If the diameter of the space station is 770 m, how many revolutions per minute are needed for the "artificial gravity" acceleration to be 9.80m/s^2 ?

Answers

Answer 1

Revolutions per minute are needed for the space station which is at 385m from center of the planet is 1.52 rev/min

What is Orbital Velocity ?

Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet.

Orbital velocity is given by,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex] where  G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²

                               M = Mass of the planet

                               R = Radius of the planet

                                h = height of the object(satellite)

Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).

Given,

Diameter of space station, D = 770m {Radius (R+h) = 385m}

Acceleration due to gravity [tex]g_{h}[/tex]= 9.8 m/s²

our given equation is,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex]

[tex]v_{c}^{2} = \frac{GM}{R+h}}[/tex].........1)

we know that v=rω

v²=r²ω²

where r = (R+h) = Radius of planet + height of space station from surface of the planet.

v²=(R+h)²ω²......2)

with equation 2), equation 1 becomes.

(R+h)²ω² = [tex]\frac{GM}{R+h}}[/tex]

ω² = GM÷ (R+h)³.............3)

we know that [tex]g_{h} = \frac{GM}{(R+h)^{2} }[/tex].....4)

equ 3 becomes,

ω² = [tex]\frac{g_{h}}{(R+h)}[/tex]

Putting all values in equation,

ω² = 9.8 ÷ 385

ω² = 0.025454

ω = 0.1595 ≅ 0.16 rad/s

let,

ω = 2πn

n= ω ÷ 2π

n = 0.02547 rev/s

n= 0.02547*60 = 1.52 rev/min

Hence 1.52 rev/min is needed for space station at artificial gravity of 9.8 m/s

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Related Questions

To lift a box 5m in 10s, 250W of power are produced. How much force was applied?

Answers

quiero una resolución para acer esto mandame un foto

What is the time if the velocity is 294 ft/s and the acceleration is 22 ft/s²? ​

Answers

If the velocity is 294 ft/s and the acceleration is 22 ft/[tex]s^{2}[/tex], the time will be 13.36 s.

Given,

Final velocity, v = 294 ft/s

acceleration, a = 22 ft/[tex]s^{2}[/tex]

According to the first equation of motion

v = u + at

Where u = initial velocity

and t = time

To find out time (t) we will use the first equation of motion as

v = u + at

or, t = [tex]\frac{v-u}{a}[/tex]

where u = 0 ft/s

So, t = [tex]\frac{294-0}{22}[/tex]

= 13.36 s

Hence, the time will be 13.36 s.

Question 17 of 25
Which two phrases describe critical thinking skills used in the pursuit of
science?
A. Concluding that one comet is more interesting than another
comet
B. Analyzing observations of a comet's velocity to estimate when it
will pass by the Sun again
OC. Gathering people's opinions about the historical impacts that
comet appearances had on society
D. Evaluating whether research into comets should be funded by the
government
E. Writing detailed descriptions of a comet's appearance as seen
through a telescope

Answers

The two phrases that describe the critical thinking skills used in the pursuit of science are options B and E. Analyzing  observations of a comet's velocity to estimate when it will pass by the sun again and writing detailed description of comet.

What is critical thinking skill?

Critical thinking skills are very important in scientific investigations and data interpretations. Thinking on an observation or scientific backgrounds of a phenomenon and solving complex problems and sorting it eventually leads to the accurate conclusions for the problem.

Here, the estimation of velocity of a comet for its passage around sun will involve critical thinking and use of some theoretical knowledge as well. Gathering of people's opinion or searching history or for fund does nor need any critical thinking.

Making a description of comet through he observation by telescope also need some critical thinking. Therefore, options B and E are correct.

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PLEASE HELP ME THIS IS FOR GYM! YOU WILL MAKE MY DAY FOR WHOEVER DOES THIS.

In a three (3) page, double spaced, typed paper, discuss why cardiovascular fitness and flexibility are important factors in maintaining a healthy lifestyle. In this assignment, define cardiovascular fitness and flexibility. Research two (2) cardiovascular fitness activities and explain why these activities are important in maintaining good health. Finally, discuss in detail several flexibility exercises a person should complete before engaging in physical activity.

Answers

Cardiovascular fitness and flexibility are both important factors in maintaining a healthy lifestyle because they contribute to overall physical health and well-being.

Why are  cardiovascular fitness and flexibility important factors in maintaining a healthy lifestyle?

Cardiovascular fitness refers to the ability of the heart, lungs, and circulatory system to deliver oxygen-rich blood to the body's tissues during physical activity. Regular cardiovascular exercise, such as running, swimming, or cycling, can improve heart health, lower blood pressure, reduce the risk of heart disease, and improve overall fitness and endurance.

In combination, cardiovascular fitness and flexibility can provide a foundation for good physical health, allowing individuals to engage in a wide range of physical activities and enjoy an active lifestyle. Regular exercise that includes both cardiovascular fitness and flexibility can also help improve mental health and reduce the risk of chronic diseases, such as obesity, type 2 diabetes, and some forms of cancer. Overall, maintaining good cardiovascular fitness and flexibility is an important part of a healthy lifestyle.

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Observing a set of pith balls with positive charges, how does the distance between the pith balls affect the electric electrical charge?

Answers

The electrical force between two charged objects decreases as the distance between them increases. This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases. Therefore, the electrical charge on each pith ball is not affected by the distance between them. The charge on each pith ball will remain the same regardless of the distance between them. However, the electrical force between the pith balls will be weaker at greater distances, and stronger at smaller distances.

Answer:

i'm pretty sure what the other guy means is:

The greater the distance between the pith balls, the lesser the amount of electric charge that exists between them.

Explanation:

"This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases"

URGENT HELP NEEDED!!!
Two train cars are moving towards each other. The loaded car has a mass of 134,000 kg, and is moving north at a speed of 2.9 m/s. The unloaded car has a mass of 22,600 kg, and is moving south at a speed of 0.8 m/s. When the cars collide, they lock together, and move as a single unit. What is the velocity of the cars after they join together?

2.4 m/s north

2.1 m/s north

2.4 m/s south

2.1 m/s south

Answers

To solve this problem, we need to apply the principle of conservation of momentum, which states that the total momentum of a system remains constant if there is no external force acting on it.

The initial momentum of the loaded car moving north is:

p1 = m1 * v1 = 134,000 kg * 2.9 m/s = 388,600 kg*m/s (north)

The initial momentum of the unloaded car moving south is:

p2 = m2 * v2 = 22,600 kg * (-0.8 m/s) = -18,080 kg*m/s (south)

Note that we have used a negative velocity for the unloaded car, as it is moving in the opposite direction to the positive direction we have chosen (north).

When the cars collide, they lock together and move as a single unit. The final momentum of the joined cars is:

p = (m1 + m2) * v

where v is the final velocity of the joined cars.

Since the momentum is conserved, we can set the initial and final momenta equal:

p1 + p2 = (m1 + m2) * v

Substituting the values we have calculated:

388,600 kgm/s - 18,080 kgm/s = (134,000 kg + 22,600 kg) * v

370,520 kg*m/s = 156,600 kg * v

v = 2.366 m/s (north)

Therefore, the velocity of the cars after they join together is 2.4m/s north.

Note that this answer is between the initial velocities of the two cars, which makes sense since the collision causes the cars to slow down and move together in the north direction.

Find the total equivalent resistance for the circuit. Req = [?] 2 9.0 V 30 Ω www 40 Ω www 50 Ω Enter 20Ω 10Ω​

Answers

The total equivalent resistance for the circuit is 35.89 Ω

How do i determine the total equivalent resistance?

First, we shall determine the equivalence resistance between 30 Ω and 40 Ω. Details below:

Resistor 1 (R₁) = 30 Ω Resistor 2 (R₂) = 40 ΩEquivalent (R) = ?

R = (R₁ × R₂) / (R₁ + R₂)

R = (30 × 40) / (30 + 40)

R = 17.14 Ω

Next, we shall determine the equivalence resistance between 20 Ω and 10 Ω. Details below:

Resistor 1 (R₁) = 20 Ω Resistor 2 (R₂) = 10 ΩEquivalent (R) = ?

R = R₁ + R₂

R = 20 + 10

R = 30 Ω

Next, we shall determine the equivalence resistance between 50 Ω and the equivalence of 20 Ω and 10 Ω (i.e 30 Ω). Details below:

Resistor 1 (R₁) = 50 Ω Resistor 2 (R₂) = 30 ΩEquivalent (R) = ?

R = (R₁ × R₂) / (R₁ + R₂)

R = (50 × 30) / (50 + 30)

R = 18.75 Ω

Finally, we shall determine the total equivalent resistance for the circuit. Details below:

Equivalence resistance between 30 Ω and 40 Ω = 17.14 ΩEquivalence resistance between 50 Ω and the equivalence of 20 Ω and 10 Ω = 18.75 ΩTotal equivalent resistance =?

Total equivalent resistance = 17.14 + 18.75

Total equivalent resistance = 35.89 Ω

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A 75.0 kg ladder that is 3.00 m long is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.20 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.800. There is no friction between the wall and the ladder. What is the vertical force of the ground on the ladder?

Answers

The vertical force is given as 735.75 N

How to solve for the vertical force

Given that there is no friction existing between the wall and the ladder, we would have

w - n = 0

w is the weight of thios ladder

while N is the vertical force that acts on it

n = w

the formula for n = mg

this is mass of ladder * the gravitational constant

= 75.0 kg ladder * 9.81

= 735.75 N

written as substituting the weight of the ladder, W = 75.0 kg * 9.81 m/s^2 = 735.75 N

Therefore the vertical force is givem as 735.75 N

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Baliz help meh

The level of education that a state’s population attains directly impacts the economy. Identify which economic consequence matches which level of education.
well-paying jobs

Answers

The economic consequence matches which level of education are :

Well paying jobs - High School diploma or higher Higher tax revenues - High School diploma or higher Increased purchasing power - High School diploma or higher Failure of local businesses  - High School dropout or lower More social assistance programs - High School dropout or lower Less tax collected - High School dropout or lower

What are the economic consequences of education ?

Studies have shown that individuals with a high school diploma or higher tend to have higher incomes and greater access to well-paying jobs, which can lead to increased purchasing power and higher tax revenues for their local communities.

In contrast, individuals who have not completed high school may be more likely to struggle with unemployment or low-paying jobs, which can lead to a greater need for social assistance programs and less tax collected by local governments.

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A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
a. How much work does he do on the wall? ____________
b. How much energy is used?__________
c. How much power is exerted?____________

Answers

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

What is force?

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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A positive point charge Q1
= 2.8×10−5 C
is fixed at the origin of coordinates, and a negative point charge Q2
= −5.4×10−6 C
is fixed to the x
axis at x=+2.0m.

Find the location of the place along the x
axis where the electric field due to these two charges is zero.

Answers

The x-axis point 2.202 m to the right of the origin is where the electric field caused by the two charges is zero.

A positive point charge is what?

A positive line charge with a uniform density is separated by r0 from a positive point charge that has been released from rest. The speed v of the point charge is proportional to A as a function of the instantaneous separation r from the line charge (rr0)

The electric field caused by Q1 at a position along the x-axis is given by:

E1 = kQ1/x^2

Similar to that, the electric field caused by Q2 at a point on the x-axis is given by:

E2 = kQ2/(x - 2)^2

As a result, we must determine the value of x where:

E1 + E2 = 0

The result of substituting the values of E1 and E2 is:

kQ1/x^2 + kQ2/(x - 2)^2 = 0

Simplifying the equation, we get:

Q1/(4πε0x^2) + Q2/(4πε0(x - 2)^2) = 0

where ε0 is the permittivity of free space.

Substituting the given values of Q1 and Q2, we get:

(2.8×10−5)/(4πε0x^2) - (5.4×10−6)/(4πε0(x - 2)^2) = 0

Multiplying both sides by (4πε0x^2(x - 2)^2), we get:

(2.8×10−5)(x - 2)^2 - (5.4×10−6)x^2 = 0

Expanding the equation and simplifying, we get a quadratic equation in x:

2.8×10−5x^2 - 1.12×10−4x + 6.48×10−6 = 0

Solving this quadratic equation using the quadratic formula, we get:

x = 0.064 m or x = 2.202 m

The null point must be to the right of the positive point charge because the positive point charge is fixed at the origin. Hence, the null point is at x = 2.202 m.

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A cyclist starts from rest and coasts down a 4.5 degree hill. The mass of the cyclist plus bicycle is 80 kg. The cyclist has traveled 260 m.

a) What was the net work done by gravity on the cyclist? (in J)
Express your answer using two significant figures.

b) How fast is the cyclist going? Ignore air resistance. (m/s)
Express your answer using two significant figures.

Answers

a) The net work done by gravity on the cyclist is equal to the change in the kinetic energy of the cyclist-bicycle system. Since the cyclist starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the equation:

KE = (1/2)mv^2

where m is the mass of the cyclist-bicycle system and v is the final velocity of the cyclist.

The work-energy principle states that the net work done on an object is equal to its change in kinetic energy:

W_net = KE_final - KE_initial

Since the initial kinetic energy is zero, the net work done by gravity on the cyclist is equal to the final kinetic energy:

W_net = (1/2)mv^2

To calculate the final velocity, we can use the conservation of energy principle, which states that the total mechanical energy of a system is conserved:

E_i = E_f

where E_i is the initial mechanical energy and E_f is the final mechanical energy. Since the cyclist starts from rest, the initial mechanical energy is equal to the gravitational potential energy:

E_i = mgh

where h is the vertical distance the cyclist travels down the hill. We can use trigonometry to calculate the vertical distance:

h = d*sin(theta)

where d is the distance the cyclist travels and theta is the angle of the hill in radians.

Plugging in the given values:

h = 260sin(4.5pi/180) = 20.05 m

Therefore, the initial mechanical energy is:

E_i = (80 kg)(9.81 m/s^2)(20.05 m) = 15742 J

Since there is no non-conservative work done on the system, the final mechanical energy is equal to the initial mechanical energy:

E_f = E_i = 15742 J

The final mechanical energy can also be expressed as the sum of the final kinetic and potential energies:

E_f = (1/2)mv^2 + mgh

Plugging in the known values and solving for v:

(1/2)(80 kg)v^2 = 15742 J - (80 kg)(9.81 m/s^2)(20.05 m)

v = sqrt[(2(15742 J - 15686 J))/80 kg] = 7.0 m/s

Therefore, the net work done by gravity on the cyclist is:

W_net = (1/2)(80 kg)(7.0 m/s)^2 = 1960 J (to two significant figures)

b) The final velocity of the cyclist is 7.0 m/s, as calculated in part a).

A 5.3-cm -thick layer of oil (n=1.46) is sandwiched between a 1.5-cm -thick sheet of glass and a 2.3-cm -thick sheet of polystyrene plastic (n=1.59). How long (in ns ) does it take light incident perpendicular to the glass to pass through this 9.1- cm -thick sandwich?

Answers

Time taken to incident light perpendicular to glass to pass through this 9.1 cm thick sandwich is 0.399 ns.

How long it took to calculate:

Being aware of

Layer thickness / light speed equals the amount of time required.

Also,

V is equal to the product of the sound speed and the refractive index.

Now

T1 = 0.05*1.46/3*10^8 = 2.43*10^-10 s

t2 = 0.01*1.5/3*10^8 = 5*10^-11 s

t3 = 0.02*1.59/3*10^8 = 1.06*10^-10 s

So,

Total time is equal to 2.43*10-10, 5*10-11, and 1.06*10-10 s, or 0.399*10-9 s.

= 0.399 ns

Light Speed:

When a light beam passes through a certain media, its speed in that medium may be determined using the light speed in vacuum and the medium's refractive index. With the use of the medium's light speed, the value of the amount of time needed to travel a particular distance can be determined.

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What’s the right answer for 2

Answers

The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound.

refer to the attachment and answer the question;-;​

Answers

The electric current is of two types, direct current and alternating current. Direct current do not change its direction and amperage with time whereas alternating current change with time.

What are direct current and alternating current?

Direct current (DC) is an electric current which is uni-directional, and so the flow of charge is always in the same direction. As opposed to the alternating current, the direction and amperage of direct currents do not change with time. Direct current is used in many household electronics and in all the devices which use batteries.

Alternating current is an electric current which periodically reverses its direction and change its magnitude continuously with the time in contrast to direct current, which flows only in one direction. The current produced by the generators or turbines is the AC current, as it is the current which is obtained from our home power sockets.

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Infrared observations of a star show that the star is most intense at a wavelength of 800 nm. What is the temperature of the star's surface in K?

Answers

The star's surface has a temperature of about 3622.5 K.

What wavelength does a 6000 K star emit the majority of its radiation?

In comparison to the same thing at a cooler temperature, hotter objects produce more energy at all wavelengths. Even though the peaks of the 4,000 K object are closer to this wavelength, the 6,000 K object produces more energy at this wavelength than the 4,000 K one.

The Wien's displacement law can be used to calculate the star's surface temperature.

λ_max = b/T

Before applying Wien's law, we must convert the supplied wavelength of 800 nm to metres.

800 nm = 800 × 10⁻⁹ m

When the values are added to the formula, we obtain:

λ_max = b/T

800 × 10⁻⁹ m = (2.898 × 10⁻³ m·K) / T

Solving for T, we get:

T = (2.898 × 10⁻³ m·K) / 800 × 10⁻⁹ m

T = 3622.5 K

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The displacement of two interfering light waves are y1=4sinwt and y2=3sin(wt+π/2)The amplitude of the resultant wave is a. 5 b. 7 c. 1 d. 0

Answers

Answer:

Explanation:

Amplitude of first wave a1=4

Amplitude of second wave a2=3

Angle between two waves =Π/2

Resultant amplitude=[tex]\sqrt{a_{1} ^{2}+a_{2} ^{2} +2a_{1} a_{2} cos\alpha }[/tex]

=[tex]\sqrt{4^{2}+3^{2} +2*4*3*cos90 }[/tex]

=5

Answer is a

if five violins sound the same note of 1000Hz, each at the same sound pressure level of 60 dB, what is their total intensity in decibels, compared with the violin alone?

Answers

The total sound pressure level of the five violins is 47 dB, which is 13 dB less than the sound pressure level of a single violin at 60 dB.

What is the total intensity?

The total intensity of the five violins can be found by summing their individual intensities. The intensity of a sound wave is proportional to the square of the sound pressure level, so we can use the following equation:

I = I0 * 10^(L/10)

where;

I0 is the reference intensity (for sound at the threshold of hearing, I0 = 1e-12 W/m^2), L is the sound pressure level in decibels, and I is the intensity in W/m^2.

Since each violin has a sound pressure level of 60 dB, the intensity of each violin can be calculated as follows:

I_violin = I0 * 10^(60/10) = 1e-12 * 1000 = 1e-9 W/m^2

The total intensity of the five violins can then be found by adding the individual intensities:

I_total = 5 * I_violin = 5 * 1e-9 = 5e-9 W/m^2

To find the sound pressure level corresponding to this total intensity, we can use the inverse of the equation above:

L = 10 * log10(I/I0)

L_total = 10 * log10(I_total/I0)

= 10 * log10(5e-9/1e-12)

= 10 * log10(5e3)

= 47 dB

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Calculate the speed (in m/s) a spherical raindrop would achieve falling from 2.70 km with air drag. Take the size across of the drop to be 3 mm, the density to be 1.00 ✕ 10^3 kg/m3, and the surface area to be r^2. (Assume the density of air is 1.21 kg/m^3.)

Please, solve as soon as possible.

Answers

A spherical raindrop would fall from a height of 2.70 km at a speed of 26.22 m/s due to air resistance.

Calculation-

(a) Height from which the raindrop falls, h = 2.70 km = 2700 m

Now,

suppose, m = mass of raindrop

v = speed of raindrop at the ground.

Apply conservation of energy -

1/2 m v^2 = m g h

v = (2 g h)^1/2

  = (2 * 9.8 * 2700)^1/2 = 230.0 m/s (Answer)

(b) In the presence of air drag -

Dynamics

m x" = m g - k x'^2

limit speed is

v = (m g / k)^1/2

where

k = 1/2 ρ A C

ρ = air density = 1.21 kg/m^3

A = area = π r^2 = 3.141 * 0.0015^2 = 7.07 x 10^-6 m^2

C = coefficient of hydraulic resistance [0.47 for a sphere]

m = ρ' V = 1.0 x 10^3 x (4/3)*pi*0.0015^3 = 1.41 x 10^-5 kg

k = 1/2*1.21*7.07x10^-6*0.47

  = 2.01 x 10^-7 kg/m

Therefore,

v = [(1.41 x 10^-5 x 9.8) / (2.01 x 10^-7)]^1/2

  = 26.22 m/s

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A 0.140 kg baseball is pitched toward home plate at 30.0 m/s. The batter hits the ball back (opposite direction) to the pitcher at 44.0 m/s. Assume that towards home plate is positive. If the ball was in contact with the bat for 0.002 seconds, what is the average force the bat exerts on the ball?

−9700 N

−1000 N

−4700 N

−5200 N

Answers

The average force the bat exerts on the ball is -5200 N. This can be calculated using the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum (pf-pi), and Δt is the time interval. In this case, Δp = m * (vf - vi) = 0.14 kg * (44 m/s - 30 m/s) = 5.4 kgm/s, and Δt = 0.002 s. Thus, F = 5.4 kgm/s / 0.002 s = -5200 N.

20 points!!! Emergency help required.
Florence is spinning a 770 g weight tied to a string over her head. The string is 0.94 m long, and the weight is moving with a speed of 4.24 m/s. What is the centripetal force pulling the weight inward?

14.7 N

20.6 N

11.0 N

19.7 N

Answers

The centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.

What is Centripetal Force?

Centripetal force is a force that acts on an object moving in a circular path, directing it toward the center of the circle. In other words, it is the force required to keep an object moving in a circular path, rather than flying off in a straight line. The word "centripetal" comes from the Latin words "centrum", which means "center", and "petere", which means "to seek or aim for".

The centripetal force, which is the force acting on an object moving in a circular path, is given by the formula:

F = m * v^2 / r

where F is the centripetal force, m is the mass of the object, v is its velocity, and r is the radius of the circular path.

In this case, the mass of the weight is 770 g, or 0.77 kg, the velocity is 4.24 m/s, and the radius is 0.94 m.

F = (0.77 kg) * (4.24 m/s)^2 / 0.94 m

F = 19.7 N

Therefore, the centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.V

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Suppose a newly discovered planet has a mass of 7.0 x1024kg and a radius of 5,600
km. What is the gravitational acceleration, g, on this planet, in m/s²?

Answers

Gravitational acceleration on the newly discovered planet is calculated to be approximately 26.7 m/s².

What is gravitational acceleration?

The acceleration of an object in free fall within a vacuum is known as gravitational acceleration.

As we know, g = G * M / r²

G is the gravitational constant (6.67 x 10⁻¹¹  N*m²/kg²)

M is the mass of the planet

r is the radius of the planet

Plugging in the given values, we get:

g = (6.67 x 10⁻¹¹ N*m²/kg²) * (7.0 x 10²⁴ kg) / (5600 km)²

g = (6.67 x 10^⁻¹¹  N*m²/kg²) * (7.0 x 10²⁴  kg) / (5600 x 1000 m)²

g ≈ 26.7 m/s²

Therefore, the gravitational acceleration on the newly discovered planet is approximately 26.7 m/s².

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A general contractor has received plans for a new high-rise hotel in an urban area. The hotel will be 12 stories tall and will have 144 rooms. The contractor is preparing to make a bid on the project. Among the usual specifications for a high-rise building, the plans detail specifications for a friction pile foundation and a glass curtain wall. First, identify the type of construction (residential, commercial, or industrial) and explain why it fits into that category. Next, explain what materials will be needed for each of the specifications in the plan and what workers will be required to install those materials. Finally, identify how carpenters and ironworkers will contribute to the project and what materials they will need to do their jobs.

Answers

Answer:

The type of construction in this case is commercial construction. This is because the hotel will be used for commercial purposes, specifically to provide accommodation to paying guests.

For the friction pile foundation, the materials needed will include concrete and steel. Workers will be required to drill holes into the ground and insert steel reinforcing bars into them. The holes will then be filled with concrete to create a solid foundation. Workers such as concrete pourers, foundation drillers, and steelworkers will be required for this part of the project.

For the glass curtain wall, materials needed will include glass panels, metal framing, and sealant. Workers such as glaziers, metal fabricators, and caulking specialists will be required to install the glass panels and metal framing. The sealant will be used to create a weather-tight seal between the glass panels and the metal framing.

Carpenters will contribute to the project by constructing the interior walls, installing doors and windows, and creating millwork such as cabinets and shelves. They will need materials such as wood, nails, screws, and drywall.

Ironworkers will contribute to the project by erecting the steel framework for the building. They will need materials such as steel beams, bolts, and welding equipment to do their jobs.

Explanation:

Before the coyote begins to fall, what can you tell about the potential and kinetic energy of the roadrunner vs the coyote?

Select all correct responses.

A. Ignoring air resistance and assuming they have the same mass, the kinetic energy of both is equal right before impact with the ground.
B. The potential energy of the one with the most mass is greater than the other.
C. Weight is the same for both, regardless of mass.
D. The potential energy of both are equal.

Answers

Before they begin to fall, the potential energy of the roadrunner and the coyote is the same regardless of their mass. Both the roadrunner and the coyote have zero kinetic energy just before they begin to fall.

What are some illustrations of kinetic and potential energy?

The energy an individual or an object has as a result of motion—in this case, the motion of the falling apple—is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill.

What is the connection between potential difference and kinetic energy?

By virtue of energy conservation, kinetic energy (KE) must be equal to the change in potential energy (qV), or vice versa. The voltage between the plates and the electron's energy are numerically equivalent in electron-volts. A 5000-V potential difference, for instance, results in 5000-eV electrons.

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Which weighs more, a liter of ice or a liter of water?

Answers

Answer:

Water is denser so a liter of water weighs more than a liter of ice

A general contractor has received plans for a new high-rise hotel in an urban area. The hotel will be 12 stories tall and will have 144 rooms. The contractor is preparing to make a bid on the project. Among the usual specifications for a high-rise building, the plans detail specifications for a friction pile foundation and a glass curtain wall. First, identify the type of construction (residential, commercial, or industrial) and explain why it fits into that category. Next, explain what materials will be needed for each of the specifications in the plan and what workers will be required to install those materials. Finally, identify how carpenters and ironworkers will contribute to the project and what materials they will need to do their jobs.

(WILL GIVE BRAINLIEST IF RIGHT)

Answers

Answer:

The type of construction for this project is commercial. This is because the hotel is intended for business purposes, and will generate income for the owners through renting out rooms and other amenities. Commercial construction typically involves larger and more complex projects than residential construction, and often requires specialized expertise in areas such as HVAC, plumbing, and electrical systems.

For the friction pile foundation, materials will include piles, rebar, and concrete. Workers will be required to install the piles and rebar, and pour the concrete to create a stable foundation for the building. Workers may also be required to excavate the site to prepare for the foundation.

For the glass curtain wall, materials will include glass panels, metal framing, and sealant. Workers will be required to install the metal framing and sealant, and then attach the glass panels to create a transparent and aesthetically pleasing exterior for the building.

Carpenters and ironworkers will contribute to the project by installing the structural steel framework for the building, which will support the floors, walls, and roof. Carpenters will also be required to install interior finishes such as doors, trim, and cabinetry. Materials needed for these tasks will include structural steel, wood framing, drywall, and various finishing materials such as paint and flooring. Ironworkers will also be responsible for installing any necessary safety features, such as guardrails or safety nets, to protect workers during construction.

Explanation:

A 5.0 kilogram initially at rest is accelerated by a force of 25 newtons such that it attains 5.0 x 102 joules of kinetic energy. Determine the final speed of the object.

Answers

Answer:

Below

Explanation:

Final Kinetic Energy = 1/2 m v^2

           5 x 10^2 J    = 1/2 ( 5 kg)(v^2 )

                 1000 / 5 = v^2

                     200 = v^2

                         v = 10 sqrt 2      or   14.1 m/s

A projectile is shot up vertically with a velocity of 100ms-1 .How long does it take the projectile to reach a height of 375m?​

Answers

A projectile is shot up vertically with a velocity of  [tex]100ms^-^1[/tex], so the projectile takes approximately 8.66 seconds to reach a height of 375 meters, one can use the equations of motion to calculate the time it takes for a projectile to reach a given height.

       

What is the calculation of the time?

using the equations of motion this will be solved ,

the initial velocity of the projectile is 100 m/s, the acceleration is -g (where g is the acceleration due to gravity, approximately [tex]9.8 m/s^2[/tex]), and the initial displacement is 0 m.

s = ut + 0.5a[tex]t^2[/tex]

t = √(2s/a)

t = √(2 x 375 m / [tex]9.8 m/s^2[/tex])

t = 8.66 s (rounded to two decimal place)

Hence, A projectile is shot up vertically with a velocity of [tex]100ms^-^1[/tex], so the projectile takes approximately 8.66 seconds to reach a height of 375 meters.

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When you are riding a carousel that is turning at a steady rate, you are accelerating. Explain why
there is an acceleration even though the speed of the carousel is steady. What is the direction of this
acceleration? What is the name of this acceleration? What will happen to you if this acceleration
studently disappears as you are going around.

Answers

1) Yes, there is acceleration since the direction is changing

2) The acceleration is towards the center of the carousel

3) It is centripetal acceleration

4) You will fall off.

Is there acceleration when  riding a carousel that is turning at a steady rate?

There is acceleration when riding a carousel that is turning at a steady rate, even though the speed of the carousel remains constant. This is because acceleration is a change in velocity, which includes a change in direction.

When riding a carousel, the direction of motion is constantly changing as the rider moves in a circle, even though the speed remains constant. Therefore, the rider is experiencing acceleration.

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Name 3 different ways of reducing the effect of sound waves.

Answers

Answer:

There are several basic ways to reduce sound: increasing the distance between source and receiver, decoupling, using noise barriers to reflect or absorb the energy of the sound waves, using damping structures such as sound baffles for absorption, or using active antinoise sound generators.

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