Which two values are irrational?
370
A
9
B 2.910
CV52
D 150
33
E
4

Answer:

The answer would be y=-1/3x+1.

Step-by-step explanation:

To find the slope, you must use the formula y2-y1/x2-x1. That would make it 1-2/0-(-3) which the slope is -1/3. Now, using the formula y-y1=m(x-x1) which would be y-2=-1/3(x-(-3) if you plug it in. Solving the equation, you would get y=-1/3x+1.

Answer:

(3)(6)

Step-by-step explanation:

I did the quiz

George could have used the expression (0.30)(60) to determine 30% of 60.

George could have used the expression (0.10)(6)(0.10)(60) to determine 30% of 60.

(0.10) represents 10% or 0.10 as a decimal. Since 30% is three times 10%, George can use three instances of (0.10) to represent 30%.

(6) represents the value 6, which is the number being multiplied by the percentage.

(0.10)(60) represents 10% of 60, which is 6.

Multiplying (0.10)(6)(0.10)(60) gives us the result of 6, which is 30% of 60.

Therefore, George could have used the expression (0.10)(6)(0.10)(60) to calculate 30% of 60.

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#SPJ2

Answer:

Terminating

Step-by-step explanation:

Just did it!

Answer:

-5.236 is a terminating decimal. I hope this helps you!

a. 2√21 units

Hi there !

Area formula

A = π·r²

84π = πr²

r² = 84π/π

r² = 84

r² = 2²×3×7

r = √2²×3×7

r = 2√3×7

r = 2√21

Good luck !

Answer:

-2(x+2)(4x-35)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

B, D, and E

Step-by-step explanation:

Answer: 1.28

Step-by-step explanation:

$6.84 divided by 3 = 3.28

$10.24 divided by 4 = 4.56

3.28 - 4.56 = 1.28

Hope this helps!

(If you need me to explain more just comment)

Answer:

Step-by-step explanation:

Every linear equation that is a conditional equation has one solution. However, not every linear equation in one variable has a single solution. There are two other cases: no solution and the solution set of all real numbers. resulting value on the right side will always be one greater than the value on the left side.

Answer:

Every linear equation that is a conditional equation has one solution. However, not every linear equation in one variable has a single solution. There are two other cases: no solution and the solution set of all real numbers. resulting value on the right side will always be one greater than the value on the left side.

Step-by-step explanation:

Answer:

thousandths

hope this helpsss

Answer: 385

Step-by-step explanation:

Mean the three groups of 10 kids=35

Total weight of 3 groups (10x35)=350

Mean weight of 3 groups and one boy  ( 35 + 350)=385

8x^(2)+3x-18, simplified,

Answer:

Solve for  

x

by simplifying both sides of the inequality, then isolating the variable.

Step-by-step explanation:

Answer:

Does the name, Josh, Sound familiar? Maybe that'll ring a bell of why I'm saying this.

Step-by-step explanation:

Answer:10

Step-by-step explanation:

I guessed

The area of the rectangle is 200 square cm

The radius of the circle is given as:

[tex]r = 5cm[/tex]

The width of the rectangle is made by 2 circles (i.e. 4 radii).

So, we have:

[tex]Width = 4r[/tex]

The length of the rectangle is made by 1 circle (i.e. 2 radii).

So, we have:

[tex]Length = 4r[/tex]

The area of the rectangle is then calculated as:

[tex]Area =Length * Width[/tex]

This gives

[tex]Area = 2r * 4r[/tex]

[tex]Area = 8r^2[/tex]

Substitute 5 for r

[tex]Area = 8 * 5^2[/tex]

[tex]Area = 200[/tex]

Hence, the area of the rectangle is 200 square cm

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Answer:

if its not simplified then 18/5 but if it has to be simplified then its 3 3/5

Answer:

2x + 5 ≤ x - 3

Step-by-step explanation:

Answer:

[tex]2x + 1 < 5[/tex]

Answer:

The area of the shaded part is 100 [tex]cm^2[/tex]

Step-by-step explanation:

Subtracting Areas:

We can find the shaded area by adding or subtracting areas.

We'll use the latter method.

The total shape is a rectangle of side lengths 15 cm and 10 cm. Thus its area is:

[tex]A_t=15\ cm\cdot 10\ cm=150\ cm^2[/tex]

The area of each non-shaded square is:

[tex]A_s=(5\ cm)^2=25\ cm^2[/tex]

The total non-shaded area is

[tex]2*A_s=50\ cm^2[/tex]

Thus, the shaded area is:[tex]A_{shaded}=A_t-2*A_s=150 - 50 = 100[/tex]

The area of the shaded part is 100 [tex]cm^2[/tex]

Answer:

Step-by-step explanation:First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

5m +5n+6m−4n

Next, group like terms:

5m+6m+5n−4n

Now, combine like terms:

(5+6)m+(5−4)n

11m+1n

11m+n

9514 1404 393

Answer:

Step-by-step explanation:

1. The graph looks like the vertex is at x = -1/2. So we can start with the equation y = (x +1/2)^2 +k. At x=0, this becomes 1 = 1/4 +k, or k = 3/4. The leading coefficient of 1 is consistent with the other points shown, so the equation is ...

  y = (x +1/2)^2 +3/4 . . . . vertex is (-1/2, 3/4)

  y = x^2 +x +1

__

2. The zeros appear to be at x=1 and x=4, so the factored form of the equation is ...

  y = a(x -1)(x -4)

At x = 0, this is ...

  12 = a(-1)(-4)

  3 = a

So, the equation is ...

  y = 3x^2 -15x +12

The values at the two points of interest are ...

  y = 3(-2-1)(-2-4) = 54 . . . . point (-2, 54)

  y = 3(5 -1)(5 -4) = 12 . . . . point (5, 12)

__

3. Using the vertex shown, the vertex form of the equation is ...

  y = a(x -2)^2 +7

Filling in the point (-2, -1), we can find the value of a:

  -1 = a(-2-2)^2 +7

  -8 = 16a

  a = -8/16 = -1/2

So, the equation is ...

  y = -1/2x^2 +2x +5

For x=0, the y-value is 5. The y-intercept is (0, 5).

Answer:

9514 1404 393

y = x^2 +x +1; (-1/2, 3/4)

y = 3x^2 -15x +12; (-2, 54), (5, 12)

y = -1/2x^2 +2x +5; (0, 5)  

1. The graph looks like the vertex is at x = -1/2. So we can start with the equation y = (x +1/2)^2 +k. At x=0, this becomes 1 = 1/4 +k, or k = 3/4. The leading coefficient of 1 is consistent with the other points shown, so the equation is ...

 y = (x +1/2)^2 +3/4 . . . . vertex is (-1/2, 3/4)

 y = x^2 +x +1

Answer:

no solution

Step-by-step explanation:

Step-by-step explanation:

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Asymptotes f(x)=(2x^2)/(x^2-1)

f

(

x

)

=

2

x

2

x

2

−

1

Find where the expression

2

x

2

x

2

−

1

is undefined.

x

=

−

1

,

x

=

1

The vertical asymptotes occur at areas of infinite discontinuity.

x

=

−

1

,

1

Consider the rational function

R

(

x

)

=

a

x

n

b

x

m

where

n

is the degree of the numerator and

m

is the degree of the denominator.

1. If

n

<

m

, then the x-axis,

y

=

0

, is the horizontal asymptote.

2. If

n

=

m

, then the horizontal asymptote is the line

y

=

a

b

.

3. If

n

>

m

, then there is no horizontal asymptote (there is an oblique asymptote).

Find

n

and

m

.

n

=

2

m

=

2

Since

n

=

m

, the horizontal asymptote is the line

y

=

a

b

where

a

=

2

and

b

=

1

.

y

=

2

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x

=

−

1

,

1

Horizontal Asymptotes:

y

=

2

No Oblique Asymptotes

Answer:

that depends on the year. like round from 2020?

Step-by-step explanation:

Answer:

$78.25

Step-by-step explanation:

Each adult = $11.50

Each child = $8.75

3 adults and 5 children

(11.50 x 3) + (8.75 x 5)

34.5 + 43.75 = $78.25

11.50 x 3 = 34.50

8.75 x 5 = 43.75

34.50 + 43.75 = 78.23

$78.23

Answer:

a. remain the same

b. decrease

c. remain the same

d. t decreases

the answers are in bold letters under each question. Thank you

Step-by-step explanation:

a. A switch from using a two-tailed test to a one-tailed test

A switch from 2 tailed test to one tailed test will have t statistic remain the same. This does not change the value of t statistic

b. An increase in the sample variance (s^2)

when sample variance s^2 is increased, we will have it that standard error has increased. therefore t statistic will decrease

c. An increase In the significance level (such as using α= 0.05 instead of σ= 0.02)

t statistics will remain the same. this is due to the fact that significance level is not a part of the t statistics formula.

d. A decrease in the sample Size (n)

when sample size is decreased, standard error will increase. therefore t statistic will decrease.

The use of student-test implies:

The solution is:

a) t(s) will be the same

b) t(s) will decrease

c) t(s) will be the same

d) t(s) will decrease

a) To calculate t(s), we use the equation:

t(s) = (μ  -  μ₀)/s/√n         (1)

where:

μ is sample mean

μ₀ is the population mean

s is sample standard deviation

n sample size

As  we can see, t(s) does not depend on the confidence level (α), therefore changing confidence level,  would not affect t(s) value

b) Increasing s²,  will make t(s) decrease as from equation (1)

c) As explained in letter a), t(s) does not depend on α. Hence, changing α, would not affect the value of t(s)

d) If the sample size n  decrease t(s) will decrease

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Answer:

Y = 2x^2+12x+44 (standard form / quadratic form)

Step-by-step explanation:

2(x+3)^2+26

2(x^2+6x+9) + 26

2x^2+12x+18+26

2x^2+12x+44

Answer:

  x = 4/5

Step-by-step explanation:

Subtract 3/x+4, then multiply by x/5:

  [tex]\dfrac{3}{x}+9=\dfrac{7}{x}+4\\\\5=\dfrac{4}{x}\\\\\boxed{x=\dfrac{4}{5}}[/tex]

_____

If you meant 3/(x+9) = 7/(x+4), you need to write it with parentheses around the denominator. (In that case, x=-12.75.)