What do you call a person or an institution who invests the money or the
one who makes the funds available?
Answers
An institutional investor is a person or organization that trades securities in large enough quantities that it qualifies for preferential treatment and lower fees. A retail investor is an individual or non-professional investor who buys and sells securities through brokerage firms or savings accounts.
tip: make sure to reword it
Answer:
Lender
Quizzz review some of this the test name is
Math Math Math!!!!
10 questions
By:Mrs. Bagauisan
Related Questions
is this right or no?
Answers
1/3 of 12= 4
5/12 of 12= 5
1/4 of 12= 3
Plssssss I neeed help I will mark brainlist
Answers
Answer:
so i think it is rst on the right
Which equation could have the graph shown below? y = (x – 4)(x – 1)(2 + x)(3 + x) y = (x – 4)(1 – x)(2 + x)(3 + x) y = (x + 4)(x + 1)(2 – x)(3 – x) y = (x + 4)(x + 1)(2 – x)(x – 3)
Answers
Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
Step-by-step explanation: Step by Step Solution
More Icon
STEP
1
:
Equation at the end of step 1
((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
2
:
Equation at the end of step 2
(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
3
:
Equation at the end of step 3
((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
4
:
Multiplying Exponential Expressions:
4.1 Multiply (x-4) by (x-4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-4) and the exponents are :
1 , as (x-4) is the same number as (x-4)1
and 1 , as (x-4) is the same number as (x-4)1
The product is therefore, (x-4)(1+1) = (x-4)2
Equation at the end of step
4
:
(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
5
:
5.1 Rewrite (1-x) as (-1) • (x-1)
Multiplying Exponential Expressions:
5.2 Multiply (x-1) by (x-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-1) and the exponents are :
1 , as (x-1) is the same number as (x-1)1
and 1 , as (x-1) is the same number as (x-1)1
The product is therefore, (x-1)(1+1) = (x-1)2
STEP
7
:
Pulling out like terms
7.1 Pull out like factors :
-x - 2 = -1 • (x + 2)
Multiplying Exponential Expressions:
7.2 Multiply (x + 2) by (x + 2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+2) and the exponents are :
1 , as (x+2) is the same number as (x+2)1
and 1 , as (x+2) is the same number as (x+2)1
The product is therefore, (x+2)(1+1) = (x+2)2
STEP
9
:
Pulling out like terms
9.1 Pull out like factors :
-x - 3 = -1 • (x + 3)
Multiplying Exponential Expressions:
9.2 Multiply (x + 3) by (x + 3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+3) and the exponents are :
1 , as (x+3) is the same number as (x+3)1
and 1 , as (x+3) is the same number as (x+3)1
The product is therefore, (x+3)(1+1) = (x+3)
((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
10
:
Equation at the end of step 10
(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
11
:
STEP
12
:
Pulling out like terms
12.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
12
:
((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
13
:
STEP
14
:
Pulling out like terms
14.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
14
STEP
15
STEP
16
:
Pulling out like terms
16.1 Pull out like factors :
-x - 4 = -1 •
Equation at the end of step
16
:
STEP
17
:
STEP
18
:
Pulling out like terms
18.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Multiplying Exponential Expressions:
18.2 Multiply (x + 4) by (x + 4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+4) and the exponents are :
1 , as (x+4) is the same number as (x+4)1
and 1 , as (x+4) is the same number as (x+4)1
The product is therefore, (x+4)(1+1) = (x+4)2
Equation at the end of step
18
:
(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)
STEP
19
:
STEP
20
:
Pulling out like terms
20.1 Pull out like factors :
-x - 1 = -1 • (x + 1)
Multiplying Exponential Expressions:
20.2 Multiply (x + 1) by (x + 1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+1) and the exponents are :
1 , as (x+1) is the same number as (x+1)1
and 1 , as (x+1) is the same number as (x+1)1
The product is therefore, (x+1)(1+1) = (x+1)2
Equation at the end of step
20
:
((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)
STEP
21
:
21.1 Rewrite (2-x) as (-1) • (x-2)
Multiplying Exponential Expressions:
21.2 Multiply (x-2) by (x-2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-2) and the exponents are :
1 , as (x-2) is the same number as (x-2)1
and 1 , as (x-2) is the same number as (x-2)1
The product is therefore, (x-2)(1+1) = (x-2)2
22.1 Multiply (x-3) by (x-3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-3) and the exponents are :
1 , as (x-3) is the same number as (x-3)1
and 1 , as (x-3) is the same number as (x-3)1
The product is therefore, (x-3)(1+1) = (x-3)2
Final result :
(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
what is the domain and range
Answers
Answer:
domain: [0, positive infinity)
range: (negative infinity, positive infinity)
Hamza decides to increase the prices of all items in his shop by 10%, Work out the new price of in item normally priced at £210
Answers
10% = 21
New price = 110%
110% = 231
£231
Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x + 14)^2 (5 points)
Shift the graph of y = x2 down 14 units.
Shift the graph of y = x2 right 14 units.
Shift the graph of y = x2 left 14 units.
Shift the graph of y = x2 up 14 units.
Answers
Step-by-step explanation:
For y = x², y = 0 when x = 0.
For y = (x + 14)², y = 0 when x = -14.
Notice that the zero of the function has went from 0 to -14, or 14 units to the left.
The answer is "Shift the graph of y = x² left 14 units.".
Answer:
We conclude that the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.
Step-by-step explanation:
Please check the attached graph.
The blue graph is representing the graph of y = x². The red graph is representing the graph of y = (x + 14)².If we carefully analyze the given graph which is attached below, it is clear that the given graph y = (x + 14)² is the transformed image of form f(x+b) of parent graph y = x².
In this graph, the function y = x² has been moved over 14 units to the left.
In other words,
f(x+2) = f(x+14)² means the function f(x) is shifted 14 units to the left.
Therefore, the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.
how much is 21 hundreds
Answers
Answer:
21,000
Step-by-step explanation:
1+y=-4/5x-2
Solve for Y
Answers
Step-by-step explanation:
y=-4/5x-2-1
y=-4/5x-3
y/4=5x-3
(y/4)-3 =5x
(y-12)/4=5x
The solution for y will be y = -4/5x-3
What is expression?Numbers, symbols and operators grouped together that show the value of something.
Given an expression, 1+y=-4/5x-2
Solving for y, we get
1+y=-4/5x-2
y = -4/5x-2-1
y = -4/5x-3
Hence, The solution for y will be y = -4/5x-3
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Kara recorded the ages of the people in her book club in this table.
29 34 31 39 43
28 37 35 33 60
26 33 38 36 41
If the outlier is not included, what will happen to the range and the IQR of this data set?
A.
The range will stay the same, but the IQR will change.
B.
The range and the IQR will both stay the same.
C.
The IQR will stay the same, but the range will change.
D.
The range and the IQR will both change.
Answers
Answer:
D.
The range and the IQR will both change.
Step-by-step explanation:
PLATO
The correct answer is C. The IQR will stay the same, but the range will change.
How to calculate the IQR?To determine what will happen to the range and the IQR of this data set if the outlier is not included, we first need to identify the outlier.
One way to identify an outlier is to use the 1.5 x IQR rule. According to this rule, any data point that is more than 1.5 times the IQR away from the first or third quartile is considered an outlier.
Using this rule, we can calculate the IQR of the data set:
Arrange the data set in order from smallest to largest:
26 28 29 31 33 33 34 35 36 37 38 39 41 43 60
Find the median, Q₂, of the data set. In this case, Q₂ = 36.
Divide the data set into two halves: the lower half, which includes all values less than or equal to Q₂, and the upper half, which includes all values greater than or equal to Q₂:
Lower half: 26 28 29 31 33 33 34 35
Upper half: 36 37 38 39 41 43 60
Find the median, Q₁, of the lower half. In this case, Q₁= 30.
Find the median, Q₃, of the upper half. In this case, Q₃ = 41.
Calculate the IQR as the difference between Q₃ and Q₁: IQR = Q₃ - Q₁ = 11.
Multiply the IQR by 1.5: 1.5 x 11 = 16.5.
Add 16.5 to Q₃ and subtract 16.5 from Q₁ to get the upper and lower bounds for outliers:
Upper bound: Q₃ + 16.5 = 57.5
Lower bound: Q₁ - 16.5 = 13.5
Any value outside this range is considered an outlier.
In this data set, the value 60 is greater than the upper bound of 57.5, so it is an outlier.
Therefore, the correct answer is C. The IQR will stay the same, but the range will change.
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Guy spent £11.40 buying ingredients to make cupcakes. He sold all the cakes for a total of £39.90. What percentage profit did Gary make?
Answers
Answer:
sup
Step-by-step explanation:
Where is the point (-8,0) located on the coordinate plane?
1. On the X-axis
2. In quadrant ll
3. In quadrant lll
4. On the y-axis
Answers
Answer:
On the X-asis
Tell me if I am wrong. :) Hope it helps though.
Step-by-step explanation:
Answer:
in quadrant ii (-8,0) located
does anyone minding helping me with exterior angles ? due in 2 days
Answers
Answer:
x=25
Step-by-step explanation:
(x+40)+(3x+10)=6x
4x+50=6x
50=2x
25=x
Answer:
see explanation
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ CBD is an exterior angle of the triangle, then
6x = x + 40 + 3x + 10, that is
6x = 4x + 50 ( subtract 4x from both sides )
2x = 50 ( divide both sides by 2 )
x = 25
Thus
∠ CBD = 6x = 6 × 25 = 150°
∠ CBA and ∠ CBD are adjacent angles and supplementary, sum to 180°, then
150° + ∠ CBA = 180° ( subtract 150° from both sides )
∠ CBA = 30°
what is the answer 6a+5a-b-5b+2a
Answers
Answer: 13a-6b
Step-by-step explanation:
Answer:
13a - 6b
Step-by-step explanation:
6a + 5a - b - 5b + 2a
~Combine like terms
13a - 6b
Best of Luck!
What is the ratio of red circles to blue circles
Answers
Answer:
1:1 or one red circle to one blue circle
There is one red and one blue circle
Someone can help me with this assignment about The Pythagorean Theorem.
I have to solve it for the missing side length (s).
Answers
Answer:
√45^2-27^2
which is 36
hope it helps u dear
Mark me BRAINLIEST ❣️❤️❤️❣️❣️
I need help ASAP!!!!!!!!!!!!!!!!
Answers
Answer: 5/13
Step-by-step explanation: Cosine equals adjacent over hypotenuse so adjacent is the side closest to the angle neglecting the hypotenuse of course because that's always the longest side. So Cos=A/H or 5/13
1 divided by 20 equalyufghytfjbhbh
Answers
Answer:
1 divided by 20 is equal to 0.05.
Step-by-step explanation:
In this problem, we need to find 1 divided by 20 is equal to what.
1 should be in the numerator and 20 should be in the denominator.
[tex]\dfrac{1}{20}=\dfrac{1}{2}\times \dfrac{1}{10}\\\\=0.5\times 0.1\\\\=0.05[/tex]
Hence, 1 divided by 20 is equal to 0.05.
Riley buys ice cream and oranges at the store.
She pays a total of $37.15.
She pays a total of $3.62 for the ice cream.
She buys 7 bags of oranges that each cost the same amount.
How much does each bag of oranges cost?
Answers
Answer:
4.79 dollars.
Step-by-step explanation:
7x + 3.62 = 37.15
7x= 37.15-3.62
7x=33.53
x= 33.53/7=4.79 dollars.
Dianna made several loaves of bread yesterday. Each loaf required 2 and two-thirds cups of flour. All together, she used 13 and one-third cups of flour. How many loaves did Dianna make?Which is the best estimate of 11 and one-fifth divided by 2 and three-fourths?
Answers
Answer:
5 loaves and 4
Step-by-step explanation:
what is 25% of 50 please
Answers
answer is idk because it is a half
Which of the following is the axis of symmetry
Answers
What is a correct name for the angle shown?
Answers
Answer:
SRT
Step-by-step explanation:
Answer:
obtuse angle
Step-by-step explanation:
a L is a right angle, a right angle is 90 degrees. if the angle is more then 90 degrees and looks like its being stretched it is obtuse. and if it is smaller then 90% and looks like it is being squashed it an acute angle.
Lynn, Jude, and Anne were given the function f (x) = -3x^2 + 12 and they were asked to find (2). Lynn's answer was 48, Jude's answer v correct? Show Your Work
Answers
Answer:
(2) is equal to 48 because you substitute x for 2 in the equation. F(2)= -3(2)^2 +12= -3 times 2 is -6 then you square it to get 36 and add 12 to get 48
Step-by-step explanation:
solve the right angle trig. round to the nearest tenth.
Answers
Answer:
x ≈ 58.9
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightGeometry
[Right Triangles Only] tan∅ = opposite over adjacentStep-by-step explanation:
Step 1: Define
We are given a right triangle. We can use trig to find the missing side length.
Step 2: Identify Variables
POV from the angle measure
Angle = 23°
Opposite Leg = 25
Adjacent Leg = x
Step 3: Solve for x
Substitution [tangent]: tan23° = 25/xMultiply x on both sides: xtan23° = 25Isolate x: x = 25/tan23°Evaluate: x = 58.8963Round: x ≈ 58.9please help me.......
Answers
Answer:
x = 12
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Equality PropertiesStep-by-step explanation:
Step 1: Define
-10(x + 9) + 14x = -42
Step 2: Solve for x
Distribute -10: -10x - 90 + 14x = -42Combine like terms: 4x - 90 = -42Add 90 to both sides: 4x = 48Divide 4 on both sides: x = 12Anita received 3 postcards of zebras and 2 postcards of monkeys each month for 3 months. How many postcards is that?
Answers
Answer:
8 post cards
Step-by-step explanation:
Eight
Answer:
15
Step-by-step explanation:
3+2=5
5x3=15
SOME PLEASE HELP PLEASE
Answers
Answer:
i think y= 6x+4
Step-by-step explanation:
Help easy math problems!!!!!
Answers
Answer:
Answer Below
Step-by-step explanation:
tan(D): yes
sin(F): yes
Cos(F): no
Sin(D): no
Answer:
tan(D): yes
sin(F): yes
Cos(F): no
Sin(D): no
Step-by-step explanation: Solve for values of all, then check if the equation makes sense.
Prove ΔABC ∼ ΔGEF. (10 points)
Answers
Answer:
Step-by-step explanation:
If we take the below diagram for the given triangles, then ∠B=∠E and ∠A=∠G if AB=GE or if BC=EF, then corresponding angles will be equal.
Therefore, if we rotate the diagram, then also the angles will remain the same.
⇒
2. ⇒⇒ the triangles ABC and EFG have 2 angles equals ⇒ ABC~ EFG
5. ⇒ < ABC=6. < GFE = < BCA= < ECD =
⇒ the triangles ABC and EFG have 2 angles equals ⇒ ABC~ EFG
Marshall Middle School is planning a field trip to see Romeo and Juliet at the local theater. The cost of a teacher ticket is $25 and the cost of a student ticket is $13. Write an expression to show the cost of t teacher tickets and s student tickets.
Answers
Answer:
25t + 13sStep-by-step explanation:
Teacher ticket = $25Student ticket = $13Expression to show the cost of t teacher tickets and s student tickets:
25t + 13s