Answer:
a) 3.66 s
b) 124.4 m
c) 3.12s
Explanation:
Given that
Speed of the Red Car, v₁ = 34 m/s
Speed of the Blue Car, v₂ = 28 m/s
Distance between the two cars, d = 22 m
The difference between the speed of the cars is: 34 - 28 = 6 m/s
From this, we can deduce that the red car will be catching up to the blue car at a speed of 6 m/s.
1)
If we divide the distance by the difference in speed. This becomes
d/v = 22/6 = 3.66 s. Which means, It takes 3.66 seconds for the red car to meet up with the blue car.
2
From the previous part, we were able to confirm that it took 3.66 seconds for the red car to meet up the blue car. Also, the speed with which it were traveling was travelling at, was constant, so we only need to multiply it by the time from (1) to get the distance.
v = d * t = 34 * 3.66 = 124.4
Therefore the red car travels at 124.4 m before catching up to the blue car.
3
If the red car starts to accelerate the moment we see it, the time it will take, to get to the blue car will be less than what we had gotten. We can find this using one of the equations of motion.
S = ut + ½gt², where
S = 22
u = 6
t = ?
g = 2/3
22 = 6t + 1/3t²
By using the quadratic formula, we find out the two answers listed below
t1 = 3.12 s
t2 = - 21.12 s
We all know that negative time is not possible, so the answer is t1. At 3.12 seconds
While making some observations at the top of the 63 m tall Astronomy tower, Ron
accidently knocks a 0.5 kg stone over the edge. How fast will the stone be moving when
it hits the ground?
Analysing the Question:
We are given:
height of the tower (h) = 63 m
mass of stone (m) = 0.5 kg
initial vertical velocity of the stone (u) = 0 m/s [ since the stone fell, there was no force applied on it to go downwards]
final vertical velocity of the stone (v) = v m/s
acceleration of the stone due to gravity (a) = 10 m/s² [we are letting g = 10]
** We will be neglecting air resistance in this answer**
Finding the final velocity of the stone:
from the third equation of motion
v² - u² = 2ah
replacing the variables
v² - (0)² = 2(10)(63)
v² = 1260
v = √1260
v = 35.5 m/s
create a body composition and agility chart.
PLEASE HELP
And also help me with my math and my brother work.
PLEASE
Answer:
I think this is something you're looking for so I hope they help
Explanation:
If the height of a lab table in a classroom is 0.60 m, how long would it take for a ball launched off the edge of these tables to reach
the floor?
Explanation:
Using the equation of motion S = ut+1/2gt² where;
S is the height of the table = 0.60m
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.81m/s²
t is the time taken
Substitute
0.6 = 0+1/2(9.81)t²
0.6 = 4.905t²
t² = 0.6/4.905
t² = 0.1223
t = √0.1223
t = 0.3497
t≈0.35secs
Hence it will take 0.35seconds for a ball launched off the edge of these tables to reach the floor
What is the formula for the compound formed between Na and Se?
Answer:
gold
Explanation:
The higher the altitude then _________ the air pressure... *
lower
higher
hotter
colder
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Physics,
Since we know that, earth is surrounded by a atmosphere, hence on the surface we have high air density but at a higher altitude there is less air, thus pressure of air also less,
The higher the Altitude then lower the air pressure..
Does density depend on the amount of stubstance that you have ? explain your answer
You cause a particle to move from point A, where the electric potential is 14.7 V, to point B, where the electric potential is −24.5 V. Calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, a proton, a neutral hydrogen atom, and a singly ionized helium atom (i.e., lacking one electron from its neutral state).
Answer:
Explanation:
If a particle to move from point A, where the electric potential is 14.7 V, to point B, where the electric potential is −24.5 V, the change in electric potential is expressed as:
∆V = VB-VA
Given VB = -24.5V
VA = 14.7V
∆V = -24.5-14.7
∆V = -39.2V
To calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, we will use the formula:
∆U = q∆V where q is the charge on the electron
Charge on an electron = -1.6×10^-19C
∆U = -1.6×10^-19C×-39.2
∆U = 62.72×10^-19 Joules
For a proton:
q = 1.6×10^-19C
∆U = 1.6×10^-19C×-39.2
∆U = -62.72×10^-19 J (calculation is similar as above, the only difference is the sign)
For a neutral hydrogen atom:
Charge on a neutral hydrogen atom is +1
∆U = 1×-39.2
∆U = -39.2Joules
For a singly ionized helium atom
Charge on the atom q = +1
∆U = 1×-39.2
∆U = -39.2Joules
Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown below.
What is his average acceleration from 0 to 10 seconds?
Answer: its actually 0
Explanation: i read the khan academy hints and the answer is 0
yes the answer is 0 and if its not and have this graph its -2.0
Calculate the net force (N) acting
on an object with the following: 5 N
to the right and 10 N to the left.
Answer:
Explanation:
its unbalanced
Which state is made up of separated electrons and positive ions?
Answer: Plasma
Explanation: It's particles are ionized and just took quiz
Answer:
plasma
Explanation:
PLEASE HELP!!
A picnic basket falls out of a hot air balloon that is traveling horizontally at 14 m/s. The hot air balloon is
at an altitude of 250 m. Where does the picnic basket land relative to where it was dropped from?
Answer:
99.9999 m
Explanation:
[tex]a_{x} =0[/tex] [tex]v_{xo} =14[/tex] [tex]a_{y} =-g[/tex] [tex]v_{yo} =0[/tex]
X-direction | Y-direction
[tex]x=x_{o}v_{xo}t+\frac{1}{2} a_{x}t^2[/tex] | [tex]y=y_{o}v_{yo}t+\frac{1}{2} a_{y}t^2[/tex]
[tex]x=0+14(7.14285)[/tex] | [tex]0=250-\frac{1}{2} (-9.8)t^2[/tex]
x = 99.9999 m | [tex]-250=-4.9t^2[/tex]
| [tex]\sqrt{\frac{-250}{-4.9} } =\sqrt{t^2}[/tex]
| 7.14285s = t
Analysing the Question:
We are given:
height of the hot air balloon (h) = 250 m
horizontal velocity of hot air balloon (p) = 14 m/s
Since the balloon had no vertical velocity, the basket will drop vertically at a velocity of 0 m/s and gain its velocity due to acceleration
whereas the horizontal velocity of the balloon is 14 m/s, so the basket will have a horizontal velocity of 14 m/s when falling
there will be no change in the horizontal velocity of the basket since there is no force against the horizontal velocity of the falling basket
Time taken by the basket to reach the ground:
from the last section, we deduced that:
initial vertical velocity (u) = 0 m/s
time taken by the basket to reach the ground (t) = t seconds
acceleration of the basket due to gravity (a) = 10 m/s²
from the second equation of motion:
h = ut + 1/2*at²
replacing the variables
250 = (0)t + 1/2 * (10)(t)²
250 = 5t²
t² = 50
t = √50
t = 5√2 seconds OR 7 seconds
Horizontal distance travelled by the basket:
Distance travelled = horizontal speed * time taken to reach the ground
Distance travelled = 14 * 7
Distance travelled = 98 m
The diagram shows a ball resting at the top of a hill.
Which statement best describes the energy in this
system?
Х
O The potential energy in the system is greatest at X.
O The kinetic energy in the system is greatest at X.
O Total energy in the system decreases as the ball
moyes from X to Y.
O Tofd energy in the system increases as the ball
moves from X to Y.
Y
Answer:
the answer is A The potential energy in the system is greatest at X.
Explanation:
i know things
A certain light truck can go around a curve having a radius of 119 m with a maximum speed of 30 m/s. To have the same acceleration, at what maximum speed can it go around a curve having a radius of 59.5 m
Answer:
The maximum speed is 21.1 m/s
Explanation:
Given that,
Radius of curve = 119 m
Maximum speed = 30 m/s
New radius = 59.5 m
We need to calculate the maximum acceleration
Using formula of acceleration
[tex]a_{c}=\dfrac{v^2}{r}[/tex]
Where, v = maximum speed
r = radius
a = acceleration
Put the value into the formula
[tex]a_{c}=\dfrac{30^2}{119}[/tex]
[tex]a_{c}=7.5\ m/s^2[/tex]
We need to calculate the maximum speed
Using formula of speed
[tex]v_{max}=\sqrt{a\times r}[/tex]
Put the value into the formula
[tex]v_{max}=\sqrt{7.5\times59.5}[/tex]
[tex]v_{max}=21.1\ m/s[/tex]
Hence, The maximum speed is 21.1 m/s
A stone is thrown straight up at an upward speed of 8.0 m/s from the top of the cliff. The stone hits the ground and stops 5.0 s later. What is the height of the cliff?
Answer:
22
Explanation:
4. Two identical charges are 25cm apart. They repel each other with the force of 2 x 10-6 Find Each
charge?
Answer:
Both charges are of the same sign (positive or negative) and with a value of 3.73 ηc.
Explanation:
Coulomb's Law
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
We know both charges are identical, i.e. q1=q2=q. Since the force is repulsive, both charges are positive or negative.
We also are given the force between them:
[tex]F=2\cdot 10^{-6}\ N[/tex]
And also the distance
d=25 cm = 0.25 m
Substituting all into the formula:
[tex]\displaystyle 2\cdot 10^{-6}=9\cdot 10^9\frac{q.q}{0.25^2}[/tex]
The product of [tex]q.q=q^2[/tex]. Operating:
[tex]\displaystyle 2\cdot 10^{-6}=9\cdot 10^9\frac{q^2}{0.0625}[/tex]
Operating:
[tex]\displaystyle 0.0625\cdot 2\cdot 10^{-6}=9\cdot 10^9\cdot q^2[/tex]
Solving for q:
[tex]\displaystyle q^2=\frac{0.0625\cdot 2\cdot 10^{-6}}{9\cdot 10^9}[/tex]
[tex]q^2=1.39\cdot 10^{-17}[/tex]
[tex]q=\sqrt{1.39\cdot 10^{-17}}=3.73\cdot 10^{-9}\ c= 3.73\ \eta c[/tex]
Both charges are of the same sign (positive or negative) and with a value of 3.73 ηc.
Read the following scenario and decide if it is a hypothesis, theory or law.
Sue is camping and decides to drop a rock off a cliff. She finds a small rock, drops it.
and notes that it takes approximately two seconds to land. She then finds a somewhat
larger rock and concludes that the bigger rock should take less than two seconds to
land because it is bigger.
Answer:
Law
Explanation:
This is newton's second law of motion.
PLEASE HELP!!
A football kicker lines up to kick a game winning kick. The goalpost is 30m away and the ball must clear the
3.3m high cross-bar. If the kick leaves his foot at an angle of 35 degrees, how fast must the kick be to be
good (assuming no one blocks it)?
Answer:
19.26 m/s
Explanation:
I will put a photo
A car goes from 80 kn/h to 20 km/h in 0.5 h. What is the acceleration in km/h^2? *
Answer:
In physics, acceleration is defined as the rate of change of the velocity of an object with respect to time. That is A = VF - VI /T; Where A = Acceleration VF = Final velocity = 20 km VI = Initial velocity = 80 km T= Time = 0.5 hr A = (20 - 80)/ 0.5 = - 60/.5 A = - 120 Km/ hr^2 Therefore, the acceleration of the car is -120 km/hr^2. Because the value is negative, the appropriate name that describe it is deceleration.I Hope this helps
The surface of an insulating sphere (A) is charged up uniformly with positive charge, and brought very close to an identical–size conducting sphere (B) that has no net charge on it. The spheres do not make contact.
A) Sketch the distribution of charge on each sphere.
B) Will the spheres attract, repel, or not interact with each other? Explain.
C) When the spheres make contact, they repel each other. Explain this behavior.
Answer:
A) A negative charge of value Q is induced on sphere B
B) there is an attraction between sphere
C) The charge of sphere A is distributed between the two spheres,
Explanation:
This is an electrostatic problem, in general charges of the same sign attract and repel each other.
with this principle let's analyze the different situations
A) The sphere A that is insulating has a charge on its surface and zero charge is its interior
The conducting sphere B has zero charge, but the sphere A creates an attraction in the electrons, therefore a negative charge of the same value as the charge of the sphere A is induced in the part closest and in the part farther away than one that a positive charge.
A negative charge of value Q is induced on sphere B
B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge
C) When the two spheres come into contact, the charge of sphere A is distributed between the two spheres, therefore each one has a positive charge of value half of the initial charge, as now we have net positive charges in the two spheres charges of the same sign repel each other so the spheres separate
Because of your knowledge of physics, you have been hired as a consultant for a new James Bond movie, "Oldfinger". In one scene, Bond jumps horizontally off the top of a cliff to escape a villain. To make the stunt more dramatic, the cliff has a horizontal ledge a distance h beneath the top of the cliff which extends a distance LL from the vertical face of the cliff. The stunt coordinator wants you to determine the minimum horizontal speed, in terms of L and h, with which Bond must jump so that he misses the ledge.
Answer:
v = [√(g/2h)]L
Explanation:
Let v be the initial horizontal velocity, t be the time James Bond uses to jump over the ledge of length, L.
So, vt = L and t = L/v
Also, since James Bond has no initial horizontal velocity, he falls freely through the distance, h so we use the equation y - y' = ut - 1/2gt², where y = 0 (at the top of the cliff) and y' = -h, u = 0 (initial vertical velocity), g = acceleration due to gravity = 9.8 m/s² and t = the time it takes to jump off the cliff = L/v.
Substituting these values into the equation, we have
y' - y = ut - 1/2gt²
-h - 0 = 0 × t - 1/2g(L/v)²
-h = - 1/2gL²/v²
v² = gL²/2h
taking square root of both sides, we have
v = [√(g/2h)]L
So, James Bond's minimum horizontal speed is v = [√(g/2h)]L
A penguin is trying to cross the street. It’s velocity v as a function of time t is given in the graph below where rightwards is the positive velocity given. At what time does the penguib have the same positition as t = 0s?
Answer:
3.5
Explanation:
Khan Academy gives the answer here.
The Problems: 1. Xavier starts at a position of 0 m and moves with an average speed of 0.50 m/s for 3.0 seconds. He normally moves faster than this but he'd just woken up. Determine his final position. 2. A hedgehog starts at a position of 0 m and moves with an average speed of 0.75 m/s for 4.0 s. Determine the final position of the hedgehog. 3. A tortoise starts at a position of 1.0 m and moves with an average speed of 1.25 m/s for 3.0 s, what is the final position of the tortoise? Cintia, in a 100 m race, has an average speed of 1.25 m/s. What was her race time? 5. Angel runs a marathon with an average speed of 5 miles/hour. How long did it take to finish?
Answer:
(1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
Explanation:
(1). Given that,
Initial position = 0 m
Average speed = 0.50 m/s
Time = 3.0 s
We need to calculate the final position
Using formula of average speed
[tex]v_{av}=\dfrac{x_{f}+x_{i}}{t}[/tex]
Where, [tex]x_{f}[/tex] = final position
[tex]x_{i}[/tex] = Initial position
t = total time
Put the value into the formula
[tex]0.50=\dfrac{x_{f}+0}{3.0}[/tex]
[tex]x_{f}=0.50\times3.0[/tex]
[tex]x_{f}=1.5\ m[/tex]
(2). Given that,
Initial position = 0 m
Average speed = 0.75 m/s
Time = 4.0 s
We need to calculate the final position
Using formula of average speed
[tex]v_{av}=\dfrac{x_{f}+x_{i}}{t}[/tex]
Put the value into the formula
[tex]0.75=\dfrac{x_{f}+0}{4.0}[/tex]
[tex]x_{f}=0.75\times4.0[/tex]
[tex]x_{f}=3\ m[/tex]
(3). Given that,
Average speed = 1.25 m/s
Time = 3.0 sec
Initial position = 1.0 m
We need to calculate the final position
Using formula of average speed
[tex]v=\dfrac{x_{f}+x_{i}}{t}[/tex]
Put the value into the formula
[tex]1.25=\dfrac{x_{f}+1.0}{3.0}[/tex]
[tex]x_{f}=1.25\times3.0-1.0[/tex]
[tex]x_{f}=2.75\ m[/tex]
(4). Given that,
Average speed = 1.25 m/s
Distance = 100 m
We need to calculate the time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
Put the value into the formula
[tex]t=\dfrac{100}{1.25}[/tex]
[tex]t=80 sec[/tex]
(5). Given that,
Average speed = 5 miles/hr
Suppose, distance = 25 miles
We need to calculate the time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
Put the value into the formula
[tex]t=\dfrac{25}{5}[/tex]
[tex]t=5\ hr[/tex]
Hence, (1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
How could you increase electric force using each factor
Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. Electrical forces are extremely sensitive to distance.
The increment of the electric force by each factor should be explained below.
What is electric force?An electric force refers to the interaction of the attractive force or the repulsive force that lies between two charged bodies. In the case when there should be increment in the separation distance that lies between the objects so it reduced the attraction force. Due to the reduction in the seperate distance there should be an increment in the attraction force. Also, the electric force should be very sensitive with respect to the distance.
Learn more about electric force here: https://brainly.com/question/17562167
Different colors of light are associated with different wavelengths.
Answer:
yepp
Explanation:
you sure is right
A ball is dropped from the top of a building and hits the street below in 4.25 s. How tall is the building? Show work for brainliest.
Answer:
90.3125 m
Explanation:
[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]
a = 10m/s^2 (constant)
S=height
U=initial velocity
a= gravitational acceleration
t= time
s = 0 + 1/2 * 10 * 4.25 ^2
u is 0 because it is dropped without velocity
s =90.3125 m
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational field strength of Planet X?
Answer:
B . The gravitational field strength of Planet X is Wx/m.
Explanation:
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational field strength of Planet X?
A . The gravitational field strength of Planet X is mg.
B . The gravitational field strength of Planet X is Wx/m.
C . The gravitational field strength of Planet X is 9.8 N/kg.
D . The gravitational field strength of Planet X is m.Wx.
Step 1: Given data
Mass of the ball: m
Weight of the ball on Planet X: Wx
Gravitational field strength of Planet X: g
Step 2: Determine which is a correct expression for the gravitational field strength of Planet X
According to Newton's second law, the acceleration (a) of an object is directly related to the net force (F) and inversely related to its mass (m), which is seen in the following expression.
a = F/m
In our case, the net force is represented by the weight of the ball on Planet X and the acceleration is that due to the gravitational field strength of Planet X. The resulting expression is:
g = Wx/m
Here, we are required to provide a correct expression for the gravitational field strength of planet X where a ball of mass m is found to have a weight Wx.
A correct expression for the gravitational field strength of planet X is; Wx/m.The mass of an object, m is a measure of the quantity of matter present in the object. Mass is therefore constant irrespective of location.
However, the weight of an object, W is a measure of the gravitational field strength of the object as quantified by the acceleration due to gravity of that location.The mathematical relationship between the Weight of an object, it's mass and the gravitational field strength is as follows;Wx = m × a
Since acceleration due to gravity a, is a measure of the gravitational field strength, an expression that represents the gravitational field strength of planet X is;a = Wx/m
Read more:
https://brainly.com/question/21335480
If you find a solid-surface world in our solar system with few craters, what has occurred there?
Answer:
Bruh
Explanation:
I think
Moments later, your friend passes the ball back up to you. Your friend throws it straight
upwards at a speed of 16.6 m/s. If you catch it when it is still travelling upward at 5.3
m/s how far apart are you and your friend?
Analysing the question:
since the ball is thrown upwards, the gravity will be applied opposite to the motion of the ball
We are given:
acceleration due to gravity (a) = -10 m/s²
initial upward velocity (u) = 16.6 m/s
final upward velocity (v) = 5.3 m/s
distance between the friends (s) = s m
Neglecting air resistance
Solving for the distance between the friends:
from the first equation of motion
v = u + at
replacing the variables
5.3 = 16.6 + (-10)(t)
-10(t) = 5.2 - 16.6
-10 (t) = -11.3
t = 1.13 seconds
from the second equation of motion
s = ut + 1/2 at²
replacing the variables
s = (16.6)(1.13) + -5(1.13)²
s = 18.8 - 6.4
s = 12.4 m
Therefore, the 2 friends are 12.4 m apart
What is the acceleration of the object at t = 4s?
Answer:
no answer of this bcuz to find aclleration.initial velocity and final velocity too... I think question is wrong
2. Who bombarded molybdenum with atomic number (Z=42) with fast moving
neutrons?
Answer:
This question appears incomplete
Explanation:
This question appears incomplete, however Molybdenum-99 (⁹⁹Mo) is produced by bombarding Molybdenum-98 (⁹⁸Mo) with fast moving neutrons (¹₀n) as shown below
⁹⁸₄₂Mo + ¹₀n ⇒ ⁹⁹₄₂Mo + ⁰₀γ
This reaction is a nuclear caption reaction (which occurs in a nuclear reactor) for the production of Molybdenum-99 (⁹⁹Mo) which serves as a "precursor" for the production of medically viable/ Clinical Grade Technutium-99m (⁹⁹Tc) through Ion-exchange technique.