Confirm if this is correct or not. If it isn't correct, please correct it.

Answer:

Explanation:

According to newton's third law of motion, Action and reaction are equal and opposite, hence for an object that weighs 150N suspended by a wire, the tension on the wire is 150N

Ultimately the tension on a string or an object is equal to the mass times   gravity(which is same as the weight of the object)

Answer:

its 150

Explanation:

Answer:

1.2 kg m²

Explanation:

Angular momentum is conserved:

L = L

Iω = Iω

(4.6 kg m²) (1.0 rev / 1.5 s) = I (2.5 rev/s)

I = 1.2 kg m²

Answer:

16 seconds

Explanation:

To do this you would set up the equation 75x=1200. Then you would divide 75 from both sides so you get x=16 or it takes 12 seconds for it to travel 1200 meters

Answer:

Time = 16 s

Explanation:

Distance =Speed x Time

1200 = 75 x time

Time = 1200/75 = 16 sec

Answer:

Charge that will be left on sphere A is -8 x 10^-8 C

Explanation:

Number of electrons = 1.0 x 10^12 electrons

charge on an electron is = -1.6 × 10^-19 coulombs

for the number of electron, total charge = (1.0 x 10^12) x (-1.6 × 10^-19)

==> -1.6 x 10^-7 C

Since the two spheres were in contact when the charge was added to one of the spheres A, the sphere will then be distributed between the two spheres A and B equally. This means that after separation, sphere A will be left with

==> (-1.6 x 10^-7 C) ÷ 2 = -8 x 10^-8 C

Explanation:

A theory is a way of explaining an object or event using a set of facts.

Answer:

The direction of the acceleration of the mass is due East.

Explanation:

Data obtained from the question include the following:

Mass = 5 kg

Force due South = 10 N.

Force due East = 15 N.

To know which direction the acceleration of the mass will go, we must first obtain the resultant force.

This is illustrated below:

Resultant force = 15 – 10 = 5 N

Therefore, the resultant force is 5 N due East since the larger force is due East

Since the resultant force is due East, it means that the mass will accelerate toward the East.

According to the question,

The resultant force will be:

= [tex]15-10[/tex]

= [tex]5 \ N[/tex]

Since the larger force is due east. Thus the answer above is right.

Learn more about force here:

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Answer:

[tex]\displaystyle F_g = \frac{GM_1 m_2}{r^2}[/tex]

[tex]F_g[/tex] is the force.

[tex]G[/tex] is the gravitational constant.

[tex]M_1[/tex] is the mass of one object.

[tex]m_2[/tex] is the mass of the other object.

[tex]r[/tex] is the distance between the two objects.

Answer:

a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°

Explanation:

Given the following ;

From the triangle sketch :

Base length = 50 yards

Angle of elevation = 72°

a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?

Using trigonometry :

The height of the blimp will be calculated using :

Tangent :

Tan θ = opposite / Adjacent

B.) How high above the ground is the blimp?

Using :

Tan θ = opposite / Adjacent

Θ = 72° ; adjacent = 52, opposite = height(h)

Tan 72° = h / 50

h = 3.0776835 * 50

h = 153.88 yds

C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?

1 yard = 3 Feets

153.88 yards = 3 * 153.88

= 461.65 feets

No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.

To make viewing possible, the angle of elevation should be:

50 yards is equivalent to (3 * 50) = 150 feets

Max imum Height of blimp = 150 Feets

From pythagoras ;

Tanθ = 150 Feets / 150 Feets

Tanθ = 1

θ = tan^-1(1)

θ = 45°

To make viewing advertisement possible, angle of elevation should not exceed 45°

d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°

Answer:

0.25m/s

Explanation:

m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1

m1*0.50m/s=2m1*v2

V2= m1*0.50m/s÷2m1

V2= 0.25m/s

Answer:

Option d = all of the above.

Explanation:

This question is more of a driving lesson or tutorial Question and not that scientific, it is logical and the "rule" attached to reversing and driving that is operating of vehicles especially cars, trucks and so on.

All the options given in the Question from option 'a' to option 'c' are all correct when driving backwards that is reversing or backing . Driving backward(backing or reversing) is not as easy as during forward (drive mode).

=> " Position your right hand on the back of the passenger seat. Grip the steering wheel at the 12 o’clock position with your left hand"

REASON: FOR BALANCING.

=> " Move the wheel left or right in the direction in which you want the rear of the vehicle to go."

The above, given in the Question are all correct.

When backing straight or to the right, all of the mentioned options are correct and recommended practices are to Position your right hand on the back of the passenger seat. The correct option is option d.

a) Position your right hand on the back of the passenger seat: This is a technique used by some drivers to help them have a better sense of the vehicle's position and reference point while backing up.

b) Grip the steering wheel at the 12 o'clock position with your left hand: This hand position allows for better control and maneuverability of the steering wheel while backing up.

c) Move the wheel left or right in the direction in which you want the rear of the vehicle to go: This is the fundamental principle of steering while backing up. By turning the wheel in the desired direction, you can guide the rear of the vehicle in that direction.

Therefore, These practices can assist in improving control, visibility, and maneuverability while backing up, ensuring a safer and more effective backing maneuver. The correct option is option d.

To know more about the principle of steering:

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Answer:

acceleration is the answer

Answer:

Acceleration

Explanation:

Answer:

8.8 mT

Explanation:

Current through the conductor = 12.5 A

Magnetic force per unit length on the wire = 0.110 N/m

Recall that the magnetic force per unit length on a current carrying conductor is in a uniform magnetic field is

[tex]\frac{F}{l}= IBsin\alpha[/tex]

where B is the magnetic field magnitude

[tex]I[/tex] is the current in the conductor

α is the angle the conductor makes with the  magnetic field ( since it is perpendicular in this case, α is 90°)

imputing values into the equation, we'll have

0.11 = 12.5 x B x sin 90°

but sin 90° = 1, therefore, we have

0.11 = 12.5B

B = 0.11/12 = 8.8 x 10^-3 T

or rather = 8.8 mT

Answer:

[tex]D.\ 970\ N[/tex]

Explanation:

Given:

Mass of Piano: 99kg

Required:

Calculate its weight

The weight of an object is calculate as thus;

[tex]Weight = Mass\ (m) * Acceleration\ due\ to\ gravity\ (g)[/tex]

[tex]m = 99kg[/tex] and [tex]g = 9.8m/s^2[/tex]

The formula becomes

[tex]Weight = 99kg * 9.8m/s^2[/tex]

[tex]Weight = 970.2\ kgm/s^2[/tex]

[tex]Weight = 970.2\ N[/tex]

[tex]Weight = 970\ N[/tex] Approximated

Hence, the weight of the piano is 970N

Answer:

1.25x10^-19N

Explanation:see attached file pls

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

[tex]W = F\cdot \Delta s[/tex]

Where:

[tex]W[/tex] - Work, measured in joules.

[tex]F[/tex] - Force exerted on the object, measured in newtons.

[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]

[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]

[tex]W_{net} = (F-F)\cdot \Delta s[/tex]

[tex]W_{net} = 0\cdot \Delta s[/tex]

[tex]W_{net} = 0\,J[/tex]

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

[tex]W_{net} = W_{Joel}[/tex]

[tex]W_{net} = F\cdot \Delta s[/tex]

Hence, the work done by Joel is greater than the work done by Jerry.

Answer:

The correct answer is "By increasing the amount of flooding because of rising sea levels".

Explanation:

Answer:

[tex]f^{-1}(-4) = \frac{1}{10}[/tex]

Explanation:

Firstly finding [tex]f^{-1}(x)[/tex]

So,

[tex]f(x) = 10x-5[/tex]

Substitute [tex]y = f(x)[/tex]

[tex]y = 10x-5[/tex]

Exchange the values of x and y

[tex]x = 10y-5[/tex]

Solving for y

[tex]x = 10y-5[/tex]

Adding 5 to both sides

[tex]10y = x+5[/tex]

Dividing both sides by 10

[tex]y = \frac{x+5}{10}[/tex]

Replace [tex]y = f^{-1}(x)[/tex]

[tex]f^{-1}(x) = \frac{x+5}{10}[/tex]

For x = -4

[tex]f^{-1}(-4) = \frac{-4+5}{10}[/tex]

[tex]f^{-1}(-4) = \frac{1}{10}[/tex]

Answer:

[tex]\frac{1}{10}[/tex]

Explanation:

f(x) = y (output)

y = 10x - 5

Switch variables.

Solve for y.

x = 10y - 5

x + 5 = 10y

x/10 + 1/2 = y

[tex]f^{-1}(x)[/tex] = 1/10x + 1/2

Put x as -4.

1/10(-4) + 1/2

-4/10 + 1/2

-4/10 + 5/10

= 1/10

Answer:

Explanation:

1. A parsec is defined as the distance from the Sun which would result in a parallax of_TWO____ arcsecond as seen from Earth when observed 6 months apart.

2. One parsecs is about_3.3____light years

3. The more distant a star, the_LESS ____its parallax.

4. The statement "we can measure stellar parallax for most stars in our galaxy" is__TRUE .___.

5. The closest stars have parallaxes smaller than_.002 _____arcsecond.

6. The first successful measurements of stellar parallax were made by_Friedrich Bessel_____in year_1838_____for the star named.

7. Star Fred has parallax four times greater than star Bob. Star Fred is__4____times_nearer_____than star Bob.

Answer:

C

Explanation:

Answer:

c. A dog of mass 14 kg running with speed 6 m/sation:

Answer:

Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.

Explanation:

The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat

Hope this helps...

Have a nice day!!!!

Explanation:

Things you need to know:

Accuracy refers to the maximum error encountered when a particular observation is made.

Error in measurement is normally one-half the magnitude of the smallest scale reading.

Because one has to align one end of the rule or device to the starting point of the measurement, the appropriate error is thus twice that of the smallest scale reading.

Error is usually expressed in at most 1 or 2 significant figures.

Tape

Equipment: It is made up of a long flexible tape and can measure objects or places up to 10 – 50 m in length. It has markings similar to that of the rigid rule. The smallest marking could be as small as 0.1 cm or could be as large as 0.5 cm or even 1 cm.

How to use: The zero-mark of the measuring tape is first aligned flat to one end of the object and the tape is stretched taut to the other end, the reading is taken where the other end of the object meets the tape.

Ruler

Equipment: It is made up of a long rigid piece of wood or steel and can measure objects up to 100 cm in length. The smallest marking is usually 0.1 cm.

How to use: The zero-end of the rule is first aligned flat with one end of the object and the reading is taken where the other end of the object meets the rule.

Vernier Caliper

Equipment: It is made up of a main scale and a vernier scale and can usually measure objects up to 15 cm in length. The smallest marking is usually 0.1 cm on the main scale.

It has:

a pair of external jaws to measure external diameters

a pair of internal jaws to measure internal diameters

a long rod to measure depths

How to use: The jaws are first closed to find any zero errors. The jaws are then opened to fit the object firmly and the reading is then taken.

Micrometer Screw Gauge

Equipment: It is made up of a main scale and a thimble scale and can measure objects up to 5 cm in length. The smallest marking is usually 1 mm on the main scale (sleeve) and 0.01 mm on the thimble scale (thimble). The thimble has a total of 50 markings representing 0.50 mm.

It has:

an anvil and a spindle to hold the object

a ratchet on the thimble for accurate tightening (prevent over-tightening)

How to use: The spindle is first closed on the anvil to find any zero errors ( use the ratchet for careful tightening). The spindle is then opened to fit the object firmly (use the ratchet for careful tightening) and the reading is then taken.

Answer:

Yes great job it was well written!:)

Explanation:

Given,

I = 5 A

V = 240 V

T = 25 mins = 1500 sec

Now,

Energy dissipated = IVT= 5×240×1500 = 1800000 J

Answer:

some common devices that use current carrying conductors and magnetic fields are electric motor electric generator loudspeakers microphones and measuring instruments like galvanometer ammeter and voltmeter

Answer:

Explanation:

Magnetic field = permeability x turn density x current

Magnetic field = 0.22T

turn density = 4150 /1.6 = 2593.75 t/m

permeability : µ = k µ°

µ°= 4 π 10^-7

k = 1

I = 0.22 / 4 π 10^-7 * 2593.75 = 0.22 10^7 /32594 = 67.497 A

Answer:

v = 14.32 m/s

Explanation:

According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;

[tex]m_{1} u_{1}[/tex] + [tex]m_{2} u_{2}[/tex] = ([tex]m_{1}[/tex] + [tex]m_{2}[/tex]) v

0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v

0.420 + 1.800 = (0.155) v

2.22 = 0.155 v

⇒ v = [tex]\frac{2.22}{0.155}[/tex]

      = 14.323

The velocity of the balls after collision is 14.32 m/s.

Answer:

a)4500V

b)750V

Explanation:

Given:

Distance between the plate=

6.00 cm

We need to convert to m

Then the Distance between the plate=

0.06m

electric field strength between two parallel plates =

7.50 × 104 V/m .

Then E= 7.50 × 104 V/m .

(a) What is the potential difference between the plates?

potential difference between the plates can be calculated using the formula below

Δ Vab=ED

Where E is the given electric field strength

D= The Distance between the plate

ΔVab=7.50 × 10⁴V/m ×

0.06m

= 4500V

(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

the potential 1cm from the zero volt plate

Then the 1cm must be converted to m

= 0.01m

Let us say plate A as the plate at 0 volts:

The potential increases linearly going from plate A (0 V) to plate B (4500V).

Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also

If the plate with Lowest potential is taken to be zero then

=ΔVab=Vab-Vb=Va-0=Va=ED

Va=7.50 × 10⁴V/m × 0.01=750V

Answer:

15.96 m³ (corrected to 2 d.p.)

Explanation:

Using idea gas law:

pV = nRT

pressure p = 125000 Pa

volume V = unknown

no. of moles n= 3.27 moles

ideal gas constant R = 8.3145 J K−1 mol−1

Temperature t (in Kelvins) = 15 + 273.15 = 288.15K

125000 x v = 3.27 x 8.3145 x 288.15

v = 15.96 m³ (corrected to 2 d.p.)

Answer:

0.0626 m^3

Explanation:

First, we know that the equation to calculate the behavior of gases is:

PV=nRT

Looking at the problem, we understand that we are needing to solve for V, which means we need to isolate V to solve for it.

The new equation will look something like this:

V=nRT/P

The last step is to simply plug in the remaining variables:

n=3.27

R=8.31 (that is not given but is a standard number that you will always use for "R"/ the ideal gas constant-it helps to right it down somewhere to reference it if you ever need it!)

P=125000

T=288 (the temp needs to be in degrees K, so take 15.0 degrees c and + 273)

Finally, when you input all of those, you will have something that looks like this:

V=(3.27*8.31*288)/125000

V=0.02608205 m^3

V= 0.0626 m^3 (rounded to 3 sig. figs)

I hope this was helpful and easy to understand!

Answer:

Explanation: Let assume that bars are labeled A and B

Method 1

Using just the identical appearing bar magnet and unmagnetized iron bar.

Place the end of bar A in the middle of bar B.

If bar A sticks to bar B, then bar A is the magnet and bar B the umagnetized iron bar.

If bar A jumps to one of the ends of bar B, then bar B is the magnet.

Reason been that the magnetic field on a bar magnet is greatest at the two poles where the field comes out of the magnet. The center, between the poles, will be the weakest part of the field.

Method 2

Another solution would be to separate the two by quite some distance, float them on a piece of cork/wood in a plastic bucket or suspend them from long strings, then see which one consistently (eventually) lines up tending towards the Earth’s magnetic field.