Figure 5 below shows four abiotic factors of an ecosystem. Choose the
statement that identifies a major characteristic of abiotic factors in
ecosystems.


A. They are all living.
B. There are equal amounts in every ecosystem.
C. They are not alive, never have been alive, and never will be alive.
D. They are impossible to measure.

Answer:

Protons I think. I might be wrong but I think its Protons

Answer:

the nucleus is the center of atoms and its made of of protons and neutrons

Explanation:

Answer:

I'm not really sure how to answer it but this is the best I can do:

If the capacity of a mass is 1350 and heat is transferred to increase the temperature by 15. degrees Celcius then the amount of heat that needs to be transferred would be about  45 degrees.

Explanation:

I'm sorry if it's wrong or not exactly the way it's supposed to be answered, I'm not very good with math and temperature problems. But i hope it helps! :)

Answer:

1) chemical property

2) physical property

3) chemical property

4) physical property

Explanation:

Physical properties:

Physical properties are those properties which can be measured without changing the composition of mater. We can observe the object and tell its physical properties like its texture, physical appearance, color, melting point, boiling point, odor, density etc.

Chemical properties:

Chemical properties involve chemical reaction or we can say that change is happen in mater during chemical reaction and the properties, we measured  during this or as a result of this reaction is called chemical properties. Like flammability, toxicity, combustion, decomposition etc.

1) Water can split into hydrogen and oxygen

chemical property

2) water is liquid at room temperature

physical property

3) water react with certain metals

chemical property

4)The density of water is 1.0 g/cm³

physical property

Answer:

Simplified for PLATO Users : )

Answer:

252.06492

Explanation:

How many grams (NH4)2Cr2O7 in 1 mol? The answer is 252.06492.

We assume you are converting between grams (NH4)2Cr2O7 and mole.

You can view more details on each measurement unit:

molecular weight of (NH4)2Cr2O7 or mol

The SI base unit for amount of substance is the mole.

1 grams (NH4)2Cr2O7 is equal to 0.0039672319337415 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams (NH4)2Cr2O7 and mole.

Type in your own numbers in the form to convert the units!

Answer:

SeF4

Explanation:

SeF4

Answer:

The anwser is SeF4

Answer:

Explanation:

C₂H₄ + HCl = C₂H₅Cl

28 g                  64.5 g

28 g of ethylene reacts to give 64.5 g of ethyl chloride

4.66 g of ethylene reacts to give 64.5 x 4.66 / 28  g of ethyl chloride

= 10.73g

yield = 89.4 %

ethyl chloride produced = 10.73 x .894

= 9.6 g .

Answer:

its division

Explanation:

Answer:

Proteins

Elements: C, H, O, N, and some S

Monomer: amino acids

Functions: catalyzing chemical reactions, synthesizing and repairing DNA, structural support, transporting materials across the cell

Examples: hemoglobin, actin and myosin, albumin, keratin

Carbohydrates

Elements: C, H, O

Monomer: monosaccharides

Functions: cellular identity, source of energy, storage of energy, structural support, cell signaling, make ATP, convert solar energy

Examples: glucose, starch, glycogen, peptidoglycan, cellulose, chitin

Nucleic Acids

Elements: C, H, O, N, P

Monomer: nucleotides

Functions: storage and expression of genetic information, transmission of genetic code required for making proteins

Examples: DNA, RNA

Lipids

Elements: C, H, O, and some P and N

Monomer: fatty acids

Functions: energy storage, cell structure, insulation and protection, regulating and signaling, digestion

Examples: steroids (cholesterol), waxes, fats and oils, phospholipids

Hope that helps.

The outer core is about 1,400 miles thick, and it's made mostly of a combination (called an alloy) of iron and nickel, along with small amounts of other dense elements like gold, platinum, and uranium. These metals can, of course, be found on the surface of Earth in solid form.

Answer:

A is the answer; 'more-efficient extraction techniques

Explanation:

I just took the test and got it right :D

Answer:

A is the answer to the question

Answer:

Explanation:

To find the volume when the pressure is changed to 546 kPa , we use the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{384000 \times 590}{546000} = \frac{226560000}{546000} \\ = 414.945054...[/tex]

We have the final answer as

Hope this helps you

Answer:

I just did this question and it’s I

Explanation:

Answer:

Iodine (I) has a lower Ionization Energy.

Explanation:

Our Periodic Trend for Ionization Energy is up and to the right.

We know that Fluorine and Iodine are both in Group 17. However, Fluorine is in Period 2 and Iodine is in Period 5.

According the Coulomb's Law, the greater the distance between the electrons and the nucleus, the less Forces of Attraction (FOA) there are. Since Iodine has a lot more electrons than Fluorine, and those electrons are spread out farther from the nucleus, they will have less FOA acting on them. Therefore, it will require less energy to remove those electrons from Iodine.

Since Iodine has so many electrons, it will also have more core electrons than Fluorine. This will create the Shielding Effect, where the core electrons "shield" the nucleus' FOA. With the reduced FOA, the outer electrons aren't held as closely to the nucleus as the core electrons. Since higher sublevels also means more energy, those outer electrons contain a lot of energy. All electrons want to have the lowest energy level possible, and since the FOA is reduced, less energy is needed to remove the electrons of Iodine rather than Fluorine.

Density can be observed without changing identity of a substance .

Density of a substance is defined as the mass of the substance mass per unit of volume. It is represented by a capital letter'D'. It is mathematically defined as   mass divided by volume.

It is defined loosely as weight of substance per unit volume. It is scientifically inaccurate  it is more specifically called as specific weight.Different substances have different densities  and these are related to purity and buoyancy.

Osmium and iridium are the densest known elements. To simplify comparisons, it is replaced sometimes by a quantity which is dimensionless called relative density. Density of a material varies with temperature and pressure. The variation is small for solids and greater for gases. Increase in pressure increases the density.

Learn more about density,here:

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Algae is a member of the Protista kingdom, a group of mostly aquatic photosynthetic organisms. Yeast, any one of roughly 1,500 species of single-celled fungi, the majority of which belong to the phylum Ascomycota with just a few Basidiomycota species.

What are characteristics of algae and yeast ?

To know more about algae and yeast check this:

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#SPJ2

Answer:

a)beta decay; to reduce the number of neutrons

Explanation:

When an isotope decays by beta decay, a neutron is converted into a proton, an electron and a neutrino (a particle that serves to balance spins). This process reduces the neutron/proton ratio.

During the beta decay of carbon-14, an atom of 14C decays into an atom of 14N. Hence the number of protons in the atom increases by one, creating a nitrogen atom.

1. Which law is associated with inertia?

2. If you increase the force in an object what happens to the acceleration?

3. If you use the same force on a less massive object what happens to the acceleration?

4. Which law states force is dependent on the mass and acceleration of an object?

5. What causes an object to slowdown or speed-up?

                  HOPE IT HELPS YOU

Answer:

Protons

Explanation:

The nucleus contains two type of subatomic particles.

Answer:

Gas particles

Explanation:

Particles in the gaseous state have the greatest amount of energy, they move around rapidly and they have large spaces between them

Answer:

V equals four-thirds times pi times r cubed

Explanation:

Volume = a³ , where a is length of each side. Volume = l × w × h , where l is length, w is width and h is height. Volume = 4/3 πr³ , where r is the radius. Volume = πr²h , where r is the radius and h is the height.

Answer:

[tex]m_{CoSO_4\ \ 7H_2O}^{sample}=0.558gm_{CoSO_4\ \ 7H_2O}[/tex]

Explanation:

Hello.

In this case, considering a representative reaction by which BaSO4 is yielded via CoSO4, for instance:

[tex]CoSO_4\ \ 7H_2O+BaCl_2\rightarrow BaSO_4+CoCl_2+7H_2O[/tex]

Since it is desired to obtain 0.345 g of BaSO4 (molar mass = 233.38 g/mol), we can compute the theoretical mass of CoSO4·7H20 (molar mass = 281 g/mol) via the following stoichiometric procedure:

[tex]m_{CoSO_4\ \ 7H_2O}=0.345gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4}*\frac{1molCoSO_4\ \ 7H_2O}{1molBaSO_4} *\frac{281.00gCoSO_4\ \ 7H_2O}{1molCoSO_4\ \ 7H_2O} \\\\m_{CoSO_4\ \ 7H_2O}=0.415gCoSO_4\ \ 7H_2O[/tex]

Next, given the percent purity of the cobalt (II) sulfate heptahydrate, we can compute the mass of the whole sample as shown below:

[tex]m_{CoSO_4\ \ 7H_2O}^{sample}=0.415gCoSO_4\ \ 7H_2O^{pure}*\frac{100gCoSO_4\ \ 7H_2O^{sample}}{74.4gCoSO_4\ \ 7H_2O^{pure}} \\\\m_{CoSO_4\ \ 7H_2O}^{sample}=0.558gm_{CoSO_4\ \ 7H_2O}[/tex]

Best regards!

To obtain 0.345 g of BaSO₄, we need to weigh 0.559 g of CoSO₄.7H₂O with a purity of 74.4%.

Let's consider a possible reaction for the obtaining of BaSO₄ from CoSO₄.7H₂O.

CoSO₄.7H₂O(aq) + Ba(NO₃)₂(aq) ⇒ BaSO₄(s) + Co(NO₃)₂(aq) + 7 H₂O(l)

We want to find the mass of CoSO₄.7H₂O required to form 0.345 g of BaSO₄. We will consider the following relationships:

[tex]0.345gBaSO_4 \times \frac{1molBaSO_4}{233.38gBaSO_4} \times \frac{1molCoSO_4.7H_2O}{1molBaSO_4} \times \frac{281.10gCoSO_4.7H_2O}{1molCoSO_4.7H_2O} =0.416gCoSO_4.7H_2O[/tex]

The purity of the sample is supposed to be 74.4%, that is, there are 74.4 g of CoSO₄.7H₂O every 100 g of sample. The mass of the sample that contains 0.416 g of CoSO₄.7H₂O is:

[tex]0.416gPure \times \frac{100gSample}{74.4gPure} = 0.559gSample[/tex]

To obtain 0.345 g of BaSO₄, we need to weigh 0.559 g of CoSO₄.7H₂O with a purity of 74.4%.

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Answer:

11.4 g CO₂

Explanation:

Your chemical equation is:

4 CO₂  +  2 H₂O  ⇒  2 C₂H₂  +  5 O₂

You need to produce 3.382 g of acetylene.  To find out how many grams of carbon dioxide you need, first convert grams of acetylene to moles using the molar mass.  The molar mass of acetylene is 26.04 g/mol.

(3.382 g)/(26.04 g/mol) = 0.130 mol C₂H₂

Now, use the mole ratio between acetylene and carbon dioxide to convert from moles of acetylene to moles of carbon dioxide.  You can find the mole ratio by looking at the chemical equation.  The mole ratio is (4 mol CO₂)/(2 mol C₂H₂).

(0.130 mol C₂H₂) × (4 mol CO₂)/(2 mol C₂H₂) = 0.260 mol CO₂

Since you now have moles of carbon dioxide, you can convert to grams using the molar mass.  The molar mass of carbon dioxide is 44.01 g/mol.

0.260 mol × 44.01 g/mol = 11.4 g CO₂

You will need 11.4 g of CO₂ to produce 3.382 g of C₂H₂.

Answer:

1) acetylide

2) enol

3) aldehydes

4) tautomers

5) alkynes

6) Hydroboration

7) Keto

8) methyl ketones

Explanation:

Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.

Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.

The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.

Answer:

[tex][H_3O]^+=2.18x10^{-3}M[/tex]

Explanation:

Hello.

In this case, for the given ionization chemical reaction of acetic, the equilibrium expression is:

[tex]Ka=\frac{[H_3O^+][CH_3COO^-]}{[CH_3COOH]}[/tex]

Since aqueous species are considered only. Next, by introducing the reaction extent [tex]x[/tex] based on the ICE table, in which it equals the concentration of both H3O+ and CH3COO-, we can also write:

[tex]1.8x10^{-5}=\frac{x*x}{0.265M-x}[/tex]

As the acid ionization constant is small in comparison to 0.265 M, we can make an approximation to compute [tex]x[/tex] as shown below:

[tex]1.8x10^{-5}=\frac{x*x}{0.265M}\\\\x=\sqrt{1.8x10^{-5}*0.265}= 2.18x10^{-3}M[/tex]

It means that the concentration of H3O+ is:

[tex][H_3O]^+=2.18x10^{-3}M[/tex]

Best regards.

A solution of acetic acid (Ka  = 1.8 × 10⁻⁵) with an initial concentration of CH₃COOH of 0.265 mol/L has an equilibrium concentration of H₃O⁺ at 25 °C of 2.18 × 10⁻³ M.

Let's consider the reaction for the acid ionization of acetic acid.

CH₃COOH(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃COO⁻(aq)

The acid ionization constant (Ka) is 1.8 × 10⁻⁵ and the initial concentration of the acid (Ca) is 0.265 mol/L.

Considering that it is a weak monoprotic acid, we can calculate the equilibrium concentration of H₃O⁺ at 25 °C using the following expression.

[tex][H_3O^{+} ]= \sqrt{Ka\times Ca } = \sqrt{1.8\times 10^{-5} \times 0.265 } = 2.18 \times 10^{-3} M[/tex]

A solution of acetic acid (Ka  = 1.8 × 10⁻⁵) with an initial concentration of CH₃COOH of 0.265 mol/L has an equilibrium concentration of H₃O⁺ at 25 °C of 2.18 × 10⁻³ M.

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Answer:

Calcium, Magnesium, Barium, strontium, Beryllium, Radium

Explanation:

sorry if im wrong.....:(

Answer:

lithoshpere

Explanation:

Answer:

Latitude

I hope this helps!