Which of the following plant organs may act as a source for translocation of sugars inside a plant?
a Young growing leaves
b Mature leaves
c Developing flowers
d Any non-green tissue

The periosteal and meningeal layers of the dura mater are two tough membranes that surround and protect the brain. These layers form the outermost protective layer of the brain known as the cranial dura mater. The periosteal layer is the outermost layer and is attached to the skull bones.

The meningeal layer is the innermost layer and is fused to the periosteal layer except in certain areas where they separate to form dural sinuses.

Together, the periosteal and meningeal layers enclose a space known as the subdural space. This space is filled with a thin layer of fluid that helps cushion and protect the brain from any sudden movements or shocks. The dura mater also plays a vital role in the maintenance of the brain's blood supply, as it contains numerous blood vessels that help to nourish the brain. In summary, the periosteal and meningeal layers of the dura mater play a crucial role in protecting the brain and providing it with the necessary blood supply to function properly.

To know more about blood supply click this link-

brainly.com/question/31715597

#SPJ11

The statement is False. While smoking cigarettes can indeed cause genetic mutations in tumor-suppressor genes, it is not the only way in which smoking induces the formation of lung cancer.

Lung cancer is a type of cancer that begins in the cells of the lungs. The lungs are the organs responsible for oxygenating the blood and removing carbon dioxide. There are two types of lung cancer: small cell lung cancer (SCLC) and non-small cell lung cancer (NSCLC), with NSCLC being the more common type. Lung cancer typically begins in the cells that line the bronchi or bronchioles, which are the tubes that lead to the lungs. The cancer cells can then grow and spread to other parts of the lung or to other parts of the body.

Lung cancer is often caused by smoking, but exposure to other substances such as asbestos, radon, and air pollution can also increase the risk. Symptoms of lung cancer can include coughing, shortness of breath, chest pain, and weight loss. Treatment for lung cancer may involve surgery, chemotherapy, radiation therapy, or a combination of these treatments.

To learn more about Lung cancer visit here:

brainly.com/question/16427743

#SPJ4

Histone H4 is required for DNA-dependent nucleosome assembly.

It binds to the histone chaperone protein Nucleosome Assembly Protein 1 (NAP1) Complex Factor (PNCF), which helps to facilitate the assembly of nucleosomes. Histone H4 is a core histone protein that plays a crucial role in DNA packaging within cells. It helps to form the histone octamer, which is made up of two copies of histones H2A, H2B, H3, and H4. These histones assemble with DNA to form nucleosomes, which are the basic building blocks of chromatin. The assembly of nucleosomes requires the involvement of histone chaperone proteins, such as the Nucleosome Assembly Protein 1 (NAP1) Complex Factor (PNCF). H4 binds to PNCF, and together they help to promote the proper assembly of nucleosomes, ensuring the proper organization and function of DNA within cells.

To know more about nucleosome please visit:

https://brainly.com/question/16681455

#SPJ11

The correct statement about the gas exchange system in fish is that it relies on the parallel flow of blood and water in the gills. As water flows over the gill filaments, blood flows in the opposite direction through the capillaries within the filaments.

This allows for the efficient exchange of oxygen and carbon dioxide across the thin gill membranes. Oxygen diffuses from the water into the blood, while carbon dioxide diffuses from the blood into the water. This is an efficient system, as it maintains a steep concentration gradient for oxygen and allows for a high rate of gas exchange.

The other statements are not accurate - oxygen moves from higher to lower partial pressure, and while oxygen does diffuse across the entire length of the gill capillaries, this is not the primary mechanism for gas exchange. Additionally, the partial pressure of oxygen is actually lower in water than in air.

Learn more about gas exchange here:

https://brainly.com/question/821370

#SPJ11

DNA polymerase is an enzyme that plays a vital role in the replication of DNA. It is most active during the S phase of the cell cycle, and it is required for the construction of the lagging strand during DNA replication.

Here, correct option is C.

This enzyme is responsible for catalyzing the formation of a new DNA strand by adding nucleotides to an existing strand of DNA. DNA polymerase is also involved in the repair of damaged DNA, which helps to maintain the integrity of the genetic material.

In addition, DNA polymerase is essential in the process of transcription, which involves the conversion of DNA into mRNA. Together, these processes ensure that the genetic information contained within DNA is accurately and faithfully transmitted to the next generation.

Therefore, correct option is C.

know more about DNA polymerase here

https://brainly.com/question/14315652#

#SPJ11

The additional volume of air the patient inspires above the tidal volume is the  : Inspiratory Reserve Volume (IRV)

Inspiratory Reserve Volume (IRV) is the extra amount of air that a person can inhale after taking a normal breath (tidal volume).

The additional volume of air inspired above the tidal volume is known as the Inspiratory Reserve Volume (IRV).

This helps in increasing the oxygen available to the body during increased physical activity or when more oxygen is required.

Hence,  The additional volume of air inspired above the tidal volume is known as the Inspiratory Reserve Volume (IRV).

learn more about Inspiratory Reserve Volume (IRV) click here:

https://brainly.com/question/30056385

#SPJ11

The great cardiac vein runs alongside the anterior interventricular artery.

The great cardiac vein is a major blood vessel in the heart that runs alongside the anterior interventricular artery. This vein collects deoxygenated blood from the anterior portion of the heart and drains it into the coronary sinus, which then empties into the right atrium of the heart. The anterior interventricular artery, also known as the left anterior descending artery, is responsible for supplying oxygenated blood to the anterior walls of the left ventricle and the interventricular septum. It is one of the major arteries in the heart and is often involved in coronary artery disease.

In summary, the great cardiac vein runs alongside the anterior interventricular artery in the heart, and both play crucial roles in the circulation of blood throughout the body.

Learn more about arteries here:

https://brainly.com/question/30647579

#SPJ11

The statement in the question is incomplete and there are some errors in it. Here's a corrected version of the statement: In the stomach, pepsinogen is secreted by chief cells in the gastric gland. Hydrochloric acid (HCl) secreted by parietal cells in the same gland will then remove some amino acids from pepsinogen and convert it into pepsin, an enzyme that is necessary for protein digestion.

It's worth noting that the hydrochloric acid secreted by parietal cells also helps to denature dietary proteins, making them more accessible to pepsin for digestion. Additionally, pepsin works best in an acidic environment, and the low pH of the stomach (due to the presence of HCl) helps to optimize pepsin's activity.

In summary, pepsinogen is secreted by chief cells in the gastric gland, and HCl secreted by parietal cells converts it into pepsin, which is necessary for protein digestion. The presence of pepsin stimulates the conversion of more pepsinogen into pepsin, leading to a positive feedback loop.

To know more about amino acids,

https://brainly.com/question/14583479

#SPJ11

Complete question:

HCL will remove some amino acids from pepsinogen and turn it into also in the gastric gland, the parietal cells will secrete. true/false.

Answer:

A

Explanation:

B, C, and D are examples of single species on Earth, while A is not.

Option B refers to all the water lilies in a pond, which is a single species of plant.

Option C refers to all the bullfrogs in a pond, which is a single species of amphibian.

Option D refers to all the small mouth bass in a pond, which is a single species of fish.

Option A, however, refers to all the bacteria in a pond. Bacteria are a diverse group of microorganisms, and a pond can contain many different species of bacteria, making option A not an example of a single species on Earth.Therefore, the correct answer is A.

The true statement about thyroid hormones is that T3 and T4 both enter the target cells (Option A).

The thyroid hormones (TH), T4 and T3, are essential for brain development and influence mood and behavior. T3 is the active hormone, interacting with the nuclear receptors and regulating gene expression. T4 has low affinity for the nuclear receptors and is predominantly a prohormone as a precursor of T3 in tissues. Both thyroid hormones, triiodothyronine (T3) and thyroxine (T4), are able to enter the target cells and regulate the cell's metabolism by binding to the nuclear receptors.

Learn more about thyroid hormones: https://brainly.com/question/29848027

#SPJ11

Population 2 has a greater frequency of the r allele compared to population 1, as the r allele frequency in population 2 is 0.5, while in population 1, it is only 0.1.

Hardy-Weinberg equilibrium, which is a principle in population genetics that states that the frequency of alleles and genotypes in a population will remain constant over generations in the absence of other evolutionary influences.

To determine which population has a greater frequency of the r allele, we need to use the Hardy-Weinberg equation:

p² + 2pq + q² = 1

where p is the frequency of the dominant allele (in this case, R) and q is the frequency of the recessive allele (r). The terms p², 2pq, and q² represent the frequencies of the three possible genotypes (RR, Rr, and rr).

In population 1, 75% of the flowers are red, which means that 25% must be white. Therefore, the frequency of the R allele can be calculated as follows:

p² + 2pq + q² = 1
p² + 2p(0.5)q + q² = 1
0.75 = p² + pq

Solving for p, we get:

p = √(0.75 - pq)

We know that q = 0.25, so:

p = √(0.75 - 0.25p)

Solving for p using algebra, we get:

p = 0.9

So the frequency of the R allele in population 1 is 0.9, and the frequency of the r allele is 0.1.

In population 2, 25% of the flowers are white, which means that 75% must be red. Therefore, the frequency of the r allele can be calculated as follows:

p² + 2pq + q² = 1
p² + 2p(0.25)q + q² = 1
0.75 = p² + 0.5pq

Solving for q, we get:

q = √(0.75 - p²)

We know that p = 0.75, so:

q = √(0.75 - 0.5625)

Solving for q using algebra, we get:

q = 0.5

So the frequency of the r allele in population 2 is 0.5, and the frequency of the R allele is 0.5.

Therefore, population 2 has a greater frequency of the r allele compared to population 1, as the r allele frequency in population 2 is 0.5, while in population 1, it is only 0.1.

To know more about allele, refer

https://brainly.com/question/23516288

#SPJ11

Answer:

cladistic analysis

Explanation:

Conservative estimates suggest that over 90% of all organisms that have ever lived are now extinct, while simultaneously, there is remarkable biodiversity with 1.7 million species described by science, representing only a small fraction of existing species. Reconciling these two facts involves understanding the evolutionary process and the immense timescale of Earth's history.

Over millions of years, species undergo adaptation and diversification, driven by natural selection, leading to the vast biodiversity we see today. Extinction events, such as climate change or natural disasters, contribute to the high percentage of extinct organisms. However, these events also open up new ecological niches, allowing the survivors to adapt and thrive.

Moreover, the sheer amount of time Earth has existed allows for numerous species to emerge, evolve, and go extinct. With constant speciation and extinction events, a considerable number of extinct organisms is expected, while simultaneously allowing for present-day biodiversity.

Thus the high extinction rate and existing biodiversity can be reconciled through understanding the dynamics of evolution, the impact of extinction events, and the vast timescale of Earth's history.

Learn more about extinction here:

https://brainly.com/question/29887672

#SPJ11

A(n) aneurysm is the widening of a weakened portion of an arterial wall.

An aneurysm can occur in any arterial wall but is most commonly found in the aorta, the main artery that carries blood from the heart to the rest of the body.

Aneurysms are often asymptomatic, widening and may go unnoticed until they rupture, which can be life-threatening.

The risk factors for developing an aneurysm include age, high blood pressure, smoking, and atherosclerosis. Treatment options for aneurysms depend on the location, size, and symptoms of the aneurysm and may include surgical repair or endovascular techniques.

To learn more about arterial, click here:

https://brainly.com/question/10086106

#SPJ11

Natural disasters are density independent limiting variables. Option B is correct.

The given statement "The natural greenhouse effect keeps the Earth’s temperatures warm enough for life" is true because Natural disasters are density independent limiting variables. Option A is correct.

The more biodiversity in an ecosystem the greater the stability of that ecosystem. Option C is correct.

Human actions that destroy habitat pose the biggest danger to biodiversity. Option A is correct.

The agricultural green revolution and the availability of antibiotics are the two factors most responsible for the fast growth in human population. Option D is correct.

Overall world temperatures will rise if man continues to add carbon dioxide to the atmosphere. Option D is correct.

Ecosystem disturbance is anything that disrupts the homeostasis of an ecosystem. Option A is correct.

Species diversity describes the variety and abundance of different types of species that inhabit an area. Option B is correct.

1. Density-independent limiting factors, such as natural disasters, affect populations regardless of their size or density, while density-dependent factors, such as predation, competition, and disease, are influenced by the size and density of the population. Option B is correct.

2. The natural greenhouse effect is a real phenomenon that keeps the Earth's temperatures warm enough to sustain life on the planet. Option A is correct.

3. The greater the biodiversity in an ecosystem, the greater its stability, because diverse ecosystems are better able to withstand disturbances and maintain their functions and services. Option C is correct.

4. Habitat destruction is the greatest threat to biodiversity, as it directly and indirectly affects the survival of many species and their habitats. Option A is correct.

5. The agricultural green revolution and antibiotic availability have allowed for increased food production and improved human health, leading to a rapid increase in human population. Option D is correct.

6. Burning fossil fuels and adding more carbon dioxide to the atmosphere can lead to overall global warming, as well as more frequent and severe droughts and storms, among other potential consequences. Option D is correct.

7. Ecosystem disturbance is any event or process that disrupts the normal functioning of an ecosystem, leading to changes in its structure, composition, and function. Option A is correct.

8. Species diversity refers to the variety and abundance of different types of species that exist in an area, and it is an important component of biodiversity that contributes to ecosystem functioning and services. Option B is correct.

To know more about the Species, here

https://brainly.com/question/23709397

#SPJ1

You can improve your ability to retain information in your short-term memory and make it easier to transfer that information to your long-term memory for later recall.

There are several strategies that can help increase the length of time that you can hold information in your short-term memory:

Rehearsal: Repeating the information to yourself can help keep it active in your short-term memory. For example, if you are trying to remember a phone number, you can repeat it to yourself several times.

Chunking: Grouping information into smaller, more manageable chunks can make it easier to remember. For example, instead of trying to remember a 10-digit number, you can group it into three chunks: the area code, the first three digits, and the last four digits.

Visualization: Creating a mental image of the information you are trying to remember can help make it more memorable. For example, if you are trying to remember a list of items, you can create a mental image that incorporates all of the items.

Focus and attention: Paying close attention to the information and minimizing distractions can help you retain it in your short-term memory.

Mnemonic devices: Using memory aids such as acronyms or songs can help you remember information more easily.

Practice: Practicing recalling information from your short-term memory can help improve your ability to hold onto it for longer periods.

For more such questions on long-term memory

https://brainly.com/question/1090561

#SPJ11

The statement that best describes the state of erk protein is "In cells with the mutant Ras, adding the new drug would decrease signaling through the cell proliferation-signaling pathway". The correct answer is A.

In a healthy cell with no Ras mutations, when a growth factor is present and no drugs are present, the state of the ERK protein is activated.

Ras is a small GTPase protein that plays a crucial role in regulating cell proliferation, differentiation, and survival by activating the ERK signaling pathway.

When a growth factor binds to a receptor on the cell surface, it activates Ras, which in turn activates the downstream effectors of the ERK signaling pathway, leading to ERK activation.

In cells with mutant Ras, adding a new drug could potentially decrease signaling through the cell proliferation-signaling pathway.

This is because mutant Ras proteins can lead to hyperactivation of the ERK pathway, which is frequently observed in various cancers.

The drug could potentially inhibit the mutant Ras protein or downstream effectors of the ERK pathway to reduce its signaling activity, thereby decreasing cell proliferation.

A Ras protein that exchanges GDP for GTP more easily than normal would increase signaling, as this would increase the activation of Ras and downstream effectors of the ERK pathway.

Similarly, a Ras protein that cannot hydrolyze GTP to GDP would also increase signaling, as it would lead to constitutive activation of Ras and downstream effectors.

Both scenarios could lead to hyperactivation of the ERK pathway and potentially contribute to oncogenesis. The correct statement is A.

For more such answers on erk protein

https://brainly.com/question/19121848

#SPJ11

The father affected with hemophilia A will pass the defective gene to all of his daughters, who will be carriers of the disease. His sons have a 50% chance of inheriting the disease.

Hemophilia A is an X-linked recessive genetic disorder, which means that the gene responsible for the disease is located on the X chromosome.

Females have two X chromosomes, while males have one X and one Y chromosome. If a female inherits a defective gene on one of her X chromosomes, she is considered a carrier of the disease. If a male inherits a defective gene on his X chromosome, he will have hemophilia A.

In this case, the father affected with hemophilia A will pass his defective X chromosome to all of his daughters, who will be carriers of the disease. His sons have a 50% chance of inheriting the defective X chromosome and having hemophilia A.

For more questions like Chromosomes click the link below:

https://brainly.com/question/30993611

#SPJ11

There are 2795 individuals with the genotype TT, 2375 individuals with the genotype Tt, and 320 individuals with the genotype tt.

Let's call the dominant allele for tasting PTC "T" and the recessive "t". The capacity to taste PTC is governed by a dominant gene, thus only homozygous recessive (tt) people cannot taste it.

3500 of 5000 random samples are tasters. We may use the following equation to predict the number of homozygous dominant (TT) or heterozygous (Tt) people who can taste PTC:

TT+Tt = tasters

We can plug 3500 tasters into the equation:

TT + Tt = 3500

We require the population's homozygous dominant genotype frequency to count TTs. We can compute the frequency of the dominant allele "T" using the following equation:

T + t = 1

Rearranging this equation gives the T allele frequency:

T = 1 - t

Since a dominant allele controls PTC taste, we may infer that the population's frequency of T is significantly larger than t. The T allele frequency is the square root of the fraction of tasters:

[tex]T = sqrt(3500/5000)=0.748[/tex]

This number may compute genotype frequencies:

[tex]TT = T^2 = (0.748)Tt = 2Tt = 2(0.748)(0.252) = 0.475 T^2 = (1 - T)^2 = (0.252)^2 = 0.064[/tex]

Finally, multiplying the genotype frequency by the sample size yields the number of people with each genotype:

Tt = 0.475 x 5000 = 2375 Tt = 0.064 x 5000 = 320

Learn more about PTC, here:

https://brainly.com/question/14732007

#SPJ1

The answer to reducing bacterial colonization on contaminated toothbrushes is to use a whisky soak. Soaking your toothbrush in whisky for a few minutes can help kill any bacteria on the bristles. It is important to rinse your toothbrush thoroughly with water before use to avoid any residual whisky taste or smell.

Whisky is effective in reducing bacterial colonization on toothbrushes is that it contains a high percentage of alcohol which is a natural disinfectant. The alcohol in whisky helps to break down and kill bacteria on the bristles, thus reducing the risk of infection or illness from using a contaminated toothbrush.

It is not recommended to use a microwave or hairdryer to reduce bacterial colonization on toothbrushes as this can damage the bristles or handle of the toothbrush and potentially cause harm to the user. Additionally, these methods may not be as effective in killing bacteria as using a whisky soak.

To know more about bacterial colonization visit:

brainly.com/question/28287737

#SPJ11

Because they provide a mechanism for recycling nutrients between the living and non-living components of the Earth, biogeochemical cycles enable the ecosystem as a whole to flourish at the same time.

A biogeochemical cycle, or more broadly a cycle of matter, describes how chemical elements and compounds travel through and are changed by living things, the atmosphere, and the Earth's crust. The lithosphere (soil), hydrosphere (water), and atmosphere (air) are examples of these non-living components.

Nitrogen levels in the biosphere and carbon dioxide levels in the atmosphere have both significantly increased as a result of human activity. Climate change and altered biogeochemical cycles make biodiversity, food security, human health, and water quality more susceptible to climatic change.

To know about biogeochemical cycle

https://brainly.com/question/13869547

#SPJ4

Based on the time-of-entry data from Part A, we can assemble a rough map of the loci. The three loci are labeled as A, B, and C. To place the loci on the map, we need to use the information about the time of entry for each locus. We know that loci that are closer together will have a shorter time of entry.

After analyzing the data, we can place loci A and B in the same bin as they have a very short time of entry difference. Locus C has a longer time of entry compared to A and B, so we can place it in a separate bin. Therefore, the rough map of the loci would look like this:
| Bin 1: A, B |
| Bin 2: C |

For more such questions on loci

https://brainly.com/question/9193540

#SPJ11

The genetic code is a set of rules that enable us to translate a nucleic acid sequence into an amino acid sequence. It works by assigning each of the four nucleotides (A, T, C, G) a specific 3-letter codon.

Each codon corresponds to a specific amino acid, allowing us to determine the sequence of amino acids in a protein from a given nucleic acid sequence. The genetic code is a universal code, meaning that any organism from bacteria to humans uses the same codon-to-amino acid mapping.

It is also a degenerate code, meaning that more than one codon can code for the same amino acid. This redundancy provides the genetic code with a high level of robustness, making it easier for organisms to tolerate mutations. The genetic code is also read in triplets, meaning that it is read in sets of three nucleotides at a time.

know more about genetic code here

https://brainly.com/question/29413263#

#SPJ11

complete question is :-

given the genetic code able to translate a nucleic acid sequence into an amino acid sequence. EXPLAIN.

The answer is a. Antennae.

Proturans are hexapods that are named for their "first" or primitive characteristics, and "tail" which refers to their long caudal filaments.

They are unique in that they lack antennae, which are sensory appendages commonly found in most hexapods, including insects.

Despite lacking antennae, proturans have other sensory structures that enable them to navigate and find food in their underground habitats.

To know more about hexapods, visit here :

brainly.com/question/13048915

#SPJ11

The insertion of a needle or cannula into a vein for the purpose of withdrawing blood is called venipuncture.

This procedure is commonly performed in healthcare settings such as hospitals, clinics, and laboratories. Venipuncture is a routine diagnostic test used to obtain blood samples for various medical purposes such as checking for infections, monitoring glucose levels, and screening for diseases.

The procedure of venipuncture involves the use of a sterile needle or cannula that is inserted into a vein, usually in the arm or hand, to withdraw blood. The site of venipuncture is typically cleaned with an antiseptic solution and a tourniquet may be applied to restrict blood flow and make the vein more visible. After the blood sample is obtained, pressure is applied to the puncture site to stop bleeding and prevent hematoma formation.

Venipuncture is a safe and common procedure, but it can cause some discomfort and minor complications such as bruising or infection. Proper training and technique are essential for healthcare professionals performing venipuncture to ensure patient safety and accuracy of test results.

To know more about insertion of a needle click here:

https://brainly.com/question/17307848

#SPJ11

In this exercise, a test was performed to distinguish between bacteriostatic and bactericidal agents. The test involved exposing bacterial cultures to different agents and observing whether the bacteria continued to grow or were killed off. Based on the results of the test, it appears that the test was effective in distinguishing between bacteriostatic and bactericidal agents.

Bacteriostatic agents were those that inhibited bacterial growth, but did not kill the bacteria outright. This was observed in the cultures that continued to grow, but at a slower rate than the control group. Bactericidal agents, on the other hand, were those that killed the bacteria completely. This was observed in the cultures that showed no growth at all.

Therefore, the test was effective in distinguishing between these two types of agents. It allowed for a clear differentiation between agents that only inhibited bacterial growth and those that killed the bacteria outright. This is an important distinction to make, as different types of agents may be more effective in different situations. For example, bactericidal agents may be more effective in treating severe infections, while bacteriostatic agents may be more appropriate for milder infections.

To know more about bacteriostatic and bactericidal agents visit:-

https://brainly.com/question/29076654

#SPJ11

Sebaceous glands. Sebaceous glands are small glands located throughout the skin that secrete sebum, which is an oily substance that helps to coat and condition the skin and hair.

Sebum also helps to protect the skin from bacteria and other harmful substances.

Sebaceous glands secrete sebum, which is an oily secretion that helps to condition and protect the skin and hair.
An oily secretion that coats and conditions the skin and hair is secreted by the sebaceous glands.
Sebaceous glands are microscopic exocrine glands in the skin that secrete an oily substance called sebum. Sebum helps to lubricate and protect the skin and hair, keeping them moisturized and preventing them from drying out.

Hence, sebaceous glands produce the oily secretion that coats and conditions the skin and hair.

learn more about  Sebaceous glands click here:

https://brainly.com/question/10649665

#SPJ11

The habitat in which the major phototrophs consist of the smallest unicellular bacteria is likely to be in the ocean, option C is correct.

This is because the ocean contains a large diversity of microorganisms, including small unicellular bacteria such as cyanobacteria and prochlorophytes, which are important phototrophs in marine ecosystems.

While small unicellular bacteria may also be present in other habitats such as wetlands or deserts, the ocean is the most likely habitat to have the highest concentration of these types of organisms. Forests, on the other hand, are typically dominated by larger, multicellular photosynthetic organisms such as trees and other plants, option C is correct.

To learn more about bacteria follow the link:

https://brainly.com/question/8008968

#SPJ1

The complete question is:

A habitat in which the major phototrophs consist of the smallest unicellular bacteria is (group of answer choices)

A) forests

B) desert

C) ocean

D) wetland

One possible hypothesis for the stabilization of house finch abundance in 1995 and 1996 is that the population had reached the carrying capacity of their environment.

House finches are granivorous birds that primarily feed on seeds, which are abundant during the fall and winter months. In the early 1990s, a bacterial disease known as Mycoplasma gallisepticum (MG) spread rapidly among house finch populations in North America. This disease caused severe conjunctivitis in infected birds, leading to reduced survival and reproductive success.

The disease caused a significant decline in house finch populations in the following years. However, some evidence suggests that the disease may have also contributed to the stabilization of the population size. In infected birds, the disease caused a decrease in reproductive output, which could have slowed population growth.

To learn more about population follow the link:

https://brainly.com/question/27991860

#SPJ4

Answer:

the outer folds of skin are called labia majora and labia minora