Answer:
0,
Explanation:
if n was 2, then 1,0,-1
A 75.0 mL sample of 0.020 M acetic acid (HC2H3O2) is titrated with 0.020 M NaOH. ? Determine the pH of the solution before the addition of any NaOH. (Ka of acetic acid is 1.8 x 10-5) HC2H3O2 (aq) + H2O (l) D C2H3O2-(aq) + H3O+ (aq) (Hint: before titration so acid only, use ICE table)
Answer:
pH = 3.23
Explanation:
Before the addition of any NaOH, the only you have is a 0.020M acetic acid solution. That is in equilibrium with water as follows:
HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂⁻(aq) + H₃O⁺(aq)
The Ka of this reaction is:
Ka = 1.8x10⁻⁵ = [C₂H₃O₂⁻] [H₃O⁺] / [HC₂H₃O₂]
Where [] are concentrations in equilibrium of each species
As you have in solution just HC₂H₃O₂, the equilibrium concentrations will be:
[HC₂H₃O₂] = 0.020M - X
[C₂H₃O₂⁻] = X
[H₃O⁺] = X
Where X is reaction coordinate.
Repalcing in Ka expression:
1.8x10⁻⁵ = [C₂H₃O₂⁻] [H₃O⁺] / [HC₂H₃O₂]
1.8x10⁻⁵ = [X] [X] / [0.020M - X]
3.6x10⁻⁷ - 1.8x10⁻⁵X = X²
3.6x10⁻⁷ - 1.8x10⁻⁵X - X² = 0
Solving for X:
X = -0.0006M → False solution. There is no negative concentrations
X = 0.000591M → Right solution.
As:
[H₃O⁺] = X
[H₃O⁺] = 0.000591M
As pH = -log[H₃O⁺]
pH = 3.23Use the References to access important values if needed for this question.
For the following reaction, 3.83 grams of hydrogen gas are allowed to react with 9.60 grams of
ethylene (C2H4).
hydrogen(g) + ethylene (C2H4)(g) ethane (C2H)(g)
What is the maximum mass of ethane (C2H6) that can be formed?
grams
What is the FORMULA for the limiting reagent?
What mass of the excess reagent remains after the reaction is complete?
grams
Submit Answer
Retry Entire Group
9 more group attempts remaining
Answer:
A. 10.29 g of C2H6.
B. C2H4.
C. 3.14 g of H2.
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction. This is given below:
C2H4 + H2 —> C2H6
Step 2:
Determination of the masses of C2H4 and H2 that reacted and the mass of C2H6 produced from the balanced equation.
This is illustrated below:
Molar mass of C2H4 = (12x2) + (4x1) =28 g/mol
Mass of C2H4 from the balanced equation = 1 x 28 = 28 g.
Molar mass of H2 = 2x1 = 2 g/mol
Mass of H2 from the balanced equation = 1 x 2 = 2 g.
Molar mass of C2H6 = (12x2) + (6x1) = 30 g/mol.
Mass of C2H6 from the balanced equation = 1 x 30 = 30 g
From the balanced equation above,
28 g of C2H4 reacted with 2 g of H2 to produce 30 g of C2H6.
Step 3:
Determination of the limiting reactant. This can be obtained as follow:
From the balanced equation above,
28 g of C2H4 reacted with 2 g of H2.
Therefore, 9.6 g of C2H4 will react with = (9.6 x 2)/28 = 0.69 g of H2.
From the calculations made above, we can see that only 0.69 g out of 3.83 g of H2 given is needed to react completely with 9.6 g of C2H4.
Therefore, C2H4 is the limiting reactant and H2 is the excess reactant.
A. Determination of the maximum mass of ethane, C2H6 produced from the react.
In this case, the limiting reactant will be used because it will produce the maximum yield of the reaction since all of it is consumed in the reaction.
The limiting reactant is C2H4 and the maximum mass of C2H6 can be obtained as follow:
From the balanced equation above,
28 g of C2H4 reacted to produce 30 g of C2H6.
Therefore, 9.6 gof C2H4 will react to produce = (9.6 x 30)/28 = 10.29 g of C2H6.
Therefore, 10.29 g of ethane, C2H6 were produced from the reaction.
B. The limiting reactant is ethylene with formula C2H4. Please refer to step 3 above for details.
C . Determination of the mass of the excess reactant that remained after the reaction.
The excess reactant is H2, please refer to step 3 above for details and the mass that remained after the reaction can be obtained as follow:
Mass of H2 given = 3.83 g
Mass of H2 that reacted = 0.69 g
Mass of H2 remaining =.?
Mass of H2 remaining = mass of H2 given – mass of H2 that reacted.
Mass of H2 remaining = 3.83 – 0.69
Mass of H2 remaining = 3.14 g
Therefore, 3.14 g of H2 remained after the reaction.
The atomic number of an element is 31 and the mass number of one of its atoms is 65. This atom contains: a 31 neutrons b 34 protons c 65 protons d 34 neutrons e 34 electrons
Answer:
d, 34 neutrons
Explanation:
Mass number is the sum of the number of protons and the number of neutrons.
Atomic number equals to the number of protons.
Since the element has an atomic number of 31, it has 31 protons. The number of neutrons equal to mass number - no. of protons,
which in this case is 65 - 31
= 34 neutrons.
In a neutral atom, the no. of electrons equal to the no. of protons, because each proton carries a +1 charge and each electron carries a -1 charge. To cancel out the charge, their numbers must be equal. So, this atom has 31 electrons.
From the options, only d is correct. (34 neutrons)
consider the following reaction
N2 + 3H2=2NH3
if 30 dm3 of each reactant react together then the volume of mixture at the end is
a 10 dm3
b 20 dm3
c 30 dm3
d 40 dm3
Answer:
d, 40 dm3.
Explanation:
According to Avogadro's law, the mole ratio of chemicals in a reaction is equal to the ratio of volumes of chemicals reacted (for gas).
From the equation, the mole ratio of N2 : H2 : NH3 = 1 : 3 : 2, meaning 1 mole of N2 reacts completely with 3 moles of H2 to give 2 moles of NH3, the ratio of volume required is also equal to 1 : 3 : 2.
Considering both N2 and H2 have 30dm3 of volume, but 1 mole of N2 reacts completely with 3 moles of H2, so we can see H2 is limiting while N2 is in excess. Using the ratio, we can deduce that 10dm3 equals to 1 in ratio (because 3 moles ratio = 30dm3).
With that being said, all H2 has reacted, meaning there's no volume of H2 left. 2 moles of NH3 is produced, meaning the volume of NH3 produced = 10 x 2 = 20 dm3. (using the ratio again)
1 mole of N2 has reacted, meaning from the 30dm3, only 10 dm3 has reacted. This also indicate that 20 dm3 of N2 has not been reacted.
So at the end, the mixture contains 20dm3 of NH3, and 20 dm3 of unreacted N2. Hence, the answer is d, 40 dm3.
Name the physical properties used in seperating kerosene and petrol
simple distillation can be used when the temperature difference between the boiling points of two miscible liquid is at least 25°c. the temperature difference between the boiling points of kerosene and petrol is 25c. hence, this mixture can separated using simple distillation.
answer:simple distillation
A buffered solution containing dissolved aniline, C6H5NH2, and aniline hydrochloride, C6H5NH3Cl, has a pH of 5.57 . A. Determine the concentration of C6H5NH+3 in the solution if the concentration of C6H5NH2 is 0.200 M. The pKb of aniline is 9.13. g
Answer:
[C₆H₅NH₃⁺] = 0.0399 M
Explanation:
This excersise can be easily solved by the Henderson Hasselbach equation
C₆H₅NH₃Cl → C₆H₅NH₃⁺ + Cl⁻
pOH = pKb + log (salt/base)
As we have value of pH, we need to determine the pOH
14 - pH = pOH
pOH = 8.43 (14 - 5.57)
Now we replace data:
pOH = pKb + log ( C₆H₅NH₃⁺/ C₆H₅NH₂ )
8.43 = 9.13 + log ( C₆H₅NH₃⁺ / 0.2 )
-0.7 = log ( C₆H₅NH₃⁺ / 0.2 )
10⁻⁰'⁷ = C₆H₅NH₃⁺ / 0.2
0.19952 = C₆H₅NH₃⁺ / 0.2
C₆H₅NH₃⁺ = 0.19952 . 0.2 = 0.0399 M
Using the Bohr model, determine the lowest possible energy, in joules, for the electron in the Li2+ ion.
Answer: E = - 19.611×[tex]10^{-18}[/tex] J
Explanation: The lowest possible energy can be calculated using the formula:
[tex]E_{n} = - Z^{2}.\frac{k}{n^{2}}[/tex]
where:
Z is atomic number of the atom;
k is a constant which contains other constants and is 2.179×[tex]10^{-18}[/tex] J
n is a layer;
For the lowest possible, n=1.
Atom of Lithium has atomic number of Z=3
Substituing:
[tex]E_{1} = - 3^{2}.\frac{2.179.10^{-18}}{1}[/tex]
[tex]E_{1} =[/tex] [tex]-19.611.10^{-18}[/tex] J
The energy for the electron in the [tex]Li^{+2}[/tex] ion is - 19.611 joules
The lowest possible energy, in Joules, for the electron in the [tex]Li^{2+}[/tex] ion is equal to [tex]1.96\times 10^{-17}\; Joules[/tex]
To determine the lowest possible energy, in Joules, for the electron in the [tex]Li^{2+}[/tex] ion, we would use the Bohr model:
Mathematically, Bohr's model is given by the equation:
[tex]Energy = -Z^2 \frac{k}{n^2}[/tex]
Where:
Z is the atomic number of an atom.n is the number of energy level.k is Rydberg constant.We know that the atomic number of lithium (Li) is equal to 3.
Also, at the lowest possible energy, n = 1.
Rydberg constant = [tex]2.179 \times 10^{-18}[/tex]
Substituting the parameters into the equation, we have;
[tex]E_1 = -3^2 \times \frac{2.179 \times 10^{-18}}{1^2} \\\\E_1 =9 \times 2.179 \times 10^{-18}\\\\E_1 =1.96\times 10^{-17}\; Joules[/tex]
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What is the name of the molecule below?
A) 2-pentene
B) pentane
C) 2-pentyne
D) 2-pentane
The name of the molecule which is given below is 2-pentene.
What are alkene?Alkenes are the organic compounds which are composed of carbon and hydrogen atoms, in which double bond is present.
In the given diagram:
Each corner and joints shows the carbon atoms and number of carbon atoms in it is 5.One double bond is present in the 2nd position.So the compound is 2 pentene.
Hence, 2 pentene is the name of the compound.
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Calculate the entropy change for the reaction: HCl(g) + NH3(g) -> NH4Cl(s) Entropy data: HCl: 187 J/K mol NH3: 193 J/K mol NH4Cl: 94.6 J/K mol
Answer:
-285.4 J/K
Explanation:
Let's consider the following balanced equation.
HCl(g) + NH₃(g) ⇒ NH₄Cl(s)
We can calculate the standard entropy change for the reaction (ΔS°r) using the following expression.
ΔS°r = 1 mol × S°(NH₄Cl(s)) - 1 mol × S°(HCl(g)) - 1 mol × S°(NH₃(g))
ΔS°r = 1 mol × 94.6 J/K.mol - 1 mol × 187 J/K.mol - 1 mol × 193 J/K.mol
ΔS°r = -285.4 J/K
Answer:
-198.3 J/K mol
Explanation:
I got it correct on founders edtell
Re-order each list of elements in the table below, if necessary, so that the elements are listed in order of decreasing electronegativity.
Answer:
O, S, Te
Cl, Br, Se
Explanation:
Main group elements have an electronegativity that increases across a period (from left to right) and decreases down a group.
Each atom has its own value which you can find on the electronegativity chart.
Metals have low values
Nonmetals have high values
I'm your case:
O = 3.5
S = 2.5
Te = 2.1
Cl = 3.0
Br = 2.8
Se = 2.4
O, S, Te, and Cl, Br, Se are the correct order for the elements listed in order of decreasing electronegativity.
What is electronegativity?
Electronegativity. is the tendency or the efficiency of an atom to attract the lone pair of electrons towards itself to become stable and complete their octave is known as electronegativity.
In the periodic table oxygen, fluorine and nitrogen are the three top, most electronegative elements, and from moving up to down in periodic table electronegativity. decreases and left to right increases.
Therefore, the correct order for the elements listed in order of decreasing electronegativity is O, S, Te, and Cl, Br, Se.
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The accepted value of the number of Liters of gas in a mole is 22.4. List two possible reasons on why our experiment yielded a different value for the number of Liters in a mole of a gas.
Hint: Our experiment was conducted in July, in St. Paul, Minnesota.
Answer:
- Pressure in St. Paul, Minnesota
- Temperature in St. Paul, Minnesota
Explanation:
22.4 L or dm³ is the volume for a gas under Standard pressure and temperature conditions.
It is logically to say, that tempereature value at the day of the experiment was not 273.15 K, which is 32°F
We can say, that the pressure was not 1 atm. St Paul Minnesota has a minimum, but a little height, so the pressure differs by few figures from the standard pressure values.
We also have to mention, that 22.4 L is the value for the Ideal gases at standards conditions. Ideal gases does not exisist on practice, we always talk about real gases. Don't forget the Ideal Gases Law equation:
P . V = n . R . T
Pressure . Volume = number of moles . 0.082 L.atm /mol. K . 273.15K
Number of moles must be 1 at STP, to determine a volume of 22.4L
Qualitatively estimate the relative melting points for each of the solids, and rank them in decreasing order.
Rank from highest to lowest melting point. To rank items as equivalent, overlap them.
sodium chloride
graphite
solid ammonia
Answer:
Graphite> sodium chloride> solid ammonia
Explanation:
Melting points of solids has a lot to do with the nature of intermolecular forces in the solid. A substance melts when the intermolecular forces holding the crystal lattice has been overcome such that that the crystal structure of the solid just collapses.
Graphite consists of covalently bonded layers of carbon atom which form a giant lattice. The melting point of graphite is very high because of the fact that the strong covalent bonds that hold the carbon atoms together in the layers require a lot of heat energy to break. Grapoghite melts at about 3600°C
Sodium chloride is an ionic compound that melts at about 801°C. The lattice is composed of alternate sodium and chloride ions.
Solid ammonia is held together by much weaker intermolecular interaction hence it has a melting point of about −77.73 °C.
If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 ATM and the temperature is raised to 302K what will be the resulting volume of the gas
Answer:
15.0L
Explanation:
p/v = constan
(9*21)/253 =(15v)/ 302
v = (9*21*302)/(15*253)
v=15.0
How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3H2O
Answer:
0.677 moles
Explanation:
Take the atomic mass of K = 39.1, O =16.0, P = 31.0
no. of moles = mass / molar mass
no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)
= 0.02256 mol
From the equation, the mole ratio of KOH : K3PO4 = 3 :1,
meaning every 3 moles of KOH used, produces 1 mole of K3PO4.
So, using this ratio, let the no. of moles of KOH required to be y.
[tex]\frac{3}{1} =\frac{y}{0.02256} \\[/tex]
y = 0.02256 x3
y = 0.0677 mol
If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.
Calculate the number of ATP generated from one saturated 10 ‑carbon fatty acid. Assume that each NADH molecule generates 2.5 ATP and that each FADH2 molecule generates 1.5 ATP .
Answer:
Total ATP molecules produced = 66 molecules of ATP
Explanation:
A 10-carbon fatty acid when it has undergone complete oxidation will yield 5 acetyl-CoA molecules and 4 FADH₂ and 4 NADH molecules each. Each of the 5 acetyl-CoA molecules enters into the citric acid cycle and is completely oxidized to yield further ATP and FADH₂ and NADH molecules.
The total yield of ATP in the various enzymatic step is calculated below:
Acyl-CoA dehydrodenase = 4 FADH₂
β-Hydroxyacyl-CoA dehydrogenase = 4 NADH
Isocitrate dehydrogenase = 5 NADH
α-Ketoglutarate dehydrogenase = 5 NADH
Succinyl-CoA synthase = 5 ATP (from substrate-level phosphorylation of GDP)
Succinate dehydrogenase = 5 FADH₂
Malate dehydrogenase = 5 NADH
Total ATP from FADH₂ molecoles = 9 * 1.5 = 13.5
Total NADH molecules = 19 * 2.5 = 47.5
Total ATP molecules produced = 13.5 + 47.5 + 5
Total ATP molecules produced = 66 molecules of ATP
Answer:
Number of ATP generated = = [tex]64 ATPs[/tex]Explanation:
First, calculate the number of acetyl-CoA molecules formed:
Number of acetyl-CoA molecules = [tex]\frac{number of carbons in fatty acid}{2}[/tex]
[tex]= \frac{10}{2}\\\\ = 5 acetyl-CoA molecules[/tex]
Next, calculate the number of rounds of beta-oxidation:
Number of rounds = number of acetyl-CoA molecules - 1
[tex]= 5 - 1\\\\ = 4 rounds[/tex]
Calculate the number of ATP from NADH and FADH2:
If each NADH yields 2.5 ATPs and each FADH2 yields 1.5 ATPs, then multiply the number of rounds by 4 and multiply the number of acetyl-CoA molecules by 10.
[tex](4 * 4) + (5 * 10) = 66 ATP[/tex]
Subract two ATP molecules for activation of the fatty acid.
[tex]Total ATP = 66 - 2\\\\ = 64 ATPs[/tex]
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g What is the standard cell potential for the following reaction occurring in an electrochemical cell. The equation is balanced. 3 Cl2(g) + 2 Fe(s) → 6 Cl-(aq) + 2 Fe3+(aq) The following data may be helpful: Cl2(g) + 2 e- → 2 Cl-(aq) Eº = 1.36 V Fe3+(aq) + 3 e- → Fe(s) Eº = -0.036 V a) -1.40 V b) 1.40 V c) 2.84 V
Answer:
b) 1.40 V
Explanation:
Oxidation half equation;
2Fe(s) → 2Fe3+(aq) + 6 e-
Reduction half equation;
3Cl2(g) + 6 e- → 6 Cl-(aq)
E°cathode= 1.36 V
E°anode= -0.036 V
E°cell= E°cathode - E°anode
E°cell= 1.36 -(-0.036)
E°cell= 1.36 + 0.036
E°cell= 1.396 V
E°cell= 1.40 V
Decide which element probably has a density most and least similar to the density of lithium.
Answer:
Helium and potassium
Explanation:
The density of helium is 0.18 and potassium 0.86, while lithium is 0.53
In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table below. Isotope Atomic Mass (amu) Relative Abundance O-16 15.995 99.759% O-17 16.995 0.037% O-18 17.999 0.204% Calculate the average atomic mass of oxygen. Show all of your calculations below.
Answer: The average atomic mass of oxygen is 15.999 amu
Explanation:
Mass of isotope O-16 = 15.995 amu
% abundance of isotope O-16= 99.759 % = [tex]\frac{99.759}{100}=0.99759[/tex]
Mass of isotope O-17 = 16.995 amu
% abundance of isotope O-17 = 0.037% = [tex]\frac{0.037}{100}=0.00037[/tex]
Mass of isotope O-18 = 17.999 amu
% abundance of isotope O-18 = 0.204% = [tex]\frac{0.204}{100}=0.00204[/tex]
Formula used for average atomic mass of an element :
[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]
[tex]A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)][/tex]
[tex]A=15.999[/tex]
Thus the average atomic mass of oxygen is 15.999 amu
Answer:
Converting the percent abundance into decimal form, we get:
O-16: 99.759% = 99.759/100 = 0.9975
O-17: 0.037% = 0.037/100 = 0.00037
O-18: 0.204% = 0.204/100 = 0.0020
Average atomic mass of oxygen is:
(15.995) x (0.9975) + (16.995) x (0.00037) + (17.999) x (0.0020)
= 15.955 + 0.0062 + 0.0359
= 15.997 amu
Explanation:
From PLATO
A study of the system, 4NH3(g) + 7O2(g) <--> 2N2O4(g) + 6H2O(g), was carried out. A system was prepared with [NH3] = [O2] = 3.60 M as the only components initially. At equilibrium, [N2O4] is 0.600 M. Calculate the equilibrium concentration of NH3(g).
Answer:
The equilbrium concentration of NH₃(g) is 2.4 M
Explanation:
The balanced reaction is:
4 NH₃(g) + 7 O₂(g) ⇔ 2 N₂O₄(g) + 6 H₂O(g)
By stoichiometry of the reaction, 2 moles of N₂O₄ are formed from 4 moles of NH₃.
Considering that the concentration is [tex]concentration=\frac{number of moles}{volume}[/tex] and with a volume of 1 liter, it is possible to apply the following rule of three: if 2 M of N₂O₄ are formed from 4 M of NH₃, 0.6 M of N₂O₄ from what concentration of NH₃ are formed?
[tex]concentration of NH_{3}=\frac{0.6 M of N_{2}O_{3} *4MofNH_{3} }{2 M of N_{2}O_{3} }[/tex]
concentration of NH₃= 1.2 M
By subtracting the moles of NH3 in equilibrium from the moles of NH₃ initially, you will see how many moles of NH₃ were converted and remain in equilibrium: 3.6 M - 1.2 M= 2.4 M
The equilbrium concentration of NH₃(g) is 2.4 M
Carbon-14 has a half-life of 5720 years and this is a fast-order reaction. If a piece of wood has converted 75 % of the carbon-14, then how old is it?
Answer:
11445.8years
Explanation:
Half-life of carbon-14 = 5720 years
First we have to calculate the rate constant, we use the formula :
What is the molar mass of a protein if a solution of 0.020 g of the protein in 25.0 mL of solution has an osmotic pressure of 0.56 torr at 25 ∘ C
Answer:
26.5 kD
Explanation:
Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.56 - ( given ). This is only one part of the information we are given / can conclude in this case ....
i = van’t Hoff factor = 1 for a protein molecule,
R = gas constant = 62.36 L torr / K-mol,
T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K
( Known initially ) ∏ = osmotic pressure = 0.56 torr
..... besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.
_____
Substitute derived / known values to solve for M ( moles / liter ) -
∏ = iMRT
⇒ 0.56 = ( 1 )( M )( 62.36 )( 298 )
⇒ 0.56 = M( 18583.28 )
⇒ M = 0.56 / 18583.28 ≈ 0.00003013461 ....
_____
We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -
M = mol / l
⇒ 0.00003013461 = 0.020 / 25 mL ( 0.025 L ),
0.020 / 0.025 = 0.8 g / L
⇒ 0.8 g = 0.00003013461 moles,
molar mass = 0.8 g / 0.00003013461 moles = 26,548 g / mol = 26.5 kD
Which nonmetal is extremely nonreactive, refusing to bond with other elements except under very unusual conditions created in the laboratory?
Answer:
Helium
Explanation:
Though all noble gases are stable, helium only has two electrons and one shell so it basically doesn't have room for others.
Choose the incorrect statement A. Replacing 3 of the H of LiALH4 with OR groups make it a more reactive reducing agents than NaBH4. B. Ester functional group has a higher priority than aldehyde in nomenclature. C. Ketones are more reactive than esters. D. Aldehydes are less reactive than acyl halides. E. Reactions of aldehydes with (1) NaBH4 and (2) H3O+ form primary alcohols.
Answer:
Replacing 3 of the H of LiALH4 with OR groups make it a more reactive reducing agents than NaBH4
Explanation:
LiAlH4 and NaBH4 are two well known reducing agents in organic chemistry. These two reducing agents function by transfer of hydrogen to the substrate.
If the hydrogen atoms in LiAlH4 are replaced by the -OR moiety, the new compound will be far less reducing than NaBH4 because the hydrogen atoms necessary to effect the reduction has been removed. Thus, the new compound containing -OR moiety can never be more reducing than NaBH4. This implies that the statement written in the answer is false as written.
Solution A has a pH of 10, and solution B has a pH of 1. Which statement best describes these solutions?
Answer:
Solution A is a Weak Alkali, Solution B is a strong Acid.
Explanation:
At pH 10, the colour is blue, therefore it's a weak alkali.
At pH 1, the colour is red, therefore it's a strong Acid.
Which is the correct way to write 602,200,000,000 ,000,000,000,000 in scientific notation
Answer:
6.022 × 10^23
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Which molecule or ion has a trigonal planar shape?
Answer:B
Explanation: A P E X
Where are the lanthanides and actinides found on the periodic table?
A. Columns 7 and 8
B. Columns 3 - 12, in the center of the table
C. Rows 6 and 7, separated from the rest of the table
D. Columns 1 and 2
Answer:
C. Rows 6 and 7, separated from the rest of the table
Explanation:
The lanthanides and actinides are groups of elements in the periodic table, that are thirty (30) in number. They are separated from the rest of the periodic table, usually appearing as separate rows at the bottom. They are often called the inner transition metals, because they all fill the f-block.
Therefore, the correct option is C
" They are found in Rows 6 and 7, separated from the rest of the table"
A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What is the molarity of this solution? Express your answer to four significant figures and include the appropriate units.
Answer:
Approximately [tex]1.854\; \rm mol\cdot L^{-1}[/tex].
Explanation:
Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.
Formula mass of strontium hydroxideLook up the relative atomic mass of [tex]\rm Sr[/tex], [tex]\rm O[/tex], and [tex]\rm H[/tex] on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.
[tex]\rm Sr[/tex]: [tex]87.62[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].[tex]\rm H[/tex]: [tex]1.008[/tex].Calculate the formula mass of [tex]\rm Sr(OH)_2[/tex]:
[tex]M\left(\rm Sr(OH)_2\right) = 87.62 + 2\times (15.999 + 1.008) = 121.634\; \rm g \cdot mol^{-1}[/tex].
Number of moles of strontium hydroxide in the solution[tex]M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1}[/tex] means that each mole of [tex]\rm Sr(OH)_2[/tex] formula units have a mass of [tex]121.634\; \rm g[/tex].
The question states that there are [tex]10.60\; \rm g[/tex] of [tex]\rm Sr(OH)_2[/tex] in this solution.
How many moles of [tex]\rm Sr(OH)_2[/tex] formula units would that be?
[tex]\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}[/tex].
Molarity of this strontium hydroxide solutionThere are [tex]8.71467\times 10^{-2}\; \rm mol[/tex] of [tex]\rm Sr(OH)_2[/tex] formula units in this [tex]47\; \rm mL[/tex] solution. Convert the unit of volume to liter:
[tex]V = 47\; \rm mL = 0.047\; \rm L[/tex].
The molarity of a solution measures its molar concentration. For this solution:
[tex]\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}[/tex].
(Rounded to four significant figures.)
Which statement describes global winds?
They flow from the same direction.
They travel over short distances.
They generate land breezes.
They blow away from the poles to the equator.
Idk the answer
Answer:
They blow away from poles to the equator.
Explanation:
Hello,
In this case, we must take into account that global wind systems are formed by the constant increase in the temperature of the Earth’s surface. Thus, they drive the oceans’ surface currents. In such a way, we can say wind is the basic movement of air from an area of higher pressure to an area of lower pressure, for that reason they blow away from the poles to the equator.
Best regards.
The statement that describes the global winds is they travel over short distances.
What is winds?
Wind is a pattern or type of the movement of the natural air or any other composition of gases over to the relative position of the planet's surface.
Global winds are those winds which can travel in a straight path and originated due to global convention currents. Global winds always move from west to east direction and travels short distances only.
Hence, option (2) is correct.
To know more about global winds, visit the below link:
https://brainly.com/question/1319281
For each of the following names, write down the correct formula.
i. Silicon tetrafluoride
ii. Disulfur decafluoride
iii. Sulfur trioxide
iv. Diphosphorus pentoxide
v. Dichlorine oxide
Explanation:
I hope it helps you
good luck
Answer for the question