Answer:
the amount of space occupied by a three-dimensional solid object
Step-by-step explanation:
Volume is a measure of the space in a 3D solid object enclosed by the closed surfaces of the solid object.
By using the definition of volume, we can see that the correct option is the last one:
"The amount of space occupied by a three-dimensional solid object"
What does volume measure?
Volume is defined as a 3-dimensional metric derived from longitude, that measures a region in the space. So, each region that "takes space" has a volume.
With that in mind, the option that correctly describes volume is the last option:
"The amount of space occupied by a three-dimensional solid object"
If you want to learn more about volume, you can read:
https://brainly.com/question/1972490
Find the length ofPR
Answer:
PR=8x+4
Step-by-step explanation:
Given:
PQ=3x-2
QR=5x+6
Required:
PR=?
Formula:
PR=PQ+QR
Solution:
PR=PQ+QR
PR=3x-2+5x+6
PR=3x+5x+6-2
PR=8x+4
Hope this helps ;)❤❤❤
Answer:
4(2x + 1)
Step-by-step explanation:
4(2x + 1)
A gift package contains 6 wedges of cheese . If each wedges is 2/3 onuce what is the totel weight in pounds of cheese?
Answer:
4 ounces
Step-by-step explanation:
6x2/3= 4
what is 4 1/3 x 4 1/5=
Answer:
18 1/5
Step-by-step explanation:
Hey there!
Well to multiply them let's make them improper.
13/3 * 21/5
13*21 = 273
3*5 = 15
273/15
Simplified
18 1/5
Hope this helps :)
Answer:
[tex]\huge\boxed{4\dfrac{1}{3}\times4\dfrac{1}{5}=18\dfrac{1}{5}}[/tex]
Step-by-step explanation:
[tex]4\dfrac{1}{3}\times4\dfrac{1}{5}\\\\\bold{STEP\ 1}\\\text{convert the mixed numbers to the improper fractions}\\\\4\dfrac{1}{3}=\dfrac{4\times3+1}{3}=\dfrac{12+1}{3}=\dfrac{13}{3}\\\\4\dfrac{1}{5}=\dfrac{4\times5+1}{5}=\dfrac{20+1}{5}=\dfrac{21}{5}\\\\\bold{STEP\ 2}\\\text{simplify fractions}\\\\4\dfrac{1}{3}\times4\dfrac{1}{5}=\dfrac{13}{3}\times\dfrac{21}{5}=\dfrac{13}{1}\times\dfrac{7}{5}\\\\\bold{STEP\ 3}\\\text{multiply numerators and denominators}\\\\=\dfrac{13\times7}{1\times5}=\dfrac{91}{5}[/tex]
[tex]\bold{STEP 4}\\\text{convert the improper fraction to the mixed number}\\\\=\dfrac{91}{5}=\dfrac{90+1}{5}=\dfrac{90}{5}+\dfrac{1}{5}=18\dfrac{1}{5}[/tex]
CAN ANYONE HELP ME THANKS FOR BRAINLIEST ANSWER? Find slope ( simplest form) parallel to the line 4x+2y=3
Answer:
Slope = -2
Step-by-step explanation:
You want to get it to the slope intercept form first.
2y = -4x + 3
Divide by 2
y = -2x + 3/2
Parallel means in the new slope intercept form there will still be -2x.
y = -2x + b (enter in points ( 0, 1.5 ) )
1.5 = 0 + b
b = 1.5
y = -2x + 1.5 ( just an example of a line parallel to 4x + 2y = 3 )
Please help!! Over several years, Stephon gathered data about his age and the time it took him to run two laps on the school track. The scatter plot shows the data he gathered and the line of best fit. The equation of the line of best fit is y = -2.1x + 565.6. Based on the line of best fit, approximately how long will it take Stephon to run two laps on the track when he is 192 months old?
Answer:
Time taken by Stephen = 162 seconds
Step-by-step explanation:
Stephan gathered data which fits in the line of best fit,
y = -2.1x + 565.6
Where x represents the age (in months)
And y represents the time (in seconds) taken by Stephen to run two laps on the track.
Time taken to run 2 laps at the age of 192 months,
By substituting x = 192 months,
y = -2.1(192) + 565.6
= -403.2 + 565.6
= 162.4 seconds
≈ 162 seconds
Therefore, time taken by Stephen to cover 2 laps was 162 seconds when he was 192 months old.
The graph of an exponential function has a y-intercept of 4 and contains the point (3,500). Construct the exponential function that describes the graph.
Answer:
The "formula" for an exponential function is f(x) = a * bˣ where a is the initial value / y-intercept. Therefore, a = 4 so f(x) = 4 * bˣ. To solve for b, we can plug in the values x = 3 and f(x) = 500 which becomes:
500 = 4 * b³
125 = b³
b = 5 so the answer is f(x) = 4 · 5ˣ.
Answer:
f(x)=4(5)x
Step-by-step explanation:
An exponential equation in the form y=a(b)x has initial value a and common ratio b. The initial value is the same as the y-intercept, 4, so the equation is in the form y=4(b)x. Substituting the point (3,500) gives 500=4(b)3. Solve for b to find that the common ratio is 5.
Question 15
1 pts
The cost of three avatars and three bats is $29.85. The cost of
three avatars and two bats is $23.90. How much will you pay
altogether if you purchase one of each.
O $5.95
O $8.92
$9.95
O $10.99
O $11.00
1 pts
Question 16
9
Answer:
$9.95.
Step-by-step explanation:
Let's say that you are buying a avatars and b bats.
3a + 3b = 29.85
Divide all terms by 3.
a + b = 9.95
You will pay $9.95 if you buy one of each.
Hope this helps!
A group of patients select from among 38 numbers, with 18 odd numbers (black) and 18 even
numbers (red), as well as 0 and 00 (which are green). If a doctor pays $7 that the outcome is an odd
number, the probability of losing the $7 is 20/38 and the probability of winning $14 (for a net gain of
only $7, given you already paid $7) is 18/38
If a doctor pays $7 that the outcome is an odd number, how would you figure out what is the doctors
expected value is?
Answer: $2.95
Step-by-step explanation:
Given: Probability of losing the $7 = [tex]\dfrac{20}{38}[/tex]
Probability of winning $14 = [tex]\dfrac{18}{38}[/tex]
Then, the expected value = (- $7) x ( Probability of losing the $7) + $14 x(Probability of winning $14)
= [tex](-\$ 7)\times\dfrac{20}{38}+(\$14)\times\dfrac{18}{38}[/tex]
= [tex]-\dfrac{70}{19}+\dfrac{126}{19}[/tex]
= [tex]\dfrac{56}{19}\times\approx\$2.95[/tex]
∴ If a doctor pays $7 that the outcome is an odd number, the doctor's
expected value is $2.95.
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a
mean of 100 and a standard deviation of 15.
n
f0 and
102
130
are
The area of the shaded region is (Round to four decimal places as needed.)
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Kented in
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andomly
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ents
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Enter your answer in the answer box and then click Check Answer.
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Answer: 0.4255
Step-by-step explanation:
Given: IQ scores of adults, and those scores are normally distributed
Mean: [tex]\mu=100[/tex]
Standard deviation: [tex]\sigma= 15[/tex]
Let X denotes the IQ of a random adults.
The area between 102 and 130 = [tex]P(102<X<130)=P(\dfrac{102-100}{15}<\dfrac{X-\mu}{\sigma}<\dfrac{130-100}{15})[/tex]
[tex]=P(0.13<Z<2)\ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=P(Z<2)-P(Z<0.13)\\\\=0.9772- 0.5517\ [\text{By z-table}]\\\\=0.4255[/tex]
Hence, area between 102 and 130 = 0.4255
A family dines in a popular franchise restaurant. At the end of the meal, they decide to leave their server a monetary tip that is equal to 20% of the total bill amount, $60.50. How much will the family leave their server as a tip?
Answer:
$12.10
Step-by-step explanation:
First, you have to set up a proportion to find what 20% of $60.50, or 60.5, is. On one side of the proportion you have 20/100 to represent the percent, anytime you have a percent it will always go over 100. On the other side you'll have x/60.5 because you are trying to find a value out of 60.5. This gives you the proportion 20/100=x/60.5. In order to solve this you have to cross multiply using the equation 20(60.5)=100x. First, you multiply to get 1210=100x, then divide both sides by 100 to get 12.1=x. In order for this to represent money, we add a zero on the end. This means that 20% of $60.50 is $12.10, so $12.10 is the tip.
if you vertically stretch the expontial function f(x) = 2^2 by a factor of 5, what is the equation of the new function?
Answer:
g(x) = [tex]5(2^{2x} )[/tex]
Step-by-step explanation:
If a function f(x) is vertically stretched by a factor of k, the new function we get in the form of k.f(x).
Rule to be followed,
y = k.f(x)
Where k > 1
If the function is vertically compressed then 0 < k < 1
Following the same rule,
A function, f(x) = [tex]2^{2x}[/tex] when vertically stretched by a factor of 5,
Transformed function will be,
g(x) = [tex]5(2^{2x} )[/tex]
In the periodic compound interest formula Upper A equals Upper P (1 plus StartFraction r Over n EndFraction )Superscript nt , what does the variable n represent?
Answer:
The variable n represents the number of times in a year in which we compound the interest rate
Step-by-step explanation:
The periodic compound interest formula is given as;
A = P( 1 + r/n)^nt
The variable n represents the number of times in a year in which the interest rate is compounded
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6970 subjects randomly selected from an online group involved with ears. There were 1334 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
Answer:
we will fail to reject the null hypothesis and conclude that the return rate is less than 20%.
Step-by-step explanation:
We are given;
Sample size;n = 6970
Success rate;X = 1334/6970 = 0.1914
Now, we want to test the claim that the return rate is less than p = 0.2, hence the null and alternative hypothesis are respectively;
H0: μ < 0.2
Ha: μ ≥ 0.2
The standard deviation formula is;
σ = √(x(1 - x)/n)
σ = √(0.1914(1 - 0.1914)/6970)
σ = 0.004712
Now for the test statistic, formula is;
z = (x - μ)/σ
z = (0.1914 - 0.2)/0.004712
z = -1.825
From the a-distribution table attached, we have a value of 0.03362.
This p-value gotten from the z-table is more than the significance value of 0.01. Thus, we will fail to reject the null hypothesis and conclude that the return rate is less than 20%.
Which expression is equivalent to the expression below? StartFraction 6 c squared + 3 c Over negative 4 c + 2 EndFraction divided by StartFraction 2 c + 1 Over 4 c minus 2 EndFraction StartFraction 3 c (2 c minus 1) Over 2 c + 1 EndFraction StartFraction negative 3 c (2 c + 1) squared Over 4 (2 c minus 1) squared EndFraction 3c –3c
Answer:
its D. -3c
Step-by-step explanation:
just took the test
The expression that is equivalent to the expression [(6c² + 3c)/(-4c + 2)] ÷ [(2c + 1)/(4c - 2)] is; -3c
The fraction we are given to work with is;[(6c² + 3c)/(-4c + 2)] ÷ [(2c + 1)/(4c - 2)]
Simplifying the fraction equation by factorization gives:[3c(2c + 1)/(-2(2c - 1))] ÷ [(2c + 1)/(2(2c - 1)]
Now, in division of fractions, we know that;3/2 ÷ 1/5 is the same as; 3/2 × 5/1
Applying this same method to our question gives;
[3c(2c + 1)/(-2(2c - 1))] × [(2(2c - 1)/(2c + 1)]
2(2c - 1) is common and will cancel out to get; 3c(2c + 1)/(-1/(2c + 1))2c + 1 is common and will cancel out to get; -3cRead more about simplification of fractions at;https://brainly.com/question/6109670
Write the following Arithmetic Sequence using a Recursive Formula: a = -7 + 3(n - 1)
A : A1 = -7, an = an-1 + 3
B : A1= -7, a, = an+1 + 3
C : A1 = 3, an = an+1 - 7
D : A1 = 3, an = an-1 - 7
NEED ANSWER ASAP
Answer:
A : A1 = -7, an = an-1 + 3
Step-by-step explanation:
a1=-7, a2=-7+(1)3=-4
a3=-7+(2)3=-1
What is the average rate of change of f(x)=-2/x^2 when the interval is 1 to 2
Answer:
1.5
Step-by-step explanation:
average rate of change = (f(x2) - f(x1))/(x2 - x1)
f(x) = -2/x^2
f(x2) = f(2) = -2/(-2)^2 = -2/4 = -0.5
f(x1) = f(1) = -2/1^2 = -2
average rate of change = (-0.5 - (-2))/(2 - 1)
average rate of change = (-0.5 + 2)/1
average rate of change = 1.5
Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 4.5 m34.5\text{ m}^34.5 m34, point, 5, start text, space, m, end text, cubed. Syrus isn't sure if the tent will be tall enough for him to stand inside. What is the height of the tent?
Answer:
2 meters
Step-by-step explanation:
The volume is 4.5
⋅1.5⋅h⋅3
=2.25h
=h
The height of the tent is 2 meters.
Hope this helps :)
Answer:
2 meters
Step-by-step explanation:
Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)
Answer:
There are two or zero positive solutions and zero negative roots (zeros).
Step-by-step explanation:
Use Descartes' Rule of Signs to determine the number of real zeros of [tex]f(x)=2x^6-3x^3+1-2x^5[/tex]
[tex]f(x)=2x^6-2x^5-3x^3+1\\[/tex]
Simplify the expression:
4 + 5u + 8 – 4
Answer:
5u+8
Step-by-step explanation:
Both of the 4's will cancel out with each other.
5u+8. it works actuallly by taking common nunbers and cancelling them. in this case. 4. leaving it with just 5u+8 :)
Use Newton's method to approximate the indicated root of the equation correct to six decimal places. The negative root of ex = 4 − x2
Answer:
x = -1.964636
Step-by-step explanation:
Given equation;
eˣ = 4 - x²
This can be re-written as;
eˣ - 4 + x² = 0
Let
f(x) = eˣ - 4 + x² -----------(i)
To use Newton's method, we need to get the first derivative of the above equation as follows;
f¹(x) = eˣ - 0 + 2x
f¹(x) = eˣ + 2x -----------(ii)
The graph of f(x) has been attached to this response.
As shown in the graph, the curve intersects the x-axis twice - around x = -2 and x = 1. These are the approximate roots of the equation.
Since the question requires that we use the negative root, then we start using the Newton's law with a guess of x₀ = -2 at n=0
From Newton's method,
[tex]x_{n+1} = x_n + \frac{f(x_{n})}{f^1(x_{n})}[/tex]
=> When n=0, the equation becomes;
[tex]x_{1} = x_0 - \frac{f(x_{0})}{f^1(x_{0})}[/tex]
[tex]x_{1} = -2 - \frac{f(-2)}{f^1(-2)}[/tex]
Where f(-2) and f¹(-2) are found by plugging x = -2 into equations (i) and (ii) as follows;
f(-2) = e⁻² - 4 + (-2)²
f(-2) = e⁻² = 0.13533528323
And;
f¹(2) = e⁻² + 2(-2)
f¹(2) = e⁻² - 4 = -3.8646647167
Therefore
[tex]x_{1} = -2 - \frac{0.13533528323}{-3.8646647167}[/tex]
[tex]x_{1} = -2 - \frac{0.13533528323}{-3.8646647167}[/tex]
[tex]x_{1} = -2 - -0.03501863503[/tex]
[tex]x_{1} = -2 + 0.03501863503[/tex]
[tex]x_{1} = -1.9649813649[/tex]
[tex]x_{1} = -1.96498136[/tex] [to 8 decimal places]
=> When n=1, the equation becomes;
[tex]x_{2} = x_1 - \frac{f(x_{1})}{f^1(x_{1})}[/tex]
[tex]x_{2} = -1.96498136 - \frac{f(-1.9649813)}{f^1(-1.9649813)}[/tex]
Following the same procedure as above we have
[tex]x_{2} = -1.96463563[/tex]
=> When n=2, the equation becomes;
[tex]x_{3} = x_2 - \frac{f(x_{2})}{f^1(x_{2})}[/tex]
[tex]x_{3} = -1.96463563- \frac{f( -1.96463563)}{f^1( -1.96463563)}[/tex]
Following the same procedure as above we have
[tex]x_{3} = -1.96463560[/tex]
From the values of [tex]x_2[/tex] and [tex]x_3[/tex], it can be seen that there is no change in the first 6 decimal places, therefore, it is safe to say that the value of the negative root of the equation is approximately -1.964636 to 6 decimal places.
Newton's method of approximation is one of the several ways of estimating values.
The approximated value of [tex]\mathbf{e^x = 4 - x^2}[/tex] to 6 decimal places is [tex]\mathbf{ -1.964636}[/tex]
The equation is given as:
[tex]\mathbf{e^x = 4 - x^2}[/tex]
Equate to 0
[tex]\mathbf{4 - x^2 = 0}[/tex]
So, we have:
[tex]\mathbf{x^2 = 4}[/tex]
Take square roots of both sides
[tex]\mathbf{ x= \pm 2}[/tex]
So, the negative root is:
[tex]\mathbf{x = -2}[/tex]
[tex]\mathbf{e^x = 4 - x^2}[/tex] becomes [tex]\mathbf{f(x) = e^x - 4 + x^2 }[/tex]
Differentiate
[tex]\mathbf{f'(x) = e^x +2x }[/tex]
Using Newton's method of approximation, we have:
[tex]\mathbf{x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}}[/tex]
When x = -2, we have:
[tex]\mathbf{f'(-2) = e^{(-2)} +2(-2) = -3.86466471676}[/tex]
[tex]\mathbf{f(-2) = e^{-2} - 4 + (-2)^2 = 0.13533528323}[/tex]
So, we have:
[tex]\mathbf{x_{1} = -2 - \frac{0.13533528323}{-3.86466471676}}[/tex]
[tex]\mathbf{x_{1} = -2 + \frac{0.13533528323}{3.86466471676}}[/tex]
[tex]\mathbf{x_{1} = -1.96498136}[/tex]
Repeat the above process for repeated x values.
We have:
[tex]\mathbf{x_{2} = -1.96463563}[/tex]
[tex]\mathbf{x_{3} = -1.96463560}[/tex]
Up till the 6th decimal places,
[tex]\mathbf{x_2 = x_3}[/tex]
Hence, the approximated value of [tex]\mathbf{e^x = 4 - x^2}[/tex] to 6 decimal places is [tex]\mathbf{ -1.964636}[/tex]
Read more about Newton approximation at:
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Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts.
Diet Regular
μ μ1 μ2
n 20 20
x 0.78062lb 0.81645 lb
s 0.00444 lb 0.00745 lb
A. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.
What are the null and alternative and hypotheses?
B. What is the test statistic? (Round to two decimal places as needed.)
C. What is the P-value? (Round to three decimal places as needed.)
State the conclusion for the test.
A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
b. Construct a confidence interval appropriate for the hypothesis test in part (a).
___lb < u1 - u2 < ___lb (Round to three decimal places as needed.)
Does the confidence interval support the conclusion found with the hypothesis test?
(No/Yes) because the confidence interval contains (zero/only positives values/ only negative values)
Answer:
(A) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex]
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex]
(B) The value of t-test statistics is -18.48.
(C) The P-value is Less than 0.005%.
(D) Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
Step-by-step explanation:
We are given that the Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right;
Diet Regular
μ μ1 μ2
n 20 20
x 0.78062lb 0.81645 lb
s 0.00444 lb 0.00745 lb
Let [tex]\mu_1[/tex] = mean weight of contents of cans of diet soda.
[tex]\mu_2[/tex] = mean weight of contents of cans of regular soda.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex] {means that the contents of cans of diet soda have weights with a mean that is more than or equal to the mean for the regular soda}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex] {means that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda}
The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;
T.S. = [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ~ [tex]t__n_1_+_n_2_-_2[/tex]
where, [tex]\bar X_1[/tex] = sample mean weight of cans of diet soda = 0.78062 lb
[tex]\bar X_2[/tex] = sample mean weight of cans of regular soda = 0.81645 lb
[tex]s_1[/tex] = sample standard deviation of cans of diet soda = 0.00444 lb
[tex]s_2[/tex] = sample standard deviation of cans of regular soda = 0.00745 lb
[tex]n_1[/tex] = sample of cans of diet soda = 20
[tex]n_2[/tex] = sample of cans of diet soda = 20
Also, [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(20-1)\times 0.00444^{2}+ (20-1)\times 0.00745^{2}}{20+20-2} }[/tex] = 0.00613
So, the test statistics = [tex]\frac{(0.78062-0.81645)-(0)}{0.00613 \times \sqrt{\frac{1}{20}+\frac{1}{20} } }[/tex] ~ [tex]t_3_8[/tex]
= -18.48
The value of t-test statistics is -18.48.
Also, the P-value of the test statistics is given by;
P-value = P( [tex]t_3_8[/tex] < -18.48) = Less than 0.005%
Now, at a 0.01 level of significance, the t table gives a critical value of -2.429 at 38 degrees of freedom for the left-tailed test.
Since the value of our test statistics is less than the critical value of t as -18.48 < -2.429, so we have sufficient evidence to reject our null hypothesis as it will not fall in the rejection region.
Therefore, we conclude that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.
Draw a picture of the standard normal curve and shade the area that corresponds to the requested probabilities. Then use the standard normal table to find the following probabilities. Enter the probabilities as decimals. Enter the final answer only. 1.P(z>1.38)= 2.P(1.233 −2.43)= 7.P(z>−2.43)=
Answer:
a)P [ z > 1,38 ] = 0,08379
b) P [ 1,233 < z < 2,43 ] = 0,1012
c) P [ z > -2,43 ] = 0,99245
Step-by-step explanation:
a) P [ z > 1,38 ] = 1 - P [ z < 1,38 ]
From z-table P [ z < 1,38 ] = 0,91621
P [ z > 1,38 ] = 1 - 0,91621
P [ z > 1,38 ] = 0,08379
b) P [ 1,233 - 2,43 ] must be P [ 1,233 < z < 2,43 ]
P [ 1,233 < z < 2,43 ] = P [ z < 2,43 ] - P [ z > 1,233 ]
P [ z < 2,43 ] = 0,99245
P [ z > 1,233 ] = 0,89125 ( approximated value without interpolation)
Then
P [ 1,233 < z < 2,43 ] = 0,99245 - 0,89125
P [ 1,233 < z < 2,43 ] = 0,1012
c) P [ z > -2,43 ]
Fom z-table
P [ z > -2,43 ] = 1 - P [ z < -2,43 ]
P [ z > -2,43 ] = 1 - 0,00755
P [ z > -2,43 ] = 0,99245
[tex]3x+5y=7\\9x+11y=13[/tex] Solve for the variables.
Answer:
x = -1
y =2
Step-by-step explanation:
3x+ 5y = 7
9x+ 11y = 13
Multiply the first equation by -3 so we can eliminate x
-3 (3x+ 5y = 7)
-9x -15y = -21
Add this to the second equation
-9x -15y = -21
9x+ 11y = 13
-------------------
- 4y = -8
Divide by -4
-4y/-4 = -8/-4
y=2
Now solve for x
3x+5y = 7
3x+5(2) = 7
3x+10 = 7
Subtract 10
3x = 7-10
3x = -3
Divide by 3
3x/3 = -3/3
x = -1
Answer:
-1, 2
Step-by-step explanation:
Although you already have the answer, here's another method of doing it that may or may not help you someday. First, we solve the top equation for x. We get:
[tex]x = \frac{7}{3} - \frac{5}{3}y\\9x + 11y = 13[/tex]
Now that we know what x is, we can plug it into the bottom equation to solve for y.
[tex]9(\frac{7}{3} - \frac{5}{3}y) + 11y = 13[/tex]
Simplify everything out, and you'll see that y = 2. We can now plug it into our equation to solve for x.
x = 7/3 - 5/3 x 2; x = -1
In the figure below, YZA and YZX are right angles, XYZ and AYZ are congruent, and XZ = 10. What is the length of ?
A.
25
B.
20
C.
10
D.
5
Answer:
C. 10
Step-by-step explanation:
The given information tells you that triangles YZX and YZA are congruent, so ZA = ZX = 10.
Please help what’s the answer!!!
Answer:
-1
Step-by-step explanation:
Anything raised to 0 is 1
Multiply i 1 by 1
Simplify.
Rewrite i2 as −1
Move −1 to the left of i
Rewrite −1 i as −i
Factor out i2
Rewrite i2 as −1
Rewrite i2 as −1
Rewrite i4 as 1
Multiply −1 by 1
Noah tried to prove that cos(θ)=sin(θ) using the following diagram. His proof is not correct.
Answer:
The first statement is incorrect. They have to be complementary.
Step-by-step explanation:
You can't say the measure of angle B is congruent to theta because it is possible for angles in a right triangle to be different.
You can only say that what he said is true if the angle was 45 degrees, but based on the information provided it is not possible to figure that out.
The other two angles other than the right angle in a right triangle have to add up to 90 degrees, which is the definition of what it means for two angles to be complementary. A is the correct answer.
Answer:
[tex]\boxed{\sf A}[/tex]
Step-by-step explanation:
The first statement is incorrect. The angle B is not equal to theta θ. The two acute angles in the right triangle can be different, if the triangle was an isosceles right triangle then angle B would be equal to theta θ.
Need help with solving for x!
Answer:
x = c × sin(α)
x = 15 x sin(38)
= 9.23492
= 9.2
Step-by-step explanation:
Please helppp!!!!! Geometry
Answer:
[tex]\boxed{Option \ 4}[/tex]
Step-by-step explanation:
∠YVZ = 180 - 52 - 43 - 38 (Angles on a straight line add up to 180 degrees so if we try to find an unknown angle on the straight line, we need too subtract all the other angles from 180 degrees)
=> ∠YUZ = 47 degrees
Step-by-step explanation: In the figure shown, <UVW is a straight angle.
This means it measures 180 degrees.
So to find <YVZ, we add up all the angles and subtract the sum
from 180 to get the answer to this problem.
43 + 52 + 38 gives us a sum of 133.
Now we take 180 - 133 yo get 47.
So m<YVZ is 47 degrees.
CAN SOMEONE PLEASE HELP ME! To find x
ANSWERS
A-(11)
B-(14)
C-(7)
D-(3)
Answer:
C-(7)
Step-by-step explanation:
Given figure is a trapezoid and 21 - x is the mid segment.
Therefore by mid-segment formula of a trapezoid, we have:
21 - x = 1/2(17 + 11)
21 - x = 1/2 * 28
21 - x = 14
21 - 14 = x
7 = x
x = 7
A lease provides that the tenant pays $760 minimum rent per month plus 4% of the gross sales in excess of $150,000 per year. If the tenant paid a total rent of $20,520 last year, what was the gross sales volume?
Answer:
$435,000
Step-by-step explanation:
$760 per month * 12 months = $9,120
The minimum rent requires an annual rental cost of $9,120.
The annual rent was $20,520.
The excess was $20,520 - $9,120 = $11,400.
The amount of $11,400 of the rent was due to the gross sales in excess of $150,000.
$11,400 is 4% of the amount in excess of $150,000.
Let the amount in excess of $150,000 = x.
$11,400 = 4% of x
0.04x = 11,400
x = 285,000
$285,000 is the amount in excess of $150,000.
Total gross sales volume = $285,000 + $150,000 = $435,000