what kind of pressure prevents a white dwarf from collapsing?

The total sound intensity level is approximately 87 dB.

When two sounds with different intensities are present simultaneously, the total sound intensity level is found by adding the individual sound intensity levels in decibels (dB) using the following equation,

L_total = 10 log10(I_total/I_0)

where L_total is the total sound intensity level, I_total is the total sound intensity, and I_0 is the reference sound intensity (usually taken as 10^-12 W/m^2).

In this case, we have two sounds with intensity levels of 80.0 dB and 90.0 dB. To find the total sound intensity level, we first need to convert each intensity level to sound intensity,

I_1 = I_0 10^(L_1/10) = (10^-12 W/m^2) 10^(80.0/10) = 10^-5 W/m^2

I_2 = I_0 10^(L_2/10) = (10^-12 W/m^2) 10^(90.0/10) = 10^-4 W/m^2

where L_1 and L_2 are the intensity levels of the two sounds in dB.

The total sound intensity is the sum of these two sound intensities,

I_total = I_1 + I_2 = 10^-5 W/m^2 + 10^-4 W/m^2 = 1.1 x 10^-4 W/m^2

L_total = 10 log10(I_total/I_0) = 10 log10(1.1 x 10^-4/10^-12) ≈ 87 dB

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The magnitude of the average force exerted on the mud ball during the impact of a 2-kilogram mud ball is dropped from a height of 18 meters is 46N.

First we need to use the equation:

force = mass x acceleration

We know the mass of the mud ball is 2 kilograms, and we can calculate the acceleration by using the equation:

acceleration = change in velocity / time

To find the change in velocity, we need to use the equation for the conservation of energy:

potential energy = kinetic energy

The potential energy of the mud ball at a height of 18 meters can be calculated using the equation:

potential energy = mass x gravity x height

where gravity is approximately 9.8 m/s².

So, the potential energy of the mud ball is:

Potential Energy [tex]= 2 *9.8 *18 = 352.8 joules.[/tex]

When the mud ball hits the ground, all of its potential energy is converted to kinetic energy. The equation for kinetic energy is:

kinetic energy = 0.5*mass*(velocity)²

We can rearrange this equation to solve for velocity:

[tex]velocity = \sqrt{(2*(KE)/ mass)}[/tex]

Using the value we found for the potential energy, we can calculate the velocity of the mud ball just before it hits the ground:

[tex]velocity = \sqrt{(2*352.8 / 2)}= 14.97 m/s[/tex]

Now that we know the velocity of the mud ball just before it hits the ground, we can use the equation for acceleration to find the acceleration during the impact:

[tex]acceleration = change in velocity / time[/tex]

The change in velocity is equal to the velocity just before the impact, since the mud ball comes to a stop during the impact. So:

[tex]acceleration = 14.97 / 0.65 = 23 m/s^2[/tex]

Finally, we can use the equation for force to find the magnitude of the average force exerted on the mud ball during the impact:

[tex]force = mass*acceleration = 2 *23 = 46 N[/tex]

So the magnitude of the average force exerted on the mud ball during the impact is 46 N.

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A child in free fall and an astronaut on the moon is will be weightless.

Weightlessness refers to the absence of weight, which is the gravitational force that an object exerts on another object. It occurs when an object is in a state of free fall.

Astronauts, when they're in space, experience weightlessness because they're in a state of free fall. It's the same experience that people would have if they were in an elevator and the cable snapped.

The moon's gravity is about one-sixth of the Earth's gravity. Therefore, an astronaut on the moon would weigh less than on Earth. Even though the astronaut wouldn't be completely weightless, he would be close enough to weightless that it would be hard to notice any difference in weight.

A child in the air as she jumps on a trampoline will also feel weightless when falling freely.

A scuba diver exploring a deep-sea wreck is not weightless. The force of gravity is still acting on the diver, pulling them downwards towards the seafloor. However, because the water provides an upward force called buoyancy, the diver may feel a sense of weightlessness or reduced weight compared to their weight on land. This is because the buoyant force counteracts some of the force of gravity acting on the diver, making them feel lighter. However, the diver still has mass and is not truly weightless.

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The wavelength at which the brown dwarf will emit the most radiation at a wavelength of 1932 nm (nanometers).

Wien's law formula is:

λmax = b/T

where λmax is the wavelength at which the object emits the most radiation.

b is Wien's constant which is equal to 2.898 × 10^-3 m K and T is the temperature of the object in Kelvin.

To calculate the wavelength at which the brown dwarf will emit the most radiation,

surface temperature of 1500 K=

λmax = b/T

         = 2.898 × 10^-3 m K / 1500 K

         = 1.932 × 10^-6 m

         = 1932 nm

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If you do not wear your required glasses or corrective lenses while driving and are stopped by police, you may face fines or penalties for violating the law.

Depending on the state, you could be fined or your license could be suspended. To avoid these consequences, it is best to always wear your corrective lenses or glasses while driving.

Additionally, driving without your required glasses or corrective lenses may put you and others on the road at risk of accidents, which could result in property damage, injuries, or even fatalities.

Therefore, it is highly recommended that you always wear your required glasses or corrective lenses while driving to ensure the safety of yourself and others on the road.

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A.The incline angle needs to be around 78.52° for the sphere to accelerate linearly at 0.70g.

B. The right answer is c. More than 0.70g of acceleration would be experienced.

(a) To find the incline angle for the uniform solid sphere with linear acceleration 0.70g, we can use the equation for the acceleration of a rolling sphere down an incline:

a = (5/7) * g * sin(theta)

Where a is the linear acceleration, g is the gravitational acceleration (9.81 m/s²), and theta is the incline angle. We are given a = 0.70g, so we can solve for theta:

0.70g = (5/7) * g * sin(theta)

Divide both sides by g:

0.70 = (5/7) * sin(theta)

Now, divide both sides by (5/7):

(0.70 * 7)/5 = sin(theta)

0.98 = sin(theta)

To find the angle, take the inverse sine of 0.98:

theta = sin^(-1)(0.98) ≈ 78.52°

So, the incline angle must be approximately 78.52° for the sphere to have a linear acceleration of 0.70g.

(b) If a frictionless block were to slide down the incline at that angle, its acceleration magnitude would be more than 0.70g. This is because the sphere's acceleration is reduced due to its rotation. A frictionless block doesn't have any rotation, so its acceleration down the incline is given by:

a_block = g * sin(theta)

Since sin(theta) is greater than the (5/7) factor in the sphere's acceleration equation, the acceleration of the frictionless block will be more than 0.70g. Therefore, the correct answer is c. The acceleration magnitude would be more than 0.70g.

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A uniform solid sphere rolls down an incline, the incline angle if the linear acceleration of the center of the sphere is to have magnitude 0.70g can be determined using-

The linear acceleration of the center of a uniform solid sphere rolling down an inclined plane is determined by the inclination angle of the plane.

It is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

For the linear acceleration of the center of the sphere to have a magnitude of 0.70g, we substitute 0.70g for a in the formula.

[tex]θ = sin⁻¹ (0.70) = 44.92°[/tex]

Therefore, the inclination angle must be approximately 44.92 degrees for the linear acceleration of the center of the sphere to have a magnitude of 0.70g.

(b) If a frictionless block were to slide down the incline at that incline angle, would its acceleration magnitude be more less than or equal to 0.70g?

The acceleration of a frictionless block sliding down an inclined plane is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

Since the inclination angle of the plane is the same as in part (a), we can substitute 44.92° for θ in the formula

[tex]a= g sin θ = 9.81 × sin 44.92° = 6.78 m/s²[/tex]

Since the magnitude of the acceleration of the block is less than 0.70g, the acceleration magnitude would be less than 0.70g. Therefore, option (b) is the correct answer.

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The force f (in n) the person is exerting on the mower is 18 n.

The force of friction opposing the motion refers to the force that acts in the opposite direction to the motion of an object and makes it harder to move.

According to the given statement, the force of friction opposing the motion is equal to the force f (in N) the person is exerting on the mower.

This indicates that the person's pushing force must be equal to the force of friction opposing the motion for the mower to move at a constant speed.

Using the above information, we can calculate the force f (in N) that the person is exerting on the mower as 18 n since it is equal to the force of friction opposing the motion.

Therefore, the person must push with a force f (in N) of 18 n to overcome the friction and maintain a constant speed for the mower.

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In statistical mechanics, the partition function (denoted as Q) is a mathematical function that describes the distribution of energy among the possible microstates of a system in thermodynamic equilibrium. The partition function depends on the energy levels and degeneracies of the system, as well as on the temperature and other external parameters.

The Boltzmann factor (denoted as e^(-E/kT)) is a term that appears in the partition function and represents the probability of a system occupying a particular energy level. Here, E is the energy of the level, k is the Boltzmann constant, and T is the temperature of the system in Kelvin. The Boltzmann factor is derived from the Boltzmann distribution, which is a probability distribution that describes the occupation of energy levels in a system.

The Boltzmann factor can be used to estimate the probability of a system occupying a particular energy state by comparing the Boltzmann factors for different states. The ratio of the Boltzmann factors for two energy states gives the relative probability of the system occupying each state. For example, if the ratio of the Boltzmann factors for two energy levels is 10:1, then the system is 10 times more likely to occupy the lower energy level than the higher energy level at that temperature.

Overall, the partition function and the Boltzmann factor are fundamental concepts in statistical mechanics that allow us to describe the distribution of energy among the microstates of a system in thermal equilibrium and estimate the probability of the system occupying specific energy states.

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yes it is any plant is apart of reproduction

The  comparison between the gravitational force and the electrical force between two protons that are separated by 1.2 x 10-15 m is 4.47 * 10⁻⁴⁰

Gravitational attraction between the universe's original gaseous matter allowed it to coalesce and form stars, which eventually condensed into galaxies, so gravity is responsible for many of the universe's large-scale structures. Gravity has an infinite range, but its effects weaken as objects move further away. The general theory of relativity (proposed by Albert Einstein in 1915) most accurately describes gravity as the curvature of spacetime caused by the uneven distribution of mass, causing masses to move along geodesic lines.

using the formula

F = G [tex]\frac{M1 * M2}{R * R}[/tex]

FORCE COMES OUT TO BE ;

4.47 * 10⁻⁴⁰

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The maximum force that can be applied to the object before it starts moving is 49 N

To calculate the maximum force that can be applied to the object before it starts moving, we need to use the formula:

Fmax = μsN

where μs is the coefficient of static friction, N is the normal force exerted on the object, and F(max) is the maximum force that can be applied to the object before it starts moving.

Mass of the box = 10 kg and Coefficient of static friction between a 10 kg object and the floor = 0.50.

Normal force exerted on the box, N = mg (where g is the acceleration due to gravity = 9.8 m/s²)

So, N = 10 kg × 9.8 m/s² = 98N.

We can now use the above formula to calculate the maximum force that can be applied to the object before it starts moving:

Fmax = μsN = 0.50 × 98 N = 49 N.

Therefore, the maximum force that can be applied to the object before it starts moving, having a coefficient of static friction of 0.50 is 49 N.

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Yes, running electrical accessories while needing lots of cranking to start the engine will run down the car battery. The electrical accessories include headlights, radio, air conditioning, seat warmers, GPS system, power windows, and more.

Automobiles use rechargeable batteries known as lead-acid batteries. The battery serves two purposes in an automobile. The first function is to start the engine. The second function is to provide electrical energy to the automobile's electrical system when the alternator is not operational. If the battery is not working correctly, the automobile will not start, and the electrical accessories will not work.

The battery will run down when electrical accessories are running because the battery's stored electrical energy is being consumed by electrical accessories. When the engine is running, the alternator charges the battery, and the electrical accessories receive their energy from the alternator. If the battery has insufficient stored electrical energy or is not receiving a charge from the alternator, the electrical accessories will stop functioning.

Electrical accessories running while needing lots of cranking to get the engine started will drain the battery faster than using electrical accessories while the engine is running. This is because the battery must provide energy to start the engine while simultaneously powering the electrical accessories. If the battery is not charged enough, the engine will not start, and the battery will be drained even more. Therefore, it is advisable to turn off all electrical accessories when trying to start the engine.

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The velocity of the river is 8 m/s. The standard unit for velocity is meters per second (m/s).

What is Velocity?

Velocity is a physical quantity that refers to the rate at which an object changes its position with respect to a reference point.  In other words, velocity describes both how fast an object is moving and in what direction it is moving.

This problem can be solved using vector addition.

Let the velocity of the swimmer be v_s = 4 m/s at an angle of 30 degrees to the normal to the riverbank.

Let the velocity of the river be v_r = ? m/s in an unknown direction.

The velocity of the swimmer relative to the river can be found using vector addition:

v_s/r = sqrt(v_s^2 + v_r^2 - 2v_sv_r*cos(theta))

where theta is the angle between the velocity of the swimmer and the velocity of the river.

Since the swimmer is crossing the river directly perpendicular to the river, theta = 90 degrees.

v_s/r = sqrt(v_s^2 + v_r^2 - 2v_sv_r*cos(90))

v_s/r = sqrt(v_s^2 + v_r^2)

Substituting in the values:

4/v_r = sqrt(4^2 + v_r^2)

16/v_r^2 = 16 + v_r^2

v_r^2 + 16v_r - 256 = 0

Using the quadratic formula:

v_r = (-16 ± sqrt(16^2 + 41256)) / 2*1

v_r = (-16 ± sqrt(1024)) / 2

v_r = (-16 ± 32) / 2

The negative solution is not physically meaningful, so we take the positive solution:

v_r = 8 m/s

Therefore, the velocity of the river is 8 m/s.

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The sound waves are heard at a higher frequency as the car approaches the students.

The words that complete the blanks are;

Refraction

Diffraction

Electromagnetic spectrum

Intensity

Transverse waves

Frequency

Vibration

What is a wave?

A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

The frequency of a wave is defined as the number of full waves that are generated in a second or the number of vibrations or oscillations that a sound wave experiences as it travels through a medium. Hertz is the SI unit of frequency (Hz).

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If an interstellar cloud lies between Earth and a hot star, we can detect its presence in the stellar spectrum of the star. From the stellar spectrum, the elemental abundance property of the interstellar cloud can be determined.Correct answer is option 4)elemental abundance

An interstellar cloud is a cloud of gas and dust situated in a galaxy or between galaxies that constitutes the raw material for stars and planets. Molecular hydrogen (H2) accounts for the majority of the cloud, with trace amounts of other molecules, such as helium, and ionized gas.The elemental abundance property of the interstellar cloud can be determined from the stellar spectrum. A spectral line refers to the electromagnetic radiation emitted or absorbed when electrons in atoms or molecules transition between energy levels. By analyzing a stellar spectrum, it's possible to see which elements and their isotopes are present in the star's atmosphere by looking for these spectral lines. As a result, by examining a star's spectrum, one can determine the elemental abundance of the interstellar cloud between the Earth and the star.In conclusion, from the stellar spectrum, the elemental abundance property of the interstellar cloud can be determined.Correct answer is option 4)elemental abundance

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The furnace you are referring to is commonly known as a blast furnace that is vertically cylindrical and equipped with a tapping spout near its base.

Blast furnaces are a type of industrial furnace that is used for smelting iron ore into pig iron. They are typically tall, cylindrical structures made of steel, lined with fireproof bricks, and equipped with several openings for charging raw materials, injecting hot air and fuel and tapping molten iron.

The process involves heating the iron ore with coke and limestone in a controlled environment to produce carbon monoxide, which reduces the iron oxide to iron.

The molten iron is then extracted from the furnace through a tapping spout located near its base, while the molten scrape metal, a byproduct of the process, is tapped off separately. Blast furnaces are still used today in the iron and steel industry, although newer technologies are gradually replacing them.

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Just the pull from the rope's tension acts horizontally on mass 1, functioning as the only force. In this case, T=m1*F/(m1+m2) represents the tension (again, the acceleration is the same because of the rope and the lack of friction, I think).

The blocks with masses of 1 kg and 2 kg lie on a rough horizontal surface and are joined by a spring. It is not strained to any degree. K=2 N/m represents the spring constant. Blocks and a horizontal surface interact with each other with a 0.5 coefficient of friction.

The masses shift in such a way that the string's length between P1 and P2 is parallel to the inclined plane.

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The total lifetime of the Sun is estimated to be about 10 billion years.

It is currently about 4.6 billion years old, so it has roughly 5 billion years left until it exhausts the hydrogen fuel in its core and starts to evolve into a red giant. During the red giant phase, the Sun will expand to a size that may reach beyond the current orbit of Earth and will become much brighter. This phase is expected to last for about 1 billion years.

Eventually, the Sun will shed its outer layers and become a compact, hot object known as a white dwarf. This final phase is expected to last for trillions of years. So in total, the Sun's lifetime is estimated to be about 10 billion years until it exhausts its fuel and starts to evolve, and then trillions of years as a white dwarf.

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G2-type stars take the longest time, while O9-type stars take a shorter time to go from a protostar to a main-sequence star during the formation process.

Based on the spectral types provided, the order of the stars from the longest to the shortest time taken to go from a protostar to a main-sequence star during the formation process is as follows:
1. G2
2. O9
- Stars with lower masses, like G2-type stars, take longer to form because they have a lower rate of fusion and lower pressure at their cores.
- On the other hand, O9-type stars have a higher mass, which results in a higher rate of fusion and higher pressure at their cores.

This means they will form faster than G2-type stars.

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An emf source with a resistor and a capacitor are connected in series. as the capacitor charges, when the current in the resistor is 0.900 a. The magnitude of the charge on each plate of the capacitor will be: 0.900 A * t.

When an emf source with a resistor and a capacitor are connected in series, the current in the resistor will start decreasing as the capacitor charges up. When the current in the resistor is 0.900 A, the magnitude of the charge on each plate of the capacitor can be determined by the equation:

Q = I * t
where Q is the magnitude of the charge, I is current, and t is the time.

In this case, since the current is 0.900 A, the magnitude of the charge on each plate of the capacitor can be calculated by multiplying the current (0.900 A) by the time (t). The magnitude of the charge on each plate of the capacitor will therefore be 0.900 A * t.

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The average mass of the skiers is 66.0 kg. The power output of the motor is 4.70 kw. The maximum speed at which the skiers can be towed is 4.21 m/s.

Since there are 10 skiers, the total mass is:

M = 10m = 10(66.0 kg) = 660.0 kg

The force exerted by the tow rope is:

F = Mg sin([tex]\theta[/tex])

F = (660.0 kg)(9.81 m/s^2) sin(8.5 degrees)

F = 1117.9 N

Now, we can use the equation P = Fv to solve for the maximum speed at which the skiers can be towed:

v = P/F

v = (4.70 kW)/(1117.9 N)

v = 4.21 m/s

Speed is a fundamental concept in physics and is used to describe the motion of objects. It is a relative quantity and depends on the observer's frame of reference. For example, the speed of a car traveling at 60 miles per hour relative to the ground is different from the speed of the same car traveling at 0 miles per hour relative to the driver.

Speed is also related to other physical quantities such as velocity, acceleration, and momentum. Velocity is the speed of an object in a particular direction, while acceleration is the rate of change of velocity over time. Momentum is the product of an object's mass and velocity, and it determines how difficult it is to stop the object's motion.

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The two limiting cruising altitudes usable on V343 for a VFR-on-top flight from DBS VORTAC to Raney Intersection are 6,000 feet and 14,000 feet.

VFR-on-top is a type of flight that must remain in visual meteorological conditions (VMC) and must not exceed the airspace altitude limitations. The airspace altitude limitations along V343 from DBS VORTAC to Raney Intersection are 6,000 feet and 14,000 feet.

To find out the limiting cruising altitudes:
1. Consult the airspace altitude limitations along the route of flight.
2. Note the airspace altitude limitations along V343 from DBS VORTAC to Raney Intersection.

Therefore, the two limiting cruising altitudes usable on V343 for a VFR-on-top flight from DBS VORTAC to Raney Intersection are 6,000 feet and 14,000 feet.

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The magnification of a telescope can be calculated using the following formula: magnification = (objective lens diameter / eyepiece focal length). In this case, the magnification is (300mm / 10mm) = 30x.

The magnification of a telescope is determined by the ratio of the focal length of the objective lens to the focal length of the eyepiece. In this case, the objective lens has a diameter of 300 mm and a focal length of 300 mm, and the eyepiece has a focal length of 10 mm. Therefore, the magnification of the telescope is 30x. To calculate this, we can use the following formula:

Therefore, in this case, the magnification of the telescope is: Magnification = 300 mm / 10 mm = 30x

In conclusion, the magnification of the telescope is 30x.

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Mass of weight is 10 N.

The scale reads the tension on both sides which is 9.8N each.

Let's first draw a free body diagram for both the blocks.

Free Body Diagram for both blocks and PulleyMass 1:

Taking the direction of motion to be upwards for Mass 1,

we can see that the net force in the upward direction is

Tension(T) - mg = 0

where m = mass of the block which is 1 kg.

Hence, T = mg = 1 x 9.8 = 9.8 N

Therefore, the tension in the string attaching Mass 1 to the scale is 9.8 N.

Mass 2: Taking the direction of motion to be upwards for Mass 2,

we can see that the net force in the upward direction is T - mg = 0

where m=mass of the block which is 1 kg.

Hence, T = mg = 1 x 9.8 = 9.8 N

Therefore, the tension in the string attaching Mass 2 to the scale is 9.8 N.

Scale: The net force acting on the scale is 0 as the weights are hanging still,

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The charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C

The electric field 0.300 m from a very long uniform line of charge is 850 n/c. How much charge is contained in a section of the line of length 1.70 cm? The answer is 1.277 × 10⁻⁷ C. Explanation: To begin, let's consider the electric field due to an infinite line of charge. The electric field generated by a uniformly charged infinite line of charge is given by:$$E = \frac{λ}{2πεr}$$where, E is the electric field, λ is the linear charge density (charge per unit length), r is the distance from the wire, and ε is the permittivity of free space. To begin with, we can rearrange the equation for electric field:$$λ=\frac{2πεrE}{l}$$Where, l is the length of the line section of interest, E is the electric field at the distance r from the line of charge, and λ is the linear charge density. Now we can plug in the given values:$$(1.70 cm)λ = Q$$$$λ=\frac{2πεrE}{l}$$λ = (2π * 8.85 × 10⁻¹² F/m) * (0.300 m) * (850 N/C) / (0.0170 m)λ = 2.16 × 10⁻⁵ C/mSo, the charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C$$Therefore, 1.277 × 10⁻⁷ C.

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An alternative piece of evidence that supports the idea that solar energy could play a part in solving the energy crisis is the fact that it is a clean and renewable source of energy. This means that it does not contribute to pollution and it will not run out anytime soon.

The solar energy is renewable energy because:

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The given statement "turns people upside down" and "people should not drop down" are both due to the centrifugal force.

Centrifugal force is defined as the apparent force that tends to move a rotating body away from the center of rotation. When an object moves in a circular path, a force must act towards the center of the circle to keep it moving in a circle. This force is known as the centripetal force.

The opposite force that acts to push the object away from the center of the circle is called centrifugal force. So, the given statement "turns people upside down" and "people should not drop down" are both due to the centrifugal force.


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In a binary system with a 3 solar mass star and a 10 solar mass star, the 10 solar mass star would evolve off the main sequence first. This is because more massive stars have shorter lifetimes due to their higher rate of nuclear fusion.

As per the masses of the 3 solar mass star and the 10 solar mass star, the 3 solar mass star would evolve off the main sequence first if they formed together in a binary system. The main sequence is a continuous and distinctive band that appears on plots of stellar color versus brightness. Most stars are found in this band, including the Sun.

The main sequence is the band that represents the stars in the core hydrogen-burning phase. In contrast to the core helium-burning red clump giants and the helium-fusing horizontal branch stars, stars on the main sequence are in a stable state of nuclear fusion.

Because of the higher temperatures inside, more massive stars have a greater rate of nuclear reactions and consume their fuel more quickly. As a result, if a 3 solar mass star and a 10 solar mass star formed together in a binary system, the 3 solar mass star would evolve off the main sequence first.

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Answer:

(option a)

Explanation:

The star that is white in color is Canopus. Betelgeuse is a red supergiant, Deneb is a blue-white supergiant, and Aldebaran is an orange giant.

Answer:

A. Canopus

Explanation:

Canopus is a first-magnitude star in the constellation Carina: the second brightest star in the heavens.

From Earth Sirius appears to be about twice as bright as Canopus. However, Sirius is only 8.6 lightyears from us, but Canopus is 310 lightyears away. Since light dims by the square of the distance we can say that if they were of equal apparent brightness Canopus would be (310/8.6)^2 or 1,300 time brighter.

In actuality, Sirius is 25.4 times as luminous as the sun, while Canopus is 10,700 times more luminous. So Canopus is 421 times brighter than Sirius. If you are asking why the brighter one looks dimmer, I have answered that.

If you are asking why Canopus is actually so much brighter than Sirius, I will try to answer that now. Stars are powered by atomic reactions that go on in or near the core. These reactions are caused by extreme heat and pressure. These are caused by the weight of the star crushing down from above. The larger the star the greater the heat and pressure, the faster the star burns its fuel, and the brighter it is. Sirius is just a bit over twice the mass of the sun (2.063), but Canopus is between 8 and 10 times as hefty as the sun.

Stars use the heat and pressure in the core to turn hydrogen into helium, which results in light. When it runs out of hydrogen the star starts to collapse. That generates more pressure and heat and allows the star to turn helium into carbon. This makes the star swell up and its surface temperature cools. The larger the star is cooler, but it has many times the surface area to generate light. Canopus is now burning helium and has swollen, but its surface temperature is still 3/4 that of Sirius. Sirius is only 1.7 times the width of the sun, but Canopus is 71 times bigger or 1,750 times the surface area.

If you did not catch all of that, I’ll sum it up. Canopus is more massive, and has a MUCH bigger size than Sirius. This allows it to produce a lot of light on its MUCH larger surface area and to radiate it out into space.