What is the x-coordinate of point P on the coordinate grid?

What Is The X-coordinate Of Point P On The Coordinate Grid?

Answers

Answer 1

Answer:

-3/2

Step-by-step explanation:

We have to see where the point lies, check the x-axis from the graph.

(-3/2, 1/2)

x = -3/2

What Is The X-coordinate Of Point P On The Coordinate Grid?
Answer 2

-3/2

Step-by-step explanation:

We have to see where the point lies, check the x-axis from the graph.

(-3/2, 1/2)

x = -3/2


Related Questions

Plot 1 1/3 and 2 7/9

Answers

Answer:

I plotted them for you!

The first dot (closest to the left) is 1 1/3 and the one closest to the right is 2 7/9 :)

Step-by-step explanation:

Hope this helped :) good luck!

Can anyone plz help me

Answers

Answer:

vertex (-4,-1)

2nd point ( 0,31)

Step-by-step explanation:

f(x) = 2x^2 + 16x + 31

First find the vertex

The x coordinate of the vertex is -b/2a  where ax^2 +bx +c

-16/ 2(2) = -16/4 = -4

Substitute into the function

f(-4) = 2 ( -4)^2 +16(-4) +31

       = 2 *16-64 + 31

       = 31 -64 +31

       = -1

The vertex is at ( -4,-1)

Another point can be x=0

f(0) = 0+16(0)+31

     = 31

( 0,31)

What is the mass in grams of 1.00 gal of water? The density of water is 1.00 g/ml.

Answers

The answer is 3,785.41

The mass of water will be - 3785.41 grams.

We have density of water is 1.00 g/ml.

We have to determine the mass in grams of 1.00 gal of water.

Describe the relation between Mass (m) and Density (ρ).

The relation between Mass (m) and Density (ρ) is -

m = ρV

where -  V is the volume of object.

According to the question -

Density of water -  1.00 g/ml

Volume of water -  1 gallon = 3785.41 ml

m = ρV

m = 1 x 3785.41 = 3785.41 grams.

Hence, the mass of water will be - 3785.41 grams.

To solve more questions on Mass and Density, visit the link below -

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Can someone help with this please thanks!

Answers

Answer:

150 I believe but don't quote me on that

I believe the answer to this question is 150

Find the variation constant and an equation of variation where y varies directly as x and y=16 when x=2

Answers

Answer:

variation constant = k = 8

equation of variation : y = 8x

Step-by-step explanation:

Any relationship of variation can be written as y = kx

where k is the variation constant.

_______________________________________

Let the equationof relation between y and x be y =kx here as well

given

y = 16 when x = 2

substituting this value in the equation y = kx

16 = k*2

=> k = 16/2 = 8

Thus,

variation constant = k = 8

equation of variation : y = 8x

I need help with this question, i am not exactly sure how to do it, help is veryy much appreciated

Answers

Yeah i believe this question is a error!!if not it should be 88

If y varies jointly with x and y=5 when x=15 and z=24 find y when x=6 and z=14

Answers

Answer:

if they vary together then y would be 2

Step-by-step explanation:

since they vary together 5 multiplied by 3 is 15 so you would divide 6 by 3 to get 2 the z is irrelevant because it has no relation to x or y

In the figure below, PR and PQ are tangent to the circle with center O. Given that OQ = 10 and OP = 26, find PR.​

Answers

Answer: PR = 24

Explanation:

OQ = 10 is the radius, and so is segment RO. Both are the same length as they are the radii of the same circle. Triangle ORP has a leg of RO = 10 and a hypotenuse of PO = 26. The unknown side is PR = x.

Use the pythagorean theorem. We can use this theorem because the tangent formed (at point R) creates a 90 degree angle.

a^2 + b^2 = c^2

(PR)^2 + (RO)^2 = (PO)^2

x^2 + 10^2 = 26^2

x^2 + 100 = 676

x^2 = 676 - 100

x^2 = 576

x = sqrt(576) ... apply square root

x = 24

Find the algebraic representation of the reflection below.

Answers

Answer:

(x,y) -> (x, -y)

Step-by-step explanation:

This is a reflection about the x-axis.

Algebraically, it can be represented by:

(x,y) -> (x, -y)

since the position along the x-axis does not change, and the y-coordinates are flipped about the x-axis, therefore flipped in sign.

Answer:

Step-by-step explanation:

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Find the algebraic representation of the reflection below. a. (-x ...brainly.com › Mathematics › Middle School

Apr 15, 2020 - Find an answer to your question Find the algebraic representation of the reflection below. a. (-x ,y) b. ( x,-y) c. (-x ,-y) d. ( y,x )

The number of members of an online community increases each month. The
function M(t) = N(1 + ) represents the number of members at month t, where
Nis the initial number of members and ris the rate of increase. Select the
correct statement.
O A. Nincreases each month.
B. The initial value is (1 + r).
C. The function is linear.
D. The value of Mis a product of Nand a factor that does not depend
on N.

Answers

The correct answer is D

Hurry!!


State the domain of the glven relation.

Answers

Answer:

x ≤ -1

Step-by-step explanation:

Aaron covers 300 miles in 6 hours, what's his average speed?​

Answers

Answer:

50mph

Step-by-step explanation:

Speed=v

time=t

distance=s

v=s/t

v=300m/6h

v=50mph

Let me know if my answer is wrong.

Hope this helps :) ❤❤❤

Answer:

[tex]\boxed{Speed = 50 miles/hr}[/tex]

Step-by-step explanation:

Given:

Distance = S = 300 miles

Time = t = 6 hours

Required:

Average Speed = v = ?

Formula:

Average Speed = Total Distance Covered / Total Time Taken

Solution:

v = S/t

v = 300 miles / 6 hours

v = 50 miles/hr

Which equation is correct regarding the measure of ∠MNP?

Answers

Answer:

I need the numbers

Step-by-step explanation:

Answer:

m∠MNP = (x – y)

m∠MNP = (x + y)

m∠MNP = (z + y)

m∠MNP = (z – y)

Find m to the second power + 1/m to the second power if m+1/m = square root of 71 . WILL MARK BRAINLIEST

Answers

Answer:  69

=============================================

Explanation:

Note that m + 1/m and m^2 + 1/(m^2) are very similar. If we square (m + 1/m), then we end up with something in the form (a+b)^2 = a^2 + 2ab + b^2, where a = m and b = 1/m. The 2ab portion is equal to 2*m*(1/m) = 2 which allows us to isolate m^2 + 1/(m^2) fully.

The steps below show this

[tex]m + \frac{1}{m} = \sqrt{71}\\\\\left(m + \frac{1}{m}\right)^2 = \left(\sqrt{71}\right)^2\\\\m^2 + 2*m*\frac{1}{m} + \frac{1}{m^2} = 71\\\\m^2 + 2 + \frac{1}{m^2} = 71\\\\m^2 + 2 + \frac{1}{m^2} - 2 = 71-2\\\\m^2 + \frac{1}{m^2} = 69\\\\[/tex]

-------------

Alternatively, you can isolate m in the equation [tex]m + \frac{1}{m} = \sqrt{71}[/tex] to get two irrational solutions. Plug either solution into m^2 + 1/(m^2) and you should get the same result as above.

How is everyone doing today? Here is a problem for the day! Problem - 10 + 8 x 119

Answers

Answer:

..

-10 + 8× 119

= -10 + 952

= 942. .....

Answer:

236 (i think)

Step-by-step explanation:

cuz 0-10= -10+8= -2 X 119=236   (sorry if you cant read this my keyboard sucks

helpppp me now plz help

Answers

I’m pretty sure to find the mean then after you find the average u can determine the answer

Answer:

0.53 is the right answer

I NEED HELP ASAP! What is the interquartile range (IQR) of the data set below? Will give one lucky person the title as the brainliest (if they are correct).

Answers

Hey there! I'm happy to help!

First, we arrange the numbers from least to greatest.

26,29,31,31,32,37,43

The median here is 31 because it is the middle number. The three numbers before it is one half of it and the last 3 numbers are their own half, because you cannot split the 31 between the two halves.

Now, we want to find the first quartile. This is basically the media of the first half of numbers. So, our first half consists of 26,29, and 31.

The middle number of this first half is 29.

So, our Q1 (first quartile) is 29.

Now, for the third quartile. We do the exact same thing here but with the second half.

32,37,43

Looking at this, our Q3 is 37

The interquartile range is how far apart Q1 and Q3 are, so to find it, we subtract our Q1 from the Q3.

37-29=48

Therefore, our IQR is 8.

Congratulations! Now you can find the IQR of a data set! Have a wonderful day! :D

Answer:

8

Step-by-step explanation:

You first put the numbers in order. Then you find the median(in this case, 31) and after that you find the Q1 and Q3(think of Q1 as the median of the lower half and Q3 as the mdian of the upper half.) Subtract Q1 from Q3, in this case, 37-29=8. 8 is the IQR or the interquratile range.

The fourth and fifth graders at Jackson Elementary had a competition to see who could
recycle the most newspaper in a 3-day period. Use the chart to answer the question,
The students at Lee Elementary collected 3 times as much as the students at Jackson. How
many pounds did the students at Lee recycle?

Answers

Answer: the elementary 45

Step-by-step explanation: if you need anything else let me know

30 POINTS! Arrange the steps to solve this problem. 9 steps.

Answers

Answer:

1. Multiply the first equation by 3

3(x + y ) = 3(-2)

3x + 3y - 6

2. Add 3x + 3y = - 6 ( obtained in step 1) to

2x - 3y = - 9 (given) and solve for x

3. x = - 3

4. Substitute the value of x in the first equation

( x + y = - 2) to get y = - 1

5. The solution for the linear system of equations is ( - 3 , 1)

Hope this helps you

Describe the transformation of ƒ(x) = log5 x which is given by g(x) = 3 log5 (x−7). Question 16 options: A) g(x) is shrunk vertically by a factor of 1∕3 and translated to the right 7 units compared to ƒ(x). B) g(x) is stretched vertically by a factor of 2 and translated to the left 7 units compared to ƒ(x). C) g(x) is stretched vertically by a factor of 3 and translated to the right 7 units compared to ƒ(x). D) g(x) is shrunk vertically by a factor of 1∕3 and translated to the left 7 units compared to ƒ(x)

Answers

Answer:

C) g(x) is stretched vertically by a factor of 3 and translated to the right 7 units compared to ƒ(x).

Step-by-step explanation:

Notice that by transforming  [tex]f(x)=log_5\,(x)[/tex]  into [tex]g(x)=3\,log_5\,(x-7)[/tex] we have performed the following transformations:

a) a horizontal shift to the right 7 units by subtracting 7 from the x-variable, and

b) stretching the full function vertically by a factor of 3, by multiplying the full function by 3.

Therefore, our answer matches answer C in the list of possible options

(30 POINTS!!!) One press can run the day’s newspapers in 6 hours, while another can do the same job in 8 hours. After running together for 2 hours to complete the job, the faster one breaks. How much longer must the slower press run to finish the newspapers?

Answers

Amount of the job done after 2 hours:

2(1/6 + 1/8)

2(4/24 + 3/24)

2(7/24)

7/12 (amount of job finished)

.

amount of job left to do:

1 - 7/12

 

12/12 - 7/12

5/12 (remaining)

.

Let x = time (hours) slower press takes to finish job

then

x(1/6) = 5/12

multiplying both sides by 6:

x = 5/12 *6

x = 5/2 hours

or

x = 2 hours and 30 minutes

The slower press (8-hour press), will take h 3 hours, 20 minutes to complete the job

how is this question solved?

Answers

Answer:

[tex]\large \boxed{\sf \ \ 35.805 \ \ }[/tex]

Step-by-step explanation:

Hello,

First of all we need to find the intersection points of y = 12 and

[tex]y=f(x)=e^x+e^{-x}[/tex]

We need to solve the following equation.

[tex]e^x+e^{-x}=12\\\\\text{*** We multiply by }e^x\text{ both side ***}\\\\\left(e^x\right)^2+1=12e^x\\\\\text{*** Let's note } X =e^x\text{, it comes *** }\\\\X^2-12X+1=0[/tex]

[tex]\Delta=b^2-4ac=12^2-4=140=2^2\cdot 35\\\\X_1=\dfrac{12-2\sqrt{35}}{2}=6-\sqrt{35}\\\\X_2=\dfrac{12+2\sqrt{35}}{2}=6+\sqrt{35}\\[/tex]

And, we take the greater solution to solve:

[tex]X=e^x=6+\sqrt{35}<=>\boxed{x=ln(6+\sqrt{5})}[/tex]

Let's note it a.

Let's compute the integral.

We need to compute the following (because 12-f(x) is pair the integral that we are looking for is)

[tex]\displaystyle 2\int\limits^a_{0} {\left(12-(e^x+e^{-x})\right)} \, dx =12*(2a)-2\int\limits^a_{0} {(e^x+e^{-x})} \, dx \\\\=24a-2[e^x-e^{-x}]_{0}^a=24a-2(e^a-e^{-a})[/tex]

We can replace a by the value we already found.

[tex]24\cdot ln(6+\sqrt{35})-2\left( 6+\sqrt{35}-\dfrac{1}{6+\sqrt{35}}\right)\\\\=24\cdot ln(6+\sqrt{35})-2\left(6+\sqrt{35}-\dfrac{\sqrt{35}-6}{(\sqrt{35}-6)(\sqrt{35}+6)}\right)\\\\=24\cdot ln(6+\sqrt{35})-2\left(\dfrac{29*6+29*\sqrt{35}-\sqrt{35}+6}{29}\right)\\\\\\=24\cdot ln(6+\sqrt{35})-2\left(\dfrac{180+28\sqrt{35}}{29}\right)\\\\[/tex]

= 59.46933...-26.66432...=35.8050...

So the answer is [tex]\boxed{\sf \ \ 35.805 \ \ }[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

35.805 that’s the answer good luck

ALGEBRA 1
Find the number of terms in the sequence given below:
1.5, 9, 13, ........, 201
a. 51
b. 42
c. 59
d. 45

Answers

Answer:

a. 51

Step-by-step explanation:

[tex]t_{n} =a+(n-1)d[/tex]

201 = 1 + (n - 1)4

200 = (n - 1)4

50 = n - 1

51 = n

A

I just took the test

A line passes through the point (6,1)and has a slope of 3/2. write an equation in slope intercept form

Answers

Answer:

Step-by-step explanation:

Slope intercept form :  y - y1 = m(x -x1)

m = 3/2

(x1, y1) = (6, 1)

[tex]y - 1 = \frac{3}{2}(x - 6)\\\\y -1 = \frac{3}{2}*x -\frac{3}{2}*6\\\\y-1=\frac{3}{2}x-3*3\\\\y-1=\frac{3}{2}x-9\\\\y=\frac{3}{2}x-9+1\\\\y=\frac{3}{2}x -8[/tex]

Answer:

y=3/2 x  -8

Step-by-step explanation:

The slope should be in front of the x and the y intercept should be right after the x to create the slope intercept form. I used a graphing calculator which continued the line of 6,1 with a slope of 3/2 and then got

y=3/2x-8

Identify an equation in point-slope form for the line perpendicular to
y=-2x+ 8 that passes through (-3,9).
O A. y - 9 = -2(x+3)
O B. y+3 - 3(x-9)
O C. y-9-(x + 2)
O D.y +9 = 2(x – 3)

Answers

The answer is A because the slope is -2 and that is the only one that shows -2 as a slope

The correct option is A. The equation in point-slope form for the line perpendicular to y = -2x + 8 and passing through (-3, 9) is: y - 9 = 1/2(x + 3).

To find the equation of a line perpendicular to y = -2x + 8 that passes through the point (-3, 9), we need to determine the slope of the perpendicular line.

The given equation is in slope-intercept form, y = mx + b, where m represents the slope. In this case, the slope of the given line is -2.

Since the perpendicular line has a slope that is the negative reciprocal of -2, we can determine its slope as 1/2.

Now that we have the slope (1/2) and a point (-3, 9) on the line, we can use the point-slope form of a line to write the equation:

y - y₁ = m(x - x₁)

where (x₁, y₁) is the given point and m is the slope.

Plugging in the values, we get:

y - 9 = 1/2(x - (-3))

Simplifying:

y - 9 = 1/2(x + 3)

Rearranging to match the given options:

y - 9 = 1/2(x) + 3/2

The equation in point-slope form for the line perpendicular to y = -2x + 8 and passing through (-3, 9) is:

y - 9 = 1/2(x + 3)

Therefore, the correct option is A.

Learn more about equation here

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Complete question is below

Identify an equation in point-slope form for the line perpendicular to

y=-2x+ 8 that passes through (-3,9).

A. y - 9 = 1/2(x+3)

B. y+3 = 3(x-9)

C. y - 9 = (x + 2)

D. y + 9 = 1/2(x – 3)

Brett is making chocolate bars. He wants to make 35 bars from Monday to Friday. One cocoa pod makes ⅚ of bar. If he harvests the same number of cocoa pods each day, how many cocoa pods should he harvest each day to reach his goal of making 35 bars total from Monday to Friday?

Answers

Answer:

one cocoa pod makes 5/6 bar

to make 35 bars, he needs

35 / (5/6) = 35 * 6/5 = 42 pods

Monday - Friday is 5 days

42/5 = 8.4

Which equation gives the length of the altitude of ABC?

Answers

Answer:

B. AD = sqrt(CD * BD)

Step-by-step explanation:

By the right triangle altitude theorem,

CD/AD = AD/BD

AD^2 = CD * BD

AD = sqrt(CD * BD)

Answer: B. AD = sqrt(CD * BD)

Answer:

B

Step-by-step explanation:

[tex]$\frac{CD}{AD} =\frac{AD}{BD} $[/tex]

[tex]AD^2=CD \cdot BD[/tex]

[tex]AD=\sqrt{CD \cdot BD}[/tex]

In this question, you are clearly supposed to use the geometric mean theorem or known as the right triangle altitude theorem. But note that there are other approaches to find the height of the triangle.

Using Pythagorean theorem:

[tex]AD^2+CD^2=AC^2 \Rightarrow AD=\sqrt{AC^2-CD^2}[/tex]

Also,

[tex]AD=AC\sin(c)[/tex]

One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What weight of candies did they each eat?

Answers

Answer:

First person ate 2.1 pounds and second person ate 4.8 pounds

Step-by-step explanation:

First we find the common denominator. So 3/5=12/20. 12/20+3/20+15/20. That means that 5/20=1.5 lb. So 1/20=.3 pounds. So person number one ate .9+1.2=2.1 pounds of candy and person number two ate 4.5+.3=4.8

AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.

Answers

Answer:

The distance of the midpoint of AB = 4 cm

The distance of the midpoint of CD = 28 cm

Step-by-step explanation:

The given information are;

Segment AD = 36

Point C and point B are points on AD such that AB:BC:CD = 2:3:4

Which gives;

The proportion of AB in AD = 2/(2+3+4) = 2/9

The length of AB = 2/9×36 = 8 cm

The proportion of BC in AD = 3/(2+3+4) = 3/9

The length of AD = 3/9×36 = 12 cm

The proportion of CD in AD = 3/(2+3+4) = 4/9

The length of AD = 4/9×36 = 16 cm

The coordinate of the midpoint of AB = 8/2 = 4 cm from A

The distance of the midpoint of AB = 4 cm

The coordinate of the midpoint of CD = 8 + 12 + 16/2 = 28 cm from A

The distance of the midpoint of CD = 28 cm.

The linear combination method gives a solution of (–4, 2) for which of these systems of linear equations? 3 x + 13 y = 14. 6 x + 11 y = negative 2. 4 x + 5 y = 12. 8 x + 3 y = negative 4. 5 x + 4 y = 12. 7 x + 8 y = 12. 10 x + 3 y = 8. 17 x + 6 y = 10.

Answers

Answer:choice one

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I did the test

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