The balanced chemical equation is [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].
What is a balanced chemical equation?
An equation that has the same quantity and type of atom on both ends of the arrow was seen to represent a balanced chemical reaction. A chemical reaction would be represented symbolically in writing by a chemical equation.
The balanced chemical equation is [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].
It can be seen that,
The number of Ag molecules on the reactant side is 2.
The number of Ag molecules on the reactant side is 2.
The number of K molecules on the reactant side is 2.
The number of K molecules on the reactant side is 2.
The balanced chemical equation is [tex]2AgNO_{3} + K_{2} CrO_{4}[/tex] → [tex]2KNO_{3} + Ag_{2} CrO_{4}[/tex].
Therefore, the correct answer will be an option (C).
To know more about the balanced chemical equation.
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What is the percent yield of lithium hydroxide from a reaction of 7.40g of lithium with 10.2g of water? The actual yield was measured to be 12.1g.
Answer:
[tex]\boxed{Percentage \ Yield = 47.6 \ percent}[/tex]
Explanation:
The balanced chemical reaction is
[tex]2Li + 2H_{2}O \ \ \ -> \ \ \ 2LiOH + H_{2}[/tex]
For the balanced reaction, we've
Lithium = 14 g
Water = 36 g
LiOH = 48 g
Hydrogen gas = 2 g
So,
14 g of lithium = 48 g of lithium hydroxide
And we have:
7.40 g of lithium = x grams of lithium hydroxide
Cross Multiplying,
x grams = [tex]\frac{48*7.4}{14}[/tex]
Grams of lithium = 25.4 g of lithium hydroxide
So, Theoretical Yield = 25.4 g of lithium hydroxide
Now, The %age yield:
%age Yield = [tex]\frac{Actual \ Yield}{Theoretical \ Yeild } * 100[/tex]
%age Yield = [tex]\frac{12.1}{25.4} * 100[/tex]
%age Yield = 47.6%