=−16t²+v0*t+h0
Being v0 the initial velocity (54 ft/s) and h0 the initial height (40 ft) and replacing you get:
h(t)=−16t²+54*t+40
To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:
0=−16t²+54*t+40
Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:
[tex]\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}[/tex]
In this case you have that:
a=-16b= 54c= 40Replacing in the expression of the calculation of roots you get:
[tex]\frac{-54+\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}[/tex] Expresion (A)
and
[tex]\frac{-54-\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}[/tex] Expresion (B)
Solving the Expresion (A):
[tex]\frac{-54+\sqrt{5476 } }{2*(-16)}= \frac{-54+74}{2*(-16)}=\frac{20}{2*(-16)}=\frac{20}{-32}= -\frac{5}{8}[/tex]
Solving the Expresion (B):
[tex]\frac{-54-\sqrt{5476 } }{2*(-16)}= \frac{-54-74}{2*(-16)}=\frac{-128}{2*(-16)}=\frac{-128}{-32}= 4[/tex]
These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then the time it will take for the object to hit the ground will be 4.
Answer:
4 seconds
Explanation:
i checked on the test and the other person was right give them brainliest
Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0 X 1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what is the charge of sphere A
Answer:
Charge that will be left on sphere A is -8 x 10^-8 C
Explanation:
Number of electrons = 1.0 x 10^12 electrons
charge on an electron is = -1.6 × 10^-19 coulombs
for the number of electron, total charge = (1.0 x 10^12) x (-1.6 × 10^-19)
==> -1.6 x 10^-7 C
Since the two spheres were in contact when the charge was added to one of the spheres A, the sphere will then be distributed between the two spheres A and B equally. This means that after separation, sphere A will be left with
==> (-1.6 x 10^-7 C) ÷ 2 = -8 x 10^-8 C
How much work is done when 0.0042 C is moved through a potential difference of 12.0 V? Use W = qV A. 0.050 J B. 0.00035 J C. 2900 J D. 12 J
Answer:
Work done by charge (W) = 0.050 (Approx)
Explanation:
Given:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
Work done by charge (W) = 0.050 (Approx)
Answer:
Work done by charge (W) = 0.050 (Approx)
Explanation:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
Work done by charge (W) = 0.050 (Approx)
Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.
Answer:
The work done by Joel is greater than the work done by Jerry.
Explanation:
Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:
[tex]W = F\cdot \Delta s[/tex]
Where:
[tex]W[/tex] - Work, measured in joules.
[tex]F[/tex] - Force exerted on the object, measured in newtons.
[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.
During the first 10 minutes, the net work exerted on the object is zero. That is:
[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]
[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]
[tex]W_{net} = (F-F)\cdot \Delta s[/tex]
[tex]W_{net} = 0\cdot \Delta s[/tex]
[tex]W_{net} = 0\,J[/tex]
In exchange, the net work in the next 5 minutes is the work done by Joel on the object:
[tex]W_{net} = W_{Joel}[/tex]
[tex]W_{net} = F\cdot \Delta s[/tex]
Hence, the work done by Joel is greater than the work done by Jerry.
Can anyone tell me how to read a micrometer screw gauge I want very clear instructions.
Explanation:
Things you need to know:
Accuracy refers to the maximum error encountered when a particular observation is made.
Error in measurement is normally one-half the magnitude of the smallest scale reading.
Because one has to align one end of the rule or device to the starting point of the measurement, the appropriate error is thus twice that of the smallest scale reading.
Error is usually expressed in at most 1 or 2 significant figures.
Tape
Equipment: It is made up of a long flexible tape and can measure objects or places up to 10 – 50 m in length. It has markings similar to that of the rigid rule. The smallest marking could be as small as 0.1 cm or could be as large as 0.5 cm or even 1 cm.
How to use: The zero-mark of the measuring tape is first aligned flat to one end of the object and the tape is stretched taut to the other end, the reading is taken where the other end of the object meets the tape.
Ruler
Equipment: It is made up of a long rigid piece of wood or steel and can measure objects up to 100 cm in length. The smallest marking is usually 0.1 cm.
How to use: The zero-end of the rule is first aligned flat with one end of the object and the reading is taken where the other end of the object meets the rule.
Vernier Caliper
Equipment: It is made up of a main scale and a vernier scale and can usually measure objects up to 15 cm in length. The smallest marking is usually 0.1 cm on the main scale.
It has:
a pair of external jaws to measure external diameters
a pair of internal jaws to measure internal diameters
a long rod to measure depths
How to use: The jaws are first closed to find any zero errors. The jaws are then opened to fit the object firmly and the reading is then taken.
Micrometer Screw Gauge
Equipment: It is made up of a main scale and a thimble scale and can measure objects up to 5 cm in length. The smallest marking is usually 1 mm on the main scale (sleeve) and 0.01 mm on the thimble scale (thimble). The thimble has a total of 50 markings representing 0.50 mm.
It has:
an anvil and a spindle to hold the object
a ratchet on the thimble for accurate tightening (prevent over-tightening)
How to use: The spindle is first closed on the anvil to find any zero errors ( use the ratchet for careful tightening). The spindle is then opened to fit the object firmly (use the ratchet for careful tightening) and the reading is then taken.