How to solve this problem?

Answer:

in simplify this is- 9a2i+42ab+49b2

Step-by-step explanation:

Step-by-step explanation:

6 = b

7 = d

8 = c

9 = a

hope this answer helps you dear...take care and may u have a great day ahead!

Answer:

-10 × -10= 100

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Answer:

Answer is option 2 (as it doesn't contain H)

Step-by-step explanation:

If you like my answer than please mark me brainliest

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The term in the formula which isn't dependent on height is :

no noeeeeeeeeeeeeeeeeed

Answer:

5+2x+x+2=34

7+3x=34

7-7+3x=34-7

3x=27

3x/3=27/3

x=9

5+2x=AS

5+(2*9)=AS

5+18=AS

23=AS

23 units

Step-by-step explanation:

Answer:

15 cups

Step-by-step explanation:

2:3

10:?

2x5:3x5

10:15

Answer:

2

Step-by-step explanation:

12-8/-3-(-5)=4/2

m=4/2

Answer:

Jennifer has the faster training rate.

Step-by-step explanation:

In order to determine the equation that represents the distance, y (in kilometers), that Jennifer traveled in x minutes:

Choose two ordered pairs from the table: (5, 40) and (64, 8).

Let (x1, y1) = (40, 5)

(x2, y2) = (64, 8)

Substitute these values into the slope formula:

m = (y2 - y1)/(x2 - x1)

m = (8 - 5)/(64 -40)

m = 3/24 = 1/8

Therefore, y = 1/8x represents the distance, y (in kilometers), that Jennifer traveled in x minutes.

In order to find out who has the faster training rate, choose one of the given x values from the table, and substitute it into Patrick's and Jennifer's equations:

Let x = 40:

Patrick:

y = 1/9x

y = 1/9(40)

y = 4.44 km  ⇒ This represents the distance that Patrick traveled in 40 minutes.

In contrast, Jennifer traveled for 5 kilometers in 40 minutes (according to the given table). She reached a farther distance than Patrick, given their training time of 40 minutes.

Therefore, Jennifer has the faster training rate.

Using the principle of common difference , we can observe that the distance moved per roll increases by a constant amount of centimeters . Hence, the distance moved in the 5th roll is 180 cm

Setting up a proportional relationship :

The common difference between each roll can be obtained thus :

d2 - d1 = d3 - d2 = d4 - d3

60 - 20 = 100 - 60 = 140 - 100

40 = 40 = 40

Hence, the common difference = 40

The distance obtained on the fifth roll :

d(5) = d(4) + common difference

d(5) = 140 + 40

d(5) = 180

Therefore, the distance obtained on the fifth roll is 180 cm

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Answer:

79m

Step-by-step explanation:

344-(93x2)=158

158/2=79m

Step-by-step explanation:

perimeter = 344

length = 93

perimeter of rectangle = 2( l+ b )

344 = 2 (93 + b)

344÷2 = 93 + b

172 = 93 + b

172 - 93 = b

79 = b

in other words width is 79

hope it helps

Answer:

No.

Step-by-step explanation:

A rational number is a number that can be written in the form a/b, where a and b are integers. A rational number does not have to be written in the form a/b. I just needs to be able to be written in that form.

Can 5 1/3 be written as a fraction of integers?

5 1/3 = 5 + 1/3 = 15/3 + 1/3 = 16/3

5 1/3 = 16/3

16/3 is in the form a/b, where a and b are integers.

Since 5 1/3 can be written as a fraction of integers, it is rational.

Anna is incorrect.

The number of real solutions is 0, the correct answer is A.

Let the quadratic equation given be of the form ax^2 + bx + c = 0, then

The quantity b^2 - 4ac is called its discriminant.

The solution contains the term [tex]\sqrt{b^2 - 4ac}[/tex] which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

There are two roots of a quadratic equations always(assuming existence of complex numbers). We say that the considered quadratic equation has 2 solution if roots are distinct, and have 1 solutions when both roots are same.

We are given that;

The equation -2x^2+x-28= 0

Now,

The discriminant of a quadratic equation ax^2 + bx + c = 0 is given by b^2 - 4ac. The discriminant can be used to determine the number of real solutions of the equation as follows:

If the discriminant is positive, there are two distinct real solutions.

If the discriminant is zero, there is one repeated real solution.

If the discriminant is negative, there are no real solutions.

In this case, the quadratic equation is -2x^2 + x - 28 = 0. Comparing it with the standard form, we can identify that a = -2, b = 1, and c = -28. Therefore, the discriminant is:

b^2 - 4ac

= 1^2 - 4(-2)(-28)

= 1 - 224

= -223

Since, the discriminant is negative, there are no real solutions for this equation.

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Answer:

4 x 3 x 1 = 12

12 = 12

Step-by-step explanation:

I used a calculator, pls let me know if im incorrect

Answer:

8(2x-1)

Step-by-step explanation:

Answer:

A = 4; B = -1 ; C = -29

Step-by-step explanation:

y = 4(x + 6) + 5

y = 4x + 24 +5

y = 4x + 29

Standard form: Ax + By = C

 4x - y = -29  

Answer:

Step-by-step explanation:

Hope this Helps ;)

Answer:

x=0

Step-by-step explanation:

1st Step(Plug in 0 for x):   2(0-3)+9=3(0+1)+x

2nd Step(Simplify):   2*(-3)+9=3*(1)+x

3rd Step(Multiply):   -6+9=3+x

4th Step(Add):   3=3+x

5th Step(Subtract 3 from both sides): x=0

For any questions saying what is the value of x in the equation, just plug in one of the options from a,b,c,d. And work from there

Answer:

3) 7x + 4

6) 4 + 5x

9) 8y

12) 4y

14) 23 + 4x

15) 8x + 14

Step-by-step explanation:

Answer:

a) -8yx-20y

b) -6x ² - 3xy - 16x -2y - 8

Step-by-step explanation:

a) -4y(2x+5) apply multiplicative distribution law

-4y × 2x - 4y × 5 multiply the monomials

-8yx - 20y

b) kinda the same steps like a

:) distributive property btw

hope it helps if you need the steps for b I'll send them in the comment

Answer:

g = 6

Step-by-step explanation:

Step 1: Subtract 3.3g from both sides.

Step 2: Subtract 8 from both sides.

Step 3: Divide both sides by 2.

(hope this helps) :)

Two point three tens times m equals zero point forty six hundredths

The given equation in the form of a statement can be written as Two times of the sum of the t and 4 times of q is equal to the sum of two times of q and  four times of t.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The given equation can be written in the form of an statement as:

Two times of the sum of the t and 4 times of q is equal to the sum of two times of q and  four times of t.

Hence, the given equation in the form of a statement can be written as Two times of the sum of the t and 4 times of q is equal to the sum of two times of q and  four times of t.

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Answer:

A. (4, -4)

Step-by-step explanation:

Equation form x = 4, y = −4

Answer:

Option A

Step-by-step explanation:

5x + 2 y = 12 -----------(I)

5x - 2y = 28 ------------(II)

Add equation (I) & (II). So, y will be eliminated and we will get the value of x

(I)     5x + 2y = 12

(II)     5x -2y  = 28    {Now add}

         10x      =  40

                  x = 40/10

x = 4

Plugin x = 4 in equation (I)

5*4 + 2y = 12

20 + 2y = 12

        2y = 12 - 20

        2y = -8

          y = -8/2

y = -4

Answer:

my brother said it is 5 and 10... but i do not know if it is

Answer: help what?????

Step-by-step explanation:

Answer:

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Step-by-step explanation:

Rahul- 1.54m

Akash- 1500mm

Meera- 152cm

Lakshmi- 1560mm

Let's start by converting all the measurements to meters.

Rahul is already in meters, so he can just stay the same.

1500mm = 1.5m

152cm = 1.52m

1560mm = 1.56m

So our new measurements are:

Rahul- 1.54m

Akash- 1.5m

Meera= 1.52m

Lakshmi= 1.56m

We can now make our conclusions.

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Answer:

Step-by-step explanation:

Let's convert all the heights to meters:

Rahul 1.54m

Akash 1.50 m

Meera 1.52 m

Lakshmi 1.56m

Now, let's arrange their heights in ascending order (shortest to tallest):

Akash 1.50 m

Meera 1.52 m

Rahul 1.54m

Lakshmi 1.56m

a) 1500 mm, 152 cm, 1.54 m, 1560 mm

b) therefore Lakshmi is the tallest.

Answer: x = -11

Step-by-step explanation:

Expand the expression (distributive property): 3 - 9x = -8x + 14

// subtract 14 from both sides = -11

// add 9x on both sides = x

Simplify: x = -11

Answer:

[tex]x=-11[/tex]

Step-by-step explanation:

1) Rearrange Terms

[tex]3(-3x+1)=2(-4x+7)[/tex]

2) Distribute

[tex]-9x+3=2(-4x+7)[/tex]

3) Distribute

[tex]-9x+3=-8x+14[/tex]

4) Subtract 3 from both sides of the equation

[tex]-9x+3-3=-8x+14-3[/tex]

5) Simplify

A. Subtract the numbers

[tex]-9x=-8x+14-3[/tex]

B. Subtract the numbers

[tex]-9x=-8x+11[/tex]

6) Add 8x to both sides of the equation

[tex]-9x+8x=-8x+11+8x[/tex]

7) Simplify

A. Combine like terms

[tex]-x=-8x+11+8x[/tex]

B. Combine like terms

[tex]-x=11[/tex]

8) Divide both sides of the equation by the same term

[tex]\frac{-x}{-1} =\frac{11}{-1}[/tex]

9) Simplify

A. Cancel terms that are in both the numerator and denominator

[tex]x=\frac{11}{-1}[/tex]

B. Divide the numbers

[tex]x=-11[/tex]

Answer:

5)

V= 1,-4

S) x=1

Min= 1,-4

zeros= (-1,0)(3,0)

6)

V= -2,0

S= x=-2

min= -2,0

zeros= -2,0

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]