Answer:
Reactivity
Explanation:
state the law of conversation of momentum
Which of the following biogeochemical cycles moves water through the atmosphere, surface, and crust of Earth?
A. Carbon cycle
B. Hydrologic cycle
C. Nitrogen cycle
D. Phosphorus cycle
Question 4 A car of mass 820 kg has a maximum power of 30 kW and moves against a constant resistance of motion to 910 N. Calculate the maximum speed of the car in the following situation; b)Up an incline (hill) of 8.75° to the horizontal?
Answer:
P = W / t = m g s / t = m g v where work by auto = m g s
30 kw = 30000 watts = 30000 J / s
Work wasted = F v as shown above relating work and power
Work done against incline = m g s sin 8.75 and power against incline
= m g v sin 8.75 = 1222 v Joules / sec
power in moving auto = power available - power lost to friction
power in moving auto = 30000 - resistance = 30000 - 910 v
1222 v = 30000 - 910 v
v = 30000 / 2132 = 14 m/s
Note: constant resistance to motion must mean P = W / t = F s / t = F v
Maximum speed will be v = 14.07 m/s
What is power ?Power is defined time rate of doing work or delivering energy.
Work done = Force * displacement
Power = work done / time
= (Force * displacement ) / time
since , displacement / time = velocity
Power = force * (displacement / time ) = force * velocity
Power = mass * acceleration * velocity ( as force = mass * acceleration)
since , car is travelling up in an incline of 8.75° to the horizontal
hence , it will have two components of velocity
vertical component = v sin (theta ) = v sin(8.75°)
horizontal component = v cos (theta)= v cos (8.75°)
Power = m* a * v sin (theta )
= 820 * 9.8 * v *sin (8.75°) ( a = g = 9.8 m[tex]/s^{2}[/tex])
= 1221.472 v
Power lost due to resistance in motion = 910 * velocity = 910 v
Power = Total power - power lost due to resistance in motion
= 30 * [tex]10^{3}[/tex] - 910 v
30 * [tex]10^{3}[/tex] - 910 v = 1221.472 v
v = 14.07 m/s
Maximum speed will be v = 14.07 m/s
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The length, breadth and height of a box is 50cm, 20cm and 10cm respectively then find surface area of its base and volume.
I just hope this pic will help you
1. An MR-2 starts from rest and accelerates westward to a speed of 27 m/s in
11.8 seconds.
a) What is its acceleration?
b) What is the displacement it covered?
Answer:
a) 2.28 m/s²
b) 159.86 m
Explanation:
Part A:
u = 0 m/s
v = 27 m/s
t = 11.8 seconds
a = ?
Formula:
v = u + at
=> 27 = 0 + a(11.8)
=> 27 = a(11.8)
=> a(11.8) = 27
=> a = 27/11.8
=> a = 2.28 m/s²
Part B:
s = ?
Formula:
s = (v² - u²)/2a
s = (27² - 0²) /2(2.28)
= 729/4.56
= 159.86 m
Displacement vs. Time
80.0
60.0
40.0
20.0
Displacement (m)
0.0
-20.0
-40.0
-60.0
4.0
6.0
18.0
22.0
0.0 2.0
8.0 10.0 12.0 14.0 16.0 20.0
Time (s)
What is the velocity of the objected represented by the graph between 0.0 s and 4.0 s?
O 7.5 m/s
240 m/s
15 m/s
120 m/s
Please find attached photograph for your answer. Hope it helps. Please do comment. The option is c. 15m/s.
Suppose 2kg of glycerine have a temperature of 30°C. Heat is supplied to a steady rate of 100W. The temperature after 35 minutes is 75°C.
Calculate the specific heat capacity of glycerine.
Answer:
210000.................
The specific heat capacity of glycerine is 2333.3 J/(kg·K).
We can use the formula for heat (Q) absorbed by a substance:
Q = mcΔT
Where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
We know the mass of glycerine (m = 2 kg), the time for which heat is supplied (t = 35 minutes = 2100 seconds), the rate of heat supply (P = 100 W), the initial temperature (T1 = 30°C = 303 K), and the final temperature (T2 = 75°C = 348 K).
First, we need to calculate the total heat absorbed by the glycerine:
Q = Pt
Q = 100 W × 2100 s
Q = 210000 J
Next, we can calculate the change in temperature:
ΔT = T2 - T1
ΔT = 348 K - 303 K
ΔT = 45 K
Finally, we can calculate the specific heat capacity of glycerine:
c = Q/(mΔT)
c = 210000 J/(2 kg × 45 K)
c = 2333.3 J/(kg·K)
Therefore, the specific heat capacity (c) = 2333.3 J/(kg·K).
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4. The modern particle theory of matter was generally accepted
in what century? Whose concept of matter was overturned by
this revolution in science?
Answer:
the modern particle theory of matter was accepted in the mid-ninteenth century. Aistotle's continoues theory of matter was overturned. They gave matter order and determine many of its properties. your welcome :)
A car starts from rest and is moving at 51 9 m/s after 120 seconds. What is the cat's
average acceleration?
Answer:
the cats acceleration is 4.25m/s2
A mass of 20kg which moved vertically produced a momentum of 300kg.m/s, how much power was needed to move the mass?
Answer:
Power is 3000 W
Explanation:
Momentum = mass × velocity
[tex]300 = 20 \times v \\ velocity = 15 \: {ms}^{ - 1} [/tex]
For power:
[tex]P = \frac{force \times distance}{time} \\ \\ P = force \times ( \frac{distance}{time} )[/tex]
but distance/time is velocity, so:
[tex]P = force \times velocity[/tex]
but force = mass × acceleration:
[tex]P = (mass \times acceleration) \times velocity \\ P = (20 \times 10) \times 15 \\ P = 3000 \: \: watts[/tex]
[ taken acceleration to be 10 m/s² ]
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.50 m above the ground and measure that it hits the ground 0.809 s later.
Assuming that the planet has the same density as that of earth (5500 kg/m3), what is the radius of the planet?
Explanation:
By the formula,
[tex]s=ut+\frac12at^2[/tex]
[tex]-3.5=0+\frac12a(0.809)^2[/tex]
[tex]a=-10.659 ms^{-2}[/tex]
where a is the acceleration of objects by gravity.
We also know that by the Law of Gravitation,
[tex]F=-\frac{GMm}{r^2}=ma[/tex]
[tex]a=-\frac{GM}{r^2}[/tex]
The mass of the planet is given by
[tex]M=\rho V=\rho(\frac 43\pi r^3)[/tex]
So
[tex]a=-\frac{G(\rho\frac 43\pi R^3)}{r^2}= - \frac{(6.67 \times 10^{-11})(5500)(\frac43)\pi R^3}{(R+3.5)^2} = -10.659[/tex]
Since R>>3.5, so we approximate
[tex](R+3.5)^2\approx R^2[/tex]
Solving the last equation,
[tex]R=6936.483 km[/tex]
A car travels 40 kilometers at an average speed of 80km/h and then travels 40 kilometers at an average speed of 40km/h. The average speed of the car for this 80-km trip is
Speed = distance / time
Part 1: 40 km at 80 km per goir = 0.50 hours
Part 2: 40 km at 40 km per hour = 1 hour
The time of the trip was 1.5 hours
Total distance was 40 + 40 = 80 ins.
Speed = distance / time = 80/1.5 = 53.33 km/he ( round answer as needed)
Why is the level of glycerin initially decreases when heated ?
Twelve seconds after starting from rest an object falling freely will have a speed of
Answer:
(4.9)×(12)^2 m/s
Explanation:
velocity =1/2 × g× t^2
g=9.8m/s^2
t=12sec
What is the correct clases for this drugs
Compazine
heelp me please
Explanation:
Compazine belongs to class of drugs called Antiemetic Agents, Antipsychotics, Phenothiazine.
The most suitable unit for expressing nuclear radius is
A) micro B) nanometre
C) fermi D) angstrom
Answer:
Fermi is used to express nuclear radius
Answer:
the most suitable unit for expressing nuclear radius is Fermi.
Help, I really need to solve this right away!!
Answer:
can you like zoom in i cant see that much.
Explanation:
which part of vernier caliper is used to measure internal diameter of cylinder
Answer:
Circled in Red...plus the scales, of course.
Explanation:
(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where the acceleration due to gravity is 9.82m/s2. What is its new period
I assume this is the motion of the simple pendulum
T = 2π × [tex]\sqrt{\frac{L}{g } }[/tex]
=> [tex]\frac{T1}{T2 }[/tex] = [tex]\sqrt{\frac{g2}{g1} }[/tex]
Given T1= 3s g1= 9.79 g2= 9.82
=> T2 = 3.00459 s
Two cars next to each other start moving in the same direction from rest, car A accelerates at m/s2 4 for 10 s and then travels at a constant speed, while car B accelerates at m/s2 5 until it reaches 25 m/s and then maintains This speed. What is the distance between the two cars when t = 15s?
in complete sentnces write down everything you know about maps. What are they for?
how Do you use them?
maps are for locating an area or a country
Explanation:
they are really beneficial because u will have the advantage to know every country and its location and lines of longitude and latitudes
Two falling inflated balls of different masses
land at the same time.
Answer:
-The air resistance statement goes with the pieces of paper statements
-The force of gravity statement goes with the dog statements
-The acceleration due to gravity goes with the two inflated balls
a sound wave of frequency 1210 Hz has a wave speed of 343 m/s. what is the wavelength of the wave?
Answer:
wavelength = 0.28m
Explanation:
wavelength = velocity/ frequency
wavelength = 343/1210 = 0.28m
An airplane with a total mass of 950 kg has an engine malfunction, causing it
to provide a constant horizontal force of 3000 N. The pilot, who has a mass
of 65 kg, decides to eject from the airplane. With the reduced total mass,
what is the new approximate acceleration of the airplane?
A. 3.7 m/s2
B. 2.8 m/s2
C. 3.2 m/s2
D. 3.4 m/s2
Answer:
3.4 m/s2
Explanation:
Multiple choice Questions about the statement true and how you can be separated by filtration and the way you treat your business and your business to make your life easier and easier to understand and understand the importance of life and damage
The new approximate acceleration of the airplane will be D. 3.4 m/s2
What is Newton's second law of motion ?
Newton's second law of motion states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Initial mass = 950 kg
mass of piolet = 65 kg
reduced mass = 950 - 65 = 885 kg
according to Newton's second law of motion
force = mass * acceleration
3000 N = 885 kg * acceleration
acceleration = 3000 / 885 = 3.39 m/s^2 = 3.4 m/s^2
correct answer is D. 3.4 m/s2
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¿Qué valor de voltaje se requiere para que pasen 35 mA a través de una resistencia de 15 kΩ? Si se aplica ese mismo voltaje a una resistencia de 500Ω, ¿Cuál será la nueva corriente?
Answer:
perdón yo no hablo inglés
Question 1 of 10
Rays bend as they pass through a boundary between two media. This is
called:
A. indention.
B. reflection.
C. refraction.
D. diffraction.
School PlanSchool Plannerner
50 POINTS!
Motion Diagrams: Observe each motion and describe how to object is moving. If the motion diagrams show more than one kind, highlight and label each kind. Please thoroughly explain. Thank you so much!
No:1
The object is moving with constant or uniform acceleration and in average speed
No:-2The object is de accelerating
No:-3The object deaccelerated and came to rest so fast.
No:-4The object moves slowly first then accelerated.
No:-5The object accelerated at first so fast then move with constant acceleration then again accelerated .
two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both projectile strict the ground at the distance and time interval of both when they are in arir?
Answer:
Yes, if θ = 45°
Explanation:
Give reason
It is more difficult to climb a vertical slope than a slanted slope because
Answer:
because in vertical slope force of gravity is more than compared to slanted slope
Answer:
because gravity is always pulling objects down so when you climb upward gravity weighs you down, you have to use effort to move yourself in the opposite direction that gravity is pulling you that is why it is harder to climb up a slope.