Which of the following exponential functions is represented by the graph? Question 7 options: A) ƒ(x) = (1∕5)x B) ƒ(x) = (1∕5)–x C) ƒ(x) = –5x D) ƒ(x) = 5–x
Answers
Answer:
[tex]f(x) = (\frac{1}{5})^{-x}[/tex]
Step-by-step explanation:
Given
The graph above
Required
Determine from the list of options, the function of the graph
To determine the function, we have to test each of the options
But first, we nees to write out the points on the graph
(1,5), (0,1), (-1,1/5) and (-2, 1/25)
A. [tex]f(x) = (\frac{1}{5})^x[/tex]
Point 1: When x = 1, f(x) = 5
[tex]f(x) = (\frac{1}{5})^x[/tex]
[tex]f(1) = (\frac{1}{5})^1[/tex]
[tex]f(1) = (\frac{1}{5})[/tex]
There's no need to check further as the first point doesn't lie on the graph
B. [tex]f(x) = (\frac{1}{5})^{-x}[/tex]
Point 1: When x = 1, f(x) = 5
[tex]f(x) = (\frac{1}{5})^{-x}[/tex]
[tex]f(1) = (\frac{1}{5})^{-1}[/tex]
[tex]f(1) = 1/(\frac{1}{5})[/tex] --- Law of indices
[tex]f(1) = 1*(\frac{5}{1})[/tex]
[tex]f(1) = 1*5[/tex]
[tex]f(1) = 5[/tex]
Point 2: When x = 0, f(x) = 1
[tex]f(0) = (\frac{1}{5})^{-0}[/tex]
[tex]f(0) = (\frac{1}{5})^{0}[/tex]
[tex]f(0) = 1[/tex] --- The expression raise to power 0 is 1
Point 3: When x = -1, x = 1/5
[tex]f(x) = (\frac{1}{5})^{-x}[/tex]
[tex]f(-1) = (\frac{1}{5})^{-(-1)}[/tex]
[tex]f(-1) = (\frac{1}{5})^{1}[/tex] ----- Law of indices
[tex]f(-1) = (\frac{1}{5})[/tex]
Point 4: When x = -2, x = 1/25
[tex]f(x) = (\frac{1}{5})^{-x}[/tex]
[tex]f(-2) = (\frac{1}{5})^{-(-2)}[/tex]
[tex]f(-2) = (\frac{1}{5})^{2}[/tex] ----- Law of indices
[tex]f(-2) = \frac{1}{5} * \frac{1}{5}[/tex]
[tex]f(-2) = \frac{1}{25}[/tex]
There's no need to check other options as this function satisfy the 4 points on the graph;
Hence;
[tex]f(x) = (\frac{1}{5})^{-x}[/tex] is the exponential function represented on the graph
Related Questions
What is the value of x? (Use only the digits 0 - 9 and the decimal point, if needed, to write the number.)
x + 12.66 = 18
Answers
Answer: 5.34
Step-by-step explanation: 18 - 12.66 = 5.34
how do you solve these problems?
Answers
Answer:
Step-by-step explanation:
Hello,
a. The area of region P is the area of the rectangle 1 * e minus the
[tex]\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^{1}_{0}=e-1[/tex]
So this is e - (e-1) = e - e + 1 = 1
b. The area of region P is the area of the rectangle 1 * e minus P and minus the
[tex]\displaystyle \int\limits^0_1 {e^{-x}} \, dx=[-e^{-x}]^{1}_{0}=-e^{-1}+1[/tex]
So this is
[tex]e - 1 - (-e^{-1}+1) = e-1+e^{-1}-1=e+e^{-1}-2[/tex]
This is around 1.08616127...
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
write a system of equations for the problem, and then solve the system. if a plane can travel 340 miles per hour with the wind only 260 miles per hour against the wind, find the speed of the wind and the speed of the plane in still air. please show step by step
Answers
Answer:
The speed of plane = 40 m/s
The speed of the wind = 300 m/s
Step-by-step explanation:
Let the speed of the plane = Y
And the speed of the wind = X
If the plane then travel 340 miles per hour with the wind, that means the plane and the wind are moving in the same direction. Therefore,
X + Y = 340 ..... ( 1 )
Also, 260 miles per hour against the wind. That is, the plane is moving opposite to the direction of the wind. Therefore,
X - Y = 260 ..... ( 2 )
Solve the two equations simultaneously by addition. That will eliminate Y
X + Y = 340
X - Y = 260
2X = 600
X = 600/2
X = 300 m/s
Substitutes X in equation (1)
300 + Y = 340
Make Y the subject of formula by collecting the like terms
Y = 340 - 300
Y = 40 m/s
Therefore, the speed of the plane is 40 m/s. While the speed of the wind is 300 m/s.
please help with this
Answers
Answer:
158m^3
Step-by-step explanation:
First, let's figure out the total amount of water in the tank.
It measures 4.5m by 6m by 8m. The volume of a rectangular prism is V=lwh.
Therefore, the volume is:
[tex]V=(4.5)(6)(8)=216 m^3[/tex]
We are told is it filled to the brim, so we can conclude that there are 216 cubic meters of water in the tank.
We used 58 cubic meters of water, so we simply need to subtract that from 216:
[tex]216m^3-58m^3=158m^3[/tex]
There is still 158 cubic meters of water left in the tank.
Answer:
158 m^3
Step-by-step explanation:
Volume of the tank
= 4.5 * 6 * 8
= 216 m^3.
So amount left in the tank
= 216 - 58
= 158 m^3.
Suppose a hardware manufacturer is checking its nails to make sure they are of the right length. A quality control investigator collects a sample of 100 nails and measures their lengths, finding that their mean is 2.000cm with a sample standard deviation of 0.002cm. Suppose the investigator knows that nearly all of the nail population produced will be within 2 standard deviations. What will be the most likely upper bound on the length of a randomly chosen nail from all nails manufactured by the company?
Answers
Answer:
The upper bound on the length of a randomly chosen nail from all nails manufactured by the company is 2.004 cm.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
Then, the mean of the sample means is given by,
[tex]\mu_{\bar x}=\bar x[/tex]
And the standard deviation of the sample means (also known as the standard error) is given by,
[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]
In this case the sample of nails selected is quite large, i.e. n = 100 > 30.
So, the sampling distribution of sample mean length of nails will be approximately normal.
Then according to the Empirical rule, 95% of the normal distribution is contained in the range,
[tex]\mu\pm 2\cdot \frac{s}{\sqrt{n}}[/tex]
Compute the upper bound as follows:
[tex]\text{Upper Bound}=\mu\pm 2\cdot \frac{s}{\sqrt{n}}[/tex]
[tex]=2+(2\times\frac{0.002}{\sqrt{100}})\\\\=2+0.0004\\\\=2.004[/tex]
Thus, the upper bound on the length of a randomly chosen nail from all nails manufactured by the company is 2.004 cm.
Jackson is attending a lacrosse game that is halfway through the first quarter.
4) What fractional part of the game is leh?
3) If 74 minutes of playing time have past, how many total minutes of playing
time are there in the game?
6) How many minutes of playing time are left in the game?
(okay so I have to draw the picture so someone please help meh :p)
Answers
Answer:
7/8 of the game is left. The game lasts for 592 minutes.
Step-by-step explanation:
It is halfway through the first quarter so it is 1/8. So that's 7/8 part of the game left. if 74 minutes of playing time has past, then you do 74*8 so that's 592 minutes.
Answer:
4) 1/8
3)74x8=592
6)592-74= 518
Step-by-step explanation:
A painter leans a 25-foot ladder against the wall. The bottom of the ladder is 20 feet from the base of the wall. The painter then moves the bottom of the ladder 13 feet closer to the wall. How much higher is the top of the ladder on the wall?
Answers
Answer:
9 ft
Step-by-step explanation:
a²+b²=c²
20²+b²=25²
400=b²=625
b²=625-400
b²=225
b=15 (the distance up the wall the ladder is to begin with)
20-13=7
7²+b²=25²
49+b²=625
b²=625-49
b²=576
b=24 (The distance up the wall the ladder is after moving it)
24-15=9
Rectangle JKLM is rotated 90° clockwise about the origin. On a coordinate plane, rectangle J K L M has points (negative 4, 1), (negative 1, 1), (negative 1, negative 1), (negative 4, negative 1). What are the coordinates of J’? J’(–1, –4) J’(4, –1) J’(1, 4) J’(4, 1)
Answers
Answer:
(4,-1)
Step-by-step explanation:
The required coordinate of J is (1, 4). Hence the option c is correct.
Rectangle JKLM is rotated 90° clockwise about the origin.
On a coordinate plane, rectangle J K L M has points (negative 4, 1), (negative 1, 1), (negative 1, negative 1), (negative 4, negative 1).
Rectangle is four sided polygon whose opposites sides are equal and has angle of 90° between its sides.
While rotating the rectangle about origin clock wise, the new coordinates forms of rectangle J K L M has points ( 4, 1), (1, 1), (negative 1, 1), (negative1 , 4).
Thus, the required coordinate of J is (1, 4).
Learn more about rectangles here:
https://brainly.com/question/16021628
#SPJ2
2. Kelsea needs a test average of at least 90 to get an "A-" this marking period in math. Her three test grades
are 87,91 and 86. What score must she get on her fourth test to receive at least an A- ?
Define variable:
Equation:
Solution:
can someone check this please :)
Answers
Answer:
Equation: 87 + 91 + 86 + x = 360
Solution: 264 + x = 360
x = 360 - 264
x = 96
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
First three Kelsea's test grades : 87, 91 and 86
2. What score must she get on her fourth test to receive at least an A- ?
Define variable: x that represents the grade needed by Kelsea on her fourth test to receive at least an A-
Equation: 87 + 91 + 86 + x = 360
Solution: 264 + x = 360
x = 360 - 264
x = 96
Now you can understand if the previous work you did is correct
please help me with this
Answers
Answer:
Step-by-step explanation:
Open box is in rectangular shape. cuboid that is open in the top
l = length = 30 - (2.5 + 2.5 ) = 30 - 5 = 25 cm
h = 2.5 cm
w = width = 30 - (2.5 + 2.5) = 30 - 5 = 25 cm
Surface Area = 2lh + 2wh + lw
= 2*25*2.5 + 2* 25*2.5 + 25*25
=125 + 125 + 625
= 875 square cm
Volume = lwh
= 25*25*2.5
= 1562.5 cubic cm
Help ASAP!! This one's is difficult for me to understand!! Help me please!
Answers
Answer:
Ok so im in 7thgrade so ima try to help answer is x= 8x9
If tan x°= z/10 and cos x°= 10/y , what is the value of sin x°?
A. sin x° = z/y
B. sin x° = y/z
C. sin x° = 10z
D. sin x° = 10y
Answers
Answer:
A. z/y
Step-by-step explanation:
Because the trig ratios are; tangent : opp/adj cos : adj/hyp sin : opp/hyp
because tan of x is z/10, z must be opposite
and because cos of x is 10/y, then y must be the hypotenuse
this means sin of x must be z/y
Answer:
A. sin x = z/y
Step-by-step explanation:
this squared based pyramid is cut horizontally at a height of 15cm to leave this frustum base area=10cm
Answers
Answer:
583.33 cm³
Step-by-step explanation:
From the image attached, the total height (H) of the pyramid is 30 cm, the height of the frustrum (h) = 15 cm, the Frustrum base = lower base = B = 10 cm . To find the length of the upper base (b), we use:
[tex]\frac{b}{H-h}=\frac{B}{H}\\ b=(H-h)\frac{B}{H}\\b=(30-15)\frac{10}{30}=5\\b=5\ cm[/tex]
The volume of the frustrum is given by:
[tex]V=\frac{1}{3}h(B_1+B_2+\sqrt{B_1B_2} )\\ Where\ B_1\ is \ the\ area \ of\ the\ upper\ base= 5cm*5cm=25cm^2\\B_1\ is \ the\ area \ of\ the\ lower\ base= 10cm*10cm=100cm^2\\V=\frac{1}{3}(10)(25+100+\sqrt{25*100} )=583.33\\V=583.33\ cm^3[/tex]
Which of the following geometric series converges?
Answers
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is
[tex]S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}[/tex]
Multiply both sides by r :
[tex]rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n[/tex]
Subtract the latter sum from the first, which eliminates all but the first and last terms:
[tex]S_n-rS_n=a-ar^n[/tex]
Solve for [tex]S_n[/tex]:
[tex](1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}[/tex]
Then as gets arbitrarily large, the term [tex]r^n[/tex] will converge to 0, leaving us with
[tex]S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}[/tex]
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Please help me answer my questions...
Answers
Answer:
80$
Step-by-step explanation:
total amount of needed=200
Total =Tef +Angelina+Jason
200=90+30+Angelina
Angelina=200-120
Angelina=80$
Micah is handing out miniature chocolate bars and butterscotch hard candies for Halloween. He wants tohave a total of 7 pounds of candy, but he doesn't want to spend more than $11.00 total on the candy. If miniature chocolate bars costs $1.80 per pound, and butterscotch hard candies costs $1.00 per pound, how many pounds of each type of candy should he buy?
Answers
Answer:
5 pounds of miniature chocolate and 2 butterscotch hard candies
Step-by-step explanation:
5 x $1.80 =$9 for 5 pounds of candy
2 x $1.00 =$2 for 2 pounds of candy
2 + 5 =7 pounds
7 pounds of candy using $11.00
Plz Help me solve this
Answers
Answer:
Step-by-step explanation:I think the answer is 12?
help please. Find the length of x.
Answers
Answer:
x=10
Step-by-step explanation:
The triangles are similar so we can use ratios to solve
6.5 (6.5+6.5)
------ = -----------------------
5 x
6.5 (13)
------ = -----------------------
5 x
Using cross products
6.5x = 65
Divide by 6.5
6.5x/6.5 = 65/6.5
x = 10
Please help ASAP!
Rearrange the equation so x is the independent variable. -5x - 4y = -8
Answers
Answer:
Hey there!
Original Equation
-5x-4y=-8
Multiply by -1
5x+4y=8
Subtract 4y
5x=8-4y
Divide by 5
x=(8-4y)/5
Let me know if this helps :)
Answer:
x = -4/5y + 8/5
Step-by-step explanation:
So to single out x we use the communicative property,
its the moving of numbers and variables to each side of the equation.
So we have,
-5x - 4y = -8
+4y
-5x = 4y - 8
Divide -5 by both sides,
x = -4/5y + 8/5
Thus,
the equation rearanged is x = -4/5y + 8/5.
Hope this helps :)
Please answer quickly.
Answers
Answer:
Option 4
Step-by-step explanation:
=> [tex]\frac{4}{5} x^{-9}y^6z^8[/tex]
If there is any variable having a negative exponent, we should move it to its opposite side (Denominator to numerator and vice versa) So that it's exponent become positive.
=> [tex]\frac{4y^6z^8}{5x^9}[/tex]
Answer: D) [tex]\frac{4y^6z^8}{5x^9}[/tex]
Step-by-step explanation:
(4/5)x^-9y^6z^8 = [tex]\frac{4x^{-9}y^6z^8}{5}[/tex]
Any negative exponent can be taken to the other side of the fraction to be positive. Thus,
[tex]\frac{4x^{-9}y^6z^8}{5}[/tex] = [tex]\frac{4y^6z^8}{5x^9}[/tex]
Hope it helps <3
Select the correct answer from each drop-down menu.
The given equation has been solved in the table.
Step
Statement
1
= 15
- - 6 =
- - 6 + 6 = 15 +
+4
- = 21
N
3
4.
2
-2 - 21
5
y = -42
Use the table to complete each statement.
In step 2, the
In step 4, the
property of equality was applied.
property of equality was applied.
V
Reset
Next
Answers
Answer:
Step 2: addition property of equality
Step 4: multiplication property of equality
Step-by-step explanation:
=>In step 2, from step 1, where you have [tex] -\frac{y}{2} - 6 = 15 [/tex] , to make -6 cross over to the other side of the equation, the addition property of equality was applied. That would ensure the equation remains balanced. Thus, 6 is added to both sides of the equation.
[tex] -\frac{y}{2} - 6 + 6 = 15 + 6 [/tex]
[tex] = -\frac{y}{2} = 21 [/tex]
=>In step 4, the multiplication property of equality was used as both sides of the equation were multiplied by -2, to balance the equation and also solve for y.
Answer:
Step 2 > addition
Step 4 > multiplication
Step-by-step explanation:
five sixths of a number equals 200. What is the number?
Answers
Answer: 240
Step-by-step explanation:
5/6x=200
(6/5)5/6x=200(6/5)
1x=40(6/1)
x=40(6)
x=240
is 3 over the square root of 27 rational or irrational
Answers
Answer:
rational (I think
Step-by-step explanation:
What is the Domain and Range *DON'T FORGET PARENTHESES AND BRACKETS*
Answers
Answer:
Domain: (-5,-4,-3,-2,-1,0,1,2,3,4,5)
Range: (0,1,2,3,4, -1, -2)
Step-by-step explanation:
Domain means all of the x-axis values on the graph, so for example in (-2,0), -2 would be part of the domain and 0 part of the range. Therefor, what you would do would be take all of the plots and put all x values as the domain and all y values as the range. Hope this helped!
What is the length of DF?
Answers
Answer:
7.06
Step-by-step explanation:
17/8 = 15/DF
DF = 7.06
I think that’s right
If the quadratic formula is used to solve 2x2-3x - 1 = 0, what are the solutions?
1-3 + fin 3 - i7)
4.
4.
0 -3-17 3 - 171
4
4
이
13 +17 3 - (1)
4
4
Answers
Answer:
x = (3 +/- sqrt(17) / 4.
Step-by-step explanation:
x = [-(-3) +/- sqrt((-3)^2 - 4*2*-1)] / 4
x = (3 +/- sqrt(17) / 4.
question 9: consecutive angles in a parallelogram are___ A: cute B: congruent C: parallel D: Supplementary E: Convex
Answers
Answer:
Consecutive angles in a parallelogram are, D supplementary.
Step-by-step explanation:
Consecutive angles in a parallelogram will always sum to 180 degrees.
Answer:
Supplementary
Step-by-step explanation:
Correct answer in Ap3x. Just took the quiz.
Questions are attached
Answers
Answer:
V = 32 in^3
Step-by-step explanation:
The area of the triangle is (1/2)(base)(height), which here comes to:
(1/2)(4 in)(8 in) = 16 in^2.
The volume is (16 in^2)(height) = (16 in^2)(2 in) = 32 in^3
Which value makes the inequality x^2 ≥ x false?
A. -1/4
B. 0
C. 1/4
D. 1
Answers
Answer:
D
Step-by-step explanation:
cas if x =1
then 1^2>or=1
1is not >or=1
For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
A. (5+1/2 x)^6
B. (Y- 1/2 x) ^6
C. (5- 1/2 x) ^6
D. (-5 + (- 1/2 x))^6
Answers
Answer:
C. [tex](5-\frac{1}{2})^6[/tex]
Step-by-step explanation:
Given
[tex]15(5)^2(-\frac{1}{2})^4[/tex]
Required
Determine which binomial expansion it came from
The first step is to add the powers of he expression in brackets;
[tex]Sum = 2 + 4[/tex]
[tex]Sum = 6[/tex]
Each term of a binomial expansion are always of the form:
[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]
Where n = the sum above
[tex]n = 6[/tex]
Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion
[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]
Substitute 6 for n
[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]
[Next is to solve for a and b]
From the above expression, the power of (5) is 2
Express 2 as 6 - 4
[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]
By direct comparison of
[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]
and
[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]
We have;
[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]
Further comparison gives
[tex]^nC_r = 15[/tex]
[tex]a^{n-r} =(5)^{6-4}[/tex]
[tex]b^r= (-\frac{1}{2})^4[/tex]
[Solving for a]
By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]
[tex]a = 5[/tex]
[tex]n = 6[/tex]
[tex]r = 4[/tex]
[Solving for b]
By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]
[tex]r = 4[/tex]
[tex]b = \frac{-1}{2}[/tex]
Substitute values for a, b, n and r in
[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]
[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
Solve for [tex]^6C_4[/tex]
[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]
[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]
Check the list of options for the expression on the left hand side
The correct answer is [tex](5-\frac{1}{2})^6[/tex]