What is 2000 + 2000 - 2000 X 2000 divided by 2000

Answer:

-82

Step-by-step explanation:

(-62) - (-20) = -82

Answer:

1. 6

2. 600

3. 60,000

4 6,000,000

5. 0.5

6. 0.5

7. 0.5

8. 0.5

Explanation:

It is simple math and also you put the last on 30,000x2,000 I Know what you meant so I fixed it.

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the equation

(5x+3x)+(-32+12)=180

8x-20=180

Step 2: Add 20 to both sides.

8x-20+20= 180+20

              8x= 200

Step 3: Divide both sides by 8

8x/8= 200/8

     x= 25

Answer:

...................................

Answer:

And....? Is there anything else to it?

Answer:

0.49

Step-by-step explanation:

We can use the formula to find the error bound:

EBM=(zα/2)(σ/√n)

We know that σ=2 and n=65. We are also given that the confidence level (CL) is 95%, or 0.95. So, we can calculate alpha (α).

α=1−CL

=1−0.95

=0.05

Since α=0.05, we know that α2=0.05/2=0.025. The value of z0.025 is 1.960.

Now we can substitute the values into the formula to find the error bound.

EBM=(zα/2)(σ/√n)

=(1.960)(2/√65)

≈(1.960)(0.248)

≈0.49

So, the error bound (EBM) is 0.49.

The quotient of the synthetic division problem -1 | 2 7 5 in polynomial form is 2x + 5

The synthetic division problem is given as:

-1 | 2 7 5

Remove the number before the | sign

2 7 5

Remove the middle number

2 5

Introduce a variable starting from an exponent of 0 (let the variable be x)

2x¹ 5x⁰

Evaluate the exponents

2x 5

Express as sum

2x + 5

Hence, the quotient of -1 | 2 7 5 in polynomial form is 2x + 5

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Answer:

the rate iof change is 286

Step-by-step explanation:

Answer:

Rate of Change is 65

Step-by-step explanation:

260/4 = 65

585/9 = 65

845/13 = 65

1105/17 = 65

1625/25 = 65

Answer:

56.54866776

Step-by-step explanation:

:) Hope this helps

56.5486677646

or just 56.54 works :)

Answer:

A-Volume is the amount of space inside an object.

C-Surface area is the sum of the areas of the faces of an object.

D-Surface area and volume are measurements of three-dimensional objects.

Step-by-step explanation:

Got it right on edge unit test

The true statements are:-

A-Volume is the amount of space inside an object.

C-Surface area is the sum of the areas of the faces of an object.

D-Surface area and volume are measurements of three-dimensional objects.

Volume is defined as the space occupied by any object in the three dimensions. All three parameters are required for the volume like length, width, and height of the cube.

The correct statements can be written below:-

A-Volume is the amount of space inside an object.

C-Surface area is the sum of the areas of the faces of an object.

D-Surface area and volume are measurements of three-dimensional objects.

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Answer:

tbh not sure sorry hope somebody anwsers

Step-by-step explanation:

Answer:

Since EF bisects ∠DEF, we know that EF splits ∠DEF in 2 halves from the word 'bisects', which can be written as 'bi- sects' , where bi means 2 and sects means sections

Hence, ∠DEG = ∠GEF --------------(1)

We are given the measure of these angles:

∠DEG = 3x - 4

∠GEF = x + 13

Now, replacing the values in (1):

3x - 4 = x + 13

2x = 17

x = 17/2

Now, finding the measure of ∠DEF:

∠DEF = ∠DEG + ∠GEF

∠DEF = 3x - 4 + x + 13

∠DEF = (51 / 2) - 4 + (17/2) + 13                      (x = 17/2)

∠DEF = 34 - 4 + 13

∠DEF = 43°

Answer:-17/12

Step-by-step explanation:

convert fractions, subtract

Answer:

10.48

Step-by-step explanation:

Answer:

10.48 mi

Step-by-step explanation:

2.62 times 4= 10.48

Answer:

Step-by-step explanation:

Let the weight of a pen be x

Then its weight can be between

This can be shown as

Answer:

X ≥ 112,6 $

Step-by-step explanation:

Normal Distribution  N ( 95 , 16 )

μ₀ = 95

σ  =  16

We need to get z (score) for area 0,1357; then from z - Table we get

z (score) = 1,1

Now  z (score ) = ( X - μ₀ )/σ

1,1 = ( X - 95 ) / 16

17,60 + 95  = X

X = 112,6 $

That means that in order to get a gift customes has to spend at least 112,6 $

Answer:

is this in slope intercept form for what kind

Answer:

i just joined and i get points for an answer, im sorry i cant answer te question

Answer:

x= 3 ; the answer choice D.

Step-by-step explanation:

EDGE 2020, just took the test.

Answer:C

Step-by-step explanation:

The maximum load this boat could hold without sinking is 225 g. The correct option is C.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the rectangular boat pictured below is floating in water with a density of 1.0 g/mL. The sides of the boat are 4.5 cm high, and the base of the boat measures 10.0 cm x 5.0 cm.

The weight will be calculated as,

Density = mass/volume

1 = mass / ( 5 x 10 x 4.5 )

mass = 225 g

Hence, the correct option is C.

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Answer:

18.

Step-by-step explanation:

Answer:

We divide right? if yes then great!

18 remainder 3 so 18.3

Answer:

  y = -2x +6

Step-by-step explanation:

For the two points (3, 0) and (-2, 10), the equation of the line can be written using the two-point form.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (10 -0)/(-2 -3)(x -3) +0

  y = 10/-5(x -3)

  y = -2x +6

Answer:

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃    to maximize

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Step-by-step explanation:

Let´s call Xij   product size i produced in center j

According to this, we get the following set of variable

X₁₁    product size huge produced in center 1

X₁₂    product size huge produced in center 2

X₁₃   product size huge produced in center 3

X₂₁   product size average produced in center 1

X₂₂   product size average produced in center 2

X₂₃   product size average produced in center 3

X₃₁  product size-tiny produced in center 1

X₃₂ product size-tiny produced in center 2

X₃₃ product size-tiny produced in center 3

Then Objective function is

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Constrains

Center capacity

1.-   First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

2.-   Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

3.- Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275

Water available

1.-  22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

2.-  22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

3.-   22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

Demand constrain

Product huge

X₁₁  +  X₁₂  + X₁₃  ≤  710

Product average

X₂₁  + X₂₂ + X₂₃  ≤  900

Product tiny

X₃₁ + X₃₂ + X₃₃  ≤  350

Fraction SP/CC must be the same

First and second centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   =  (X₁₂ + X₂₂ + X₃₂)/ 2700

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

First and third centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   = ( X₁₃ + X₂₃ + X₃₃)/ 3400

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

________Hours of sleep______

Age ___<6__6-6.9___ 7-7.9 __≥8 ___total

≤ 39___38___60_____77____65____240

≥ 40___36___57_____75____92____260

A.) test of independence for row and column variables :

Null: row and column variables are independent

Alternative : row and column variables are not independent

Expected frequencies :

[(row total) * (column total] / sample size

E1: ((38+60+77+65)*(38+36))/500 = 35.52

E2: ((38+60+77+65)*(60+57))/500 = 56.16

E3: ((38+60+77+65)*(77+75))/500 = 72.96

E4: ((38+60+77+65)*(65+92))/500 = 75.36

E5: ((36+57+75+92)*(38+36))/500 = 38.48

E6: ((36+57+75+92)*(60+57))/500 = 60.84

E7: ((36+57+75+92)*(77+75))/500 = 79.04

E8: ((36+57+75+92)*(65+92))/500 = 81.64

Then performing the Chisquare independence test X²

X² = Σ[(f1-e1)²/e1 + (f2-e2)²/e2... (fn - en)²/en]

F1 to f8 = 38,60,77,65,36,57,75,92

X² = ((38-49.92)^2)/35.52 + ((60-56.16)^2)/56.16 + ((77-72.96)^2)/72.96 + ((65-75.36)^2)/75.36 + ((36-38.48)^2)/38.48 + ((57-60.84)^2)/60.84 + ((75-79.04)^2)/79.04 + ((92-81.64)^2)/81.64

= 4.0070162

X² = 4.00

α = 0.05

Reject Null if p < α

df = (row - 1)*( column - 1)

df = (2 - 1)*(4-1) = 1*3 = 3

To obtain the p value, we can use an online calculator to compute the P-value from the X² square score at α = 0.05 and 3 degree of freedom

p = 0.261

Since ; p > α ; 0.261 > 0.05 ; The result is not significant at α 0.05 ; Hence we fail to reject the Null.

Answer:

The liters that the tank will contain at 5:11 PM that day are:

Step-by-step explanation:

Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:

And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:

Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:

And replace the values to obtain the new volume pumped:

At last, you must subtract these liters from the last volume identified in the tank:

The volume in the tank at 5:11 PM is 4416 Liters.

The tank will contain 4416 L of water at 5:11 PM .

Given that,  the tank contains 19140 L at 4:47 PM and 8097 L at 5:05 PM

It means that, in 18 minutes the amount of water discharge is,

                        [tex]=19140-8097=11043L[/tex]

The rate of flow is,

                            [tex]=\frac{11043}{18}=613.5L/min[/tex]

From 5:05 PM to 5:11 PM , six minutes are passes.

Water discharge in that six minute is ,

                                [tex]=613.5*6=3681L[/tex]

The tank will contain at 5:11 PM is,

                                        =[tex]8097-3681=4416L[/tex]

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Answer:   0

i⁹⁷ - i = 0