Answers
Answer:
2-ethoxy-2-methylpropan-1-ol
Explanation:
On this reaction, we have an "epoxide" (2-methyl-1,2-epoxypropane). Additionally, we have acid medium (due to the sulfuric acid [tex]H_2SO_4[/tex]). The acid medium will produce the hydronium ion ([tex]H^+[/tex]). This ion would be attacked by the oxygen of the epoxide. Then a carbocation would be produced, in this case, the most stable carbocation is the tertiary one. Then an ethanol molecule acts as a nucleophile and will attack the carbocation. Finally, a deprotonation step takes place to produce 2-ethoxy-2-methylpropan-1-ol.
See figure 1
I hope it helps!
Related Questions
Calculate the entropy change for the reaction: HCl(g) + NH3(g) -> NH4Cl(s) Entropy data: HCl: 187 J/K mol NH3: 193 J/K mol NH4Cl: 94.6 J/K mol
Answers
Answer:
-285.4 J/K
Explanation:
Let's consider the following balanced equation.
HCl(g) + NH₃(g) ⇒ NH₄Cl(s)
We can calculate the standard entropy change for the reaction (ΔS°r) using the following expression.
ΔS°r = 1 mol × S°(NH₄Cl(s)) - 1 mol × S°(HCl(g)) - 1 mol × S°(NH₃(g))
ΔS°r = 1 mol × 94.6 J/K.mol - 1 mol × 187 J/K.mol - 1 mol × 193 J/K.mol
ΔS°r = -285.4 J/K
Answer:
-198.3 J/K mol
Explanation:
I got it correct on founders edtell
The atomic number of an element is 31 and the mass number of one of its atoms is 65. This atom contains: a 31 neutrons b 34 protons c 65 protons d 34 neutrons e 34 electrons
Answers
Answer:
d, 34 neutrons
Explanation:
Mass number is the sum of the number of protons and the number of neutrons.
Atomic number equals to the number of protons.
Since the element has an atomic number of 31, it has 31 protons. The number of neutrons equal to mass number - no. of protons,
which in this case is 65 - 31
= 34 neutrons.
In a neutral atom, the no. of electrons equal to the no. of protons, because each proton carries a +1 charge and each electron carries a -1 charge. To cancel out the charge, their numbers must be equal. So, this atom has 31 electrons.
From the options, only d is correct. (34 neutrons)
Which is the correct way to write 602,200,000,000 ,000,000,000,000 in scientific notation
Answers
Answer:
6.022 × 10^23
hope this helps :)
If the heat of combustion for a specific compound is −1380.0 kJ/mol and its molar mass is 44.53 g/mol, how many grams of this compound must you burn to release 822.00 kJ of heat?mass:g
Answers
Answer:
Mass = 26.53 g
Explanation:
Heat of combustion = −1380.0 kJ/mol
This means 1 mol of the compound releases 1380 kJ
Molar mass = 44.53 g/mol
This means 1 mol of the compound has a mass of 44.53 g
How many grams would release 822kJ..?
First, we have to obtain the number of moles
1 mol = 1380
x = 822
x = 0.5957 moles
Moles = Mass / Molar mass
Mass = Molar mass * moles
Mass = 44.53 * 0.5957
Mass = 26.53 g
* Question Completion Status:
QUESTION 1
'What compound represents conjugate base in the following chemical reaction? H2SO4 + H2O HSO4 + H30+
O a. H2SO4
O b. H2O
O c. HSO4
O d. H30+
Answers
Answer: b. HSO4-
Explanation:
H2SO4 (sulfuric acid) will donate a hydrogen ion in solution to form H3O+(hydronium). The remaining HSO4- would be the conjugate base of this dissociation.
A conjugate base contains one less H atom and one more - charge than the acid that formed it.
A conjugate acid contains one more H atom and one more + charge than the base that formed it.
Decide which element probably has a density most and least similar to the density of lithium.
Answers
Answer:
Helium and potassium
Explanation:
The density of helium is 0.18 and potassium 0.86, while lithium is 0.53
A buffered solution containing dissolved aniline, C6H5NH2, and aniline hydrochloride, C6H5NH3Cl, has a pH of 5.57 . A. Determine the concentration of C6H5NH+3 in the solution if the concentration of C6H5NH2 is 0.200 M. The pKb of aniline is 9.13. g
Answers
Answer:
[C₆H₅NH₃⁺] = 0.0399 M
Explanation:
This excersise can be easily solved by the Henderson Hasselbach equation
C₆H₅NH₃Cl → C₆H₅NH₃⁺ + Cl⁻
pOH = pKb + log (salt/base)
As we have value of pH, we need to determine the pOH
14 - pH = pOH
pOH = 8.43 (14 - 5.57)
Now we replace data:
pOH = pKb + log ( C₆H₅NH₃⁺/ C₆H₅NH₂ )
8.43 = 9.13 + log ( C₆H₅NH₃⁺ / 0.2 )
-0.7 = log ( C₆H₅NH₃⁺ / 0.2 )
10⁻⁰'⁷ = C₆H₅NH₃⁺ / 0.2
0.19952 = C₆H₅NH₃⁺ / 0.2
C₆H₅NH₃⁺ = 0.19952 . 0.2 = 0.0399 M
Write a balanced equation for: capture of an electron by cadmium-104
Answers
Answer:
104 48 Cd + 0 -1 e ---------> 104 47 Ag
Explanation:
In the process of electron capture, the nucleus captures an electron and thus converts a proton into a neutron with the emission of a neutrino. This process increases the Neutron/Proton ratio, the captured electron is usually from the K shell. An electron from a higher energy level now drops down to fill the vacancy in the K shell and characteristic X-ray is emitted. This process usually occurs where the Neutron/proton ratio is very low and the nucleus has insufficient energy to undergo positron emission.
For 104 48 Cd, the balanced equation for K electron capture is;
104 48 Cd + 0 -1 e ---------> 104 47 Ag
Write the electron configuration for the element titanium, TiTi. Express your answer in order of increasing orbital energy as a string without blank space between orbitals. For example, the electron configuration of LiLi could be entered as 1s^22s^1 or [He]2s^1.
Answers
Answer:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d² or [Ar] 3d² 4s²
Explanation:
Electron configuration can basically be referred to as the location of electron; how the electrons are arranged in the orbitals of the atoms.
Following Aufbau principle, electrons are arranged in the following order of orbitals.
1s 2s 2p 3s 3p 4s 3d and so on.
The s can hold a maximum of 2 electrons, p can hold a maximum of 6 electrons and d can hold a maximum of 10 electrons.
Titanium has an atomic number of 22. So the arrangement is given as;
Ti = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²
The short hand notation is given as;
[Ar] 3d² 4s²
The electron configuration of Ti is
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex] or [tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
The electron configuration of an element is the distribution of electrons in atomic orbitals.
According to Aufbau's principle, the orbitals with lower energies are filled before the orbitals with higher energies.
We can know this order, using the diagonal rule (attached image).
The maximum number of electrons in each sublevel is:
s = 2p = 6d = 10f = 14Considering all these facts, and that Titanium has 22 electrons, the electron configuration of Ti is:
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex]
Since [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex] is the electron configuration of Argon, this can also be written as:
[tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
The electron configuration of Ti is
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex] or [tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
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Answers
Answer:
A. copper is highly water soluble. It will turn into 5 different hydrates as it absorbs more and more water.
b. Glycerol is easily soluble in water, due to the ability of the polyol groups to form hydrogen bonds with water molecules
c. octane is considered to be non-polar, it will not be soluble in water, since water is a polar solvent. This will happen because octane (hydrocarbons in general) contains neither ionic groups, nor polar functional groups that can interact with water molecules.
d. Nitric acid decomposes into water, nitrogen dioxide, and oxygen, forming a brownish yellow solution.
e. Barium carbonate is a white powder. It is insoluble in water and soluble in most acids
Explanation:
Carbon-14 has a half-life of 5720 years and this is a fast-order reaction. If a piece of wood has converted 75 % of the carbon-14, then how old is it?
Answers
Answer:
11445.8years
Explanation:
Half-life of carbon-14 = 5720 years
First we have to calculate the rate constant, we use the formula :
Using the Bohr model, determine the lowest possible energy, in joules, for the electron in the Li2+ ion.
Answers
Answer: E = - 19.611×[tex]10^{-18}[/tex] J
Explanation: The lowest possible energy can be calculated using the formula:
[tex]E_{n} = - Z^{2}.\frac{k}{n^{2}}[/tex]
where:
Z is atomic number of the atom;
k is a constant which contains other constants and is 2.179×[tex]10^{-18}[/tex] J
n is a layer;
For the lowest possible, n=1.
Atom of Lithium has atomic number of Z=3
Substituing:
[tex]E_{1} = - 3^{2}.\frac{2.179.10^{-18}}{1}[/tex]
[tex]E_{1} =[/tex] [tex]-19.611.10^{-18}[/tex] J
The energy for the electron in the [tex]Li^{+2}[/tex] ion is - 19.611 joules
The lowest possible energy, in Joules, for the electron in the [tex]Li^{2+}[/tex] ion is equal to [tex]1.96\times 10^{-17}\; Joules[/tex]
To determine the lowest possible energy, in Joules, for the electron in the [tex]Li^{2+}[/tex] ion, we would use the Bohr model:
Mathematically, Bohr's model is given by the equation:
[tex]Energy = -Z^2 \frac{k}{n^2}[/tex]
Where:
Z is the atomic number of an atom.n is the number of energy level.k is Rydberg constant.We know that the atomic number of lithium (Li) is equal to 3.
Also, at the lowest possible energy, n = 1.
Rydberg constant = [tex]2.179 \times 10^{-18}[/tex]
Substituting the parameters into the equation, we have;
[tex]E_1 = -3^2 \times \frac{2.179 \times 10^{-18}}{1^2} \\\\E_1 =9 \times 2.179 \times 10^{-18}\\\\E_1 =1.96\times 10^{-17}\; Joules[/tex]
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Determine the number of moles of the anhydrous salt present after heating, assuming that the contents of the aluminum cup after heating are pure anhydrous KAl(SO 4 ) 2 .
Answers
Answer:
0.2 moles, assuming weight of dried salt
Explanation:
In order to determine the number of moles, we need to be aware of the mass of the substance in question.
Assuming the mass of the dehydrated [tex]KAl(SO_{4} )_{2}.H_{2} O[/tex] is 50g.
No. of moles = mass of substance/ molar mass of the substance.
= [tex]\frac{50g}{39+27+32*2+16*4*2\\)g/mol}[/tex]
= 0.2 moles moles.
What is the molar mass of a protein if a solution of 0.020 g of the protein in 25.0 mL of solution has an osmotic pressure of 0.56 torr at 25 ∘ C
Answers
Answer:
26.5 kD
Explanation:
Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.56 - ( given ). This is only one part of the information we are given / can conclude in this case ....
i = van’t Hoff factor = 1 for a protein molecule,
R = gas constant = 62.36 L torr / K-mol,
T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K
( Known initially ) ∏ = osmotic pressure = 0.56 torr
..... besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.
_____
Substitute derived / known values to solve for M ( moles / liter ) -
∏ = iMRT
⇒ 0.56 = ( 1 )( M )( 62.36 )( 298 )
⇒ 0.56 = M( 18583.28 )
⇒ M = 0.56 / 18583.28 ≈ 0.00003013461 ....
_____
We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -
M = mol / l
⇒ 0.00003013461 = 0.020 / 25 mL ( 0.025 L ),
0.020 / 0.025 = 0.8 g / L
⇒ 0.8 g = 0.00003013461 moles,
molar mass = 0.8 g / 0.00003013461 moles = 26,548 g / mol = 26.5 kD
Re-order each list of elements in the table below, if necessary, so that the elements are listed in order of decreasing electronegativity.
Answers
Answer:
O, S, Te
Cl, Br, Se
Explanation:
Main group elements have an electronegativity that increases across a period (from left to right) and decreases down a group.
Each atom has its own value which you can find on the electronegativity chart.
Metals have low values
Nonmetals have high values
I'm your case:
O = 3.5
S = 2.5
Te = 2.1
Cl = 3.0
Br = 2.8
Se = 2.4
O, S, Te, and Cl, Br, Se are the correct order for the elements listed in order of decreasing electronegativity.
What is electronegativity?
Electronegativity. is the tendency or the efficiency of an atom to attract the lone pair of electrons towards itself to become stable and complete their octave is known as electronegativity.
In the periodic table oxygen, fluorine and nitrogen are the three top, most electronegative elements, and from moving up to down in periodic table electronegativity. decreases and left to right increases.
Therefore, the correct order for the elements listed in order of decreasing electronegativity is O, S, Te, and Cl, Br, Se.
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A study of the system, 4NH3(g) + 7O2(g) <--> 2N2O4(g) + 6H2O(g), was carried out. A system was prepared with [NH3] = [O2] = 3.60 M as the only components initially. At equilibrium, [N2O4] is 0.600 M. Calculate the equilibrium concentration of NH3(g).
Answers
Answer:
The equilbrium concentration of NH₃(g) is 2.4 M
Explanation:
The balanced reaction is:
4 NH₃(g) + 7 O₂(g) ⇔ 2 N₂O₄(g) + 6 H₂O(g)
By stoichiometry of the reaction, 2 moles of N₂O₄ are formed from 4 moles of NH₃.
Considering that the concentration is [tex]concentration=\frac{number of moles}{volume}[/tex] and with a volume of 1 liter, it is possible to apply the following rule of three: if 2 M of N₂O₄ are formed from 4 M of NH₃, 0.6 M of N₂O₄ from what concentration of NH₃ are formed?
[tex]concentration of NH_{3}=\frac{0.6 M of N_{2}O_{3} *4MofNH_{3} }{2 M of N_{2}O_{3} }[/tex]
concentration of NH₃= 1.2 M
By subtracting the moles of NH3 in equilibrium from the moles of NH₃ initially, you will see how many moles of NH₃ were converted and remain in equilibrium: 3.6 M - 1.2 M= 2.4 M
The equilbrium concentration of NH₃(g) is 2.4 M
Calculate the number of ATP generated from one saturated 10 ‑carbon fatty acid. Assume that each NADH molecule generates 2.5 ATP and that each FADH2 molecule generates 1.5 ATP .
Answers
Answer:
Total ATP molecules produced = 66 molecules of ATP
Explanation:
A 10-carbon fatty acid when it has undergone complete oxidation will yield 5 acetyl-CoA molecules and 4 FADH₂ and 4 NADH molecules each. Each of the 5 acetyl-CoA molecules enters into the citric acid cycle and is completely oxidized to yield further ATP and FADH₂ and NADH molecules.
The total yield of ATP in the various enzymatic step is calculated below:
Acyl-CoA dehydrodenase = 4 FADH₂
β-Hydroxyacyl-CoA dehydrogenase = 4 NADH
Isocitrate dehydrogenase = 5 NADH
α-Ketoglutarate dehydrogenase = 5 NADH
Succinyl-CoA synthase = 5 ATP (from substrate-level phosphorylation of GDP)
Succinate dehydrogenase = 5 FADH₂
Malate dehydrogenase = 5 NADH
Total ATP from FADH₂ molecoles = 9 * 1.5 = 13.5
Total NADH molecules = 19 * 2.5 = 47.5
Total ATP molecules produced = 13.5 + 47.5 + 5
Total ATP molecules produced = 66 molecules of ATP
Answer:
Number of ATP generated = = [tex]64 ATPs[/tex]Explanation:
First, calculate the number of acetyl-CoA molecules formed:
Number of acetyl-CoA molecules = [tex]\frac{number of carbons in fatty acid}{2}[/tex]
[tex]= \frac{10}{2}\\\\ = 5 acetyl-CoA molecules[/tex]
Next, calculate the number of rounds of beta-oxidation:
Number of rounds = number of acetyl-CoA molecules - 1
[tex]= 5 - 1\\\\ = 4 rounds[/tex]
Calculate the number of ATP from NADH and FADH2:
If each NADH yields 2.5 ATPs and each FADH2 yields 1.5 ATPs, then multiply the number of rounds by 4 and multiply the number of acetyl-CoA molecules by 10.
[tex](4 * 4) + (5 * 10) = 66 ATP[/tex]
Subract two ATP molecules for activation of the fatty acid.
[tex]Total ATP = 66 - 2\\\\ = 64 ATPs[/tex]
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A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What is the molarity of this solution? Express your answer to four significant figures and include the appropriate units.
Answers
Answer:
Approximately [tex]1.854\; \rm mol\cdot L^{-1}[/tex].
Explanation:
Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.
Formula mass of strontium hydroxideLook up the relative atomic mass of [tex]\rm Sr[/tex], [tex]\rm O[/tex], and [tex]\rm H[/tex] on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.
[tex]\rm Sr[/tex]: [tex]87.62[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].[tex]\rm H[/tex]: [tex]1.008[/tex].Calculate the formula mass of [tex]\rm Sr(OH)_2[/tex]:
[tex]M\left(\rm Sr(OH)_2\right) = 87.62 + 2\times (15.999 + 1.008) = 121.634\; \rm g \cdot mol^{-1}[/tex].
Number of moles of strontium hydroxide in the solution[tex]M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1}[/tex] means that each mole of [tex]\rm Sr(OH)_2[/tex] formula units have a mass of [tex]121.634\; \rm g[/tex].
The question states that there are [tex]10.60\; \rm g[/tex] of [tex]\rm Sr(OH)_2[/tex] in this solution.
How many moles of [tex]\rm Sr(OH)_2[/tex] formula units would that be?
[tex]\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}[/tex].
Molarity of this strontium hydroxide solutionThere are [tex]8.71467\times 10^{-2}\; \rm mol[/tex] of [tex]\rm Sr(OH)_2[/tex] formula units in this [tex]47\; \rm mL[/tex] solution. Convert the unit of volume to liter:
[tex]V = 47\; \rm mL = 0.047\; \rm L[/tex].
The molarity of a solution measures its molar concentration. For this solution:
[tex]\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}[/tex].
(Rounded to four significant figures.)
Citra is using the basic permanent wrap method to perm Holly's hair. As Citra divides Holly's hair into panels, how wide should she make them?
Answers
Answer:
Citra should make it equal to the length of the rod.
Explanation:
A basic permanent wrap method is a 9 section wrap method in which all the base sections are horizontal, having same length and width of the rod
Basic permanent wrap method causes a uniform curl from the scalp to the end of the hair.
In permanent wrap method, paneling the hair equal to the length will make the will give the same size as the rod.
The length of the rod determines the size of the curl.
Once Holly's hair is divided into panel and make it as wide as the length of the rod, it will curl in the same size as the rod lengths and the hair will perm well.
An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. What molarity of sodium acetate will you need to add to the solution
Answers
Answer:
Molarity of sodium acetate you will need to add is 0.0324M
Explanation:
Assuming volume of the buffer is 1L.
The pH of a buffer can be determined using Henderson-Hasselbalch equation:
pH = pKa + log [A⁻] / [HA]
Where pKa is pKa of the weak acid, [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid
Replacing for the acetic buffer (pKa = 4.76):
pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]
As you have 0.010 moles of acetic acid in 1L:
[Acetic Acid] = 0.010mol / 1L = 0.010M
And you require a pH of 5.27:
5.27 = 4.76 + log [Sodium Acetate] / [0.010M]
0.51 = log [Sodium Acetate] / [0.010M]
10^0.51 = [Sodium Acetate] / [0.010M]
3.236 = [Sodium Acetate] / [0.010M]
3.236 [0.010M] = [Sodium Acetate]
0.0324M = [Sodium Acetate]
Molarity of sodium acetate you will need to add is 0.0324M
In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table below. Isotope Atomic Mass (amu) Relative Abundance O-16 15.995 99.759% O-17 16.995 0.037% O-18 17.999 0.204% Calculate the average atomic mass of oxygen. Show all of your calculations below.
Answers
Answer: The average atomic mass of oxygen is 15.999 amu
Explanation:
Mass of isotope O-16 = 15.995 amu
% abundance of isotope O-16= 99.759 % = [tex]\frac{99.759}{100}=0.99759[/tex]
Mass of isotope O-17 = 16.995 amu
% abundance of isotope O-17 = 0.037% = [tex]\frac{0.037}{100}=0.00037[/tex]
Mass of isotope O-18 = 17.999 amu
% abundance of isotope O-18 = 0.204% = [tex]\frac{0.204}{100}=0.00204[/tex]
Formula used for average atomic mass of an element :
[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]
[tex]A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)][/tex]
[tex]A=15.999[/tex]
Thus the average atomic mass of oxygen is 15.999 amu
Answer:
Converting the percent abundance into decimal form, we get:
O-16: 99.759% = 99.759/100 = 0.9975
O-17: 0.037% = 0.037/100 = 0.00037
O-18: 0.204% = 0.204/100 = 0.0020
Average atomic mass of oxygen is:
(15.995) x (0.9975) + (16.995) x (0.00037) + (17.999) x (0.0020)
= 15.955 + 0.0062 + 0.0359
= 15.997 amu
Explanation:
From PLATO
g What is the standard cell potential for the following reaction occurring in an electrochemical cell. The equation is balanced. 3 Cl2(g) + 2 Fe(s) → 6 Cl-(aq) + 2 Fe3+(aq) The following data may be helpful: Cl2(g) + 2 e- → 2 Cl-(aq) Eº = 1.36 V Fe3+(aq) + 3 e- → Fe(s) Eº = -0.036 V a) -1.40 V b) 1.40 V c) 2.84 V
Answers
Answer:
b) 1.40 V
Explanation:
Oxidation half equation;
2Fe(s) → 2Fe3+(aq) + 6 e-
Reduction half equation;
3Cl2(g) + 6 e- → 6 Cl-(aq)
E°cathode= 1.36 V
E°anode= -0.036 V
E°cell= E°cathode - E°anode
E°cell= 1.36 -(-0.036)
E°cell= 1.36 + 0.036
E°cell= 1.396 V
E°cell= 1.40 V
Why is the chemical formula Li2H incorrect? Select the correct answer below: A. There should be one lithium, not two. B. There should be one lithium and two hydrogens. C. Lithium does not react with hydrogen. D. There should be three lithiums, not two.
Answers
Answer:
There should be one lithium, not two.
Explanation:
Lithium reacts with hydrogen at about 750°C to yield lithium hydride (LiH). LiH is white and powdery in appearance. It releases hydrogen gas when it reacts with water.
The correct formula for Lithium hydride is LiH and not Li2H because both lithium and hydrogen are univalent. Lithium has a valency of +1 while hydrogen has a valency of -1 in lithium hydride. Hydrides are formed between hydrogen and highly electro positive metals. In hydrides, hydrogen is forced to accept an electron from the highly electro positive metal.
18. Sucralose contains which two functional groups: (2 points)
A) benzene
B) halogen
C) carboxyl
D) hydroxy!
Answers
Answer:
The correct answer is option B and D, that is, halogen (chlorine) and hydroxyl.
Explanation:
An artificial sweetener and sugar substitute is sucralose. It is noncaloric as the majority of the sucralose ingested does not get dissociated within the body. The generation of sucralose takes place by the chlorination of sucrose. It is about 300 to 1000 times sweeter in comparison to sucrose.
The consumption of sucralose is safe for both nondiabetics and diabetics, it is used in various food and beverage components due to non-caloric sweetener characteristics. It does not affect the levels of insulin and does not affect dental health. As it is produced by chlorination of sucrose, thus, the functional groups present in it are a halogen (chlorine) and a hydroxyl.
A 75.0 mL sample of 0.020 M acetic acid (HC2H3O2) is titrated with 0.020 M NaOH. ? Determine the pH of the solution before the addition of any NaOH. (Ka of acetic acid is 1.8 x 10-5) HC2H3O2 (aq) + H2O (l) D C2H3O2-(aq) + H3O+ (aq) (Hint: before titration so acid only, use ICE table)
Answers
Answer:
pH = 3.23
Explanation:
Before the addition of any NaOH, the only you have is a 0.020M acetic acid solution. That is in equilibrium with water as follows:
HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂⁻(aq) + H₃O⁺(aq)
The Ka of this reaction is:
Ka = 1.8x10⁻⁵ = [C₂H₃O₂⁻] [H₃O⁺] / [HC₂H₃O₂]
Where [] are concentrations in equilibrium of each species
As you have in solution just HC₂H₃O₂, the equilibrium concentrations will be:
[HC₂H₃O₂] = 0.020M - X
[C₂H₃O₂⁻] = X
[H₃O⁺] = X
Where X is reaction coordinate.
Repalcing in Ka expression:
1.8x10⁻⁵ = [C₂H₃O₂⁻] [H₃O⁺] / [HC₂H₃O₂]
1.8x10⁻⁵ = [X] [X] / [0.020M - X]
3.6x10⁻⁷ - 1.8x10⁻⁵X = X²
3.6x10⁻⁷ - 1.8x10⁻⁵X - X² = 0
Solving for X:
X = -0.0006M → False solution. There is no negative concentrations
X = 0.000591M → Right solution.
As:
[H₃O⁺] = X
[H₃O⁺] = 0.000591M
As pH = -log[H₃O⁺]
pH = 3.2316. A metal element and a non-metal element are brought near each other and allowed to react. What's the most likely type of compound
that will form between these two elements?
A. lonic and covalent
B. lonic
C. Covalent
D. Neither, metals and non-metals don't react.
Answers
Answer:
B) Ionic
Explanation:
The accepted value of the number of Liters of gas in a mole is 22.4. List two possible reasons on why our experiment yielded a different value for the number of Liters in a mole of a gas.
Hint: Our experiment was conducted in July, in St. Paul, Minnesota.
Answers
Answer:
- Pressure in St. Paul, Minnesota
- Temperature in St. Paul, Minnesota
Explanation:
22.4 L or dm³ is the volume for a gas under Standard pressure and temperature conditions.
It is logically to say, that tempereature value at the day of the experiment was not 273.15 K, which is 32°F
We can say, that the pressure was not 1 atm. St Paul Minnesota has a minimum, but a little height, so the pressure differs by few figures from the standard pressure values.
We also have to mention, that 22.4 L is the value for the Ideal gases at standards conditions. Ideal gases does not exisist on practice, we always talk about real gases. Don't forget the Ideal Gases Law equation:
P . V = n . R . T
Pressure . Volume = number of moles . 0.082 L.atm /mol. K . 273.15K
Number of moles must be 1 at STP, to determine a volume of 22.4L
Answer all to the best of your ability please
Answers
Answer:
2–Ethyl–3–methlypentanal.
Explanation:
To name the compound given in the question above, we must observe the following:
1. The functional group of the compound is Alkanal i.e Aldehyde,
—CHO and it is located at carbon 1.
Note: the aldehyde functional group is always at carbon 1 and there will be no need to state it's position in the compound.
2. The longest continuous carbon chain is 5 i.e pentane. But the presence of the functional group will replace the –e at the end of pentane with –al, making the name to the pentanal.
3. The substituents attached are:
a. Ethyl, CH2CH3 at carbon 2.
b. Methyl, CH3 at carbon 3.
4. Combine the above to get the name of the compound.
Therefore, the name of the compound is:
2–Ethyl–3–methlypentanal.
If you did not use a watch glass to cover your stock iodine solution, and the concentration of iodine decreased over the course of your trials, how would this affect the quality of your data
Answers
Answer::
Lower rate of reaction
Explanation:
Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.
This however may not be the case if the iodine in question is catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.
I hope this explanation fits the brief.
What is the percent composition of sulfur in SO2?
OA
32.1 g
(32.1 g + 16.0 g + 16.0 g)
x 100%
32.1 g
O B.
x 100%
(16.0 g + 16.0 g)
O c.
(32.1 g + 16.0 g + 16.0 g)
X 100%
32.1 g
(32.1 g)(6.02 x 102)
O D.
100 g
Answers
Answer:
5 .04 percent.
Explanation:
it is also known as sulfur dioxide. so it's 5.0.4 percent.
Your question is incomplete. Read below to find the content.
0.4 % is the percent composition of sulfur in SO2.
How is SO2 prepared from sulfur?In the laboratory, sulfur dioxide is prepared by the reaction of metallic sulfite or a metallic bisulfite with dilute acid. For example, a reaction between the dilute sulphuric acid and sodium sulfite will result in the formation of SO2.
What do you mean by percentage composition?The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. Here, the quantity is measured in terms of grams of the elements present.
Learn more about percentage composition here: https://brainly.com/question/26150306
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