A = 100(1+r)^4
Expand the right of this formula.
appreciate your help with an explanation

Answers

Answer 1

Answer:

100r^4 + 400r^3 + 600r^2 + 400r + 100

Step-by-step explanation:

Expanding ( r + 1 )^4 gives :-

r^4 + 4r^3 + 6r^2 + 4r + 1

So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-

100r^4 + 400r^3 + 600r^2 + 400r + 100


Related Questions

What is the quotient? URGENT!!

Answers

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

[tex] \frac{4x + 1}{6x} \div \frac{x}{3x - 1} [/tex]

[tex] = \frac{4x + 1}{6x} \times \frac{3x - 1}{x} [/tex]

[tex] = \frac{(4x + 1)(3x - 1)}{x(6x)} [/tex]

[tex] = \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} } [/tex]

[tex] = \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} } [/tex]

A study regarding the relationship between age and the amount of pressure sales personnel feel in relation to their jobs revealed the following sample information. At the 0.10 significance level, is there a relationship between job pressure and age.
(Round your answers to 3 decimal places.)
Degree of Job Pressure
Age (years) Low Medium High
Less than 25 25 27 20
25 up to 40 49 53 40
40 up to 60 59 59 52
60 and older 35 42 44
H0: Age and pressure are not related. H1: Age and pressure are related.
Reject H0 if X2 > .
X2=
(Click to select)Reject Do not reject H0. Age and pressure (Click to select)areare not related.

Answers

Answer:

Reject H0

Age and pressure are related

Step-by-step explanation:

The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value. In the given scenario we reject the null hypothesis because job pressure and age are related to each other.

Given the equation (x−13)2+y2=64, identify the center and radius. Do not enter any spaces when typing your answers.

Answers

Answer:

centre = (13,0)

radius = 8

Step-by-step explanation:

The standard equation of the circle is

(x-x0)^2 + (y-y0)^2 = r^2 ...............(1)

where

(x0,y0) is the centre,

r is the radius.

For

(x-13)^2 + y^2 = 64  ..............(2)

we rewrite (2)

(x-13)^2 + (y-0)^2 = 8^2 ...............(3)

and compare (3) with (1)

to identify

x0 = 13, y0 = 0, and r = 8

Therefore

centre = (13,0)

radius = 8

Find the volume of the given solid region in the first octant bounded by the plane 9z+15y+15z=45 and the coordinate​ planes, using triple integrals.

Answers

First,

[tex]9x+15y+15z=45\implies 3x+5y+5z=15[/tex]

The volume is given by the integral (one of 6 possible combinations),

[tex]\displaystyle\int_0^5\int_0^{\frac{15-3x}5}\int_0^{\frac{15-3x-5y}5}\mathrm dz\,\mathrm dy\,\mathrm dx=\boxed{\frac{15}2}[/tex]

Compute the following values when the log is defined by its principal value on the open set U equal to the plane with the positive real axis deleted.

a. log i
b. log(-1)
c. log(-1 + i)
d. i^i
e. (-i)^i

Answers

Answer:

Following are the answer to this question:

Step-by-step explanation:

The principle vale of Arg(3)

[tex]Arg(3)=-\pi+\tan^{-1} (\frac{|Y|}{|x|})[/tex]

The principle value of the [tex]\logi= \log(0+i)\ \ \ \ \ _{where} \ \ \ x=0 \ \ y=1> 0[/tex]

So, the principle value:

a)

[tex]\to \log(i)=\log |i|+i Arg(i)\\\\[/tex]

             [tex]=\log \sqrt{0+1}+i \tan^{-1}(\frac{1}{0})\\\=\log 1 +i \tan^{-1}(\infty)\\\=0+i\frac{\pi}{2}\\\=i\frac{\pi}{2}[/tex]

b)

[tex]\to \log(-i)= \log(0-i ) \ \ \ x=0 \ \ \ y= -1<0\\[/tex]

Principle value:

[tex]\to \log(-i)= \log|-i|+iArg(-i) \\\\[/tex]

                 [tex]=\log \sqrt{0+1}+i(-\pi+\tan^{-1}(\infty))\\\\=\log1 + i(-\pi+\frac{\pi}{2})\\\\=-i\frac{\pi}{2}[/tex]

c)

[tex]\to \log(-1+i) \ \ \ \ x=-1, _{and} y=1 \ \ \ x<0 and y>0[/tex]

The principle value:

[tex]\to \log(-1+i)=\log |-1+i| + i Arg(-1+i)[/tex]

                     [tex]=\log \sqrt{1+1}+i(\pi+\tan^{-1}(\frac{1}{1}))\\\\=\log \sqrt{2} + i(\pi-\tan^{-1}\frac{\pi}{4})\\\\=\log \sqrt{2} + i\tan^{-1}\frac{3\pi}{4}\\\\[/tex]

d)

[tex]\to i^i=w\\\\w=e^{i\log i}[/tex]

The principle value:

[tex]\to \log i=i\frac{\pi}{2}\\\\\to w=e^{i(i \frac{\pi}{2})}\\\\=e^{-\frac{\pi}{2}}[/tex]

e)

[tex]\to (-i)^i\\\to w=(-i)^i\\\\w=e^{i \log (-i)}[/tex]

In this we calculate the principle value from b:

so, the final value is [tex]e^{\frac{\pi}{2}}[/tex]

f)

[tex]\to -1^i\\\\\to w=e^{i log(-1)}\\\\\ principle \ value: \\\\\to \log(-1)= \log |-1|+iArg(-i)[/tex]

                [tex]=\log \sqrt{1} + i(\pi-\tan^{-1}\frac{0}{-1})\\\\=\log \sqrt{1} + i(\pi-0)\\\\=\log \sqrt{1} + i\pi\\\\=0+i\pi\\=i\pi[/tex]

and the principle value of w is = [tex]e^{\pi}[/tex]

g)

[tex]\to -1^{-i}\\\\\to w=e^(-i \log (-1))\\\\[/tex]

from the point f the principle value is:

[tex]\to \log(-1)= i\pi\\\to w= e^{-i(i\pi)}\\\\\to w=e^{\pi}[/tex]

h)

[tex]\to \log(-1-i)\\\\\ Here x=-1 ,<0 \ \ y=-1<0\\\\ \ principle \ value \ is:\\\\ \to \log(-1-i)=\log\sqrt{1+1}+i(-\pi+\tan^{-1}(1))[/tex]

                    [tex]=\log\sqrt{2}+i(-\pi+\frac{\pi}{4})\\\\=\log\sqrt{2}+i(-\frac{3\pi}{4})\\\\=\log\sqrt{2}-i\frac{3\pi}{4})\\[/tex]

Select the type of equations. Consistent. Equivalent. Inconsistent

Answers

Answer:

Consistent.

Step-by-step explanation:

Since there is one solution ( the lines intersect), the equations are consistent

They would be inconsistent if the lines do not intersect

The would be equivalent if they are the same line

The answer would be consistent.

Step-by-step explanation:

In the graph shown here, there is only one solution

because the lines intersect at the point (5, 3).

In order for the lines to be inconsistent, the lines would have to not

meet or intersect each other but notice that this is not the case here.

The would be equivalent if they are the same exact line

so it would look like there would just be one line.

k/4 + 3= 14 k = pls help

Answers

Answer:

k = 44

Step-by-step explanation:

k/4 + 3 = 14

k/4 = 11

k = 44

Answer:

[tex]\boxed{\sf k=44}[/tex]

Step-by-step explanation:

[tex]\sf \frac{k}{4} +3=14[/tex]

Subtract 3 from both sides.

[tex]\sf \frac{k}{4} +3-3=14-3[/tex]

[tex]\sf \frac{k}{4}=11[/tex]

Multiply both sides by 4.

[tex]\sf \frac{k}{4}(4)=11(4)[/tex]

[tex]\sf k=44[/tex]

Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 4.5 m^3. Syrus isn't sure if the tent will be tall enough for him to stand inside. What is the height of the tent?

Answers

Answer: 2neters

Step-by-step explanation: I also recently did it on Khan academy

The height of the tent of the figure is H = 2 m

What is the volume of a prism?

A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.

The volume of a prism is the product of its base area and height

Volume of Prism = B x h

where B = base area of prism

h = height of prism

Given data ,

Let the volume of the tent be represented as V

Now , the value of V is

V = 4.5 m³

Let the height of the prism be H

Now , the base of the triangle B = 1.5 m

And , the length of the tent L = 3 m

So , Volume of Prism = B x h

4.5 = ( 1/2 ) x 1.5 x H x 3

On simplifying , we get

4.5 = 2.25H

Divide by 2.25 on both sides , we get

H = 2 m

Hence , the height of the tent is 2 m

To learn more about volume of prism click :

https://brainly.com/question/11336446

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The complete question is attached below :

Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 4.5 m^3. Syrus isn't sure if the tent will be tall enough for him to stand inside. What is the height of the tent?

These two polygons are similar.

Answers

Answer:

[tex]\huge\boxed{z=3}[/tex]

Step-by-step explanation:

If two polygons are similar, then corresponding sides are in proportion.

The corresponding sides:

4 → x

y → 15

3 → w

2 → 6

z → 9

therefore:

[tex]\dfrac{z}{9}=\dfrac{2}{6}[/tex]         cross multiply

[tex](z)(6)=(9)(2)[/tex]

[tex]6z=18[/tex]         divide both sides by 6

[tex]z=3[/tex]

Answer:

Step-by-step explanation:

Test the given claim. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, and then state the conclusion about the null​ hypothesis, as well as the final conclusion that addresses the original claim. Among 2160 passenger cars in a particular​ region, 243 had only rear license plates. Among 358 commercial​ trucks, 55 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.05 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval.

Answers

Answer:

For 0,90 of Confidence we reject H₀

For  0,95 CI we reject H₀

Step-by-step explanation:

To evaluate a difference between two proportion with big sample sizes we proceed as follows

1.-Proportion 1

n = 2160

243 had rear license  p₁ = 243/2160     p₁ = 0,1125

2.Proportion 2

n = 358

55   had rear license   p₂ = 55/ 358     p₂ = 0,1536

Test Hypothesis

Null Hypothesis                            H₀      ⇒   p₂   =  p₁

Alternative Hypothesis                Hₐ     ⇒    p₂  >  p₁

With signficance level  of  0,05  means  z(c) = 1,64

T calculate   z(s)

z(s) =  ( p₂ - p₁ ) / √ p*q ( 1/n₁  +  1/n₂ )

p = ( x₁  +  x₂ ) / n₁  +  n₂

p = 243  +  55 / 2160 + 358

p = 0,1183     and then    q = 1 -  p     q =  0,8817

z(s) =  ( 0,1536 - 0,1125 ) / √ 0,1043 ( 1/ 2160   +  1 / 358)

z(s) =  0,0411 /√ 0,1043*0,003256

z(s) = 0,0411 / 0,01843

z(s) =  2,23

Then  z(s) > z(c)      2,23  >  1,64

z(s) is in the rejection region we reject H₀

If we construct a CI for  0,95   α = 0,05   α/2  =  0,025

z (score ) is  from z- table    z = 1,96

CI = ( p ±  z(0,025*SE)

CI = ( 0,1536 ± 1,96*√ 0,1043*0,003256 )

CI = ( 0,1536 ± 1.96*0,01843)

CI = ( 0,1536 ± 0,03612 )

CI = ( 0,11748  ;  0,18972 )

In the new CI we don´t find  0 value so we have enough evidence to reject H₀

What is 0.09% written as a decimal?
A. 0.9
B. 0.009
C. 0.0009
D. 0.09

Answers

Answer:

C. 0.0009

Step-by-step explanation:

0.09/100

= 0.0009

Answer:A

Step-by-step explanation:0.09=0.9

In the news, you hear “tuition is expected to increase by 7% next year.” If tuition this year was $1200 per quarter, what will it be next year?

Answers

Answer: $1284 per quarter

Step-by-step explanation:

Answer:

$5136

step by step:

this year tuition-1200

in a year there are 4 quarters

so total this yr is 1200×4=4800

Next year

tuition is 100%+7%per 4months

so

1.07×1200=1284per month

per year 1284×4=5136

Fifty students are enrolled in a Business Statistics class. After the first examination, a random sample of 5 papers was selected. The grades were 60, 75, 80, 70, and 90. a) Determine the standard error of the mean

Answers

Answer:

The standard error  S.E of the mean is 5

Step-by-step explanation:

From the given data;

Fifty students are enrolled in a Business Statistics class.

After he first examination, a random sample of 5 papers was selected.

Now; let consider a random sample of 5 papers was selected. with the following grades : 60, 75, 80, 70, and 90

The objective of this question is to determine the standard error of the mean

In order to achieve this ; we need to find the mean and the standard deviation from the given data.

TO start with the mean;

Mean [tex]\overline X[/tex] = [tex]\dfrac{1}{n} \sum x_i[/tex]

Mean [tex]\overline X[/tex] = [tex]\dfrac{1}{5} (60+75+80+70+90)[/tex]

Mean [tex]\overline X[/tex] = 0.2(375)

Mean [tex]\overline X[/tex] = 75

On the other hand; the standard deviation is :

[tex]s = \sqrt{\dfrac{1}{n-1}\sum(x_i - \overline X)^2}[/tex]

[tex]s = \sqrt{\dfrac{1}{5-1}((60-75)^2+(75-75)^2+(80-75)^2+(70-75)^2+(90-75)^2 )}[/tex]

[tex]s = \sqrt{\dfrac{1}{4}(225+0+25+25+225 )}[/tex]

[tex]s = \sqrt{\dfrac{1}{4}(500 )}[/tex]

[tex]s = \sqrt{125}[/tex]

s = 11.18

Finally; the standard error  S.E of the mean is:

[tex]S.E = \dfrac{s}{\sqrt{n}}[/tex]

[tex]S.E = \dfrac{11.18}{\sqrt{5}}[/tex]

[tex]S.E = \dfrac{11.18}{2.236}[/tex]

[tex]S.E = 5[/tex]

The standard error  S.E of the mean is 5

Please! help and tell me the answers, or help me figure out these answers for 20 points? please! And please help me. Can anybody help me?

Answers

Answer:

1. Pattern (rule) : y = x-6

2. Pattern (rule) : y=x^2+1

3. Pattern (rule)  : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

Step-by-step explanation:

Note: question number correspond to your order of questions.

1. Pattern (rule) : y = x-6

for missing parts, see attached table.

2. Pattern (rule) : y=x^2+1

3. Pattern (rule)  : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

6th grade math, help me please:)

Answers

Answer:

21

Step-by-step explanation:

Just like a dilation you want to find some sort of scale factor. Now when 7/2 is simplified it then becomes 3.5. Now multiply that by 6 since we are trying to find the ratio. when multiplied by 6 it becomes 21 so the ration of wins to losses is 21/6

Katie wants to create a rectangular frame for a picture. She has 60 inches of material. If she wants the length to be 3 more than 2 times the width what is the largest possible length

Answers

Answer:

Largest possible length is 21 inches.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = [tex]l[/tex] inches and

Width = [tex]w[/tex] inches

As per given condition:

[tex]l = 2w+3[/tex] ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

[tex]P = 2 \times (Width + Length)[/tex]

Putting the given values and conditions as per equation (1):

[tex]60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch[/tex]

Putting in equation (1):

[tex]l = 2\times 9+3\\\Rightarrow l = 21\ inch[/tex]

So, the answer is:

Largest possible length is 21 inches.


An experiment involves 17 participants. From these, a group of 3 participants is to be tested under a special condition. How many groups of 3 participants can
be chosen, assuming that the order in which the participants are chosen is irrelevant?

Answers

Answer: 680

Step-by-step explanation:

When order doesn't matter,then the number of combinations of choosing r things out of n = [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

Given: Total participants = 17

From these, a group of 3 participants is to be tested under a special condition.

Number of groups of 3 participants chosen = [tex]^{17}C_3=\dfrac{17!}{3!(17-3)!}\[/tex]

[tex]^{17}C_3=\dfrac{17!}{3!(17-3)!}\\\\=\dfrac{17\times16\times15\times14!}{3\times2\times14!}\\\\=680[/tex]

Hence, there are 680 groups of 3 participants can  be chosen,.

The principal P is borrowed at a simple interest rate r for a period of time t. Find the simple interest owed for the use of the money. Assume there are 360 days in a year. P​ = ​$7000​, r​ = ​0.2%, t​ = 6months

Answers

Answer:

$7

Step-by-step explanation:

Simple interest formula:

I = Prt

6 months = 6 * 30 days = 180 days

1 year = 360 days

t = (180 days)/(360 days) = 0.5

I = $7000 * 0.002 * 0.5

I = $7

Answer:

$7

Step-by-step explanation:

Recall that simple interest is given by

I = Prt,

Where :

I = interest (we are asked to find this)

P = principal amount = given as $7000

r = rate = given as 0.2% = 0.002

t = time in years = given as 6 months = 0.5 years

SImply substitute the known values into the equation above:

I = Prt

= (7000)(0.002)(0.5)

= $7

Calculate the volume of a cube with sides measuring 2.5 metres

Answers

Answer:

15.625 m³

Step-by-step explanation:

The volume of a cube has a formula: V = a³

V = volume

a = side length

The side length is given 2.5 meters.

V = 2.5³

Solve for V.

V = 15.625

The volume is 15.625 cubic meters.

Answer:

15.625cm^3

Step-by-step explanation:

Formula:

V=lxwxh

Given:

l=2.5m

w=2.5m

h=2.5m

Answer:

V=lxwxh

V=2.5m*2.5m*2.5m

V=6.25m^2*2.5m

V=15.625m^3

Hope this helps :)

A merchant had a batch of 120 face shields. If you sold 5/6 of the lot yesterday, how many protectors do you have to sell?

Answers

Answer:

Step-by-step explanation:

lot = 120 face shields

sold 5/6 of 120 =

5 × 120 ÷ 6 =

600 ÷ 6 = 100 sold of the lot.

then: 120-100 = 20

They need to sell 20 protectors.

Answer:

20 face shields.

Step-by-step explanation:

You have 120 face shields.

You sell 5/6 of them. That means that you still have to sell 1 - 5/6 = 1/6 of the lot.

120 * (1/6) = 20 * 1 = 20 face shields to sell.

Hope this helps!

Which value for x makes the sentence true?
3/4x+ 4 = 7

1)4
2) 44/3
3) -3
4) 8

Answers

Answer:

x=4

Step-by-step explanation:

3/4x+ 4 = 7

Subtract 4 from each side

3/4x+ 4-4 = 7-4

3/4x = 3

Multiply each side by 4/3

4/3 * 3/4 x = 3 * 4/3

x = 4

what is the domain and range of the relation shown?

Answers

Answer:

A.

{-4 ≤ x ≤ 4}

{-4 ≤ y ≤ 4}

Step-by-step explanation:

We’ll domain is the amount of x values,

Range is the amount of y values

_______________________________

Domain:

Starts from -4 to 4

{-4 ≤ x ≤ 4}

I made the sign less than or equal to because the circle lines are solid.

Range:

This starts from -4 to 4 also.

{-4 ≤ y ≤ 4}

Thus,

answer choices A. is correct

Hope this helps :)

Hey there! I'm happy to help!

Note that this is not a function because some inputs can have more than one output, that's why they say relation, not function! :D

DOMAIN

The domain is all of the possible x-values of the relation.  We see that the lowest x-value is -4, while the highest is 4. If you plug in these two or any number in between, there will be at least one corresponding output.

This domain can be written as -4 ≤ x ≤ 4.

RANGE

The range is all of the possible outputs or y-values. We see that the minimum y-value is -4 and that the highest is 4. Therefore, we will just write it the same as the domain but use a different variable.

-4 ≤ y ≤ 4.

This matches with Option A.

I hope that this helps! Have a wonderful day!

Five times a number is divided by $7$ more than the number. If the result is $2$, then what was the original number? please help!

Answers

Answer:

3

Step-by-step explanation:

Because the number 5 is a number that you get from 7 more than n, and 2 is the other divisor that means n must equal 10 and 7 less than 10 is 3.

When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.

What are linear equations in one variable?

Linear equations are first-order equations. Lines in the coordinate system are determined by linear equations. A linear equation in one variable is defined as an equation with a homogeneous variable of degree 1 (i.e. only one variable).

How to solve the given question?

In the question, we are asked to find a number, which satisfies the statement, "Five times a number is divided by 7 more than the number. The result of this division is 2".

We assume the number to be x.

Now we try to form a linear equation in one variable from the given statement.

Five times a number is 5x.

7 more than a number is x + 7.

We are said that five times a number is divided by 7 more than a number. This can be shown as 5x/(x + 7).

Now, the result is given as 2, which can be shown as:

5x/(x+ 7) = 2, which is the required linear equation in one variable.

To get the number, we solve the equation using the following steps:

5x/(x+ 7) = 2

or, {5x/(x+ 7)}*(x + 7) = 2*(x + 7) (Multiplying both sides by (x + 7))

or, 5x = 2x + 14 (Simplifying)

or, 5x - 2x = 2x + 14 - 2x (Subtracting 2x from both sides)

or, 3x = 14 (Simplifying)

or, 3x/3 = 14/3 (Dividing both sides by 3)

or, x = 14/3 (Simplifying)

∴ When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.

Learn more about the linear equation in one variable at

https://brainly.com/question/24145091

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A basketball coach is curious about the heights of players in the league. Let the proportion of basketball players who are over 72 inches be p. If the coach wanted to know if the proportion of basketball players who are over 72 inches is more than 85%, what are the null and alternative hypothesis? Select the correct answer below: H0: p=0.85; Ha: p<0.85 H0: p>0.85; Ha: p=0.85 H0: p=0.85; Ha: p>0.85 H0: μ=0.85; Ha: μ>0.85

Answers

Answer:

H0: p=0.85;

Ha: p>0.85

Step-by-step explanation:

What was being tested is that:

the coach wanted to know if the proportion of basketball players who are over 72 inches is more than 85%.

The null hypothesis which we are testing against would be that the proportion of basketball players who are over 72 inches is 85%.

H0: p=0.85;

Ha: p>0.85

All sides of the building shown above meet at right angles. If three of the sides measure 2 meters, 7 meters, and 11 meters as shown, then what is the perimeter of the building in meters?

Answers

Answer:

69 meters

Step-by-step explanation:

Answer:

Please privately chat to us why you chose to cheat during online class, otherwise we will contact your parents and kick you out of our program for the reason stated.

Step-by-step explanation:

Please contact your Quantitive Reasoning teacher at her email, as stated in Google Classroom.

Which relation is a function?

Answers

Answer:

A

Step-by-step explanation:

A function is that of which has only one x value. Therefore you are looking for the graph that does not have multiple x values. Doing a vertical line test to see whether there is more than one point on a line of the graph will show you that A is the only one that has one answer for each x value that is given. All the other graphs have two points for some of the x's, which makes them not a function.

Two ballpoint pens are selected at random from a box that contains3 blue pens, 2 red pensand 3 green pens. If X is the number of blue pens

Answers

Answer:  3/(28) ≈ 10.7%

Step-by-step explanation:

3 blue + 2 red + 3 green = 8 total pens

   First pick    and           Second pick

 [tex]\dfrac{3\ blue\ pens}{8\ total\ pens}\quad \times \quad \dfrac{2\ remaining\ blue\ pens}{7\ remaining\ total\ pens}\quad =\large\boxed{\dfrac{3}{28}}[/tex]  

A random sample of 64 students at a university showed an average age of 20 years and a sample standard deviation of 4 years. The 90% confidence interval for the true average age of all students in the university is

Answers

Answer:

The 90%  confidence level is  [tex]19.15< L < 20.85[/tex]

Step-by-step explanation:

From the question we are told that

     The sample size is  [tex]n = 64[/tex]

     The mean age is  [tex]\= x = 20 \ years[/tex]

      The standard deviation  is   [tex]\sigma = 4 \ years[/tex]

 

Generally  the degree of freedom for this data set is mathematically represented as

        [tex]df = n - 1[/tex]

substituting values

        [tex]df = 64 - 1[/tex]

        [tex]df = 63[/tex]

Given that the level of confidence is  90%  the significance level is mathematically evaluated as

          [tex]\alpha = 100 - 90[/tex]

         [tex]\alpha =[/tex]10 %  

         [tex]\alpha = 0.10[/tex]

Now   [tex]\frac{\alpha }{2} = \frac{0.10}{2} = 0.05[/tex]

Since we are considering a on tail experiment

The  critical value for half of  this significance level at the calculated  degree of freedom is obtained from the critical value table as

           [tex]t_{df, \frac{ \alpha}{2} } = t_{63, 0.05 } = 1.669[/tex]

   The margin for error is mathematically represented as

          [tex]MOE = t_{df , \frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]

substituting values  

          [tex]MOE = 1.699 * \frac{4 }{\sqrt{64} }[/tex]

         [tex]MOE = 0.85[/tex]

he 90% confidence interval for the true average age of all students in the university is evaluated as follows

           [tex]\= x - MOE < L < \= x + E[/tex]

substituting values  

         [tex]20 - 0. 85 < L < 20 + 0.85[/tex]

         [tex]19.15< L < 20.85[/tex]

hey guys can you please help me with this. i’m really desperate please help anything helps. thank u :(

Answers

Answer:

- 29 / 20

Step-by-step explanation

The cosec (x) = 1 / sin(x)

There are 2 ways to do this:

Either using a calculator:

sin^-1(20 / 29) = 43.60281897

so inputting into 1/sin(-x) where x = 43.6.....

This gives: -29 / 20

OR

1 / sin(x) = cosec ( x)

so cosec (x) = 1/(20/29)

= 29/20

By observing the cosec(x) graph, we see that to get cosec (-x), all we need to do is to minus our answer seeing as the graph is symmetrical across the axes. Therefore x = -29/20

slope=4/3 find the equation of the parallel line through (5,5)

Answers

Answer:

[tex]y=\frac{4}{3}x-1.75[/tex]

Step-by-step explanation:

If the slope of a line is 4/3,

and we wanna find the equation of a line that is parallel to it and crosses through (5,5).

So we already have the slope because the slope of 2 parallel lines are the same.

y = 4/3x

Look at the image below↓

So now we just need to find the y-intercept.

After some numbers we got,

[tex]y=\frac{4}{3}x-1.75[/tex]

Look at the other image below↓

Thus,

the equation of the parallel line is [tex]y=\frac{4}{3}x-1.75[/tex].

Hope this helps :)

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