What is the electric field strength at a distance of 10 cm from a charge of 2 uC

Answers

Answer 1

The electric field strength at a distance of 10 cm from a charge of 2 μC is 3.6 x 10⁵ N/C.

What is called electric field?

If there's a charge present in any form, an electric field is linked with every point in space. The strength and direction of the electric field are expressed by the value of E, sometimes referred to as the strength of the electrical field, electric field intensity, or simply the electric field.

The following formula determines the magnitude of the electric field generated by a point charge:

where,

E = Electrical Field Strength = ?

k = 9 x 10⁹ Nm²/C²

q = magnitude of charge

q = 2 μC = 2x 10⁻⁶ C

r = distance = 10 cm

r = 0.10 m

Therefore,

When the values are entered into the equation, we obtain:

E = 9 x 10⁹ * (2 x 10⁻⁶) / (0.1)²

E = 3.6 x 10⁵ N/C

Because of this, the electric field intensity at 10 cm from a 2 μC charge is  3.6 x 10⁵ N/C.
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Related Questions

A rock is launched horizontally by a slingshot. Once the rock is moving, there is a total of 45 J of energy stored in the isolated system.

How much energy was stored in the system before the slingshot went off and launched the rock?

Group of answer choices

more than 45 J because an isolated system gains energy as energy is converted from one form to another

Less than 45 J because an isolated system loses energy as energy is converted from one form to another.

There is no way to tell without knowing the speed of the rock

45 J, because the initial and final energy must be the same in an isolated system

Answers

The correct answer is 45 J, because in an isolated system, the total amount of energy remains constant.

The energy stored in the system before the slingshot went off and launched the rock must be equal to the energy stored in the system after the rock is launched, which is 45 J. Therefore, the correct answer is 45 J.

What is an isolated system?

An isolated system is a physical system that does not exchange any matter or energy with its surroundings. In other words, an isolated system is a closed system that does not allow the transfer of mass or energy across its boundary.

In an isolated system, the total amount of energy is constant. This means that energy cannot be created or destroyed, but it can be converted from one form to another. For example, if an isolated system contains a certain amount of thermal energy, this energy can be transferred from one part of the system to another, but the total amount of thermal energy in the system remains constant.

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Lola Is making breakfast. she makes toast, scrambles eggs, butters, the toast, fries bacon and squeezes oranges for orange juice. Of the tasks Lola completes, which ones were physical changes, Lola is making breakfast. She makes toast, scrambles eggs, butters the toast, fries bacon, and and how do you know? A- Answer the question: P- Provide evidence: E- Explain and expand:​

Answers

A- When preparing breakfast, Lola undergoes the following physical changes: Butter the bread and fries the bacon. oranges are squeezed for orange juice

A- Answer the question: P- Provide evidence:

Butter the toast: The heat of the toast causes the butter to gently melt when Lola spreads it on the bread. This is a physical modification because it only modifies the butter's and toast's physical characteristics, not their chemical makeup.

Fry bacon: When Lola fries the bacon, the heat melts the fat and denatures and coagulates the proteins, giving the bacon a crispy quality. This is likewise a physical modification because it only modifies the bacon's physical characteristics, not its chemical makeup.

Oranges are squeezed to produce orange juice. The juice is drawn from the orange cells and separated from the pulp when Lola squeezes oranges.

A- Answer the question: E- Explain and expand:​

A physical alteration is one in which just the substance's physical characteristics, such as shape, size, colour, or state, are altered. The substance's chemical makeup remains unchanged. The butter, bacon, and orange are all enduring physical modifications in the activities that Lola completes because they simply alter their physical characteristics without altering their chemical makeup. For instance, altering the physical qualities of things without altering their chemical makeup includes melting butter and bacon and extracting the juice from an orange.

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Earth Science
PLEASE HELP

Answers

Tide are waves on oceans. The 5th day tide are know as extreme and called the king or spring tide, while the 13th day tide are called the neap tide.

What are tides as described in the picture?

Tides are long waves that move across the oceans as a result of the moon's effect on the gravitational forces of the earth and, to a lesser extent, the sun.

The tides on day 5 are extreme because both the moon and the sun contribute equally to tide formation; these are known as spring or king tides. The diagram will be drawn so that the sun, moon, and earth are all in the same straight line.

The tides are not extreme on day 13 because the sun cancels out the moon tides. It is referred to as neap tide, which means "powerless tide." The diagram will depict all three (the sun, moon, and earth) arranged at a right angle.

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Ackee
Ackee is a unique fruit in that it has a lot of fat, a very unusual feature for a fruit. This
has caused many persons to think that eating it may be unhealthy.
False statements like "eating ackees will increase a man's risk of prostate cancer" are
still being made, even by health professionals. On the contrary, the fruit is not only
delicious, but also a very healthy food choice.
The scientific name for our national fruit, ackee, is Blighia Sapida. Ackee was named
after Captain William Bligh, an English sailor who took the fruit from Jamaica to
England, in 1793. It is originally from West Africa. Jamaica is the only place where
the fruit is extremely popular among locals and tourists. However, it has been
introduced into most of the other Caribbean islands (for example, Trinidad, Grenada,
Antigua and Barbados) as well as Central America and Florida.
The Pan American Health Organization states that the ackee is a good source of
healthy fats and an excellent source of good fats in the Jamaican diet.
Traditionally, ackee is cooked with salt fish to produce an often oily meal.
Unfortunately, the type of oil used in cooking ackee and salt fish often contains
unhealthy fats. These 'bad' fats or excess salt in the salt fish may be responsible for the
view that ackee is bad for you. The ackee itself is a very healthy food. Today, there
are many ways to prepare healthy and tasty ackee dishes, without using cooking oils
that may be harmful.
Ackee contains no cholesterol or unhealthy fat, and I have not found any scientific
evidence to suggest that ackee causes prostate cancer.

Answers

It is important to distinguish between the health benefits of the ackee fruit itself and the potential negative health effects of the oil used in cooking it with salt fish.

Ackee is actually a healthy fruit that contains good fats, including omega-3 and omega-6 fatty acids, which are important for heart health and brain function. It is also a good source of protein, dietary fiber, vitamins, and minerals, including vitamin C, calcium, and potassium.

However, it is true that the oil used to cook ackee with salt fish can be unhealthy, depending on the type of oil used. Traditional cooking methods often involve using oils high in saturated or trans fats, which can contribute to heart disease and other health problems. To make ackee dishes healthier, it is recommended to use healthier cooking oils, such as olive oil or coconut oil, and to limit the amount of salt fish used in the dish.

Overall, ackee is a healthy and delicious fruit that can be enjoyed as part of a balanced diet. However, it is important to be mindful of how it is prepared and cooked to ensure that it is not combined with unhealthy ingredients that can detract from its nutritional value.

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Space tourists promoted motel and restaurant development.

Retired space professionals promoted new home and community growth.

Space themed business opened all over.

More colleges and universities taught space related mathematics, engineering, sciences, and foreign languages.


Which of these is true of all the above statements?

Responses


A Space is the only important aspect of Florida's culture.Space is the only important aspect of Florida's culture.

B Space has had very little influence of Florida's culture.Space has had very little influence of Florida's culture.

C Space is a very important aspect of Florida's culture.Space is a very important aspect of Florida's culture.

D Space has not been a very important aspect of Florida's culture.

(update: its c)

Answers

The right answer is C. Space plays a significant role in Florida culture. Space plays a significant role in Florida culture.

What additional elements, outside space-related activity, have helped Florida's culture develop?

The natural environment, history, diversified population, and well-liked attractions like beaches and amusement parks are some of the influences on Florida's culture.

What are some possible negative effects of making space-related pursuits a significant part of Florida's culture?

Although Florida has benefited economically and educationally from space-related activity, focusing on this industry as a significant part of the state's culture could have negative effects. Moreover, emphasizing space-related operations could put other crucial industries, like healthcare or environmental conservation.

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The moon has a radius of 1,738,000 m and a mass of 7.35 x 1022 kg. It orbits the
earth at a radius of 3.84 x 10¹¹ m. The earth's mass is 6 x 1024 kg. What is the
force gravity between the earth and the moon?

Answers

To calculate the gravitational force between the Earth and the Moon, we can use Newton's law of universal gravitation, which is given by:

F = (G * m1 * m2) / r²

Where F is the force of gravity, G is the gravitational constant (6.674 x 10⁻¹¹ N·(m/kg)²), m1 and m2 are the masses of the two objects (Earth and Moon), and r is the distance between the centers of the two objects.

In this case, m1 (Earth's mass) = 6 x 10²⁴ kg, m2 (Moon's mass) = 7.35 x 10²² kg, and r (distance between the Earth and the Moon) = 3.84 x 10¹¹ m.

Plugging these values into the formula, we get:

F = (6.674 x 10⁻¹¹ N·(m/kg)²) * (6 x 10²⁴ kg) * (7.35 x 10²² kg) / (3.84 x 10¹¹ m)²

Now, calculate the force:

F ≈ 1.9821 x 10²⁰ N·m²/kg² / 1.4756 x 10²³ m²
F ≈ 1.3426 x 10²⁷ N·m² / 1.4756 x 10²³ m²
F ≈ 9.09 x 10²³ N

The gravitational force between the Earth and the Moon is approximately 9.09 x 10²³ N.

A star has a mass that is 6.6 times that of the Sun. Assuming that it's on the main sequence, how many solar luminosities is it?

Answers

The star has a luminosity that is approximately 195.8 times that of the Sun.

The luminosity of a star is directly proportional to its mass to the power of approximately 3.5. This relationship is known as the mass-luminosity relation. Using this relation, we can calculate the luminosity of the star relative to the Sun as follows:

L_star/L_sun = (M_star/M_sun)^3.5

where L_star is the luminosity of the star, M_star is the mass of the star, L_sun is the luminosity of the Sun, and M_sun is the mass of the Sun.

Substituting the given values, we get:

L_star/L_sun = (6.6)^3.5

Using a calculator, we find:

L_star/L_sun = 195.8

Therefore, the star has a luminosity that is approximately 195.8 times that of the Sun.

What is luminosity?

Luminosity is a measure of the total amount of energy emitted by a star, galaxy, or other astronomical object per unit time. It is a fundamental property of an astronomical object and is related to its size, temperature, and composition.

Luminosity is often compared to the concept of brightness, which is a measure of the amount of light received by an observer from an astronomical object.

Luminosity is typically measured in units of watts (W) or solar luminosities (L☉), where one solar luminosity is equal to the luminosity of the Sun (about 3.828 x 10^26 W).

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what effect does density have on transverse waves

Answers

It affects transverse waves because it compacts their energy so when something touches it it give a jolt of energy instead of something snmall

Block 1 of mass 4.0 kg is sliding to the right with velocity 5.5 m/s and collides with block 2 of mass 4.5 kg moving with velocity -2.5 m/s. The collision is perfectly elastic. What is the velocity of block 1 after the collision? Positive velocity indicates motion to the right while negative velocity indicates motion to the left.​

Answers

The final velocities of the two blocks after the collision are:

Block 1: 2.32 m/s to the right

Block 2: 2.43 m/s to the left

What is the final velocity of the blocks?

We can use the conservation of momentum and the conservation of kinetic energy to solve this problem.

Since the collision is perfectly elastic, the total kinetic energy before and after the collision should be the same.

Let's first calculate the momentum of each block before the collision:

Momentum of block 1 = mass x velocity = 4.0 kg x 5.5 m/s = 22.0 kg m/s to the right

Momentum of block 2 = mass x velocity = 4.5 kg x (-2.5 m/s) = -11.25 kg m/s to the left

The total momentum before the collision is:

P_before = 22.0 kg m/s - 11.25 kg m/s = 10.75 kg m/s to the right

Now, let's use the conservation of momentum to find the velocity of the blocks after the collision. Since the momentum is conserved, the total momentum after the collision should also be 10.75 kg m/s to the right.

Let the final velocity of block 1 be v1 and the final velocity of block 2 be v2. Then we have:

Momentum of block 1 after collision = mass x velocity = 4.0 kg x v1

Momentum of block 2 after collision = mass x velocity = 4.5 kg x v2

Total momentum after collision = 4.0 kg x v1 + 4.5 kg x v2 = 10.75 kg m/s to the right

We also know that the total kinetic energy before and after the collision should be the same. The kinetic energy of a block is given by:

Kinetic energy = 0.5 x mass x velocity^2

The total kinetic energy before the collision is:

KE_before = 0.5 x 4.0 kg x (5.5 m/s)^2 + 0.5 x 4.5 kg x (-2.5 m/s)^2 = 30.625 J

The total kinetic energy after the collision is:

KE_after = 0.5 x 4.0 kg x v1^2 + 0.5 x 4.5 kg x v2^2

Since the collision is perfectly elastic, we know that the kinetic energy is conserved, so KE_before = KE_after.

Therefore, we can set these two equations equal to each other and solve for v1:

0.5 x 4.0 kg x (5.5 m/s)^2 + 0.5 x 4.5 kg x (-2.5 m/s)^2 = 0.5 x 4.0 kg x v1^2 + 0.5 x 4.5 kg x v2^2

Simplifying this equation gives:

15.875 = 2.0 v1^2 + 5.0625

10.8125 = 2.0 v1^2

v1^2 = 5.40625

v1 = ±2.32 m/s

Since block 1 was originally moving to the right, we can discard the negative solution and conclude that the final velocity of block 1 after the collision is:

v1 = 2.32 m/s to the right

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An electric heater rated 2.75 kW is connected to a 240 V power line with a circuit breaker rated 10 A. Deduce whether or not the line will be active. when the heater is switched on.​

Answers

To determine whether the line will be active when the heater is switched on, we need to calculate the current that will flow through the circuit when the heater is in operation. We can use Ohm's law, which states that current is equal to voltage divided by resistance, or I = V/R.

The resistance of the heater can be calculated using the formula:

R = V^2/P

where V is the voltage and P is the power of the heater.

In this case, the resistance of the heater is:

R = 240^2/2.75 kW = 20.87 Ω

Using Ohm's law, we can now calculate the current that will flow through the circuit when the heater is on:

I = V/R = 240/20.87 = 11.5 A

Since the current required by the heater (11.5 A) is greater than the circuit breaker rating (10 A), the circuit breaker will trip when the heater is switched on, and the line will not be active.

Help with (iii) and (iv) please:
A train consists of an engine and three trucks with masses and resistances to motion as shown in
Fig. 1. There is also a driving force of 37 000 N. All the couplings are light, rigid and horizontal.
(i) Show that the acceleration of the train is 0.3 ms2.
(i) Draw a diagram showing all the forces acting on truck Z in the line of its motion.
Calculate the force in the coupling between trucks Y and Z.
[3]
[4]
With the driving force removed, brakes are applied, so adding a further resistance of 11 000 N to
the total of the resistances shown in Fig. 1.
(iii) Calculate the new acceleration of the train.
(iv) Calculate the new force in the coupling between trucks Y and Z if the brakes are applied
(A) to the engine,
(B) to truck Z
In cach case state whether the force is a tension or a thrust.
[2]
[6]

Answers

(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:

F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N

The acceleration of the train is given by the formula:

a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²

Therefore, the acceleration of the train is 0.3 m/s².

(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:

Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z

(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:

R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N

The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:

a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²

Therefore, the new acceleration of the train is 0 m/s².

(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:

F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N

The force in the coupling between trucks Y and Z is a tension.

When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:

F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N

The force in the coupling between trucks Y and Z is a thrust.

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The motion of objects in regard to other objects is called _____ motion.

Answers

Answer:

The motion of objects in regard to other objects is called relative motion.

Explanation:

Relative motion is the motion of an object in relation to another object or point. It is the description of the movement of an object with respect to a frame of reference or another object in motion. The concept of relative motion is used to describe the motion of objects in everyday life, such as the motion of a car on a highway relative to the motion of other cars or the motion of a person walking on a moving train relative to the motion of the train. The velocity and direction of an object's relative motion are determined by comparing its motion to the motion of a chosen reference point or object.

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If you want to increase the mechanical advantage of a machine, what do you also have to increase?
Group of answer choices

The distance the force is applied over while using the machine

The amount of force applied while using the machine

The amount of energy put into the machine while using it

The amount of time the force is applied while using the machine

Answers

Explanation:

The distance the force is applied over while using the machine.

In the figure, a small block of mass m = 0.019 kg can slide along the frictionless loop-the-loop, with loop radius R = 13 cm. The block is
released from rest at point P, at height h = 5R above the bottom of the loop. How much work does the gravitational force do on the
block as the block travels from point P to (a) point Q and (b) the top of the loop? If the gravitational potential energy of the block-Earth system is taken to be zero at the bottom of the loop, what is that potential energy when the block is (c) at point P, (d) at point Q, and (e) at the top of the loop?

Answers

The amount of work done as the block travels from point P to (a) point Q is 0.096J, (b) the top of the loop is 0.072J, the  potential energy when the block is (c) at point P is 0.121 J, (d) at Q is 0.024 J, (e) at top is 0.048 J

Given the mass of small block (m) = 0.019kg

The radius of loop (R) = 13cm.

The height of point P (H) = 5R = 5 *13 = 65cm

the gravitational potential energy of the block-Earth system is taken to be zero at the bottom of the loop.

We know that the potential energy is calculated as (PE) = m*g*h where g is the gravitational acceleration = [tex]9.8m/s^2[/tex]

(a) The work done by the gravitational force on the block as the block travels from point P to point Q is: W = F * d = m*g*d

the distance from point P to Q = 4R = 4 * 13 = 52cm

W =[tex](0.019 kg)*(9.8 m/s^2)*(4R) = 0.096J[/tex]

(b) The work done by the gravitational force on the block as the block travels from point P to the top of the loop is:

Here the displacement from point P to top of loop = H - 2R = 3R = 39cm

W = m*g*h = [tex](0.019 kg)*(9.8 m/s^2)*(3R) = 0.072J[/tex]

(c) The gravitational potential energy of the block-Earth system at point P is: PE = mgh = [tex](0.019 kg) * (9.8 m/s^2) * (5R) = 0.121 J[/tex]

(d) The gravitational potential energy of the block-Earth system at point Q is: PE = mgh = [tex](0.019 kg) * (9.8 m/s^2) * (R) = 0.024 J[/tex]

(e) The gravitational potential energy of the block-Earth system at the top of the loop is:

PE = mgh =[tex](0.019 kg)*(9.8 m/s^2)*(2R) = 0.048 J[/tex]

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Joe wishes to hang a sign weighing 800 N so that cable A, attached to the store, makes a 30.0° angle, as shown below. Cable B is horizontal and attached to an adjoining building.
What is the tension in cable 87

Answers

The tension in cable B is 87.5 N, see the computation in the section below

Given DataWeight of sign = 800 N Angle of cable A = 30.0° Tension in cable B = 87.5 N

Tension in cable A = 800sin30 = 400 N

Tension in cable B = 800cos30 = 693.33 N

Total Tension = 400 + 693.33 = 1093.33 N

Tension in cable B = 1093.33 - 800 = 293.33 N

Tension in cable B = 293.33/2 = 87.5 N

The tension in cable B, attached to an adjoining building, is 87.5 N in order to hang a sign weighing 800 N so that cable A, attached to the store, makes a 30.0° angle.

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You are on an island where a huge explosion at a distance of 500 miles away can be heard. How long (in seconds) does it take the sound to travel to your location? Assume the temperature of the air is 20 oC. (1 mile = 1.6 km)

A. 1.4 s

B. 2340.1 s

C. 50.7 s

D. 8955.4 s

Answers

The option B. 2340.1 s is correct. It takes 2340.1 s  for the sound to travel to your location when a huge explosion at a distance of 500 miles away can be heard.

Given the distance the sound of explosion can be heard (d) = 500miles

the temperature of the air is (T) = 20°C = 20 + 273 = 293K

1 mile = 1.6km then 500 miles = 500 * 1.6 = 800km

The time up to which the sound can be heard = t

The speed of sound at normal temperature = 331m/s

Then the speed of sound in air at 20°C is (v) = [tex]331 * \sqrt{T/273}[/tex]

Also time is calculated as distance per unit speed such that t = d/v

Then, t =[tex]800km/331 * \sqrt{T/273} = 800 * 10^3/331 * \sqrt{293/273} = 2413/1.03[/tex]

t =  2340.1 s

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what are complementary angles and supplementary angles difference between them​

Answers

Answer:

Complementary Angles and Supplementary Angles: Differences and Definitions

Complementary angles and supplementary angles are two common types of angles in geometry. Although they are related concepts, they have different definitions and properties. Here is a brief explanation of the differences between complementary angles and supplementary angles:

Complementary Angles:

Complementary angles are two angles whose sum is equal to 90 degrees. In other words, when two angles are complementary, they add up to a right angle. Complementary angles are denoted as "∠A" and "∠B", where ∠A + ∠B = 90°.

For example, if one angle measures 30 degrees, the complementary angle would measure 60 degrees, since 30 + 60 = 90. Another example of complementary angles would be 45 degrees and 45 degrees, since 45 + 45 = 90.

Supplementary Angles:

Supplementary angles are two angles whose sum is equal to 180 degrees. In other words, when two angles are supplementary, they add up to a straight angle. Supplementary angles are denoted as "∠C" and "∠D", where ∠C + ∠D = 180°.

For example, if one angle measures 60 degrees, the supplementary angle would measure 120 degrees, since 60 + 120 = 180. Another example of supplementary angles would be 90 degrees and 90 degrees, since 90 + 90 = 180.

Differences:

The main difference between complementary angles and supplementary angles is the sum of their measures. Complementary angles add up to 90 degrees, while supplementary angles add up to 180 degrees. Another difference is the types of angles that they form. Complementary angles form a right angle, while supplementary angles form a straight angle.

In conclusion, complementary angles and supplementary angles are two common types of angles in geometry. Complementary angles add up to a right angle of 90 degrees, while supplementary angles add up to a straight angle of 180 degrees. Understanding the differences between these types of angles is essential for solving problems in geometry and trigonometry.

Explanation:

Answer:

complementary angles start from 90 degree and supplementary start after 180 degree

a. Whats the initial momentum of the ball.

b. what is the final momentum after the ball was hit ?

c. what is the change in momentum of the ball ?

Answers

(a) The initial momentum of the ball of mass 0.045 kg is 0 kgm/s.

(b) The final momentum after the ball was hit is 1.215 kgm/s.

(c) The change in momentum of the ball is 1.215 kgm/s.

What is momentum?

Momentum is the product of mass and velocity

(a) To calculate the initial momentum of the ball, we use the formula below

M' = mu...............Equation 1

Where:

M' = Initial momentumm = Mass of the ballu = Initial velocity

From the question,

Given:

m = 0.045 kgu = 0 m/s

Substitute these values into equation 1

M' = 0.045×0M' = 0 kgm/s

(b) To calculate the final momentum after the ball was hit, we use the formula below

M = mv.................... Equation 2

Where:

M = Final momentum of the ballv = Final velocity of the ball = 27 m/s

Substitute into equation 2

M = 0.045×27M = 1.215 kgm/s

(c) To calculate the change in momentum of the ball, we use the formula below.

ΔM = M-M'................................ Equation 1

Where:

ΔM = Change in momentum

Substitute into equation 3

ΔM = 1.215-0ΔM = 1.215 kgm/s

Hence, The Initial momentum, final and change in momentum of the ball is 0 kgm/s, 1.215 kgm/s, 1.215 kgm/s respectively.

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Which statement about electric charges is correct? (1 point)

*two objects with negative charges will attract each other
*an object with a negative charge and an object with a positive charge will attract each other
*an object with a positive charge and an object with a negative charge will repel each other
*two objects with positive charges will attract each other

Answers

Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

What is charge ?

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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Asteroid A has 5.0 times the mass and 2.0 times the velocity of Asteroid B. If Asteroid B has a kinetic energy of 4,700,000 J then what is the kinetic energy of Asteroid A?​

Answers

Asteroid A has a kinetic energy of 94,000,000 J.

What kind of energy does an asteroid possess?

Such a body is predicted to strike the planet once per million years or so and produce energy about equal to 10,000 megatons of TNT, slightly more than the energy released during a nuclear war and sufficient to trigger a nuclear winter scenario (see graph above).

The following equation determines an object's kinetic energy:

KE = 0.5 * m * v².

Then, we could type:

m_A = 5.0 * m_B (mass of Asteroid A)

v_A = 2.0 * v_B (velocity of Asteroid A)

Asteroid B's kinetic energy is listed as 4,700,000 J. When we substitute the mass and velocity estimates for asteroid B, we obtain:

KE_B = 0.5 * m_B * v_B² = 4,700,000 J

Solving for the mass of Asteroid B, we get:

m_B = 2 * KE_B / v_B²

The equation for the mass of asteroid A is given by replacing this expression for m B with m A = 10 * KE B / v B².

The following results are obtained by substituting the two asteroids' masses and velocities in the kinetic energy formula:

KE_A = 0.5 * m_A * v_A²

= 0.5 * (10 * KE_B / v_B²) * (2 * v_B)²

= 20 * KE_B

As a result, asteroids A and B have kinetic energies that are 20 times greater than each other.

KE_A = 20 * 4,700,000 J

= 94,000,000 J

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LIGHT
L MULTIPLE CHOICE. Choose the best answer from the box provided.
Translucent
Reflected Rays
Transparent
Beam of light
Photometry
Incident Rays
or medium.
of one steradian
Non-Luminous Objects Luminous Objects
Candela
Brightness
Dispersion
Luminous Intensity
Refracted Rays
Light Ray
Opaque
1. It can be expressed as luminous intensity with a unit known as Candela.
2. It refers to the light traveling in one direction in a straight line.
3. Rays of light that point towards and strike a surface.
4. It is the fundamental unit of luminous intensity.
5. Allow light to easily pass through.
6. It is the process of splitting white light into its constituent colors ROYGBIV.
7. Rays that formed when a light goes through a surface and bend due to a change of material
8. It does not let light pass through.
9. It refers to the amount of light power emanating from a point source within a solid angle
10. It deals with the measurement of visible light as perceived by the human eye.
11. Allow light to pass through but distant the light during the passage.
12. It is a group of rays given out from a source.
13. These are objects that can not emit their own light.
14. Rays of light that bounce off of a surface.
15. Those that can not emit their own light.

Answers

1.Luminous Intensity-It can be expressed as luminous intensity with a unit known as Candela.

2.Light Ray- It refers to the light traveling in one direction in a straight line.

3.Incident Rays- Rays of light that point towards and strike a surface.

4.Candela- It is the fundamental unit of luminous intensity.

5.Transparent-Allow light to easily pass through.

6.Dispersion-It is the process of splitting white light into its constituent colors ROYGBIV.

7.Refracted Rays-Rays that formed when a light goes through a surface and bend due to a change of material.

8.Opaque- It does not let light pass through.

9.Photometry-It refers to the amount of light power emanating from a point source within a solid angle

10.Brightness-It deals with the measurement of visible light as perceived by the human eye.

11.Translucent- Allow light to pass through but distant the light during the passage.

12.Beam of light-It is a group of rays given out from a source.

13.Non-Luminous Objects- These are objects that cannot emit their own light.

14.Reflected Rays- Rays of light that bounce off of a surface.

15.Non-Luminous Objects-Those that cannot emit their own light.

What is Luminous intensity?

Luminous intensity is a measure of the amount of light emitted from a point source in a particular direction per unit time. It is expressed in the SI unit of candela (cd).

Luminous intensity is a fundamental concept in photometry, which is the study of the measurement of visible light as perceived by the human eye. The luminous intensity of a light source depends on various factors such as the amount of power it emits, the wavelength of light, and the efficiency of the source in converting electrical energy into light.

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What is the formula of energy

Answers

Answer:

Hey Buddy!

Explanation:

This is ur answer....

E = mc^2

Hope it helps!

Brainliest pls!

Have a good day ~

Answer:

The formula for energy is E = mc²,where E is energy, m is mass, and c is the speed of light.

◉⁠‿⁠◉

Can someone please help me find the equivalent resistance of this circuit.

Answers

The equivalent resistance of 5 resistors in parallel, each having a value of "R" is R/5.

What is the equivalent resistance of parallel circuit?

A parallel circuit is an electrical circuit that has two or more paths for the current to flow through. In a parallel circuit, the components are connected in such a way that the voltage across each component is the same, while the current through each component may be different

The given circuit has 5 resistors arranged parallel to each other.

The equivalent resistance of 5 resistors in parallel, each having a value of "R" is given by:

1/R_eq = 1/R + 1/R + 1/R + 1/R + 1/R

Simplifying the equation, we get:

1/R_eq = 5/R

Multiplying both sides by R, we get:

R_eq = R/5

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A satellite orbiting the earth has a mass of 8695 Kilograms, however because of how far it is from the earth's surface earth's gravity is only 0.35 m/s?. What is the weight of the satellite orbiting the earth?

Answers

The weight of the satellite orbiting the earth is 3068.25 Newtons.

Calculation of weight satellite

This is calculated using the equation

Weight = Mass x Acceleration or

W = m x g.

Where, m = 8695 kg and

g = 0.35 m/s2.

Therefore,  W = 8695 kg x 0.35 m/s2 = 3068.25 N.

A satellite is an artificial object that orbits a planet or other astronomical body. It is used for communication, navigation, weather forecasting, and other purposes.

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A 2750 kg helicopter flies horizontally at constant speed. Air resistance creates a 7510 N backward force. What is the direction of the lift force created
by the propellers?

Answers

Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

To find the direction of the lift force created by the propellers?

Since the helicopter is flying horizontally at a constant speed, we know that the net force acting on it must be zero.

The weight of the helicopter can be calculated as :

weight = mass x gravity

weight = 2750 kg x 9.81 m/s²

weight = 26977.5 N

Since the net force acting on the helicopter is zero, we can write:

forward force - backward force + lift force + weight = 0

Substituting the given values, we get

forward force - 7510 N + lift force + 26977.5 N = 0

Simplifying the equation, we get:

forward force + lift force = 7510 N - 26977.5 N

forward force + lift force = -19467.5 N

Since the helicopter is flying at a constant speed, we know that the forward force created by the propellers must be equal in magnitude to 7510 N. Therefore, we can write:

7510 N + lift force = -19467.5 N

Solving for the lift force, we ge:

lift force = -26977.5 N

Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

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Energy stored in food can be considered as a type of what kind of energy

Answers

Answer: We get chemical energy from foods, which we use to run about, and move and talk  kinetic and sound energy  Chemical energies are stored in fuels which we burn to release thermal energy - this is one way of making electricity, see Electricity for more information



hope this helps

What type of system is represented by the image below?


Group of answer choices

Isolated system

Closed system

Open system

Semi-open system

Answers

Answer:

This is an open system

Explanation:

By the definition

"An open system is a system that has flows of information between the system and its environment, and which adapts to the exchange"

In the above diagram

The system and the surroundings are interacting

Hence it is an open system (Option 3)

Hope it helps

Please mark brainliest :)

Explanation:

most would say "closed system". so, this is the correct answer, although I personally disagree with that term.

an open system allows matter and energy to be exchanged with the surroundings.

a closed system allows energy to be exchanged with the surroundings. and this contradicts in my opinion the word "closed". not to forget : matter is energy and energy is matter.

an isolated system exchanges neither matter nor energy with the surroundings. there is no such thing like a 100% isolated system (except maybe - MAYBE - the whole universe).

there are semi-open systems in various branches of engineering, but I am not aware of such a generic system type in general physics.

A subway train starting from rest leaves a
station with a constant acceleration. At the
end of 7.06 s, it is moving at 12.2844 m/s.
What is the train’s displacement in the first
5.39384 s of motion?
Answer in units of m.

Answers

The train's displacement in the first 5.39384 s of motion is 24.0 m.

Steps

We can use the kinematic equation:

v = u + at

where:

v = final velocity = 12.2844 m/s

u = initial velocity = 0 m/s (train starting from rest)

a = acceleration

t = time = 7.06 s

Solving for acceleration:

v = u + at

a = (v - u) / t

a = (12.2844 m/s - 0 m/s) / 7.06 s

a = 1.736 m/s²

Now, we can use another kinematic equation to find the displacement in the first 5.39384 s:

s = ut + 0.5at²

where:

s = displacement

u = initial velocity = 0 m/s

a = acceleration = 1.736 m/s²

t = time = 5.39384 s

s = 0 + 0.5(1.736 m/s²)(5.39384 s)²

s = 24.0 m

Therefore, the train's displacement in the first 5.39384 s of motion is 24.0 m.

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This is physics thanks .:)

Answers

The image formed when an object is placed at the center of the curvature of a concave mirror is real.

What are the characteristics of the image?

When an object is placed at the center of curvature (D₀ = R) of a concave mirror, the image formed is known as the real and inverted image.

The image characteristics are as follows:

Nature: Real and Inverted

The image formed by a concave mirror when an object is placed at the center of curvature is a real image, which means that the light rays actually converge at a point in front of the mirror, forming an inverted image.

Size:

The size of the image formed at the center of curvature of the concave mirror is the same as the size of the object. Therefore, the image size is equal to the object size.

Position:

The position of the image formed is at the center of curvature (C) of the concave mirror. Hence, the distance of the image from the mirror is equal to the distance of the object from the mirror, i.e., Dᵢ = D₀ = R.

Real or Virtual:

The image formed is real because the light rays converge at a point in front of the mirror, and the image can be obtained on a screen.

Magnification:

The magnification of the image formed is unity, which means that the size of the image is the same as that of the object. Hence, the magnification is equal to one.

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A 70kg astronaut is 300km above the surface of the earth. Calculate the gravitational field strength at this altitude. What is the weight (force of gravity) of the astronaut at this altitude?

Answers

Answer:

The gravitational field strength at an altitude of 300 km above the surface of the earth can be calculated using the formula:

g = GM/(r+h)^2

where g is the gravitational field strength, G is the gravitational constant, M is the mass of the earth, r is the radius of the earth, h is the altitude above the surface of the earth.

Using the values:

G = 6.67 x 10^-11 N(m/kg)^2

M = 5.97 x 10^24 kg

r = 6.38 x 10^6 m

h = 3 x 10^5 m

we can calculate:

g = (6.67 x 10^-11) x (5.97 x 10^24)/((6.38 x 10^6 + 3 x 10^5)^2)

g = 8.62 m/s^2

This means that the gravitational field strength at an altitude of 300 km above the surface of the earth is about 8.62 m/s^2.

To calculate the weight of the astronaut at this altitude, we can use the formula:

F = mg

where F is the force of gravity (weight), m is the mass of the astronaut, and g is the gravitational field strength at this altitude.

Using the value: m = 70 kg, and g = 8.62 m/s^2, we get:

F = 70 x 8.62

F = 603.4 N

Therefore, the weight of the astronaut at an altitude of 300 km above the surface of the earth is about 603.4 N.

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