Explain what is wrong with each of the following randomization procedures, and describe how you would do the randomization correctly.

a. Twenty students are to be used to evaluate a new treatment. Ten men are assigned to receive the treatment, and 10 women are assigned to be the controls.
b. Ten subjects are to be assigned to two treatments, 5 to each. For each subject, a coin is tossed. If the coin comes up heads, the subject is assigned to the first treatment: if the coin comes up tails, the subject is assigned to the second treatment.
c. An experiment will assign 40 rats to four different treatment conditions. The rats arrive from the supplier in batches of 10, and the treatment lasts two weeks. The first batch of 10 rats is randomly assigned to one of the four treatments, and data for these rats are collected. After a one-week break, another batch of 10 rats arrives and is assigned to one of the three remaining treatments. The process continues until the last batch of rats is given the treatment that has not been assigned to the three previous batches.

Answers

Answer 1

Answer:

Kindly check explanation

Step-by-step explanation:

A.)

The problem with the here is that we might have introduced bias into our sample by failing to randomize the assignment of gender. By pacing the male gender in the treatment group and females into the control group, this might spring up a spurious association in our experiment as a result of a possible confounding variable, gender. Therefore, assignment of subject shouldn't be on the basis of gender.

2.)

Using a coin toss in placing subjects into groups will give a good random assignment, however, since only ten subjects are available and of which 5 will be placed into each group, there is no certainty that there will be equal number of heads and tails during the 10 flips. Alternatively, a random selection of the name of the 10 subjects could be chosen from a raffle.

3.)

Each batch of rat might be homogenous and hence will affect our experiment and definitely our conclusion. It would be best to assign rats from each batch to all treatment groups in other to obtain a good random design


Related Questions

I need help please and go look at my other answer i need that answer to that fast its 20 points and i will mark as brainlest

Answers

The answer is A because when you divide into 175 to find the amount discounted, then you subtract that to 175 and you get 145.25

How to expand 6x(x-2y)

Answers

Answer:

[tex]6x^{2} - 12xy[/tex]

Step-by-step explanation:

6x  × x = [tex]6x^{2}[/tex]

6x  ×  -2y = -12xy

[tex]6x^{2} - 12xy[/tex]

The firm is requested to send 3 employees who have positive indications of asbestos on to a medical center for further testing. Suppose 40% of the employees have positive indications of asbestos in their lungs. a) Find the probability that exactly 10 employees will be tested in order to find 3 positives

Answers

Answer:

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

40% of the employees have positive indications of asbestos in their lungs

This means that [tex]p = 0.4[/tex]

a) Find the probability that exactly 10 employees will be tested in order to find 3 positives

2 within the first 9([tex]P(X = 2)[/tex] when [tex]n = 9[/tex]), and the 10th, with 0.4 probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{9,2}.(0.4)^{2}.(0.6)^{7} = 0.1612[/tex]

0.4*0.1612 = 0.0645

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

The width of a rectangle is 23 yd. What is the perimeter of the rectangle if the length is 6 yd less than the width?
a. 40 yd
c. 391 yd
b. 104 yd
d. 80 yd

Answers

C is the answer to your question

1.32 Factory defective rate. A factory quality control manager decides to investigate the percentage of defective items produced each day. Within a given work week (Monday through Friday) the percentage of defective items produced was 2%, 1.4%, 4%, 3%, 2.2%. (a) Calculate the mean for these data. (b) Calculate the standard deviation for these data, showing each step in detail.

Answers

Answer:

a) the mean percentage of defective item produced is 2.52 %

b) the standard deviation of percentage of defective item produced is 1.01%

       

Step-by-step explanation:

Given that;

the percentage of defective items produced was 2%, 1.4%, 4%, 3%, 2.2%.

sample size n = 5

a) Calculate the mean for these data

mean percentage of defective item produced will be;

[tex]x^{bar}[/tex] = ∑x / n

[tex]x^{bar}[/tex] = ∑x / n = ( 2% + 1.4% + 4% + 3% + 2.2% ) / 5

[tex]x^{bar}[/tex]  = 12.6 / 5

[tex]x^{bar}[/tex]  = 2.52 %

Therefore, the mean percentage of defective item produced is 2.52 %

b) Calculate the standard deviation for these data

Formula for standard deviation is;

S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )

so we make a table;

x                   ( x - [tex]x^{bar}[/tex] )%                ( x - [tex]x^{bar}[/tex] )²%

2%                 -0.52                         0.2704

1.4%               -1.12                           1.2544

4%                  1.48                          2.1904  

3%                  0.48                         0.2304

2.2%.             -0.32                         0.1024

summation                                     4.048

so (∑(x-[tex]x^{bar}[/tex] )² = 4.048%  

so we substitute the value into our equation;

S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )

S = √( (4.048%) / (5-1) )

S = √( 4.048% / 4 )

S = √( 1.0121

S =  1.00598 % ≈ 1.01%

Therefore, the standard deviation of percentage of defective item produced is 1.01%

What is the ratio in simplest form between the length of a side in MARDT and the length of its corresponding side in JPLSF?
A. 3/4
B. 4/3
C. 3/2
D. 2/1

Answers

Answer:

b i think

Step-by-step explanation:

The ratio of the corresponding sides of  MARDT and JPLSF is A. 3/4.

What is congruency?

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

By observing the given figures MARDT is similar to JPLSF.

So, the ratio of their corresponding sides must also be equal.

Given, Length of MA is 4 and the length of JP is 3.

Therefore, The ratio of sides MARDT and JPLSF is 3/4.

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Solve the following system of equations and show all work.

y=-x^2 + 4
y=2x+1

Answers

Answer:

Step-by-step explanation:

y = -x²+4 and y = 2x+1

Therefore,  -x²+4 = 2x+1

x²+2x-3 = 0

x = 1,-3

There are two solutions:

(1,3) and (-3,-5)

The solutions to the system of equations are (x, y) = (-3, -5) and (1, 3).

We have,

To solve the system of equations:

Set the expressions for y equal to each other:

-x² + 4 = 2x + 1

Rearrange the equation to bring all terms to one side:

-x² - 2x + 3 = 0

Solve the quadratic equation by factoring, completing the square, or using the quadratic formula. In this case, we will use factoring.

Factor the quadratic equation:

(-x - 3)(x - 1) = 0

Set each factor equal to zero and solve for x:

-x - 3 = 0 or x - 1 = 0

Solve the first equation:

-x = 3

x = -3

Solve the second equation:

x = 1

Substitute the values of x back into one of the original equations to find the corresponding values of y.

For x = -3:

y = 2(-3) + 1

y = -6 + 1

y = -5

For x = 1:

y = 2(1) + 1

y = 2 + 1

y = 3

Therefore,

The solutions to the system of equations are (x, y) = (-3, -5) and (1, 3).

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convert 50 watts to kilowatts

Answers

Answer:

0.05 kilowatts

Answer:

0. 05

Step-by-step explanation:

Use the grouping method to factor 2x3 + 6x2 - 7x- 21.
O A. (x - 3)(x + 7)
O B. (x+3)(2x2 - 7)
C. 2x(x + 3)(x - 7)
O D. (x - 3)(2x2 + 7)

Answers

Answer:

B. (x+3)(2x2−7)

Step-by-step explanation:

2x3 + 6x2 - 7x- 21

(2x3+6x2)(-7x-21)

2x2(x+3)-7(x+3)

(x+3)(2x2-7)

HELPPPP!!! PLEASEEEE I’M FAILING ALGEBRA AND I NEED HELP WITH THIS QUESTION

Answers

a/b The decay can be modeled by this equation, (1 - r), the r being the rate of decay. So it would be 1-0.115. (0.115 is your answer for a) You have to convert the percent into a decimal by moving the deicmal place two places to the left. 0.885 is your answer for b.

c. For function notation, that just means write an equation. So you want your decay times your inital.  V(t)=15000(0.885)^x. We get the V(t) from the directions that they want us to put it in; it's basically y.

d. Since it's two years, plug in 2 for x. This shows the decay after two years

V(t)=15000(0.885)^2

e. As with d, plug in 10 for x. V(t)=15000(0.885)^t

hello your answer would most likely be

Verizon Wireless charges
$0.09 for every 5 text
messages sent. How much
is your bill if you send 75
texts?
Make this into a equation

Answers

(75 divided by 5) x 0.09 = 1.35
(75 / 5) x 0.09 = 1.35

1. In the right triangle shown below, determine the value of x. (Round to the nearest
tenth.)

Answers

Answer:

20.8

Step-by-step explanation:

so x is opposite the 60 degree angle so that means that it is half of the hypotanuese times root three

so then x would be equal

24/12=12 root three which is equal to 20.8

Solve for W
-2.5 + w = 3.7
w=

Answers

Answer:

6.2

Step-by-step explanation:

3.7 + 2.5 = 6.2 Therefore w = 6.2

Suppose that 30% of the applicants for a certain industrial job possess advanced training in computer programming. Applicants are interviewed sequentially and are selected at random from the pool.
(a) Find the probability that the first applicant with advanced training in programming is found on the fifth interview.
(b) What is the expected number of applicants who need to be interviewed in order to find the first one with advanced training?
(c) Let Y denote the number of the trial on which the first applicant with computer training was found. If each interview costs $30, find the expected value and variance of the total cost incurred interviewing candidates until an applicant with advanced computer training is found.

Answers

Answer:

Step-by-step explanation:

From the given information:

Assume X represents the no. interviewed until 1 has advanced training.

X obeys a Geometric distribution with parameter 0.3.

X  [tex]\sim[/tex] Geom (0.30)

For geometric distribution, the probability density is:

[tex]P(X =x) = p(1-p) ^{x-1} \ \ \ where; x =1,2,3...[/tex]

TO calculate the required probability;

[tex]P(X =5) =0.30 (1-0.30)^{5-1}[/tex]

[tex]P(X =5) =0.30 (0.70)^{4}[/tex]

[tex]P(X=5) = 0.30 \times 0.2401[/tex]

[tex]\mathbf{P(X=5) = 0.07203}[/tex]

(b)

The expected no. of applicants that need to be interviewed are:

[tex]E(X)=\dfrac{1}{p}[/tex]

[tex]E(X)=\dfrac{1}{0.30}[/tex]

E(X) = 3.33

(c)

The mean and the variance can be computed as:

[tex]E(Y) = \dfrac{1}{p}[/tex]

[tex]E(Y) = \dfrac{1}{0.30}[/tex]

E(Y) = 3.33

[tex]V(Y)=\dfrac{1-p}{p^2}[/tex]

[tex]V(Y)=\dfrac{1-0.3}{0.3^2}[/tex]

[tex]V(Y)=\dfrac{0.7}{0.3^2}[/tex]

[tex]V(Y)=7.778[/tex]

Suppose  C represents the no. of the total cost and given that each interview costs $30.

Then C = 30Y

Recall that; C is constant for a random variable X

E(C) = E(30Y)

E(C) = 30E(Y)

E(C) = 30*3.33

E(C) =99.9

E(C) [tex]\simeq[/tex] 100

V(C) = V(30Y)

V(C) = 900 V(Y)

V(C) = 900*7.778

V(C) = 7000.2

V(C) [tex]\simeq[/tex] 7000

May someone please help me? The question is:

What type of triangle is DAE? Look at the image above.

Answers

Answer:

Right angle triangle

Step-by-step explanation:

hey i need help!!!!!!​

Answers

21% 2x10+1 21=21/100 so 21%

Answer:2.10%

Step-by-step explanation:

2 is the whole number with 1/10 being also = to 10/100s

Ana, Profesora de Psicología de una escuela, planeo realizar un estudio sobre las
respuestas de los espectadores a ciertos aspectos de las peliculas A By Después
de encuestar su clase de 55 estudiantes, determinó la siguiente información: 17
han visto A. 17 han visto B. 23 han visto c. 6 han visto A y B. & han visto A y C 10
han visto By C 2 han visto las tres peliculas.
a. ¿Quántos estudiantes han visto exactamente dos de estas peliculas?
b. ¿Cuántos estudiantes han visto exactamente una de estas peliculas?
C. ¿Cuántos estudiantes no han visto estas películas?
d. ¿Cuántos estudiantes han visto A. pero ninguna de las otras?​

Answers

Answer:

The answer is below

Step-by-step explanation:

El número de personas que vieron solo A = n (A) = 17

El número de personas que vieron solo B = n (B) = 17

El número de personas que vieron solo C = n (C) = 23

El número de personas que vieron A y B = n (A ∩ B) = 6

El número de personas que vieron A y C = n (A ∩ C) = 8

El número de personas que vieron B y C = n (B ∩ C) = 10

El número de personas que vieron las tres películas = n (A ∩ B ∩ C) = 2

1) Número de estudiantes que han visto dos películas = n (A ∩ B) + n (A ∩ C) + n (B ∩ C) = 6 + 8 + 10 = 24

2)

n (A∩ B '∩ C') = n (A) -n (A ∩ B) -n (A ∩ C) -n (A ∩ B ∩ C) = 17-8-6-2 = 1

n (A'∩ B ∩ C ') = n (B) -n (A ∩ B) -n (B ∩ C) -n (A ∩ B ∩ C) = 17-6-10-2 = 1

n (A'∩ B '∩ C) = norte (C) -n (UNA ∩ C) -n (B ∩ C) -n (UNA ∩ B ∩ C) = 23-8-10-2 = 3

estudiantes que no han visto = 55 - n (A∩ B '∩ C') -n (A'∩ B ∩ C ') - n (A'∩ B ∩ C') - n (A ∩ B) -n ( B ∩ C) -n (UNA ∩ C) -n (A∩ B ∩ C) = 55-1-1-3-6-8-10-2 = 24

3)

número de alumnos que no han visto =

4)

número de estudiantes que vieron solo A = n (A∩ B '∩ C') = 1

Please help!!!!
I do not know how to resolve this.

Answers

Answer:

5/9

Step-by-step explanation:

find the area of the shaded region under the
standard normal curve. If convenient, use technology to find the area

Answers

Answer

The area of the shaded region under the standard normal curve is 0.4834.

Step-by-step explanation:

A random variable X is said to have a normal distribution with mean, µ and variance σ².

Then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z  N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Compute the area under the curve between -2.13 and 0 as follows:

                           

Thus, the area of the shaded region under the standard normal curve is 0.4834.

Whats 743x4824
and also comment if you have a discord account and if you do comment what it is

Answers

Answer:

3584232 || N o- t h x—?

Step-by-step explanation:

Answer:

3584232

Step-by-step explanation:

Yes I do its Sunju #5984

PLEASE ANSWER I NEED HELP PLEASE PLEASEEEE

Graph the number pairs, and then complete the inequality.
3 ____-3

Answers

Answer:

3>-3

Step-by-step explanation:

make an open dot on 3 and make a line going towards the left.

I need to know this please answer asap

Answers

Answer:

y=-1/2x+1

Step-by-step explanation:

1. write an equvialent expression: -1/2 (-2x + 4y)


2. Factor to write an equivalent expression: 26a - 10.

Answers

Answer:

1) x-2y 2) 2(13a-5)

Step-by-step explanation:

1) -1/2(-2x+4y)=2/2x-4/2y=x-2y

2) 26a-10=2(13a-5)

In a survey of 2,500 people who owned a certain type of​ car, 750 said they would buy that type of car again. What percent of the people surveyed were satisfied with the​ car?

Answers

Answer:

30%

Step-by-step explanation:

Simply divide your final value (750) by your initial value (2500).



The measure of angle D is 55°, the measure of angle E is 85°, and
the measure of angle F is 10x. What is the value of x?

Answers

[tex]x = 4[/tex]

55+85=140

180-140=40

10x=40

divide by ten on each side

x=4

f (x)= 1/x-4 -6. Find the inverse of f(x) and its domain.

Answers

Answer:

B Or D

Step-by-step explanation:

The inverse function is [tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex] and the domain is [tex]x \ne 6[/tex]

The function is given as:

[tex]f(x) = \frac{1}{x - 4} - 6[/tex]

Express f(x) as y

[tex]y = \frac{1}{x - 4} - 6[/tex]

Swap the positions of x and y

[tex]x = \frac{1}{y - 4} - 6[/tex]

Add 6 to both sides

[tex]x + 6= \frac{1}{y - 4}[/tex]

Multiply both sides by y-4

[tex](x + 6)(y -4) =1[/tex]

Divide both sides by x + 6

[tex]y - 4 = \frac{1}{x + 6}[/tex]

Add 4 to both sides

[tex]y = \frac{1}{x + 6} + 4[/tex]

Rewrite as:

[tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex]

Hence, the inverse function is [tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex] and the domain is [tex]x \ne 6[/tex]

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1/5 = something/10 = something/100 = something percentage %

Answers

Answer:

20%

Step-by-step explanation:

The computation is shown below:

Let something be x

[tex]\frac{1}{5} = \frac{x}{10} = \frac{x}{100} = x\%[/tex]

[tex]0.2 = \frac{x}{10} = \frac{x}{100} = x\%[/tex]

So if we see that 0.2 would be equivalent to the [tex]\frac{x}{10}[/tex] and then [tex]\frac{x}{100}[/tex] after than x percentage

Therefore according to this the x percentage is 20%

Hence, the x percentage is 20%

Evaluate 9.3x when 8.9y and x=7 and y=8.

Answers

Answer:

136.3

Step-by-step explanation:

I assume it is asking you to add both 9.3x and 8.9y together. First you would multiply 9.3 by 7 and 8.9 by 8 which gives you 65.1 + 71.2 which equals 136.3.

A random sample of 10 employees of a company was selected to estimate the mean one-way commute time for all employees at the company. The mean and standard deviation of the sample were 38 minutes and 6 minutes, respectively. Assuming all conditions for inference are met, which of the following is the margin of error, in minutes, for a 95 percent confidence interval for the population mean one-way commute time? 1.812(610√) 1.812 times the fraction with numerator 6, and denominator the square root of 10 A 1.833(610√) 1.833 times the fraction with numerator 6, and denominator the square root of 10 B 1.96(610√) 1.96 times the fraction with numerator 6, and denominator the square root of 10 C 2.228(610√) 2.228 times the fraction with numerator 6, and denominator the square root of 10 D 2.262(610√)

Answers

Answer:

The margin of error is of [tex]2.262\frac{6}{\sqrt{10}} = 4.29[/tex]

Step-by-step explanation:

We have the standard deviation for the sample. So the T-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.262

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.262\frac{6}{\sqrt{10}} = 4.29[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

The given parameters are:

Sample size = 10Mean = 38Standard deviation = 6Confidence Interval = 95%

The margin of error is calculated using:

[tex]E = z_y \times \frac{\sigma}{\sqrt n}[/tex]

So, we have:

[tex]E = z_y \times \frac{6}{\sqrt {10}}[/tex]

The quantile at 95% confidence interval is 2.262

So, the equation becomes

[tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

Hence, the equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

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a Basketball ticket costs $45 but they are having a promotional game night and all tickets are 25% off what is the new price of the ticket​

Answers

Answer:

Should be $11.25

Step-by-step explanation:

Since 25% is 1/4 you can just divide 45 by 4.

45/4 = 11.25

Answer: 33.75. 25% of 45 is 11.25. So 45-11.25=33.75

Step-by-step explanation:

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