Answer:
The correct option is;
Terminate
Explanation:
Termination of the risk is equivalent to elimination of the risk by avoiding the activity that brings about the risk or by using a different process that does not include the risk observed in the previous process option
When the reward far outweigh the risk, it may be decided to terminate or eliminate the risk and miss the reward and also terminate the likelihood of the losses to be incurred.
What can be used as a tracing powder when checking for small oil leaks
Answer:
Talcum powder!
Explanation:
How to find the source of an oil leak:
This method simply involves using Talcum Powder as a visual aid to help pinpoint the location of an oil leak,
so you use Talcum powder for small oil leak :]
Have a wonderful day!
Which sentence is correct about the exergy of an empty (pressure around zero Pascal) tank with a volume of V, located in an environment with a pressure and temperature of P0 and T0?
a. The exergy of the tank is positive and equal to PoV.
b. Since the system receives work from the environment the exergy of the tank is negative and equal to -PoV
c. The exergy of the tank can be anything between zero to PoV.
d. Since the pressure of the tank is almost zero the tank has no exergy.
Answer:
The correct option is;
c. the exergy of the tank can be anything between zero to P₀·V
Explanation:
The given parameters are;
The volume of the tank = V
The pressure in the tank = 0 Pascal
The pressure of the surrounding = P₀
The temperature of the surrounding = T₀
Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change
The exergy balance equation is given as follows;
[tex]X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}[/tex]
Where;
X₂ - X₁ is the difference between the two exergies
Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system
Therefore, the exergy of the tank can be anything between zero to P₀·V.
A reversible steady-state device receives a flow of 1 kg/s air at 400 K, 450 kPa and the air leaves at 600 K, 100 kPa. Heat transfer of 900 kW is added from a 1000 K reservoir, 50 kW is rejected at 350 K, and some heat transfer takes place at 500 K. Find the heat transferred at 500 K and the rate of work produced.
Answer:
41 kW
690.2 kW
Explanation:
Given the following data
T1 = 400 K
P1 = 350 kPa
T2 = 600 K
P2 = 100 kPq
m = 1 kg/s
Q1 = 900 kW
Q2 = 50 kW
T(amb1) = 1000 K
T(amb2) = 350 K
T(amb3) = 500 K
We also will be using tables to solve the question.
R = 0.287 kJ/kgk
C(p) = 1.004 kJ/kgk
To find Q3, we'd use the formula
Q3 = m.T(amb3).[C(p).In(T2/T1) - R.In(P2/P1)] - [T(amb3)/T(amb1) * Q1] + [T(amb3)/T(amb2) * Q2]
Q3 = 1 * 500 * [1.004 * In(600/400) - 0.287 * In(100/450)] - 500/1000 * 900 + 500/350 * 50
After simplification, we find that
Q3 = 41 kW
Next, we use the equation
Q3 - Q2 + Q1 = W + m.C(p).(T2 - T1)
41 - 50 + 900 = W + 1 * 1.004 * (600 - 400)
891 = W + 1.004 * 200
891 = W + 200.8
W = 891 - 200.8
W = 690.2 kW
If we make W the subject of the formula, we have
Estimate the heating energy requirements for a residential building using the degree-day method (a) in Denver, Colorado, and (b) in Little Rock, Arkansas. The overall heat loss coefficient is 400 Btu/h.oF and the furnace efficiency is 0.78.
Answer:
a) 600°F days
b) 103°F days
Explanation:
Given data :
overall heat loss coefficient = 400 Btu/h.oF
Furnace efficiency = 0.78
applying the degree- day method the heating energy requirement per day can be obtained by subtracting the average temperature for a particular day from the acceptable mid/balance point temperature
lets assume the mid/balance point temperature = 65°F
a) heating energy requirement in Denver Colorado
we will have 600°F days ; considering the the average temperature - balance point temperature
= 665 - 65 = 600°F
b) heating energy requirement in Little Rock Arkansas
we will have 103° days
Question #6 Fill in the Blank Complete the following sentence. The term describes initiatives and products that preserve the environment
Answer:
The term "green" describes initiatives and products that preserve the environment
Explanation:
In order to preserve the environment the Environmental Protection Agency has provides tips for "Being Green on the Road", which highlights the topics including, Green Vehicle Guides, guides for Fuel Economy, guides for Clean Diesel and many more ways our environmental footprint can be reduced
A green economy is an economy that focuses on the reduction of risk of economic activity on the environment, such as the reduction of carbon emission and reduction in environmental pollution, biodiversity loss prevention, and promotes a sustainable development
A green tech aims to protect the environment and to reverse previous damage done to the environment, including technology for clean energy, water purification, and waste recycling.
Answer:
The correct answer is stressor. The durability of building products and structures is affected by stressors such as rain, heat, snow, and hurricanes. Construction standards consider these potential stressors.
Tech A says that you can test for defective ignition wires by using a spray bottle and water. Tech B says that you can test for defective ignition wires with a grounded test lead. Who is correct?
A) Tech A
B) Tech B
C) Both Techs A and B
D) Neither Tech A nor B
Answer: C) Both Techs A and B
Explanation:
Technician A and Technician B are both very right. Using a spray bottle and water, the ignition wire test can be carried out using any of the methods described above. Or, by using a grounded test lead that is connected to a multimeter, you can also conduct the test for faulty ignition wires.
Answer: Either A or B
Explanation:
Which size lug nut would fit a metric wheel stud?
A)7/16-20 LH
B)½ X20
C)M12X 1.5
D)7/16-20RH
A motorist is driving his car at 60km/hr when he observes that a traffic light 250m ahead turns red. The traffic light is
timed to remain red for 20 seconds before it turns green. The motorist wishes to pass the traffic lights without stopping to wait for it to turn green. make calculations for
(a) the required uniform acceleration of the car
(b) the speed of the car as it passes the traffic light in km/hr
Explanation:
Okay soo-
Given-
u = 60 km/hr = 60×1000/3600=50/3 m/s
t = 20 s
s = 250 m
a = ?
v = ?
Solution -
Here, acceleration is uniform.
(a) According to 2nd kinematics equation,
s = ut + ½at^2
250 = 50/3 ×20 + 0.5×a×20×20
250-1000/3=200a
(750-1000)/3=200a
a = -250/(3×200)
a = -5/12
a = 0.4167 m/s^2
The required uniform acceleration of the car is 0.4167 m/s^2.
(b) According to 1st kinematics equation
v = u + at
v = 50/3 + (-5/12)×20
v = 50/3-25/3
v = 25/3
v = 8.33 m/s
The speed of the car as it passes the traffic light is 8.33 m/s.
Good luck!
A light aircraft with a wing area of 200 ft^2 and a weight of 2000 lb has a lift coefficient of 0.39 and a drag coefficient of 0.06. Determine the power required to maintain level flight.
Answer: power required to maintain level flight=82.20hp
Explanation:
Given
Area = 200 ft^2
Weight = 2000 lb
Cl( Lift coefficient)= 0.39
Cd( Drag coefficient) = 0.06
The density ρ of air at standard atmospheric pressure = 2.38 X 10^-3 slugs/ft^3
For Equilibrium to be maintained during flight conditions, the lift force must be balanced by the weight of the aircraft such that
Lift force = Weight of aircraft
(1/2)ρAU²Cl= W
1/2X 2.38 X 10^-3 X 200 X U² X 0.39 = 2000
U²= 2000 X 2 / 2.38 X 10^-3 X 200 X 0.39
U=[tex]\sqrt{21,547.08}[/tex]
Velocity, U= 146.7892ft/s
Drag force of the velocity can be deduced from the formulae
Cd= Drag force(D) /1/2 ρU²A
Drag force=1/2 ρU²ACd
D=1/2 x (2.38 X 10^-3 slugs/ft^3) x (146.7892ft/s)² x 200 ft^2 x 0.06
D=307.69
Drag force= 308lb
power required to maintain level flight is given as
P = Drag force x Velocity = D x U
=308lb X 146.7892ft/s
=45,211.0736lb.ft/s
Changing to hp we have that
1 Horsepower, hp = 550 ft lbf/s
??=45,211.0736lb.ft/s
45,211.0736lb.ft/s/ 550 ft lbf/s= 82.20hp
Schrodinger equation is a ........... Equation
Answer:
linear partial differential
Explanation:
The Schrödinger equation is a linear partial differential equation that describes the wave function or state function of a quantum-mechanical system. It is a key result in quantum mechanics, and its discovery was a significant landmark in the development of the subject.
Merchants get commission from selling products that are consigned to them true or false
Answer:
true
Explanation:
How would you handle a situation where another team member was critical of your work?
is used to change physical objects and 3-D ideas into 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.
Answer:
2D CAD Software Application
Explanation:
Two Dimensional Computer-Aided Design Software Application is otherwise known as 2D CAD software application such as AutoCAD or MicroStation is used to change physical objects and 3-D ideas into a 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.
The utilization of a 2D CAD software application saves time and revision to construction drawings can quickly be made without having to redesign the whole drawings from the scratch.
Which of the following would be seen as an improvement on the quality of capital or a positive investment? A. Educational test scores are up. B. An assembly line has been closed down. C. Research and development has improved. D. Irrigation systems have been installed.
Answer:
The correct option is;
D. Irrigation systems have been installed
Explanation:
The quality of capital measures the amount of capital available within an economy and the benefit derivable from the capital
Quality of capital is improved by advances in technology which are the outcomes of research and development. With technological advancement, a unit of capital can enable a unit of labor to increase the amount of goods produced
The difference between a farm which uses manual labor to water the plants and a farm which uses an irrigation system is that the farm that uses manual watering techniques has a lower quality of capital per worker than the farm that has an irrigation system, which is a positive investment.
ldentiy three industries that often need the skills of mechanical engineers. Briefly explain the skills that mechanical engineers bring to these
industries.
Answer:
3 industries that often need the skills of mechanical engineers are:
Automotive industry Construction industry Aerospace industryThe key skills mechanical engineers bring to these industries are effective technical skills, the ability to work under pressure, problem-solving skills, creativity and teamwork.
Explanation:
Automotive industry: The skills mechanical engineers bring to automotive industry include designing new cars for development, conducting laboratory testing for performance safety, and troubleshooting design or manufacturing issues with recalled vehicles. Automotive engineers have:
good mathematical skills, for instance in calculating the stresses power trains and other parts have to withstand; understanding and application of principles of physics and chemistry to properly design engines, electrical systems and other car components; good computer skills, because 21st century engineers rely on computer-assisted design software; knowledge of ergonomics, which is applied in the process of designing a car so that the driver and passengers have a comfortable and functional environment, is another skill mechanical; engineers need.Construction industry: Mechanical engineers are responsible for designing, building, establishing, and maintaining all kinds of mechanical machinery, tools, and components in the construction industry.
Aerospace industry: Mechanical engineers in aerospace industry produce specifications for design, development, manufacture and installing of new or modified mechanical components or systems. They design more fuel-efficient aircraft that cut emissions and build the fleets of satellites that power modern GPS technology.
Why did Percy most likely send Medusa's head to Olympus when he knew this would upset the gods?
Answer: To show his father what he had done
Explanation:
Percy Jackson is the son of the great Greek god of the seas, Poseidon. He did not however, know this for a long time. After he finds out, his life becomes more exciting as he embarks on many adventures.
According to Grover who is his best friend and guardian, Percy sent Medusa's head to Mount Olympus to show his father what he had done so that Poseidon would acknowledge and be proud of him.
determine the wattmeter reading when it is connected to resistor load.
Answer:
Each wattmeter measures a line-to-line voltage between two of the three power supply lines. In this configuration, the total power, watts is accurately measured by the algebraic sum of the two wattmeter values. Pt = P1 + P2. This holds true if the system is balanced or unbalanced.
Which of the following is the property that describes the amount of volume that decreases when pressure is applied to a fluid?
O shear stress
O compressibility
O viscosity
O elasticity
Answer:
Compressibility.
Explanation:
The compressibility of a fluid can be defined as a measure of the change in volume (density) with respect to the amount of pressure applied to the fluid. Thus, as the pressure of a compressible fluid increases, both its viscosity and density increases.
Some examples of compressible fluids are vapors, gases, air etc.
Hence, compressibility is the property that describes the amount of volume that decreases when pressure is applied to a fluid.
Additionally, the compressibility of fluids plays a significant role in the field of science such as in aerodynamics, fluid mechanics, thermodynamics etc.
Answer:
compressiblity
Explanation:
The peak voltage of a 240 vrms sine wave is approximately
Answer:
339.4625
Explanation:
correct me if i am wrong
A 1-ft rod with a diameter of 0.5 in. is subjected to a tensile force of 1,300 lb and has an elongation of 0.009 in. The modulus of elasticity of the material is most nearly:
Answer:
E = 8.83 kips
Explanation:
First, we determine the stress on the rod:
[tex]\sigma = \frac{F}{A}\\\\[/tex]
where,
σ = stress = ?
F = Force Applied = 1300 lb
A = Cross-sectional Area of rod = 0.5[tex]\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2[/tex]
Therefore,
[tex]\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips[/tex]
Now, we determine the strain:
[tex]strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}[/tex]
Now, the modulus of elasticity (E) is given as:
[tex]E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}[/tex]
E = 8.83 kips
Which of the following is the use and study of liquid fluids and their motions, properties, behaviors, and interactions?
O pneumatics
O hydraulics
O torque
O fluid power
Answer:
hydraulics
Explanation:
Answer:
b
Explanation:
Considering only (110), (1 1 0), (101), and (10 1 ) as the possible slip planes, calculate the stress at which a BCC single crystal will yield if the critical resolved shear stress is 50 MPa and the load is applied in the [100] direction.
Solution :
i. Slip plane (1 1 0)
Slip direction -- [1 1 1]
Applied stress direction = ( 1 0 0 ]
τ = 50 MPa ( Here slip direction must be perpendicular to slip plane)
τ = σ cos Φ cos λ
[tex]$\cos \phi = \frac{(1,0,0) \cdot (1,1,0)}{1 \times \sqrt2}$[/tex]
[tex]$=\frac{1}{\sqrt2 }$[/tex]
[tex]$\cos \lambda = \frac{(1,0,0) \cdot (1,-1,1)}{1 \times \sqrt3}$[/tex]
[tex]$=\frac{1}{\sqrt3 }$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
ii. Slip plane --- (1 1 0)
Slip direction -- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, -1, 0)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
iii. Slip plane --- (1 0 1)
Slip direction --- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, 1)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
iv. Slip plane -- (1 0 1)
Slip direction ---- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, -1)}{1 \times \sqrt2}=\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, -1, 1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
∴ (1, 0, -1). (1, -1, 1) = 1 + 0 - 1 = 0
A ball is dropped onto a step at point A and rebounds with a velocity vo at an angle of 15° with the vertical. Determine the value of vo knowing that just before the ball bounces at point B its velocity vB forms an angle of 12° with the vertical. Also determine the velocity of B, vB and the distance d.
Answer:
v₀ = 2.68 m/s.
[tex]v_{B}[/tex] = 3.33 m/s
d = 1.61 m
Explanation:
Searching on the internet I found the picture of the answer in which the height between point A and point B is equal to 0.2 m.
To determine the value of v₀ we need to use the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Taking the initial vertical velocity ([tex]v_{0_{y}}[/tex]) as [tex]v_{A_{y}}[/tex] and the final vertical velocity ([tex]v_{f_{y}}[/tex]) as [tex]v_{B_{y}}[/tex] we have:
[tex]v_{B_{y}} = v_{A_{y}} - gt[/tex]
We can express the time (t) in terms of the velocities of A and B:
[tex] t = \frac{v_{A_{y}} - v_{B_{y}}}{g} [/tex] (1)
Now, we can use the equation:
[tex]y_{f} = y_{0} + v_{A_{y}}t - \frac{1}{2}gt^{2}[/tex] (2)
By entering equation (1) into equation (2):
[tex]y_{f} = y_{0} + v_{A_{y}}*(\frac{v_{A_{y}} - v_{B_{y}}}{g}) - \frac{1}{2}g(\frac{v_{A_{y}} - v_{B_{y}}}{g})^{2}[/tex] (3)
Since [tex]v_{A_{x}} = v_{B_{x}} [/tex] because there is no acceleration in the horizontal movement, we have:
[tex] v_{A}sin(15) = v_{B}sin(12) [/tex]
[tex] v_{A} = \frac{v_{B}sin(12)}{sin(15)} [/tex] (4)
Taking:
[tex]y_{f}[/tex] = 0
[tex]y_{0}[/tex] = 0.2 m
g = 9.81 m/s²
[tex]v_{A_{y}} = v_{A}cos(15)[/tex]
[tex]v_{B_{y}} = v_{B}cos(12)[/tex]
Entering the above values and equation (4) into equation (3) we have:
[tex] -0.4 m*9.81 m/s^{2} = (\frac{v_{B}sin(12)cos(15)}{sin(15)})^{2} - (v_{B}cos(12))^{2} [/tex]
By solving the above quadratic equation:
[tex]v_{B} = 3.33 m/s [/tex]
Hence, the velocity of the ball [tex]v_{B}[/tex] is 3.33 m/s.
Now, we can find [tex]v_{A}[/tex] by using equation (4):
[tex]v_{A} = \frac{v_{B}sin(12)}{sin(15)} = \frac{3.33 m/s*sin(12)}{sin(15)} = 2.68 m/s [/tex]
Then, the value of v₀ of the ball is 2.68 m/s.
Finally, to find the distance between point A and point B we need to calculate the time by using equation (1):
[tex]t = \frac{v_{A_{y}} - (-v_{B_{y}})}{g} = \frac{v_{A_{y}} + v_{B_{y}}}{g}[/tex]
The minus sign in [tex]v_{B_{y}}[/tex] is because the vertical component of the vector is negative.
[tex] t = \frac{v_{A_{y}} + v_{B_{y}}}{g} = \frac{2.68 m/s*cos(15) + 3.33 m/s*cos(12)}{9.81 m/s^{2}} = 0.60 s [/tex]
Now, the distance is:
[tex] x = v_{0}*t = 2.68 m/s*0.60 s = 1.61 m [/tex]
I hope it helps you!
A section of highway has a speed-flow relationship of the form q = au 2 + bu. It is known that at capacity (which is 3100 veh/h) the space-mean speed of traffic is 28 mi/h. Determine the speed when the flow is 1500 veh/h and the free-flow speed.
Find the resultant of two forces 130 N and 110 N respectively, acting at an angle whose tangent
is 12/5.
Answer:
[tex]F_r = 200N[/tex]
Explanation:
Given
Let the two forces be
[tex]F_1 = 130N[/tex]
[tex]F_2 = 110N[/tex]
and
[tex]\tan(\theta) = \frac{12}{5}[/tex]
Required
Determine the resultant force
Resultant force (Fr) is calculated using:
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]
This means that we need to first calculate [tex]\cos(\theta)[/tex]
Given that:
[tex]\tan(\theta) = \frac{12}{5}[/tex]
In trigonometry:
[tex]\tan(\theta) = \frac{Opposite}{Adjacent}[/tex]
By comparing the above formula to [tex]\tan(\theta) = \frac{12}{5}[/tex]
[tex]Opposite = 12[/tex]
[tex]Adjacent = 5[/tex]
The hypotenuse is calculated as thus:
[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex]
[tex]Hypotenuse^2 = 12^2 + 5^2[/tex]
[tex]Hypotenuse^2 = 144 + 25[/tex]
[tex]Hypotenuse^2 = 169[/tex]
[tex]Hypotenuse = \sqrt{169[/tex]
[tex]Hypotenuse = 13[/tex]
[tex]\cos(\theta)[/tex] is then calculated using:
[tex]\cos(\theta)= \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos(\theta)= \frac{5}{13}[/tex]
Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]cos(\theta)[/tex] in
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]
[tex]F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}[/tex]
[tex]F_r^2 = 16900 + 12100 + 11000[/tex]
[tex]F_r^2 = 40000[/tex]
Take square roots of both sides
[tex]F_r = \sqrt{40000[/tex]
[tex]F_r = 200N[/tex]
Hence, the resultant force is 200N
Solve for R.
What is the current going through the 6 ohms light bulb?
Answer:
9A
Explanation:
Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. Which international organizations would it MOST LIKELY turn to? A. UNDP or UNICEF B. World Bank or UNICEF C. UNDP or World Bank D. UNDP or IMF
Answer:
C. UNDP or World Bank.
Explanation:
Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. The international organizations which Bangladesh would most likely turn to are UNDP or World Bank.
Anthony and Angel are making plans for Friday. Anthony wants to go bowling. Angel doesn't bowl well and prefers to go ice-skating at the mall.
Anthony wants Angel to have a good time so he agrees ice-skating will be fun for both of them. Anthony's decision to go ice-skating is an example
of
O evaluation
O arbitration
Omed ation
O compromise
Answer:
4. Compromise
Explanation:
A compromise is when the two disagreeing parties give up something to make a conclusion that both are satisfied with. In this case, Anthony wants Angel to have a good time, so he gives up his bowling.
For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion
This question is incomplete, the complete question is;
For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion
y = 1 - exp( -ktⁿ )
Answer: the time required for 95% transformation is 242.17 s
Explanation:
First, we calculate the value of k which is the dependent variable in Avrami equation
y = 1 - exp( -ktⁿ )
exp( -ktⁿ ) = 1 - y
-ktⁿ = In( 1 - y )
k = - In( 1 - y ) / tⁿ
now given that; n = 2, y = 40% = 0.40, and t = 100 s
we substitute
k = - In( 1 - 0.40 ) / 100²
k = - In(0.60) / 10000
k = 0.5108 / 10000
k = 0.00005108 ≈ 5.108 × 10⁻⁵
Now calculate the time required for 95% transformation
tⁿ = - In( 1 - y ) / k
t = [- In( 1 - y ) / k ]^1/n
n = 2, y = 95% = 0.95 and k = 5.108 × 10⁻⁵
we substitute our values
t = [- In( 1 - 0.95 ) / 5.108 × 10⁻⁵ ]^1/2
t = [2.9957 / 5.108 × 10⁻⁵]^1/2
t = [ 58647.22 ]^1/2
t = 242.17 s
Therefore the time required for 95% transformation is 242.17 s
A genetically engineered hormone.
increasing muscle mass.
can treat Mary's child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
the answer is scientifically science chemistry biochemistry aerospace engineering plato english history world ap history yes
Explanation:
que