Which of the following chemical equations depicts a balanced chemical
equation?
O A. AgNO3 + K2 CrO4- > KNO3 + Ag2Cr04
B. 3AgNO3 + 2K2 CrO4- > 3KNO3 + 2Ag2 CrO4
OC. 2AgNO3 + K2 CrO4- > 2KNO3 + Ag2Cr04
OD. AgNO3 + K2 CrO4- > 2KNO3 + Ag2Cr04
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Answers

Answer 1
OC. (Third one) is balanced
Answer 2

The balanced chemical equation is [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].

What is a balanced chemical equation?

An equation that has the same quantity and type of atom on both ends of the arrow was seen to represent a balanced chemical reaction. A chemical reaction would be represented symbolically in writing by a chemical equation.

The balanced chemical equation is  [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].

It can be seen that,

The number of Ag molecules on the reactant side is 2.

The number of Ag molecules on the reactant side is 2.

The number of K molecules on the reactant side is 2.

The number of K molecules on the reactant side is 2.

The balanced chemical equation is [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].

Therefore, the correct answer will be an option (C).

To know more about the balanced chemical equation.

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Related Questions

What is the percent yield of lithium hydroxide from a reaction of 7.40g of lithium with 10.2g of water? The actual yield was measured to be 12.1g.

Answers

Answer:

[tex]\boxed{Percentage \ Yield = 47.6 \ percent}[/tex]

Explanation:

The balanced chemical reaction is

[tex]2Li + 2H_{2}O \ \ \ -> \ \ \ 2LiOH + H_{2}[/tex]

For the balanced reaction, we've

Lithium = 14 g

Water = 36 g

LiOH = 48 g

Hydrogen gas = 2 g

So,

14 g of lithium = 48 g of lithium hydroxide

And we have:

7.40 g of lithium = x grams of lithium hydroxide

Cross Multiplying,

x grams = [tex]\frac{48*7.4}{14}[/tex]

Grams of lithium = 25.4 g of lithium hydroxide

So, Theoretical Yield = 25.4 g of lithium hydroxide

Now, The %age yield:

%age Yield = [tex]\frac{Actual \ Yield}{Theoretical \ Yeild } * 100[/tex]

%age Yield = [tex]\frac{12.1}{25.4} * 100[/tex]

%age Yield = 47.6%

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