The sales tax on clothing in Nebraska is 5.5%. Calculate how much tax you need to pay on a shirt if it costs $18.20 before tax. Round your answer to the nearest cent. ( pls answer asap and thanks ) will give BRANLIEST

Answer:

It took 31 days for the patch to cover half the lake

Step-by-step explanation:

The patch grows to double its size everyday

the patch completely covers the lake in 32 days

Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.

Therefore, the the patch covered half the lake on the 31st day, i.e it took 31 days for the patch to cover half the lake

Answer:

x = 28 degrees. 180 degrees in a triangle, 180-85-67=28

Answer:

28 degrees

Step-by-step explanation:

The interior angles of a triangle add up to 180 degrees.

The three angles given are: x, 85, and 67.

Therefore, these three angles must add to 180.

x+85+67=180

Combine like terms on the left. Add 85 and 67.

x+ (85+67)=180

x+152=180

We want to find x. We need to get x by itself. 152 is being added to x. The inverse of addition is subtraction. Subtract 152 from both sides.

x+152-152=180-152

x=180-152

x=28

x is 28 degrees.

Answer:

$3750 and $4250

Step-by-step explanation:

x + 500 = y

.045x + .035y = 317.50

.045x + .035(x + 500) = 317.50

.045x + .035x + 17.5 = 317.50

.08x = 300.00

x = 3750

y = 4250

Answer:

1) The inequality is $55 ≥ $11.50 × S + $2.75

2) Alonso can afford 4 boxes of sugar

Step-by-step explanation:

The given information are;

The total amount with Alonso = $55

The amount of eggs Alonso needs = 12 eggs

The costs of the pack of 12 eggs = $2.75

The number of packs of eggs Alonso buys = 1

The cost of each box of sugar =  $11.50

Let the number of boxes of sugar Alonso buys = S

Given that the total amount of money with Alonso is $55, then the inequality will be such that $55 will be equal to or larger than the expression for items bought

Therefore, the inequality is given as follows;

$55 ≥ $11.50 × S + $2.75

2) To find out how many boxes of sugar Alonso can afford, we have;

$55 ≥ $11.50 × S + $2.75

$55 - $2.75≥ $11.50 × S

$52.25 ≥ $11.50 × S

∴ S ≤ $52.25/$11.50 = 4.54

S ≤ 4.54 boxes of sugar

As the sugar comes in whole boxes, Alonso can therefore afford only 4 whole boxes of sugar.

Alonso can afford to buy 4 boxes of sugar.

An inequality to represent how many boxes of sugar can Alonso afford is 55 ≥ 2.75 + 11.50s

Given:

Amount with Alonso = $55

Package of 12 eggs = $2.75

Cost of each box of sugar = $11.50

let

s = number of boxes of sugar Alonso can afford

The inequality:

55 ≥ 2.75 + 11.50s

solve for s

55 - 2.75 ≥ 11.50s

52.25 ≥ 11.50s

divide both sides by 11.50

52.25 / 11.50 ≥ s

4.5434782608695 ≥ s

Alonso can only buy a whole box of sugar

Therefore, the number of boxes of sugar Alonso can afford is 4 boxes

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Answer:

100.

Step-by-step explanation:

Let the number of robberies be x ( in 2013).

Then x - 0.10x = 90

0.90x = 90

x = 90 / 0.90

= 100.

Answer:

Option B is the correct option.

Step-by-step explanation:

[tex]y = - 2x + 4...........(i)[/tex]

[tex]y = x - 5..........(ii)[/tex]

Equate ( i ) and ( ii ),

[tex] - 2x + 4 = x - 5[/tex]

Move variable to L.H.S and change its sign

Similarly, Move constant to R.H.S and change its sign

[tex] - 2x - x = - 5 - 4[/tex]

Calculate

[tex] - 3x = - 9[/tex]

Divide both sides of the equation by -3

[tex] \frac{ - 3x}{ - 3} = \frac{ - 9}{ - 3} [/tex]

Any expression divided by itself equals 1

[tex]x = \frac{ - 9}{ - 3} [/tex]

Dividing two negatives equals a positive [tex]( - ) \div ( - ) = ( + )[/tex]

[tex]x = \frac{9}{3} [/tex]

calculate the quotient

[tex]x = 3[/tex]

Value of X is 3

Now, put the value of X in equation ( i ) in order to find the value of y

[tex]y = x - 5[/tex]

plug the value of X

[tex] = 3 - 5[/tex]

Calculate

[tex] = - 2[/tex]

Value of y is -2

So, ( 3 , -2 ) is the solution of the given equation.

Hope this helps ....

Best regards!!

Answer:

Step-by-step explanation:

∠OAB is 90 degrees, tangent and a radius met at 90 degree angle

∠OCB=90 degrees, tan and radius meet at 90 degrees angle

OB=12

find angle BOC:

triangle BOA is right angle triangle:

cos(AOB)=adj/hyp=7/12=54.33

angle B= 180-(90+54.33)=35.67

angle COB=54.33 equal to angle AOB

angle AOC=54.33+54.33=108.66

the sum of angles of circle =360

360-108.66= 251.34( exterior angle at the center AOC)

length of the arc= angle (251.34 degrees*7)

convert degrees to radians=4.386 (251.34/π)

length=r*angle in radian=4.386*7=30.71

( i hope this is the answer)

Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now =  L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle =  800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) =  800 - 400 = 400 meters

Answer:

(A)[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the  following factors with multiplicity 1:

[tex]x-(2+i)\\x-\sqrt{2}[/tex]

We apply the following to find the factored form of the polynomial.

[tex]\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}[/tex]

Therefore, the factored form of the polynomial is:

[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]

Answer:

A

Step-by-step explanation:

EDGE 2021

Answer:

[15, ∞).

Step-by-step explanation:

–3(6 – 2x) ≥ 4x + 12

-18 + 6x ≥ 4x + 12

6x - 4x ≥ 12 + 18

2x ≥ 30

x ≥ 15

This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).

Hope this helps!

Answer:

P(X > 112) = 0.21186.

Step-by-step explanation:

We are given that the random variable X is normally distributed, with mean [tex]\mu[/tex] = 100 and standard deviation [tex]\sigma[/tex] = 15.

Let X = a random variable

The z-score probability distribution for the normal distribution is given by;

                               Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean = 100

            [tex]\sigma[/tex] = standard deviaton = 15

Now, the probability that the random variable X is greater than 112 is given by = P(X > 112)

      P(X > 112) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{112-100}{15}[/tex] ) = P(Z > 0.80) = 1- P(Z [tex]\leq[/tex] 0.80)

                                                       = 1 - 0.78814 = 0.21186  

The above probability is calculated by looking at the value of x = 0.80 in the z table which has an area of 0.78814.

The y-intercept is [tex](0,\frac{6}{2})=(0,3)[/tex] and there is no x-intercept since the equality can simplified to the point of obtaining a constant function [tex]y=3[/tex] which does not depend on x.

Hope this helps.

Answer:

Step-by-step explanation:

A of triangle = 1/2 * b * h

b = 6

h = 2

2 * 6 * 0.5

= 12 * 0.5

A of square = l * w

2 * 2

A of Triangle = 1/2 * b * h

2 * 2 * 0.5 =

4 * 0.5

2 + 4 + 6

= 6 + 6

Answer:

did you already try A???

Answer:

Probability : [tex]\frac{5}{33}[/tex]

Step-by-step explanation:

The probability of drawing an orange on the first attempt would be 5 / 12, considering that in this first attempt their are 5 oranges present out of a total of 12 fruits. Now after that fruit is chosen their are 4 out of 11 oranges present, such that the probability of drawing an orange on the second attempt would be 4 / 11.

Probability of choosing an orange on the first try : [tex]5 / 12[/tex]

Probability of choosing an orange on the second try : [tex]4 / 11[/tex]

Probability of selecting two oranges in a row ( blindfolded ) : [tex]5 / 12 * 4 / 11[/tex]

[tex]\frac{5}{12}\cdot \frac{4}{11}[/tex] ( cross cancel common factor 4 )

[tex]\frac{5}{3}\cdot \frac{1}{11}[/tex] ( multiply fractions )

[tex]\frac{5\cdot \:1}{3\cdot \:11}[/tex] = [tex]\frac{5}{3\cdot \:11}[/tex] = [tex]\frac{5}{33}[/tex] - the probability of selecting two oranges in a row blindfolded, is [tex]\frac{5}{33}[/tex].

Answer: it 70

Step-by-step explanation:

Latesha’s mother puts $85 in Latesha’s lunch account at school. Each day Latesha uses $3 from her account for lunch. The table below represents this situation.

How much is left in Latesha’s lunch account after she has had lunch for 5 days?

$15

$67

$82

you tube guests are for hire

Answer:

5.6

Step-by-step explanation:

(3÷3/4)÷5/7

[tex] \frac{3 \times 4}{3} \div \frac{5}{7} [/tex]

[tex]4 \div \frac{5}{7} [/tex]

[tex]4 \times \frac{7}{5} [/tex]

[tex] \frac{28}{5} [/tex]

=5.6

use "keep, change, flip " when dividing a number by a fraction.

keep the whole number

flip the divide sign to multiply

change the placement of number e.g. 5/7 becomes 7/8

then solve

Answer:

both are at the same distance

Step-by-step explanation:

Answer:

Austin and Devyn both have 1/3 of the way left on their way to school. They both also have walked the same amount.

Step-by-step explanation:

If Austin has to walk to his school, which could be said as 3/3 and Austin has already walked 2/3. Then if we conduct the equation 3/3-2/3=x. x=1/3. Now Devyn has already walked 4/6 of the way to school. If she has to walk a total of 6/6, then we can again make an equation 6/6-4/6=2/6. Now if we take the distance that they both have left to their school, its 1/3 and 2/6. These are both equavalent fractions because if you scale up 1/3, it equals to 2/6. Since they both have an equal amount of distance to travel, that must mean that they both have covered the same amount of distance already. We can double check to be sure. 2/3 *2/2=4/6. The reason we used 2/2 is because4/2=2 and 6/3=2.

Answer:

Option : Statistic because the value is a numerical measurement describing a characteristic of a sample.

Step-by-step explanation:

A sample of professors is selected and it is found that Modifying 35 % with underline own a television.

The 35% is the value that summarizes the characteristic of the sample taken from the population. Thus, the value 35% is a statistic.

While a parameter gives a value describing the characteristic of the population itself

Given: Sample proportion is (P)=[tex]35%[/tex]%.

Statistics are the constants that are computed from sample observations alone. This is a simple definition of statistics.

Answer: The correct statement is  Statistic because the value is a numerical measurement describing a characteristic of a population.

Explanation: That is, statistic because the value is a numerical measurement describing the characteristic of a sample.

The remaining statements are incorrect.

As parameters are the constants of the population. They describe only the population not the sample.

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Answer:

We have the problem:

|3r−15| if r<5

First we see the equality, if r = 5 we have:

I3r - 15I = I3*5 - 15I = I0I = 0.

Then the only restriction that we have is:

I3r - 15I > 0.

now, we could simplify it a bit further:

if r < 5, then the thing inside the absolute value will always be negative:

Then we can write:

I3*r - 15I = -(3*r -15) > 0

multiplying by -1 in both sides

(3r - 15) < 0.

if we keep simplifying this, we will get our initial restriction:

3r - 15 < 0

3r < 15

r < 15/3 = 5

r < 5

Answer:

Step-by-step explanation:

[tex]x^2+19x+70\ \implies a=1\,,\ b=19\,,\ c=70\\\\x=\frac{-19\pm\sqrt{19^2-4\cdot1\cdot70}}{2\cdot1}=\frac{-19\pm\sqrt{361-280}}{2}=\frac{-19\pm9}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-5\\\\x^2+19x+70=(x+14)(x+5)\\\\\\x^2-225=x^2-(15)^2=(x-15)(x+15)\\\\\\x^2-5x-150\ \implies a=1\,,\ b=-5\,,\ c=-150\\\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-150)}}{2\cdot1}=\frac{5\pm\sqrt{25+600}}{2}=\frac{5\pm25}{2}\ \Rightarrow\ x_1=-10\,,\ x_2=15\\\\x^2-5x-150=(x+10)(x-15)[/tex]

[tex]x^2+24x+140\ \implies a=1\,,\ b=24\,,\ c=140\\\\x=\frac{-24\pm\sqrt{24^2-4\cdot1\cdot140}}{2\cdot1}=\frac{-24\pm\sqrt{576-560}}{2}=\frac{-24\pm4}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-10\\\\x^2-5x-150=(x+14)(x+10)[/tex]

[tex]\dfrac{x^2+19x+70}{x^2-225}\,\cdot\,\dfrac{x^2-5x-150}{x^2+24x+140}=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{(x+10)(x-15)}{(x+14)(x+10)}=\\\\\\=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{x-15}{x+14}=\dfrac{x+5}{x+15}\cdot\dfrac11=\boxed{\dfrac{x+5}{x+15}}[/tex]

Answer:

The answer is option 3.

Step-by-step explanation:

First, you have to factorize the expressions :

[tex] \frac{ {x}^{2} + 19x + 70 }{ {x}^{2} - 225 } \times \frac{ {x}^{2} - 5x - 150}{ {x}^{2}24x + 140 } [/tex]

[tex] = \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]

Next, you have to cut out the common terms like (x + 14), (x - 15) and (x + 10):

[tex] \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]

[tex] = \frac{x + 5}{x + 15} [/tex]

Answer:

190

Step-by-step explanation:

the weight is 191 lbs rounded is 190

Answer:

The first term is 12. The common difference is 4.

Step-by-step explanation:

[tex] a_n = a_1 + d(n - 1) [/tex]

The difference between the third and seventh terms is

36 - 20 = 16

The 7th term is the 4th term after the 3rd term, so the common difference is

16/4 = 4

[tex] a_3 = a_1 + 4(3 - 1) [/tex]

[tex] 20 = a_1 + 4(3 - 1) [/tex]

[tex] 20 = a_1 + 8 [/tex]

[tex] a_1 = 12 [/tex]

Answer: The first term is 12. The common difference is 4.

Step-by-step explanation:

The equation is   sinθ * cosθ - sinθ = 0

θ = 0 + 2kπ

θ = 2kπ where k is any integer

The solutions to the equation are: {0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}

Hence, the correct option is C.

The given equation is:

sin theta × cos theta - sin theta = 0

We can factor out the sine theta:

sin theta (cos theta - 1) = 0

This means that either sin theta = 0 or cos theta - 1 = 0.

If sin theta = 0, then theta = 0, 180 degrees, 360 degrees, etc.

If cos theta - 1 = 0, then cos theta = 1, which means that theta = 0 degrees and 360 degrees.

Therefore, the solutions to the equation are:

{0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}

So the answer is C.

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Answer:

Step-by-step explanation:

Parallel lines have the same slope.

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

The point-slope form of an equation of a line:

y - y₁ = m(x - x₁)

(x₁, y₁) - point on a line

m - slope

We have the line y - 9 = 7(x + 5). The slope m = 7.

A) y - 9 = 3x + 4 → m = 3

B) y = -9x - 5 → m = -9

C) y + 5 = 7(x - 9) → m = 7

D) y - 9 = 5(x + 4) → m = 5

The line C) y + 5 = 7(x - 9) has the same slope.

Answer:

? = 3

Step-by-step explanation:

The parallel segments shown divide the sides in the ratio

[tex]\frac{6}{4}[/tex] = [tex]\frac{?}{2}[/tex] ( cross- multiply )

4? = 12 ( divide both sides by 4 )

? = 3

Answer: 3(x minus 5.50) = 111.75; the monthly Internet service is $42.75

Step-by-step explanation:

Given the following :

Total amount spent on internet for 3 months = $111.75

Monthly credit received on bill = $5.50

Monthly Credit of $5.50 means $5.50 is deducted from the amount being paid on thir bill monthly.

Assume their monthly internet service fee = x

The amount paid before the credit deduction each month:

Amount paid - credit

(x - $5.50)

For 3 months :

3 × (x - $5.50) = $117.75

3(x - $5.50) = $117.75

Monthly fee paid before credit deduction:

3(x - $5.50) = $117.75

3x - $16.50 = $117.75

3x = $117.75 + $16.50

3x = $128.25

x = $128.25 / 3

x = $42.75

Answer:

It's b !! :o]

Step-by-step explanation:

Answer:

16.704m

Step-by-step explanation:

To solve the above question, we are going to use the Trigonometric function of Sine.

sin θ = Opposite side/Hypotenuse

Where are given θ = 8°

Sin 8° = 0.1392

In the question, we are told that ,

A car travels 120m along a straight road that is inclined at 8° to the horizontal, hence,

Hypotenuse = 120m

We are asked to calculate the vertical distance through which the car rises hence,

Opposite side = vertical distance.

Therefore,

Sin 8° = Opposite/ 120m

Opposite = Sin 8° × 120m

Opposite = 0.1392 × 120m

Opposite = 16.704m

Therefore, the vertical distance through which the car rises is 16.704m

Answer:

Step-by-step explanation:

-9x + 6y = -30

-7x + 12y = -16

18x - 12y = 60

 -7x + 12y = -16

11x = 44

x = 4

-36 + 6y = -30

6y = 6

y = 1

(4,1)

Answer:

(4,1)

Step-by-step explanation:

-9x + 6y = -30.............(1)

-7x + 12y = -16 ............(2)

(2) - 2(1)

-7x+12y - 2(-9x+6y) = -16 - 2(-30)

simplify

11x = 44

or

x = 4 .......................(3a)

substitute (3) in (1)

-9(4) + 6y = -30

6y = -30 + 36

6y = 6

y =  1 ......................(3b)

Using results from (3a) and (3b), we have

solution :  (4,1)

Answer: D) Construct the perpendicular bisectors for AB and AC.

The intersection of all three perpendicular bisectors will form the circumcenter, which is the center of the circumcircle. This circle goes through all three corner points of the triangle. At minimum, you only need two perpendicular bisectors to get the job done. Choice B is close, but is missing that second perpendicular bisector.

The angle bisectors intersect to form the incenter, which is the center of the incircle (it's the largest possible circle to fit inside the triangle without spilling over).

Answer:

D.  Construct the perpendicular of ab and ac

Step-by-step explanation:

Circumscribe a Circle on a Triangle

Construct the perpendicular bisector of one side of the triangle.

Construct the perpendicular bisector of another side.

Where they cross is the center of the Circumscribed circle.

Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle

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Answer:

Postulate 3: Through any three points that are not one line, exactly one plane exists. State the postulate that verifies line segment AB is in plane Q when points A and B are in Q.

Step-by-step explanation:

Postulate 4: If two points lie in a plane, the line containing them lies in that plane. hope this helps you :)