When a cold air mass catches up with a warm air mass, the resut is often
a(n)
front.

Answer:

a. Remain the same.

Explanation:

The total energy of the spring mass system is given as

[tex]$E=\frac{1}{2}kx^2 $[/tex]

where k is the spring constant of the spring

           x is the compression or expansion of the spring

The energy of the spring mass system is always independent of mass. It does not depends on the mass object attached to the spring.

Therefore, the total energy of the system will remain the same in the experiment when the mass is changes the second time.

Answer:

0.12C

Explanation:

A defibrillator passes 12A through the torso of an individual

The time is 0.0100

The charge can be calculated as follows

= I × t

= 12 × 0.0100

= 0.12C

Hence the charge is 0.12C

Answer:

Yes

Explanation:

because that temperature creates the bulk movement of molecules due to increase in their kinetic energy

Answer:

a)  v = 0.515 km / min ,   b)  x_total = 52 km

Explanation:

The measured speed is defined by the distance traveled between the time

         v = [tex]\frac{\Delta x}{\Delta t}[/tex]

In this case they give us the speed in several time intervals

let's find the distance traveled in each interval

a) Goes at 75 km/h for 10 min

        v = [tex]\frac{x}{t}[/tex]x / t

         x₁ = v t

let's reduce speed to km / min

         v₁ = 75 km / h (1h / 60 min) = 1.25 km / min

the distance traveled in this time is

        x₁ = 1.25 10

        x₁ = 12.5 km

b) goes to v = 95 km / h for 6 min

        v = 95 km / h (1h 60 min) = 1.5833 km / min

the distance traveled is

        x₂ = v₂2 t

        x₂ = 1.58333 6

        x₂ = 9.5 km

c) goes to v = 40 km / h for 45.0 min

         v₃ = 40 km / h (1 h / 60min) = 0.6667 km / min

         x₃ = 0.6667 45

         x₃ = 30 km

d) t = 40 min, stopped

         x₄ = 0

A) let's calculate the average speed of the trip

          v =[tex]\frac{x_{1}+x_{2}+x_{3}+x_{4} }{t_{1}+t_{2}+t_{3}+t_{4} }[/tex]

          v = (12.5 +9.5 +30 +0) / (10 +6 +45 +40)

          v = 52/101

         v = 0.515 km / min

B) the distance between the two cities is

        x_total = x₁ + x₂ + x₃

        x_total = 12.5 +9.5 + 30

        x_total = 52 km

Correct question is;

A tiny water droplet of radius 0.010 cm descends through air from a high building .Calculate its terminal velocity . Given that η of air = 19 × 10^(-6) kg/m.s and density of water ρ = 1000kg/ms

Answer:

1.146 m/s

Explanation:

We are given;

Radius; r = 0.010 cm = 0.01 × 10^(-2) m

η = 19 × 10^(-6) kg/m.s

ρ = 1000 kg/ms

The formula for the terminal velocity is given by;

V_t = 2r²ρg/9η

g is acceleration due to gravity = 9.8 m/s²

Thus;

V_t = (2 × (0.01 × 10^(-2))² × 1000 × 9.8)/(9 × 19 × 10^(-6))

V_t = 1.146 m/s

Answer: Option C.

Explanation:

When the box is moving, he pushes with a force F.

in this case, the coefficient is μk, and the box is accelerating, this means that the net force is not zero, so F is larger than the friction force.

When the box is still, the man pushes again with a force F, but now the box does not move, so there is no acceleration, which means that the net force is zero, then F is not greater than the maximum static friction force.

Now, the friction force between an object of mass M, and a surface with a coefficient of friction  μ is:  μ*m*g

where g is the gravitational acceleration.

Then, from the first part, we can conclude that:

μk*m*g < F

(the force F is larger than the kinetic friction force)

and from the second part, we know that:

F ≤  μs*m*g

(The force F is not greater than the static friction force)

If we write those two together, we have:

μk*m*g < F ≤  μs*m*g

Then the correct option is c.

Answer:

The needed force is 35,000 N.

Explanation:

By the second Newton's law, we know that:

F = M*a

Force equals mass times acceleration.

If we know that the mass of the car is 1750kg, then M = 1750kg, and the acceleration is 20 m/s^2, then a = 20m/s^2

We can replace these values in the original equation to find the value of F.

F =  1750kg*20 m/s^2 = 35,000 N

The dive profile used when planning our dive would be 22 metres/70 feet for 30 minutes.

Diving is the sport or activity of swimming for exploring under water.

My buddy and I are planning to dive at a site where the water and air temperature are near freezing. We plan to dive to 18 meters for 30 minutes.

A General rule as printed on the RDP Table and eRDPML is that if someone planning a dive in cold water that might be harmful. Plan the dive assuming the depth is 4 meters/10 feet deeper than actual. For any other information, see the RDP/eRDPML Instructions for Use booklet.

Thus, dive profile used would be 22 metres/70 feet for 30 minutes.

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Answer:

30 mm

Explanation:

[tex]\lambda[/tex] = Wavelength of light = 503 nm

d = Diameter of hole = 0.2 mm

D = Distance of screen from light source = 4.9 m

Diameter of the central bright area is given by

[tex]x=\dfrac{2.44\lambda D}{d}\\\Rightarrow x=\dfrac{2.44\times 503\times 10^{-9}\times 4.9}{0.2\times 10^{-3}}\\\Rightarrow x=0.03\ \text{m}=30\ \text{mm}[/tex]

The diameter of the central bright area is 30 mm.

Answer:

[tex]149.112\ \text{N}[/tex]

[tex]120.94\ \text{N}[/tex]

[tex]302.77\ \text{N}[/tex]

[tex]58.44\ \text{N}[/tex]

Explanation:

m = Mass of block = 15.2 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

[tex]\theta[/tex] = Angle

a = Acceleration

F = Applied force

Normal force is given by

[tex]N=mg\\\Rightarrow N=15.2\times 9.81\\\Rightarrow N=\boldsymbol{149.112\ \mathbf{N}}[/tex]

[tex]\theta=35^{\circ}[/tex]

[tex]N=mg\cos\theta\\\Rightarrow N=15.2\times 9.81\times \cos35.8^{\circ}\\\Rightarrow N=\mathbf{120.94\ N}[/tex]

[tex]a=3.53\ \text{m/s}^2[/tex]

[tex]N=m(g+a)\\\Rightarrow N=15.2(9.81+3.53)\\\Rightarrow N=\boldsymbol{302.77\ \mathbf{N}}[/tex]

[tex]F=155\ \text{N}[/tex]

[tex]N=mg-F\sin35.8^{\circ}\\\Rightarrow N=15.2\times 9.81-155\sin35.8^{\circ}\\\Rightarrow N=\boldsymbol{58.44\ \mathbf{N}}[/tex]

Answer:

All true statements are shown: a) The average speed of the car is [tex]\frac{v}{2}[/tex], c)The magnitude of the acceleration of the car is [tex]\frac{v}{t}[/tex].

Explanation:

Let prove the validity of each statement:

a) The average speed of the car is [tex]\frac{v}{2}[/tex].

The average speed ([tex]\bar v[/tex]) is defined by the following formula:

[tex]\bar v = \frac{v_{o}+v_{f}}{2}[/tex] (1)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the racing car.

If we know that [tex]v_{o} = 0[/tex] and [tex]v_{f} = v[/tex], then the average speed of the racing car:

[tex]\bar v = \frac{0+v}{2}[/tex]

[tex]\bar v = \frac{v}{2}[/tex]

The statement is true.

b) The car travels a distance [tex]v\cdot t[/tex].

Since the racing car is accelerating uniformly, the distance travelled by the car is represented by the following kinematic formula:

[tex]x - x_{o}=v_{o}\cdot t + \frac{1}{2}\cdot a\cdot t^{2}[/tex] (2)

Where [tex]a[/tex] is the acceleration of the racing car, measured in meters per square second.

The statement is false.

c) The magnitude of the acceleration of the car is [tex]\frac{v}{t}[/tex].

Since the racing car is accelerating uniformly, the velocity of the racing car is represented by the following kinematic formula:

[tex]v_{f} = v_{o}+a\cdot t[/tex] (3)

Then, we clear the acceleration of the expression:

[tex]a = \frac{v_{f}-v_{o}}{t}[/tex]

If we know that [tex]v_{o} = 0[/tex] and [tex]v_{f} = v[/tex], then the acceleration of the car is:

[tex]a = \frac{v-0}{t}[/tex]

[tex]a = \frac{v}{t}[/tex]

The statement is true.

d) The velocity of the car remains constant.

Since the car accelerates uniformly, the vehicle does not travel at constant velocity.

The statement is false.

Answer:

981N

Explanation:

The gravitational force between the football player and the Earth at the given distance is 979.91 N.

The given parameters:

The gravitational force between the football player and the Earth at the given distance is calculated by applying Newton's law of universal gravitation as follows.

[tex]F = \frac{GmM}{r^2} \\\\F = \frac{6.67 \times 10^{-11} \times 100 \times 5.98 \times 10^{24}}{(6.38 \times ^6)^2} \\\\F = 979.91 \ N[/tex]

Thus, the gravitational force between the football player and the Earth at the given distance is 979.91 N.

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Answer:

Median

Explanation:

Extra information:-

Median formula:-

[tex]\boxed{\begin{minipage}{6cm}$\bigstar$\:\:\sf Median = l + $\sf\dfrac{\frac{n}{2}-C.f.}{f}\times h\\\\Here: \\1)\:n = \sum f =\\2)\:l=Lower\:limit\:of\:median\:class=\\3)\:C.f.=Cumulative\:frequency\:of\:class\\preceeding\:the\:median\:class=\\4)\:f= frequency\:of\:median\:class=\\5)\:h= Class\:interval = \end{minipage}}[/tex]

Answer:

The answer is above this

Explanation:

Answer:

The correct answer is a

Explanation:

The electric field is given by the relation

         F = q E

where The force is the Coulomb force and q is a positive test charge, therefore the electric field has the same direction as the electric force.

Consequently if the charge is positive the field must go out of the charge, if the charge is negative the electric field must be directed towards the charge.

Consequently, in this exercise we are told that the lines are directed towards the load, therefore the load must have a negative sign.

The correct answer is a

Answer:

Stationary listener frequency = 77.68 kHz

Explanation:

Given:

Speed of airplane = 344/2 = 172 m/s

Sound of frequency = 5.84 kHz

Computation:

f0 = fs[(v+v0)/(v-vs)]

f0 = 5.84[(344+0)/(344-172)]

f0 = 5.84[(344)/172]

Stationary listener frequency = 77.68 kHz

Answer:

The value is [tex]q = 3.4 *10^{-6} \ C[/tex]

Explanation:

From the question we are told that

    The mass of each sphere is [tex]m_1 = m_2 = m = 0.020 \ kg[/tex]

     The length of the string is  [tex]l = 0.18 \ m[/tex]

     The angle of with the vertical is [tex]\theta = 7^o[/tex]

      The acceleration due to gravity is [tex]g = 9.8 \ m/s^2[/tex]

Generally the force acting between the forces is mathematically represented as

       [tex]F = T cos \theta = \frac{k* q^2}{ r^2}[/tex]

=>     [tex]T cos \theta = \frac{k* q^2}{ r^2}[/tex]

Generally from Pythagoras theorem the radius of the circular curve created by the force is

         [tex]r = 2 L sin (\theta )[/tex]

=>      [tex]r = 2* 0.180 sin (7)[/tex]

=>      [tex]r = 0.043 \ m[/tex]  

=>     [tex]q = tan \theta * \frac{m * g * r^2 }{k}[/tex]

=>      [tex]q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}[/tex]

=>      [tex]q = 3.4 *10^{-6} \ C[/tex]

Answer:

1.5* 10¹⁵ Hz

Explanation:

        [tex]c = \lambda * f (1)[/tex]

       [tex]f = \frac{c}{\lambda} = \frac{3e8m/s}{200e-9m} = 1.5e15 1/sec = 1.5e15 Hz (2)[/tex]

Answer:

Magnitude of the force = 1.25 N

Explanation:

Given:

Spring constant k = 50.0 N/m

Distance s = 2.50 cm = 0.025 m

Find:

Magnitude of the force

Computation:

Magnitude of the force = Ks

Magnitude of the force = 50 x 0.025

Magnitude of the force = 1.25 N

Given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.

Potential difference is simply referred to as work done required to move a charge from point A to point B per unit charge.

It is expressed as;

V = W / q

Given the data in the question;

We substitute our values into the exression above.

V = W / q

V = 10J / 2C

V = 5V

Therefore, given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.

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Mesas form by weathering and erosion of horizontally layered rocks that have been uplifted by tectonic activity. Variations in the ability of different types of rock to resist weathering and erosion cause the weaker types of rocks to be eroded away, leaving the more resistant types of rocks topographically higher than their surroundings. This process is called differential erosion. 

Hope it helps!

Answer:

negative plus positive with energy = battery

Explanation:

It is given that up direction be positive.

Ball velocity at the time is was dropped is 3 m/s.

g = -9.8 m/s²

s = -50 m

Now, using equation of motion for time :

s = ut + at²/2

3t - 4.9t² + 50 = 0

4.9t² - 3t - 50 = 0

Solving above equation, we get :

t = 3.52 s

Therefore, the rock will splash into the water after 3.52 s.

Answer:

kinetic energy + potential energy

Answer:

D is the correct answer: Total energy = Kinetic energy + potential energy

Answer:

The answer would be a

Explanation:

Answer:

(a) 0.92 cm= 0.092 m.

(b) 141.64 g=0.14164 kg.

(c) 15. 8 cm³=0.0000158 m³

(d) 63.6 g/cm³= 63600 kg/m³

Explanation:

The International System of Units, abbreviated S.I., also called the International System of Measurements is a system of measurements in which its units are based on fundamental physical phenomena. The units of the S.I. They are the international reference for the indications of all measuring instruments.

The International System of Units (SI) arose from the need to unify and give coherence to a great variety of unit subsystems.

The International System of Units consists of seven basic units, also called fundamental units, which define the corresponding fundamental physical quantities and which allow any physical quantity to be expressed in terms or as a combination of them. The fundamental physical quantities are complemented by two more physical quantities, called supplementary ones.

By combining the basic units, the other units are obtained, called units derived from the International System, and which allow defining any physical quantity.

(a)  The SI unit of length is the meter. Being 1 cm = 0.01 m, then 0.92 cm= 0.092 m.

(b)  The SI unit of mass is kg. Being 1 g = 0.001 kg, then 141.64 g=0.14164 kg.

(c) Being 1 cm³ = 0.000001 m³, then 15. 8 cm³=0.0000158 m³

(d) Being 1 g/cm³= 1000 kg/m³, then 63.6 g/cm³= 63600 kg/m³

Answer:

D

Explanation:

Valley Formations

Answer:

-4.35 × 10^-6 N

Explanation:

i just answered it on ap3x :)

Answer:

68 kg/m

Explanation:

bro

Answer:

C. Gas

Explanation:

Segment CD represents gaseous phase of matter as segment CD shows highest energy which is in case of gas.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.The intermolecular forces of attraction are different in different states of matter.Particles of matter have different sizes.

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