What is the magnitude of the force in coulomb's law when one of the charge is double

Answers

Answer 1

Answer: Doubled

Explanation:


Related Questions

4 A student notices that she gets a shock when she touches a metal door handle she has been charged by walking across a carpet. Would she get a shock if the handle was made of plastic?​

Answers

Answer:

Not likely

Explanation:

She might feel a slight shock if she touches a plastic door handle after walking across a carpet, but not nearly as much as when she touches a metal handle. This is because plastic is an insulator, which means it does not conduct electricity very well. Metal is an excellent conductor. When the student drags her feet across a carpet, she builds up a negative electric charge on her body. Free electrons are released from the carpet due to friction between the carpet and her shoes, and the electrons collect on the surface of her body.  If she touches a metal object like a door handle, the electrons flow from her body to the metal, resulting in a static discharge--a shock. However, if she touches a plastic object, the charge will not flow as easily and she is less likely to feel a shock.  The electrons on her body repel the electrons in the metal door knob, leaving the surface of the metal doorknob positively charged, so the electrons jump across a short air gap to the metal door and she feels an electrical shock.  This won't happen so dramatically with a plastic handle because the electrons in plastic won't be as easily repelled as in a metal handle.

11 When you stand on scales you see your mass in kg. Explain whether
it is your mass or your weight that makes the scales work.

Answers

When yоu stаnd оn а scаle, thе reаding thаt yоu sее is аctuаlly а meаsurement оf thе forсe thаt yоur bоdy is еxеrting оn thе scаle.

What makes the scale work

This forсe rеsults frоm thе grаvitаtiоnаl аttrаctiоn between yоur bоdy аnd thе eаrt. Тhe scаle meаsures thе forсe with а sрring or а string gаuge, cоnverts thе reаding tо а morе рrecise meаsurement in kilogrаms, аnd finаlly reсords thе rеsult.

Thus, thе scаles operаte bаsed оn thе forсe еxеrtеd by yоur bоdy, whiсh is dirеctly proportiоnаl tо yоur wеight. Тhe forсe оf grаvity аcting оn аn оbject is cаlled wеight, аnd it vаries bаsed оn thе mаss оf thе оbject аnd thе strength оf thе grаvitаtiоnаl field. On thе othеr hаnd, mаss is а meаsurement оf thе quаntity оf mаtter present in аn оbject аnd is cоnstаnt аcross time.

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Mel adjusted, in a futile attempt to strengthen his pectoral muscles, stretches a spring exercise device 0.73 meters by exerting a force of 177N. What is the stiffness constant

Answers

In the case, Mel stretches a spring exercise device by 0.73 meters with a force of 177 N. We can use Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position, to calculate the stiffness constant.

Hooke's law is given by the equation:

F = kx, where F is the force applied to the spring, k is the stiffness constant, and x is the displacement of the spring from its equilibrium position.

Plugging in the given values:

Force (F) = 177 N Displacement (x) = 0.73 m

We can rearrange the equation to solve for the stiffness constant (k):

k = F / x

Plugging in the values:

k = 177 N / 0.73 m

k ≈ 242.47 N/m (rounded to two decimal places)

Therefore, the stiffness constant of the spring exercise device is approximately 242.47 N/m.

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Simple machines make work easier. You must left a move this load of Saul for your parents. It is heavy you’re using to simple machines when you use this wheel barrow wight simple machine included in the wheelbarrow makes it easier to move the song from one place to another.

Answers

The use of the wheel barrow in this case makes it a simple machine

What is the simple machine?

A wheelbarrow is an illustration of a straightforward device that can simplify labour by lowering the force needed to move a large load. The wheel and axle and the lever are two basic machines that are used.

The wheelbarrow's wheel is made of an axle and wheel. The friction between the wheel and the ground is decreased by the wheel's rotation around the axle. It can also be seen as one of the classes of the lever.

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Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.​

Answers

The position of the center of mass of the system from corner A is 4.3692cm.

To find the position of the center of mass of the system, we need to use the formula:

C.M. = (m1r1 + m2r2 + m3r3 + m4r4)/(m1 + m2 + m3 + m4)

where m1, m2, m3, and m4 are the masses of the four-point masses, and r1, r2, r3, and r4 are the distances of the point masses from the reference point (in this case, corner A).

Let's first find the distances of the four-point masses from corner A. We can see that the distance of the 2kg mass from corner A is 2 cm. The distance of the 4kg mass from corner A is the diagonal of a square of side 2 cm, which is sqrt(22 + 22) = 2.828 cm. Similarly, the distances of the 6kg and 8kg masses from corner A are also 2.828 cm.

Now, let's substitute the values in the formula:

C.M. = (2kg2cm + 4kg2.828cm + 6kg2.828cm + 8kg2.828cm)/(2kg + 4kg + 6kg + 8kg)

C.M. = (4cm + 11.312cm + 16.968cm + 22.624cm)/20kg

C.M. = 1.824cm + 0.5656cm + 0.8484cm + 1.1312cm

C.M. = 4.3692cm

Therefore, the position of the center of mass of the system from corner A is 4.3692cm.

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A 100-volt electromotive force is applied to an RC-series circuit in which the resistance is 400 ohms and the capacitance is 10−4 farad. Find the charge q(t) on the capacitor if q(0) = 0

And also the current in I(t)

Answers

The charge q(t) on the capacitor would be, [tex]q(t)= 0.25c(1-e^{-t/0.04s})[/tex]

And the current I(t) in the circuit will be,[tex]I(t)= 0.25mA(1-e^{-t/0.04s})[/tex]

To find the charge q(t) on the capacitor at any time t, we can use the equation for the charge on a capacitor in an RC circuit:

[tex]q(t)= Q_{max} (1-e^{-t/RC})[/tex]

where Qmax is the maximum charge on the capacitor, R is the resistance, C is the capacitance, and t is time.

To find Qmax, we can use the equation for the maximum charge on a capacitor in an RC circuit:

Qmax = E × C

where E is the electromotive force.

So, we have:

Qmax = 100 V × 10⁻⁴F = 0.01 C

Using the given values of R and C, we have:

R*C = 400 ohms × 10⁻⁴F = 0.04 s

Substituting these values into the equation for q(t), we get:

[tex]q(t)= Q_0.01(1-e^{-t/0.04C})[/tex]

To find the current I(t), we can use Ohm's law and the equation for the charge on a capacitor:

I(t) = (1/R) × d(q(t))/dt

where d(q(t))/dt is the derivative of q(t) with respect to time.

Taking the derivative of q(t), we get:

[tex]dq(t)/dt= 0.01C (1-e^{-t/0.04C})[/tex]

Substituting this into the equation for I(t), we get:

[tex]I(t)= (1/400ohm)(0.01/0.04s) (1-e^{-t/0.04C})[/tex]I

Simplifying, we get:

[tex]I(t)= 0.25mA(1-e^{-t/0.04C})[/tex]

Therefore, the charge q(t) on the capacitor is:

[tex]q(t)= 0.25c(1-e^{-t/0.04s})[/tex]

And the current I(t) in the circuit is:

[tex]I(t)= 0.25mA(1-e^{-t/0.04s})[/tex]

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6.1 Instantaneous communication. In your own words, explain why you
cannot send a message instantaneously using the mechanism of ex-
periment 6.1. If quantum mechanics were deterministic rather than
probabilistic, yet the distant atoms still always left from opposite
exits of a stern gerlach analyzer, would you then be able to send a message instantaneously?
What if the operator of the left-hand Stern-Gerlach analyzer were
somehow able to force his atom to come out of the + exit?

Answers

In Experiment 6.1, two entangled atoms are delivered to several Stern-Gerlach analyzers where the spins are detected in various orientations. Each atom's measurement result is probabilistic and arbitrary. Because there is no way to influence how the measurement on the distant atom turns out, it is impossible to use this process to convey a message instantly.

What is quantum mechanics?

A fundamental area of physics called quantum mechanics examines how matter and energy behave at the atomic and subatomic scales. The behavior of particles like electrons, protons, and photons as well as their interactions are understood and described mathematically.

The idea of entanglement, which describes how two or more particles can come to be connected in such a way that their states are correlated even though they are separated by a considerable distance, is also introduced by quantum mechanics.

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A solution of ethanol is pumped to a vessel 25 m above a reference level through a 25-mm-inside-diameter steel pipe at a rate of 10 m3 /h. The length of pipe is 30 m and contains two elbows with friction equivalent to 20 diameters each. Compute the power requirements of the pump. Solution properties include density of 975 kg/m3 and viscosity of 4 3 1024 Pa s

Answers

Answer:

To compute the power requirements of the pump, we need to determine the head loss and the pump's efficiency. The head loss in the pipeline is given by the Darcy-Weisbach equation:

hL = f (L / D) (V^2 / 2g)

where hL is the head loss, f is the friction factor, L is the length of the pipe, D is the inside diameter of the pipe, V is the average fluid velocity, and g is the acceleration due to gravity.

First, we need to calculate the fluid velocity:

Q = A * V

where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the fluid velocity.

The cross-sectional area of the pipe is:

A = π/4 * D^2

A = π/4 * (0.025 m)^2

A = 4.91 x 10^-4 m^2

So, the fluid velocity is:

V = Q / A

V = 10 m^3/h / (3600 s/h) / (4.91 x 10^-4 m^2)

V = 5.04 m/s

Next, we need to calculate the Reynolds number to determine the friction factor:

Re = (ρVD) / μ

where ρ is the fluid density and μ is the fluid viscosity.

Re = (975 kg/m^3)(5.04 m/s)(0.025 m) / (4.3 x 10^-4 Pa s)

Re = 5.73 x 10^5

Using the Moody chart or a Colebrook equation solver, we can determine the friction factor for the given Reynolds number and roughness of the steel pipe. For simplicity, we will assume a friction factor of 0.02.

The head loss due to friction in the pipe is:

hL = f (L / D) (V^2 / 2g)

hL = 0.02 (30 m / 0.025 m) (5.04 m/s)^2 / (2 x 9.81 m/s^2)

hL = 24.4 m

The head loss due to the two elbows is:

hL = K (V^2 / 2g)

where K is the equivalent length of the elbow in diameters and is equal to 20 diameters each. From a piping handbook, K for a long radius 90° elbow is approximately 30 diameters.

hL = 30 (5.04 m/s)^2 / (2 x 9.81 m/s^2)

hL = 7.82 m

The total head loss is:

hL_total = hL_friction + hL_elbows

hL_total = 24.4 m + 7.82 m

hL_total = 32.2 m

The power required by the pump is:

P = ρQhL_total / η

where η is the pump efficiency.

We will assume a pump efficiency of 75%.

P = (975 kg/m^3)(10 m^3/h)(3600 s/h)(32.2 m)/(0.75)

P = 1.13 x 10^6 W or 1.13 MW

Therefore, the power requirements of the pump are 1.13 MW.

[Rotational motion] Calculate the length L between the 40N weight and the pivot needed to balance the beam shown in Figure 10.9. (solution says it's 7 m but it's unclear how it was obtained)

Answers

Answer:

L = 7m

Explanation:

The beam is balanced (not moving), so the moments about the pivot have to sum to 0.

Let x = dist. from pivot to the 10N ↓ force

CCW rotation is +

CW rotation is -

(100 N)(3 m) - (10 N)(x) - (40 N)(L) = 0

300 N·m - (10 N)(x) - (40 N)(L) = 0      divide by 10 on both sides

30 - x - 4L = 0

x + 4L = 30

10N is the Weight of the beam, so it is at the midpoint of the beam.

x = 5 - 3 = 2 m  substitute into the equation above:

2 + 4L = 30

4L = 30 - 2 = 28

L = 28/4 = 7 m

What is the force of gravity between two 70.0kg masses that are separated by 2.50m?

Answers

Answer:

F = 5.2324 x 10⁻⁸ N

Explanation:

F = G(m₁ · m₂) / r²

where F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N·m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between them.

Plugging in the given values m1 = m2 = 70.0 kg, r = 2.5 m:

F = (6.674 x 10⁻¹¹)(70.0 kg)² / (2.50 m)²

F = 5.2324 x 10⁻⁸ N

Therefore, the gravitational force between the two 70.0 kg masses separated by 2.50 m is approximately 5.2324 x 10⁻⁸ N.

The figure below shows electrons moving along an electric current towards and away from the light bulb.

Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.

Does this figure show a direct or alternating current? Explain your response.

Answers

Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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Which model of the universe is the most widely accepted, and what does it
predict?
A. An open universe, in which the universe never stops expanding
B. A flat universe, in which the universe stops expanding but does not
contract
C. A closed universe, in which the universe stops expanding but does
not contract
OD. A closed universe, in which the universe never stops expanding

Answers

The answer to this question is c

are physical quantities and fundamental quantities same

Answers

Answer:

The physical quantities are the quantities that are the base quantities of the measurement. They are known as the fundamental quantities. The units of those units are known as the fundamental units. The derived physical quantities are dependent on the fundamental quantities.

What type of circuit is shown

Answers

=When three resistors are connected in parallel, they form a parallel circuit. In a parallel circuit, each resistor is connected across the same two points, with the current split between the resistors.

In this configuration, the voltage across each resistor is the same, but the current through each resistor can be different. The total resistance of the circuit is calculated using the equation:

1/R_total = 1/R1 + 1/R2 + 1/R3

where R1, R2, and R3 are the resistance values of the individual resistors.

The total current in the circuit is equal to the sum of the currents through each resistor:

I_total = I1 + I2 + I3

where I1, I2, and I3 are the currents through each resistor.

The total power dissipated in the circuit can be calculated using the equation:

P_total = V² / R_total

where V is the voltage across the resistors.

In summary, when three resistors are connected in parallel, they form a parallel circuit, with each resistor connected across the same two points, and the current split between them. The total resistance, current, and power dissipated in the circuit can be calculated using the equations provided.

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Economics NCS Topic Test No 5. Perfect Market 1.3. Give ONE term for each of the following descriptions. Write uonly the term next to the question numbers (1.3.1 to 1.3.5) in the ANSWER BOOK. Abbreviations, acronyms and examples will NOT be accepted. 1.3.1 Actual expenditure of business such as wages and interest 1.3.2 The cost that changes as more or less outputs are produced 1.3.3 An institution that can make final decisions by reviewing the decisions of the competition commission and Tribunal. 1.3.4 A word that describe the characteristics of differentiated product in oligopoly or monopolistic competition. 1.3.5 A period when inputs or factors of production are fixed. (5x1) (5) TOTAL SECTION A: [201​

Answers

1.3.1 - Operating costs

1.3.2 - Variable costs

1.3.3 - Competition Appeal Court

1.3.4 - Product differentiation

1.3.5 - Short run

Which step of the PRICES method is represented by the letter S?
A.
Raise the injured area above the heart.
B.
Stop the activity until the injury is evaluated.
C.
Wrap the injured site to decrease swelling.
D.
Apply a brace or a splint to the area.

Answers

should be D for support also why is this Physics

A 0.1 kg toy train car moving at 1.0 m/s runs into a stationary car with a mass of 0.15 kg. At what speed do they move off together?

Answers

We can use the conservation of momentum principle to solve this problem. According to this principle, the total momentum of a system of objects remains constant if there are no external forces acting on the system. In this case, we can assume that there are no external forces acting on the two cars after they collide, so the total momentum of the system before the collision must be equal to the total momentum of the system after the collision.

The momentum of an object is defined as its mass multiplied by its velocity:

momentum = mass * velocity

Before the collision, the momentum of the first car (m1) is:

p1 = m1 * v1 = (0.1 kg) * (1.0 m/s) = 0.1 kg⋅m/s

Since the second car is stationary, its momentum before the collision is zero:

p2 = m2 * v2 = (0.15 kg) * (0 m/s) = 0 kg⋅m/s

The total momentum of the system before the collision is:

p1 + p2 = 0.1 kg⋅m/s + 0 kg⋅m/s = 0.1 kg⋅m/s

After the collision, the two cars move together with a common velocity (v), so the momentum of the system is:

p = (m1 + m2) * v

We can set the total momentum before the collision equal to the total momentum after the collision:

p1 + p2 = p

0.1 kg⋅m/s + 0 kg⋅m/s = (0.1 kg + 0.15 kg) * v

0.1 kg⋅m/s = 0.25 kg * v

v = 0.1 kg⋅m/s ÷ 0.25 kg

v = 0.4 m/s

Therefore, the two cars move off together at a speed of 0.4 m/s after the collision.

What is the inertia of motion? ​ ​

Answers

Answer:

The ability of a body to resist changes to its uniform motion condition is known as inertia of motion.

___________________

Hope this helps!

A 5.0 kg block and a 4.0 kg block are connected by a 0.6 kg rod. The links between the blocks and the rod are denoted by A and B. A force F is applied to the upper block.

In Figure 4.2, the blocks and rod assembly move downward at constant velocity. The applied force F is closest to:
a)88 N
b)90 N
c)92 N
d)94 N
e)96 N

Answers

Answer::

D) 94 N

F = M a = (5.0 + 4.0 + .6) a

a = 9.80 m/s^2     since only acceleration is gravitational

F = 9.6 * 9.8 = 94 N

Two whistles emit sounds of wavelength 3.2 m and 2.9 m which produce a beat frequency of about? a) 2 hertz b) 3 hertz c) 4 hertz d) 7 hertz e) 11 hertz

Answers

Two whistles emitting sound of wavelength 3.2 m and 2.9 m would produce a beat of frequency 11 Hertz, hence option e.

The beat frequency (f_beat) is given by the difference in frequency (f) between the two whistles,

f_beat = |f₁ - f₂ |, frequencies of the two whistles are f₁ and f₂ . The frequencies can be calculated from the wavelengths (λ) using the formula,

f = c/λ, speed of sound in air is c, which is approximately 343 m/s at room temperature and atmospheric pressure. For the first whistle with a wavelength of 3.2 m,

f₁ = c/λ₁

= 343/3.2

= 107.1875 Hz

For the second whistle with a wavelength of 2.9 m,

f₂ = c/λ₂

= 343/2.9

= 118.2759 Hz

The difference in frequency is,

f_beat = |f_1 - f_2|

= |107.1875 - 118.2759| ≈ 11.1 Hz

Therefore, the beat frequency is approximately 11 hertz.

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13. List the general strengths and weaknesses of epidemiology for providing an answer to Mary Beth’s question.
14. List the specific strengths and weaknesses of this study.
15. List the general strengths and weaknesses of toxicology for providing an answer to Mary Beth’s question.

Answers

The general strengths of epidemiology for providing an answer to Mary Beth’s question.

epidemiology can study a large populationepidemiology can identify patterns and trends in health and diseaseepidemiology can be used to study different diseases and health conditions

The general  weaknesses of epidemiology for providing an answer to Mary Beth’s question:

epidemiology may not provide a definitive answer or explanationepidemiology results may be affected by biases and confounding variables

The Specific strengths of a study:

Big sample sizeLengthy  follow-up period

The specific weaknesses of a study are :

Use of self-recorded data, which may be inaccurate or biasedBiased selection due to non-random sampling

What is epidemiology?

Epidemiology is described as  the study and analysis of the distribution, patterns and determinants of health and disease conditions in a defined population.

The main objective of epidemiology has been said is to find  out what causes different health outcomes in different groups of people.

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b) What is the cost of operating a 60-W light bulb for 3 days, if the cost of electricity is $0.088 per kW · h?

Answers

The cost of operating a 60-W light bulb in 3 days is $0.38016.

What is electric power?

Electric power is the rate at which electrical energy is transferred by an electric circuit.

To calculate the cost of operating a 60-W light bulb in 3 days, we use the formula below

Formula:

C = PtC'/1000................ Equation 1

Where:

C = Cost of operating the 60-W light bulb in 3 daysP = Power of the bulbt = TimeC' = Cost per kW.h

From the question,

Given:

P = 60 Wt = 3 days = 3×24 = 72 hoursC' = $0.088 per kWh

Substitute these values into equation 1

C = (60×72×0.088)/1000C = $0.38016

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6.
Sonography uses infrasonic waves to create images of objects found inside other objects.
True
False

Answers

Sonography uses infrasonic waves to create images of objects found inside other objects.-False

Sonography, commonly known as ultrasound imaging, creates pictures of structures and organs inside the body using high-frequency sound waves (rather than infrared rays). These sound waves are emitted by a transducer, a portable device put on the skin and deliver sound waves through the body. The waves reverberate off internal organs and structures and are picked up by the transducer, which generates a visual representation on a computer screen. Ultrasonic imaging is widely used in obstetrics to monitor fetal development and in other medical specialties to diagnose and treat various disorders.

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6.3 A probability found through quantum mechanics. In the test of Bells
theorem, experiment 6.2, what is the probability given by quantum
mechanics that, if the orientation settings are different, the two
detectors will flash different colors?

Answers

According to the given information, regardless of the orientation settings, the two detectors will flash different colors with probability . This prediction is based on quantum mechanics.

How to explain the experiment

In the experiment described, a pair of atoms are produced from a central source and detected by two detectors that are separated by a distance of nearly seven miles.

Each detector has the possibility of being oriented as A, B, or C, and is mounted with two colored lamps, a red lamp, and a green lamp.

According to the predictions of quantum mechanics, if the orientation settings of the two detectors are the same, then the two detectors always flash different colors.

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Complete the following sentences:

Wave speed is NOT dependent on _________ or ____________. Instead, wave speed only changes when the ______________ changes. This means that if a sound wave is traveling in pure water and the frequency doubles, the wavelength must _________.

Answers

Wave speed is NOT dependent on amplitude or frequency. Instead, wave speed only changes when the medium changes. This means that if a sound wave is traveling in pure water and the frequency doubles, the wavelength must halve.

3. You may have seen this question previously but now you will approach it using energy
concepts.
A pair of sleds weighs 25 kg and experience a frictional force of 25 N. If a dog team applies a
175 N force pulling it 12 m find:
a) the work done by friction.
b) the work done by the dog team.
c) the net work done (using the net force). How does then net work compare to the answers
from the previous two parts of the question?
d) What form of energy does the frictional force represent? What form of energy does the net
force produce?

Answers

a) Work done by friction is 300 J.

b) Work done by the dog team is 2100 J

c) Net work done 1800 J.

d) loss of mechanical energy.

How to determine work done?

a) The work done by friction can be calculated using the formula

W = Fd, where F = frictional force and d = distance moved.

Therefore, W = 25 N × 12 m = 300 J.

b) The work done by the dog team can be calculated using the same formula, where F = force applied by the dog team.

Therefore, W = 175 N × 12 m = 2100 J.

c) The net work done is the sum of the work done by the dog team and the work done by friction.

Therefore, the net work done is

2100 J - 300 J = 1800 J.

The net work done is positive, which means that the sleds have gained energy.

d) The frictional force represents the loss of mechanical energy due to the interaction between the sleds and the ground. This energy is converted into thermal energy or heat. The net force produced by the dog team produces kinetic energy, which is the energy of motion of the sleds.

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A boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. The girl moves in a negative direction with a speed of 3 m/s. What must be the total final momentum of the boy and girl combined?
A. 0 kgm/s
B. -120 kgm/s
C. 120 kgm/s
D. -100 kgm/s

Answers

Answer:

Explanation:

The total initial momentum of the system is zero since the boy and girl are at rest initially. According to the law of conservation of momentum, the total final momentum of the system must also be zero.

If the girl moves in a negative direction with a speed of 3 m/s, then she gains a momentum of -3 x 40 = -120 kgm/s in the negative direction. To conserve momentum, the boy must gain a momentum of +120 kgm/s in the positive direction, so that the total momentum of the system remains zero.

Therefore, the total final momentum of the boy and girl combined is 120 kgm/s in the positive direction. The answer is C. 120 kgm/s.

Answer:

The girl acquires a velocity of -3 x 40 = -120 kgm/s in the negative direction if she goes with a speed of 3 m/s in the opposite direction. The boy must acquire a momentum of +120 kgm/s in the positive direction to preserve and keep the system's overall momentum at zero.

Explanation:

The answer is option D

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What is the natural period of oscillation of your leg when you march? Compute your velocity? Explain your answer; make comments. (Please use formula and explain with your words clearly)

Electric Electronics Engineering course - Vibrations and Titrations

Answers

The natural period of oscillation of a leg when marching is the time it takes for one complete cycle of oscillation. It can be calculated using the formula:

T = 2π √(L/g)

What is the oscillation  about?

Where T is the natural period of oscillation, L is the length of the leg, and g is the acceleration due to gravity (9.81 m/s^2).

Assuming an average leg length of 1 meter, the natural period of oscillation of a leg is:

T = 2π √(1/9.81) ≈ 0.64 seconds

To compute the velocity of the leg during the march, we can use the formula:

v = 2πL/T

where v is the velocity, L is the length of the leg, and T is the natural period of oscillation.

Substituting the values, we get:

v = 2π(1)/(0.64) ≈ 9.8 m/s

Therefore, This means that during the march, the leg moves back and forth with a velocity of approximately 9.8 meters per second. It's important to note that this calculation assumes a simple harmonic motion, which may not be the case in reality due to the complex motion of various joints and muscles involved in marching.

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How long will the light take in travelling a distance of 500 m in water refractive index of water is 1.33 and velocity of light in vacuum is 3 × 108 m/s. [2] Ans: 2.2 x 10 s ​

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The light will take 2.2 μs  in travelling a distance of 500 m in water refractive index of water is 1.33 and velocity of light in vacuum is 3 × 10⁸ m/s.

When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.

refractive idex of the medium is given by,

μ = velocity of light in vacuum/ velocity of light in medium

velocity of light in water = velocity of light in vacuum/ μ

velocity of light in water = 3 × 10⁸ m/s. / 1.33

velocity of light in water = 2.25 × 10⁸ m/s

Time = distance/velocity

Time = 500 m / 2.25 × 10⁸ m/s

time = 222 × 10⁸ s

time = 2.2 μs

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What is inertia of motion explain one example?​

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THE INABILITY OF A BODY TO CHANGE ITS STATE OF MOTION BY ITSELF

example : a passenger tends to fall forward when breaks are applied in a bus

The tendency of an item to resist a change in its state of motion is referred to as inertia. It specifically refers to an object's resistance to any change in velocity, whether that change be in speed or direction.

What is Inertia ?

When you are riding in a car and the driver abruptly stops, you are experiencing inertia of motion. Because of inertia, your body wants to continue going forward at the same pace and in the same direction as before the brakes were applied. You will lean forward as a result, and if you are not wearing a seatbelt, you may be flung forward. Similarly, while the automobile speeds, your body tries to remain at rest owing to inertia, causing you to be motionless. Despite being widely accepted, Aristotle's theory of motion was challenged by prominent philosophers multiple times over the course of roughly two thousand years. For instance, Lucretius claimed that mobility rather than stasis (stagnation) was the "default state" of the matter (following, presumably, Epicurus).

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