Which expression is equivalent to the following complex fraction?

Dhruv will most probably admit precisely 1 chocolate if the probability is0.2181 or (21.81%).

Probability refers to eventuality. This area of mathematics examines how arbitrary events be.

First, the total number of ways

= C( 11, 3)

= 11!/ 8! 31

= 11 x 10 x 9/ 3x 2

= 165

Now, If Dhruv gets exactly 1 chocolate there are now 7 chocolate and

3- 1 = 2 bars

So, the number of ways for 1 exactly one chocolate

= C( 9, 2)

= 9!/ 7! 21

= 9 x 8/ 2

= 36 ways

The liability that Dhruv receives exactly one chocolate is now.

= 36/ 165

= 12/ 55

Thus, the probability that Dhruv gets exactly 1 chocolate is 12/55 ≈0.2181 or 21.81%.

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Option A, 100 is the new area.

Explanation:
Let's assume that the length of the square is x. Then, according to the problem, the width of the square is one-fifth as long as the length, which means the width is x/5. The area of the square is given as 500, which means:

x * x = 500

x^2 = 500

x = sqrt(500) = 10 * sqrt(5)

So, the length of the square is 10 * sqrt(5). Using this information, we can find the width:width = x/5 = (10 * sqrt(5))/5 = 2 * sqrt(5)

Now we can find the new area of the square by multiplying the new length and width:new area = (2 * sqrt(5)) * (10 * sqrt(5)) = 100

Therefore, the new area of the square is 100, which is option A.

To calculate the probability of two separate events using the ratio method, we must first understand the odds associated with each event. The odds are expressed as a ratio, with the first number representing the chances of success and the second number representing the chances of failure. For example, the odds of an event happening might be 3:2, which indicates that there is a 3/5 chance of success.

Once the odds for each event are known, we can calculate the probability of both events occurring by multiplying the odds of each event together. So, for example, if the odds of Event A are 3:2 and the odds of Event B are 4:5, the probability of both events occurring is 3/2 * 4/5 = 6/10. This means that there is a 6 in 10 chance of both events occurring.

To sum up, calculating the probability of two separate events using the ratio method is fairly simple. Just look at the odds associated with each event and multiply them together to get the probability of both events occurring.

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Answer:

Step-by-step explanation:

When the triangle is rotated about the side with a length of 8 cm, it forms a cone with a base radius equal to 4 cm and height equal to 6 cm.

Using the formula for the volume of a cone, V = 1/3 * πr^2h, where r is the radius and h is the height, we can find the volume of the resulting solid:

V = 1/3 * π * 4^2 * 6

V ≈ 100.53 cubic centimeters

To find the approximate base area, we need to calculate the area of the circle with a radius of 4 cm (the base of the cone):

A = πr^2

A ≈ 50.27 sq. cm

Therefore, the approximate base area of the resulting three-dimensional figure is about 50.27 sq. cm.

So, the closest option available in the given choices is 38 sq. cm, but the correct answer based on calculations is approximately 50.27 sq. cm.

Answer:

I just did the quiz. Look below.

Step-by-step explanation:

There are n x (n-1) number of ways for the speaker and vice speaker to be selected in the demonstrator's party, where n is the number of members in the party.

For the demonstrator's party, the first position of the speaker can be filled by any of the n members. After the speaker is chosen, there are n-1 members left to select from for the position of vice speaker. Therefore, the total number of ways the speaker and vice speaker can be selected is n x (n-1).

For example, if the demonstrator's party has 4 members, there are 4 choices for the speaker position. After the speaker is chosen, there are 3 choices left for the position of vice speaker. So, the total number of ways to select a speaker and vice speaker in the party is 4 x 3 = 12.

This formula can be applied to any size of the party to determine the total number of possible ways to select a speaker and vice speaker.

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we can download 2 songs for £2 if each song costs 90p. This calculation can be useful for budgeting and planning purchases, and it shows the importance of being mindful of the cost of individual items when making larger purchases.

To find out how many songs can be downloaded for £2, we need to divide £2 by the cost of each song.

We know that each song costs 90p, which is equivalent to £0.90. Therefore, we can set up the following equation:

£2 / £0.90 per song = x songs

To simplify the equation, we can first divide £2 by £0.90 to get the number of songs that can be downloaded:

£2 ÷ £0.90 = 2.22 (rounded to two decimal places)

So we can download 2.22 songs with £2. However, since we can't download a fraction of a song, we need to round down to the nearest whole number of songs.

Therefore, we can download 2 songs with £2 if each song costs 90p.

We can also verify this by multiplying the number of songs by the cost per song:

2 songs × 90p per song = £1.80

This means that we have spent £1.80 on two songs, leaving us with £0.20. We cannot afford another full song, so we cannot download a third song.

In conclusion, we can download 2 songs for £2 if each song costs 90p. This calculation can be useful for budgeting and planning purchases, and it shows the importance of being mindful of the cost of individual items when making larger purchases.

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There are 6720 8-letter words that can be formed from the letters of the word "wasteful" if repetition is not allowed.

To form an 8-letter word from the letters of the word "wasteful" without repetition, we must choose 8 letters from the 7 distinct letters "w", "a", "s", "t", "e", "f", "u" available.

Let's use the permutation formula to find the number of ways we can do this.

Permutation = (Number of objects)! / ((Number of objects) - r)!Permutation = 7! / (7 - 8)!Permutation = 7! / (-1)!But (-1)! is undefined, so there are no 8-letter words that can be formed from the letters of the word "wasteful" without repetition.

If repetition was allowed, then the number of 8-letter words that could be formed = 7^8 = 5764801.

Hence, the number of 8-letter words that can be formed from the letters of the word "wasteful" if repetition is not allowed is 6720.

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Option C is a system of inequalities that best fits the figure.

To find a system of inequalities, find the inequality represented by each row.

First, let's determine the slope. You can use the gradient formula to do this.

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Taking (0, 1) and (1, 3) and plugging them into the gradient equation gives:

[tex]m=\frac{3-1}{1-0}[/tex]

[tex]m=\frac{2}{1} =2[/tex]

To write the equation for the red line, we can use the intercept form of the slope.

y=mx+b

The y-intercept of the red line is (0, 1). Therefore, it is already established that b = 1 and m = 2.

y=2x+1

Note that the shaded area is below the red line. Therefore y is less than the expression.

[tex]y\leq 2x+1[/tex]

let's find the slope again. Two points are available: (0, 2) and (2, 3). with this:

m=[tex]\frac{3-2}{2-0} =\frac{1}{2}[/tex]

So the slope is 1/2. Note that the y-intercept is (0, 2). So replace m with 1/2 and b with 2.

[tex]y=\frac{1}{2}x+2[/tex]

y is greater than the formula because the shaded area is above the blue line. The sign is above because it is shaded. So the formula is:

[tex]y\geq \frac{1}{2}x+2[/tex]

Hence the inequalities are:

[tex]y\leq 2x+1\\y\geq \frac{1}{2}x+2[/tex]

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Answer:

Step-by-step explanation:

Its answer A.

y < 2x + 1

y > 1/2 x + 2

The output of the graphed function when x = 6 is given as follows:

y = 1.2.

The coordinates of the vertex are (h,k), meaning that:

Considering a leading coefficient a, the quadratic function is given as follows:

y = a(x - h)² + k.

The vertex is the turning point of a quadratic equation, hence it's coordinates for this problem are given as follows:

(0, -6).

Meaning that the function is defined as follows:

y = ax² - 6.

When x = 5, y = -1, hence the leading coefficient a is obtained as follows:

-1 = 25a - 6

a = 0.2.

Hence the function is:

y = 0.2x² - 6.

Hence the output when x = -6 is given as follows:

y = 0.2(-6)² - 6

y = 1.2.

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Answer: 1 1/12

Step-by-step explanation:

so you would subtract 2-1=1

Then you do 1/3-1/4=1/12

The answer would be 1 1/12

UR WELCOME

Answer:

10

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms.

Defining a confidence interval is important in analyzing a dataset to test the validity of data. The choice of population parameter, test statistic, and confidence interval depends on the type of data being analyzed and the level of confidence required by the researcher.

When analyzing a dataset, it is important to determine the confidence interval to test the validity of the data. The confidence interval measures the precision of an estimate and indicates the range in which the population parameter is likely to exist.

There are several types of datasets where defining a confidence interval would be important for testing validity of data, some of them include;

1. Medical research: In medical research, researchers gather data to examine how a treatment plan affects a group of people. They can define a confidence interval to determine the range of possible outcomes. They use the test statistic to help them determine how significant the results are.

2. Business Data: When analyzing business data, defining a confidence interval is crucial to determine the success rate of a marketing campaign, sales data, or employee turnover. It allows the business to assess their performance and make data-driven decisions.

3. Political Polling: When conducting political polls, defining a confidence interval is necessary to determine the reliability of the data. It helps the pollsters to estimate the likely outcome of the election and the level of confidence that can be placed in the results.

When analyzing a dataset, it is essential to determine which population parameter and test statistic to use. The population parameter is the numerical value that describes the entire population. It can be the mean, proportion, variance, or standard deviation. The test statistic is used to determine if the population parameter is within the confidence interval, or if it lies outside the interval. The choice of population parameter and test statistic depends on the type of data being analyzed.

The confidence interval to choose depends on the level of confidence required by the researcher. The commonly used confidence intervals are 90%, 95%, and 99%. The level of confidence chosen by the researcher determines the size of the interval. The higher the confidence level, the wider the confidence interval. The researcher should choose a confidence interval that is wide enough to contain the population parameter, but not too wide to reduce the precision of the estimate.

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a) The number of areas sampled within a stream site is directly proportional to the taxa richness values obtained.

b)  If the number of areas sampled is increased to 500, the taxa richness values would be expected to increase even further, as more areas increase the likelihood of encountering rare and less frequently occurring species

The number of areas sampled within a stream site is directly proportional to the taxa richness values obtained. In general, the more areas sampled, the higher the number of taxa observed. Therefore, in the scenario where only 5 areas are sampled, the taxa richness values obtained would be lower than those obtained from 50 sampled areas.

Similarly, increasing the number to 500 would likely result in even higher taxa richness values. However, it is important to note that there is a point of diminishing returns where the number of additional areas sampled does not result in a significant increase in taxa richness values. Therefore, the number of areas to sample should be determined based on available resources and the goals of the study.

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The given question is incomplete, the complete question is:

In designing an invertebrate biodiversity study of a stream, different areas within the study site need to be sampled. A major consideration is how many areas to sample, which will largely be determined by available resources (people, money, time). Imagining two possible scenarios, one where only 5 areas within a stream site are sampled, and another where 50 are sampled, how would the taxa richness values of the two differ? If the number was increased to 500, how might it change?

An exponential model for the worth of the savings account is [tex]W = 1250(1.045)^t[/tex]

The worth predicted by the exponential model is greater than predicted by the linear model at the end of 2020 by $131.2.

In Mathematics, an exponential function can be modeled by using the following mathematical equation:

[tex]f(x) = a(b)^x[/tex]

Where:

Based on the information provided about the savings account, we would determine the growth rate as follows;

[tex]W = P_{0}e^{rt}[/tex]

Growth rate, r = 1/(1 - 0)ln(1250/1306)

Growth rate, r = ln(1250/1306)

Growth rate, r = 0.0438

In the form [tex]W = a(b)^t[/tex], the required exponential function is given by;[tex]W = 1250(1.045)^t[/tex]

Years = 2020 -2010 = 10 years.

From the linear function, we have:

W = 56t + 1250

W = 56(10) + 1250

W = $1,810.

From the exponential function, we have:

[tex]W = 1250(1.045)^t\\\\W = 1250(1.045)^{10}[/tex]

W = $1,941.2

Difference = $1,941.2 - $1,810

Difference = $131.2.

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Answer:

$12.50

Step-by-step explanation:

62% would be left,so

[tex]\frac{62}{100}[/tex] × $20

=$12.50

⇒First take out the highest common factor 2 form the quadratic equation and divide each and every term of that equation by that common factor.

⇒Factorise the equation and equate the factors of the equation to 0 and solve for the unknown variable x.

⇒Below are the steps on solving for the unknown variable.

[tex]2(x^{2} -14x+49)=0 \\\frac{2(x^{2} -14x+49)}{2} =\frac{0}{2} \\x^{2} -14x+49=0\\(x-7)(x-7)=0\\x-7=0\\x=7[/tex]

The width of the enlargement will be 9 inches since the ratio of the length and width of the original recipe card is equal to the ratio of the length and width of the enlarged recipe card.

Since we want to enlarge the recipe on a 3-inch-by-5-inch index card to a length of 15 inches while maintaining the same proportions, we can use equivalent ratios to find the width of the enlargement.

Let x be the width of the enlargement in inches. Then, we can set up the following ratio:

3/5 = x/15

This ratio is formed by comparing the length and width of the original recipe card with the length and width of the enlarged recipe card.

To solve for x, we can cross-multiply and simplify:

3/5 = x/15

=> 3 * 15 = 5 * x

=> 45 = 5x

=> x = 9

Therefore, the width of the enlargement will be 9 inches.

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Yes

The logarithm function is continuous for all x>0. Its derivative is 1/x and r12 ln x dx = x ln x - x + c.

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The corticospinal tracts carry information from the motor cortex, which is responsible for coordinating the movement of muscles, to the lower motor neurons. The extra-pyramidal tracts are made up of several types of neurons that play a role in modulating and fine-tuning the movement of muscles.

Neurons in the central nervous system (CNS) send instructions to muscles along a descending neural network called the descending motor pathways, which decussate in the medulla oblongata. This means that information from the brain travels down the spinal cord on both sides of the body, and crosses over to the opposite side at the medulla. The descending pathways start from the brainstem and motor cortex, and control the contraction of skeletal muscles, which are responsible for body movements.

The descending motor pathways are a series of neurons that connect the CNS to the muscles, transmitting the information required for voluntary body movements. Through the descending pathways, the brain can communicate with the muscles and control them. The pathways are divided into two parts, the corticospinal tracts and the extra-pyramidal tracts.

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The percentage of the area under the density curve where x is less than 2 is 50%.

What is percentage?

A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. The proportion therefore refers to a component per hundred.

To find the percentage of the area under the density curve where x is less than 2, we need to find the area under the curve to the left of x = 2 and divide it by the total area under the curve.

To calculate the area under the curve to the left of x = 2, we can break it up into two parts: the rectangular area to the left of x = 2 and the triangular area above it.

The rectangular area has a width of 2 and a height of 0.2, so its area is 2 × 0.2 = 0.4.

The triangular area has a base of 2 and a height of 0.2 - 0 = 0.2, so its area is (1/2) × 2 × 0.2 = 0.2.

Therefore, the total area under the curve to the left of x = 2 is 0.4 + 0.2 = 0.6.

To find the total area under the curve, we can calculate the area of the rectangle with width 6 and height 0.2, which is 6 × 0.2 = 1.2.

So the percent of the area under the density curve where x is less than 2 is -

(0.6 / 1.2) × 100% = 50%

Therefore, the area under curve is obtained as 50%.

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The probability that an even number or a number greater than 3 is rolled on a 12-sided die is 0.833.

A 12-sided die has 12 equally likely outcomes, numbered from 1 to 12. To find the probability of rolling an even number or a number greater than 3, we need to count the number of outcomes that satisfy this condition and divide it by the total number of possible outcomes.

There are 6 even numbers on a 12-sided die, namely 2, 4, 6, 8, 10, and 12, and there are 9 numbers greater than 3, namely 4, 5, 6, 7, 8, 9, 10, 11, and 12. However, we need to be careful not to count the numbers that satisfy both conditions twice, namely 4, 6, 8, 10, and 12.

Therefore, the number of outcomes that satisfy the condition is 6 + 9 - 5 = 10. The probability of rolling an even number or a number greater than 3 is therefore 10/12, which simplifies to 5/6 or approximately 0.833.

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433 students like at most two types of these chocolate candies.

A survey of 500 high school students was conducted to determine their favorite chocolate candy.

139 students liked snickers, 184 liked Twix, 181 liked Reese's Peanut Butter Cups, 129 liked Snickers and Twix, 109 liked Twix and Reese's Peanut Butter Cups, 71 liked Snickers and Reese's Peanut Butter Cups, and 70 liked all three types of chocolate candy. So, how many students like at most two types of these chocolate candies?

Step-by-step explanation:

If you use the Principle of Inclusion-Exclusion, you can figure out how many students enjoy two or fewer candies. The PIE formula is as follows:

n(Snickers U Twix U Reese's) = n(Snickers) + n(Twix) + n(Reese's) - n(Snickers ∩ Twix) - n(Snickers ∩ Reese's) - n(Twix ∩ Reese's) + n(Snickers ∩ Twix ∩ Reese's)n(Snickers U Twix U Reese's)

= 139 + 184 + 181 - 129 - 109 - 71 + 70

n(Snickers U Twix U Reese's) = 503

Students who liked two or fewer types of candies can be found by subtracting the number of people who liked all three from the total number of individuals in the study who like any one candy.

503 - 70 = 433 students

Therefore, 433 students like at most two types of these chocolate candies.

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Answer:

Y = 4x

Step-by-step explanation:

In this equation, x represents the input value, and Y represents the output value. Coefficient 4 illustrates the rate of change or slope of the function, indicating that for every unit increase in x, the value of Y increases by four units. When x is 0, Y is also 0, consistent with the given data. Similarly, when x is 1, 2, and 3, Y is 4, 8, and 12, respectively, matching the provided output values.

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 850\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=years \end{cases} \\\\\\ 850 = 500[1+(0.1)(t)] \implies \cfrac{850}{500}=1+0.10t\implies \cfrac{17}{10}=1+0.10t \\\\\\ \cfrac{17}{10}-1=0.10t\implies \cfrac{7}{10}=0.10t\implies \cfrac{7}{(10)(0.10)}=t\implies 7=t[/tex]

When taking data at different inclined plane angles, it will have an effect on the final results specifically the uncertainties because of gravitational force.

       This is because as the angle of the plane increases, the gravitational force acting on the object decreases, while the force of friction increases.

         Therefore, by taking data at different inclined-plane angles, the uncertainties in the results will be affected. The uncertainties will increase as the angle of the plane increases because it becomes more difficult to measure the gravitational force acting on the object. In order to minimize uncertainties, it is recommended to take measurements at several different angles and take an average of the results.

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The values of a and b are a = 1 and b = π/4.

Explanation:

We know that the height of the innertube can be modeled by the function:

h = asinbx + 3

where h is the height in meters,

a is the amplitude of the wave,

b is the frequency of the wave in cycles per meter, and

3 is the average height of the wave.

We also know that the innertube's height fluctuates between 2 meters and 4 meters, so we can set up the following equation:

2 <= asinbx + 3 <= 4

Subtracting 3 from each term, we get:

-1 <= asinbx <= 1

Dividing by a, we get:

-1/a <= sinbx <= 1/a

Since the maximum value of sinbx is 1 and the minimum value is -1, we know that:

1/a >= 1 or -1/a <= -1

Simplifying, we get:

a <= 1 or a >= -1

However, a must be positive because it represents the amplitude of the wave. Therefore, we have:

a >= 1

Next, we can use the fact that the innertube reaches its maximum height every 8 seconds to find the value of b. Since the period of a sine function is given by:

period = 2π / b

and the period in this case is 8 seconds, we have:

8 = 2π / b

Solving for b, we get:

b = 2π / 8 = π / 4

Therefore, the values of a and b are:

a = 1 and b = π / 4

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[tex] \: [/tex]

[tex] \: [/tex]

put the value of y = 2 in equation

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

[tex] \: [/tex]

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hope it helps ⸙

The measures such as overall team free throw percentage, the percentages of the other players, the median, the mean, and the shape of the distribution would remain the same.

The 3 players with the highest free throw percentage increased their percentage by 4 points, but all other statistical measures, such as overall team free throw percentage and the percentages of the other players, would stay the same.

The overall team free throw percentage is calculated by adding the percentages of all players and dividing the total by the number of players. Since the percentages of the other players remain the same, the overall team free throw percentage would remain unchanged.

Additionally, since only the 3 players with the highest percentages increased theirs, the median and mean of the free throw percentages would remain the same.

The increase in free throw percentage of the 3 players affects the free throw percentage distribution, but the shape of the distribution would remain the same.

That is, the distribution will still have the same range, but the 3 players with the highest free throw percentage would have a slightly higher percentage.

In conclusion, the only statistical measure that would change after Mrs. Carroll recalculates the free throw percentages of the team is the percentage of the 3 players with the highest free throw percentage, which would increase by 4 points.

All other measures, such as overall team free throw percentage, the percentages of the other players, the median, the mean, and the shape of the distribution would remain the same.

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Answer:

True.

explanation:

The data from the Florida Crash Reports and annual registrations and licensure numbers indicate that in 2004, 416 motorcyclists  died in Florida while in 2008 the number reached 532.In 2008, 55 % of the fatalities were wearing helmets, while 35% were with no helmet. The Florida Rider Training Program (FRTP) is an effort established to educate the public on fatalities in motor cycle fatalities.