Answer: see below:
The universe experiences the opposite energy change as the surroundings to keep the total energy of the system constant. The energy of the system, surroundings, and universe must be equivalent. The energy of the universe must remain 0, so the energy of the system and surroundings cannot change. I reaaallly hope this helped, luv ya, have a nice day!! <333
How would you determine the sign of a charge on a body using an electroscope? PLEASE HELP!!!
Answer:
Now the electroscope will allow you to identify whether an object is positively or negatively charged. If you bring a negative object near the electroscope, the electrons in the scope will be repelled toward the leaves, balancing the charge.
Explanation:
The electrostatic force obeys the principle of linear super-position which basically states
that force between two particles does not get affected by the charge of the other and hence if the
rod is brought close to a suspended metal needle and is getting attracted then needle definitely
should possess opposite charge relative to the rod or basically negative charge as opposite charges
attract.
(b) In case the needle which is brought near the sus[ended needle and gets repelled that shows that
both of them possess same charge and hence positive charge on both objects and will start
repelling each other.
Which of the following elements has properties different than the rest?
H
K
N
O
Answer:
I think K . If it not, then sorry.Hope I helped you.
Answer: The answer [b] or also known as k
Explanation:
PLEASE HELP
You are given a liquid mixture to identify as a colloid, suspension, or solution. When you shine light from a laser pointer you can see the beam spread out in the mixutre. Only some light passes through. What is the next test you should perform to determine the type of mixture?
Heat the mixture to evaporate the water.
Shine the light through again several times.
Wait to see if the particles settle out of the mixture.
Shake the mixture.
Waiting to see if the particles settle out of the mixture will be the next test to perform to determine the type of mixture.
What is a Mixture?This comprises of two or more substances which aren't chemically bonded together.
Suspension is a heterogeneous mixture that settle out of solution while colloid is a heterogeneous mixture that do not settle out of solution which is why option C was chosen.
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thanks for the points :D
Physics help please !!!
Answer:
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what is the function of thrombocytes
Answer:
the function of the thrombocytes is to clott blood
Yellow light passes through a diffraction grating. it's first order maximum occurs at an angle of 21.2. What is the slit separation d?
Answer:
19.284
or
9.33
Explanation:
Answer:
1.66
Explanation:
Found answer on chegg. Works for acellus
What is the density of a block of marble that
occupies 287 cm3
and has a mass of 816 g?
Answer in units of g/cm3
.
Explanation:
Solution,
Volume (v)=287 cm^3
Mass(m)=816 g
Density(d)=m/v
=816/287
=2.84
So, the density of the block of marbles is 2.84 g/cm^3.
I hope it helped U
stay safe stay happy
A car speeds up from 0.0 m/s to 14.0 m/s
in 3.25 s.
The acceleration of the car is:
A. 14.0 m/s2
B. 4.31 m/s2
C. 45.5 m/s2
D. 10.8 m/s2
Explanation:
Its speed is zero at the beginning of the 3.25 s and 14 m/s at the end.
I'm thinking you probably wanted to find the car's acceleration.
Acceleration =(change in speed) / (time for the change).
Acceleration =(14m/s )/ (3.25s) .
Acceleration = 4.31m/s² .
I hope it will help you so.
Have a great day.
Be safe and be happy.
which form of the energy is used to generate electrical energy in a tidal power station
Tidal energy is the form of energy used to generate electrical energy.
The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.
What is kinetic energy?Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.
After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.
Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.
Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.
Thus, kinetic energy is used to generate electrical energy in a tidal power station.
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Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).
Answer:
1.33 mA
Explanation:
V=IR
I=10/(7.5×10³)
=1.33×10-³A
=1.33mA
what happens to the value of g when we move from equator to the pole.the weight of an object is greater at poles than at equator .
why?
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Answer:
[tex]thank \: you[/tex]
Revolution: One orit of an object in space around another_ days?
Answer:
365 days..
Explanation:
Hope it may help you シ︎♡︎
[tex] \huge\mathfrak\green{365 \: or \: 366 \: Days.}
[/tex]
[tex]Hope \: it \: helps[/tex]
A mineral oil has a density of 0.875 g/cm3. Suppose you spread 0.60 g of this oil over the surface of water in a large dish with an inner diameter of 21.6 cm. How thick is the oil layer
With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that
0.875 g/cm³ = (0.60 g)/V ==> V ≈ 0.686 cm³
If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that
V = π ((21.6 cm)/2)² d ==> d ≈ 0.0202 cm
astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horizantal range ?
Answer:
Range is 62.5 metres
Explanation:
Time of flight
[tex]t = \frac{2u \sin( \theta) }{g} [/tex]
for range, acceleration is zero
from second newton's equation:
[tex]S = ut + \frac{1}{2} {at}^{2} [/tex]
but a = 0:
let range be x:
[tex]x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres[/tex]
[ taken g to be 10 m/s² ]
A uniform rod of length 0.7 m and mass 10 kg rotates freely about a horizontal axis passing through one end of the rod a bullet of mass 20 g traveling horizontally with velocity v=200 m/s penetrates the end of the rod. and hooked on the rod find the angular velocity of the rod when the bullet hits the bar
Answer:
ω = 1.7 rad/s
Explanation:
Conservation of angular momentum
Assuming the rod is initially hanging vertically at rest.
Initial angular momentum is carried by the bullet only
L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s
the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²
2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω
2.8 = (1.64313333...)ω
ω = 1.70406134...
Question 15 OT 25
Which process is an example of an exothermic reaction?
A. The reactions taking place in a cold pack
B. A plant using photosynthesis to create sugars
C. Natural gas burning on a stove
o
D. The reactions taking place inside a baking cake
Answer:
A. The reactions taking place in a cold pack
Explanation:
This is because in a cold pack, there is no heat gained therefore a reaction stands by losing it's own heat to the surrounding.
[tex].[/tex]
An oil tanker has a mass of to, 40000 tonnes. It is 500m long and 40m wide. What is the mininum depth of harbor it requires?
The minimum depth of harbor of the oil tank is 2.22 m
The given parameters:
mass of the oil tanker, m = 40,000 tonnes
length of the tanker, l = 500 m
width of the tanker, w = 40 m
To find:
minimum depth of harbor
Note: The specific gravity of oil is approximately 0.9
The density of water ([tex]\rho_w[/tex]) = 1000 kg/m³
Covert the given mass to kilogram
1 tonne = 1000 kg
40,000 tonnes = 40,000,000 kg
The density of the oil tanker is calculated as:
[tex]S.G = \frac{\rho_o}{\rho_w} \\\\\rho_o = S.G \times \rho_w\\\\\rho_o = 0.9 \times 1000\\\\\rho_o = 900 \ kg/m^3[/tex]
The volume of the oil tanker is calculated as:
[tex]Volume = \frac{mass}{density} \\\\Volume = \frac{40,000,000}{900} \\\\Volume = 44,444.44 \ m^3[/tex]
The minimum depth of harbor is calculated as:
[tex]height = \frac{volume}{Length \times width} \\\\height = \frac{44,444.44}{500\times 40} \\\\height = 2.22 \ m[/tex]
The minimum depth of harbor of the oil tank is 2.22 m
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What is the relationship between resistivity of a wire and length of a wire is?
[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]
Or
[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]
Rho stands for resistivity of wireR stands for resistance of wire l stands for length of areaA stands for surface area of wireName another way that energy is made
Answer:
The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. Most electricity is generated with steam turbines using fossil fuels, nuclear, biomass, geothermal, and solar thermal energy.
Explanation:
Solar
Wind
Geothermal
Hydrogen
TidaWave
Hydroelectric
Biomass
Late one night on a highway, a car speeds by you and fades into the distance. Under these conditions the pupils of your eyes have diameters of about 7.0 m m. The taillights of this car are separated by a distance of 1.4 m and emit red light (wavelength = 660 nm in vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction?
Which Scientist discovered
atomic Theory?
Answer:
John dalton discovered
Differences between law of flotation and Archimedes's principle
Answer:
Differences between law of flotation and Archimedes's principle
here
Explanation:
An arrow is moving at 35 m/s and travels for 5 seconds. How far did the arrow travel?
What are you solving for? Show work! Help please!
Answer:
175m
Explanation:
So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…
[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds
Answer:
175 is the right answer 35×5=175
Explanation:
175
what do you mean by MA of a lever is 3 , VR of a lever is 4 and efficiency of a machine is 60%
An engineering company needs to solve a design problem.
It is designing a high-speed train to transport passengers
between Boston and Atlanta.
Which statement is a criterion for this project?
O A. The train must not take more than six years to build.
B. The train must not have wheels with bearings that need
lubrication,
O C. The train must cost less than $150 million to design.
D. The train must be able to maintain a speed of 250 km/h.
The engineering company must consider the speed of the train in the design.
The correct answer is option D.
To design a high speed train to transport passengers between Boston and Atlanta, the engineering company must include the following design criterion in the project:
the speed of the train: this must be high in order to satisfy the high-speed criterion in the statement of the problem.Thus, the only statement in all the given options that considered speed of the train is option D.
"D. The train must be able to maintain a speed of 250 km/h."
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Answer:
The train must provide a smooth ride for passengers between bosten and atlanta
Explanation:
how many grams of CaCo3, will react with dil HCL to produce 75gm of Co2 ?
Answer:
100g is correct answer.
Answer:
100 grams
Explanation:
CaCO3 ➡️ CaO + CO2
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what happens when you mix water and baking soda
An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15m if her initial speed is 3m/s.What is the acceleration due to gravity on the planet?
Explanation:
As the astronaut jumps and reaches the highest point, he is momentarily at rest, i.e.
[tex]v=0[/tex]
We also know
[tex]u=3, s=15[/tex]
By the formula,
[tex]v^2-u^2=2as[/tex]
where a is the acceleration of objectc due to gravity,
[tex]0^2-3^2=2a(15)[/tex]
[tex]-9=30a[/tex]
[tex]a=-0.3 ms^{-2}[/tex]
where negative sign indicates a downwards acceleration.
2. Samuel leaves the end of a 4.0-m-high diving board and strikes the
water 1.3 s later, 3.0 m beyond the end of the board. Considering the
diver as a particle, determine:
(a) His initial velocity,
(b) The maximum height reached;
(c) The velocity Vf
with which he enters the water.
Answer:
a) v = 4.9 m/s at 62° above the horizontal
b) h = 0.94 m above the board or 4.94 m above the water
c) v = 10 m/s at 77° below the horizontal
Explanation:
Assume UP and FOREWARD are positive and the diving board is the origin.
Ignore air resistance.
s = s₀ + v₀t + ½at²
In the vertical
-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)
vy₀ = 4.281 m/s
in the horizontal
3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)
vx₀ = 2.307... m/s
v = √(4.281² + 2.307²) = 4.863...
tanθ = 4.281 / 2.307
θ = 61.680...
v² = u² + 2as
s = (v² - u²) / 2a
h = (0² - 4.281²) / 2(-9.8) = 0.9350...
v² = 4.863² + 2(9.8)(4)
v = 10.1019...
cosθ = 2.307/10.1019
θ = 76.798
(a) The initial velocity of Samuel is 4.02 m/s
(b) The maximum height reached by Samuel is 0.55 m
(c) The final velocity when he enters the water is 5.20 m/s
The given parameter:
the height of the board, h = 4 mtime to strike the water, t = 1.3 sthe horizontal distance traveled, x = 3.0 m(a) The initial velocity of Samuel is calculated as;
[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]
Assume downward motion to be in negative direction
The vertical component of the velocity is calculated as;
[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]
The horizontal component of the velocity is calculated as;
Assume forward motion to be in positive direction
[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]
The resultant of initial velocity is calculated as;
[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]
(b) The maximum height reached by Samuel is calculated as;
[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]
(c) The final velocity when he enters the water;
The height traveled before he hits the water, h = 0.55 m
[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]
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