Which material allows light to pass through A. opaque materials only
B. transparent materials only C. translucent and opaque materials
D. transparent and translucent materials

Answer:

1525 meters above ground

Explanation:

So to do this you will need to write this in slope intercept form or [tex]y=mx+b[/tex]. So 650 would be the b, 175 would be the m, and the x would be 5 so the equation would be [tex]y=175(5)+650[/tex] so if you solve or simplify the equation you will get 1525 meters above the ground and that would be our final answer.

Answer:

p=m÷v

Explanation:

that is the formula for it. now, using your numbers p=density,m=mass and v= volume. you just divide it.

after you measurement would be in cm/3

Answer:

You can simply find density by using formula

[tex]d = \frac{m}{v} [/tex]

where m represents mass of an object and v represents volume of an object.

hope it helps..

Answer:

THE APPARENT CUBIC EXPANSIVITY OF A LIQUID : is defined as the increase in volume per unit volume per unit rise in temperature when the liquid is heated in an expansible vessel.

The only thing that mkes this question inconvenient is that it uses a mixture of units ... speed in km/hr, and acceleration in m/s².  You can't directly mash those together.

What's the speed when we express it in m/s ?

Speed = (90 km/hr) · (1,000 m/km) · (1 hr/3,600 sec)

Speed = (90 · 1,000 · 1 / 3,600) · (km-m-hr / hr-km-sec)

Speed = 25 m/s

OK great !  

-- The car is traveling at 25 m/s when the brakes are applied.

-- The brakes slow it down by 0.5 m/s every second.

-- So it takes (25/0.5) = 50 seconds to stop the car.

-- During that time, the car's average speed is (1/2)·(25m/s + 0) = 12.5 m/s .

-- Moving at an average speed of 12.5 m/s for 50 sec, the car travels

(12.5 m/s) · (50 s)  =  625 meters

Answer:

421.83 m.

Explanation:

The following data were obtained from the question:

Height (h) = 396.9 m

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

First, we shall determine the time taken for the ball to get to the ground.

This can be calculated by doing the following:

t = √(2h/g)

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 396.9 m

Time (t) =.?

t = √(2h/g)

t = √(2 x 396.9 / 9.8)

t = √81

t = 9 secs.

Therefore, it took 9 secs fir the ball to get to the ground.

Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:

Time (t) = 9 secs.

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

s = ut

s = 46.87 x 9

s = 421.83 m

Therefore, the horizontal distance travelled by the ball is 421.83 m

Answer:

C and D

Explanation:

A: is a simple composition

B: is a single replacement

C: C is a double displacement

D: is a double replacement

Answer:

The answers are C abd D.

Explanation:

Here,

A no. Is a combination or analysis chemical reaction.

B no.is a single displacement reaction as cl2 goes to zn.

C no. Is double displacement reaction.

D no. Is a double displacement reaction.

Hope it helps.....

Answer:

The best description of the general direction that the blue line points is East direction

Answer:

c. east

Explanation:

Answer:

the velocity of a moving body relative to another body is called relative velocity.

Answer:

A = [m/s]

B = [m/s²]

Explanation:

Assuming that V has SI units of m/s, then A and BT must also have units of m/s.

A = [m/s]

BT = [m/s]

Since T has SI units of s:

B [s] = [m/s]

B = [m/s²]

Answer:

A claim made by scientists backed up with evidence and research!

Explanation:

Hope this helped! :)

Answer:

  C.  lever

Explanation:

Any sort of prying tool is an example of a lever.

Answer:

A lever

Explanation:

Answer:

A. I and V

Explanation:

According to Le Chatelier's Principle, increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.  By the same principle, II is false.

For gases, decreasing the pressure will cause the equilibrium to shift towards the side with higher number of moles.  So V is true.

The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false.  And adding a catalyst has no effect on the equilibrium, so III is false.

The changes would result in more reactants being produced will increase NO₂ and decrease the pressure. Then the correct option is A.

The chemical reaction is the reaction between two reactants that led to the formation of products.

The products are substances that form after the reaction. The reactants are the substances that are original materials.

Given the reaction: N₂(g) +2O₂(g) ⇌ 2NO₂(g)

The forward reaction is endothermic. Increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.  

By the same principle, II is false.

For gases, the decrease in pressure will shift the equilibrium toward the high number of moles side.  

So V is true.

The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false.  Adding a catalyst has no effect on the equilibrium, so III is false.

The changes would result in more reactants being produced will increase NO₂ and decrease the pressure.

Then the correct option is A.

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Answer:

a) wavelength for the two frequencies are 0.33 m and 0.12 m

(b) 2560 MHz

Explanation:

Given:

microwave frequencies are

900 and 2560 MHz

f1= 900MHz we need to convert it to Go so the unit will be able to be consistent

f1= 900MHz= 900× 10^6Hz

f2= 2560 MHz= 2560×10^6Hz

a)Calculate the wavelength of each

But we can calculate our wavelength λ using the below formula

λ=c/f

c which is the speed of light has a constant value of =3*10^8m/s

Then for the first frequency

λ=c/f =(3×10^8)/900×10^6

=0.33 m

=33 cm.

For the second frequency

λ=c/f = (3×10^8)/2560×10^6

=0.12 m

=12 cm

(b) Which frequency would produce smaller hot spots in foods due to interference effects

(b) 2560 MHz( has the smallest wavelength)

This is because a small wavelength microwave gives a pattern with which is interference with waves and have a closer hotspot

Answer:

10 rad/s

Explanation:

The gears have the same linear speed.

ω₁ r₁ = ω₂ r₂

(25 rad/s) (2R) = ω (5R)

ω = 10 rad/s

Answer:

The actual height of the tree is 28 m

Explanation:

The given information are;

The length of the shadow of an upright meter rule = 25 cm

The actual height of the meter rule = 100 cm

The length of the shadow of the tree = 7 m

The actual  height of the tree  = h

We have

[tex]\dfrac{The \ length \ of \ the \ shadow \ of \ an \ upright \ metre \ rule}{The \ actual \ height \ of \ the \ metre \ rule} = \dfrac{The \ length \ of \ the \ shadow \ of \ the \ tree}{The \ actual \ height \ of \ the \ tree}[/tex]Which gives;

[tex]\dfrac{25 \ cm}{100 \ cm} = \dfrac{7 \ m}{The \ actual \ height \ of \ the \ tree}[/tex]

Therefore;

[tex]The \ actual \ height \ of \ the \ tree = 7 \ m \times \dfrac{100 \ cm}{25\ cm} = 7 \ m \times 4 = 28 \ m[/tex]

That is the actual height of the tree = 28 m.

Answer:

my big long peen for ur mom

Explanation:

Explanation:

It is given that,

Initial velocity of the projectile, u = 142 ft/s

Initial height off the ground, [tex]h_o = 93\ feet[/tex]

We need to find the height of the projectile t seconds after its shot. It is a concept of kinematics. The equation of projectile is given by the formula as follows :

[tex]h= -16t^2+ut+h_o[/tex]

t is time in seconds

So, putting all the values we get :

[tex]h= -16t^2+128t+112[/tex]

Hence, this is the required solution.

Answer:

We have 14 friends, and each team must have 6 players:

Then, in the two teams, we have 2*6 = 12 players.

This will mean that 2 of the friends can not be included in the game.

To solve this:

For example, each of those 2 players go to one of the teams, so we actually have two teams of 7 players.

Only 6 of them will play at the time, and the other player will rotate each fixed amount of time

Then the correct answer would be:

Rotate the players (in the teams) so all of them can play.

Answer:

The correct option is

a. The inductive reactance is doubled and the capacitive reactance is halved

Explanation:

For a series RLC circuit, is a resonant circuit such that the impedance, Z, is minimum at the resonance frequency

Also we have that the capacitive reactance [tex]X_C[/tex], is given as follows;

[tex]X_c = \dfrac{1}{\omega \cdot C}[/tex]

Where;

ω = Angular frequency = 2πf

Where;

f = The frequency in the circuit

[tex]\therefore X_c = \dfrac{1}{2 \cdot \pi \cdot f \cdot C}[/tex]

The inductive reactance is also given as follows;

[tex]X_L = \omega \cdot L = 2 \cdot \pi \cdot f \cdot L[/tex]

Therefore, when the circuit frequency doubles, the inductive reactance doubles and the capacitive reactance halves

When the alternating current frequency in a series RLC circuit is halved,  the inductive reactance is doubled and the capacitive reactance is halved.

An Alternating current (ac) frequency is known to be the amount of cycles per second that can be found  in an ac sine wave.

The Frequency is known to be the rate through which the current changes direction in terms of per second. It is said to be often measured in hertz (Hz). Note that the alternating current frequency in a series RLC circuit is halved,  the inductive reactance increases and the capacitive reactance is reduced.

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Answer:

The correct option is;

(b) The end A of the solenoid behaves like a north pole

Explanation:

According to Lenz's law we have that the induced emf direction in the solenoid due to the rapid introduction of the bar magnet will be such that the electric current induced will have a resultant magnet field that will  oppose to the movement of the north pole of the bar magnet that resulted in the magnetic field

Therefore, the opposing magnetic pole to the north pole of a magnet is a north pole and the solenoid end A will act like the north pole.

Answer:

50m/s

Explanation:

Formula:

velocity= distance/ time

velocity= 150/ 3

velocity= 50 m/s

I hope this helped you :)

When a  ball is launched horizontally at 150 m/s from a cliff then its horizontal velocity after 3 seconds would be 150 m/s, therefore the correct option is C.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.

The mathematical expression for velocity is given by

velocity= total displacement/Total time

Suppose an object has a total displacement of 100 meters in a total time of 25 seconds its velocity would be 4 meter/seconds

For the given problem situation when a ball is launched horizontally at 150 m/s from a cliff then its horizontal velocity after 3 seconds would be 150 m/s  because the horizontal component of the velocity remains constant during a projectile motion, therefore, the correct option is C.

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If we launched a very fast dart from the Space Shuttle in a direction away from any planet, Assuming the dart is traveling at an extremely high speed (close to the speed of light), it might eventually encounter a cloud of interstellar gas or dust.

Space is mostly empty, consisting of a vacuum with very low density. However, space also contains various astronomical objects, such as stars, planets, moons, asteroids, comets, and other celestial bodies.

There is also interstellar gas and dust scattered throughout space, which can sometimes form clouds that give birth to new stars. Additionally, space is permeated by electromagnetic radiation, including cosmic rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Space also contains various forms of energy, including dark energy, which is believed to be responsible for the accelerating expansion of the universe, and dark matter, which is thought to make up the majority of the matter in the universe but cannot be directly observed. Overall, space is a vast and complex environment that continues to fascinate astronomers and scientists.

Here in this question,

Therefore, if launched a very fast dart from the Space Shuttle, is pointed in some direction away from any planet, it could travel beyond the solar system. it would be most likely to hit a cloud of interstellar gas or dust. first after traveling outward for a while.

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Answer:

the answer B

Explanation:

Answer:

Explanation:

force on charge q  in electric field E = q E

force on charge of bee in given electric field

= 23 x 10⁻¹² x 100

= 23 x 10⁻¹⁰ N

weight of honey bee = .10 x 10⁻³ x 9.8

= 9.8 x 10⁻⁴ N

Ratio of force / weight of bee

= 23 x 10⁻¹⁰  / 9.8 x 10⁻⁴

= 2.347 x 10⁻⁶ .

Answer:

55 MW.

Explanation:

So, we are given the following data or parameters Below;

=> "2.0 MW is to arrive at a large shopping mall over two 0.100Ω line.

=> " the voltage is stepped up from 120 V to 1200 V and then down again, rather than simply transmitting at 120 V."

=> "Assume the transformers are each 99% efficient."

STEP ONE: determine the current in the transmission line.

Output Current, i = Power/ voltage.

Output Current,i = (2.0 MW × 10^6 W/ 1 MW)/120.

Output Current,i = 1.66 × 10^4 A.

Therefore, current in the transmission line = output voltage × output current/99% × line voltage.

= 120 × 1.66 × 10^4/ 99% × 1200 = 1.68 × 10^3 A.

STEP TWO: determine the power loss in the two lines.

Power loss = i^2 × Resistance

Power loss = (1.66 × 10^4 )^2 × 0.1 × 2 = 5.5 × 10^7 watt.

STEP THREE: determine the power generated.

Power generated = 2 × 10^6 +5.5 × 10^7.

Power generated = 5.57 × 10^7 watt.

STEP FOUR: determine the step down transformer power.

= 2 × 10^6/99% = 2.02 × 10^6.

Thus, 2.02 × 10^6 + 5.57 × 10^5 = 2.58 × 10^6 watt.

STEP FIVE: Determine the total power and the saved power.

Total power = 2.58 × 10^6/ 99%= 2.6 × 10^6.

Saved power = 5.7 × 10^7 - 2.6 × 10^6 .

Conversion to MW gives saved power = 55 MW.

=

if it is horizontal line, that means position is same but time is increasing.

velocity=0 . particle is not even moving

Answer:

1.01×10^20 molecules of ozone.

Explanation:

Data obtained from the question include:

Volume (V) = 2 L

Temperature (T) = 275 K

Pressure (P) = 1.89×10¯³ atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) of ozone =.?

Using the ideal gas equation, we can obtain the number of mole of ozone as follow:

PV = nRT

1.89×10¯³ x 2 = n x 0.0821 x 275

Divide both side by 0.0821 x 275

n = (1.89×10¯³ x 2) /(0.0821 x 275)

n = 1.67×10¯⁴ mole.

Therefore the number of mole of ozone in 2 L of air is 1.67×10¯⁴ mole.

Finally, we shall determine the number of molecules present in 1.67×10¯⁴ mole of ozone.

This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ozone contains 6.02×10²³ molecules.

If 1 mole of ozone contains 6.02×10²³ molecules,

therefore, 1.67×10¯⁴ mole of ozone will contain = 1.67×10¯⁴ x 6.02×10²³ = 1.01×10^20 molecules.

Therefore, 1.01×10^20 molecules of ozone are present in 2 L of air.

Answer:

According to the question ,

Source point is A and the destination point is D

We have to find the distance of AD

From figure,

AE = AB - EB

EB = DC and ED = BC

Therefore in triangle AED

AD² = AE² + ED²

AD² = 4² + 3²

AD² = 16 + 9

AD² = 25

AD = 5

So , the man is 5km far from the starting point

Hope this helps and pls mark as brainliest :)

Answer:

The distance of the goggle from the edge of the pool is 4.726 m

Explanation:

The given information are;

The depth of the swimming pool = 3.0 m deep

The height of the laser pointer above the swimming pool edge = 1.0 m

The distance from the pool edge the laser  pointer enters the water  = 2.0 m

The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°

Therefore, the angle of incidence to the vertical [tex]\theta_i[/tex],  = θ - ∅ = 90 - 26.57° = 63.43°

By Snell's law we have;

The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;

[tex]\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}[/tex]

Where:

[tex]n_r[/tex] = Refractive index of the refractive medium which is water = 1.33

[tex]n_i[/tex] = Refractive index of the incidence medium which is air = 1.00

Therefore;

[tex]\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}[/tex]

We have that tan([tex]\theta_r[/tex]) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)

tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)

∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m

The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water

The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m

The distance of the goggle from the edge of the pool = 4.726 m.