how many rational number are there between 0 and 5 explain your answer in words​

The solution is, the initial amount that you invested is $1200.

Interest is the price you pay to borrow money or the cost you charge to lend money. Interest is most often reflected as an annual percentage of the amount of a loan. This percentage is known as the interest rate on the loan.

here, we have,

Let the initial amount that you invested be $ x.

We are told that the new balance after investing $500 is $1760.

Thus, the balance you had before the deposit $500 us;

$1760 - $500 = $1260

So, when the amount invested was $x, the balance was $1260.

Since this money earned 5% interest on the amount you initially

Thus;

$1260 = initial deposit + (5% of inital deposit)

Thus;

x + (5% * x) = 1260

x + (0.05x) = 1260

1.05x = 1260

x = 1260/1.05

x = $1200

Hence, The solution is, the initial amount that you invested is $1200.

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The area of the resulting shape is 90 sq meters

The cylinder represents the given parameter

Such that we have the following dimensions

Radius = 6 cm

Height = 15 cm

When the solid cylinder is cut vertically through its center, we have a rectangle with the following dimensions

Length = 6 cm

Width = 15 cm

The area is then calculated as

Area = Length * Width

So, we have

Area = 6 * 15

Evaluate

Area = 90

Hence, the area is 90 square meters

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Answer:

84

Step-by-step explanation:

6.3+16.1=22.4

22.4/2=11.2

11.2x7.5=84

Answer:

78.12 cm^2

Step-by-step explanation:

i will call the 6.3 cm line A, 7.5 line B and 16.1 cm C

first we divide this into two shapes, a rectangle and a triangle

THE RECTANGLE:

the formula to find the area of a rectangle: L x W

A x B

6.3 x 7.5 = 47.25 cm^2

THE TRIANGLE:

this is a right angle triangle

formula to find the area of a right angle triangle: (1/2) x BASE x H

B is parallel to H and share the same length

to find BASE we need to subtract 6.3cm from 16.1cm (check attachment)

16.1 - 6.3 = 9.8

(1/2) x 9.8 x 6.3 = 30.87 cm^2

FINAL VALUE:

now we simply add our two values of area together

30.87 + 47.25 = 78.12 cm^2

Answer: ??

Step-by-step explanation:

Answer:

19/3

Step-by-step explanation:

B

B=G-11 and B+G=28 could be used to solve the problem

The future value of $2000 earning 18% interest, compounded monthly, for 4 years is $6,116.23.

To calculate the future value, we use the formula:

[tex]FV = P(1 + r/n)^{nt}[/tex]

Where:

FV is the future value

P is the principal amount ($2000)

r is the annual interest rate (18%)

n is the number of times the interest is compounded per year (12 for monthly compounding)

t is the number of years (4)

Plugging in these values, we get:

[tex]FV = 2000(1 + 0.18/12)^{12*4}[/tex]

FV = 6116.23

Therefore, the future value of $2000 earning 18% interest compounded monthly for 4 years is approximately $6,116.23. This means that if you invest $2000 today and earn 18% interest compounded monthly for 4 years, your investment will grow to $6,116.23 at the end of the 4-year period. It's important to note that the actual value may vary depending on the exact compounding method used by the bank or financial institution.

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

multiply x by y multiply x by y multiply x by y 3 plus 5 minus 5 to the power of 2 then divide 3 plus 87 then you give your mom and dad a high five then go make out with a girl for an hour and then your answer is 72 to the power of x multiplyed by y.

The value of the function (f·g)(-9) is 186.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The given functions f(x)=2x²-4x-15 and g(x)=x+12.

Here, (f·g)(x)=f(x)+g(x)

= 2x²-4x-15+x+12

= 2x²-3x-3

(f·g)(-9)=2(-9)²-3(-9)-3

= 2×81+27-3

= 162+27-3

= 162+24

= 186

Therefore, the value of (f·g)(-9) is 186.

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Therefore, the probability of Blake making more than 7 out of 25 shots in practice is 0.9984.

To determine the probability of Blake making more than 7 out of 25 shots in practice, we can use the binomial probability formula: P(X = x) = (n choose x) * p^x * (1-p)^(n-x), where n is the number of trials, x is the number of successes, and p is the probability of success.

In this case, n = 25, p = 0.52, and we want to find the probability of x > 7. We can calculate this by finding the probability of x ≤ 7 and subtracting it from 1.

P(X > 7) = 1 - P(X ≤ 7)

= 1 - [(25 choose 0) * (0.52)^0 * (0.48)^25 + (25 choose 1) * (0.52)^1 * (0.48)^24 + ... + (25 choose 7) * (0.52)^7 * (0.48)^18]

= 1 - 0.0016

= 0.9984

Therefore, the probability of Blake making more than 7 out of 25 shots in practice is 0.9984.

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A) The Rational Root Theorem states that the only rational zeros of p(x) = x4+12x-5 must be a factor of -5 divided by a factor of 1. Therefore, the four possible rational zeros are -5, -1, 1, and 5.

B) The other three zeros is 1 - 2i, 1 + 2i, 1 - √(7), 1 + √(7)

A) The Rational Root Theorem states that if a polynomial with integer coefficients has a rational root r = p/q (where p and q have no common factors), then p must divide the constant term of the polynomial and q must divide the leading coefficient.

The constant term of p(x) = x^4 + 12x - 5 is -5, which has the factors ±1 and ±5. The leading coefficient is 1, which has the factors ±1. Therefore, the possible rational roots are:

±1/1, ±5/1, ±1/5, ±5/5 (which simplifies to ±1)

B) If r = 1 - 2i is a zero of p(x), then its complex conjugate r* = 1 + 2i is also a zero of p(x), since p(x) has real coefficients. Therefore, we can factor p(x) as:

p(x) = (x - r)(x - r*)(x²+ bx + c)

where b and c are the coefficients of the quadratic factor. We can expand this and compare coefficients to get:

x⁴ + 12x - 5 = (x - 1 + 2i)(x - 1 - 2i)(x² + bx + c)

Expanding the first two factors gives:

(x - 1 + 2i)(x - 1 - 2i) = x² - 2x + 5

Therefore, we have:

x⁴ + 12x - 5 = (x² - 2x + 5)(x² + bx + c)

Expanding the right side and comparing coefficients, we get:

b = -2 and c = -6

So the quadratic factor is:

x² - 2x - 6

We can find its roots using the quadratic formula:

x = [2 ± √(4 + 4(6))] / 2

x = 1 ± √(7)

Therefore, the four zeros of p(x) are:

1 - 2i, 1 + 2i, 1 - √(7), 1 + √(7)

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The expression 6x - x + 5 as 6 + 5 are not equivalent expression because one of the expression contain a variable while the other doesn't.

In Mathematics, an expression is sometimes referred to as an equation and it can be defined as a mathematical equation which is typically used for illustrating the relationship that exist between two (2) or more variables and numerical quantities (number).

Based on the information provided above, we have the following mathematical expression:

Expression = 6x - x + 5

Expression = 5x + 5

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The length of the short leg is 2 inches, the length of the long leg is 8 inches, and the length of the hypotenuse is 10 inches.

In a right triangle, if the length of the long leg is 2 inches more than the length of the short leg and the hypotenuse is 8 inches less than three times the length of the short leg, then the length of the short leg is x and the length of the long leg is [tex]x+2[/tex] and the hypotenuse is [tex]3x-8[/tex].

We can use the Pythagorean theorem to solve for the lengths of each side. The Pythagorean theorem states that [tex]a^{2} = b^{2} + c^{2}[/tex], where a and b are the lengths of the legs and c is the length of the hypotenuse.

So, [tex]x^{2} + (x+2)^{2} = (3x-8)^{2}[/tex]

We can solve for x, which gives us x = 6. Therefore, the length of the short leg is 2 inches, the length of the long leg is 8 inches, and the length of the hypotenuse is 10 inches.

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Peter ended up with 31 beads, and Dan ended up with 28 beads.

What is the fraction?

A fraction is a mathematical expression that represents a part of a whole. It is written in the form of a ratio between two numbers, with the top number called the numerator and the bottom number called the denominator.

Let's represent the number of beads that Peter and Dan had at the start by P and D, respectively. Then we can set up an equation based on the information given in the problem:

After giving away 1/4 of his beads, Peter had 3/4 of his original number of beads, which is (3/4)P.

After giving away 1/5 of his beads, Dan had 4/5 of his original number of beads, which is (4/5)D.

According to the problem, both had the same number of beads left after giving away some of their beads:

(3/4)P = (4/5)D

We also know that Peter had 7 more beads than Dan at the start:

P = D + 7

We can use substitution to solve for D:

(3/4)(D+7) = (4/5)D

9D/20 + 21/20 = 4D/5

D = 35

So Dan had 35 beads at the start. Using the equation P = D + 7, we can find that Peter had:

P = D + 7 = 35 + 7 = 42

After giving away 1/4 of his beads, Peter had (3/4)P = (3/4)*42 = 31.5 beads, which we can round down to 31 beads since we're dealing with whole numbers of beads. After giving away 1/5 of his beads, Dan had (4/5)D = (4/5)*35 = 28 beads.

Therefore, Peter ended up with 31 beads, and Dan ended up with 28 beads.

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Using Pivotal Condensation, the determinant of matrix A is 5.

Step 1: We start by initializing D as 1.

Step 2: We use the first row for pivotal condensation.
Row 0:  0 * D + 2 * 1 + 2 * 0 = 0
Row 1:  1 * D + 0 * 1 + 3 * 0 = 1
Row 2:  2 * D + 1 * 1 + 1 * 0 = 2

Step 3: We make the first row entries 0 by multiplying the entire row by (-2).
Row 0: -0 * D - 2 * 1 - 2 * 0 = 0
Row 1:  1 * D + 0 * 1 + 3 * 0 = 1
Row 2:  2 * D + 1 * 1 + 1 * 0 = 2

Step 4: We add row 0 to row 1 and row 0 to row 2.
Row 0:  0 * D + 2 * 1 + 2 * 0 = 0
Row 1:  1 * D + 0 * 1 + 3 * 0 = 1
Row 2:  0 * D + 3 * 1 + 3 * 0 = 3

Step 5: We make the entries of the second row 0 by multiplying the entire row by (-1/3).
Row 0:  0 * D + 2 * 1 + 2 * 0 = 0
Row 1: -1/3 * D - 0 * 1 - 3 * 0 = -1/3
Row 2:  0 * D + 3 * 1 + 3 * 0 = 3

Step 6: We add row 1 to row 0 and row 1 to row 2.
Row 0:  1/3 * D + 2 * 1 + 2 * 0 = 1/3
Row 1: -1/3 * D - 0 * 1 - 3 * 0 = -1/3
Row 2:  3/3 * D + 3 * 1 + 3 * 0 = 5

Step 7: We multiply the entries of the first row by (-3) to make the entries of the first row 0.
Row 0:  0 * D + 6 * 1 + 6 * 0 = 0
Row 1: -1/3 * D - 0 * 1 - 3 * 0 = -1/3
Row 2:  3/3 * D + 3 * 1 + 3 * 0 = 5

Step 8: We multiply the last row by D.
Row 0:  0 * D + 6 * 1 + 6 * 0 = 0
Row 1: -1/3 * D - 0 * 1 - 3 * 0 = -1/3
Row 2:  5 * D + 3 * 1 + 3 * 0 = 5D

Step 9: We subtract row 1 from row 0 and row 1 from row 2.
Row 0:  4/3 * D + 6 * 1 + 6 * 0 = 4/3D
Row 1: -1/3 * D - 0 * 1 - 3 * 0 = -1/3
Row 2:  4/3 * D + 3 * 1 + 3 * 0 = 4/3D

Step 10: We calculate the determinant by multiplying the last row entries.

Determinant of matrix A is 5.

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Answer:

Linear equation to represent the total cost:

Let x be the number of kgs of tomatoes Mail bought, and y be the number of kgs of potatoes Mail bought. The cost of x kgs of tomato at Rs. 50 per kg is 50x, and the cost of y kgs of potato at Rs. 20 per kg is 20y. Therefore, the total cost of the vegetables is:

Total cost = 50x + 20y

Substituting the value of total cost as Rs. 200, we get:

50x + 20y = 200

This is the required linear equation to represent the total cost.

Finding the value of x:

Let's assume that Mail bought x kgs of tomato and 2.5 kgs of potato. Using the equation derived above:

50x + 20(2.5) = 200

Simplifying the equation:

50x + 50 = 200

50x = 150

x = 3

Therefore, Mail bought 3 kgs of tomato.

Finding the point at which the graph of 5x+2y=20 cuts x-axis:

To find the point at which the graph of 5x+2y=20 cuts the x-axis, we need to set y = 0 in the equation and solve for x:

5x + 2(0) = 20

5x = 20

x = 4

Therefore, the point where the graph of 5x+2y=20 cuts the x-axis is (4,0).

Step-by-step explanation:

always remember Pythagoras for life :

c² = a² + b³

c is the Hypotenuse (the longest side of the right-angled triangle, it is opposite of the 90° angle). a and b are the legs.

c² = 19² + 17² = 361 + 289 = 650

c = sqrt(650) = 25.49509757... in ≈ 25.5 in

the Hypotenuse is about 25.5 in long.

Answer:

In the word problem, The account have left $67 in 13 weeks.

Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.

Here the given expression represents the medical savings account.

=> y=-24x+379

Here y represent  of money and x represent number of weeks.                                                                                                                            

Here Amount of money y = $67 then,

=> 67=- 24x+ 379

=> -24x = 67-379

=> -24x= -312

=> x = -312/-24

=> x = 13

Hence The account have left $67 in 13 weeks.

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To simplify 7-5/6•7-7/6, we need to follow the order of operations (PEMDAS) and perform the multiplication and division before addition and subtraction.

7-5/6•7-7/6

= 7 - (5/6) * 7 - (7/6) (Multiplication first)

= 7 - (35/6) - (7/6) (Simplify the multiplication)

= (42/6) - (35/6) - (7/6) (Convert 7 to a fraction with a common denominator)

= (42 - 35 - 7) / 6 (Subtract the numerators)

= 0 / 6

= 0

Therefore, 7-5/6•7-7/6 simplifies to 0.

Answer: 0

Step-by-step explanation:

7 - 5 / 6 • 7 - 7 / 6

7 - 35 / 6 - 7 / 6

7 - 42 / 6

7 - 7

0

(B) 0.9%. We can use the formula for compound interest to find the value of the investment after 2 years:

A = P(1 + r/n)^(nt)

where A is the amount of money after the time period, P is the principal (initial investment), r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time in years.

Plugging in the given values, we get:

A = 1000(1 + 0.018/2)^(2*2)

= 1000(1 + 0.009)^4

= 1000(1.009)^4

≈ 1083.02

So the investment is worth approximately $1083.02 after 2 years.

To find the interest rate per year, we can use the formula:

r = n[(A/P)^(1/nt) - 1]

Plugging in the values we know, we get:

r = 2[(1083.02/1000)^(1/(2*2)) - 1]

= 2[(1.08302)^(1/4) - 1]

≈ 0.9%

Therefore, the answer is (B) 0.9%.

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Answer:

28

Step-by-step explanation:

So for this problem, you need to use the midsegment formula. The midsegment formula is [tex]SG = \frac{1}{2} (b_{1} + b_{2})[/tex]. In this case, [tex]b_{1}[/tex] is 21 and [tex]b_{2}[/tex] 35.

Adding these together get 56. The next part of the formula is dividing by two, so [tex]\frac{56}{2} = 28[/tex] so you answer is x=28

Answer:

Step-by-step explanation:

W = w

L = 3w

H = w+4

Now V = LHW

          = (3w)(w+4)(w)

         = (3w²+12w)(w)

        = 3w³+12w²

Out of 300 grams, 147 grams of food is not water in the given food sample.

If 51% of a certain food is water, then 49% of it must be something other than water. To find out how many grams of the food are not water, we can first calculate how many grams of water there are,

300 grams x 51% = 153 grams of water

Then we can subtract this from the total weight to find the amount of food that is not water -

300 grams - 153 grams = 147 grams of food that is not water

Therefore, out of 300 grams of nutrition, 153 grams are water and 147 grams are not.

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Answer:

4-2-5

Step-by-step explanation:

16, 8, and 20 can all be divided by 4

Leaving you with 4 2 and 5.

The ratio is 4 to 2 to 5

Step-by-step explanation:

To complete the frequency table and ogive for the number of heads flipped, we need to determine the frequency of each of the indicated intervals. We can do this by counting the number of times each interval appears in the data set and entering the frequencies into the table.

Here is how to do it step-by-step:
1. Start with the first interval, which is 0-4 heads. Count the number of times this interval appears in the data set. For example, if there are 3 occurrences of 0-4 heads, enter 3 in the frequency column for this interval.
2. Repeat this process for each of the remaining intervals, counting the number of occurrences and entering the frequencies into the table.
3. Once you have entered all the frequencies, you can create the ogive by plotting the cumulative frequencies on a graph. Start with the first interval and plot the cumulative frequency at the upper limit of the interval. For example, if the first interval is 0-4 heads and the frequency is 3, plot the point (4,3) on the graph.
4. Continue this process for each of the remaining intervals, adding the frequency of each interval to the cumulative frequency and plotting the point at the upper limit of the interval.
5. Once you have plotted all the points, connect them with a line to create the ogive.

Here is the completed frequency table and ogive for the number of heads flipped:
| Interval | Frequency |
|----------|-----------|
| 0-4      | 3         |
| 5-9      | 5         |
| 10-14    | 4         |
| 15-19    | 2         |
| 20-24    | 1         |

Ogive:
(4,3) (9,8) (14,12) (19,14) (24,15)

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Answer:

c

Step-by-step explanation:

it makes sense

To determine whether a given vector is a solution to the equation \(A\vec{x}=\vec{0}\), we need to multiply the matrix A with the vector \(\vec{x}\) and check if the resulting vector is equal to the zero vector \(\vec{0}\).

Let's consider the first vector \(\vec{x_1}=\left[\begin{array}{c} 2 \\ 1 \\ 1 \end{array}\right]\). Multiplying the matrix A with this vector, we get:
\[ A\vec{x_1}=\left[\begin{array}{ccc} 3 & 6 & -6 \\ -1 & -2 & 5 \\ -1 & -2 & 2 \\ -1 & -1 & 0 \end{array}\right] \left[\begin{array}{c} 2 \\ 1 \\ 1 \end{array}\right]=\left[\begin{array}{c} 12 \\ -4 \\ -3 \\ -3 \end{array}\right] \]
Since the resulting vector is not equal to the zero vector \(\vec{0}\), the vector \(\vec{x_1}\) is not a solution to the equation \(A\vec{x}=\vec{0}\).
Similarly, we can check for the other vectors:
For the vector \(\vec{x_2}=\left[\begin{array}{c} -1 \\ 2 \\ -1 \end{array}\right]\):
\[ A\vec{x_2}=\left[\begin{array}{ccc} 3 & 6 & -6 \\ -1 & -2 & 5 \\ -1 & -2 & 2 \\ -1 & -1 & 0 \end{array}\right] \left[\begin{array}{c} -1 \\ 2 \\ -1 \end{array}\right]=\left[\begin{array}{c} 6 \\ 1 \\ 1 \\ 1 \end{array}\right] \]

Again, the resulting vector is not equal to the zero vector \(\vec{0}\), so the vector \(\vec{x_2}\) is not a solution to the equation \(A\vec{x}=\vec{0}\).
For the vector \(\vec{x_3}=\left[\begin{array}{c} 1 \\ -1 \\ 1 \end{array}\right]\):
\[ A\vec{x_3}=\left[\begin{array}{ccc} 3 & 6 & -6 \\ -1 & -2 & 5 \\ -1 & -2 & 2 \\ -1 & -1 & 0 \end{array}\right] \left[\begin{array}{c} 1 \\ -1 \\ 1 \end{array}\right]=\left[\begin{array}{c} 0 \\ 0 \\ 0 \\ 0 \end{array}\right] \]
In this case, the resulting vector is equal to the zero vector \(\vec{0}\), so the vector \(\vec{x_3}\) is a solution to the equation \(A\vec{x}=\vec{0}\).

Therefore, only the vector \(\vec{x_3}=\left[\begin{array}{c} 1 \\ -1 \\ 1 \end{array}\right]\) is a solution to the equation \(A\vec{x}=\vec{0}\).

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